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  • Fraud and Anomaly Detection using Oracle Data Mining YouTube-like Video

    - by chberger
    I've created and recorded another YouTube-like presentation and "live" demos of Oracle Advanced Analytics Option, this time focusing on Fraud and Anomaly Detection using Oracle Data Mining.  [Note:  It is a large MP4 file that will open and play in place.  The sound quality is weak so you may need to turn up the volume.] Data is your most valuable asset. It represents the entire history of your organization and its interactions with your customers.  Predictive analytics leverages data to discover patterns, relationships and to help you even make informed predictions.   Oracle Data Mining (ODM) automatically discovers relationships hidden in data.  Predictive models and insights discovered with ODM address business problems such as:  predicting customer behavior, detecting fraud, analyzing market baskets, profiling and loyalty.  Oracle Data Mining, part of the Oracle Advanced Analytics (OAA) Option to the Oracle Database EE, embeds 12 high performance data mining algorithms in the SQL kernel of the Oracle Database. This eliminates data movement, delivers scalability and maintains security.  But, how do you find these very important needles or possibly fraudulent transactions and huge haystacks of data? Oracle Data Mining’s 1 Class Support Vector Machine algorithm is specifically designed to identify rare or anomalous records.  Oracle Data Mining's 1-Class SVM anomaly detection algorithm trains on what it believes to be considered “normal” records, build a descriptive and predictive model which can then be used to flags records that, on a multi-dimensional basis, appear to not fit in--or be different.  Combined with clustering techniques to sort transactions into more homogeneous sub-populations for more focused anomaly detection analysis and Oracle Business Intelligence, Enterprise Applications and/or real-time environments to "deploy" fraud detection, Oracle Data Mining delivers a powerful advanced analytical platform for solving important problems.  With OAA/ODM you can find suspicious expense report submissions, flag non-compliant tax submissions, fight fraud in healthcare claims and save huge amounts of money in fraudulent claims  and abuse.   This presentation and several brief demos will show Oracle Data Mining's fraud and anomaly detection capabilities.  

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  • Anomaly with bash PS1 definition

    - by Michael Wiles
    My root and admin user both have the same .bashrc file. The prompt section of the .bashrc is the following: if [ "$color_prompt" = yes ]; then PS1='${debian_chroot:+($debian_chroot)}\[\033[01;32m\]\u@\h\[\033[00m\]:\[\033[01;34m\]\w\[\033[00m\]\$ ' else PS1='${debian_chroot:+($debian_chroot)}\u@\h:\w\$ ' fi unset color_prompt force_color_prompt # If this is an xterm set the title to user@host:dir case "$TERM" in xterm*|rxvt*) PS1="\[\e]0;${debian_chroot:+($debian_chroot)}\u@\h: \w\a\]$PS1" ;; *) ;; esac But the problem is that the admin user and root user have different prompts. admin's prompt is: admin@hostname:~$ and root's prompt is root@hostname:/home# So it seems root is using the "xterm" version and admin is not. Why does the .bashrc file have this difference in prompts? How do I get the admin user to also use the xterm version? How would I test that condition? If I run echo $TERM while running as the admin user I get xterm so as far as I can tell, it should be using the xterm version for the admin user.

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  • Wall jumping collision detection anomaly

    - by Nanor
    I'm creating a game where the player ascends a tower by wall jumping his way to the top. When the player has collided with the right wall they can only jump left and vice versa. Here is my current implementation: if(wallCollision() == "left"){ player.setPosX(0); player.setVelX(0); ignoreCollisions = true; player.setCanJump(true); player.setFacingLeft(false); } else if (wallCollision() == "right"){ player.setPosX(screenWidth-playerWidth*2); player.setVelX(0); ignoreCollisions = true; player.setCanJump(true); player.setFacingLeft(true); } else{ player.setVelY(player.getVelY() + gravity); } and private String wallCollision(){ if(player.getPosX() < playerWidth && !ignoreCollisions) return "left"; else if(player.getPosX() > screenWidth - playerWidth*2 && !ignoreCollisions) return "right"; else{ timeToJump += Gdx.graphics.getDeltaTime(); if(timeToJump > 0.50f){ timeToJump = 0; ignoreCollisions = false; } return "jumping"; } } If the player is colliding with the left wall it will switch between the states left and jumping repeatedly due to the varible ignoreCollisions being switched repeatedly in collision checks. This will give a chance to either jump as intended or simply ascend vertically instead of diagonally. I can't figure out an implementation that will reliably make sure the player jumps as intended. Does anyone have any pointers?

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  • Windows EFS file sharing anomaly

    - by wbkang
    Fyi, I can confirm this happening in Windows Vista (Business) and Windows 7 Professional in WORKGROUP mode (as both a client and a server). I am not totally sure if this is a Superuser question or a ServerFault question. So there are two PCs, let's call them C (client) and S (server). Both servers have a user called U with the same password. Both C and S has the same private/public key pair for EFS. S shares a folder F with U given full permission. Also locally, the user U has the full permission on F. Now, U, from C, connects to F at the server S, everything works totally fine. I can read,write, delete files and create/delete folders in S. Things go weird from here. I encrypt the folder F in S. I can delete/modify files fine (so the files in F decrypted OK). However, U from C, cannot create a folder, or create a file getting Access Denied. But this Access Denied is very special. It takes over 10 seconds at C to receive the error and the explorer freezes while trying to create a folder, eventually returning error. In S, I can watch the folder created at the same time, and what I see is "New Folder" blinking like crazy and eventually disappearing when the client receives the error. i.e. it's created and deleted in a really rapid manner. What I do not understand is that permissions look fine, I can modify/delete files, and it looks like there is no problem with EFS because I can read/write files fine. Yet it fails to create a file or a folder. Any help is appreciated. Thanks, wbkang

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  • data transfer rate anomaly (internet)

    - by Nrew
    I tested my internet speed at speedtest.net. And go the result. .42Mbps Download and .21 Upload rate. My classmate got the same download speed of .42Mbps but has .87Mbps upload rate. Does upload rate affect the transfer rate?Because even though we got the same download speed. His transfer rate is about 100kbps downloading a movie from a torrent. And mine is only about 47kbps. Also the same torrent. And even direct download its always 47kbps. Is it possible to tweak something in order to have higher transfer rates. Other details: Were also both using the same ISP. The same slow ISP. And it seems that he's getting the most out of his connection even if his plan is lower than mine. I just don't know why I'm a loser at this. And when I try to complain to the ISP. They say that I'm getting the minimum speed and its okay. That really sucks. And I'm not using any router, so is he. The computer is directly connected to the internet using the modem provided by the ISP.

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  • Lost Update Anomaly in Sql Server Update Command

    - by Javed
    Hi, I am very much confused. I have a transaction in ReadCommitted Isolation level. Among other things I am also updating a counter value in it, something similar to below: Update tblCount set counter = counter + 1 My application is a desktop application and this transaction happens to occur quite frequently and concurrently. We recently noticed an error that sometimes the counter value doesn't get updated or is missed. We also insert one record on each counter update so we are sure that records have been inserted but somehow counter fails to update. This happens once in 2000 simulaneous transactions. I seriously doubt it is a lost update anomaly I am facing but if you look at the command above, it's just update the counter from its own value: if I have started a transaction and the transaction has reached this statement, it should have locked the row. This should not cause lost update, but it's happening somehow. Is the thing that this update command works in two parts? Like first it reads the counter value (during which it doesn't get the exclusive lock) and then writes the new calculated value (when it does get an exclusive lock)? Please help, I have got really confused.

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  • Temperature anomaly calculation of time series data

    - by neel
    I have a time series like following: Data <- structure(list(Year = c(1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1991L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L, 1992L), Month = c(8L, 9L, 9L, 9L, 10L, 10L, 10L, 11L, 11L, 11L, 12L, 12L, 12L, 1L, 1L, 1L, 2L, 2L, 2L, 3L, 3L, 3L, 4L, 4L, 4L, 5L, 5L, 5L, 6L, 6L, 6L, 7L, 7L, 7L, 8L, 8L, 8L, 9L, 9L, 9L, 10L, 10L, 10L, 11L, 11L, 11L, 12L, 12L, 12L), Day = c(30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 28L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L, 10L, 20L, 30L), Hour = c(0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L, 0L), temperature = c(72.5, 64, 62.5, 64, 64, 53, 52, 52, 45.5, 49, 50, 50, 59, 63.5, 69.5, 61, 61, NaN, NaN, 39.5, 37, 45.5, 45, 39, 43.5, 52, 53, 56, 64, 66, 66.5, 73.5, 81, 85, 89.5, 87.5, 88.5, 83, 84.5, 74, 60.5, 59, 53, 60.5, 62.5, 64.5, 63, 62, 65.5)), .Names = c("Year", "Month", "Day", "Hour", "temperature"), class = "data.frame", row.names = c(NA, -49L)) and I have to calculate standardized anomaly. The steps to calculate the anomalies are following: Monthly premature departures from the long-term (1991-2007) average are obtained. Then standardized by dividing by the standard deviation of monthly temperature. The standardized monthly anomalies are then weighted by multiplying by the fraction of the average temperature for the given month. These weighted anomalies are then summed over 3 month time period. Can you please help me?

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  • Very weird C file-handling anomaly

    - by KáGé
    Hello, I got a very weird issue that I cant figure out in my school project, which is the simulation of a simple filesystem in a human-readable textfile. Unfortunately I don't yet have enough time to translate the comments in my code or make it less gibberish, so if you are bothered by that, you don't have to help, I understand. See the code HERE. Now in drive.h, at line 574 is this part: i = getline(); #ifdef DEBUG printf("Free space in all found at %d.\n\n", i); if(drive.disk != NULL){ printf("Disk OK\n\n"); } #endif //write in data state = seekline(i); Before this it finds place for the allocation database entry in the ALL sector (see the "image files" in the mounts folder, this issue was tested on mount_30.efs-dbf), then gets the line with i = getline() fine (getline is in lglobal.h, line 39), but after that any file manipulation (in this case seekline's fseek, but if I comment that out, then the first fprintf after that) crashes the program straight away. I think the file gets somehow corrupted (though the Disk OK message appears) but can't figure out how. I've tried putting i = getline(); into comment, but it didn't make any difference. I've also tried asking at local programming forums but they didn't really help either. The last few lines of the output before it crashes: Dir written. (drive.h line 562) Seekline entered: 268 (called at drive.h line 564) Getline entered. (called at drive.h line 574) Line got: 268. Free space in all found at 268. (drive.h line 576) Seekline entered: 268 (called at drive.h line 582, note that this exact call was run successfully less than 20 lines back. This one should set the pointer to the beginning of the line it is currently in) After this it crashes. Does anyone has any idea of what causes this and how could I fix it? Thank you.

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  • Cocoa window position anomaly

    - by Marius
    Hello everyone, I have a weird problem with positioning a window on screen. I want to center the window on the screen, but i don't know how to do that. Here's what i've got. The window is created from nib by the main controller: IdentFormController *ftf = [[IdentFormController alloc] initWithWindowNibName:@"IdentForm"]; [[ftf window] makeKeyAndOrderFront:self]; Now the IdentFormController has awakeFromNib() method in which it tries to position the window. For the sake of simplicity i've just tried to do setFrameOrigin(NSMakePoint(0, 0)). What happens is as follows: The first time i create this window, everything works as expected. But if i create it again after releasing the previous, it starts appearing at random positions. Why does it do that?

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  • printf anomaly after "fork()"

    - by pechenie
    OS: Linux, Language: pure C I'm moving forward in learning C progpramming in general, and C programming under UNIX in a special case :D So, I detected a strange (as for me) behaviour of the printf() function after using a fork() call. Let's take a look at simple test program: #include <stdio.h> #include <system.h> int main() { int pid; printf( "Hello, my pid is %d", getpid() ); pid = fork(); if( pid == 0 ) { printf( "\nI was forked! :D" ); sleep( 3 ); } else { waitpid( pid, NULL, 0 ); printf( "\n%d was forked!", pid ); } return 0; } In this case the output looks like: Hello, my pid is 1111 I was forked! :DHello, my pid is 1111 2222 was forked! Why the second "Hello" string occured in the child's output? Yes, it is exactly what the parent printed on it's start, with the parent's pid. But! If we place '\n' character in the end of each string we got the expected output: #include <stdio.h> #include <system.h> int main() { int pid; printf( "Hello, my pid is %d\n", getpid() ); // SIC!! pid = fork(); if( pid == 0 ) { printf( "I was forked! :D" ); //removed the '\n', no matter sleep( 3 ); } else { waitpid( pid, NULL, 0 ); printf( "\n%d was forked!", pid ); } return 0; } And the output looks like: Hello, my pid is 1111 I was forked! :D 2222 was forked! Why does it happen? Is it ... ummm ... correct behaviour? Or it's a kind of the 'bug'?

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  • backbonejs remove anomaly concept

    - by user1537158
    I was building a small app for adding and deleting li from ul using Backbonejs.One of the SO members cymen helped me code it, using that i tailored the code a little.currently if i add one element and delete , it works , but the second time i add an element (to ul) and go to delete it , i get Uncaught TypeError: Cannot call method 'remove' of undefined Pasting my code here , HTML : <input type="text" id="name"> <button id="add">Add</button> <ul id="mylist"></ul> JS: $(function(){ var myCollection = Backbone.Collection.extend(); var myView = Backbone.View.extend({ el:$('body'), tagName:'li', initialize : function(e){ this.collection.bind("add",this.render,this); this.collection.bind("remove",this.render,this); }, events:{ 'click #add' : 'addfoo' }, addfoo : function(){ var myname= $('#name').val(); $('#name').val(''); this.collection.add({name:myname}); }, render : function(){ $('#mylist').empty(); this.collection.each(function(model){ console.log("myView"); var remove = new myRemoveView({model:model}); remove.render(); }); } }); var myRemoveView = Backbone.View.extend({ el:$('body'), events:{ 'click .button':'removeFoo' }, removeFoo : function(){ console.log("here"); this.model.collection.remove(this.model); }, render : function(){ console.log("second view"); $('#mylist').append('<li>'+this.model.get('name') + "<button class='button'>"+"delete"+"</button></li>"); return; } }); var view = new myView({collection: new myCollection()}); }); Two things i did not understand : i) in the removeFoo function , we write this.model.collection.remove(this.model) shouldnt this have been this.collection.model.remove , something of that sort ? ii) i add a li to ul , then i delete it , when i add another li (appending to ul works perfect) but this time when i go to delete it throws me the above error : Uncaught TypeError :cannot call method 'remove' of undefined can you please help me figure out these 2 doubts in my code , btw SO member cymen's code works like a charm only my tailored code (above) is giving me errors. SO member cymen's code : JS Fiddle for his code Thank you

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  • If I can take a screen capture of a graphical anomaly, can it still be a hardware issue?

    - by Jay Carr
    I have a strange graphical anomaly going on my iMac right now (green and magenta boxes are appearing sporadically), I'm slowly trying to work through different possibilities but I thought I'd start with the basics: Can a graphical anomaly that I can screen capture still be a hardware issue? I know, it seems really obvious. If it's hardware, it should show up well after the operating system has had it's say. And since the operating system is (I assume) doing the screen capture, it seems like it shouldn't see the anomaly unless the problem is software in nature. But, as I've researched this problem I see a lot of people taking their computers in to service people for hardware issues and Apple then resolving said issue. To further complicate things, I also have Windows 8 installed via bootcamp, and the issues seems to be showing up there as well. Anyway, it feels like it must be a driver issue, since I assume that's what the two OSes have in common, but...I thought I'd come here for some disambiguation. In my case, yes, I can screen capture the anomaly (at least in OSX I can), so I assume it's somehow a software (or driver) issue. But I wanted to double check because the internet is being ambiguous...

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  • Why are part-time jobs in programming an anomaly?

    - by Mikle
    I've recently quit my full time developing job at mega-corp, and I decided that I'll look for a part time job. Since then I've talked to half a dozen potential employers, and every one of them had the same reaction when I said the magic words "part-time" - they all closed up and became suspicious. Now, I understand that it might just be me, so as control I asked every one of them what if I were willing to work full time, and they all said I would probably get an offer. My question is two fold: Why, as an employer, would you give up a competent, even great, developer, simply because he wants to work 3 days a week and not 5? How do I sell the story of part time job better? I usually just list my reasons which are that I prefer that balance currently in my life and that I want to work on my own projects, but it leaves them even more suspicious - am I going to start something myself and quit? Am I just lazy?

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  • Running 32 bit assembly code on a 64 bit Linux & 64 bit Processor : Explain the anomaly.

    - by claws
    Hello, I'm in an interesting problem.I forgot I'm using 64bit machine & OS and wrote a 32 bit assembly code. I don't know how to write 64 bit code. This is the x86 32-bit assembly code for Gnu Assembler (AT&T syntax) on Linux. //hello.S #include <asm/unistd.h> #include <syscall.h> #define STDOUT 1 .data hellostr: .ascii "hello wolrd\n"; helloend: .text .globl _start _start: movl $(SYS_write) , %eax //ssize_t write(int fd, const void *buf, size_t count); movl $(STDOUT) , %ebx movl $hellostr , %ecx movl $(helloend-hellostr) , %edx int $0x80 movl $(SYS_exit), %eax //void _exit(int status); xorl %ebx, %ebx int $0x80 ret Now, This code should run fine on a 32bit processor & 32 bit OS right? As we know 64 bit processors are backward compatible with 32 bit processors. So, that also wouldn't be a problem. The problem arises because of differences in system calls & call mechanism in 64-bit OS & 32-bit OS. I don't know why but they changed the system call numbers between 32-bit linux & 64-bit linux. asm/unistd_32.h defines: #define __NR_write 4 #define __NR_exit 1 asm/unistd_64.h defines: #define __NR_write 1 #define __NR_exit 60 Anyway using Macros instead of direct numbers is paid off. Its ensuring correct system call numbers. when I assemble & link & run the program. $cpp hello.S hello.s //pre-processor $as hello.s -o hello.o //assemble $ld hello.o // linker : converting relocatable to executable Its not printing helloworld. In gdb its showing: Program exited with code 01. I don't know how to debug in gdb. using tutorial I tried to debug it and execute instruction by instruction checking registers at each step. its always showing me "program exited with 01". It would be great if some on could show me how to debug this. (gdb) break _start Note: breakpoint -10 also set at pc 0x4000b0. Breakpoint 8 at 0x4000b0 (gdb) start Function "main" not defined. Make breakpoint pending on future shared library load? (y or [n]) y Temporary breakpoint 9 (main) pending. Starting program: /home/claws/helloworld Program exited with code 01. (gdb) info breakpoints Num Type Disp Enb Address What 8 breakpoint keep y 0x00000000004000b0 <_start> 9 breakpoint del y <PENDING> main I tried running strace. This is its output: execve("./helloworld", ["./helloworld"], [/* 39 vars */]) = 0 write(0, NULL, 12 <unfinished ... exit status 1> Explain the parameters of write(0, NULL, 12) system call in the output of strace? What exactly is happening? I want to know the reason why exactly its exiting with exitstatus=1? Can some one please show me how to debug this program using gdb? Why did they change the system call numbers? Kindly change this program appropriately so that it can run correctly on this machine. EDIT: After reading Paul R's answer. I checked my files claws@claws-desktop:~$ file ./hello.o ./hello.o: ELF 64-bit LSB relocatable, x86-64, version 1 (SYSV), not stripped claws@claws-desktop:~$ file ./hello ./hello: ELF 64-bit LSB executable, x86-64, version 1 (SYSV), statically linked, not stripped All of my questions still hold true. What exactly is happening in this case? Can someone please answer my questions and provide an x86-64 version of this code?

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  • Running 32 bit assembly code on a 64 bit Linux & 64 bit Processor : Expalin the anomaly.

    - by claws
    Hello, I'm in an interesting problem.I forgot I'm using 64bit machine & OS and wrote a 32 bit assembly code. I don't know how to write 64 bit code. This is the x86 32-bit assembly code for Gnu Assembler (AT&T syntax) on Linux. #include <asm/unistd.h> #include <syscall.h> #define STDOUT 1 .data hellostr: .ascii "hello wolrd\n"; helloend: .text .globl _start _start: movl $(SYS_write) , %eax //ssize_t write(int fd, const void *buf, size_t count); movl $(STDOUT) , %ebx movl $hellostr , %ecx movl $(helloend-hellostr) , %edx int $0x80 movl $(SYS_exit), %eax //void _exit(int status); xorl %ebx, %ebx int $0x80 ret Now, This code should run fine on a 32bit processor & 32 bit OS right? As we know 64 bit processors are backward compatible with 32 bit processors. So, that also wouldn't be a problem. The problem arises because of differences in system calls & call mechanism in 64-bit OS & 32-bit OS. I don't know why but they changed the system call numbers between 32-bit linux & 64-bit linux. asm/unistd_32.h defines: #define __NR_write 4 #define __NR_exit 1 asm/unistd_64.h defines: #define __NR_write 1 #define __NR_exit 60 Anyway using Macros instead of direct numbers is paid off. Its ensuring correct system call numbers. when I assemble & link & run the program. Its not printing helloworld. In gdb its showing: Program exited with code 01. I don't know how to debug in gdb. using tutorial I tried to debug it and execute instruction by instruction checking registers at each step. its always showing me "program exited with 01". It would be great if some on could show me how to debug this. (gdb) break _start Note: breakpoint -10 also set at pc 0x4000b0. Breakpoint 8 at 0x4000b0 (gdb) start Function "main" not defined. Make breakpoint pending on future shared library load? (y or [n]) y Temporary breakpoint 9 (main) pending. Starting program: /home/claws/helloworld Program exited with code 01. (gdb) info breakpoints Num Type Disp Enb Address What 8 breakpoint keep y 0x00000000004000b0 <_start> 9 breakpoint del y <PENDING> main I tried running strace. This is its output: execve("./helloworld", ["./helloworld"], [/* 39 vars */]) = 0 write(0, NULL, 12 <unfinished ... exit status 1> Explain the parameters of write(0, NULL, 12) system call in the output of strace? What exactly is happening? I want to know the reason why exactly its exiting with exitstatus=1? Can some one please show me how to debug this program using gdb? Why did they change the system call numbers? Change this program appropriately so that it can run correctly on this machine.

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  • Android Activity access Unity Classes

    - by Anomaly
    I have made my own C# classes in Unity, is there any way I can access these classes from the Android Activity that starts the UnityPlayer? Example: I have a C# class called testClass in Unity: class testClass{ public static string myString="test string"; } From the Android activity in Java I want to access that class: string str=testClass.myString; Is this possible? If so, how? Or is there some other way to do this? In the end I basically want to communicate between my Android activity and the UnityPlayer object. Thanks in advance. EDIT: Ok so I looked at building Android plugins for Unity but this wasn't satisfactory to me. I ended up building a socket client-server interface in Unity with C# and another one in Java for the Android app: So Unity listens on port X and broadcasts on port Y The Android activity listens on port Y and broadcasts on port X This is necessary as both interfaces are running on the same host. So that's how I solved my problem, but I'm open for any suggestions if anyone knows a better way of communicating between the Unityplayer and your app.

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  • Reading Hindi (Devanagari) on Windows XP SP1

    - by user31670
    Pretty much all the text that I have read on enabling Hindi (Complex Text Rendering) involve enabling it via Regional Settings Languages Install files for complex script support and left to right languages (including Thai). However, I am able to read Wikipedia without having this feature enabled. Is this normal or is this an anomaly with my Win XP SP1 CD?

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  • If Expression True in Immediate Window But Code In if Block Never Runs

    - by Julian
    I set a break point in my code in MonoDevelop to break whenever I click on a surface. I then enter the immediate window and test to see if the the if statement will return true in comparing two Vector3's. It does return true. However, when I step over, the code is never run as though the statement evaluated false. Does anyone know how this could be possible? I've attached a screenshot. Here is the picture of my debug window and immediate window. You can see where the immediate window evaluates to true. The second breakpoint is not hit. Here are the details of the two Vector3's I am comparing. Does anyone know why I am experiencing this? It really seems like an anomaly to me :/ Does it have something to do with threading?

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  • Downgrade to LTS version, preserving /home partition: Should I expect this to work?

    - by Archelon
    Specifically, I'm installing Kubuntu 12.04 over 13.04. And in fact I've already done it, and it seems to have at least mostly worked, but I'm wondering whether this one anomaly is likely to be attributable to the downgrade; to wit: I have no window borders|decorations, but only wide, featureless, white---or sometimes black---margins around all my windows. None of the settings in System Settings (the window border and decorations options are in Workspace Appearance) seem to have any effect. Is this likely to be fixable, or should I cut my losses and reinstall (formatting the /home partition and restoring any data with rsync)?

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  • Permits in iPhone apps

    - by zp26
    HI, I want to create i file in the iPhone application. I try it but i have a anomaly. In my pc the file is correctly written. In other pc with the same program the file wasn't exist. In the iPhone device the file not exist. But the strange think thing is that i haven't any error for the app in the all case. Do you have a idea? Thanks so much

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  • Most efficient way to draw circles for polygon outlines

    - by user146780
    I'm using OpenGL and was told I should draw circles at each vertex of my outline to get smoothness. I tried this and it works great. The problem is speed. It crippled my application to draw a circle at each vertex. I'm not sure how else to fix the anomaly of my outlines other than circles, but using display lists and trying with vertex array both were brutally slow. Thanks

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  • problem connecting to datasource defined in freetds.conf

    - by pkaeding
    I can connect successfully to my database using tsql when I bypass the freetds.conf file, like so: % TDSVER=8.0 tsql -H 10.100.102.202 -p 1086 -U sa After I enter my password, I am presented with a 1> prompt, and it is ready for my commands. However, if I try to connect using the definition in my freetds.conf file, like this: % tsql -S Millie -U sa after entering my password, it seems to be trying to generate a prompt, but it just keeps counting. I will see 1, followed by 2, etc, without ever displaying a > character. Here is what I have for my freetds.conf: [global] # TDS protocol version tds version = 8.0 text size = 64512 [Millie] host = 10.100.102.202 port = 1086 What could be causing this anomaly? If it helps, here is the output of tsql -C: % tsql -C Compile-time settings (established with the "configure" script) Version: freetds v0.82 freetds.conf directory: /usr/local/etc MS db-lib source compatibility: no Sybase binary compatibility: no Thread safety: yes iconv library: yes TDS version: 5.0 iODBC: no unixodbc: no

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  • Configuring IIS 7.5 to be FIPS 140.2 compliant

    - by tomfanning
    I need to configure IIS 7.5 (Server 2008 R2) to be FIPS 140.2 compliant. Specifically, this involves disabling all SSL protocols other than TLS 1.0. I have set the following registry keys: HKLM\SYSTEM\CurrentControlSet\Control\SecurityProviders\SCHANNEL\Protocols\SSL 2.0\Server HKLM\SYSTEM\CurrentControlSet\Control\SecurityProviders\SCHANNEL\Protocols\SSL 3.0\Server HKLM\SYSTEM\CurrentControlSet\Control\SecurityProviders\SCHANNEL\Protocols\PCT 1.0\Server to Enabled(DWORD) = 0 as per this KB, but SSL Labs' checker says "SSL 2.0+ Upgrade Support" is enabled. (Everything other than that and TLS 1.0 is not available, so we're getting somewhere). It also says "FIPS ready - no" - presumably because SSL 2.0+ Upgrade Support is still enabled. serversniff.net says SSL 2.0 is turned off, and doesn't say anything about SSL 2.0+ Upgrade Support. Could this be an anomaly with SSL Labs' checker?

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  • can Snort be installed on VPS?

    - by jack
    Hi Linux Admins I want the maximum security for my linux vps. I found many tutorials round the net but it doesn't cover the Snort. Only those like portentry, logsentry, tripwire and so on. So I'm beginning to think that Snort is not appropriate for a linux host. I think it's suitable only as a proxy/middle-man that checks traffic before passing to acutual targets. I'd like to whether Snort can be installed on VPS which serves typical servers like web/mail. Can Snort be in complict with OSSEC which I think it doesn't check the traffic but the log files only for Intrusion Detection/Anomaly? Thank you.

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  • MongoDB REST interface not listening after update

    - by Ones and Zeroes
    I replaced the mongodb-10gen install with the Ubuntu package (mongodb-server, mongodb-client and dev). apt-get install mongodb Thereafter, I am now unable to connect to the REST interface, where it worked before. Doing a wget to http://127.0.0.1:27018, I receive the following response: Connecting to 127.0.0.1:27018... failed: Connection refused. My previous /etc/mongodb.conf file had the following in: #enable REST rest = true Adding it to the packaged conf file does not resolve the issue, not even after restarting. I also tried changing the following with no effect: # Disable the HTTP interface (Defaults to localhost:27018). # nohttpinterface = true to # Disable the HTTP interface (Defaults to localhost:27018). nohttpinterface = false I have searched for days, and there doesn't seem to be anything on the Mongo site about a similar anomaly. If you have encountered a similar issue on Ubuntu Oneiric, please add your comments, even if you haven't found a solution to this issue.

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