C++: call original definition of operator equals
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Luis Daniel
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Published on 2013-10-21T03:45:26Z
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2013/10/21
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I am overloading the operator equals (==) as show bellow:
#include <string>
#include <algorithm>
bool operator == (std::string str1, std::string str2) {
std::transform(str1.begin(), str1.end(), str1.begin(), ::tolower);
std::transform(str2.begin(), str2.end(), str2.begin(), ::tolower);
return (str1 == str2);
}
but, the problem appear on line return (str1 == str2), because operator == is called recursively. So, how can I call the original definition for operator equals (not the overloaded) ?
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