How can I do a 'where' clause in Linux shell?
- by Hoa
I have a CSV file and I would like to filter all the lines where the 19th column has two or more characters. I know the individual pieces but can't figure out how to glue them together. First I have to cat the file. The following prints the 19th column
awk -F "," '{print $19}' file.txt
awk also has length and ifs
And I know it all has to be…