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  • The "Oldest Pirate" Passes

    <b>The Blog of Helios: </b>"What follows is a story about Alice I wrote in 2006, published in the now-offline Lobby4Linux.com website. I am reprinting this for those who may not have read it and to spend some personal time in remembering Alice."

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  • Active Directory Restricted Group confusion

    - by pepoluan
    I am trying to implement Restricted Group policy for my company's AD infrastructure, namely standardizing the local "Administrators" group. The documentation (and various webpages) said that the "Members of this group" policy will wipe out the "Administrators" group. However, an experiment made me confused: I created 2 GPOs: GPO-A replaces the Local Administrators with a list of domain users (e.g., "Alice" and "Bob") GPO-B inserts a domain user (e.g., "Charlie" -- not part of GPO A) into the Local Administrators Experiment 1: GPO-A gets applied first (link order 2) Everything happens as expected: GPO-A cleans out Local Admins and add "Alice" & "Bob" gets added; GPO-B adds "Charlie". Experiment 2: GPO-B is applied first What happens: "Charlie" gets added to the Local Admins group (which also contains 2 local users) The local users on the PC gets deleted, and "Alice" and "Bob" gets added. Result: Local Admins contain "Alice", "Bob", and "Charlie" My confusion: In Experiment 2, I thought GPO-A will totally erase the Local Admins group, including users added by GPO-B (since GPO-A gets applied after GPO-B). As it happens, it only erase local users from the Local Admins, but keeps the domain users. So, is that the way it should be? Or am I doing something incorrectly?

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  • What's the best / easiest way to combine two mailboxes on Exchange 2007?

    - by jmassey
    I've found this and this(2) (sorry, maximum hyperlink limit for new users is 1, apparently), but they both seem targeted toward much more complex cases than what I'm trying to do, and I just want to make sure I'm not missing some better approach. Here's the scenario: 'Alice' has retired. 'Bob' has taken over Alice's position. Bob was already with the organization in a different but related position, and so they already have their own Exchange account with mail, calendars, etc., that they need to keep. I need to get all of Alice's old mail, calendar entries, etc., merged into Bob's existing stuff. Ideally, I don't want to have all of Alice's stuff in a separate 'recovery' folder that Bob would have to switch back and forth between to look at older stuff; I want it all just merged into Bob's current Inbox / Calendar. I'm assuming (read: hoping) that there's a better way to do this than fiddling with permissions and exporting to and then importing from a .pst. Office version is 2007 for everybody that uses Exchange, if that helps. Exchange is version 8.1. What (preferably step-by-step - I'm new to Exchange) is the best way to do this? I can't imagine this is an uncommon scenario, but my google-fu has failed me; there seems to be nothing on this subject that isn't geared towards far more complex scenarios. (2): h t t p://technet.microsoft.com/en-us/library/bb201751%28EXCHG.80%29.aspx

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  • OpenWonderland goes to Europe

    - by user12652314
    Past my day job, I also have the privilege of being Vice President and Member of the Board of the OpenWonderland Foundation (Formerly Project Wonderland for ex-Sun folks). It's great to see the progress Wonderland is making as the platform-of-choice for open source collaborative 3-D virtual worlds built in Java. The upcoming and first european IE Summit in Madrid will show a number of projects and innovations for virtual and game-based learning. I also dropped Ultan a note after learning about the Gamification of Oracle Apps to see if collaborating with kids and schools is an area we can work together on to improve kids engagement and learning experiences online. Stay tuned.

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  • Can you help me get my head around openssl public key encryption with rsa.h in c++?

    - by Ben
    Hi there, I am trying to get my head around public key encryption using the openssl implementation of rsa in C++. Can you help? So far these are my thoughts (please do correct if necessary) Alice is connected to Bob over a network Alice and Bob want secure communications Alice generates a public / private key pair and sends public key to Bob Bob receives public key and encrypts a randomly generated symmetric cypher key (e.g. blowfish) with the public key and sends the result to Alice Alice decrypts the ciphertext with the originally generated private key and obtains the symmetric blowfish key Alice and Bob now both have knowledge of symmetric blowfish key and can establish a secure communication channel Now, I have looked at the openssl/rsa.h rsa implementation (since I already have practical experience with openssl/blowfish.h), and I see these two functions: int RSA_public_encrypt(int flen, unsigned char *from, unsigned char *to, RSA *rsa, int padding); int RSA_private_decrypt(int flen, unsigned char *from, unsigned char *to, RSA *rsa, int padding); If Alice is to generate *rsa, how does this yield the rsa key pair? Is there something like rsa_public and rsa_private which are derived from rsa? Does *rsa contain both public and private key and the above function automatically strips out the necessary key depending on whether it requires the public or private part? Should two unique *rsa pointers be generated so that actually, we have the following: int RSA_public_encrypt(int flen, unsigned char *from, unsigned char *to, RSA *rsa_public, int padding); int RSA_private_decrypt(int flen, unsigned char *from, unsigned char *to, RSA *rsa_private, int padding); Secondly, in what format should the *rsa public key be sent to Bob? Must it be reinterpreted in to a character array and then sent the standard way? I've heard something about certificates -- are they anything to do with it? Sorry for all the questions, Best Wishes, Ben. EDIT: Coe I am currently employing: /* * theEncryptor.cpp * * * Created by ben on 14/01/2010. * Copyright 2010 __MyCompanyName__. All rights reserved. * */ #include "theEncryptor.h" #include <iostream> #include <sys/socket.h> #include <sstream> theEncryptor::theEncryptor() { } void theEncryptor::blowfish(unsigned char *data, int data_len, unsigned char* key, int enc) { // hash the key first! unsigned char obuf[20]; bzero(obuf,20); SHA1((const unsigned char*)key, 64, obuf); BF_KEY bfkey; int keySize = 16;//strlen((char*)key); BF_set_key(&bfkey, keySize, obuf); unsigned char ivec[16]; memset(ivec, 0, 16); unsigned char* out=(unsigned char*) malloc(data_len); bzero(out,data_len); int num = 0; BF_cfb64_encrypt(data, out, data_len, &bfkey, ivec, &num, enc); //for(int i = 0;i<data_len;i++)data[i]=out[i]; memcpy(data, out, data_len); free(out); } void theEncryptor::generateRSAKeyPair(int bits) { rsa = RSA_generate_key(bits, 65537, NULL, NULL); } int theEncryptor::publicEncrypt(unsigned char* data, unsigned char* dataEncrypted,int dataLen) { return RSA_public_encrypt(dataLen, data, dataEncrypted, rsa, RSA_PKCS1_OAEP_PADDING); } int theEncryptor::privateDecrypt(unsigned char* dataEncrypted, unsigned char* dataDecrypted) { return RSA_private_decrypt(RSA_size(rsa), dataEncrypted, dataDecrypted, rsa, RSA_PKCS1_OAEP_PADDING); } void theEncryptor::receivePublicKeyAndSetRSA(int sock, int bits) { int max_hex_size = (bits / 4) + 1; char keybufA[max_hex_size]; bzero(keybufA,max_hex_size); char keybufB[max_hex_size]; bzero(keybufB,max_hex_size); int n = recv(sock,keybufA,max_hex_size,0); n = send(sock,"OK",2,0); n = recv(sock,keybufB,max_hex_size,0); n = send(sock,"OK",2,0); rsa = RSA_new(); BN_hex2bn(&rsa->n, keybufA); BN_hex2bn(&rsa->e, keybufB); } void theEncryptor::transmitPublicKey(int sock, int bits) { const int max_hex_size = (bits / 4) + 1; long size = max_hex_size; char keyBufferA[size]; char keyBufferB[size]; bzero(keyBufferA,size); bzero(keyBufferB,size); sprintf(keyBufferA,"%s\r\n",BN_bn2hex(rsa->n)); sprintf(keyBufferB,"%s\r\n",BN_bn2hex(rsa->e)); int n = send(sock,keyBufferA,size,0); char recBuf[2]; n = recv(sock,recBuf,2,0); n = send(sock,keyBufferB,size,0); n = recv(sock,recBuf,2,0); } void theEncryptor::generateRandomBlowfishKey(unsigned char* key, int bytes) { /* srand( (unsigned)time( NULL ) ); std::ostringstream stm; for(int i = 0;i<bytes;i++){ int randomValue = 65 + rand()% 26; stm << (char)((int)randomValue); } std::string str(stm.str()); const char* strs = str.c_str(); for(int i = 0;bytes;i++)key[i]=strs[i]; */ int n = RAND_bytes(key, bytes); if(n==0)std::cout<<"Warning key was generated with bad entropy. You should not consider communication to be secure"<<std::endl; } theEncryptor::~theEncryptor(){}

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  • running multi threads in Java

    - by owca
    My task is to simulate activity of couple of persons. Each of them has few activities to perform in some random time: fast (0-5s), medium(5-10s), slow(10-20s) and very slow(20-30s). Each person performs its task independently in the same time. At the beginning of new task I should print it's random time, start the task and then after time passes show next task's time and start it. I've written run() function that counts time, but now it looks like threads are done one after another and not in the same time or maybe they're just printed in this way. public class People{ public static void main(String[] args){ Task tasksA[]={new Task("washing","fast"), new Task("reading","slow"), new Task("shopping","medium")}; Task tasksM[]={new Task("sleeping zzzzzzzzzz","very slow"), new Task("learning","slow"), new Task(" :** ","slow"), new Task("passing an exam","slow") }; Task tasksJ[]={new Task("listening music","medium"), new Task("doing nothing","slow"), new Task("walking","medium") }; BusyPerson friends[]={ new BusyPerson("Alice",tasksA), new BusyPerson("Mark",tasksM), new BusyPerson("John",tasksJ)}; System.out.println("STARTING....................."); for(BusyPerson f: friends) (new Thread(f)).start(); System.out.println("DONE........................."); } } class Task { private String task; private int time; private Task[]tasks; public Task(String t, String s){ task = t; Speed speed = new Speed(); time = speed.getSpeed(s); } public Task(Task[]tab){ Task[]table=new Task[tab.length]; for(int i=0; i < tab.length; i++){ table[i] = tab[i]; } this.tasks = table; } } class Speed { private static String[]hows = {"fast","medium","slow","very slow"}; private static int[]maxs = {5000, 10000, 20000, 30000}; public Speed(){ } public static int getSpeed( String speedString){ String s = speedString; int up_limit=0; int down_limit=0; int time=0; //get limits of time for(int i=0; i<hows.length; i++){ if(s.equals(hows[i])){ up_limit = maxs[i]; if(i>0){ down_limit = maxs[i-1]; } else{ down_limit = 0; } } } //get random time within the limits Random rand = new Random(); time = rand.nextInt(up_limit) + down_limit; return time; } } class BusyPerson implements Runnable { private String name; private Task[] person_tasks; private BusyPerson[]persons; public BusyPerson(String s, Task[]t){ name = s; person_tasks = t; } public BusyPerson(BusyPerson[]tab){ BusyPerson[]table=new BusyPerson[tab.length]; for(int i=0; i < tab.length; i++){ table[i] = tab[i]; } this.persons = table; } public void run() { int time = 0; double t1=0; for(Task t: person_tasks){ t1 = (double)t.time/1000; System.out.println(name+" is... "+t.task+" "+t.speed+ " ("+t1+" sec)"); while (time == t.time) { try { Thread.sleep(10); } catch(InterruptedException exc) { System.out.println("End of thread."); return; } time = time + 100; } } } } And my output : STARTING..................... DONE......................... Mark is... sleeping zzzzzzzzzz very slow (36.715 sec) Mark is... learning slow (10.117 sec) Mark is... :** slow (29.543 sec) Mark is... passing an exam slow (23.429 sec) Alice is... washing fast (1.209 sec) Alice is... reading slow (23.21 sec) Alice is... shopping medium (11.237 sec) John is... listening music medium (8.263 sec) John is... doing nothing slow (13.576 sec) John is... walking medium (11.322 sec) Whilst it should be like this : STARTING..................... DONE......................... John is... listening music medium (7.05 sec) Alice is... washing fast (3.268 sec) Mark is... sleeping zzzzzzzzzz very slow (23.71 sec) Alice is... reading slow (15.516 sec) John is... doing nothing slow (13.692 sec) Alice is... shopping medium (8.371 sec) Mark is... learning slow (13.904 sec) John is... walking medium (5.172 sec) Mark is... :** slow (12.322 sec) Mark is... passing an exam very slow (27.1 sec)

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  • Can I access Spring session-scoped beans from application-scoped beans? How?

    - by Corvus
    I'm trying to make this 2-player web game application using Spring MVC. I have session-scoped beans Player and application-scoped bean GameList, which creates and stores Game instances and passes them to Players. On player creates a game and gets its ID from GameList and other player sends ID to GameList and gets Game instance. The Game instance has its players as attributes. Problem is that each player sees only himself instead of the other one. Example of what each player sees: First player (Alice) creates a game: Creator: Alice, Joiner: Empty Second player (Bob) joins the game: Creator: Bob, Joiner: Bob First player refreshes her browser Creator: Alice, Joiner: Alice What I want them to see is Creator: Alice, Joiner: Bob. Easy way to achieve this is saving information about players instead of references to players, but the game object needs to call methods on its player objects, so this is not a solution. I think it's because of aop:scoped-proxy of session-scoped Player bean. If I understand this, the Game object has reference to proxy, which refers to Player object of current session. Can Game instance save/access the other Player objects somehow? beans in dispatcher-servlet.xml: <bean id="userDao" class="authorization.UserDaoFakeImpl" /> <bean id="gameList" class="model.GameList" /> <bean name="/init/*" class="controller.InitController" > <property name="gameList" ref="gameList" /> <property name="game" ref="game" /> <property name="player" ref="player" /> </bean> <bean id="game" class="model.GameContainer" scope="session"> <aop:scoped-proxy/> </bean> <bean id="player" class="beans.Player" scope="session"> <aop:scoped-proxy/> </bean> methods in controller.InitController private GameList gameList; private GameContainer game; private Player player; public ModelAndView create(HttpServletRequest request, HttpServletResponse response) throws Exception { game.setGame(gameList.create(player)); return new ModelAndView("redirect:game"); } public ModelAndView join(HttpServletRequest request, HttpServletResponse response, GameId gameId) throws Exception { game.setGame(gameList.join(player, gameId.getId())); return new ModelAndView("redirect:game"); } called methods in model.gameList public Game create(Player creator) { Integer code = generateCode(); Game game = new Game(creator, code); games.put(code, game); return game; } public Game join(Player joiner, Integer code) { Game game = games.get(code); if (game!=null) { game.setJoiner(joiner); } return game; }

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  • Is this simple XOR encrypted communication absolutely secure?

    - by user3123061
    Say Alice have 4GB USB flash memory and Peter also have 4GB USB flash memory. They once meet and save on both of memories two files named alice_to_peter.key (2GB) and peter_to_alice.key (2GB) which is randomly generated bits. Then they never meet again and communicate electronicaly. Alice also maintains variable called alice_pointer and Peter maintains variable called peter_pointer which is both initially set to zero. Then when Alice needs to send message to Peter they do: encrypted_message_to_peter[n] = message_to_peter[n] XOR alice_to_peter.key[alice_pointer + n] Where n i n-th byte of message. Then alice_pointer is attached at begining of the encrypted message and (alice_pointer + encrypted message) is sent to Peter and then alice_pointer is incremented by length of message (and for maximum security can be used part of key erased) Peter receives encrypted_message, reads alice_pointer stored at beginning of message and do this: message_to_peter[n] = encrypted_message_to_peter[n] XOR alice_to_peter.key[alice_pointer + n] And for maximum security after reading of message also erases used part of key. - EDIT: In fact this step with this simple algorithm (without integrity check and authentication) decreases security, see Paulo Ebermann post below. When Peter needs to send message to Alice they do analogical steps with peter_to_alice.key and with peter_pointer. With this trivial schema they can send for next 50 years each day 2GB / (50 * 365) = cca 115kB of encrypted data in both directions. If they need more data to send, they simple use larger memory for keys for example with today 2TB harddiscs (1TB keys) is possible to exchange next 50years 60MB/day ! (thats practicaly lots of data for example with using compression its more than hour of high quality voice communication) It Seems to me there is no way for attacker to read encrypted message without keys even if they have infinitely fast computer. because even with infinitely fast computer with brute force they get ever possible message that can fit to length of message, but this is astronomical amount of messages and attacker dont know which of them is actual message. I am right? Is this communication schema really absolutely secure? And if its secure, has this communication method its own name? (I mean XOR encryption is well-known, but whats name of this concrete practical application with use large memories at both communication sides for keys? I am humbly expecting that this application has been invented someone before me :-) ) Note: If its absolutely secure then its amazing because with today low cost large memories it is practicaly much cheeper way of secure communication than expensive quantum cryptography and with equivalent security! EDIT: I think it will be more and more practical in future with lower a lower cost of memories. It can solve secure communication forever. Today you have no certainty if someone succesfuly atack to existing ciphers one year later and make its often expensive implementations unsecure. In many cases before comunication exist step where communicating sides meets personaly, thats time to generate large keys. I think its perfect for military communication for example for communication with submarines which can have installed harddrive with large keys and military central can have harddrive for each submarine they have. It can be also practical in everyday life for example for control your bank account because when you create your account you meet with bank etc.

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  • Variable number of two-dimensional arrays into one big array

    - by qlb
    I have a variable number of two-dimensional arrays. The first dimension is variable, the second dimension is constant. i.e.: Object[][] array0 = { {"tim", "sanchez", 34, 175.5, "bla", "blub", "[email protected]"}, {"alice", "smith", 42, 160.0, "la", "bub", "[email protected]"}, ... }; Object[][] array1 = { {"john", "sdfs", 34, 15.5, "a", "bl", "[email protected]"}, {"joe", "smith", 42, 16.0, "a", "bub", "[email protected]"}, ... }; ... Object[][] arrayi = ... I'm generating these arrays with a for-loop: for (int i = 0; i < filter.length; i++) { MyClass c = new MyClass(filter[i]); //data = c.getData(); } Where "filter" is another array which is filled with information that tells "MyClass" how to fill the arrays. "getData()" gives back one of the i number of arrays. Now I just need to have everything in one big two dimensional array. i.e.: Object[][] arrayComplete = { {"tim", "sanchez", 34, 175.5, "bla", "blub", "[email protected]"}, {"alice", "smith", 42, 160.0, "la", "bub", "[email protected]"}, ... {"john", "sdfs", 34, 15.5, "a", "bl", "[email protected]"}, {"joe", "smith", 42, 16.0, "a", "bub", "[email protected]"}, ... ... }; In the end, I need a 2D array to feed my Swing TableModel. Any idea on how to accomplish this? It's blowing my mind right now.

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  • Two strange efficiency problems in Mathematica

    - by Jess Riedel
    FIRST PROBLEM I have timed how long it takes to compute the following statements (where V[x] is a time-intensive function call): Alice = Table[V[i],{i,1,300},{1000}]; Bob = Table[Table[V[i],{i,1,300}],{1000}]^tr; Chris_pre = Table[V[i],{i,1,300}]; Chris = Table[Chris_pre,{1000}]^tr; Alice, Bob, and Chris are identical matricies computed 3 slightly different ways. I find that Chris is computed 1000 times faster than Alice and Bob. It is not surprising that Alice is computed 1000 times slower because, naively, the function V must be called 1000 more times than when Chris is computed. But it is very surprising that Bob is so slow, since he is computed identically to Chris except that Chris stores the intermediate step Chris_pre. Why does Bob evaluate so slowly? SECOND PROBLEM Suppose I want to compile a function in Mathematica of the form f(x)=x+y where "y" is a constant fixed at compile time (but which I prefer not to directly replace in the code with its numerical because I want to be able to easily change it). If y's actual value is y=7.3, and I define f1=Compile[{x},x+y] f2=Compile[{x},x+7.3] then f1 runs 50% slower than f2. How do I make Mathematica replace "y" with "7.3" when f1 is compiled, so that f1 runs as fast as f2? Many thanks!

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  • Distributed development systems

    - by Nathan Adams
    I am interested in a system that allows for distributed development with an authentication piece. What do I mean by that? Ok so lets take SVN, SVN keeps track of revisions and doesn't care who submits, as long as you have the right to submit you can submit, really, to any part in the repository. Where does my system come into play? Being able to granulate access control and give a stackoverflow like feel to the environment. In the system I am describing we have 4 users Bob, Alice, Dan, Joe. Bob is a project managed, Alice and Dan are programmers under Bob and Joe is a random programmer on the internet who wants to help. Ideally in this system, Bob can commit any changes and won't require approval. Alice and Dan can commit to their branches, or a branch, but a commit to the trunk would need approval by Bob. This is where Joe comes in, wants to help, however, you just don't want to give him the keys to the kingdom just yet so to speak, so in my system you would setup a "low user" account. Any commits that Joe makes would need to be approved by Dan, Alice or both. However, in the system, Joe can build up "Karma" where after so many approved commits it would only need approval by one of the programmers, and then eventually no approval would be necessary. Does that make sense and do you know if a system like that exists? Or am I just crazy to even think such a system/environment would be possible?

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  • How to write a custom solution using a python package, modules etc

    - by morpheous
    I am writing a packacge foobar which consists of the modules alice, bob, charles and david. From my understanding of Python packages and modules, this means I will create a folder foobar, with the following subdirectories and files (please correct if I am wrong) foobar/ __init__.py alice/alice.py bob/bob.py charles/charles.py david/david.py The package should be executable, so that in addition to making the modules alice, bob etc available as 'libraries', I should also be able to use foobar in a script like this: python foobar --args=someargs Question1: Can a package be made executable and used in a script like I described above? Question 2 The various modules will use code that I want to refactor into a common library. Does that mean creating a new sub directory 'foobar/common' and placing common.py in that folder? Question 3 How will the modules foo import the common module ? Is it 'from foobar import common' or can I not use this since these modules are part of the package? Question 4 I want to add logic for when the foobar package is being used in a script (assuming this can be done - I have only seen it done for modules) The code used is something like: if __name__ == "__main__": dosomething() where (in which file) would I put this logic ?

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  • Spawning a thread in python

    - by morpheous
    I have a series of 'tasks' that I would like to run in separate threads. The tasks are to be performed by separate modules. Each containing the business logic for processing their tasks. Given a tuple of tasks, I would like to be able to spawn a new thread for each module as follows. from foobar import alice, bob charles data = getWorkData() # these are enums (which I just found Python doesn't support natively) :( tasks = (alice, bob, charles) for task in tasks # Ok, just found out Python doesn't have a switch - @#$%! # yet another thing I'll need help with then ... switch case alice: #spawn thread here - how ? alice.spawnWorker(data) No prizes for guessing I am still thinking in C++. How can I write this in a Pythonic way using Pythonic 'enums' and 'switch'es, and be able to run a module in a new thread. Obviously, the modules will all have a class that is derived from a ABC (abstract base class) called Plugin. The spawnWorker() method will be declared on the Plugin interface and defined in the classes implemented in the various modules. Maybe, there is a better (i.e. Pythonic) way of doing all this?. I'd be interested in knowing

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  • Indirect Postfix bounces create new user directories

    - by hheimbuerger
    I'm running Postfix on my personal server in a data centre. I am not a professional mail hoster and not a Postfix expert, it is just used for a few domains served from that server. IIRC, I mostly followed this howto when setting up Postfix. Mails addressed to one of the domains the server manages are delivered locally (/srv/mail) to be fetched with Dovecot. Mails to other domains require usage of SMTPS. The mailbox configuration is stored in MySQL. The problem I have is that I suddenly found new mailboxes being created on the disk. Let's say I have the domain 'example.com'. Then I would have lots of new directories, e.g. /srv/mail/example.com/abenaackart /srv/mail/example.com/abenaacton etc. There are no entries for these addresses in my database, neither as a mailbox nor as an alias. It's clearly spam from auto-generated names. Most of them start with 'a', a few with 'b' and a couple of random ones with other letters. At first I was afraid of an attack, but all security restrictions seem to work. If I try to send mail to these addresses, I get an "Recipient address rejected: User unknown in virtual mailbox table" during the 'RCPT TO' stage. So I looked into the mails stored in these mailboxes. Turns out that all of them are bounces. It seems like all of them were sent from a randomly generated name to an alias that really exists on my system, but pointed to an invalid destination address on another host. So Postfix accepted it, then tried to redirect it to another mail server, which rejected it. This bounced back to my Postfix server, which now took the bounce and stored it locally -- because it seemed to be originating from one of the addresses it manages. Example: My Postfix server handles the example.com domain. [email protected] is configured to redirect to [email protected]. [email protected] has since been deleted from the Hotmail servers. Spammer sends mail with FROM:[email protected] and TO:[email protected]. My Postfix server accepts the mail and tries to hand it off to hotmail.com. hotmail.com sends a bounce back. My Postfix server accepts the bounce and delivers it to /srv/mail/example.com/bob. The last step is what I don't want. I'm not quite sure what it should do instead, but creating hundreds of new mailboxes on my disk is not what I want... Any ideas how to get rid of this behaviour? I'll happily post parts of my configuration, but I'm not really sure where to start debugging the problem at this point.

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  • how does public key cryptography work

    - by rap-uvic
    Hello, What I understand about RSA is that Alice can create a public and a private key combination, and then send the public key over to Bob. And then afterward Bob can encrypt something using the public key and Alice will use the public and private key combo to decrypt it. However, how can Alice encrypt something to be sent over to Bob? How would Bob decrypt it? I ask because I'm curious how when I log onto my banking site, my bank sends me data such as my online statements. How does my browser decrypt that information? I don't have the private key.

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  • How to transpose rows and columns in Access 2003?

    - by Lisa Schwaiger
    How do I transpose rows and columns in Access 2003? I have a multiple tables that I need to do this on. (I've reworded my question because feedback tells me it was confusing how I originally stated it.) Each table has 30 fields and 20 records. Lets say my fields are Name, Weight, Zip Code, Quality4, Quality5, Quality6 through Quality30 which is favorite movie. Let's say the records each describe a person. The people are Alice, Betty, Chuck, Dave, Edward etc through Tommy.. I can easily make a report like this: >>Alice...120....35055---etc, etc, etc...Jaws Betty....125....35212...etc, etc, etc...StarWars etc etc etc Tommy...200...35213...etc, etc, etc...Adaptation But what I would like to do is transpose those rows and columns so my report displays like this >>Alice........Betty......etc,etc,etc...Tommy 120.........125........etc, etc, etc...200 35055.....35212....etc, etc, etc...35213 etc etc etc Jaws...StarWars..etc,etc,etc...Adaptation Thanks for any help.

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  • Correct way to give users access to additional schemas in Oracle

    - by Jacob
    I have two users Bob and Alice in Oracle, both created by running the following commands as sysdba from sqlplus: create user $blah identified by $password; grant resource, connect, create view to $blah; I want Bob to have complete access to Alice's schema (that is, all tables), but I'm not sure what grant to run, and whether to run it as sysdba or as Alice. Happy to hear about any good pointers to reference material as well -- don't seem to be able to get a good answer to this from either the Internet or "Oracle Database 10g The Complete Reference", which is sitting on my desk.

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  • Get unique artist names from MPMediaQuery

    - by Akash Malhotra
    I am using MPMediaQuery to get all artists from library. Its returning unique names I guess but the problem is I have artists in my library like "Alice In Chains" and "Alice In Chains ". The second "Alice In Chains" has some white spaces at the end, so it returns both. I dont want that. Heres the code... MPMediaQuery *query=[MPMediaQuery artistsQuery]; NSArray *artists=[query collections]; artistNames=[[NSMutableArray alloc]init]; for(MPMediaItemCollection *collection in artists) { MPMediaItem *item=[collection representativeItem]; [artistNames addObject:[item valueForProperty:MPMediaItemPropertyArtist]]; } uniqueNames=[[NSMutableArray alloc]init]; for(id object in artistNames) { if(![uniqueNames containsObject:object]) { [uniqueNames addObject:object]; } } Any ideas?

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  • RSpec leaves record in test database

    - by DMiller
    Whenever I run a user test, RSpec leaves the Fabricated user in the test database after the test has completed, which is messing up my other tests. I will do a rake db:test:prepare, but when I run my tests again, the record is recreated in my database. I have no idea why this is happening. It only happens with user objects. In my spec_helper file I even have: config.use_transactional_fixtures = true Here is an example test that creates a record: it "creates a password reset token for the user" do alice = Fabricate(:user) post :create, email: alice.email expect(assigns(alice.password_reset_token)).to_not eq(nil) end Fabricator: Fabricator(:user) do email { Faker::Internet.email } password 'password' name { Faker::Name.name } end Could this have anything to do with my users model?

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  • Code golf: Word frequency chart

    - by ChristopheD
    The challenge: Build an ASCII chart of the most commonly used words in a given text. The rules: Only accept a-z and A-Z (alphabetic characters) as part of a word. Ignore casing (She == she for our purpose). Ignore the following words (quite arbitary, I know): the, and, of, to, a, i, it, in, or, is Clarification: considering don't: this would be taken as 2 different 'words' in the ranges a-z and A-Z: (don and t). Optionally (it's too late to be formally changing the specifications now) you may choose to drop all single-letter 'words' (this could potentially make for a shortening of the ignore list too). Parse a given text (read a file specified via command line arguments or piped in; presume us-ascii) and build us a word frequency chart with the following characteristics: Display the chart (also see the example below) for the 22 most common words (ordered by descending frequency). The bar width represents the number of occurences (frequency) of the word (proportionally). Append one space and print the word. Make sure these bars (plus space-word-space) always fit: bar + [space] + word + [space] should be always <= 80 characters (make sure you account for possible differing bar and word lenghts: e.g.: the second most common word could be a lot longer then the first while not differing so much in frequency). Maximize bar width within these constraints and scale the bars appropriately (according to the frequencies they represent). An example: The text for the example can be found here (Alice's Adventures in Wonderland, by Lewis Carroll). This specific text would yield the following chart: _________________________________________________________________________ |_________________________________________________________________________| she |_______________________________________________________________| you |____________________________________________________________| said |____________________________________________________| alice |______________________________________________| was |__________________________________________| that |___________________________________| as |_______________________________| her |____________________________| with |____________________________| at |___________________________| s |___________________________| t |_________________________| on |_________________________| all |______________________| this |______________________| for |______________________| had |_____________________| but |____________________| be |____________________| not |___________________| they |__________________| so For your information: these are the frequencies the above chart is built upon: [('she', 553), ('you', 481), ('said', 462), ('alice', 403), ('was', 358), ('that ', 330), ('as', 274), ('her', 248), ('with', 227), ('at', 227), ('s', 219), ('t' , 218), ('on', 204), ('all', 200), ('this', 181), ('for', 179), ('had', 178), (' but', 175), ('be', 167), ('not', 166), ('they', 155), ('so', 152)] A second example (to check if you implemented the complete spec): Replace every occurence of you in the linked Alice in Wonderland file with superlongstringstring: ________________________________________________________________ |________________________________________________________________| she |_______________________________________________________| superlongstringstring |_____________________________________________________| said |______________________________________________| alice |________________________________________| was |_____________________________________| that |______________________________| as |___________________________| her |_________________________| with |_________________________| at |________________________| s |________________________| t |______________________| on |_____________________| all |___________________| this |___________________| for |___________________| had |__________________| but |_________________| be |_________________| not |________________| they |________________| so The winner: Shortest solution (by character count, per language). Have fun! Edit: Table summarizing the results so far (2012-02-15) (originally added by user Nas Banov): Language Relaxed Strict ========= ======= ====== GolfScript 130 143 Perl 185 Windows PowerShell 148 199 Mathematica 199 Ruby 185 205 Unix Toolchain 194 228 Python 183 243 Clojure 282 Scala 311 Haskell 333 Awk 336 R 298 Javascript 304 354 Groovy 321 Matlab 404 C# 422 Smalltalk 386 PHP 450 F# 452 TSQL 483 507 The numbers represent the length of the shortest solution in a specific language. "Strict" refers to a solution that implements the spec completely (draws |____| bars, closes the first bar on top with a ____ line, accounts for the possibility of long words with high frequency etc). "Relaxed" means some liberties were taken to shorten to solution. Only solutions shorter then 500 characters are included. The list of languages is sorted by the length of the 'strict' solution. 'Unix Toolchain' is used to signify various solutions that use traditional *nix shell plus a mix of tools (like grep, tr, sort, uniq, head, perl, awk).

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  • Ruby on Rails redirect_to not functioning in IF statement?

    - by Hard-Boiled Wonderland
    Hi, I am redirecting a POST request to ensure the URL is correct along with other things. The redirect worked fine before I added in the if statements for town below: if !params[:address].blank? town = Town.find(:all, :conditions => ["name = ?", params[:address]]) @towns = town if !town.blank? redirect_to '/town/' + params[:address] else @town_invalid = 'test' end end end I am sure it is something simple and that I simply cannot see it. Also if you see any glaring errors or code mishaps let me know as I am just starting out. EDIT: I should mention this is what I get back from Safari when a real town is entered: Safari can’t open the page.Safari can’t open the page “http://localhost:3000/” because the server unexpectedly dropped the connection. This sometimes occurs when the server is busy. Wait for a few minutes, and then try again. Thanks!

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  • Adding custom columns to Propel model?

    - by Hard-Boiled Wonderland
    At the moment I am using the below query: $claims = ClaimQuery::create('c') ->leftJoinUser() ->withColumn('CONCAT(User.Firstname, " ", User.Lastname)', 'name') ->withColumn('User.Email', 'email') ->filterByArray($conditions) ->paginate($page = $page, $maxPerPage = $top); However I then want to add columns manually, so I thought this would simply work: foreach($claims as &$claim){ $claim->actions = array('edit' => array( 'url' => $this->get('router')->generate('hera_claims_edit'), 'text' => 'Edit' ) ); } return array('claims' => $claims, 'count' => count($claims)); However when the data is returned Propel or Symfony2 seems to be stripping the custom data when it gets converted to JSON along with all of the superflous model data. What is the correct way of manually adding data this way?

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  • Rails 3 routes and using GET to create clean URLs?

    - by Hard-Boiled Wonderland
    I am a little confused with the routes in Rails 3 as I am just starting to learn the language. I have a form generated here: <%= form_tag towns_path, :method => "get" do %> <%= label_tag :name, "Search for:" %> <%= text_field_tag :name, params[:name] %> <%= submit_tag "Search" %> <% end %> Then in my routes: get "towns/autocomplete_town_name" get "home/autocomplete_town_name" match 'towns' => 'towns#index' match 'towns/:name' => 'towns#index' resources :towns, :module => "town" resources :businesses, :module => "business" root :to => "home#index" So why when submitting the form do I get the URL: /towns?utf8=?&name=townname&commit=Search So the question is how do I make that url into a clean url like: /towns/townname Thanks, Andrew

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  • Calling method from view in mvc

    - by Alice in wonderland
    I'm implementing paging on an mvc view, and I want to call a method in the controller from the view view: >a href=">%= Url.Action("Search", new { page = NextPage(Request["exactPage"])).ToString()}) %" controller: public string NextPage(string currentPage) { return (int.Parse(currentPage) + 1).ToString(); } How can I call the NextPage method from the view? thanks!

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  • ASP.NET MVC: calling a controller method from view

    - by Alice in wonderland
    I'm implementing paging on an ASP.NET MVC view, and I want to call a method in the controller from the view. Code in the view: <a href="<%= Url.Action("Search", new { page = NextPage(Request["exactPage"])).ToString()}) %>"> Controller method: public string NextPage(string currentPage) { return (int.Parse(currentPage) + 1).ToString(); } How can I call the NextPage method from the view? thanks!

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