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  • parse xml with elementtree, custom sorting

    - by microspace
    I want to parse xml file in utf-8 and sort it by some field. Soring is made by custom alphabet (s1 from sourcecode). History of question is here: sorting of list containing utf-8 charachters. I've found how to sort xml here. Sorting work correctly, the problem is with elementtree, I must admit that it doesn't work on python3 Here is source code: #!/usr/bin/env python # -*- coding: utf-8 -*- #import xml.etree.ElementTree as ET # Python 2.5 import elementtree.ElementTree as ET s1='aáàAâÂbBcCçÇdDeéEfFgGgGhHiIîÎíiiIjJkKlLmMnNóoOöÖpPqQrRsSsStTuUûúÛüÜvVwWxXyYzZ' s2='11111122334455666aabbccddeeeeeeffgghhiijjkklllllmmnnooppqqrrsssssttuuvvwwxxyy' trans = str.maketrans(s1, s2) def unikey(seq): return seq[0].translate(trans) tree = ET.parse("tosort.xml") container = tree.find("entries") data = [] for elem in container: keyd = elem.findtext("k") data.append((keyd, elem)) print (data) data.sort(key=unikey) print (data) container[:] = [item[-1] for item in data] tree.write("sorted.xml", encoding="utf-8") Here are instructions to import elementtree module. When I import module this way :import xml.etree.ElementTree as ET, I get a message: Traceback (most recent call last): File "pcs.py", line 19, in <module> container[:] = [item[-1] for item in data] File "/usr/lib/python3.1/xml/etree/ElementTree.py", line 210, in __setitem__ assert iselement(element) AssertionError When I use this method to import: import elementtree.ElementTree as ET, I get this message: Traceback (most recent call last): File "pcs.py", line 4, in <module> import elementtree.ElementTree as ET File "/usr/local/lib/python3.1/dist-packages/elementtree/ElementTree.py", line 794, in <module> _escape = re.compile(eval(r'u"[&<>\"\u0080-\uffff]+"')) File "<string>", line 1 u"[&<>\"\u0080-\uffff]+" ^ SyntaxError: invalid syntax I use Python 3.1.3 (r313:86834, Nov 28 2010, 11:28:10). In python2.6 elementtree work without a problem. Content of tosort.xml: <xdxf> <entries> <ar><k>zaaaa</k>definition1</ar> <ar><k>saaaa</k>definition2</ar> ... ... </entries> </xdxf>

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  • Using SimpleXMLTreeBuilder in elementtree

    - by Shard
    I have been developing an application with django and elementtree and while deploying it to the production server i have found out it is running python 2.4. I have been able to bundle elementtree but now i am getting the error: "No module named expat; use SimpleXMLTreeBuilder instead" Unfortunately i cannot upgrade python so im stuck with what i got. How do i use SimpleXMLTreeBuilder as the parser and/or will i need to rewrite code?

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  • : in node causing Keyerror in xmlparsing using ElementTree

    - by kguckian
    Hi I'm using ElementTree to parse out an xml feed from Kuler. I'm only beginning in python but am stuck here. The parsing works fine until I attempt to retrieve any nodes containing ':' e.g kuler:swatchHexColor Below is a cut down version of the full feed but same structure: <rss xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:kuler="http://kuler.adobe.com/kuler/API/rss/" xmlns:rss="http://blogs.law.harvard.edu/tech/rss" version="2.0"> <channel> <title>kuler popular themes</title> <item> <title>Theme Title: Fresh Money</title> <description> &lt;img src="http://kuler-api.adobe.com/kuler/themeImages/theme_808366.png" /&gt;&lt;br /&gt; Artist: thesylph005&lt;br /&gt; ThemeID: 808366&lt;br /&gt; Posted: 03/02/2010&lt;br /&gt; Hex: 2F400D, 8CBF26, A8CA65, E8E5B0, 419184 </description> <kuler:themeItem> <kuler:themeID>808366</kuler:themeID> <kuler:themeTitle>Fresh Money</kuler:themeTitle> <kuler:themeImage>http://kuler-api.adobe.com/kuler/themeImages/theme_808366.png</kuler:themeImage> <kuler:themeAuthor> <kuler:authorID>370750</kuler:authorID> <kuler:authorLabel>thesylph005</kuler:authorLabel> </kuler:themeAuthor> <kuler:themeTags/> <kuler:themeRating>4</kuler:themeRating> <kuler:themeDownloadCount>708</kuler:themeDownloadCount> <kuler:themeCreatedAt>20100302</kuler:themeCreatedAt> <kuler:themeEditedAt>20100302</kuler:themeEditedAt> <kuler:themeSwatches> <kuler:swatch> <kuler:swatchHexColor>2F400D</kuler:swatchHexColor> <kuler:swatchColorMode>rgb</kuler:swatchColorMode> <kuler:swatchChannel1>0.183333</kuler:swatchChannel1> <kuler:swatchChannel2>0.25</kuler:swatchChannel2> <kuler:swatchChannel3>0.05</kuler:swatchChannel3> <kuler:swatchChannel4>0.0</kuler:swatchChannel4> <kuler:swatchIndex>0</kuler:swatchIndex> </kuler:swatch> <kuler:swatch> <kuler:swatchHexColor>8CBF26</kuler:swatchHexColor> <kuler:swatchColorMode>rgb</kuler:swatchColorMode> <kuler:swatchChannel1>0.55</kuler:swatchChannel1> <kuler:swatchChannel2>0.75</kuler:swatchChannel2> <kuler:swatchChannel3>0.15</kuler:swatchChannel3> <kuler:swatchChannel4>0.0</kuler:swatchChannel4> <kuler:swatchIndex>1</kuler:swatchIndex> </kuler:swatch> <kuler:swatch> <kuler:swatchHexColor>A8CA65</kuler:swatchHexColor> <kuler:swatchColorMode>rgb</kuler:swatchColorMode> <kuler:swatchChannel1>0.659722</kuler:swatchChannel1> <kuler:swatchChannel2>0.791667</kuler:swatchChannel2> <kuler:swatchChannel3>0.395833</kuler:swatchChannel3> <kuler:swatchChannel4>0.0</kuler:swatchChannel4> <kuler:swatchIndex>2</kuler:swatchIndex> </kuler:swatch> <kuler:swatch> <kuler:swatchHexColor>E8E5B0</kuler:swatchHexColor> <kuler:swatchColorMode>rgb</kuler:swatchColorMode> <kuler:swatchChannel1>0.91</kuler:swatchChannel1> <kuler:swatchChannel2>0.898047</kuler:swatchChannel2> <kuler:swatchChannel3>0.688705</kuler:swatchChannel3> <kuler:swatchChannel4>0.0</kuler:swatchChannel4> <kuler:swatchIndex>3</kuler:swatchIndex> </kuler:swatch> <kuler:swatch> <kuler:swatchHexColor>419184</kuler:swatchHexColor> <kuler:swatchColorMode>rgb</kuler:swatchColorMode> <kuler:swatchChannel1>0.254901</kuler:swatchChannel1> <kuler:swatchChannel2>0.57</kuler:swatchChannel2> <kuler:swatchChannel3>0.519034</kuler:swatchChannel3> <kuler:swatchChannel4>0.0</kuler:swatchChannel4> <kuler:swatchIndex>4</kuler:swatchIndex> </kuler:swatch> </kuler:themeSwatches> Tue, 30 Mar 2010 11:27:12 PST So if I do a findall on say each item's description, I get that back fine. But the minute I try to retrieve anything with a : in the nodename I get Exception Type: KeyError Exception Value: ':' So this works from elementtree.ElementTree import Element, SubElement, dump, parse def xml(): kulerurl = 'http://kuler-api.adobe.com/rss/get.cfm?listType=popular&startIndex=0&itemsPerPage=5&timeSpan=30&key=mykey' rss = parse(urllib.urlopen(kulerurl)).getroot() for element in rss.findall('channel/item'): print(element.findtext('description')) dump (rss) but this doesn't def xml(): kulerurl = 'http://kuler-api.adobe.com/rss/get.cfm?listType=popular&startIndex=0&itemsPerPage=5&timeSpan=30&key=mykey' rss = parse(urllib.urlopen(kulerurl)).getroot() for element in rss.findall('channel/item/kuler:themeItem'): print(element.findtext('kuler:themeID')) dump (rss) I'm sure it's something simple if anyone could point me to what I'm doing wrong here I'd be most grateful thanks Kieran

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  • Merging elements inside a xml.etree.ElementTree

    - by theAlse
    I have a huge test data like the one provided below (and yes I have no control over this data). Each line is actually 6 parts and I need to generate an XML based on this data. Nav;Basic;Dest;Smoke;No;Yes; Nav;Dest;Recent;Regg;No;Yes; Nav;Dest;Favourites;Regg;No;Yes; ... Nav;Dest using on board;By POI;Smoke;No;Yes; Nav;Dest using on board;Other;Regg;No;Yes; The first 3 elements on each line denotes "test suites"-XML element and the last 3 element should create a "test case"-XML element. I have successfully converted it into a XML using the following code: # testsuite (root) testsuite = ET.Element('testsuite') testsuite.set("name", "Tests") def _create_testcase_tag(elem): global testsuite level1, level2, level3, elem4, elem5, elem6 = elem # -- testsuite (level1) testsuite_level1 = ET.SubElement(testsuite, "testsuite") testsuite_level1.set("name", level1) # -- testsuite (level2) testsuite_level2 = ET.SubElement(testsuite_level1, "testsuite") testsuite_level2.set("name", level2) # -- testsuite (level3) testsuite_level2 = ET.SubElement(testsuite_level2, "testsuite") testsuite_level2.set("name", level3) # -- testcase testcase = ET.SubElement(testsuite_level2, "testcase") testcase.set("name", "TBD") summary = ET.SubElement(testcase, "summary") summary.text = "Test Type= %s, Automated= %s, Available=%s" %(elem4, elem5, elem6) with open(input_file) as in_file: for line_number, a_line in enumerate(in_file): try: parameters = a_line.split(';') if len(parameters) >= 6: level1 = parameters[0].strip() level2 = parameters[1].strip() level3 = parameters[2].strip() elem4 = parameters[3].strip() elem5 = parameters[4].strip() elem6 = parameters[5].strip() lines_as_list.append((level1, level2, level3, elem4, elem5, elem6)) except ValueError: pass lines_as_list.sort() for elem in lines_as_list: _create_testcase_tag(elem) output_xml = ET.ElementTree(testsuite) ET.ElementTree.write(output_xml, output_file, xml_declaration=True, encoding="UTF-8") The above code generates an XML like this: <testsuite name="Tests"> <testsuite name="Nav"> <testsuite name="Basic navigation"> <testsuite name="Set destination"> <testcase name="TBD"> <summary>Test Type= Smoke test Automated= No, Available=Yes</summary> </testcase> </testsuite> </testsuite> </testsuite> <testsuite name="Nav"> <testsuite name="Set destination"> <testsuite name="Recent"> <testcase name="TBD"> <summary> Test Type= Reggression test Automated= No, Available=Yes </summary> </testcase> </testsuite> </testsuite> </testsuite> </testsuite> ... This is all correct, but as you can see I have created a whole tree for each line and that is not what I need. I need to combine e.g. all testsuite with the same name into one testsuite and also perform that recursively. So the XML looks like this instead: <testsuite name="Tests"> <testsuite name="Nav"> <testsuite name="Basic navigation"> <testsuite name="Set destination"> <testcase name="TBD"> <summary>Test Type= Smoke test Automated= No, Available=Yes</summary> </testcase> </testsuite> <testsuite name="Recent"> <testcase name="TBD"> <summary> Test Type= Reggression test Automated= No, Available=Yes </summary> </testcase> </testsuite> </testsuite> </testsuite> </testsuite> I hope you can understand what I mean, but level1, level2 and level3 should be unique with testcases inside. How should I do this? Please do not suggest the use of any external libraries! I can not install new libraries in customer site. xml.etree.ElementTree is all I have. Thanks

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  • Can ElementTree be told to preserve the order of attributes?

    - by dmckee
    I've written a fairly simple filter in python using ElementTree to munge the contexts of some xml files. And it works, more or less. But it reorders the attributes of various tags, and I'd like it to not do that. Does anyone know a switch I can throw to make it keep them in specified order? Context for this I'm working with and on a particle physics tool that has a complex, but oddly limited configuration system based on xml files. Among the many things setup that way are the paths to various static data files. These paths are hardcoded into the existing xml and there are no facilities for setting or varying them based on environment variables, and in our local installation they are necessarily in a different place. This isn't a disaster because the combined source- and build-control tool we're using allows us to shadow certain files with local copies. But even thought the data fields are static the xml isn't, so I've written a script for fixing the paths, but with the attribute rearrangement diffs between the local and master versions are harder to read than necessary. This is my first time taking ElementTree for a spin (and only my fifth or sixth python project) so maybe I'm just doing it wrong. Abstracted for simplicity the code looks like this: tree = elementtree.ElementTree.parse(inputfile) i = tree.getiterator() for e in i: e.text = filter(e.text) tree.write(outputfile) Reasonable or dumb? Related links: How can I get the order of an element attribute list using Python xml.sax? Preserve order of attributes when modifying with minidom

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  • Passing around an ElementTree

    - by PulpFiction
    Hello. In my program, I need to make use of an ElementTree object in various functions in my program. More specifically, I am doing this: tree = etree.parse('somefile.xml') I am passing this tree around in my program. I was wondering whether this is a good approach, or can I do this: Create a global tree (I come from a C++ background and I know global is bad) Create the tree again wherever required. Or is my approach ok?

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  • Repeatedly querying xml using python

    - by Jack
    I have some xml documents I need to run queries on. I've created some python scripts (using ElementTree) to do this, since I'm vaguely familiar with using it. The way it works is I run the scripts several times with different arguments, depending on what I want to find out. These files can be relatively large (10MB+) and so it takes rather a long time to parse them. On my system, just running: tree = ElementTree.parse(document) takes around 30 seconds, with a subsequent findall query only adding around a second to that. Seeing as the way I'm doing this requires me to repeatedly parse the file, I was wondering if there was some sort of caching mechanism I can use so that the ElementTree.parse computation can be reduced on subsequent queries. I realise the smart thing to do here may be to try and batch as many queries as possible together in the python script, but I was hoping there might be another way. Thanks.

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  • Python + Expat: Error on &#0; entities

    - by clacke
    I have written a small function, which uses ElementTree and xpath to extract the text contents of certain elements in an xml file: #!/usr/bin/env python2.5 import doctest from xml.etree import ElementTree from StringIO import StringIO def parse_xml_etree(sin, xpath): """ Takes as input a stream containing XML and an XPath expression. Applies the XPath expression to the XML and returns a generator yielding the text contents of each element returned. >>> parse_xml_etree( ... StringIO('<test><elem1>one</elem1><elem2>two</elem2></test>'), ... '//elem1').next() 'one' >>> parse_xml_etree( ... StringIO('<test><elem1>one</elem1><elem2>two</elem2></test>'), ... '//elem2').next() 'two' >>> parse_xml_etree( ... StringIO('<test><null>&#0;</null><elem3>three</elem3></test>'), ... '//elem2').next() 'three' """ tree = ElementTree.parse(sin) for element in tree.findall(xpath): yield element.text if __name__ == '__main__': doctest.testmod(verbose=True) The third test fails with the following exception: ExpatError: reference to invalid character number: line 1, column 13 Is the � entity illegal XML? Regardless whether it is or not, the files I want to parse contain it, and I need some way to parse them. Any suggestions for another parser than Expat, or settings for Expat, that would allow me to do that?

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  • Can't parse XML effectively using Python

    - by Harshit Sharma
    import urllib import xml.etree.ElementTree as ET def getWeather(city): #create google weather api url url = "http://www.google.com/ig/api?weather=" + urllib.quote(city) try: # open google weather api url f = urllib.urlopen(url) except: # if there was an error opening the url, return return "Error opening url" # read contents to a string s = f.read() tree=ET.parse(s) current= tree.find("current_condition/condition") condition_data = current.get("data") weather = condition_data if weather == "<?xml version=": return "Invalid city" #return the weather condition #return weather def main(): while True: city = raw_input("Give me a city: ") weather = getWeather(city) print(weather) if __name__ == "__main__": main() gives error , I actually wanted to find values from google weather xml site tags

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  • SyntaxError using gdata-python-client to access Google Book Search Data API

    - by isbadawi
    >>> import gdata.books.service >>> service = gdata.books.service.BookService() >>> results = service.search_by_keyword(isbn='0434003484') Traceback (most recent call last): File "<pyshell#4>", line 1, in <module> results = service.search_by_keyword(isbn='0434003484') ... snip ... File "C:\Python26\lib\site-packages\atom\__init__.py", line 127, in CreateClassFromXMLString tree = ElementTree.fromstring(xml_string) File "<string>", line 85, in XML SyntaxError: syntax error: line 1, column 0 This is a minimal example -- in particular, the book service unit tests included in the package also fail with the exact same error. I've looked at the wiki and open issue tickets on Google Code to no avail (and this seems to me more apt to be a silly error on my end rather than a problem with the library). I'm not sure how to interpret the error message. If it matters, I'm using python 2.6.5.

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  • How to obtain the root of a tree without parsing the entire file?

    - by Matt.
    I'm making an xml parser to parse xml reports from different tools, and each tool generates different reports with different tags. For example: Arachni generates an xml report with <arachni_report></arachni_report> as tree root tag. nmap generates an xml report with <nmaprun></nmaprun> as tree root tag. I'm trying not to parse the entire file unless it's a valid report from any of the tools I want. First thing I thought to use was ElementTree, parse the entire xml file (supposing it contains valid xml), and then check based on the tree root if the report belongs to Arachni or nmap. I'm currently using cElementTree, and as far as I know getroot() is not an option here, but my goal is to make this parser to operate with recognized files only, without parsing unnecessary files. By the way, I'm Still learning about xml parsing, thanks in advance.

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  • Python ImportError when executing 'import.py', but not when executing 'python import.py'

    - by Martin Del Vecchio
    I am running Cygwin Python version 2.5.2. I have a three-line source file, called import.py: #!/usr/bin/python import xml.etree.ElementTree as ET print "Success!" When I execute "python import.py", it works: C:\Temp>python import.py Success! When I run the python interpreter and type the commands, it works: C:\Temp>python Python 2.5.2 (r252:60911, Dec 2 2008, 09:26:14) [GCC 3.4.4 (cygming special, gdc 0.12, using dmd 0.125)] on cygwin Type "help", "copyright", "credits" or "license" for more information. >>> #!/usr/bin/python ... import xml.etree.ElementTree as ET >>> print "Success!" Success! >>> But when I execute "import.py', it does not work: C:\Temp>which python /usr/bin/python C:\Temp>import.py Traceback (most recent call last): File "C:\Temp\import.py", line 2, in ? import xml.etree.ElementTree as ET ImportError: No module named etree.ElementTree When I remove the first line (#!/usr/bin/python), I get the same error. I need that line in there, though, for when this script runs on Linux. And it works fine on Linux. Any ideas? Thanks.

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  • Should I use a class in this: Reading a XML file using lxml.

    - by PulpFiction
    Hi everyone. This question is in continuation to my previous question, in which I asked about passing around an ElementTree. I need to read the XML files only and to solve this, I decided to create a global ElementTree and then parse it wherever required. My question is: Is this an acceptable practice? I heard global variables are bad. If I don't make it global, I was suggested to make a class. But do I really need to create a class? What benefits would I have from that approach. Note that I would be handling only one ElementTree instance per run, the operations are read-only. If I don't use a class, how and where do I declare that ElementTree so that it available globally? (Note that I would be importing this module) Please answer this question in the respect that I am a beginner to development, and at this stage I can't figure out whether to use a class or just go with the functional style programming approach.

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  • How to update the text of a tag in XML using Elementree

    - by Christopher
    Using elementree, the easiest way to read the text of a tag is to do the following: import elementtree.ElementTree as ET sKeyMap = ET.parse("KeyMaps/KeyMap_Checklist.xml") host = sKeyMap.findtext("/BrowserInformation/BrowserSetup/host") Now I want to update the text in the same file, hopefully without having to re-write it with something easy like: host = "4444" sKeyMap.replacetext("/BrowserInformation/BrowserSetup/host") Any ideas? Thx in advance Christopher

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  • Yahoo BOSS Python Library, ExpatError

    - by Wraith
    I tried to install the Yahoo BOSS mashup framework, but am having trouble running the examples provided. Examples 1, 2, 5, and 6 work, but 3 & 4 give Expat errors. Here is the output from ex3.py: gpython examples/ex3.py examples/ex3.py:33: Warning: 'as' will become a reserved keyword in Python 2.6 Traceback (most recent call last): File "examples/ex3.py", line 27, in <module> digg = db.select(name="dg", udf=titlef, url="http://digg.com/rss_search?search=google+android&area=dig&type=both&section=news") File "/usr/lib/python2.5/site-packages/yos/yql/db.py", line 214, in select tb = create(name, data=data, url=url, keep_standards_prefix=keep_standards_prefix) File "/usr/lib/python2.5/site-packages/yos/yql/db.py", line 201, in create return WebTable(name, d=rest.load(url), keep_standards_prefix=keep_standards_prefix) File "/usr/lib/python2.5/site-packages/yos/crawl/rest.py", line 38, in load return xml2dict.fromstring(dl) File "/usr/lib/python2.5/site-packages/yos/crawl/xml2dict.py", line 41, in fromstring t = ET.fromstring(s) File "/usr/lib/python2.5/xml/etree/ElementTree.py", line 963, in XML parser.feed(text) File "/usr/lib/python2.5/xml/etree/ElementTree.py", line 1245, in feed self._parser.Parse(data, 0) xml.parsers.expat.ExpatError: syntax error: line 1, column 0 It looks like both examples are failing when trying to query Digg.com. Here is the query that is constructed in ex3.py's code: diggf = lambda r: {"title": r["title"]["value"], "diggs": int(r["diggCount"]["value"])} digg = db.select(name="dg", udf=diggf, url="http://digg.com/rss_search?search=google+android&area=dig&type=both&section=news") Any help is appreciated. Thanks!

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  • Write xml file using lxml library in Python

    - by systempuntoout
    I'm using lxml to create an XML file from scratch; having a code like this: from lxml import etree root = etree.Element("root") root.set("interesting", "somewhat") child1 = etree.SubElement(root, "test") How do i write root Element object to an xml file using write() method of ElementTree class?

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  • Write xml file with lxml

    - by systempuntoout
    Having a code like this: from lxml import etree root = etree.Element("root") root.set("interesting", "somewhat") child1 = etree.SubElement(root, "test") How do i write root Element object to an xml file using write() method of ElementTree class?

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  • Python script to remove all comments from XML file

    - by Jennifer Greentree
    I am trying to build a python script that will take in an XML document and remove all of the comment blocks from it. I tried something along the lines of: tree = ElementTree() tree.parse(file) commentElements = tree.findall('//comment()') for element in commentElements: element.parentNode.remove(element) Doing this yields a weird error from python: "KeyError: '()' I know there are ways to easily edit the file using other methods ( like sed ), but I have to do it in a python script.

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  • Which Python XML library should I use?

    - by PulpFiction
    Hello. I am going to handle XML files for a project. I had earlier decided to use lxml but after reading the requirements, I think ElemenTree would be better for my purpose. The XML files that have to be processed are: Small in size. Typically < 10 KB. No namespaces. Simple XML structure. Given the small XML size, memory is not an issue. My only concern is fast parsing. What should I go with? Mostly I have seen people recommend lxml, but given my parsing requirements, do I really stand to benefit from it or would ElementTree serve my purpose better?

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  • Close a tag with no text in lxml

    - by PulpFiction
    I am trying to output a XML file using Python and lxml However, I notice one thing that if a tag has no text, it does not close itself. An example of this would be: root = etree.Element('document') rootTree = etree.ElementTree(root) firstChild = etree.SubElement(root, 'test') The output of this is: <document> <test/> </document I want the output to be: <document> <test> </test> </document> So basically I want to close a tag which has no text, but is used to the attribute value. How do I do that? And also, what is such a tag called? I would have Googled it, but I don't know how to search for it.

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  • Help with Python structure in *nixes.

    - by user198553
    I came from a Windows background whern it comes to development environments. I'm used to run .exe's from everything I need to run and just forget. I usually code in php, javascript, css, html and python. Now, I have to use Linux at my work, in a non changeable Ubuntu 8.04, with permissions to upgrade my system using company's repositories only. I need to install Python 2.4.3 to start coding in an old legacy system. I had Python 2.5. I downloaded Python 2.4.3 tarballs, ran ./configure make and such. Everything worked out, but now the "default" installation is my system is Python2.4 instead of of Python2.5. I want help from you to change it back, and if possible, some material to read about symlinks, multiple Python installations, virtualenvs and such: everything I need to know before installing/upgrading Python modules. I installed for example the ElementTree package and don't even know in which Python installation it was installed. Thanks in advance!

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  • Error in {% markdown %} filter in Django Nonrel

    - by Robert Smith
    I'm having trouble using Markdown in Django Nonrel. I followed this instructions (added 'django.contrib.markup' to INSTALLED_APPS, include {% load markup %} in the template and use |markdown filter after installing python-markdown) but I get the following error: Error in {% markdown %} filter: The Python markdown library isn't installed. In this line: /path/to/project/django/contrib/markup/templatetags/markup.py in markdown they will be silently ignored. """ try: import markdown except ImportError: if settings.DEBUG: raise template.TemplateSyntaxError("Error in {% markdown %} filter: The Python markdown library isn't installed.") ... return force_unicode(value) else: # markdown.version was first added in 1.6b. The only version of markdown # to fully support extensions before 1.6b was the shortlived 1.6a. if hasattr(markdown, 'version'): extensions = [e for e in arg.split(",") if e] It seems obvious that import markdown is causing the problem but when I run: $ python manage.py shell >>> import elementtree >>> import markdown everthing works alright. Running Markdown 2.0.3, Django 1.3.1, Python 2.7. UPDATE: I thought maybe this was an issue related to permissions, so I changed my project via chmod 777 -R, but it didn't work. Ideas? Thanks!

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