Java Socket - how to catch Exception of BufferedReader.readline()
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Hasan Tahsin
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Published on 2012-11-28T05:01:58Z
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2012/11/28
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I have a Thread (let's say T1) which reads data from socket:
public void run() {
while (running) {
try {
BufferedReader reader = new BufferedReader( new InputStreamReader(socket.getInputStream()) );
String input = reader.readLine();
} catch (IOException e) {
e.printStackTrace();
}
}
}
Another Thread (lets say T2) try to finish the program in one of its method. Therefore T2 does the following:
T1.running = false;
socket.close();
Here is this scenario for which i couldn't find a solution:
- T1 is active and waiting for some input to read i.e. blocking.
- context switching
- T2 is active and sets running to false, closes the socket
- context switching
- because T1 was blocking and T2 closed the socket, T1 throws an Exception. What i want is to catch this SocketException. i can't put a try/catch(SocketException) in T1.run(). So how can i catch it in T1's running-method? If it's not possible to catch it in T1's running, then how can i catch it elsewhere?
PS: "Another question about the Thread Debugging"
Normally when i debug the code step by step, i lose the 'active running line' on a context switch. Let's say i'm in line 20 of T1, context switch happens, let's assume the program continues from the 30.line of T2, but the debugger does not go/show to the 30.line of T2, instead the 'active running line' vanishes. So i lose the control over the code. I use Eclipse for Java and Visual Studio for C#. So what is the best way to track the code while debugging on a context switch ?
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