JSON Returning Null in PHP
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by
kira423
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Published on 2012-10-13T03:24:40Z
Indexed on
2012/10/13
3:37 UTC
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Here is the two scripts I have
Script 1:
if(sha1($json+$secret) == $_POST['signature']) {
$conversion_id = md5(($obj['amount']));
echo "OK";
echo $conversion_id;
mysql_query("INSERT INTO completed (`id`,`uid`,`completedid`) VALUES ('','".$obj['uid']."','".$conversion_id."')");
} else {
}
?>
Script 2:
<?
$json = $_POST['payload'];
$secret = "78f12668216b562a79d46b170dc59f695070e532";
$obj = json_decode($json);
if(sha1($json+$secret) == $_POST['signature']) {
print "OK";
} else {
}
?>
The problem here is that it is returning all NULL values. I am not an expert with JSON so I have no idea what is going on here. I really have no way of testing it because the information is coming from an outside website sending information such as this:
{
payload: {
uid: "900af657a65e",
amount: 50,
adjusted_amount: 25
},
signature: "4dd0f5da77ecaf88628967bbd91d9506"
}
The site allows me to test the script, but because json_decode is providing NULL values it will not get through the signature block.
Is there a way I can test it myself? Or is there a simple error in this script that I may have just looked over?
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