Search Results

Search found 563 results on 23 pages for 'c1'.

Page 1/23 | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

• Nesting Linq-to-Objects query within Linq-to-Entities query –what is happening under the covers?

  - by carewithl

  var numbers = new int[] { 1, 2, 3, 4, 5 }; var contacts = from c in context.Contacts where c.ContactID == numbers.Max() | c.ContactID == numbers.FirstOrDefault() select c; foreach (var item in contacts) Console.WriteLine(item.ContactID); Linq-to-Entities query is first translated into Linq expression tree, which is then converted by Object Services into command tree. And if Linq-to-Entities query nests Linq-to-Objects query, then this nested query also gets translated into an expression tree. a) I assume none of the operators of the nested Linq-to-Objects query actually get executed, but instead data provider for particular DB (or perhaps Object Services) knows how to transform the logic of Linq-to-Objects operators into appropriate SQL statements? b) Data provider knows how to create equivalent SQL statements only for some of the Linq-to-Objects operators? c) Similarly, data provider knows how to create equivalent SQL statements only for some of the non-Linq methods in the Net Framework class library? EDIT: I know only some Sql so I can't be completely sure, but reading Sql query generated for the above code it seems data provider didn't actually execute numbers.Max method, but instead just somehow figured out that numbers.Max should return the maximum value and then proceed to include in generated Sql query a call to TSQL's build-in MAX function. It also put all the values held by numbers array into a Sql query. SELECT CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN '0X0X' ELSE '0X1X' END AS [C1], [Extent1].[ContactID] AS [ContactID], [Extent1].[FirstName] AS [FirstName], [Extent1].[LastName] AS [LastName], [Extent1].[Title] AS [Title], [Extent1].[AddDate] AS [AddDate], [Extent1].[ModifiedDate] AS [ModifiedDate], [Extent1].[RowVersion] AS [RowVersion], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[CustomerTypeID] END AS [C2], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[InitialDate] END AS [C3], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[PrimaryDesintation] END AS [C4], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[SecondaryDestination] END AS [C5], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[PrimaryActivity] END AS [C6], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[SecondaryActivity] END AS [C7], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[Notes] END AS [C8], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[RowVersion] END AS [C9], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[BirthDate] END AS [C10], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[HeightInches] END AS [C11], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[WeightPounds] END AS [C12], CASE WHEN (([Project1].[C1] = 1) AND ([Project1].[C1] IS NOT NULL)) THEN [Project1].[DietaryRestrictions] END AS [C13] FROM [dbo].[Contact] AS [Extent1] LEFT OUTER JOIN (SELECT [Extent2].[ContactID] AS [ContactID], [Extent2].[BirthDate] AS [BirthDate], [Extent2].[HeightInches] AS [HeightInches], [Extent2].[WeightPounds] AS [WeightPounds], [Extent2].[DietaryRestrictions] AS [DietaryRestrictions], [Extent3].[CustomerTypeID] AS [CustomerTypeID], [Extent3].[InitialDate] AS [InitialDate], [Extent3].[PrimaryDesintation] AS [PrimaryDesintation], [Extent3].[SecondaryDestination] AS [SecondaryDestination], [Extent3].[PrimaryActivity] AS [PrimaryActivity], [Extent3].[SecondaryActivity] AS [SecondaryActivity], [Extent3].[Notes] AS [Notes], [Extent3].[RowVersion] AS [RowVersion], cast(1 as bit) AS [C1] FROM [dbo].[ContactPersonalInfo] AS [Extent2] INNER JOIN [dbo].[Customers] AS [Extent3] ON [Extent2].[ContactID] = [Extent3].[ContactID]) AS [Project1] ON [Extent1].[ContactID] = [Project1].[ContactID] LEFT OUTER JOIN (SELECT TOP (1) [c].[C1] AS [C1] FROM (SELECT [UnionAll3].[C1] AS [C1] FROM (SELECT [UnionAll2].[C1] AS [C1] FROM (SELECT [UnionAll1].[C1] AS [C1] FROM (SELECT 1 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable1] UNION ALL SELECT 2 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable2]) AS [UnionAll1] UNION ALL SELECT 3 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable3]) AS [UnionAll2] UNION ALL SELECT 4 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable4]) AS [UnionAll3] UNION ALL SELECT 5 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable5]) AS [c]) AS [Limit1] ON 1 = 1 LEFT OUTER JOIN (SELECT TOP (1) [c].[C1] AS [C1] FROM (SELECT [UnionAll7].[C1] AS [C1] FROM (SELECT [UnionAll6].[C1] AS [C1] FROM (SELECT [UnionAll5].[C1] AS [C1] FROM (SELECT 1 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable6] UNION ALL SELECT 2 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable7]) AS [UnionAll5] UNION ALL SELECT 3 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable8]) AS [UnionAll6] UNION ALL SELECT 4 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable9]) AS [UnionAll7] UNION ALL SELECT 5 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable10]) AS [c]) AS [Limit2] ON 1 = 1 CROSS JOIN (SELECT MAX([UnionAll12].[C1]) AS [A1] FROM (SELECT [UnionAll11].[C1] AS [C1] FROM (SELECT [UnionAll10].[C1] AS [C1] FROM (SELECT [UnionAll9].[C1] AS [C1] FROM (SELECT 1 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable11] UNION ALL SELECT 2 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable12]) AS [UnionAll9] UNION ALL SELECT 3 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable13]) AS [UnionAll10] UNION ALL SELECT 4 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable14]) AS [UnionAll11] UNION ALL SELECT 5 AS [C1] FROM (SELECT 1 AS X) AS [SingleRowTable15]) AS [UnionAll12]) AS [GroupBy1] WHERE [Extent1].[ContactID] IN ([GroupBy1].[A1], (CASE WHEN ([Limit1].[C1] IS NULL) THEN 0 ELSE [Limit2].[C1] END)) Based on this, is it possible that Linq2Entities provider indeed doesn't execute non-Linq and Linq-to-Object methods, but instead creates equivalent SQL statements for some of them ( and for others it throws an exception )? Thank you in advance

  Read the article

• Basics of Join Factorization

  - by Hong Su

  We continue our series on optimizer transformations with a post that describes the Join Factorization transformation. The Join Factorization transformation was introduced in Oracle 11g Release 2 and applies to UNION ALL queries. Union all queries are commonly used in database applications, especially in data integration applications. In many scenarios the branches in a UNION All query share a common processing, i.e, refer to the same tables. In the current Oracle execution strategy, each branch of a UNION ALL query is evaluated independently, which leads to repetitive processing, including data access and join. The join factorization transformation offers an opportunity to share the common computations across the UNION ALL branches. Currently, join factorization only factorizes common references to base tables only, i.e, not views. Consider a simple example of query Q1. Q1:    select t1.c1, t2.c2    from t1, t2, t3    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2   union all    select t1.c1, t2.c2    from t1, t2, t4    where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3; Table t1 appears in both the branches. As does the filter predicates on t1 (t1.c1 > 1) and the join predicates involving t1 (t1.c1 = t2.c1). Nevertheless, without any transformation, the scan (and the filtering) on t1 has to be done twice, once per branch. Such a query may benefit from join factorization which can transform Q1 into Q2 as follows: Q2:    select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                   from t2, t3                    where t2.c2 = t3.c2 and t2.c2 = 2                                  union all                   select t2.c1 item_1, t2.c2 item_2                   from t2, t4                    where t2.c3 = t4.c3) VW_JF_1    where t1.c1 = VW_JF_1.item_1 and t1.c1 > 1; In Q2, t1 is "factorized" and thus the table scan and the filtering on t1 is done only once (it's shared). If t1 is large, then avoiding one extra scan of t1 can lead to a huge performance improvement. Another benefit of join factorization is that it can open up more join orders. Let's look at query Q3. Q3:    select *    from t5, (select t1.c1, t2.c2                  from t1, t2, t3                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c2 = 2 and t2.c2 = t3.c2                 union all                  select t1.c1, t2.c2                  from t1, t2, t4                  where t1.c1 = t2.c1 and t1.c1 > 1 and t2.c3 = t4.c3) V;   where t5.c1 = V.c1 In Q3, view V is same as Q1. Before join factorization, t1, t2 and t3 must be joined first before they can be joined with t5. But if join factorization factorizes t1 from view V, t1 can then be joined with t5. This opens up new join orders. That being said, join factorization imposes certain join orders. For example, in Q2, t2 and t3 appear in the first branch of the UNION ALL query in view VW_JF_1. T2 must be joined with t3 before it can be joined with t1 which is outside of the VW_JF_1 view. The imposed join order may not necessarily be the best join order. For this reason, join factorization is performed under cost-based transformation framework; this means that we cost the plans with and without join factorization and choose the cheapest plan. Note that if the branches in UNION ALL have DISTINCT clauses, join factorization is not valid. For example, Q4 is NOT semantically equivalent to Q5.   Q4:     select distinct t1.*      from t1, t2      where t1.c1 = t2.c1  union all      select distinct t1.*      from t1, t2      where t1.c1 = t2.c1 Q5:    select distinct t1.*     from t1, (select t2.c1 item_1                   from t2                union all                   select t2.c1 item_1                  from t2) VW_JF_1     where t1.c1 = VW_JF_1.item_1 Q4 might return more rows than Q5. Q5's results are guaranteed to be duplicate free because of the DISTINCT key word at the top level while Q4's results might contain duplicates.   The examples given so far involve inner joins only. Join factorization is also supported in outer join, anti join and semi join. But only the right tables of outer join, anti join and semi joins can be factorized. It is not semantically correct to factorize the left table of outer join, anti join or semi join. For example, Q6 is NOT semantically equivalent to Q7. Q6:     select t1.c1, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t2.c2 (+) = 2  union all    select t1.c1, t2.c2    from t1, t2      where t1.c1 = t2.c1(+) and t2.c2 (+) = 3 Q7:     select t1.c1, VW_JF_1.item_2    from t1, (select t2.c1 item_1, t2.c2 item_2                  from t2                  where t2.c2 = 2                union all                  select t2.c1 item_1, t2.c2 item_2                  from t2                                                                                                    where t2.c2 = 3) VW_JF_1       where t1.c1 = VW_JF_1.item_1(+)                                                                  However, the right side of an outer join can be factorized. For example, join factorization can transform Q8 to Q9 by factorizing t2, which is the right table of an outer join. Q8:    select t1.c2, t2.c2    from t1, t2      where t1.c1 = t2.c1 (+) and t1.c1 = 1 union all    select t1.c2, t2.c2    from t1, t2    where t1.c1 = t2.c1(+) and t1.c1 = 2 Q9:   select VW_JF_1.item_2, t2.c2   from t2,             (select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 1           union all            select t1.c1 item_1, t1.c2 item_2            from t1            where t1.c1 = 2) VW_JF_1   where VW_JF_1.item_1 = t2.c1(+) All of the examples in this blog show factorizing a single table from two branches. This is just for ease of illustration. Join factorization can factorize multiple tables and from more than two UNION ALL branches.  SummaryJoin factorization is a cost-based transformation. It can factorize common computations from branches in a UNION ALL query which can lead to huge performance improvement. 

  Read the article

• Arcad C1 3d cad

  - by borisha

  Recently I saw a version of Arcad in the Ubuntu software center. What kind of version is this? A trial version, evaluation version or full software for only 32 US? Second question. I tried to buy this software from software center but for some reason my transaction online couldn't end successfully. I contact my bank but they told me insufficent credit but is not possible. Anyway, is another way, like bank transfer order to buy this software?

  Read the article

• R: How to remove outliers from a smoother in ggplot2?

  - by John

  I have the following data set that I am trying to plot with ggplot2, it is a time series of three experiments A1, B1 and C1 and each experiment had three replicates. I am trying to add a stat which detects and removes outliers before returning a smoother (mean and variance?). I have written my own outlier function (not shown) but I expect there is already a function to do this, I just have not found it. I've looked at stat_sum_df("median_hilow", geom = "smooth") from some examples in the ggplot2 book, but I didn't understand the help doc from Hmisc to see if it removes outliers or not. Is there a function to remove outliers like this in ggplot, or where would I amend my code below to add my own function? library (ggplot2) data = data.frame (day = c(1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7,1,3,5,7), od = c( 0.1,1.0,0.5,0.7 ,0.13,0.33,0.54,0.76 ,0.1,0.35,0.54,0.73 ,1.3,1.5,1.75,1.7 ,1.3,1.3,1.0,1.6 ,1.7,1.6,1.75,1.7 ,2.1,2.3,2.5,2.7 ,2.5,2.6,2.6,2.8 ,2.3,2.5,2.8,3.8), series_id = c( "A1", "A1", "A1","A1", "A1", "A1", "A1","A1", "A1", "A1", "A1","A1", "B1", "B1","B1", "B1", "B1", "B1","B1", "B1", "B1", "B1","B1", "B1", "C1","C1", "C1", "C1", "C1","C1", "C1", "C1", "C1","C1", "C1", "C1"), replicate = c( "A1.1","A1.1","A1.1","A1.1", "A1.2","A1.2","A1.2","A1.2", "A1.3","A1.3","A1.3","A1.3", "B1.1","B1.1","B1.1","B1.1", "B1.2","B1.2","B1.2","B1.2", "B1.3","B1.3","B1.3","B1.3", "C1.1","C1.1","C1.1","C1.1", "C1.2","C1.2","C1.2","C1.2", "C1.3","C1.3","C1.3","C1.3")) > data day od series_id replicate 1 1 0.10 A1 A1.1 2 3 1.00 A1 A1.1 3 5 0.50 A1 A1.1 4 7 0.70 A1 A1.1 5 1 0.13 A1 A1.2 6 3 0.33 A1 A1.2 7 5 0.54 A1 A1.2 8 7 0.76 A1 A1.2 9 1 0.10 A1 A1.3 10 3 0.35 A1 A1.3 11 5 0.54 A1 A1.3 12 7 0.73 A1 A1.3 13 1 1.30 B1 B1.1 This is what I have so far and is working nicely, but outliers are not removed: r <- ggplot(data = data, aes(x = day, y = od)) r + geom_point(aes(group = replicate, color = series_id)) + # add points geom_line(aes(group = replicate, color = series_id)) + # add lines geom_smooth(aes(group = series_id)) # add smoother, average of each replicate

  Read the article

• How to implement child-parent aggregation link in C++?

  - by Giorgio

  Suppose that I have three classes P, C1, C2, composition (strong aggregation) relations between P <>- C1 and P <>- C2, i.e. every instance of P contains an instance of C1 and an instance of C2, which are destroyed when the parent P instance is destroyed. an association relation between instances of C1 and C2 (not necessarily between children of the same P). To implement this, in C++ I normally define three classes P, C1, C2, define two member variables of P of type boost::shared_ptr<C1>, boost::shared_ptr<C2>, and initialize them with newly created objects in P's constructor, implement the relation between C1 and C2 using a boost::weak_ptr<C2> member variable in C1 and a boost::weak_ptr<C1> member variable in C2 that can be set later via appropriate methods, when the relation is established. Now, I also would like to have a link from each C1 and C2 object to its P parent object. What is a good way to implement this? My current idea is to use a simple constant raw pointer (P * const) that is set from the constructor of P (which, in turn, calls the constructors of C1 and C2), i.e. something like: class C1 { public: C1(P * const p, ...) : paren(p) { ... } private: P * const parent; ... }; class P { public: P(...) : childC1(new C1(this, ...)) ... { ... } private: boost::shared_ptr<C1> childC1; ... }; Honestly I see no risk in using a private constant raw pointer in this way but I know that raw pointers are often frowned upon in C++ so I was wondering if there is an alternative solution.

  Read the article

• Stale statistics on a newly created temporary table in a stored procedure can lead to poor performance

  - by sqlworkshops

  When you create a temporary table you expect a new table with no past history (statistics based on past existence), this is not true if you have less than 6 updates to the temporary table. This might lead to poor performance of queries which are sensitive to the content of temporary tables.I was optimizing SQL Server Performance at one of my customers who provides search functionality on their website. They use stored procedure with temporary table for the search. The performance of the search depended on who searched what in the past, option (recompile) by itself had no effect. Sometimes a simple search led to timeout because of non-optimal plan usage due to this behavior. This is not a plan caching issue rather temporary table statistics caching issue, which was part of the temporary object caching feature that was introduced in SQL Server 2005 and is also present in SQL Server 2008 and SQL Server 2012. In this customer case we implemented a workaround to avoid this issue (see below for example for workarounds).When temporary tables are cached, the statistics are not newly created rather cached from the past and updated based on automatic update statistics threshold. Caching temporary tables/objects is good for performance, but caching stale statistics from the past is not optimal.We can work around this issue by disabling temporary table caching by explicitly executing a DDL statement on the temporary table. One possibility is to execute an alter table statement, but this can lead to duplicate constraint name error on concurrent stored procedure execution. The other way to work around this is to create an index.I think there might be many customers in such a situation without knowing that stale statistics are being cached along with temporary table leading to poor performance.Ideal solution is to have more aggressive statistics update when the temporary table has less number of rows when temporary table caching is used. I will open a connect item to report this issue.Meanwhile you can mitigate the issue by creating an index on the temporary table. You can monitor active temporary tables using Windows Server Performance Monitor counter: SQL Server: General Statistics->Active Temp Tables. The script to understand the issue and the workaround is listed below:set nocount onset statistics time offset statistics io offdrop table tab7gocreate table tab7 (c1 int primary key clustered, c2 int, c3 char(200))gocreate index test on tab7(c2, c1, c3)gobegin trandeclare @i intset @i = 1while @i <= 50000begininsert into tab7 values (@i, 1, ‘a’)set @i = @i + 1endcommit trangoinsert into tab7 values (50001, 1, ‘a’)gocheckpointgodrop proc test_slowgocreate proc test_slow @i intasbegindeclare @j intcreate table #temp1 (c1 int primary key)insert into #temp1 (c1) select @iselect @j = t7.c1 from tab7 t7 inner join #temp1 t on (t7.c2 = t.c1)endgodbcc dropcleanbuffersset statistics time onset statistics io ongo–high reads as expected for parameter ’1'exec test_slow 1godbcc dropcleanbuffersgo–high reads that are not expected for parameter ’2'exec test_slow 2godrop proc test_with_recompilegocreate proc test_with_recompile @i intasbegindeclare @j intcreate table #temp1 (c1 int primary key)insert into #temp1 (c1) select @iselect @j = t7.c1 from tab7 t7 inner join #temp1 t on (t7.c2 = t.c1)option (recompile)endgodbcc dropcleanbuffersset statistics time onset statistics io ongo–high reads as expected for parameter ’1'exec test_with_recompile 1godbcc dropcleanbuffersgo–high reads that are not expected for parameter ’2'–low reads on 3rd execution as expected for parameter ’2'exec test_with_recompile 2godrop proc test_with_alter_table_recompilegocreate proc test_with_alter_table_recompile @i intasbegindeclare @j intcreate table #temp1 (c1 int primary key)–to avoid caching of temporary tables one can create a constraint–but this might lead to duplicate constraint name error on concurrent usagealter table #temp1 add constraint test123 unique(c1)insert into #temp1 (c1) select @iselect @j = t7.c1 from tab7 t7 inner join #temp1 t on (t7.c2 = t.c1)option (recompile)endgodbcc dropcleanbuffersset statistics time onset statistics io ongo–high reads as expected for parameter ’1'exec test_with_alter_table_recompile 1godbcc dropcleanbuffersgo–low reads as expected for parameter ’2'exec test_with_alter_table_recompile 2godrop proc test_with_index_recompilegocreate proc test_with_index_recompile @i intasbegindeclare @j intcreate table #temp1 (c1 int primary key)–to avoid caching of temporary tables one can create an indexcreate index test on #temp1(c1)insert into #temp1 (c1) select @iselect @j = t7.c1 from tab7 t7 inner join #temp1 t on (t7.c2 = t.c1)option (recompile)endgoset statistics time onset statistics io ondbcc dropcleanbuffersgo–high reads as expected for parameter ’1'exec test_with_index_recompile 1godbcc dropcleanbuffersgo–low reads as expected for parameter ’2'exec test_with_index_recompile 2go

  Read the article

• flex and bison: wrong output

  - by user2972227

  I am doing a homework using flex and bison to make a complex number calculator. But my program cannot give a correct output. .lex file: %option noyywrap %{ #include<stdio.h> #include<stdlib.h> #include "complex_cal.h" #define YYSTYPE complex #include "complex_cal.tab.h" void RmWs(char* str); %} /* Add your Flex definitions here */ /* Some definitions are already provided to you*/ ws [ \t]+ digits [0-9] number (0|[1-9]+{digits}*)\.?{digits}* im [i] complexnum {ws}*[-]*{ws}*{number}{ws}*[+|-]{ws}*{number}{ws}*{im}{ws}* op [-+*/()] %% {complexnum} {RmWs(yytext); sscanf(yytext,"%lf %lf",&(yylval.real),&(yylval.img)); return CNUMBER;} {ws} /**/ {op} return *yytext; %% /* function provided to student to remove */ /* all the whitespaces from a string. */ void RmWs(char* str){ int i=0,j=0; char temp[strlen(str)+1]; strcpy(temp,str); while (temp[i]!='\0'){ while (temp[i]==' '){i++;} str[j]=temp[i]; i++; j++; } str[j]='\0'; } .y file: %{ #include <stdio.h> #include <stdlib.h> #include "complex_cal.h" /* prototypes of the provided functions */ complex complex_add (complex, complex); complex complex_sub (complex, complex); complex complex_mul (complex, complex); complex complex_div (complex, complex); /* prototypes of the provided functions */ int yylex(void); int yyerror(const char*); %} %token CNUMBER %left '+' '-' %left '*' '/' %nonassoc '(' ')' %% /* start: Add your grammar rules and actions here */ complexexp: complexexp '+' complexexpmultidiv {$$=complex_add($1, $3);} | complexexp '-' complexexpmultidiv {$$=complex_sub($1, $3);} | complexexpmultidiv {$$.real=$1.real;$$.img=$1.img;} ; complexexpmultidiv: complexexpmultidiv '*' complexsimple {$$=complex_mul($1, $3);} | complexexpmultidiv '/' complexsimple {$$=complex_div($1, $3);} | complexsimple {$$.real=$1.real;$$.img=$1.img;} ; complexsimple: '(' complexexp ')' {$$.real=$2.real;$$.img=$2.img;} | '(' CNUMBER ')' {$$.real=$2.real;$$.img=$2.img;} ; /* end: Add your grammar rules and actions here */ %% int main(){ return yyparse(); } int yyerror(const char* s){ printf("%s\n", s); return 0; } /* function provided to do complex addition */ /* input : complex numbers c1, c2 */ /* output: nothing */ /* side effect : none */ /* return value: result of addition in c3 */ complex complex_add (complex c1, complex c2){ /* c1 + c2 */ complex c3; c3.real = c1.real + c2.real; c3.img = c1.img + c2.img; return c3; } /* function provided to do complex subtraction */ /* input : complex numbers c1, c2 */ /* output: nothing */ /* side effect : none */ /* return value: result of subtraction in c3 */ complex complex_sub (complex c1, complex c2){ /* c1 - c2 */ complex c3; c3.real = c1.real - c2.real; c3.img = c1.img - c2.img; return c3; } /* function provided to do complex multiplication */ /* input : complex numbers c1, c2 */ /* output: nothing */ /* side effect : none */ /* return value: result of multiplication in c3 */ complex complex_mul (complex c1, complex c2){ /* c1 * c2 */ complex c3; c3.real = c1.real*c2.real - c1.img*c2.img; c3.img = c1.img*c2.real + c1.real*c2.img; return c3; } /* function provided to do complex division */ /* input : complex numbers c1, c2 */ /* output: nothing */ /* side effect : none */ /* return value: result of c1/c2 in c3 */ complex complex_div (complex c1, complex c2){ /* c1 / c2 (i.e. c1 divided by c2 ) */ complex c3; double d; /*divisor calculation using the conjugate of c2*/ d = c2.real*c2.real + c2.img*c2.img; c3.real = (c1.real*c2.real + c1.img*c2.img)/d; c3.img = (c1.img*c2.real - c1.real*c2.img)/d; return c3; } .h file: #include <string.h> /* struct for holding a complex number */ typedef struct { double real; double img; } complex; /* define the return type of FLEX */ #define YYSTYPE complex Script for compiling the file: bison -d -v complex_cal.y flex -ocomplex_cal.lex.yy.c complex_cal.lex gcc -o complex_cal complex_cal.lex.yy.c complex_cal.tab.c ./complex_cal Some correct sample run of the program: input:(5+6i)*(6+1i) output:24.000000+41.000000i input:(7+8i)/(-3-4i)*(5+7i) output:-11.720000-14.040000i input:(7+8i)/((-3-4i)*(5+7i)) output:-0.128108+0.211351i But when I run this program, the program only give an output which is identical to my input. For example, when I input (5+6i)(6+1i), it just gives (5+6i)(6+1i). Even if I input any other things, for example, input "abc" it just gives "abc" and is not syntax error. I don't know where the problem is and I hope to know how to solve it.

  Read the article

• Assigning values to the lable through database depending on listbox values

  - by SurajVitekar

  I want to assign the values of five labels from database regarding to values selected in listbox. The db query returns single column with multiple records. Please help. I'm working with C# 2010 and MS SQL. My current code is: private void listBox1_SelectedIndexChanged(object sender, EventArgs e) { try { String c1, c2; c1 = "NULL"; MessageBox.Show("LB index :"+listBox1.SelectedIndex.ToString()); //p = listBox1.SelectedItem.ToString(); SqlConnection con = new SqlConnection(); con.ConnectionString = "Data Source=localhost;Initial Catalog=eVoting;Integrated Security=True;Pooling=False"; con.Open(); MessageBox.Show("List bOx sect :"+listBox1.SelectedValue.ToString()); SqlCommand cmd = new SqlCommand("select Firstname from candidates where position ='" + listBox1.SelectedValue.ToString() + "'", con); int index = 0; SqlDataReader reader = cmd.ExecuteReader(); while(reader.Read()) { if (index == 0) { c1 = reader[index].ToString(); radioButton1.Text = c1; } if (index == 1) { c1 = reader[index].ToString(); radioButton2.Text = c1; } if (index == 2) { c1 = reader[index].ToString(); radioButton3.Text = c1; } if (index == 3) { c1 = reader[index].ToString(); radioButton4.Text = c1; } if (index == 4) { c1 = reader[index].ToString(); radioButton4.Text = c1; } if (index == 5) { c1 = reader[index].ToString(); radioButton5.Text = c1; } MessageBox.Show("c1 :" + c1); index++; } } catch (Exception E) { } }

  Read the article

• No Telnet login prompt when used over SSH tunnel

  - by SCO

  Hi there ! I have a device, let's call it d1, runnning a lightweight Linux. This device is NATed by my internet box/router, hence not reachable from the Internet. That device runs a telnet daemon on it, and only has root as user (no pwd). Its ip address is 192.168.0.126 on the private network. From the private network (let's say 192.168.0.x), I can do: telnet 192.168.0.126 Where 192.168.0.126 is the IP address in the private network. This works correctly. However, to allow administration, I'd need to access that device from outside of that private network. Hence, I created an SSH tunnel like this on d1 : ssh -R 4455:localhost:23 ussh@s1 s1 is a server somewhere in the private network (but this is for testing purposes only, it will endup somewhere in the Internet), running a standard Linux distro and on which I created a user called 'ussh'. s1 IP address is 192.168.0.48. When I 'telnet' with the following, let's say from c1, 192.168.0.19 : telnet -l root s1 4455 I get : Trying 192.168.0.48... Connected to 192.168.0.48. Escape character is '^]'. Connection closed by foreign host . The connection is closed after roughly 30 seconds, and I didn't log. I tried without the -l switch, without any success. I tried to 'telnet' with IP addresses instead of names to avoid reverse DNS issues (although I added to d1 /etc/hosts a line refering to s1 IP/name, just in case), no success. I tried on another port than 4455, no success. I gathered Wireshark logs from s1. I can see : s1 sends SSH data to c1, c1 ACK s1 performs an AAAA DNS request for c1, gets only the Authoritave nameservers. s1 performs an A DNS request, then gets c1's IP address s1 sends a SYN packet to c1, c1 replies with a RST/ACK s1 sends a SYN to c1, C1 RST/ACK (?) After 0.8 seconds, c1 sends a SYN to s1, s1 SYN/ACK and then c1 ACK s1 sends SSH content to d1, d1 sends an ACK back to s1 s1 retries AAAA and A DNS requests After 5 seconds, s1 retries a SYN to c1, once again it is RST/ACKed by c1. This is repeated 3 more times. The last five packets : d1 sends SSH content to s1, s1 sends ACK and FIN/ACK to c1, c1 replies with FIN/ACK, s1 sends ACK to c1. The connection seems to be closed by the telnet daemon after 22 seconds. AFAIK, there is no way to decode the SSH stream, so I'm really stuck here ... Any ideas ? Thank you !

  Read the article

• Register all GUI components as Observers or pass current object to next object as a constructor argu

  - by Jack

  First, I'd like to say that I think this is a common issue and there may be a simple or common solution that I am unaware of. Many have probably encountered a similar problem. Thanks for reading. I am creating a GUI where each component needs to communicate (or at least be updated) by multiple other components. Currently, I'm using a Singleton class to accomplish this goal. Each GUI component gets the instance of the singleton and registers itself. When updates need to be made, the singleton can call public methods in the registered class. I think this is similar to an Observer pattern, but the singleton has more control. Currently, the program is set up something like this: class c1 { CommClass cc; c1() { cc = CommClass.getCommClass(); cc.registerC1( this ); C2 c2 = new c2(); } } class c2 { CommClass cc; c2() { cc = CommClass.getCommClass(); cc.registerC2( this ); C3 c3 = new c3(); } } class c3 { CommClass cc; c3() { cc = CommClass.getCommClass(); cc.registerC3( this ); C4 c4 = new c4(); } } etc. Unfortunately, the singleton class keeps growing larger as more communication is required between the components. I was wondering if it's a good idea to instead of using this singleton, pass the higher order GUI components as arguments in the constructors of each GUI component: class c1 { c1() { C2 c2 = new c2( this ); } } class c2 { C1 c1; c2( C1 c1 ) { this.c1 = c1 C3 c3 = new c3( c1, this ); } } class c3 { C1 c1; C2 c2; c3( C1 c1, C2 c2 ) { this.c1 = c1; this.c2 = c2; C4 c4 = new c4( c1, c2, this ); } } etc. The second version relies less on the CommClass, but it's still very messy as the private member variables increase in number and the constructors grow in length. Each class contains GUI components that need to communicate through CommClass, but I can't think of a good way to do it. If this seems strange or horribly inefficient, please describe some method of communication between classes that will continue to work as the project grows. Also, if this doesn't make any sense to anyone, I'll try to give actual code snippets in the future and think of a better way to ask the question. Thanks.

  Read the article

• Java - Is Set.contains() broken on OpenJDK 6?

  - by Peter

  Hey, I've come across a really strange problem. I have written a simple Deck class which represents a standard 52 card deck of playing cards. The class has a method missingCards() which returns the set of all cards which have been drawn from the deck. If I try and compare two identical sets of missing cards using .equals() I'm told they are different, and if I check to see if a set contains an element that I know is there using .contains() I am returned false. Here is my test code: public void testMissingCards() { Deck deck = new Deck(true); Set<Card> drawnCards = new HashSet<Card>(); drawnCards.add(deck.draw()); drawnCards.add(deck.draw()); drawnCards.add(deck.draw()); Set<Card> missingCards = deck.missingCards(); System.out.println(drawnCards); System.out.println(missingCards); Card c1 = null; for (Card c : drawnCards){ c1 = c; } System.out.println("C1 is "+c1); for (Card c : missingCards){ System.out.println("C is "+c); System.out.println("Does c1.equal(c) "+c1.equals(c)); System.out.println("Does c.equal(c1) "+c.equals(c1)); } System.out.println("Is c1 in missingCards "+missingCards.contains(c1)); assertEquals("Deck confirm missing cards",drawnCards,missingCards); } (Edit: Just for clarity I added the two loops after I noticed the test failing. The first loop pulls out a card from drawnCards and then this card is checked against every card in missingCards - it always matches one, so that card must be contained in missingCards. However, missingCards.contains() fails) And here is an example of it's output: [5C, 2C, 2H] [2C, 5C, 2H] C1 is 2H C is 2C Does c1.equal(c) false Does c.equal(c1) false C is 5C Does c1.equal(c) false Does c.equal(c1) false C is 2H Does c1.equal(c) true Does c.equal(c1) true Is c1 in missingCards false I am completely sure that the implementation of .equals on my card class is correct and, as you can see from the output it does work! What is going on here? Cheers, Pete

  Read the article

• Multiple Table Join in Linq C# Dynamically

  - by kmkperumal

  I have 3 data table a,b,c In this I need to write Join Query Dynamically using linQ. The Selecting columns given by customer and Condition columns also given customer at run time. So i need to create Querys dynamically.Please check below example.Because i dont which table they want and which column also For example Select a.c1,a.c2,b.c1,b.c2 From a Left Join b on a.c1=b.c1 2.Select c.c1,c.c2,a.c1,a.c2 From c Left Join a on c.c3=a.c1 3.Select a.c1,a.c2,b.c1,b.c2,c.c1,c.c2 From a Left Join b on a.c2=b.c2 Left join c on c.c1=a.c1 Like i need create different set of query's. Please help me on this.

  Read the article

• hall.dll errors

  - by Robert Elliott

  I am getting frequent BSoDs, mostly with hall.dll errors. I have Dell Inspiron laptop running Windows 7 SP1. The following file, werfault, is shown below. Can anyone help me work out what is wrong? Version=1 EventType=BlueScreen EventTime=129987824768810026 ReportType=4 Consent=1 ReportIdentifier=1c3e1c58-3b30-11e2-9074-002219f61870 IntegratorReportIdentifier=113012-32557-01 Response.type=4 DynamicSig[1].Name=OS Version DynamicSig[1].Value=6.1.7601.2.1.0.768.3 DynamicSig[2].Name=Locale ID DynamicSig[2].Value=2057 UI[2]=C:\Windows\system32\wer.dll UI[3]=Windows has recovered from an unexpected shutdown UI[4]=Windows can check online for a solution to the problem. UI[5]=&Check for solution UI[6]=&Check later UI[7]=Cancel UI[8]=Windows has recovered from an unexpected shutdown UI[9]=A problem caused Windows to stop working correctly. Windows will notify you if a solution is available. UI[10]=Close Sec[0].Key=BCCode Sec[0].Value=a Sec[1].Key=BCP1 Sec[1].Value=0000000000000000 Sec[2].Key=BCP2 Sec[2].Value=0000000000000002 Sec[3].Key=BCP3 Sec[3].Value=0000000000000000 Sec[4].Key=BCP4 Sec[4].Value=FFFFF80002C0E477 Sec[5].Key=OS Version Sec[5].Value=6_1_7601 Sec[6].Key=Service Pack Sec[6].Value=1_0 Sec[7].Key=Product Sec[7].Value=768_1 File[0].CabName=113012-32557-01.dmp File[0].Path=113012-32557-01.dmp File[0].Flags=589826 File[0].Type=2 File[0].Original.Path=C:\Windows\Minidump\113012-32557-01.dmp File[1].CabName=sysdata.xml File[1].Path=WER-75941-0.sysdata.xml File[1].Flags=589826 File[1].Type=5 File[1].Original.Path=C:\Users\Robert\AppData\Local\Temp\WER-75941-0.sysdata.xml File[2].CabName=Report.cab File[2].Path=Report.cab File[2].Flags=196608 File[2].Type=7 File[2].Original.Path=Report.cab FriendlyEventName=Shut down unexpectedly ConsentKey=BlueScreen AppName=Windows AppPath=C:\Windows\System32\WerFault.exe *********From the minidump file**** RAX = fffff88002f22150 RBX = fffffa80074141f0 RCX = 000000000000000a RDX = 0000000000000000 RSI = fffffa8007278180 RDI = 0000000000000001 R9 = 0000000000000000 R10 = fffff80002c0e477 R11 = 0000000000000000 R12 = fffffa800523e7a0 R13 = 0000000000001000 R14 = 0000000000000028 R15 = fffffa80074141f0 RBP = fffff88002f22210 RIP = fffff80002cd3fc0 RSP = fffff88002f22048 SS = 0000 GS = 002b FS = 0053 ES = 002b DS = 002b CS = 0010 Flags = 00200286 fffff800`02e99ac0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e99ad0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e99ae0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e99af0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e99b00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e99b10 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e99b20 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e99b30 00 00 00 00 00 00 00 00 00 00 00 00 04 00 00 00 ................ fffff800`02e99b40 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e99b50 00 00 00 00 00 00 00 00 00 00 00 00 ............ fffff800`02e81928 00 00 00 00 .... fffff800`02e81924 00 00 00 00 .... fffff800`02e0a880 37 36 30 31 2E 31 37 39 34 34 2E 61 6D 64 36 34 7601.17944.amd64 fffff800`02e0a890 66 72 65 2E 77 69 6E 37 73 70 31 5F 67 64 72 2E fre.win7sp1_gdr. fffff800`02e0a8a0 31 32 30 38 33 30 2D 30 33 33 33 00 00 00 00 00 120830-0333..... fffff800`02e0a8b0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e0a8c0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e0a8d0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e0a8e0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e0a8f0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e0a900 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e0a910 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e0a920 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e0a930 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e0a940 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e0a950 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ fffff800`02e0a960 35 36 65 38 62 61 31 33 2D 37 30 32 39 2D 34 37 56e8ba13-7029-47 fffff800`02e0a970 32 38 2D 61 35 30 36 2D 32 64 64 62 34 61 30 63 28-a506-2ddb4a0c fffff800`02c0e000 C5 0F 85 79 02 00 00 8B 9C 24 90 00 00 00 E9 A5 ...y.....$...... fffff800`02c0e010 00 00 00 44 2B C3 45 33 C9 E8 5E 14 00 00 49 3B ...D+.E3..^...I; fffff800`02c0e020 C5 74 2B 44 8B 8C 24 90 00 00 00 48 8B C8 41 8D .t+D..$....H..A. fffff800`02c0e030 51 FF 41 3B D5 76 0D 44 8B C2 49 83 E8 01 48 8B Q.A;.v.D..I...H. fffff800`02c0e040 49 08 75 F6 48 89 79 08 41 03 D9 48 8B F8 3B DD I.u.H.y.A..H..;. fffff800`02c0e050 75 08 48 8B C7 E9 26 02 00 00 48 8B 96 98 00 00 u.H...&...H..... fffff800`02c0e060 00 48 8D 84 24 90 00 00 00 44 8B C5 48 89 44 24 .H..$....D..H.D$ fffff800`02c0e070 28 44 2B C3 45 33 C9 48 8B CE 44 88 6C 24 20 E8 (D+.E3.H..D.l$ . fffff800`02c0e080 CC 14 00 00 49 3B C5 74 2B 44 8B 8C 24 90 00 00 ....I;.t+D..$... fffff800`02c0e090 00 48 8B C8 41 8D 51 FF 41 3B D5 76 0D 44 8B C2 .H..A.Q.A;.v.D.. fffff800`02c0e0a0 49 83 E8 01 48 8B 49 08 75 F6 48 89 79 08 41 03 I...H.I.u.H.y.A. fffff800`02c0e0b0 D9 48 8B F8 3B DD 74 9A 44 38 AE 28 01 00 00 0F .H..;.t.D8.(.... fffff800`02c0e0c0 85 DF 00 00 00 48 8D 44 24 30 4C 8D 8C 24 A0 00 .....H.D$0L..$.. fffff800`02c0e0d0 00 00 4C 8D 84 24 A8 00 00 00 8B D5 48 8B CE 48 ..L..$......H..H fffff800`02c0e0e0 89 44 24 20 E8 F7 1F 00 00 8B F8 89 84 24 90 00 .D$ .........$.. fffff800`02c0e0f0 00 00 41 3B C5 0F 84 83 01 00 00 4C 8B A4 24 A8 ..A;.......L..$. fffff800`02c0e100 00 00 00 44 8B 84 24 A0 00 00 00 48 8B 8E 98 00 ...D..$....H.... fffff800`02c0e110 00 00 49 8B D4 44 8B C8 E8 DB 1B 00 00 49 3B C5 ..I..D.......I;. fffff800`02c0e120 74 35 48 8B 96 98 00 00 00 48 8D 84 24 90 00 00 t5H......H..$... fffff800`02c0e130 00 41 B1 01 48 89 44 24 28 44 8B C5 48 8B CE 44 .A..H.D$(D..H..D fffff800`02c0e140 88 6C 24 20 E8 43 12 00 00 49 3B C5 0F 84 2C 01 .l$ .C...I;...,. fffff800`02c0e150 00 00 E9 29 01 00 00 48 8B 5C 24 30 49 3B DD 74 ...)...H.\$0I;.t fffff800`02c0e160 2A 4D 3B E5 74 0C 48 8B D3 49 8B CC FF 15 AE CE *M;.t.H..I...... fffff800`02c0e170 01 00 48 8B CB FF 15 95 CF 01 00 33 D2 48 8B CB ..H........3.H.. fffff800`02c0e180 FF 15 AA CE 01 00 E9 F3 00 00 00 C1 E7 0C 41 B8 ..............A. fffff800`02c0e190 01 00 00 00 49 8B CC 8B D7 FF 15 99 CE 01 00 E9 ....I........... fffff800`02c0e1a0 DA 00 00 00 2B EB 33 C9 41 B8 48 61 6C 20 8B D5 ....+.3.A.Hal .. fffff800`02c0e1b0 44 8B FD 48 C1 E2 03 FF 15 33 D4 01 00 4C 8B F0 D..H.....3...L.. fffff800`02c0e1c0 49 3B C5 0F 84 8F 00 00 00 45 8B E5 41 3B ED 76 I;.......E..A;.v fffff800`02c0e1d0 3F 4C 8B E8 BA 00 10 00 00 B9 04 00 00 00 41 B8 ?L............A. fffff800`02c0e1e0 48 61 6C 20 FF 15 06 D4 01 00 49 89 45 00 48 85 Hal ......I.E.H. fffff800`02c0e1f0 C0 74 39 48 8B C8 FF 15 BC CE 01 00 48 C1 E8 20 .t9H........H.. fffff800`02c0e200 85 C0 75 28 41 FF C4 49 83 C5 08 44 3B E5 72 C4 ..u(A..I...D;.r. fffff800`02c0e210 48 8B 8E 98 00 00 00 44 8B C5 BA 01 00 00 00 E8 H......D........ fffff800`02c0e220 58 19 00 00 4C 8B E8 48 85 C0 75 6C 45 33 ED 45 X...L..H..ulE3.E fffff800`02c0e230 3B E5 76 19 49 8B EE 48 8B 4D 00 33 D2 FF 15 ED ;.v.I..H.M.3.... fffff800`02c0e240 CD 01 00 48 83 C5 08 49 83 EC 01 75 EA 33 D2 49 ...H...I...u.3.I fffff800`02c0e250 8B CE FF 15 D8 CD 01 00 41 3B DD 76 21 8B EB 48 ........A;.v!..H fffff800`02c0e260 8B 96 98 00 00 00 48 8B 5F 08 4C 8B C7 48 8B CE ......H._.L..H.. fffff800`02c0e270 E8 2B 15 00 00 48 83 ED 01 48 8B FB 75 E1 33 C0 .+...H...H..u.3. fffff800`02c0e280 48 8B 9C 24 98 00 00 00 48 83 C4 50 41 5F 41 5E H..$....H..PA_A^ fffff800`02c0e290 41 5D 41 5C 5F 5E 5D C3 8D 4D FF 85 C9 74 0C 8B A]A\_^]..M...t.. fffff800`02c0e2a0 D1 48 83 EA 01 48 8B 40 08 75 F6 48 89 78 08 49 [email protected] fffff800`02c0e2b0 8B FD 85 ED 74 29 49 8B DE 48 8B 0B FF 15 F6 CD ....t)I..H...... fffff800`02c0e2c0 01 00 41 89 45 00 48 8B 03 48 83 C3 08 48 83 C8 ..A.E.H..H...H.. fffff800`02c0e2d0 0F 49 83 EF 01 49 89 45 10 4D 8B 6D 08 75 DA 48 .I...I.E.M.m.u.H fffff800`02c0e2e0 8B 8E 98 00 00 00 48 8D 54 24 38 48 83 C1 78 FF ......H.T$8H..x. fffff800`02c0e2f0 15 83 CD 01 00 4C 8B 9E 98 00 00 00 48 8D 4C 24 .....L......H.L$ fffff800`02c0e300 38 41 01 AB D0 00 00 00 FF 15 3A CD 01 00 33 D2 8A........:...3. fffff800`02c0e310 49 8B CE FF 15 17 CD 01 00 E9 34 FD FF FF 90 90 I.........4..... fffff800`02c0e320 90 90 90 90 45 85 C0 74 43 48 89 5C 24 08 48 89 ....E..tCH.\$.H. fffff800`02c0e330 74 24 10 57 48 83 EC 20 48 8B F1 41 8B F8 48 8B t$.WH.. H..A..H. fffff800`02c0e340 5A 08 4C 8B C2 48 8B 96 98 00 00 00 48 8B CE E8 Z.L..H......H... fffff800`02c0e350 4C 14 00 00 48 83 EF 01 48 8B D3 75 E1 48 8B 5C L...H...H..u.H.\ fffff800`02c0e360 24 30 48 8B 74 24 38 48 83 C4 20 5F C3 90 90 90 $0H.t$8H.. _.... fffff800`02c0e370 90 90 90 90 48 8B C4 48 89 58 08 48 89 68 10 48 ....H..H.X.H.h.H fffff800`02c0e380 89 70 18 48 89 78 20 41 54 41 55 4C 8B D9 4D 8B .p.H.x ATAUL..M. fffff800`02c0e390 E0 48 8B F2 B9 FF 0F 00 00 4D 85 DB 75 08 4C 8B .H.......M..u.L. fffff800`02c0e3a0 D1 40 32 FF EB 12 4D 8B 93 88 00 00 00 41 8A BB [email protected].. fffff800`02c0e3b0 91 00 00 00 49 C1 EA 0C 44 8B 44 24 38 41 8B C1 ....I...D.D$8A.. fffff800`02c0e3c0 4C 2B 4E 20 23 C1 49 C1 E9 0C 41 BD 00 10 00 00 L+N #.I...A..... fffff800`02c0e3d0 41 8B D5 41 8B E9 2B D0 8B CA 4C 39 54 EE 30 76 A..A..+...L9T.0v fffff800`02c0e3e0 04 33 C9 EB 4F 41 3B D0 73 43 4C 8D 4C EE 38 4D .3..OA;.sCL.L.8M fffff800`02c0e3f0 39 11 77 39 49 8B 59 F8 48 8D 43 01 49 3B 01 75 9.w9I.Y.H.C.I;.u fffff800`02c0e400 2C 48 8B C3 49 33 01 48 A9 00 00 F0 FF 75 1E 40 ,H..I3.H.....u.@ fffff800`02c0e410 80 FF 01 74 0C 49 33 19 48 F7 C3 F0 FF FF FF 75 ...t.I3.H......u fffff800`02c0e420 0C 41 03 CD 49 83 C1 08 41 3B C8 72 C2 41 3B C8 .A..I...A;.r.A;. fffff800`02c0e430 41 0F 47 C8 4D 85 DB 0F 84 92 00 00 00 41 80 BB A.G.M........A.. fffff800`02c0e440 28 01 00 00 00 0F 84 84 00 00 00 4C 39 54 EE 30 (..........L9T.0 fffff800`02c0e450 76 7D 8B CA 48 8D 44 EE 38 41 3B D0 73 11 4C 39 v}..H.D.8A;.s.L9 fffff800`02c0e460 10 76 0C 41 03 CD 48 83 C0 08 41 3B C8 72 EF 49 .v.A..H...A;.r.I fffff800`02c0e470 8B 44 24 18 41 3B C8 44 8B 08 4C 8B 50 08 41 0F .D$.A;.D..L.P.A. fffff800`02c0e480 47 C8 41 C1 E9 0C EB 3A 45 8B 02 41 8D 41 01 41 G.A....:E..A.A.A fffff800`02c0e490 C1 E8 0C 44 3B C0 75 2E 41 8B C0 41 33 C1 A9 00 ...D;.u.A..A3... fffff800`02c0e4a0 00 F0 FF 75 21 40 80 FF 01 74 0D 41 8B C0 41 33 [email protected] fffff800`02c0e4b0 C1 A9 F0 FF FF FF 75 0E 4D 8B 52 08 45 8B C8 41 ......u.M.R.E..A fffff800`02c0e4c0 03 D5 3B D1 72 C2 3B D1 0F 47 D1 8B C2 EB 02 8B ..;.r.;..G...... fffff800`02c0e4d0 C1 48 8B 5C 24 18 48 8B 6C 24 20 48 8B 74 24 28 .H.\$.H.l$ H.t$( fffff800`02c0e4e0 48 8B 7C 24 30 41 5D 41 5C C3 90 90 90 90 90 90 H.|$0A]A\....... fffff800`02c0e4f0 48 89 5C 24 08 48 89 6C 24 10 48 89 74 24 18 57 H.\$.H.l$.H.t$.W fffff800`02c0e500 41 54 41 55 48 83 EC 30 48 8B 5C 24 70 4D 8B E1 ATAUH..0H.\$pM.. fffff800`02c0e510 49 8B F0 8B 03 4C 8B EA 48 8B E9 89 44 24 20 E8 I....L..H...D$ . fffff800`02c0e520 50 FE FF FF 49 8B CC 89 03 49 2B 4D 20 8B F8 48 P...I....I+M ..H fffff800`02c0e530 C1 E9 0C 8B C9 49 8B 54 CD 30 49 8B CC 48 C1 E2 .....I.T.0I..H.. fffff800`02c0e540 0C 81 E1 FF 0F 00 00 48 03 D1 48 85 F6 74 72 48 .......H..H..trH fffff800`02c0e550 39 95 88 00 00 00 73 69 4C 8B 4E 18 48 8B 84 24 9.....siL.N.H..$ fffff800`02c0e560 80 00 00 00 41 8B DC 41 8B 09 81 E3 FF 0F 00 00 ....A..A........ fffff800`02c0e570 03 CB 80 7C 24 78 01 48 89 08 75 17 4D 8B C4 49 ...|$x.H..u.M..I fffff800`02c0e580 8B D5 48 8B CD C6 44 24 28 01 89 7C 24 20 E8 C5 ..H...D$(..|$ .. fffff800`02c0e590 06 00 00 8B C7 C1 EF 0C 25 FF 0F 00 00 8D 8C 18 ........%....... fffff800`02c0e5a0 FF 0F 00 00 48 8B 46 18 C1 E9 0C 03 CF 74 0C 8B ....H.F......t.. fffff800`02c0e5b0 D1 48 83 EA 01 48 8B 40 08 75 F6 48 89 46 18 EB [email protected].. fffff800`02c0e5c0 0B 48 8B 84 24 80 00 00 00 48 89 10 48 8B 5C 24 .H..$....H..H.\$ fffff800`02c0e5d0 50 48 8B 6C 24 58 48 8B 74 24 60 48 83 C4 30 41 PH.l$XH.t$`H..0A fffff800`02c0e5e0 5D 41 5C 5F C3 90 90 90 90 90 90 90 4D 85 C0 0F ]A\_........M... fffff800`02c0e5f0 84 09 01 00 00 48 8B C4 48 89 58 08 48 89 68 10 .....H..H.X.H.h. fffff800`02c0e600 48 89 70 18 48 89 78 20 41 54 41 55 41 56 48 83 H.p.H.x ATAUAVH. fffff800`02c0e610 EC 30 44 8A 64 24 78 49 8B D8 49 8B F1 4C 8B EA .0D.d$xI..I..L.. fffff800`02c0e620 4C 8B F1 49 89 58 18 41 80 FC 01 0F 84 AF 00 00 L..I.X.A........ fffff800`02c0e630 00 8B 7C 24 70 85 FF 0F 84 9F 00 00 00 4C 8B CE ..|$p........L.. fffff800`02c0e640 4C 8B C3 49 8B D5 49 8B CE 89 7C 24 20 E8 22 FD L..I..I...|$ .". fffff800`02c0e650 FF FF 48 8B CE 49 2B 4D 20 8B E8 48 C1 E9 0C 8B ..H..I+M ..H.... fffff800`02c0e660 C9 49 8B 54 CD 30 48 8B CE 48 C1 E2 0C 81 E1 FF .I.T.0H..H...... fffff800`02c0e670 0F 00 00 48 03 D1 49 39 96 88 00 00 00 73 52 4C ...H..I9.....sRL fffff800`02c0e680 8B 4B 18 4C 8B C6 49 8B D5 49 8B CE 44 88 64 24 .K.L..I..I..D.d$ fffff800`02c0e690 28 89 6C 24 20 E8 BE 05 00 00 8B C5 44 8B DE 25 (.l$ .......D..% fffff800`02c0e6a0 FF 0F 00 00 41 81 E3 FF 0F 00 00 41 8D 8C 03 FF ....A......A.... fffff800`02c0e6b0 0F 00 00 8B C5 C1 E8 0C C1 E9 0C 03 C8 48 8B 43 .............H.C fffff800`02c0e6c0 18 74 0A 48 83 E9 01 48 8B 40 08 75 F6 48 89 43 [email protected] fffff800`02c0e6d0 18 48 03 F5 2B FD 0F 85 61 FF FF FF 48 89 5B 18 .H..+...a...H.[. fffff800`02c0e6e0 48 8B 5C 24 50 48 8B 6C 24 58 48 8B 74 24 60 48 H.\$PH.l$XH.t$`H fffff800`02c0e6f0 8B 7C 24 68 48 83 C4 30 41 5E 41 5D 41 5C C3 90 .|$hH..0A^A]A\.. fffff800`02c0e700 90 90 90 90 90 90 90 90 48 89 54 24 10 53 55 56 ........H.T$.SUV fffff800`02c0e710 57 41 54 41 55 41 56 41 57 48 83 EC 58 48 8B F2 WATAUAVAWH..XH.. fffff800`02c0e720 48 8B D9 48 8D 54 24 30 48 8D 0D B9 67 02 00 45 H..H.T$0H...g..E fffff800`02c0e730 8B E1 49 8B F8 4C 89 84 24 B0 00 00 00 FF 15 35 ..I..L..$......5 fffff800`02c0e740 C9 01 00 4C 8B 2D 86 67 02 00 4C 8B 35 77 67 02 ...L.-.g..L.5wg. fffff800`02c0e750 00 48 8B C6 44 8B C6 48 2B 43 20 41 81 E0 FF 0F .H..D..H+C A.... fffff800`02c0e760 00 00 BD 00 10 00 00 48 C1 E8 0C 45 89 45 2C 8B .......H...E.E,. fffff800`02c0e770 CD 8B C0 41 2B C8 41 89 4D 28 4C 8D 4C C3 30 48 ...A+.A.M(L.L.0H fffff800`02c0e780 8B C6 48 25 00 F0 FF FF 49 89 45 20 49 89 46 20 ..H%....I.E I.F fffff800`02c0e790 45 89 46 2C 41 89 4E 28 44 89 84 24 B8 00 00 00 E.F,A.N(D..$.... fffff800`02c0e7a0 4C 89 8C 24 A0 00 00 00 45 85 E4 0F 84 90 01 00 L..$....E....... fffff800`02c0e7b0 00 48 8B 5F 10 48 81 E3 00 F0 FF FF 75 3C 8B 07 .H._.H......u<.. fffff800`02c0e7c0 48 8B 0D 49 67 02 00 44 8D 4B 01 48 C1 E8 0C 4D H..Ig..D.K.H...M fffff800`02c0e7d0 8B C6 BA 48 61 6C 20 49 89 46 30 FF 15 DF C8 01 ...Hal I.F0..... fffff800`02c0e7e0 00 48 8B D8 48 85 C0 0F 84 36 01 00 00 4C 8B 8C .H..H....6...L.. fffff800`02c0e7f0 24 A0 00 00 00 41 B7 01 EB 09 41 8B C0 48 03 D8 $....A....A..H.. fffff800`02c0e800 45 32 FF 49 8B 01 33 FF 49 89 45 30 48 8B 0D C5 E2.I..3.I.E0H... fffff800`02c0e810 66 02 00 44 8B CF 4D 8B C5 BA 48 61 6C 20 FF 15 f..D..M...Hal .. fffff800`02c0e820 9C C8 01 00 48 8B F0 48 85 C0 75 24 FF C7 83 FF ....H..H..u$.... fffff800`02c0e830 06 7C D9 48 21 44 24 20 45 33 C9 41 B8 01 EF 00 .|.H!D$ E3.A.... fffff800`02c0e840 00 48 8B D5 B9 AC 00 00 00 FF 15 A1 CA 01 00 CC .H.............. fffff800`02c0e850 8B FD 2B BC 24 B8 00 00 00 44 3B E7 41 0F 42 FC ..+.$....D;.A.B. fffff800`02c0e860 80 BC 24 C0 00 00 00 01 8B EF 44 8B C7 75 0E 48 ..$.......D..u.H fffff800`02c0e870 8B D0 48 8B CB FF 15 AD 33 02 00 EB 0B 48 8B D3 ..H.....3....H.. fffff800`02c0e880 48 8B C8 E8 C8 A6 01 00 4D 8B C5 BA 48 61 6C 20 H.......M...Hal fffff800`02c0e890 48 8B CE FF 15 47 C8 01 00 41 80 FF 01 75 11 4D H....G...A...u.M fffff800`02c0e8a0 8B C6 BA 48 61 6C 20 48 8B CB FF 15 30 C8 01 00 ...Hal H....0... fffff800`02c0e8b0 48 8B 84 24 A8 00 00 00 4C 8B 8C 24 A0 00 00 00 H..$....L..$.... fffff800`02c0e8c0 44 2B E7 48 8B BC 24 B0 00 00 00 48 03 C5 BD 00 D+.H..$....H.... fffff800`02c0e8d0 10 00 00 48 8B 7F 08 49 83 C1 08 45 33 C0 44 3B ...H..I...E3.D; fffff800`02c0e8e0 E5 48 8B C8 41 8B D4 0F 47 D5 48 81 E1 00 F0 FF .H..A...G.H..... fffff800`02c0e8f0 FF 48 89 84 24 A8 00 00 00 49 89 4D 20 41 89 55 .H..$....I.M A.U fffff800`02c0e900 28 25 FF 0F 00 00 41 89 45 2C 49 89 4E 20 41 89 (%....A.E,I.N A. fffff800`02c0e910 46 2C 41 89 56 28 48 89 BC 24 B0 00 00 00 E9 75 F,A.V(H..$.....u fffff800`02c0e920 FE FF FF 48 83 64 24 20 00 45 33 C9 41 B8 00 EF ...H.d$ .E3.A... fffff800`02c0e930 00 00 48 8B D5 B9 AC 00 00 00 FF 15 B0 C9 01 00 ..H............. fffff800`02c0e940 CC 48 8D 4C 24 30 FF 15 FC C6 01 00 48 83 C4 58 .H.L$0......H..X fffff800`02c0e950 41 5F 41 5E 41 5D 41 5C 5F 5E 5D 5B C3 90 90 90 A_A^A]A\_^][.... fffff800`02c0e960 90 90 90 90 48 89 5C 24 08 48 89 6C 24 10 48 89 ....H.\$.H.l$.H. fffff800`02c0e970 74 24 18 57 41 54 41 55 48 83 EC 50 33 C0 49 8B t$.WATAUH..P3.I. fffff800`02c0e980 F9 41 8B F0 4C 8B E2 48 8B CA 49 C7 C3 00 F0 FF .A..L..H..I..... fffff800`02c0e990 FF 45 85 C0 74 10 4C 85 59 10 74 0A 48 8B 49 08 .E..t.L.Y.t.H.I. fffff800`02c0e9a0 FF C0 3B C6 72 F0 3B C6 75 09 49 83 21 00 E9 FB ..;.r.;.u.I.!... fffff800`02c0e9b0 00 00 00 65 48 8B 04 25 20 00 00 00 33 C9 44 8B ...eH..% ...3.D. fffff800`02c0e9c0 50 24 48 8B 05 F7 64 02 00 4A 8B 2C D0 4C 8D 4D P$H...d..J.,.L.M fffff800`02c0e9d0 30 45 85 C0 74 22 4C 8B C6 4C 85 5A 10 75 0F 8B 0E..t"L..L.Z.u.. fffff800`02c0e9e0 02 FF C1 48 C1 E8 0C 49 89 01 49 83 C1 08 49 83 ...H...I..I...I. fffff800`02c0e9f0 E8 01 48 8B 52 08 75 E1 33 DB C1 E1 0C 41 B5 01 ..H.R.u.3....A.. fffff800`02c0ea00 48 21 5D 20 21 5D 2C 89 4D 28 44 38 2D 07 65 02 H!] !],.M(D8-.e. fffff800`02c0ea10 00 75 10 48 8B 05 C6 64 02 00 4A 8B 1C D0 E9 29 .u.H...d..J....) fffff800`02c0ea20 01 00 00 48 8D 0D D6 64 02 00 FF 15 50 C6 01 00 ...H...d....P... fffff800`02c0ea30 48 85 C0 0F 85 F9 00 00 00 44 8D 40 01 45 33 C9 [email protected]. fffff800`02c0ea40 33 D2 48 8B CD C7 44 24 28 20 00 00 00 21 5C 24 3.H...D$( ...!\$ fffff800`02c0ea50 20 FF 15 71 C6 01 00 4C 8B D8 48 85 C0 74 69 45 ..q...L..H..tiE fffff800`02c0ea60 32 ED 49 8B D3 85 F6 74 36 48 8B CE 49 F7 44 24 2.I....t6H..I.D$ fffff800`02c0ea70 10 00 F0 FF FF 75 1D 41 8B 44 24 10 25 EF 0F 00 .....u.A.D$.%... fffff800`02c0ea80 00 48 0B C2 48 83 C8 10 48 81 C2 00 10 00 00 49 .H..H...H......I fffff800`02c0ea90 89 44 24 10 48 83 E9 01 4D 8B 64 24 08 75 CD 48 .D$.H...M.d$.u.H fffff800`02c0eaa0 89 2F 4C 89 5F 08 48 89 5F 10 44 88 6F 30 4C 8D ./L._.H._.D.o0L. fffff800`02c0eab0 5C 24 50 49 8B 5B 20 49 8B 6B 28 49 8B 73 30 49 \$PI.[ I.k(I.s0I fffff800`02c0eac0 8B E3 41 5D 41 5C 5F C3 48 8D 54 24 30 48 8D 0D ..A]A\_.H.T$0H.. fffff800`02c0ead0 4C 64 02 00 FF 15 66 C5 01 00 48 8B 15 FF 63 02 Ld....f...H...c. fffff800`02c0eae0 00 44 8B 0D 10 64 02 00 48 8B 02 B9 01 00 00 00 .D...d..H....... fffff800`02c0eaf0 44 8B 40 18 44 3B C9 76 1E 48 83 C2 08 48 8B 02 [email protected];.v.H...H.. fffff800`02c0eb00 44 39 40 18 7D 06 44 8B 40 18 8B D9 FF C1 48 83 D9@.}[email protected]. fffff800`02c0eb10 C2 08 41 3B C9 72 E6 48 8D 4C 24 30 FF 15 0E C6 ..A;.r.H.L$0.... fffff800`02c0eb20 01 00 48 8B 05 B7 63 02 00 44 8B DB 4A 8B 1C D8 ..H...c..D..J... fffff800`02c0eb30 EB 07 83 60 1C 00 48 8B D8 F0 83 43 18 01 48 8D ...`..H....C..H. fffff800`02c0eb40 57 18 48 8D 4B 20 FF 15 F4 C4 01 00 48 8B 4B 10 W.H.K ......H.K. fffff800`02c0eb50 41 B9 01 00 00 00 4C 8B C5 BA 48 61 6C 20 FF 15 A.....L...Hal .. fffff800`02c0eb60 5C C5 01 00 4C 8B D8 48 85 C0 0F 85 F2 FE FF FF \...L..H........ fffff800`02c0eb70 48 21 44 24 20 45 33 C9 BA 00 10 00 00 B9 AC 00 H!D$ E3......... fffff800`02c0eb80 00 00 41 B8 02 EF 00 00 FF 15 62 C7 01 00 CC 90 ..A.......b..... fffff800`02c0eb90 90 90 90 90 90 90 90 90 48 89 5C 24 08 48 89 6C ........H.\$.H.l fffff800`02c0eba0 24 18 48 89 74 24 20 57 48 83 EC 20 41 80 78 30 $.H.t$ WH.. A.x0 fffff800`02c0ebb0 00 49 8B F8 8B F2 48 8B D9 BD 01 00 00 00 75 0F .I....H.......u. fffff800`02c0ebc0 49 8B 10 49 8B 48 08 FF 15 53 C4 01 00 EB 4A 4D I..I.H...S....JM fffff800`02c0ebd0 8B 00 48 8B 4F 08 BA 48 61 6C 20 FF 15 FF C4 01 ..H.O..Hal ..... fffff800`02c0ebe0 00 80 3D 30 63 02 00 00 75 2F 48 8D 4F 18 FF 15 ..=0c...u/H.O... fffff800`02c0ebf0 3C C5 01 00 48 8B 57 10 83 C8 FF F0 0F C1 42 18 <...H.W.......B. fffff800`02c0ec00 83 C0 FF 75 14 F0 0F B1 6A 1C 75 0D 48 8D 0D ED ...u....j.u.H... fffff800`02c0ec10 62 02 00 FF 15 4F C4 01 00 85 F6 74 1E 48 8B CE b....O.....t.H.. fffff800`02c0ec20 F6 43 10 10 74 0C 8B 43 10 25 EF 0F 00 00 48 89 .C..t..C.%....H. fffff800`02c0ec30 43 10 48 2B CD 48 8B 5B 08 75 E5 48 8B 5C 24 30 C.H+.H.[.u.H.\$0 fffff800`02c0ec40 48 8B 6C 24 40 48 8B 74 24 48 48 83 C4 20 5F C3 [email protected]$HH.. _. fffff800`02c0ec50 90 90 90 90 90 90 90 90 48 89 5C 24 18 48 89 4C ........H.\$.H.L fffff800`02c0ec60 24 08 55 56 57 41 54 41 55 41 56 41 57 48 83 EC $.UVWATAUAVAWH.. fffff800`02c0ec70 70 4D 8B F1 4D 8B E8 48 8B F2 4C 8B D1 44 0F 20 pM..M..H..L..D. fffff800`02c0ec80 C7 F6 42 0A 05 74 06 48 8B 5A 18 EB 2A 45 33 C9 ..B..t.H.Z..*E3. fffff800`02c0ec90 33 D2 48 8B CE 45 8D 41 01 C7 44 24 28 20 00 00 3.H..E.A..D$( .. fffff800`02c0eca0 00 83 64 24 20 00 FF 15 1C C4 01 00 4C 8B 94 24 ..d$ .......L..$ fffff800`02c0ecb0 B0 00 00 00 48 8B D8 BD 02 00 00 00 48 85 DB 75 ....H.......H..u fffff800`02c0ecc0 4A 40 3A FD 76 1F 48 21 5C 24 20 45 33 C9 BA 00 J@:.v.H!\$ E3... fffff800`02c0ecd0 10 00 00 B9 AC 00 00 00 41 B8 05 EF 00 00 FF 15 ........A....... fffff800`02c0ece0 0C C6 01 00 CC 8A 84 24 D8 00 00 00 44 8B 8C 24 .......$....D..$ fffff800`02c0ecf0 D0 00 00 00 4D 8B C6 49 8B D5 48 8B CE 88 44 24 ....M..I..H...D$ fffff800`02c0ed00 20 E8 02 FA FF FF E9 4D 01 00 00 44 8B BC 24 D0 ......M...D..$. fffff800`02c0ed10 00 00 00 BA FF 0F 00 00 41 8B CD 23 CA 41 8B C7 ........A..#.A.. fffff800`02c0ed20 C6 84 24 B8 00 00 00 00 23 C2 44 8D A4 01 FF 0F ..$.....#.D..... fffff800`02c0ed30 00 00 41 8B C7 41 C1 EC 0C C1 E8 0C 44 03 E0 44 ..A..A......D..D fffff800`02c0ed40 89 64 24 30 40 3A FD 76 41 33 C9 49 8B C6 45 85 .d$0@:.vA3.I..E. fffff800`02c0ed50 E4 74 64 48 F7 40 10 00 F0 FF FF 74 0D 48 8B 40 [email protected].@ fffff800`02c0ed60 08 FF C1 41 3B CC 72 EB EB 4D 48 83 64 24 20 00 ...A;.r..MH.d$ .

  Read the article

• I am trying to insert value from combo box to database !! but this is not working

  - by user3675488

  At first I have taken some string in which I am trying to save the input values of textboxs and there is a combo box, I am trying to save the input value of the combo box to database, but this following code is unable to do that !!! what is the prob please help me. private void OK_Click(object sender, EventArgs e) { string sTxtcmpnyName = ""; string sTxtcmpnyAdd = ""; string sPhoneno = ""; string sTxtFax = ""; string sPanNo = ""; string sTxtTin = ""; string sTax = ""; string sAccYr = ""; string sComboSt = ""; foreach (Control c in this.Controls) ////*Adding Validation to the textbox.*// // Here the control is entered into GroupBox Grpcmp where c is denoting the name of the control into the groupbox. { // c1 is another control which denotes the textboxes under the GroupBox Grpcmp. foreach (Control c1 in c.Controls) { /////Now this following code snippets reperesents that the name of the company should not be blank. if (c1 is TextBox == true) // simpler that what you've done there { TextBox temp = (TextBox)c1; //The control is entering into Txtcompany. if (temp.Name == "Txtcompanyname") { //Condition checking is the TextBox is empty or Null then the following message will be shown. if ((temp.Text == "") || (temp.Text == "NULL")) { MessageBox.Show("Company Name should not be Blank"); } sTxtcmpnyName = temp.Text; } else if (c1.Name == "TxtcompanyAddress") { sTxtcmpnyAdd = c1.Text; } else if (c1.Name == "Txtphoneno") { sPhoneno = c1.Text; } else if (c1.Name == "TxtFax ") { sTxtFax = c1.Text; } else if (c1.Name == "Txtpanno") { sPanNo = c1.Text; } else if (c1.Name == "TxtTin") { sTxtTin = c1.Text; } else if (c1.Name == "Txtservicetax") { sTax = c1.Text; } //Now I am converting the TxtAcYr into Date format. //For this purpose two conditions are checked first. //First If the TextBox TxtAcYr is Null or empty it will show the message to enter the accountyear!! //Second If the length of the TextBox TxtAcYr is less than 10, it will again generate a message The date format should be in DD/MM/YYYY // Then the value of the use input will be picked using a For loop. if (c1.Name == "TxtAcYr") { sAccYr = c1.Text; //Here a string is taken named as yearlength and the value of the TxtAcYr is assigned to it by using control c1. //Condition Checking If the TextBox TxtAcYr is Null or empty it will show the message to enter the accountyear!! if ((c1.Text == "") || (c1.Text == "NULL")) { MessageBox.Show("Account Year should be entered!!"); } //Condition 2 is checking. Here the length of the string yearlength is whether equals to 10 or not is checked. //Because there are total 10 characters in Date Format along with special character. else // MessageBox.Show(yearlength.Length.ToString()); if (sAccYr.Length != 10) { MessageBox.Show("The Data Format DD-MM-YYYY"); } //Now the value of user will be picked by using the code snippets. else { //A string named as JK is taken for further use. String JK = ""; //This following loop is initiated to pick the user input. //The loop will check wheather the value of i is less than the length of string yearlength or not. //If Yes then it will go further. for (int i = 0; i < sAccYr.Length; i++) { //This condition is checking special characters. //The positions of special characters(Here '-') are placed at 2nd and 5th numbers. //So, the value of i can not be equals to 2 && 5. if ((i != 2) && (i != 5)) { //The new of value of year length i is assinged to the variable JK. JK = JK + sAccYr[i]; } //If the value of i is equals to 1, then enter the following. if (i == 1) { //*Should add the function of TOInt32* // If ToInt32(JK)>= the maximum length of days of a month then the following alert message will be shown. if (Convert.ToInt32(JK) >= 32) { MessageBox.Show("The Data Format DD-MM-YYYY"); } //**Comment should be added.** JK = ""; } else //If the value of i is equals to 4, then enter the following. if (i == 4) { //*Should add the function of TOInt32* // If ToInt32(JK)>= the maximum length of month then the following alert message will be shown. if (Convert.ToInt32(JK) >= 13) { MessageBox.Show("The Data Format DD-MM-YYYY"); } JK = ""; } } } } } else if (c1.Name == "state_cmb") { //sTxttate = c1.Text.ToString(); sComboSt = c1.Text; MessageBox.Show(c1.Text); } } } //////DATABASE CONNECTION///// try { SqlConnection conn = new SqlConnection(); SqlCommand cmd = new SqlCommand(); conn.ConnectionString = ("Data Source =192.168.0.2 ;database= Mee_Company; Persist Security Info =true; User ID =sa;Password = soso654321@"); conn.Open(); cmd.CommandText = ("INSERT INTO CompanyMaster(CompanyName,Address,State,Phone,Fax,PAN,TIN,STAX,AccountsYear)values('" + sTxtcmpnyName + "','" + sTxtcmpnyAdd + "','" + sComboSt + "','" + sPhoneno + "','" + sTxtFax + "','" + sPanNo + "','" + sTxtTin + "','" + sTax + "','" + sAccYr + "')"); //('" + sTxtcmpnyName + "', '" + TxtcompanyAddress.Text + "', '" + Txtphoneno.Text + "', '" + TxtFax.Text + "', '" + Txtservicetax.Text + "','" + TxtAcYr.Text + "')"); cmd.Connection = conn; cmd.ExecuteNonQuery(); conn.Close(); //cmd.Parameters.AddWithValue } catch (Exception ee) { MessageBox.Show(ee.ToString()); } } //An event is created here so that when the user will click on the Cancel Button, the Form will be closed. private void BtmCancle_Click(object sender, EventArgs e) { //this means the form. this.Close(); } //Another Event is created here named as TxtAcYr_KeyPress. //It is for making the TextBox TxtAcYr only allowance of numeric input along with special character '-'. private void TxtAcYr_KeyPress(object sender, KeyPressEventArgs e) { //If the input is number or '-' is checked //And also the backspace and delete option is enabled here. if (char.IsNumber(e.KeyChar) || e.KeyChar == (char)Keys.Back || e.KeyChar == (char)Keys.Delete || e.KeyChar == '-') { e.Handled = false; //ok } else { e.Handled = true; //not ok } }

  Read the article

• How to find every possible combination of arrays in PHP

  - by DenverZ

  $data = array( 'a' => array('a1', 'a2', 'a3'), 'b' => array('b1', 'b2', 'b3', 'b4'), 'c' => array('c1', 'c2', 'c3', 'c4', 'c5')); to get a1 a2 a3 b1 b2 b3 b4 c1 c2 c3 c4 c5 a1 b1 a1 b2 a1 b3 a1 b4 a1 c1 a1 c2 a1 c3 a1 c4 a1 c5 b1 c1 b1 c2 b1 c3 b1 c4 b1 c5 b2 c1 b2 c2 b2 c3 b2 c4 b2 c5 b3 c1 b3 c2 b3 c3 b3 c4 b3 c5 b4 c1 b4 c2 b4 c3 b4 c4 b4 c5 a1 b1 c1 a1 b1 c2 a1 b1 c3 a1 b1 c4 a1 b1 c5 a1 b2 c1 a1 b2 c2 a1 b2 c3 a1 b2 c4 a1 b2 c5 a1 b3 c1 a1 b3 c2 a1 b3 c3 a1 b3 c4 a1 b3 c5 a1 b4 c1 a1 b4 c2 a1 b4 c3 a1 b4 c4 a1 b4 c5 etc... Thanks

  Read the article

• Best practice for marking a bug as resolved in Bugzilla ?

  - by Vincent B.

  I am wondering what is the best way to handle the situation of marking a bug as resolved and providing a version of component/product in which this fix can be found. Context For a project I am working on, we are using Bugzilla for issue tracking, and we have the following: A product "A" with a version number like vA.B.C.D, This product "A" have the following components: Component "C1" with a version number like vA.B.C.D, Component "C2" with a version number like vA.B.C.D, Component "C3" with a version number like vA.B.C.D. Internally we keep track of which component versions have been used to generate the product A version vA.B.C.D. Example: Product "A" version v1.0.0.0 has been produced from component "C1" v1.0.0.3, component "C2" v1.3.0.0 and component "C3" v2.1.3.5. And Product "A" version v1.0.1.0 has been produced from component "C1" v1.0.0.4, component "C2" v1.3.0.0 and component "C3" v2.1.3.5. Each component is a SVN repository. The person in charge of generating the product "A" have only access to the different components tags folder in SVN, and not the trunk of each component repository. Problem Now the problem is the following, when a bug is found in the product "A", and that the bug is related to Component "C1", the version of product "A" is chosen (e.g. v1.0.0.0), and this version allow the developer to know which version of component "C1" has the bug (here it will be v1.0.0.3). A bug report is created. Now let's say that the developer responsible for component "C1" corrects the bug, then when the bug seems to be fixed and after some test and validation, the developer generates a new tag for component "C1", with the version v1.0.0.4. At this time, the developer of component "C1" needs to update the bug report, but what is the best to do: Mark the bug as resolved/fixed and add a comment saying "This bug has been fixed in the tags v1.0.0.4 of C1 component" ? Keep the bug as assigned, add a comment saying "This bug has been fixed in the tags v1.0.0.4 of C1 component, update this bug status to resolved for the next version of the product that will be generated with the newest version (v1.0.0.4 of C1)" ? Another possible way to deal with this problem. Right now the problem is that when a product component CX is fixed, it is not sure in which future version of the product A it will be included, so it is for me not possible to say in which version of the product it will be solved, but it is possible to say in which version of the Component CX it has been solved. So when do we need to mark a bug as solved, when the product A version include the fixed version of CX, or only when CX component has been fixed ? Thanks for your personal feedback and ideas about this !

  Read the article

• Best practice while marking a bug as resolved with Bugzilla (versioning of product and components)

  - by Vincent B.

  I am wondering what is the best way to handle the situation of marking a bug as resolved and providing a version of component/product in which this fix can be found. Context For a project I am working on, we are using Bugzilla for issue tracking, and we have the following: A product "A" with a version number like vA.B.C.D, This product "A" have the following components: Component "C1" with a version number like vA.B.C.D, Component "C2" with a version number like vA.B.C.D, Component "C3" with a version number like vA.B.C.D. Internally we keep track of which component versions have been used to generate the product A version vA.B.C.D. Example: Product "A" version v1.0.0.0 has been produced from component "C1" v1.0.0.3, component "C2" v1.3.0.0 and component "C3" v2.1.3.5. And Product "A" version v1.0.1.0 has been produced from component "C1" v1.0.0.4, component "C2" v1.3.0.0 and component "C3" v2.1.3.5. Each component is a SVN repository. The person in charge of generating the product "A" have only access to the different components tags folder in SVN, and not the trunk of each component repository. Problem Now the problem is the following, when a bug is found in the product "A", and that the bug is related to Component "C1", the version of product "A" is chosen (e.g. v1.0.0.0), and this version allow the developer to know which version of component "C1" has the bug (here it will be v1.0.0.3). A bug report is created. Now let's say that the developer responsible for component "C1" corrects the bug, then when the bug seems to be fixed and after some test and validation, the developer generates a new tag for component "C1", with the version v1.0.0.4. At this time, the developer of component "C1" needs to update the bug report, but what is the best to do: Mark the bug as resolved/fixed and add a comment saying "This bug has been fixed in the tags v1.0.0.4 of C1 component" ? Keep the bug as assigned, add a comment saying "This bug has been fixed in the tags v1.0.0.4 of C1 component, update this bug status to resolved for the next version of the product that will be generated with the newest version (v1.0.0.4 of C1)" ? Another possible way to deal with this problem. Right now the problem is that when a product component CX is fixed, it is not sure in which future version of the product A it will be included, so it is for me not possible to say in which version of the product it will be solved, but it is possible to say in which version of the Component CX it has been solved. So when do we need to mark a bug as solved, when the product A version include the fixed version of CX, or only when CX component has been fixed ? Thanks for your personal feedback and ideas about this !

  Read the article

• Hello Operator, My Switch Is Bored

  - by Paul White

  This is a post for T-SQL Tuesday #43 hosted by my good friend Rob Farley. The topic this month is Plan Operators. I haven’t taken part in T-SQL Tuesday before, but I do like to write about execution plans, so this seemed like a good time to start. This post is in two parts. The first part is primarily an excuse to use a pretty bad play on words in the title of this blog post (if you’re too young to know what a telephone operator or a switchboard is, I hate you). The second part of the post looks at an invisible query plan operator (so to speak). 1. My Switch Is Bored Allow me to present the rare and interesting execution plan operator, Switch: Books Online has this to say about Switch: Following that description, I had a go at producing a Fast Forward Cursor plan that used the TOP operator, but had no luck. That may be due to my lack of skill with cursors, I’m not too sure. The only application of Switch in SQL Server 2012 that I am familiar with requires a local partitioned view: CREATE TABLE dbo.T1 (c1 int NOT NULL CHECK (c1 BETWEEN 00 AND 24)); CREATE TABLE dbo.T2 (c1 int NOT NULL CHECK (c1 BETWEEN 25 AND 49)); CREATE TABLE dbo.T3 (c1 int NOT NULL CHECK (c1 BETWEEN 50 AND 74)); CREATE TABLE dbo.T4 (c1 int NOT NULL CHECK (c1 BETWEEN 75 AND 99)); GO CREATE VIEW V1 AS SELECT c1 FROM dbo.T1 UNION ALL SELECT c1 FROM dbo.T2 UNION ALL SELECT c1 FROM dbo.T3 UNION ALL SELECT c1 FROM dbo.T4; Not only that, but it needs an updatable local partitioned view. We’ll need some primary keys to meet that requirement: ALTER TABLE dbo.T1 ADD CONSTRAINT PK_T1 PRIMARY KEY (c1);   ALTER TABLE dbo.T2 ADD CONSTRAINT PK_T2 PRIMARY KEY (c1);   ALTER TABLE dbo.T3 ADD CONSTRAINT PK_T3 PRIMARY KEY (c1);   ALTER TABLE dbo.T4 ADD CONSTRAINT PK_T4 PRIMARY KEY (c1); We also need an INSERT statement that references the view. Even more specifically, to see a Switch operator, we need to perform a single-row insert (multi-row inserts use a different plan shape): INSERT dbo.V1 (c1) VALUES (1); And now…the execution plan: The Constant Scan manufactures a single row with no columns. The Compute Scalar works out which partition of the view the new value should go in. The Assert checks that the computed partition number is not null (if it is, an error is returned). The Nested Loops Join executes exactly once, with the partition id as an outer reference (correlated parameter). The Switch operator checks the value of the parameter and executes the corresponding input only. If the partition id is 0, the uppermost Clustered Index Insert is executed, adding a row to table T1. If the partition id is 1, the next lower Clustered Index Insert is executed, adding a row to table T2…and so on. In case you were wondering, here’s a query and execution plan for a multi-row insert to the view: INSERT dbo.V1 (c1) VALUES (1), (2); Yuck! An Eager Table Spool and four Filters! I prefer the Switch plan. My guess is that almost all the old strategies that used a Switch operator have been replaced over time, using things like a regular Concatenation Union All combined with Start-Up Filters on its inputs. Other new (relative to the Switch operator) features like table partitioning have specific execution plan support that doesn’t need the Switch operator either. This feels like a bit of a shame, but perhaps it is just nostalgia on my part, it’s hard to know. Please do let me know if you encounter a query that can still use the Switch operator in 2012 – it must be very bored if this is the only possible modern usage! 2. Invisible Plan Operators The second part of this post uses an example based on a question Dave Ballantyne asked using the SQL Sentry Plan Explorer plan upload facility. If you haven’t tried that yet, make sure you’re on the latest version of the (free) Plan Explorer software, and then click the Post to SQLPerformance.com button. That will create a site question with the query plan attached (which can be anonymized if the plan contains sensitive information). Aaron Bertrand and I keep a close eye on questions there, so if you have ever wanted to ask a query plan question of either of us, that’s a good way to do it. The problem The issue I want to talk about revolves around a query issued against a calendar table. The script below creates a simplified version and adds 100 years of per-day information to it: USE tempdb; GO CREATE TABLE dbo.Calendar ( dt date NOT NULL, isWeekday bit NOT NULL, theYear smallint NOT NULL,   CONSTRAINT PK__dbo_Calendar_dt PRIMARY KEY CLUSTERED (dt) ); GO -- Monday is the first day of the week for me SET DATEFIRST 1;   -- Add 100 years of data INSERT dbo.Calendar WITH (TABLOCKX) (dt, isWeekday, theYear) SELECT CA.dt, isWeekday = CASE WHEN DATEPART(WEEKDAY, CA.dt) IN (6, 7) THEN 0 ELSE 1 END, theYear = YEAR(CA.dt) FROM Sandpit.dbo.Numbers AS N CROSS APPLY ( VALUES (DATEADD(DAY, N.n - 1, CONVERT(date, '01 Jan 2000', 113))) ) AS CA (dt) WHERE N.n BETWEEN 1 AND 36525; The following query counts the number of weekend days in 2013: SELECT Days = COUNT_BIG(*) FROM dbo.Calendar AS C WHERE theYear = 2013 AND isWeekday = 0; It returns the correct result (104) using the following execution plan: The query optimizer has managed to estimate the number of rows returned from the table exactly, based purely on the default statistics created separately on the two columns referenced in the query’s WHERE clause. (Well, almost exactly, the unrounded estimate is 104.289 rows.) There is already an invisible operator in this query plan – a Filter operator used to apply the WHERE clause predicates. We can see it by re-running the query with the enormously useful (but undocumented) trace flag 9130 enabled: Now we can see the full picture. The whole table is scanned, returning all 36,525 rows, before the Filter narrows that down to just the 104 we want. Without the trace flag, the Filter is incorporated in the Clustered Index Scan as a residual predicate. It is a little bit more efficient than using a separate operator, but residual predicates are still something you will want to avoid where possible. The estimates are still spot on though: Anyway, looking to improve the performance of this query, Dave added the following filtered index to the Calendar table: CREATE NONCLUSTERED INDEX Weekends ON dbo.Calendar(theYear) WHERE isWeekday = 0; The original query now produces a much more efficient plan: Unfortunately, the estimated number of rows produced by the seek is now wrong (365 instead of 104): What’s going on? The estimate was spot on before we added the index! Explanation You might want to grab a coffee for this bit. Using another trace flag or two (8606 and 8612) we can see that the cardinality estimates were exactly right initially: The highlighted information shows the initial cardinality estimates for the base table (36,525 rows), the result of applying the two relational selects in our WHERE clause (104 rows), and after performing the COUNT_BIG(*) group by aggregate (1 row). All of these are correct, but that was before cost-based optimization got involved :) Cost-based optimization When cost-based optimization starts up, the logical tree above is copied into a structure (the ‘memo’) that has one group per logical operation (roughly speaking). The logical read of the base table (LogOp_Get) ends up in group 7; the two predicates (LogOp_Select) end up in group 8 (with the details of the selections in subgroups 0-6). These two groups still have the correct cardinalities as trace flag 8608 output (initial memo contents) shows: During cost-based optimization, a rule called SelToIdxStrategy runs on group 8. It’s job is to match logical selections to indexable expressions (SARGs). It successfully matches the selections (theYear = 2013, is Weekday = 0) to the filtered index, and writes a new alternative into the memo structure. The new alternative is entered into group 8 as option 1 (option 0 was the original LogOp_Select): The new alternative is to do nothing (PhyOp_NOP = no operation), but to instead follow the new logical instructions listed below the NOP. The LogOp_GetIdx (full read of an index) goes into group 21, and the LogOp_SelectIdx (selection on an index) is placed in group 22, operating on the result of group 21. The definition of the comparison ‘the Year = 2013’ (ScaOp_Comp downwards) was already present in the memo starting at group 2, so no new memo groups are created for that. New Cardinality Estimates The new memo groups require two new cardinality estimates to be derived. First, LogOp_Idx (full read of the index) gets a predicted cardinality of 10,436. This number comes from the filtered index statistics: DBCC SHOW_STATISTICS (Calendar, Weekends) WITH STAT_HEADER; The second new cardinality derivation is for the LogOp_SelectIdx applying the predicate (theYear = 2013). To get a number for this, the cardinality estimator uses statistics for the column ‘theYear’, producing an estimate of 365 rows (there are 365 days in 2013!): DBCC SHOW_STATISTICS (Calendar, theYear) WITH HISTOGRAM; This is where the mistake happens. Cardinality estimation should have used the filtered index statistics here, to get an estimate of 104 rows: DBCC SHOW_STATISTICS (Calendar, Weekends) WITH HISTOGRAM; Unfortunately, the logic has lost sight of the link between the read of the filtered index (LogOp_GetIdx) in group 22, and the selection on that index (LogOp_SelectIdx) that it is deriving a cardinality estimate for, in group 21. The correct cardinality estimate (104 rows) is still present in the memo, attached to group 8, but that group now has a PhyOp_NOP implementation. Skipping over the rest of cost-based optimization (in a belated attempt at brevity) we can see the optimizer’s final output using trace flag 8607: This output shows the (incorrect, but understandable) 365 row estimate for the index range operation, and the correct 104 estimate still attached to its PhyOp_NOP. This tree still has to go through a few post-optimizer rewrites and ‘copy out’ from the memo structure into a tree suitable for the execution engine. One step in this process removes PhyOp_NOP, discarding its 104-row cardinality estimate as it does so. To finish this section on a more positive note, consider what happens if we add an OVER clause to the query aggregate. This isn’t intended to be a ‘fix’ of any sort, I just want to show you that the 104 estimate can survive and be used if later cardinality estimation needs it: SELECT Days = COUNT_BIG(*) OVER () FROM dbo.Calendar AS C WHERE theYear = 2013 AND isWeekday = 0; The estimated execution plan is: Note the 365 estimate at the Index Seek, but the 104 lives again at the Segment! We can imagine the lost predicate ‘isWeekday = 0’ as sitting between the seek and the segment in an invisible Filter operator that drops the estimate from 365 to 104. Even though the NOP group is removed after optimization (so we don’t see it in the execution plan) bear in mind that all cost-based choices were made with the 104-row memo group present, so although things look a bit odd, it shouldn’t affect the optimizer’s plan selection. I should also mention that we can work around the estimation issue by including the index’s filtering columns in the index key: CREATE NONCLUSTERED INDEX Weekends ON dbo.Calendar(theYear, isWeekday) WHERE isWeekday = 0 WITH (DROP_EXISTING = ON); There are some downsides to doing this, including that changes to the isWeekday column may now require Halloween Protection, but that is unlikely to be a big problem for a static calendar table ;)  With the updated index in place, the original query produces an execution plan with the correct cardinality estimation showing at the Index Seek: That’s all for today, remember to let me know about any Switch plans you come across on a modern instance of SQL Server! Finally, here are some other posts of mine that cover other plan operators: Segment and Sequence Project Common Subexpression Spools Why Plan Operators Run Backwards Row Goals and the Top Operator Hash Match Flow Distinct Top N Sort Index Spools and Page Splits Singleton and Range Seeks Bitmaps Hash Join Performance Compute Scalar © 2013 Paul White – All Rights Reserved Twitter: @SQL_Kiwi

  Read the article

• Function within function in R

  - by frespider

  Can you please explain to me why th code complain saying that Samdat is not found? I am trying to switch between the models as you can see, so i declared a functions that contains these specific models and I just need to call these function as one of the argument in the get.f function where the resampling will change the structure for each design matrix in the model. the code complain the Samdat is not found when it is found. Also, is there a way I can make the condition statement as if(Model == M1()) instead I have to create another argument M to set if(M==1) Can you explain please? dat <- cbind(Y=rnorm(20),rnorm(20),runif(20),rexp(20),rnorm(20),runif(20), rexp(20),rnorm(20),runif(20),rexp(20)) nam <- paste("v",1:9,sep="") colnames(dat) <- c("Y",nam) M1 <- function(){ a1 = cbind(Samdat[,c(2:5,7,9)]) b1 = cbind(Samdat[,c(2:4,6,8,7)]) c1 = b1+a1 list(a1=a1,b1=b1,c1=c1)} M2 <- function(){ a1= cbind(Samdat[,c(2:5,7,9)])+2 b1= cbind(Samdat[,c(2:4,6,8,7)])+2 c1 = a1+b1 list(a1=a1,b1=b1,c1=c1)} M3 <- function(){ a1= cbind(Samdat[,c(2:5,7,9)])+8 b1= cbind(Samdat[,c(2:4,6,8,7)])+8 c1 = a1+b1 list(a1=a1,b1=b1,c1=c1)} ################################################################# get.f <- function(asim,Model,M){ sse <-c() for(i in 1:asim){ set.seed(i) Samdat <- dat[sample(1:nrow(dat),nrow(dat),replace=T),] Y <- Samdat[,1] if(M==1){ a2 <- Model$a1 b2 <- Model$b1 c2 <- Model$c1 s<- a2+b2+c2 fit <- lm(Y~s) cof <- sum(summary(fit)$coef[,1]) coff <-Model$cof sse <-c(sse,coff) } else if(M==2){ a2 <- Model$a1 b2 <- Model$b1 c2 <- Model$c1 s<- c2+12 fit <- lm(Y~s) cof <- sum(summary(fit)$coef[,1]) coff <-Model$cof sse <-c(sse,coff) } else { a2 <- Model$a1 b2 <- Model$b1 c2 <- Model$c1 s<- c2+a2 fit <- lm(Y~s) cof <- sum(summary(fit)$coef[,1]) coff <- Model$cof sse <-c(sse,coff) } } return(sse) } get.f(10,Model=M1(),M=1) get.f(10,Model=M2(),M=2) get.f(10,Model=M3(),M=3)

  Read the article

• A star algorithm implementation problems

  - by bryan226

  I’m having some trouble implementing the A* algorithm in a 2D tile based game. The problem is basically that the algorithm gets stuck when something gets in its direct way (e.g. walls) Note that it only allows Horizontal and Vertical movement. Here's a picture as it works fine across the map without something in its direct way: (Green tile = destination, Blue = In closed list, Green = in open list) This is what happens if I try to walk 'around' a wall: I calculate costs with the F = G + H formula: G = 1 Cost per Step H = 10 Cost per Step //Count how many tiles are between current-tile & destination-tile The functions: short c_astar::GuessH(short Startx,short Starty,short Destinationx,short Destinationy) { hgeVector Start, Destination; Start.x = Startx; Start.y = Starty; Destination.x = Destinationx; Destination.y = Destinationy; short a = 0; short b = 0; if(Start.x > Destination.x) a = Start.x - Destination.x; else a = Destination.x - Start.x; if(Start.y > Destination.y) b = Start.y - Destination.y; else b = Destination.y - Start.y; return (a+b)*10; } short c_astar::GuessG(short Startx,short Starty,short Currentx,short Currenty) { hgeVector Start, Destination; Start.x = Startx; Start.y = Starty; Destination.x = Currentx; Destination.y = Currenty; short a = 0; short b = 0; if(Start.x > Destination.x) a = Start.x - Destination.x; else a = Destination.x - Start.x; if(Start.y > Destination.y) b = Start.y - Destination.y; else b = Destination.y - Start.y; return (a+b); } At the end of the loop I check which tile is the cheapest to go according to its F value: Then some quick checks are done for each tile (UP,DOWN,LEFT,RIGHT): //...CX are holding the F value of the TILE specified // Info: C0 = Center (Current) // C1 = UP // C2 = DOWN // C3 = LEFT // C4 = RIGHT //Quick checks if(((C1 < C2) && (C1 < C3) && (C1 < C4))) { Current.y -= 1; bSimilar = false; if(DEBUG) hge->System_Log("C1 < ALL"); } //.. same for C2,C3 & C4 If there are multiple tiles with the same F value: It’s actually a switch for DOWNLEFT,UPRIGHT.. etc. Here’s one of it: case UPRIGHT: { //UP Temporary = Current; Temporary.y -= 1; bTileStatus[0] = IsTileWalkable(Temporary.x,Temporary.y); if(bTileStatus[0]) { //Proceed normal we are OK & walkable Tilex.Tile = map.at(Temporary.y).at(Temporary.x); //Search in lists if(SearchInClosedList(Tilex.Tile.ID,C0)) bFoundInClosedList[0] = true; if(SearchInOpenList(Tilex.Tile.ID,C0)) bFoundInOpenList[0] = true; //RIGHT Temporary = Current; Temporary.x += 1; bTileStatus[1] = IsTileWalkable(Temporary.x,Temporary.y); if(bTileStatus[1]) { //Proceed normal we are OK & walkable Tilex.Tile = map.at(Temporary.y).at(Temporary.x); //Search in lists if(SearchInClosedList(Tilex.Tile.ID,C0)) bFoundInClosedList[1] = true; if(SearchInOpenList(Tilex.Tile.ID,C0)) bFoundInOpenList[1] = true; //************************************************* // Purpose: ClosedList behavior //************************************************* if(bFoundInClosedList[0] && !bFoundInClosedList[1]) { //UP found in ClosedList. Go RIGHT return RIGHT; } if(!bFoundInClosedList[0] && bFoundInClosedList[1]) { //RIGHT found in ClosedList. Go UP return UP; } if(bFoundInClosedList[0] && bFoundInClosedList[1]) { //Both found in ClosedList. Random value switch(hge->Random_Int(8,9)) { case 8: return UP; break; case 9: return RIGHT; break; } } //************************************************* // Purpose: OpenList behavior //************************************************* if(bFoundInOpenList[0] && !bFoundInOpenList[1]) { //UP found in OpenList. Go RIGHT return RIGHT; } if(!bFoundInOpenList[0] && bFoundInOpenList[1]) { //RIGHT found in OpenList. Go UP return UP; } if(bFoundInOpenList[0] && bFoundInOpenList[1]) { //Both found in OpenList. Random value switch(hge->Random_Int(8,9)) { case 8: return UP; break; case 9: return RIGHT; break; } } } else if(!bTileStatus[1]) { //RIGHT is not walkable OR out of range //Choose UP return UP; } } else if(!bTileStatus[0]) { //UP is not walkable OR out of range //Fast check RIGHT Temporary = Current; Temporary.x += 1; bTileStatus[1] = IsTileWalkable(Temporary.x,Temporary.y); if(bTileStatus[1]) { return RIGHT; } else return FAILED; //Failed, no valid path found! } } break; A log for the second picture: (Cut down to ten passes, because it’s just repeating itself) ----------------------------------------------------- PASS: 1 | C1: 211 | C2: 191 | C3: 211 | C4: 191 DOWN + RIGHT SIMILAR Going DOWN ----------------------------------------------------- PASS: 2 | C1: 200 | C2: 182 | C3: 202 | C4: 182 DOWN + RIGHT SIMILAR Going DOWN ----------------------------------------------------- PASS: 3 | C1: 191 | C2: 193 | C3: 193 | C4: 173 C4 < ALL Tile(12.000000,6.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 4 | C1: 182 | C2: 184 | C3: 182 | C4: 999 UP + LEFT SIMILAR Going UP Tile(12.000000,5.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 5 | C1: 191 | C2: 173 | C3: 191 | C4: 999 C2 < ALL Tile(12.000000,6.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 6 | C1: 182 | C2: 184 | C3: 182 | C4: 999 UP + LEFT SIMILAR Going UP Tile(12.000000,5.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 7 | C1: 191 | C2: 173 | C3: 191 | C4: 999 C2 < ALL Tile(12.000000,6.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 8 | C1: 182 | C2: 184 | C3: 182 | C4: 999 UP + LEFT SIMILAR Going LEFT ----------------------------------------------------- PASS: 9 | C1: 191 | C2: 193 | C3: 193 | C4: 173 C4 < ALL Tile(12.000000,6.000000) not walkable. MAX_F_VALUE set. ----------------------------------------------------- PASS: 10 | C1: 182 | C2: 184 | C3: 182 | C4: 999 UP + LEFT SIMILAR Going LEFT ----------------------------------------------------- Its always going after the cheapest F value, which seems to be wrong. If someone could point me to the right direction I'd be thankful. Regards, bryan226

  Read the article

• My SQL query is only returning I need the parent aswell

  - by sico87

  My sql query is only returning the children of the parent I need it to return the parent as well, public function getNav($cat,$subcat){ //gets all sub categories for a specific category if(!$this->checkValue($cat)) return false; //checks data $query = false; if($cat=='NULL'){ $sql = "SELECT itemID, title, parent, url, description, image FROM p_cat WHERE deleted = 0 AND parent is NULL ORDER BY position;"; $query = $this->db->query($sql) or die($this->db->error); }else{ //die($cat); $sql = "SET @parent = (SELECT c.itemID FROM p_cat c WHERE url = '".$this->sql($cat)."' AND deleted = 0); SELECT c1.itemID, c1.title, c1.parent, c1.url, c1.description, c1.image, (SELECT c2.url FROM p_cat c2 WHERE c2.itemID = c1.parent LIMIT 1) as parentUrl FROM p_cat c1 WHERE c1.deleted = 0 AND c1.parent = @parent ORDER BY c1.position;"; $query = $this->db->multi_query($sql) or die($this->db->error); $this->db->store_result(); $this->db->next_result(); $query = $this->db->store_result(); } return $query; }

  Read the article

• New Skool Crosstabbing

  - by Tim Dexter

  A while back I spoke about having to go back to BIP's original crosstabbing solution to achieve a certain layout. Hok Min has provided a 'man' page for the new crosstab/pivot builder for 10.1.3.4.1 users. This will make the documentation drop but for now, get it here! The old, hand method is still available but this new approach, is more efficient and flexible. That said you may need to get into the crosstab code to tweak it where the crosstab dialog can not help. I had to do this, this week but more on that later. The following explains how the crosstab wizard builds the crosstab and what the fields inside the resulting template structure are there for. To create the crosstab a new XDO command "<?crosstab:...?>" has been created. XDO Command: <?crosstab: ctvarname; data-element; rows; columns; measures; aggregation?> Parameter Description Example Ctvarname Crosstab variable name. This is automatically generated by the Add-in. C123 data-element This is the XML data element that contains the data. "//ROW" Rows This contains a list of XML elements for row headers. The ordering information is specified within "{" and "}". The first attribute is the sort element. Leaving it blank means the sort element is the same as the row header element. The attribute "o" means order. Its value can be "a" for ascending, or "d" for descending. The attribute "t" means type. Its value can be "t" for text, and "n" for numeric. There can be more than one sort elements, example: "emp-full-name {emp-lastname,o=a,t=n}{emp-firstname,o=a,t=n}. This will sort employee by last name and first name. "Region{,o=a,t=t}, District{,o=a,t=t}" In the example, the first row header is "Region". It is sort by "Region", order is ascending, and type is text. The second row header is "District". It is sort by "District", order is ascending, and type is text. Columns This contains a list of XML elements for columns headers. The ordering information is specified within "{" and "}". The first attribute is the sort element. Leaving it blank means the sort element is the same as the column header element. The attribute "o" means order. Its value can be "a" for ascending, or "d" for descending. The attribute "t" means type. Its value can be "t" for text, and "n" for numeric. There can be more than one sort elements, example: "emp-full-name {emp-lastname,o=a,t=n}{emp-firstname,o=a,t=n}. This will sort employee by last name and first name. "ProductsBrand{,o=a,t=t}, PeriodYear{,o=a,t=t}" In the example, the first column header is "ProductsBrand". It is sort by "ProductsBrand", order is ascending, and type is text. The second column header is "PeriodYear". It is sort by "District", order is ascending, and type is text. Measures This contains a list of XML elements for measures. "Revenue, PrevRevenue" Aggregation The aggregation function name. Currently, we only support "sum". "sum" Using the Oracle BI Publisher Template Builder for Word add-in, we are able to construct the following Pivot Table: The generated XDO command for this Pivot Table is as follow: <?crosstab:c547; "//ROW";"Region{,o=a,t=t}, District{,o=a,t=t}"; "ProductsBrand{,o=a,t=t},PeriodYear{,o=a,t=t}"; "Revenue, PrevRevenue";"sum"?> Running the command on the give XML data files generates this XML file "cttree.xml". Each XPath in the "cttree.xml" is described in the following table. Element XPath Count Description C0 /cttree/C0 1 This contains elements which are related to column. C1 /cttree/C0/C1 4 The first level column "ProductsBrand". There are four distinct values. They are shown in the label H element. CS /cttree/C0/C1/CS 4 The column-span value. It is used to format the crosstab table. H /cttree/C0/C1/H 4 The column header label. There are four distinct values "Enterprise", "Magicolor", "McCloskey" and "Valspar". T1 /cttree/C0/C1/T1 4 The sum for measure 1, which is Revenue. T2 /cttree/C0/C1/T2 4 The sum for measure 2, which is PrevRevenue. C2 /cttree/C0/C1/C2 8 The first level column "PeriodYear", which is the second group-by key. There are two distinct values "2001" and "2002". H /cttree/C0/C1/C2/H 8 The column header label. There are two distinct values "2001" and "2002". Since it is under C1, therefore the total number of entries is 4 x 2 => 8. T1 /cttree/C0/C1/C2/T1 8 The sum for measure 1 "Revenue". T2 /cttree/C0/C1/C2/T2 8 The sum for measure 2 "PrevRevenue". M0 /cttree/M0 1 This contains elements which are related to measures. M1 /cttree/M0/M1 1 This contains summary for measure 1. H /cttree/M0/M1/H 1 The measure 1 label, which is "Revenue". T /cttree/M0/M1/T 1 The sum of measure 1 for the entire xpath from "//ROW". M2 /cttree/M0/M2 1 This contains summary for measure 2. H /cttree/M0/M2/H 1 The measure 2 label, which is "PrevRevenue". T /cttree/M0/M2/T 1 The sum of measure 2 for the entire xpath from "//ROW". R0 /cttree/R0 1 This contains elements which are related to row. R1 /cttree/R0/R1 4 The first level row "Region". There are four distinct values, they are shown in the label H element. H /cttree/R0/R1/H 4 This is row header label for "Region". There are four distinct values "CENTRAL REGION", "EASTERN REGION", "SOUTHERN REGION" and "WESTERN REGION". RS /cttree/R0/R1/RS 4 The row-span value. It is used to format the crosstab table. T1 /cttree/R0/R1/T1 4 The sum of measure 1 "Revenue" for each distinct "Region" value. T2 /cttree/R0/R1/T2 4 The sum of measure 1 "Revenue" for each distinct "Region" value. R1C1 /cttree/R0/R1/R1C1 16 This contains elements from combining R1 and C1. There are 4 distinct values for "Region", and four distinct values for "ProductsBrand". Therefore, the combination is 4 X 4 è 16. T1 /cttree/R0/R1/R1C1/T1 16 The sum of measure 1 "Revenue" for each combination of "Region" and "ProductsBrand". T2 /cttree/R0/R1/R1C1/T2 16 The sum of measure 2 "PrevRevenue" for each combination of "Region" and "ProductsBrand". R1C2 /cttree/R0/R1/R1C1/R1C2 32 This contains elements from combining R1, C1 and C2. There are 4 distinct values for "Region", and four distinct values for "ProductsBrand", and two distinct values of "PeriodYear". Therefore, the combination is 4 X 4 X 2 è 32. T1 /cttree/R0/R1/R1C1/R1C2/T1 32 The sum of measure 1 "Revenue" for each combination of "Region", "ProductsBrand" and "PeriodYear". T2 /cttree/R0/R1/R1C1/R1C2/T2 32 The sum of measure 2 "PrevRevenue" for each combination of "Region", "ProductsBrand" and "PeriodYear". R2 /cttree/R0/R1/R2 18 This contains elements from combining R1 "Region" and R2 "District". Since the list of values in R2 has dependency on R1, therefore the number of entries is not just a simple multiplication. H /cttree/R0/R1/R2/H 18 The row header label for R2 "District". R1N /cttree/R0/R1/R2/R1N 18 The R2 position number within R1. This is used to check if it is the last row, and draw table border accordingly. T1 /cttree/R0/R1/R2/T1 18 The sum of measure 1 "Revenue" for each combination "Region" and "District". T2 /cttree/R0/R1/R2/T2 18 The sum of measure 2 "PrevRevenue" for each combination of "Region" and "District". R2C1 /cttree/R0/R1/R2/R2C1 72 This contains elements from combining R1, R2 and C1. T1 /cttree/R0/R1/R2/R2C1/T1 72 The sum of measure 1 "Revenue" for each combination of "Region", "District" and "ProductsBrand". T2 /cttree/R0/R1/R2/R2C1/T2 72 The sum of measure 2 "PrevRevenue" for each combination of "Region", "District" and "ProductsBrand". R2C2 /cttree/R0/R1/R2/R2C1/R2C2 144 This contains elements from combining R1, R2, C1 and C2, which gives the finest level of details. M1 /cttree/R0/R1/R2/R2C1/R2C2/M1 144 The sum of measure 1 "Revenue". M2 /cttree/R0/R1/R2/R2C1/R2C2/M2 144 The sum of measure 2 "PrevRevenue". Lots to read and digest I know! Customization One new feature I discovered this week is the ability to show one column and sort by another. I had a data set that was extracting month abbreviations, we wanted to show the months across the top and some row headers to the side. As you may know XSL is not great with dates, especially recognising month names. It just wants to sort them alphabetically, so Apr comes before Jan, etc. A way around this is to generate a month number alongside the month and use that to sort. We can do that in the crosstab, sadly its not exposed in the UI yet but its doable. Go back up and take a look a the initial crosstab command. especially the Rows and Columns entries. In there you will find the sort criteria. "ProductsBrand{,o=a,t=t}, PeriodYear{,o=a,t=t}" Notice those leading commas inside the curly braces? Because there is no field preceding them it means that the crosstab should sort on the column before the brace ie PeriodYear. But you can insert another column in the data set to sort by. To get my sort working how I needed. <?crosstab:c794;"current-group()";"_Fund_Type_._Fund_Type_Display_{_Fund_Type_._Fund_Type_Sort_,o=a,t=n}";"_Fiscal_Period__Amount__._Amt_Fm_Disp_Abbr_{_Fiscal_Period__Amount__._Amt_Fiscal_Month_Sort_,o=a,t=n}";"_Execution_Facts_._Amt_";"sum"?> Excuse the horribly verbose XML tags, good ol BIEE :0) The emboldened columns are not in the crosstab but are in the data set. I just opened up the field, dropped them in and changed the type(t) value to be 'n', for number, instead of the default 'a' and my crosstab started sorting how I wanted it. If you find other tips and tricks, please share in the comments.

  Read the article

• Help with Collision of spawned object(postion fixed) with objects that there are translating on screen

  - by Amrutha

  Hey guys I am creating a game using Corona SDK and so coding it in Lua. So there are 2 separate functions, To translate the hit objects and change their color when they are tapped The link below is the code I am using to for the first function http://developer.anscamobile.com/sample-code/fishies Spawn objects that will hit the translating objects on collision. Alos on collision the spawned object disappears and the translating object bears a color(indicating the collision). In addition the size of this spawned object is dependent on i/p volume level. The function I have written is as follows: --VOICE INPUT CODE local r = media.newRecording() r:startRecording() r:startTuner() --local function newBar() -- local bar = display.newLine( 0, 0, 1, 0 ) -- bar:setColor( 0, 55, 100, 20 ) -- bar.width = 5 -- bar.y=400 -- bar.x=20 -- return bar --end local c1 = display.newImage("str-minion-small.png") c1.isVisible=false local c2 = display.newImage("str-minion-mid.png") c2.isVisible=false local c3 = display.newImage("str-minion-big.png") c3.isVisible=false --SPAWNING local function spawnDisk( event ) local phase = event.phase local volumeBar = display.newLine( 0, 0, 1, 0 ) volumeBar.y = 400 volumeBar.x = 20 --volumeBar.isVisible=false local v = 20*math.log(r:getTunerVolume()) local MINTHRESH = 30 local LEFTMARGIN = 20 local v2 = MINTHRESH + math.max (v, -MINTHRESH) v2 = (display.contentWidth - 1 * LEFTMARGIN ) * v2 / MINTHRESH volumeBar.xScale = math.max ( 20, v2 ) local l = volumeBar.xScale local cnt1 = 0 local cnt2 = 0 local cnt3 = 0 local ONE =1 local val = event.numTaps --local px=event.x --local py=event.y if "ended" == phase then --audio.play( popSound ) --myLabel.isVisible = false if l > 50 and l <=150 then --c1:setFillColor(10,105,0) --c1.isVisible=false c1.x=math.random( 10, 450 ) c1.y=math.random( 10, 300 ) physics.addBody( c1, { density=1, radius=10.0 } ) c1.isVisible=true cnt1= cnt1+ ONE return c1 elseif l > 100 and l <=250 then --c2:setFillColor(200,10,0) c2.x=math.random( 10, 450 ) c2.y=math.random( 10, 300 ) physics.addBody( c2, { density=2, radius=9000.0 } ) c2.isVisible=true cnt2= cnt2+ ONE return c2 elseif l >=250 then c3.x=math.random( 40, 450 ) c3.y=math.random( 40, 300 ) physics.addBody( c3, { density=2, radius=7000.0 , bounce=0.0 } ) c3.isVisible=true cnt3= cnt3+ ONE return c3 end end end buzzR:addEventListener( "touch", spawnDisk ) -- touch the screen to create disks Now both functions work fine independently but there is no collision happening. Its almost as if the translating object and the spawn object are on different layers. The translating object passes through the spawn object freely. Can anyone please tell me how to resolve this problem. And how can I get them to collide. Its my first attempt at game development, that too for a mobile platform so would appreciate all help. Also if I have not been specific do let me know. I'll try to frame the query better :). Thanks in advance.

  Read the article

• Help with Collision of spawned object(postion fixed) with objects that there are translating on screen

  - by Amrutha

  Hey guys I am creating a game using Corona SDK and so coding it in Lua. So there are 2 separate functions, To translate the hit objects and change their color when they are tapped The link below is the code I am using to for the first function http://developer.anscamobile.com/sample-code/fishies Spawn objects that will hit the translating objects on collision. Alos on collision the spawned object disappears and the translating object bears a color(indicating the collision). In addition the size of this spawned object is dependent on i/p volume level. The function I have written is as follows, --VOICE INPUT CODE local r = media.newRecording() r:startRecording() r:startTuner() --local function newBar() -- local bar = display.newLine( 0, 0, 1, 0 ) -- bar:setColor( 0, 55, 100, 20 ) -- bar.width = 5 -- bar.y=400 -- bar.x=20 -- return bar --end local c1 = display.newImage("str-minion-small.png") c1.isVisible=false local c2 = display.newImage("str-minion-mid.png") c2.isVisible=false local c3 = display.newImage("str-minion-big.png") c3.isVisible=false --SPAWNING local function spawnDisk( event ) local phase = event.phase local volumeBar = display.newLine( 0, 0, 1, 0 ) volumeBar.y = 400 volumeBar.x = 20 -- volumeBar.isVisible=false local v = 20*math.log(r:getTunerVolume()) local MINTHRESH = 30 local LEFTMARGIN = 20 local v2 = MINTHRESH + math.max (v, -MINTHRESH) v2 = (display.contentWidth - 1 * LEFTMARGIN ) * v2 / MINTHRESH volumeBar.xScale = math.max ( 20, v2 ) local l = volumeBar.xScale local cnt1 = 0 local cnt2 = 0 local cnt3 = 0 local ONE =1 local val = event.numTaps --local px=event.x --local py=event.y if "ended" == phase then --audio.play( popSound ) --myLabel.isVisible = false if l > 50 and l <=150 then -- c1:setFillColor(10,105,0) -- c1.isVisible=false c1.x=math.random( 10, 450 ) c1.y=math.random( 10, 300 ) physics.addBody( c1, { density=1, radius=10.0 } ) c1.isVisible=true cnt1= cnt1+ ONE return c1 elseif l > 100 and l <=250 then --c2:setFillColor(200,10,0) c2.x=math.random( 10, 450 ) c2.y=math.random( 10, 300 ) physics.addBody( c2, { density=2, radius=9000.0 } ) c2.isVisible=true cnt2= cnt2+ ONE return c2 elseif l >=250 then c3.x=math.random( 40, 450 ) c3.y=math.random( 40, 300 ) physics.addBody( c3, { density=2, radius=7000.0 , bounce=0.0 } ) c3.isVisible=true cnt3= cnt3+ ONE return c3 end end end buzzR:addEventListener( "touch", spawnDisk ) -- touch the screen to create disks Now both functions work fine independently but there is no collision happening. Its almost as if the translating object and the spawn object are on different layers. The translating object passes through the spawn object freely. Can anyone please tell me how to resolve this problem. And how can I get them to collide. Its my first attempt at game development, that too for a mobile platform so would appreciate all help. Also if I have not been specific do let me know. I ll try to frame the query better :). Thanks in advance.

  Read the article

• Need to combine common result of two select statements

  - by Anup

  i have to select the common coloumns c1 ,c2,c3 from result of two sql satements. 1) select c1, c2, c3,count(c3) from (select * from form_name where data_created >'1273446000' and data_creazione<'1274569200') group by c1,c2, c3 having count(c3)>1 2) select c1, c2, c3,count(c3) from (select * from form_name where data_created>'1272236400' and data_creazione<'1274569200') group by c1,c2, c3 having count(c3)>2 I need to select c1,c2,c3 all same and common found in both the result of query. how could this be done...could anyone help please?

  Read the article

1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >