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  • TechEd Video Chat: SharePoint 2010 with Andrew Connell

    Check out this video interview from TechEd 2010 with SharePoint MVP and guru, Andrew Connell: In the video, Andrew discusses: What is awesome about SharePoint 2010? Silverlight in SharePoint 2010 The SharePoint 2010 development experience Andrews CodeRush plugins that help solve SharePoint development pains Andrew's push to improve DevExpress' involvement in the SharePoint developer market SharePoint education and training from CriticalPath Is Andrew the best...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Apps Script Developer Chat: Andrew Stillman

    Apps Script Developer Chat: Andrew Stillman Join us for a chat with Andrew Stillman, the developer of several popular scripts in the Script Gallery, such as formMule, formMutant, autoCrat, doctopus, and more. We'll talk with Andrew about his experiences with Apps Script and how he applies it to his work at New Visions for Public Schools and with youpd.org. From: GoogleDevelopers Views: 0 0 ratings Time: 00:00 More in Science & Technology

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  • Transcript: Andrew Tridgell on Patent Defence

    <b>ESP Software Patents News:</b> "The following is a transcript of a talk given in New Zealand, 2010. Andrew Tridgell discusses why reading patents is usually a good idea, how to read a patent, and how to work through it with a lawyer to build a solid defence."

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  • Question about "ASP.NET 3.5 Social Networking" by Andrew Siemer (from Packt Publishing)

    - by user287745
    am currently reading a book, which has explanation of making a social website. ASP.NET 3.5 Social Networking https://www.packtpub.com/expert-guide-for-social-networking-with-asp-.net-3.5/book On page 41 I noticed that the images of the solution explorer given in the text, indicate that windowsformapplication[PROJECT] has been used instead of WebForms[create new website]. there are no webforms? how would the end result be a site? what is happening here?? the name of the book is, ASP.NET 3.5 Social Networking, please refer to page 41, thanks note:- i have always made websites which needs hosting and be accessible from other computers using webforms[create new website] which has web.config file app_data etc..... please help thank you.

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  • Guest Post: Christian Finn: Is Facebook About to Become a Victim of its Own Success?

    - by Michael Snow
    12.00 Print 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Cambria","serif"; mso-ascii-font-family:Cambria; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:Cambria; mso-fareast-theme-font:minor-latin; mso-hansi-font-family:Cambria; mso-hansi-theme-font:minor-latin;}  Since we have a number of new members of the WebCenter Evangelist team - I thought it would be appropriate to close the week with the newest hire and leader of the global WebCenter Evangelists, Christian Finn, who has just joined the Red team after many years with the small technology company up in Redmond, WA. He gave an intro to himself in an earlier post this morning but his post below is a great example of how customer engagement takes on a life of its own in our global online connected and social digital ecosystem. Is Facebook About to Become a Victim of its Own Success? What if I told you that your brand could advertise so successfully, you wouldn’t have to pay for the ads? A recent campaign by Ford Motor Company for the Ford Focus featuring Doug the spokespuppet (I am not making this up) did just that—and it raises some interesting issues for marketers and social media alike in the brave new world of customer engagement that is the Social Web. Allow me to elaborate. An article in the Wall Street Journal last week—“Big Brands Like Facebook, But They Don’t Like to Pay” tells the story of Ford’s recently concluded online campaign for the 2012 Ford Focus. (Ford, by the way, under the leadership of people such as Scott Monty, has been a pioneer of effective social campaigns.) The centerpiece of the campaign was the aforementioned Doug, who appeared as a character on Facebook in videos and via chat. (If you are not familiar with Doug, you can see him in action here, and read the WSJ story here.) You may be thinking puppet ads are a sign of Internet Bubble 2.0 and want to stop now, but bear with me. The Journal reported that Ford spent about $95M on its overall Ford Focus campaign, with TV accounting for over $60M of that spend. The Internet buy for the campaign was just over $10M, which included ad buys to drive traffic to Facebook for people to meet and ‘Like’ Doug and some amount on Facebook ads, too, to promote Doug and by extension, the Ford Focus. So far, a fairly straightforward consumer marketing story in the Internet Era. Yet here’s the curious thing: once Doug reached 10,000 fans on Facebook, Ford stopped paying for Facebook ads. Doug had gone viral with people sharing his videos with one another; once critical mass was reached there was no need to buy more ads on Facebook. Doug went on to be Liked by over 43,000 people, and 61% of his fans said they would be more likely to consider buying a Focus. According to the article, Ford says Focus sales are up this year—and increasing sales is every marketer’s goal. And so in effect, Ford found its Facebook campaign so successful that it could stop paying for it, instead letting its target consumers communicate its messages for fun—and for free. Not only did they get a 3X increase in fans beyond their paid campaign, they had thousands of customers sharing their messages in video form for months. Since free advertising is the Holy Grail of marketing both old and new-- and it appears social networks have an advantage in generating that buzz—it seems reasonable to ask: what would happen to brands’ advertising strategies—and the media they use to engage customers, if this success were repeated at scale? It seems logical to conclude that, at least initially, more ad dollars would be spent with social networks like Facebook as brands attempt to replicate Ford’s success. Certainly Facebook ad revenues are on the rise—eMarketer expects Facebook’s ad revenues to quintuple by 2012 compared with 2009 levels, to nearly 2.9B. That’s bad news for TV and the already battered print media and good news for Facebook. But perhaps not so over the longer run. With TV buys, you have to keep paying to generate impressions. If Doug the spokespuppet is any guide, however, that may not be true for social media campaigns. After an initial outlay, if a social campaign takes off, the audience will generate more impressions on its own. Thus a social medium like Facebook could be the victim of its own success when it comes to ad revenue. It may be there is an inherent limiting factor in the ad spend they can capture, as exemplified by Ford’s experience with Dough and the Focus. And brands may spend much less overall on advertising, with as good or better results, than they ever have in the past. How will these trends evolve? Can brands create social campaigns that repeat Ford’s formula for the Focus with effective results? Can social networks find ways to capture more spend and overcome their potential tendency to make further spend unnecessary? And will consumers become tired and insulated from social campaigns, much as they have to traditional advertising channels? These are the questions CMOs and Facebook execs alike will be asking themselves in the brave new world of customer engagement. As always, your thoughts and comments are most welcome.

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  • Am I right about the differences between Floyd-Warshall, Dijkstra's and Bellman-Ford algorithms?

    - by Programming Noob
    I've been studying the three and I'm stating my inferences from them below. Could someone tell me if I have understood them accurately enough or not? Thank you. Dijkstra's algorithm is used only when you have a single source and you want to know the smallest path from one node to another, but fails in cases like this Floyd-Warshall's algorithm is used when any of all the nodes can be a source, so you want the shortest distance to reach any destination node from any source node. This only fails when there are negative cycles (this is the most important one. I mean, this is the one I'm least sure about:) 3.Bellman-Ford is used like Dijkstra's, when there is only one source. This can handle negative weights and its working is the same as Floyd-Warshall's except for one source, right? If you need to have a look, the corresponding algorithms are (courtesy Wikipedia): Bellman-Ford: procedure BellmanFord(list vertices, list edges, vertex source) // This implementation takes in a graph, represented as lists of vertices // and edges, and modifies the vertices so that their distance and // predecessor attributes store the shortest paths. // Step 1: initialize graph for each vertex v in vertices: if v is source then v.distance := 0 else v.distance := infinity v.predecessor := null // Step 2: relax edges repeatedly for i from 1 to size(vertices)-1: for each edge uv in edges: // uv is the edge from u to v u := uv.source v := uv.destination if u.distance + uv.weight < v.distance: v.distance := u.distance + uv.weight v.predecessor := u // Step 3: check for negative-weight cycles for each edge uv in edges: u := uv.source v := uv.destination if u.distance + uv.weight < v.distance: error "Graph contains a negative-weight cycle" Dijkstra: 1 function Dijkstra(Graph, source): 2 for each vertex v in Graph: // Initializations 3 dist[v] := infinity ; // Unknown distance function from 4 // source to v 5 previous[v] := undefined ; // Previous node in optimal path 6 // from source 7 8 dist[source] := 0 ; // Distance from source to source 9 Q := the set of all nodes in Graph ; // All nodes in the graph are 10 // unoptimized - thus are in Q 11 while Q is not empty: // The main loop 12 u := vertex in Q with smallest distance in dist[] ; // Start node in first case 13 if dist[u] = infinity: 14 break ; // all remaining vertices are 15 // inaccessible from source 16 17 remove u from Q ; 18 for each neighbor v of u: // where v has not yet been 19 removed from Q. 20 alt := dist[u] + dist_between(u, v) ; 21 if alt < dist[v]: // Relax (u,v,a) 22 dist[v] := alt ; 23 previous[v] := u ; 24 decrease-key v in Q; // Reorder v in the Queue 25 return dist; Floyd-Warshall: 1 /* Assume a function edgeCost(i,j) which returns the cost of the edge from i to j 2 (infinity if there is none). 3 Also assume that n is the number of vertices and edgeCost(i,i) = 0 4 */ 5 6 int path[][]; 7 /* A 2-dimensional matrix. At each step in the algorithm, path[i][j] is the shortest path 8 from i to j using intermediate vertices (1..k-1). Each path[i][j] is initialized to 9 edgeCost(i,j). 10 */ 11 12 procedure FloydWarshall () 13 for k := 1 to n 14 for i := 1 to n 15 for j := 1 to n 16 path[i][j] = min ( path[i][j], path[i][k]+path[k][j] );

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  • I am trying to deploy my first rails app using Capistrano and am getting an error.

    - by Andrew Bucknell
    My deployment of a rails app with capistrano is failing and I hoping someone can provide me with pointers to troubleshoot. The following is the command output andrew@melb-web:~/projects/rails/guestbook2$ cap deploy:setup * executing `deploy:setup' * executing "mkdir -p /var/www/dev/guestbook2 /var/www/dev/guestbook2/releases /var/www/dev/guestbook2/shared /var/www/dev/guestbook2/shared/system /var/www/dev/guestbook2/shared/log /var/www/dev/guestbook2/shared/pids && chmod g+w /var/www/dev/guestbook2 /var/www/dev/guestbook2/releases /var/www/dev/guestbook2/shared /var/www/dev/guestbook2/shared/system /var/www/dev/guestbook2/shared/log /var/www/dev/guestbook2/shared/pids" servers: ["dev.andrewbucknell.com"] Enter passphrase for /home/andrew/.ssh/id_dsa: Enter passphrase for /home/andrew/.ssh/id_dsa: [dev.andrewbucknell.com] executing command command finished andrew@melb-web:~/projects/rails/guestbook2$ cap deploy:check * executing `deploy:check' * executing "test -d /var/www/dev/guestbook2/releases" servers: ["dev.andrewbucknell.com"] Enter passphrase for /home/andrew/.ssh/id_dsa: [dev.andrewbucknell.com] executing command command finished * executing "test -w /var/www/dev/guestbook2" servers: ["dev.andrewbucknell.com"] [dev.andrewbucknell.com] executing command command finished * executing "test -w /var/www/dev/guestbook2/releases" servers: ["dev.andrewbucknell.com"] [dev.andrewbucknell.com] executing command command finished * executing "which git" servers: ["dev.andrewbucknell.com"] [dev.andrewbucknell.com] executing command command finished * executing "test -w /var/www/dev/guestbook2/shared" servers: ["dev.andrewbucknell.com"] [dev.andrewbucknell.com] executing command command finished You appear to have all necessary dependencies installed andrew@melb-web:~/projects/rails/guestbook2$ cap deploy:migrations * executing `deploy:migrations' * executing `deploy:update_code' updating the cached checkout on all servers executing locally: "git ls-remote [email protected]:/home/andrew/git/guestbook2.git master" Enter passphrase for key '/home/andrew/.ssh/id_dsa': * executing "if [ -d /var/www/dev/guestbook2/shared/cached-copy ]; then cd /var/www/dev/guestbook2/shared/cached-copy && git fetch origin && git reset --hard 369c5e04aaf83ad77efbfba0141001ac90915029 && git clean -d -x -f; else git clone [email protected]:/home/andrew/git/guestbook2.git /var/www/dev/guestbook2/shared/cached-copy && cd /var/www/dev/guestbook2/shared/cached-copy && git checkout -b deploy 369c5e04aaf83ad77efbfba0141001ac90915029; fi" servers: ["dev.andrewbucknell.com"] Enter passphrase for /home/andrew/.ssh/id_dsa: [dev.andrewbucknell.com] executing command ** [dev.andrewbucknell.com :: err] Permission denied, please try again. ** Permission denied, please try again. ** Permission denied (publickey,password). ** [dev.andrewbucknell.com :: err] fatal: The remote end hung up unexpectedly ** [dev.andrewbucknell.com :: out] Initialized empty Git repository in /var/www/dev/guestbook2/shared/cached-copy/.git/ command finished failed: "sh -c 'if [ -d /var/www/dev/guestbook2/shared/cached-copy ]; then cd /var/www/dev/guestbook2/shared/cached-copy && git fetch origin && git reset --hard 369c5e04aaf83ad77efbfba0141001ac90915029 && git clean -d -x -f; else git clone [email protected]:/home/andrew/git/guestbook2.git /var/www/dev/guestbook2/shared/cached-copy && cd /var/www/dev/guestbook2/shared/cached-copy && git checkout -b deploy 369c5e04aaf83ad77efbfba0141001ac90915029; fi'" on dev.andrewbucknell.com andrew@melb-web:~/projects/rails/guestbook2$ The following fragment is from cap -d deploy:migrations Preparing to execute command: "find /var/www/dev/guestbook2/releases/20100305124415/public/images /var/www/dev/guestbook2/releases/20100305124415/public/stylesheets /var/www/dev/guestbook2/releases/20100305124415/public/javascripts -exec touch -t 201003051244.22 {} ';'; true" Execute ([Yes], No, Abort) ? |y| yes * executing `deploy:migrate' * executing "ls -x /var/www/dev/guestbook2/releases" Preparing to execute command: "ls -x /var/www/dev/guestbook2/releases" Execute ([Yes], No, Abort) ? |y| yes /usr/lib/ruby/gems/1.8/gems/capistrano-2.5.17/lib/capistrano/recipes/deploy.rb:55:in `join': can't convert nil into String (TypeError) from /usr/lib/ruby/gems/1.8/gems/capistrano-2.5.17/lib/capistrano/recipes/deploy.rb:55:in `load'

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  • Casting To The Correct Subclass

    - by kap
    Hi Guys I hava a supeclass called Car with 3 subclasses. class Ford extends Car{ } class Chevrolet extends Car{ } class Audi extends Car{ } Now i have a function called printMessge(Car car) which will print a message of a particular car type. In the implementation i use if statements to test the instance of the classes like this. public int printMessge(Car car){ if((Ford)car instanceof Ford){ // print ford }else if((Chevrolet)car instanceof Chevrolet){ // print chevrolet }else if((Audi)car instanceof Audi){ // print Audi } } for instance if i call it for the first time with Ford printMessge(new Ford()), it prints the ford message but when i call it with printMessge(new Chevrolet()), i get EXCEPTION from the first if statement that Chevrolet cannot be cast to Ford. What am i doing wrong and what is the best way. thanks

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  • Synergy setup broke on upgrade

    - by CoatedMoose
    I had synergy setup working fine with version 1.3.7, however I got a new computer and decided to set it up as well. Because the setup I was working with was ubuntu (server - dual monitors) mac (client) and the new computer (replacing the mac) was windows, I ended up updating everything to 1.4.10. ______ ______ ______ | mac | ubu1 | ubu2 | |______|______|______| The problem is currently that dragging to the left of ubu1 causes the cursor on the mac to flicker briefly and then the cursor shows up at the bottom right corner of ubu2. Here is my .synergy.conf section: screens Andrews-Mac-Mini: ctrl = ctrl alt = meta super = alt Andrew-Ubuntu: end section: links Andrew-Ubuntu: left = Andrews-Mac-Mini Andrews-Mac-Mini: right = Andrew-Ubuntu end And the output from synergys -f NOTE: client "Andrews-Mac-Mini" has connected INFO: switch from "Andrew-Ubuntu" to "Andrews-Mac-Mini" at 1679,451 INFO: leaving screen INFO: screen "Andrew-Ubuntu" updated clipboard 0 INFO: screen "Andrew-Ubuntu" updated clipboard 1 INFO: switch from "Andrews-Mac-Mini" to "Andrew-Ubuntu" at 2398,833 INFO: entering screen

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  • Inserting Records in Ascending Order function- C homework assignment

    - by Aaron McRuer
    Good day, Stack Overflow. I have a homework assignment that I'm working on this weekend that I'm having a bit of a problem with. We have a struct "Record" (which contains information about cars for a dealership) that gets placed in a particular spot in a linked list according to 1) its make and 2) according to its model year. This is done when initially building the list, when a "int insertRecordInAscendingOrder" function is called in Main. In "insertRecordInAscendingOrder", a third function, "createRecord" is called, where the linked list is created. The function then goes to the function "compareCars" to determine what elements get put where. Depending on the value returned by this function, insertRecordInAscendingOrder then places the record where it belongs. The list is then printed out. There's more to the assignment, but I'll cross that bridge when I come to it. Ideally, and for the assignment to be considered correct, the linked list must be ordered as: Chevrolet 2012 25 Chevrolet 2013 10 Ford 2010 5 Ford 2011 3 Ford 2012 15 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2013 20 from the a text file that has the data ordered the following way: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Notice that the alphabetical order of the "make" field takes precedence, then, the model year is arranged from oldest to newest. However, the program produces this as the final list: Chevrolet 2012 25 Chevrolet 2013 10 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2012 20 Ford 2010 5 Ford 2011 3 Ford 2012 15 I sat down with a grad student and tried to work out all of this yesterday, but we just couldn't figure out why it was kicking the Ford nodes down to the end of the list. Here's the code. As you'll notice, I included a printList call at each instance of the insertion of a node. This way, you can see just what is happening when the nodes are being put in "order". It is in ANSI C99. All function calls must be made as they are specified, so unfortunately, there's no real way of getting around this problem by creating a more efficient algorithm. #include <stdio.h> #include <stdlib.h> #include <string.h> #define MAX_LINE 50 #define MAX_MAKE 20 typedef struct record { char *make; int year; int stock; struct record *next; } Record; int compareCars(Record *car1, Record *car2); void printList(Record *head); Record* createRecord(char *make, int year, int stock); int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock); int main(int argc, char **argv) { FILE *inFile = NULL; char line[MAX_LINE + 1]; char *make, *yearStr, *stockStr; int year, stock, len; Record* headRecord = NULL; /*Input and file diagnostics*/ if (argc!=2) { printf ("Filename not provided.\n"); return 1; } if((inFile=fopen(argv[1], "r"))==NULL) { printf("Can't open the file\n"); return 2; } /*obtain values for linked list*/ while (fgets(line, MAX_LINE, inFile)) { make = strtok(line, " "); yearStr = strtok(NULL, " "); stockStr = strtok(NULL, " "); year = atoi(yearStr); stock = atoi(stockStr); insertRecordInAscendingOrder(&headRecord,make, year, stock); } printf("The original list in ascending order: \n"); printList(headRecord); } /*use strcmp to compare two makes*/ int compareCars(Record *car1, Record *car2) { int compStrResult; compStrResult = strcmp(car1->make, car2->make); int compYearResult = 0; if(car1->year > car2->year) { compYearResult = 1; } else if(car1->year == car2->year) { compYearResult = 0; } else { compYearResult = -1; } if(compStrResult == 0 ) { if(compYearResult == 1) { return 1; } else if(compYearResult == -1) { return -1; } else { return compStrResult; } } else if(compStrResult == 1) { return 1; } else { return -1; } } int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock) { Record *previous = *head; Record *newRecord = createRecord(make, year, stock); Record *current = *head; int compResult; if(*head == NULL) { *head = newRecord; printf("Head is null, list was empty\n"); printList(*head); return 1; } else if ( compareCars(newRecord, *head)==-1) { *head = newRecord; (*head)->next = current; printf("New record was less than the head, replacing\n"); printList(*head); return 1; } else { printf("standard case, searching and inserting\n"); previous = *head; while ( current != NULL &&(compareCars(newRecord, current)==1)) { printList(*head); previous = current; current = current->next; } printList(*head); previous->next = newRecord; previous->next->next = current; } return 1; } /*creates records from info passed in from main via insertRecordInAscendingOrder.*/ Record* createRecord(char *make, int year, int stock) { printf("CreateRecord\n"); Record *theRecord; int len; if(!make) { return NULL; } theRecord = malloc(sizeof(Record)); if(!theRecord) { printf("Unable to allocate memory for the structure.\n"); return NULL; } theRecord->year = year; theRecord->stock = stock; len = strlen(make); theRecord->make = malloc(len + 1); strncpy(theRecord->make, make, len); theRecord->make[len] = '\0'; theRecord->next=NULL; return theRecord; } /*prints list. lists print.*/ void printList(Record *head) { int i; int j = 50; Record *aRecord; aRecord = head; for(i = 0; i < j; i++) { printf("-"); } printf("\n"); printf("%20s%20s%10s\n", "Make", "Year", "Stock"); for(i = 0; i < j; i++) { printf("-"); } printf("\n"); while(aRecord != NULL) { printf("%20s%20d%10d\n", aRecord->make, aRecord->year, aRecord->stock); aRecord = aRecord->next; } printf("\n"); } The text file you'll need for a command line argument can be saved under any name you like; here are the contents you'll need: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Thanks in advance for your help. I shall continue to plow away at it myself.

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  • Returning IEnumerable from an indexer, bad practice?

    - by fearofawhackplanet
    If I had a CarsDataStore representing a table something like: Cars -------------- Ford | Fiesta Ford | Escort Ford | Orion Fiat | Uno Fiat | Panda Then I could do IEnumerable<Cars> fords = CarsDataStore["Ford"]; Is this a bad idea? It's iconsistent with the other datastore objects in my api (which all have a single column PK indexer), and I'm guessing most people don't expect an indexer to return a collection in this situation.

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  • Has "Killer Game Programming in Java" by Andrew Davison been rendered useless? What new tutorial should I follow? [duplicate]

    - by BDillan
    This question already has an answer here: Killer Game Programming [Java 3D] outdated? 5 answers Its pathetic how it was created in 2005 not so long ago when the Java 3D 1.31 API was released. Now after downloading the source code off the books website and implementing it onto my work-space it cant run. (The 3D Shooter Ch. 23) I downloaded Java 3D 1.5 API, installed it- went back to my source code and javax.media ect.., and EVERY imported class within the game simply couldn't be resolved... they are all outdated.. Please do not say how its meant for a positive curvature in your game development skills. No ~ I got the book to understand how to code 3D textures/particle systems/games. Without seeing results how can I learn? If there is still hope for this book please tell me. Otherwise what other books match this one in Game Programming? This one was very well organized, documented and long. I am not looking for a 3D game prog. book on Java. Rather one that has the same reputation as this one but is a bit newer..

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  • Remove duplicates from a list of nested dictionaries

    - by user2924306
    I'm writing my first python program to manage users in Atlassian On Demand using their RESTful API. I call the users/search?username= API to retrieve lists of users, which returns JSON. The results is a list of complex dictionary types that look something like this: [ { "self": "http://www.example.com/jira/rest/api/2/user?username=fred", "name": "fred", "avatarUrls": { "24x24": "http://www.example.com/jira/secure/useravatar?size=small&ownerId=fred", "16x16": "http://www.example.com/jira/secure/useravatar?size=xsmall&ownerId=fred", "32x32": "http://www.example.com/jira/secure/useravatar?size=medium&ownerId=fred", "48x48": "http://www.example.com/jira/secure/useravatar?size=large&ownerId=fred" }, "displayName": "Fred F. User", "active": false }, { "self": "http://www.example.com/jira/rest/api/2/user?username=andrew", "name": "andrew", "avatarUrls": { "24x24": "http://www.example.com/jira/secure/useravatar?size=small&ownerId=andrew", "16x16": "http://www.example.com/jira/secure/useravatar?size=xsmall&ownerId=andrew", "32x32": "http://www.example.com/jira/secure/useravatar?size=medium&ownerId=andrew", "48x48": "http://www.example.com/jira/secure/useravatar?size=large&ownerId=andrew" }, "displayName": "Andrew Anderson", "active": false } ] I'm calling this multiple times and thus getting duplicate people in my results. I have been searching and reading but cannot figure out how to deduplicate this list. I figured out how to sort this list using a lambda function. I realize I could sort the list, then iterate and delete duplicates. I'm thinking there must be a more elegant solution. Thank you!

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  • How should I fix problems with file permissions while restoring from Time Machine?

    - by Andrew Grimm
    While restoring files from a Time Machine backup, I got the error message "The operation can’t be completed because you don’t have permission to access some of the items." because of problems with files in one folder. What's the safest way to deal with this? The folder in question has permissions like: Andrew-Grimms-MacBook-Pro:kmer agrimm$ pwd /Volumes/Time Machine Backups/Backups.backupdb/Andrew Grimm’s MacBook Pro/2010-12-09-224309/Macintosh HD/Users/agrimm/ruby/kmer Andrew-Grimms-MacBook-Pro:kmer agrimm$ ls -ltra total 6156896 drwxrwxrwx@ 19 agrimm staff 680 18 Jan 2008 Saccharomyces_cerevisiae -r--------@ 1 agrimm staff 60221852 4 Aug 2009 hs_ref_GRCh37_chrY.fa -r--------@ 1 agrimm staff 157488804 4 Aug 2009 hs_ref_GRCh37_chrX.fa (snip a few files) -r--------@ 1 agrimm staff 676063 27 Oct 2009 NC_001143.fna -rw-r--r--@ 1 agrimm staff 6148 23 Mar 2010 .DS_Store drwxr-xr-x@ 3 agrimm staff 1530 23 Mar 2010 . drwxr-xr-x@ 30 agrimm staff 1054 20 Nov 14:43 .. Is it ok to do sudo chmod, or is there a safer approach? Background: Files within the original folder on my computer also had weird permissions - I suspect I may have used sudo to copy some files from a thumbdrive onto my computer.

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  • Regular Expression Fill-Down

    - by richardtallent
    I have a plain text file something like this: Ford\tTaurus F-150 F-250 Toyota\tCamry Corsica In other words, a two-level hierarchy where the first child is on the same line as the parent, but subsequent children on lines following, distinguished from being a parent by a two-space prefix (\t above represents a literal tab in the text). I need to convert to this using RegEx: Ford\tTaurus Ford\tF-150 Ford\tF-250 Toyota\tCamry Toyota\tCorsica So, I need to capture the parent (text between \r\n and \t not starting with \s\s), and apply that in the middle of any \r\n\s\s found until the next parent. I have a feeling this can be done with some sort of nested groups, but I think I need more caffeine or something, can't seem to work out the pattern. (Using .NET with IgnoreWhitespace off and Multiline off)

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  • Easy Credential Caching for Git

    A common question since launching our Git support is whether there is a way to cache your username and password so you don’t have to enter it on every push.  Well thanks to Andrew Nurse from the ASP.Net team, there is now a great solution for this! Credential Caching in Windows to the Rescue Using the Git extension point for credential caching, Andrew created an integration into the Windows Credentials store. After installing git-credential-winstore instead of getting that standard prompt for a username/password, you will get a Windows Security prompt. From here your credentials for CodePlex will be stored securely within the Windows Credential Store. Setup The setup is pretty easy. Download the application from Andrew's git-credential-winstore project. Launch the executable and select yes to have it prompt for credentials. That's it. Make sure you are running the latest version of msysgit, since the credential's API is fairly new. Thanks to Andrew for sharing his work.  If you have suggestions or improvements you can fork the code here.

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  • ssh-agent on ubuntu rapidly restarts

    - by Santa Claus
    I am attempting to use ssh-agent on Ubuntu 13.10 so that I will not have to enter my passphrase to unlock a key every time I want to use ssh or git. As you can see below, ssh-agent appears to be restarting for some reason. These commends were executed within a period of less than 5 seconds: andrew@zaphod:~$ ssh-agent SSH_AUTH_SOCK=/tmp/ssh-pqm5J0s70NxG/agent.2820; export SSH_AUTH_SOCK; SSH_AGENT_PID=2821; export SSH_AGENT_PID; echo Agent pid 2821; andrew@zaphod:~$ ssh-agent SSH_AUTH_SOCK=/tmp/ssh-VpkOH2WKjT1M/agent.2822; export SSH_AUTH_SOCK; SSH_AGENT_PID=2823; export SSH_AGENT_PID; echo Agent pid 2823; andrew@zaphod:~$ ssh-agent SSH_AUTH_SOCK=/tmp/ssh-EQ6X9JHNiBOO/agent.2824; export SSH_AUTH_SOCK; SSH_AGENT_PID=2825; export SSH_AGENT_PID; echo Agent pid 2825; andrew@zaphod:~$ ssh-agent SSH_AUTH_SOCK=/tmp/ssh-8Iij8kFkaapz/agent.2826; export SSH_AUTH_SOCK; SSH_AGENT_PID=2827; export SSH_AGENT_PID; echo Agent pid 2827; andrew@zaphod:~$ My guess is that ssh-agent is crashing, but how would I know? What log file would it log to?

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  • counting unique values based on multiple columns

    - by gooogalizer
    I am working in google spreadsheets and I am trying to do some counting that takes into consideration cell values across multiple cells in each row. Here's my table: |AUTHOR| |ARTICLE| |VERSION| |PRE-SELECTED| ANDREW GOLF STREAM 1 X ANDREW GOLF STREAM 2 X ANDREW HURRICANES 1 JOHN CAPE COD 1 X JOHN GOLF STREAM 1 (Google doc here) Each person can submit multiple articles as well as multiple versions of the same article. Sometimes different people submit different articles that happen to be identically named (Andrew and John both submitted different articles called "Golf Stream"). Multiple versions written by the same person do not count as unique, but articles with the same title written by different people do count as unique. So, I am looking to find a formula that Counts the number of unique articles that have been submitted [4] (without having to manually create extra columns for doing CONCATS, if possible) It would also be great to find formulas that: Count the number of unique articles that have been pre-selected (marked "X" in "PRE-SELECTED" column) [2] Count the number of unique articles that have only 1 version [4] Count the number of unique articles that have more than 1 of their versions pre-selected 1 Thank you so much! Nikita

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  • New site – and a special offer

    - by Red Gate Software BI Tools Team
    SSAS Compare has a brand new website! The old page was thrown together in the way that most Red Gate labs sites tend to be — as experimental sites for experimental products. We’ve been developing SSAS Compare for a while now, so we decided it was time for something a bit prettier. The new site is mostly the work of Andrew, our marketing manager, who has all sorts of opinions about websites. One of the opinions Andrew has is that his photo should be on every site on the internet, or at least every Red Gate site on the internet, and that’s why his handsome visage now appears on the SSAS Compare page. Well, that isn’t quite true. According to Andrew, people download more software when they have photos of human beings to look at. We want as many people to try SSAS Compare as possible, so we got the team together for an intimate photoshoot directed by Red Gate’s resident recorder of light, Dom Reed (aka Mr Flibble). The photo will appear on the site as soon as Dom is finished photoshopping us into something more palatable, which is a big job. Until then, you’ll have to put up with Andrew. We’ve also used the new site to announce a special offer. Right now, SSAS Compare is still a free beta, but by signing up to our Early Access Program, you’ll get a 20% discount when we release SSAS Compare as a fully-fledged product. We’ll use your email address to send you news and updates about business intelligence tools from Red Gate (and nothing else). If that sounds good to you, go to the SSAS Compare site to sign up. By the way, the BI Tools team wasn’t the only thing Dom photographed last week. Remember Noemi’s blog about the flamenco dance? We’ll be at SQL Saturday in our home town of Cambridge this Saturday (8th September), handing out flyers of a distinctly Mediterranean flavour. If you’re attending, be sure to say hello!

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  • Free Online Performance Tuning Event

    - by Andrew Kelly
      On June 9th 2010 I will be showing several sessions related to performance tuning for SQL Server and they are the best kind because they are free :).  So mark your calendars. Here is the event info and URL: June 29, 2010 - 10:00 am - 3:00 pm Eastern SQL Server is the platform for business. In this day-long free virtual event, well-known SQL Server performance expert Andrew Kelly will provide you with the tools and knowledge you need to stay on top of three key areas related to peak performance...(read more)

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  • Oracle Text query parser

    - by Roger Ford
    Oracle Text provides a rich query syntax which enables powerful text searches.However, this syntax isn't intended for use by inexperienced end-users.  If you provide a simple search box in your application, you probably want users to be able to type "Google-like" searches into the box, and have your application convert that into something that Oracle Text understands.For example if your user types "windows nt networking" then you probably want to convert this into something like"windows ACCUM nt ACCUM networking".  But beware - "NT" is a reserved word, and needs to be escaped.  So let's escape all words:"{windows} ACCUM {nt} ACCUM {networking}".  That's fine - until you start introducing wild cards. Then you must escape only non-wildcarded searches:"win% ACCUM {nt} ACCUM {networking}".  There are quite a few other "gotchas" that you might encounter along the way.Then there's the issue of scoring.  Given a query for "oracle text query syntax", it would be nice if we could score a full phrase match higher than a hit where all four words are present but not in a phrase.  And then perhaps lower than that would be a document where three of the four terms are present.  Progressive relaxation helps you with this, but you need to code the "progression" yourself in most cases.To help with this, I've developed a query parser which will take queries in Google-like syntax, and convert them into Oracle Text queries. It's designed to be as flexible as possible, and will generate either simple queries or progressive relaxation queries. The input string will typically just be a string of words, such as "oracle text query syntax" but the grammar does allow for more complex expressions:  word : score will be improved if word exists  +word : word must exist  -word : word CANNOT exist  "phrase words" : words treated as phrase (may be preceded by + or -)  field:(expression) : find expression (which allows +,- and phrase as above) within "field". So for example if I searched for   +"oracle text" query +syntax -ctxcatThen the results would have to contain the phrase "oracle text" and the word syntax. Any documents mentioning ctxcat would be excluded from the results. All the instructions are in the top of the file (see "Downloads" at the bottom of this blog entry).  Please download the file, read the instructions, then try it out by running "parser.pls" in either SQL*Plus or SQL Developer.I am also uploading a test file "test.sql". You can run this and/or modify it to run your own tests or run against your own text index. test.sql is designed to be run from SQL*Plus and may not produce useful output in SQL Developer (or it may, I haven't tried it).I'm putting the code up here for testing and comments. I don't consider it "production ready" at this point, but would welcome feedback.  I'm particularly interested in comments such as "The instructions are unclear - I couldn't figure out how to do XXX" "It didn't work in my environment" (please provide as many details as possible) "We can't use it in our application" (why not?) "It needs to support XXX feature" "It produced an invalid query output when I fed in XXXX" Downloads: parser.pls test.sql

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