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• Who are Alice and Bob? [closed]

  - by froadie

  I did search for this on SO, as I assumed someone must have asked it before, similar to the Foo-Bar questions. But I haven't found it, so I'm asking it myself. Is it just me, or are the names Alice and Bob used often in connection to programming, emailing, encoding...? Where did these names come from? What is their relation to computers/programming?

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• Alice In Wonderland: Good, but not Great

  - by Theo Moore

  We went to see Alice In Wonderland today. We both like Tim Burton a lot (the stranger the better) and like Johnny Depp very well also. After seeing all the previews and such, we were fired up to see this film. Honestly, I thought it was good but not great. I was prepared to be wow-ed, but I wasn't. Perhaps I expected too much. I did like it, but I'll not own it nor would I expect to see it again...unless someone I know decides they want to see it. I was about to say something to reassure you that I wasn't going to provide any spoilers but two things occurred to me: one, I never give spoilers and two, why worry about spoilers for a film that so closely follows a book? My comments about the film are hard to describe, but the basic gist is that it doesn't really feel like it..."works" to me. I can't get any more specific than that, much as I'd like to do so. Something about it seems sort of disjointed and not in that Alice way you'd expect. My only specific comment is that I didn't like the actor who plays Alice very well. She was very flat and just didn't sell he character to me. She seemed a bit, well, plastic. Depp was as good as you'd expect him to be, I am happy to say. Obviously Lewis Carroll couldn't have imagined this made into film, but I can't help thinking that he'd see this and say that Depp was the perfect Mad Hatter. So, I'd definitely recommend seeing it (we saw it in 3D which was cool, but not really necessary) at least once, but don't be surprised if you're kinda meh afterwards.

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• Friday Fun: Daisy in Wonderland

  - by Asian Angel

  Are you suffering the effects of another grinding week at work? Then it is time for you to relax for a little bit and have some fun! In this week’s game you get to engage in inter-dimensional travel as you help Daisy try to return home Latest Features How-To Geek ETC How To Create Your Own Custom ASCII Art from Any Image How To Process Camera Raw Without Paying for Adobe Photoshop How Do You Block Annoying Text Message (SMS) Spam? How to Use and Master the Notoriously Difficult Pen Tool in Photoshop HTG Explains: What Are the Differences Between All Those Audio Formats? How To Use Layer Masks and Vector Masks to Remove Complex Backgrounds in Photoshop Bring Summer Back to Your Desktop with the LandscapeTheme for Chrome and Iron The Prospector – Home Dash Extension Creates a Whole New Browsing Experience in Firefox KinEmote Links Kinect to Windows Why Nobody Reads Web Site Privacy Policies [Infographic] Asian Temple in the Snow Wallpaper 10 Weird Gaming Records from the Guinness Book

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• Using the public ssh key from local machine to access two remote users [closed]

  - by Nick

  I have an new Ubuntu (Hardy 8.04) server; it has two users, Alice and Bob. Alice is listed in sudoers. I appended my public ssh key (my local machine's public key local/Users/nick/.ssh/id_rsa.pub) to authorized_keys in remote_server/home/Alice/.ssh/authorized_keys, changed the permissions on Alice/.ssh/ to 700 and Alice/.ssh/authorized_keys to 600, and both the file and folder are owned my Alice. Then added I Alice to sshd_config (AllowUsers Alice). This works and I can login into Alice: ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from 123.456.789.00 I then copied the authorized_keys file remote_server/home/Alice/.ssh/authorized_keys to remote_server/home/Bob/.shh/authorized_keys and changed the permissions and ownership and added Bob to AllowUsers in sshd_config (AllowUsers Alice Bob). Now when I try to login to Bob it will not authenticate the same public key. ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works?

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• learning programing language concepts

  - by user309322

  As a student teacher i am very interested in how effective "mini languages" such as Scratch, Logo, Alice and Lego mindstorms are in teaching the pupil the core concepts of programing such as variables, fuctions and loops. Is one "mini language" better than another for teaching these basic core concepts ?

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• Are there Java libraries to do drag and drop

  - by Kenston

  Hello. Are there open source libraries for Java to make implementation of drag and drop easier? I plan to make something like the one shown below: The program is Alice, where you can drag some elements on the left and nest them to the right. It's open source, but they did not use any libraries I think. I'm wondering if we anyone know of open source frameworks that work this way, or assist in doing complex drag and drops.

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• Do I have to do anything for file ACLs to work both before and after I reformat a computer?

  - by Zian Choy

  Let's say that I have a computer running Windows Vista with 2 users: Alice and Bob. Alice is the admin and Bob is a normal user. They each have files in their respective My Documents folders and Bob is not allowed to view Alice's files and Alice has to jump through a UAC elevation to view Bob's. If Alice copies all the files on the computer to an external NTFS-formatted hard drive with the following 2 commands: robocopy "E:\Bob's Files" "C:\Users\Bob\My Documents" /MIR robocopy "E:\Alice's Files" "C:\Users\Alice\My Documents" /MIR And then reformats the hard drive, installs a fresh copy of Windows, and creates 2 users named Alice and Bob on the computer, then will everything in the first paragraph be true after Alice copies the files back onto the internal hard drive? Assume that when the files are copied back over, she logs in as Bob and then copies Bob's files and likewise with her own files. Possibly relevant: Alice and Bob also have passwords on their user accounts and they create new passwords after the computer is reformatted. The main post has been tweaked slightly to make the question clearer. Answers that predate April 2011 are referring to an earlier version of this post.

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• How to exploit Diffie-hellman to perform a man in the middle attack

  - by jfisk

  Im doing a project where Alice and Bob send each other messages using the Diffie-Hellman key-exchange. What is throwing me for a loop is how to incorporate the certificate they are using in this so i can obtain their secret messages. From what I understand about MIM attakcs, the MIM acts as an imposter as seen on this diagram: Below are the details for my project. I understand that they both have g and p agreed upon before communicating, but how would I be able to implement this with they both having a certificate to verify their signatures? Alice prepares ?signA(NA, Bob), pkA, certA? where signA is the digital signature algorithm used by Alice, “Bob” is Bob’s name, pkA is the public-key of Alice which equals gx mod p encoded according to X.509 for a fixed g, p as specified in the Diffie-Hellman key- exchange and certA is the certificate of Alice that contains Alice’s public-key that verifies the signature; Finally, NA is a nonce (random string) that is 8 bytes long. Bob checks Alice's signature, and response with ?signB{NA,NB,Alice},pkB,certB?. Alice gets the message she checks her nonce NA and calculates the joint key based on pkA, pkB according to the Diffie-Hellman key exchange. Then Alice submits the message ?signA{NA,NB,Bob},EK(MA),certA? to Bob and Bobrespondswith?SignB{NA,NB,Alice},EK(MB),certB?. where MA and MB are their corresponding secret messages.

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• scp through ssh gateway connection

  - by zidarsk8

  so my network layou is something like this (I don't have enough reputation to post images so here's the link) http://i.imgur.com/OaD4i.png now Alice has access to SSH gateway (just gateway from now on) with: ssh [email protected] and the authorized keys file on the gateway looks like this #/home/Alice/.ssh/authorized_keys command="ssh -t alice@web" ssh-rsa ABCD...E== alice@somehost so when Alice trys to connect to the Gateway with her private key, she actually gets connected to the Web server (the gateway pc can make a connection to the web server with a passwordless private key, so that stays transparent). The question 1) How can I set this up so that Alice will be able to scp things to web server too? 2) I know this makes a separete connection, but is there any way for this to work as a normal ssh so that even something like -R12345:localhost:22 would work?

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• P2P synchronization: can a player update fields of other players?

  - by CherryQu

  I know that synchronization is a huge topic, so I have minimized the problem to this example case. Let's say, Alice and Bob are playing a P2P game, fighting against each other. If Alice hits Bob, how should I do the network component to make Bob's HP decrease? I can think of two approaches: Alice perform a Bob.HP--, then send Bob's reduced HP to Bob. Alice send a "I just hit Bob" signal to Bob. Bob checks it, and reduce its own HP, then send his new HP to everyone including Alice. I think the second approach is better because I don't think a player in a P2P game should be able to modify other players' private fields. Otherwise cheating would be too easy, right? My philosophy is that in a P2P game especially, a player's attributes and all attributes of its belonging objects should only be updated by the player himself. However, I can't prove that this is right. Could someone give me some evidence? Thanks :)

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• Delegation of Solaris Zone Administration

  - by darrenm

  In Solaris 11 'Zone Delegation' is a built in feature. The Zones system now uses finegrained RBAC authorisations to allow delegation of management of distinct zones, rather than all zones which is what the 'Zone Management' RBAC profile did in Solaris 10.The data for this can be stored with the Zone or you could also create RBAC profiles (that can even be stored in NIS or LDAP) for granting access to specific lists of Zones to administrators.For example lets say we have zones named zoneA through zoneF and we have three admins alice, bob, carl.  We want to grant a subset of the zone management to each of them.We could do that either by adding the admin resource to the appropriate zones via zonecfg(1M) or we could do something like this with RBAC data directly: First lets look at an example of storing the data with the zone. # zonecfg -z zoneA zonecfg:zoneA> add admin zonecfg:zoneA> set user=alice zonecfg:zoneA> set auths=manage zonecfg:zoneA> end zonecfg:zoneA> commit zonecfg:zoneA> exit Now lets look at the alternate method of storing this directly in the RBAC database, but we will show all our admins and zones for this example: # usermod -P +Zone Management -A +solaris.zone.manage/zoneA alice # usermod -A +solaris.zone.login/zoneB alice # usermod -P +Zone Management-A +solaris.zone.manage/zoneB bob # usermod -A +solaris.zone.manage/zoneC bob # usermod -P +Zone Management-A +solaris.zone.manage/zoneC carl # usermod -A +solaris.zone.manage/zoneD carl # usermod -A +solaris.zone.manage/zoneE carl # usermod -A +solaris.zone.manage/zoneF carl In the above alice can only manage zoneA, bob can manage zoneB and zoneC and carl can manage zoneC through zoneF.  The user alice can also login on the console to zoneB but she can't do the operations that require the solaris.zone.manage authorisation on it.Or if you have a large number of zones and/or admins or you just want to provide a layer of abstraction you can collect the authorisation lists into an RBAC profile and grant that to the admins, for example lets great an RBAC profile for the things that alice and carl can do. # profiles -p 'Zone Group 1' profiles:Zone Group 1> set desc="Zone Group 1" profiles:Zone Group 1> add profile="Zone Management" profiles:Zone Group 1> add auths=solaris.zone.manage/zoneA profiles:Zone Group 1> add auths=solaris.zone.login/zoneB profiles:Zone Group 1> commit profiles:Zone Group 1> exit # profiles -p 'Zone Group 3' profiles:Zone Group 1> set desc="Zone Group 3" profiles:Zone Group 1> add profile="Zone Management" profiles:Zone Group 1> add auths=solaris.zone.manage/zoneD profiles:Zone Group 1> add auths=solaris.zone.manage/zoneE profiles:Zone Group 1> add auths=solaris.zone.manage/zoneF profiles:Zone Group 1> commit profiles:Zone Group 1> exit Now instead of granting carl  and aliace the 'Zone Management' profile and the authorisations directly we can just give them the appropriate profile. # usermod -P +'Zone Group 3' carl # usermod -P +'Zone Group 1' alice If we wanted to store the profile data and the profiles granted to the users in LDAP just add '-S ldap' to the profiles and usermod commands. For a documentation overview see the description of the "admin" resource in zonecfg(1M), profiles(1) and usermod(1M)

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• stackoverflow is like the Wonderland, but what are the tags more astonishing?

  - by Steel Plume

  can You put a list of tags quite hidden but more astonishing than usual tagged software categories?

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• How do I share different files in a git repo with different people?

  - by David Faux

  In a single directory with a Git root folder, I have a bunch of files. I am working on one of those files, X.py, with my friend Alice. The other files I am working on with other people. I want Alice (and everyone else) to have access to X.py. I want Alice to only have access to X.py though. How can I achieve this with Git? Is there a way I can split a directory into two repos? That sounds rather cumbersome. Maybe I could add a remote repo that Alice can access containing X.py?

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• Looking for a function that will split profits/loss equally between 2 business partners.

  - by Hamish Grubijan

  This is not homework, for I am not a student. This is for my general curiosity. I apologize if I am reinventing the wheel here.The function I seek can be defined as follows (language agnostic): int getPercentageOfA(double moneyA, double workA, double moneyB, double workB) { // Perhaps you may assume that workA == 0 // Compute result return result; } Suppose Alice and Bob want to do business together ... such as ... selling used books. Alice is only interested in investing money in it and nothing else. Bob might invest some money, but he might have no $ available to invest. He will, however, put in the effort in finding a seller, a buyer, and doing maintenance. There are no tools, education, health insurance costs, or other expenses to consider. Both Alice and Bob wish to split the profits "equally" (A different weight like 40/60 for advanced users). Both are entrepreneurs, so they deal with low ROI/wage, and high income alike. There is no fixed wage, minimum wage, fixed ROI, or minimum ROI. They try to find the best deal possible, assume risks and go for it. Now, let's stick with the 50/50 model. If Alice invests $100, Bob invests work, and they will end up with a profit (or loss) of $60, they will split it equally - either both get $30 for their efforts/investments, or Bob ends up owing $30 to Alice. A second possibility: Both Alice and Bob invest 100, then Bob does all the work, and they end up splitting $60 profit. It looks like Alice should get only $15, because $30 of that profit came from Bob's investment and Bob's effort, so Alice shall have none of it, and the other $30 is to be split 50/50. Both of the examples above are trivial even when A and B want to split it 35/65 or what have you. Now it gets more complicated: What if Alice invests $70, and Bob invests $30 + does all of the work. It appears simple: (70,30) = (30,30) + (40,0) ... but, if only we knew how to weigh the two parts relative to each other. Another complicated (I think) example: what if Alice and Bob invest $70 and $30 respectively, and also put in an equal amount of work? I have a few data points: When A and B put in the same amount of work and the same $ - 50/50. When A puts in 100% of the money, and B does 100% of the work - 50/50. When A does all of the work and puts in all of the money - 100 for A / 0 for B (and vice-versa). When A puts in 50% of the money, and B puts in 50% of the money as well as does all of the work - 25 for A, and 75 for B (and vice-versa). If I fix things such that always workA = 0%, workB = 100% of the total work, then getPercentageOfA becomes a function: height z given x and y. The question is - how do you extrapolate this function between these several points? What is this function? If you can cover the cases when workA does not have to be 0% of the total work, and when investment vs work is split as 85/15 or using some other model, then what would the new function be?

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• Got a table of people, who I want to link to each other, many-to-many, with the links being bidirect

  - by dflock

  Imagine you live in very simplified example land - and imagine that you've got a table of people in your MySQL database: create table person ( person_id int, name text ) select * from person; +-------------------------------+ | person_id | name | +-------------------------------+ | 1 | Alice | | 2 | Bob | | 3 | Carol | +-------------------------------+ and these people need to collaborate/work together, so you've got a link table which links one person record to another: create table person__person ( person__person_id int, person_id int, other_person_id int ) This setup means that links between people are uni-directional - i.e. Alice can link to Bob, without Bob linking to Alice and, even worse, Alice can link to Bob and Bob can link to Alice at the same time, in two separate link records. As these links represent working relationships, in the real world they're all two-way mutual relationships. The following are all possible in this setup: select * from person__person; +---------------------+-----------+--------------------+ | person__person_id | person_id | other_person_id | +---------------------+-----------+--------------------+ | 1 | 1 | 2 | | 2 | 2 | 1 | | 3 | 2 | 2 | | 4 | 3 | 1 | +---------------------+-----------+--------------------+ For example, with person__person_id = 4 above, when you view Carol's (person_id = 3) profile, you should see a relationship with Alice (person_id = 1) and when you view Alice's profile, you should see a relationship with Carol, even though the link goes the other way. I realize that I can do union and distinct queries and whatnot to present the relationships as mutual in the UI, but is there a better way? I've got a feeling that there is a better way, one where this issue would neatly melt away by setting up the database properly, but I can't see it. Anyone got a better idea?

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• Which server software and configuration to retrieve from multiple POP servers, routing by address to correct user

  - by rolinger

  I am setting up a small email server on a Debian machine, which needs to pick up mail from a variety of POP servers and figure out who to send it to from the address, but I'm not clear what software will do what I need, although it seems like a very simple question! For example, I have 2 users, Alice and Bob. Any email to [email protected] ([email protected] etc) should go to Alice, all other mail to domain.example.com should go to Bob. Any email to [email protected] should go to Bob, and [email protected] should go to Alice Anything to *@bobs.place.com should go to Bob And so on... The idea is to pull together a load of mail addresses that have built up over the years and present them all as a single mailbox for Bob and another one for Alice. I'm expecting something like Postfix + Dovecot + Amavis + Spamassassin + Squirrelmail to fit the bill, but I'm not sure where the above comes in, can Postfix deal with it as a set of defined regular expressions, or is it a job for Amavis, or something else entirely? Do I need fetchmail in this mix, or is its role now included in one of the other components above. I think of it as content-filtering, but everything I read about content-filtering is focussed on detecting spam rather than routing email.

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• Fossil gpg workflow for teams

  - by Alex_coder

  I'm learning fossil and trying to reproduce a workflow for two people modifying the same source code tree. So, Alice and Bob both have local repositories of some source code. Both have autosync off. Alice hacks some more, does some commits signing check-ins with her gpg key. This part is fine, as Alice I've managed to generate gpg keys, fossil asked me the key password when commiting. I'm also aware of gpg-agent but don't use it yet, because I'm trying to keep things as simple as possible for now. Now, at some point Bob pulls changes from Alice's fossil repo. How would he verify Alice's signed check-ins?

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• SQL Server: A Grouping question that's annoying me

  - by user366729

  I've been working with SQL Server for the better part of a decade, and this grouping (or partitioning, or ranking...I'm not sure what the answer is!) one has me stumped. Feels like it should be an easy one, too. I'll generalize my problem: Let's say I have 3 employees (don't worry about them quitting or anything...there's always 3), and I keep up with how I distribute their salaries on a monthly basis. Month Employee PercentOfTotal -------------------------------- 1 Alice 25% 1 Barbara 65% 1 Claire 10% 2 Alice 25% 2 Barbara 50% 2 Claire 25% 3 Alice 25% 3 Barbara 65% 3 Claire 10% As you can see, I've paid them the same percent in Months 1 and 3, but in Month 2, I've given Alice the same 25%, but Barbara got 50% and Claire got 25%. What I want to know is all the distinct distributions I've ever given. In this case there would be two -- one for months 1 and 3, and one for month 2. I'd expect the results to look something like this (NOTE: the ID, or sequencer, or whatever, doesn't matter) ID Employee PercentOfTotal -------------------------------- X Alice 25% X Barbara 65% X Claire 10% Y Alice 25% Y Barbara 50% Y Claire 25% Seems easy, right? I'm stumped! Anyone have an elegant solution? I just put together this solution while writing this question, which seems to work, but I'm wondering if there's a better way. Or maybe a different way from which I'll learn something. WITH temp_ids (Month) AS ( SELECT DISTINCT MIN(Month) FROM employees_paid GROUP BY PercentOfTotal ) SELECT EMP.Month, EMP.Employee, EMP.PercentOfTotal FROM employees_paid EMP JOIN temp_ids IDS ON EMP.Month = IDS.Month GROUP BY EMP.Month, EMP.Employee, EMP.PercentOfTotal Thanks y'all! -Ricky

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• Altruistic network connection bandwidth estimation

  - by datenwolf

  Assume two peers Alice and Bob connected over a IP network. Alice and Bob are exchanging packets of lossy compressed data which are generated and to be consumes in real time (think a VoIP or video chat application). The service is designed to cope with as little bandwidth available, but relies on low latencies. Alice and Bob would mark their connection with an apropriate QoS profile. Alice and Bob want use a variable bitrate compression and would like to consume all of the leftover bandwidth available for the connection between them, but would voluntarily reduce the consumed bitrate depending on the state of the network. However they'd like to retain a stable link, i.e. avoid interruptions in their decoded data stream caused by congestion and the delay until the bandwidth got adjusted. However it is perfectly possible for them to loose a few packets. TL;DR: Alice and Bob want to implement a VoIP protocol from scratch, and are curious about bandwidth and congestion control. What papers and resources do you suggest for Alice and Bob to read? Mainly in the area of bandwidth estimation and congestion control.

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• help redirecting IP address

  - by Alice

  Google has indexed the IP address of my site rather than the domain, so now I'm trying to set up a 301 redirect that will redirect the IP address and all subsequent pages to the domain. I currently have something like this in my .htaccess file (however don't think it's working correctly?): RewriteCond %{HTTP_HOST} ^12.34.567.890 RewriteRule (.*) (domain address)/$1 [R=301,L] I've used various redirect checker tools and keep getting the message: "... not redirecting to any URL or the redirect is NOT SEARCH ENGINE FRIENDLY" Am I doing something wrong or is there something else I should be trying? Thanks! Alice

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• maintaing a sorted list that is bigger than memory

  - by tcurdt

  I have a list of tuples. [ "Bob": 3, "Alice: 2, "Jane": 1, ] When incrementing the counts "Alice" += 2 the order should be maintained: [ "Alice: 4, "Bob": 3, "Jane": 1, ] When all is in memory there rather simple ways (some more or some less) to efficiently implement this. (using an index, insert-sort etc) The question though is: What's the most promising approach when the list does not fit into memory. Bonus question: What if not even the index fits into memory? How would you approach this?

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• MOD Rewrite Mask for Image URL

  - by user345426

  Okay so I am launching a cloned e-commerce site. I want to create a rewrite rule for the image folder for the second site to fetch images from the first site. RewriteRule ^alice.gif$ www.rhinomart.com/images/h_home.gif When I go to alice.gif directly through the browser it simply redirects me to the rhinomart.com URL and image. How do I prevent the redirect from occurring? When I go to http://www.acnbiz.net/alice.gif it should fetch alice.gif directly from Rhinomart.com/images and not redirect. is it possible???

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• R:how to get grep to return the match, rather than the whole string

  - by Mike Dewar

  Hi, I have what is probably a really dumb grep in R question. Apologies, because this seems like it should be so easy - I'm obviously just missing something. I have a vector of strings, let's call it alice. Some of alice is printed out below: T.8EFF.SP.OT1.D5.VSVOVA#4 T.8EFF.SP.OT1.D6.LISOVA#1 T.8EFF.SP.OT1.D6.LISOVA#2 T.8EFF.SP.OT1.D6.LISOVA#3 T.8EFF.SP.OT1.D6.VSVOVA#4 T.8EFF.SP.OT1.D8.VSVOVA#3 T.8EFF.SP.OT1.D8.VSVOVA#4 T.8MEM.SP#1 T.8MEM.SP#3 T.8MEM.SP.OT1.D106.VSVOVA#2 T.8MEM.SP.OT1.D45.LISOVA#1 T.8MEM.SP.OT1.D45.LISOVA#3 I'd like grep to give me the number after the D that appears in some of these strings, conditional on the string containing "LIS" and an empty string or something otherwise. I was hoping that grep would return me the value of a capturing group rather than the whole string. Here's my R-flavoured regexp: pattern <- (?<=\\.D)([0-9]+)(?=.LIS) nothing too complicated. But in order to get what I'm after, rather than just using grep(pattern, alice, value = TRUE, perl = TRUE) I'm doing the following, which seems bad: reg.out <- regexpr( "(?<=\\.D)[0-9]+(?=.LIS)", alice, perl=TRUE ) substr(alice,reg.out,reg.out + attr(reg.out,"match.length")-1) Looking at it now it doesn't seem too ugly, but the amount of messing about it's taken to get this utterly trivial thing working has been embarrassing. Anyone any pointers about how to go about this properly? Bonus marks for pointing me to a webpage that explains the difference between whatever I access with $,@ and attr.

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• Going for Gold

  - by Simple-Talk Editorial Team

  There was a spring in the step of some members of our development teams here at Red Gate, on hearing that on five gold awards at 2012′s SQL Mag Community and Editors Choice Awards. And why not? It’s a nice recognition that their efforts were appreciated by many in the SQL Server community. The team at Simple-Talk don’t tend to spring, but even we felt a twinge of pride in the fact that SQL Scripts Manager received Gold for Editor’s Choice in the Best Free Tools category. The tool began life as a “Down Tools” project and is one that we’ve supported and championed in various articles on Simple-talk.com. Over a Cambridge Bitter in the Waggon and Horses, we’ve often reflected on how nice it would be to nominate our own awards. Of course, we’d have to avoid nominating Red Gate tools in each category, even the free ones, for fear of seeming biased,  but we could still award other people’s free tools, couldn’t we? So allow us to set the stage for the annual Simple-Talk Community Tool awards… Onto the platform we shuffle, to applause from the audience; Chris in immaculate tuxedo, Alice in stunning evening gown, Dave and Tony looking vaguely uncomfortable, Andrew somehow distracted, as if his mind is elsewhere. Tony strides up to the lectern, and coughs lightly…”In the free-tool category we have the three nominations, and they are…” (rustle of the envelope opening) Ola Hallengren’s SQL Server Maintenance Solution (applause) Adam Machanic’s WhoIsActive (cheers, more applause) Brent Ozar’s sp_Blitz (much clapping) “Before we declare the winner, I’d like to say a few words in recognition of a grand tradition in a SQL Server community that continues to offer its members a steady supply of excellent, free tools. It hammers home the fundamental principle that a tool should solve a single, pressing and frustrating problem, but you should only ever build your own solution to that problem if you are certain that you cannot buy it, or that someone has not already provided it free. We have only three finalists tonight, but I feel compelled to mention a few other tools that we also use and appreciate, such as Microsoft’s Logparser, Open source Curl, Microsoft’s TableDiff.exe, Performance Analysis of Logs (PAL) Tool, SQL Server Cache Manager and SQLPSX.” “And now I’ll hand over to Alice to announce the winner.” Alice strides over to the microphone, tearing open the envelope. “The winner,” she pauses for dramatic effect “… is …Ola Hallengren’s SQL Server Maintenance Solution!” Queue much applause and consumption of champagne. Did we get it wrong? What free tool would you nominate? Let us know! Cheers, Simple-Talk Editorial Team (Andrew, Alice, Chris, Dave, Tony)

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• iCal CalDAV multiple alarm notification

  - by user13332755

  In case you work with Apple iCal CalDAV Client you might noticed an issue with several alarm notification was send / received. So Alice add Calendar of Mike in iCal, Mike created an event with email alarm notification for Tom. Guess what, Tom will receive an email alarm notification from Mike and Alice. So whenever you add Calendars which are not your own Calendar in iCal you should use the Option Ignore Alarms

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