How can I do a 'where' clause in Linux shell?

Posted by Hoa on Stack Overflow See other posts from Stack Overflow or by Hoa
Published on 2012-03-24T08:38:35Z Indexed on 2012/03/24 11:30 UTC
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linux

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bash

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shell

I have a CSV file and I would like to filter all the lines where the 19th column has two or more characters. I know the individual pieces but can't figure out how to glue them together. First I have to cat the file. The following prints the 19th column

awk -F "," '{print $19}' file.txt

awk also has length and ifs

And I know it all has to be glued together using pipes. I'm just getting stuck at the exact syntax since I have not done much bash programming before.

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