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• Installing mysqlnd for php 5.4.9 on CentOs 6.3

  - by kira423

  Okay let me get straight to the point, I am a complete noob, and have never done stuff like this at all, I have read tutorial after tuorial but I cant get anything to work. When I tried to install the rpm file I got this error rpm -Uvh ftp://ftp.pbone.net/mirror/rpms.famillecollet.com/enterprise/6/test/x86_64/php-mysqlnd-5.4.9-1.el6.remi.x86_64.rpm Retrieving ftp://ftp.pbone.net/mirror/rpms.famillecollet.com/enterprise/6/test/x86_64/php-mysqlnd-5.4.9-1.el6.remi.x86_64.rpm warning: /var/tmp/rpm-tmp.ez4vvd: Header V3 DSA/SHA1 Signature, key ID 00f97f56: NOKEY error: Failed dependencies: php-pdo(x86-64) = 5.4.9-1.el6.remi is needed by php-mysqlnd-5.4.9-1.el6.remi.x86_64 so I tried installing that rpm file and got this error rpm -ivh ftp://ftp.pbone.net/mirror/rrpms.famillecollet.com/enterprise/6/test/x86_64/php-pdo-5.4.6-1.el6.remi.x86_64.rpm Retrieving ftp://ftp.pbone.net/mirror/rrpms.famillecollet.com/enterprise/6/test/x86_64/php-pdo-5.4.6-1.el6.remi.x86_64.rpm curl: (9) Server denied you to change to the given directory error: skipping ftp://ftp.pbone.net/mirror/rrpms.famillecollet.com/enterprise/6/test/x86_64/php-pdo-5.4.6-1.el6.remi.x86_64.rpm - transfer failed I used the ftp links because I have no idea how else to get them to the server. I think I am getting overly frustrated with this, but I have to get this driver installed for any of my scripts to function correctly. Any help would be greatly appreciated!

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• Having trouble adding jquery to charisma

  - by kira423

  I am trying to add some jquery to this Charisma admin panel and have been having nothing but trouble. I am trying to add it to the charisma.js file. This is what I am adding // add multiple select / deselect functionality $("#selectall").click(function () { $('.checkbox').attr('checked', this.checked); }); // if all checkbox are selected, check the selectall checkbox // and viceversa $(".checkbox").click(function(){ if($(".checkbox").length == $(".checkbox:checked").length) { $("#selectall").attr("checked", "checked"); } else { $("#selectall").removeAttr("checked"); } }); I have tried this code wrapped in the anonymous $(function(){ as well as without, and I have inserted it into both $(document).ready(function(){ and docReady() as well as in the head of my code but I am not really "trained" on jquery so I am a bit lost as to what I am doing wrong. My class and div tags are correct for the code, as I have checked them several times for misspellings. I am not sure what I am doing wrong. Is there a better "check" all code I can use here, or am I just putting this all in the wrong place? UPDATE: I think the actual code may be working, I cannot tell, after I click the select all box it seems that I have to click the other boxes 3 times to get the check mark back into the box, so it seems like it is having trouble actually showing that the box is marked. This may be a problem with styling, but I don't know how to correct it.

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• Adding to database with multiple text boxes

  - by kira423

  What I am trying to do with this script is allow users to update a url for their websites, and since each user isn't going to have the same amount of websites is is hard for me to just add $_POST['website'] for each of these. Here is the script <?php include("config.php"); include("header.php"); include("functions.php"); if(!isset($_SESSION['username']) && !isset($_SESSION['password'])){ header("Location: pubs.php"); } $getmember = mysql_query("SELECT * FROM `publishers` WHERE username = '".$_SESSION['username']."'"); $info = mysql_fetch_array($getmember); $getsites = mysql_query("SELECT * FROM `websites` WHERE publisher = '".$info['username']."'"); $postback = $_POST['website']; $webname = $_POST['webid']; if($_POST['submit']){ var_dump( $_POST['website'] ); $update = mysql_query("UPDATE `websites` SET `postback` = '$postback' WHERE name = '$webname'"); } print" <div id='center'> <span id='tools_lander'><a href='export.php'>Export Campaigns</a></span> <div id='calendar_holder'> <h3>Please define a postback for each of your websites below. The following variables should be used when creating your postback.<br /> cid = Campaign ID<br /> sid = Sub ID<br /> rate = Campaign Rate<br /> status = Status of Lead. 1 means payable 2 mean reversed<br /> A sample postback URL would be <br /> http://www.example.com/postback.php?cid=#cid&sid=#sid&rate=#rate&status=#status</h3> <table class='balances' align='center'> <form method='POST' action=''>"; while($website = mysql_fetch_array($getsites)){ print" <tr> <input type ='hidden' name='webid' value='".$website['id']."' /> <td style='font-weight:bold;'>".$website['name']."'s Postback:</td> <td><input type='text' style='width:400px;' name='website[]' value='".$website['postback']."' /></td> </tr>"; } print" <td style='float:right;position:relative;left:150px;'><input type='submit' name='submit' style='font-size:15px;height:30px;width:100px;' value='Submit' /></td> </form> </table> </div>"; include("footer.php"); ?> What I am attempting to do insert the what is inputted in the text boxes to their corresponding websites, and I cannot think of any other way to do it, and this obviously does not works and returns a notice stating Array to string conversion If there is a more logical way to do this please let me know.

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• JSON Returning Null in PHP

  - by kira423

  Here is the two scripts I have Script 1: if(sha1($json+$secret) == $_POST['signature']) { $conversion_id = md5(($obj['amount'])); echo "OK"; echo $conversion_id; mysql_query("INSERT INTO completed (`id`,`uid`,`completedid`) VALUES ('','".$obj['uid']."','".$conversion_id."')"); } else { } ?> Script 2: <? $json = $_POST['payload']; $secret = "78f12668216b562a79d46b170dc59f695070e532"; $obj = json_decode($json); if(sha1($json+$secret) == $_POST['signature']) { print "OK"; } else { } ?> The problem here is that it is returning all NULL values. I am not an expert with JSON so I have no idea what is going on here. I really have no way of testing it because the information is coming from an outside website sending information such as this: { payload: { uid: "900af657a65e", amount: 50, adjusted_amount: 25 }, signature: "4dd0f5da77ecaf88628967bbd91d9506" } The site allows me to test the script, but because json_decode is providing NULL values it will not get through the signature block. Is there a way I can test it myself? Or is there a simple error in this script that I may have just looked over?

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