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  • Developer’s Life – Every Developer is a Captain America

    - by Pinal Dave
    Captain America was first created as a comic book character in the 1940’s as a way to boost morale during World War II.  Aimed at a children’s audience, his legacy faded away when the war ended.  However, he has recently has a major reboot to become a popular movie character that deals with modern issues. When Captain America was first written, there was no such thing as a developer, programmer or a computer (the way we think of them, anyway).  Despite these limitations, I think there are still a lot of ways that modern Captain America is like modern developers. So how are developers like Captain America? Well, read on my list of reasons. Take on Big Projects Captain America isn’t afraid to take on big projects – and takes responsibility when the project is co-opted by the evil organization HYDRA.  Developers may not have super villains out there corrupting their work, but they know to keep on top of their projects and own what they do. Elderly Wisdom Steve Rogers, Captain America’s alter ego, was frozen in ice for decades, and brought back to life to solve problems. Developers can learn from this by respecting the opinions of their elders – technology is an ever-changing market, but the old-timers still have a few tricks up their sleeves! Don’t be Afraid of Change Don’t be afraid of change.  Captain America woke up to find the world he was accustomed to is now completely different.  He might have even felt his skills were no longer necessary.  He, and developers, know that everyone has their place in a team, though.  If you try your best, you will make it work. Fight Your Own Battle Sometimes you have to make it on your own.  Captain America is an integral part of the Avengers, but in his own movies, the other superheroes aren’t around to back him up.  Developers, too, must learn to work both within and with out a team. Solid Integrity One of Captain America’s greatest qualities is his integrity.  His determine to do what is right, keep his word, and act honestly earns him mockery from some of the less-savory characters – even “good guys” like Iron Man.  Developers, and everyone else, need to develop the strength of character to keep their integrity.  No matter your walk of life, there will be tempting obstacles.  Think of Captain America, and say “no.” There is a lot for all of us to learn from Captain America, to take away in our own lives, and admire in those who display it – I am specifically thinking of developers.  If you are enjoying this series as much as I am, please let me know who else you would like to see featured. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL Tagged: Developer, Superhero

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  • Great non-obvious java tricks

    - by folone
    Consider having a class: public class Test { public static void main(String [] args) { for (int i = 0; i < args.length; i++) { System.out.println(args[i]); } } } What happens if you run it: java Test *? Answer: it prints out all the filenames in current directory. Got more such tricks?

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  • Deciding which technology to use is a big decision when no technology is an obvious choice

    Deciding which technology to use in a new venture or project is a big decision for any company when no technology is an obvious choice. It is always best to analyze the current requirements of the project, and also evaluate the existing technology climate so that the correct technology based on the situation at the time is selected. When evaluation the requirements of a new project it is best to be open to as many technologies as possible initially so a company can be sure that the right decision gets made. Another important aspect of the technology decision is what can the current network and  hardware environment handle, and what would be needed to be adjusted if a specific technology was selected. For example if the current network operating system is Linux then VB6 would force  a huge change in the current computing environment. However if the current network operation system was windows based then very little change would be needed to allow for VB6 if any change had to be done at all. Finally and most importantly an analysis should be done regarding the current technical employees pertaining to their skills and aspirations. For example if you have a team of Java programmers then forcing them to build something in C# might not be an ideal situation. However having a team of VB.net developers who want to develop something in C# would be a better situation based on this example because they are already failure with the .Net Framework and have a desire to use the new technology. In addition to this analysis the cost associated with building and maintaining the project is also a key factor. If two languages are ideal for a project but one technology will increase the budget or timeline by 50% then it might not be the best choice in that situation. An ideal situation for developing in C# applications would be a project that is built on existing Microsoft technologies. An example of this would be a company who uses Windows 2008 Server as their network operating system, Windows XP Pro as their main operation system, Microsoft SQL Server 2008 as their primary database, and has a team of developers experience in the .net framework. In the above situation Java would be a poor technology decision based on their current computing environment and potential lack of Java development by the company’s developers. It would take the developers longer to develop the application due the fact that they would have to first learn the language and then become comfortable with the language. Although these barriers do exist, it does not mean that it is not due able if the company and developers were committed to the project.

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  • The embarrassingly obvious about SQL Server CE

    - by Edward Boyle
    I have been working with SQL servers in one form or another for almost two decades now. But I am new to SQL Server Compact Edition. In the past weeks I have been working with SQL Serve CE a lot. The SQL, not a problem, but the engine itself is very new to me. One of the issues I ran into was a simple SQL statement taking excusive amounts of time; by excessive, I mean over one second. I wrote a little code to time the method. Sometimes it took under one second, other times as long as three seconds. –But it was a simple update statement! As embarrassing as it is, why it was slow eluded me. I posted my issue to MSDN and I got a reply from ErikEJ (MS MVP) who runs the blog “Everything SQL Server Compact” . I know little to nothing about SQL Server Compact. This guy is completely obsessed very well versed in CE. If you spend any time in MSDN forums, it seems that this guy single handedly has the answer for every CE question that comes up. Anyway, he said: “Opening a connection to a SQL Server Compact database file is a costly operation, keep one connection open per thread (incl. your UI thread) in your app, the one on the UI thread should live for the duration of your app.” It hit me, all databases have some connection overhead and SQL Server CE is not a database engine running as a service drinking Jolt Cola waiting for someone to talk to him so he can spring into action and show off his quarter-mile sprint capabilities. Imagine if you had to start the SQL Server process every time you needed to make a database connection. Principally, that is what you are doing with SQL Server CE. For someone who has worked with Enterprise Level SQL Servers a lot, I had to come to the mental image that my Open connection to SQL Server CE is basically starting a service, my own private service, and by closing the connection, I am shutting down my little private service. After making the changes in my code, I lost any reservations I had with using CE. At present, my Data Access Layer class has a constructor; in that constructor I open my connection, I also have OpenConnection and CloseConnection methods, I also implemented IDisposable and clean up any connections in Dispose(). I am still finalizing how this assembly will function. – That’s beside the point. All I’m trying to say is: “Opening a connection to a SQL Server Compact database file is a costly operation”

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  • When the obvious answer is obviously wrong

    - by John Paul Cook
    This post is about how simple math in T-SQL can produce undesirable results, but first we begin with a math quiz. Answer the following as quickly as possible: You just read pages 100-300 of a book. How many pages did you read? QUICKLY NOW! For those of you who answered 200 pages, I have a new question: Which page did you not read? There were 201 pages to read. If you read 200 pages, you skipped a page! What your answer be if I asked you how many pages did you read if you read pages 1-3? Three pages!...(read more)

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  • Non-Obvious Topics to Learn for Game Development

    - by ashes999
    I've been writing games for around 10 years now (from QBasic to C# and everything in-between). I need to start stretching my skills into different areas. What are other, surprising topics I should read up on? Expected topics would include the usual suspects: Programming language of your choice Scripting language Source control Project management (or Agile) Graphics API Maybe some AI (A* path-finding?) Physics (projectile physics) Unit testing (automated testing) I'm looking for more esoteric topics; things that you don't expect to need to know, but if you do know them, they make a difference. This could include things like: Art skills (drawing, lighting, colouring, layout, etc.) Natural language processing The physics of sound (sound-waves, doppler effect, etc.) Personally, I feel that having technical art skills (eg. can make decent art-work if you can only come up with ideas; or, following Photoshop/GIMP tutorials) was the most beneficial for me. This is not intended to be an open-ended question; I'm looking for specific skills that helped you and you expect will continue to benefit you in the short- and long-term.

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  • Diplomatically point out the obvious problem in a product

    - by exiter2000
    As we all know, every software has bugs in it. It is matter of time to discover it. Suppose if you just found your product has potential big issue and it was not developed by you. How would you deal with it? I usually speak up with some data & analysis even if it is not my part of code. I am wondering if it is too offensive because I often faced on some resistance(depending on the issue), which would eventually be gone.

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  • No Obvious Answer - Query-Strings and Javascript

    - by nchaud
    Say I have this main page /my-site/all-my-bath-soaps which lists all my products. It has a search filter text box that uses javascript to filter the products they want to see on that page (the URL doesn't change as they filter). Now from many other parts of the site I want to navigate to this products-page and see specific products. E.g. <a href="/my-site/all-my-bath-soaps?filter='Nivea-Soap'"> will go to /all-my-bath-soaps and apply javascript filtering to see just that product and hide all dom nodes for the other products. The problem is if the user changes the text in the filter from 'Nivea-Soap' to 'Lynx' the javascript will work fine and show the new products but the URL stays at ?filter='Nivea-Soap'. Is there anything I can do about this? Of course, I don't want to reload the page with a new query string every time they change the search criteria. Somehow it'd be great to move the ?filter=... criteria into POST data instead - but how can I do this with a link I don't know...

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  • These Are Obvious Advantages and Disadvantages to Static As Well As Dynamic Sites

    You can find mostly these types of websites that are mostly developed these days and they are static sites as well as dynamic sites because there is various importance of each of these techniques. Which one you are going to opt should be as per your requirements for your website and generally if you want a website that is going to generate revenue with PPC or affiliate programs then you should go with a static site but in case you wish to create a website that will be more appealing to audience with more interactivity then a dynamic site...

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  • Does TDD's "Obvious Implementation" mean code first, test after?

    - by natasky
    My friend and I are relatively new TDD and have a dispute about the "Obvious Implementation" technique (from "TDD By Example" by Kent Beck). My friend says it means that if the implementation is obvious, you should go ahead and write it - before any test for that new behavior. And indeed the book says: How do you implement simple operations? Just implement them. Also: Sometimes you are sure you know how to implement an operation. Go ahead. I think what the author means is you should test first, and then "just implement" it - as opposed to the "Fake It ('Till You Make It)" and other techniques, which require smaller steps in the implementation stage. Also after these quotes the author talks about getting "red bars" (failing tests) when doing "Obvious Implementation" - how can you get a red bar without a test?. Yet I couldn't find any quote from the book saying "obvious" still means test first. What do you think? Should we test first or after when the implementation is "obvious" (according to TDD, of course)? Do you know a book or blog post saying just that?

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  • not so obvious pointers

    - by mike_hornbeck
    I have a class : class X{ public : void f ( int ) ; int a ; } ; And the task is "Inside the code provide declarations for : pointer to int variable of class X pointer to function void(int) defined inside class X pointer to double variable of class X" Ok so pointer to int a will be just int *x = &a, right ? If there is no double in X can I already create pointer to double inside this class ? And the biggest problem is the second task. How one declares pointer to function ?

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  • Process is killed without a (obvious) reason and program stops working

    - by Krzysiek Gurniak
    Here's what my program is supposed to do: create 4 child processes: process 0 is reading 1 byte at a time from STDIN, then writing it into FIFO process 1 is reading this 1 byte from fifo and write its value as HEX into shared memory process 2 is reading HEX value from shared memory and writing it into pipe finally process 3 is reading from pipe and writing into STDOUT (in my case: terminal) I can't change communication channels. FIFO, then shared memory, then pipes are the only option. My problem: Program stops at random moments when some file is directed into stdin (for example:./program < /dev/urandom). Sometimes after writing 5 HEX values, sometimes after 100. Weird thing is that when it is working and in another terminal I write "pstree -c" there is 1 main process with 4 children processes (which is what I want), but when I write "pstree -c" after it stopped writing (but still runs) there are only 3 child processes. For some reason 1 is gone even though they all have while(1) in them.. I think I might have problem with synchronization here, but I am unable to spot it (I've tried for many hours). Here's the code: #include <unistd.h> #include <fcntl.h> #include <stdio.h> #include <string.h> #include <stdlib.h> #include <sys/shm.h> #include <sys/sem.h> #include <sys/types.h> #include <sys/wait.h> #include <sys/stat.h> #include <string.h> #include <signal.h> #define BUFSIZE 1 #define R 0 #define W 1 // processes ID pid_t p0, p1, p2, p3; // FIFO variables int fifo_fd; unsigned char bufor[BUFSIZE] = {}; unsigned char bufor1[BUFSIZE] = {}; // Shared memory variables key_t key; int shmid; char * tab; // zmienne do pipes int file_des[2]; char bufor_pipe[BUFSIZE*30] = {}; void proces0() { ssize_t n; while(1) { fifo_fd = open("/tmp/fifo",O_WRONLY); if(fifo_fd == -1) { perror("blad przy otwieraniu kolejki FIFO w p0\n"); exit(1); } n = read(STDIN_FILENO, bufor, BUFSIZE); if(n<0) { perror("read error w p0\n"); exit(1); } if(n > 0) { if(write(fifo_fd, bufor, n) != n) { perror("blad zapisu do kolejki fifo w p0\n"); exit(1); } memset(bufor, 0, n); // czyszczenie bufora } close(fifo_fd); } } void proces1() { ssize_t m, x; char wartosc_hex[30] = {}; while(1) { if(tab[0] == 0) { fifo_fd = open("/tmp/fifo", O_RDONLY); // otwiera plik typu fifo do odczytu if(fifo_fd == -1) { perror("blad przy otwieraniu kolejki FIFO w p1\n"); exit(1); } m = read(fifo_fd, bufor1, BUFSIZE); x = m; if(x < 0) { perror("read error p1\n"); exit(1); } if(x > 0) { // Konwersja na HEX if(bufor1[0] < 16) { if(bufor1[0] == 10) // gdy enter { sprintf(wartosc_hex, "0x0%X\n", bufor1[0]); } else { sprintf(wartosc_hex, "0x0%X ", bufor1[0]); } } else { sprintf(wartosc_hex, "0x%X ", bufor1[0]); } // poczekaj az pamiec bedzie pusta (gotowa do zapisu) strcpy(&tab[0], wartosc_hex); memset(bufor1, 0, sizeof(bufor1)); // czyszczenie bufora memset(wartosc_hex, 0, sizeof(wartosc_hex)); // przygotowanie tablicy na zapis wartosci hex x = 0; } close(fifo_fd); } } } void proces2() { close(file_des[0]); // zablokuj kanal do odczytu while(1) { if(tab[0] != 0) { if(write(file_des[1], tab, strlen(tab)) != strlen(tab)) { perror("blad write w p2"); exit(1); } // wyczysc pamiec dzielona by przyjac kolejny bajt memset(tab, 0, sizeof(tab)); } } } void proces3() { ssize_t n; close(file_des[1]); // zablokuj kanal do zapisu while(1) { if(tab[0] == 0) { if((n = read(file_des[0], bufor_pipe, sizeof(bufor_pipe))) > 0) { if(write(STDOUT_FILENO, bufor_pipe, n) != n) { perror("write error w proces3()"); exit(1); } memset(bufor_pipe, 0, sizeof(bufor_pipe)); } } } } int main(void) { key = 5678; int status; // Tworzenie plikow przechowujacych ID procesow int des_pid[2] = {}; char bufor_proces[50] = {}; mknod("pid0", S_IFREG | 0777, 0); mknod("pid1", S_IFREG | 0777, 0); mknod("pid2", S_IFREG | 0777, 0); mknod("pid3", S_IFREG | 0777, 0); // Tworzenie semaforow key_t klucz; klucz = ftok(".", 'a'); // na podstawie pliku i pojedynczego znaku id wyznacza klucz semafora if(klucz == -1) { perror("blad wyznaczania klucza semafora"); exit(1); } semafor = semget(klucz, 1, IPC_CREAT | 0777); // tworzy na podstawie klucza semafor. 1 - ilosc semaforow if(semafor == -1) { perror("blad przy tworzeniu semafora"); exit(1); } if(semctl(semafor, 0, SETVAL, 0) == -1) // ustawia poczatkowa wartosc semafora (klucz, numer w zbiorze od 0, polecenie, argument 0/1/2) { perror("blad przy ustawianiu wartosci poczatkowej semafora"); exit(1); } // Tworzenie lacza nazwanego FIFO if(access("/tmp/fifo", F_OK) == -1) // sprawdza czy plik istnieje, jesli nie - tworzy go { if(mkfifo("/tmp/fifo", 0777) != 0) { perror("blad tworzenia FIFO w main"); exit(1); } } // Tworzenie pamieci dzielonej // Lista pamieci wspoldzielonych, komenda "ipcs" // usuwanie pamieci wspoldzielonej, komenta "ipcrm -m ID_PAMIECI" shmid = shmget(key, (BUFSIZE*30), 0666 | IPC_CREAT); if(shmid == -1) { perror("shmget"); exit(1); } tab = (char *) shmat(shmid, NULL, 0); if(tab == (char *)(-1)) { perror("shmat"); exit(1); } memset(tab, 0, (BUFSIZE*30)); // Tworzenie lacza nienazwanego pipe if(pipe(file_des) == -1) { perror("pipe"); exit(1); } // Tworzenie procesow potomnych if(!(p0 = fork())) { des_pid[W] = open("pid0", O_WRONLY | O_TRUNC | O_CREAT); // 1 - zapis, 0 - odczyt sprintf(bufor_proces, "Proces0 ma ID: %d\n", getpid()); if(write(des_pid[W], bufor_proces, sizeof(bufor_proces)) != sizeof(bufor_proces)) { perror("blad przy zapisie pid do pliku w p0"); exit(1); } close(des_pid[W]); proces0(); } else if(p0 == -1) { perror("blad przy p0 fork w main"); exit(1); } else { if(!(p1 = fork())) { des_pid[W] = open("pid1", O_WRONLY | O_TRUNC | O_CREAT); // 1 - zapis, 0 - odczyt sprintf(bufor_proces, "Proces1 ma ID: %d\n", getpid()); if(write(des_pid[W], bufor_proces, sizeof(bufor_proces)) != sizeof(bufor_proces)) { perror("blad przy zapisie pid do pliku w p1"); exit(1); } close(des_pid[W]); proces1(); } else if(p1 == -1) { perror("blad przy p1 fork w main"); exit(1); } else { if(!(p2 = fork())) { des_pid[W] = open("pid2", O_WRONLY | O_TRUNC | O_CREAT); // 1 - zapis, 0 - odczyt sprintf(bufor_proces, "Proces2 ma ID: %d\n", getpid()); if(write(des_pid[W], bufor_proces, sizeof(bufor_proces)) != sizeof(bufor_proces)) { perror("blad przy zapisie pid do pliku w p2"); exit(1); } close(des_pid[W]); proces2(); } else if(p2 == -1) { perror("blad przy p2 fork w main"); exit(1); } else { if(!(p3 = fork())) { des_pid[W] = open("pid3", O_WRONLY | O_TRUNC | O_CREAT); // 1 - zapis, 0 - odczyt sprintf(bufor_proces, "Proces3 ma ID: %d\n", getpid()); if(write(des_pid[W], bufor_proces, sizeof(bufor_proces)) != sizeof(bufor_proces)) { perror("blad przy zapisie pid do pliku w p3"); exit(1); } close(des_pid[W]); proces3(); } else if(p3 == -1) { perror("blad przy p3 fork w main"); exit(1); } else { // proces macierzysty waitpid(p0, &status, 0); waitpid(p1, &status, 0); waitpid(p2, &status, 0); waitpid(p3, &status, 0); //wait(NULL); unlink("/tmp/fifo"); shmdt(tab); // odlaczenie pamieci dzielonej shmctl(shmid, IPC_RMID, NULL); // usuwanie pamieci wspoldzielonej printf("\nKONIEC PROGRAMU\n"); } } } } exit(0); }

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  • Nonresponsive UI starting a few days ago; no obvious resource shortage

    - by user3679
    The mouse stops and moves jerkily, and sometimes won't register clicks. Gnome stopped responding a few hours ago--everything looks fine, but no clicks on menu items do anything. I've been running Ubuntu 10.10 since it was released; 8GB RAM and a 60GB SSD. I haven't added any hardware or software recently except the Ubuntu recommended updates; the last thing was the bitcoin client a week ago. top shows 3 CPU cores free and over a gig of ram left. I don't know what else to look at.

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  • What are some non-obvious items that should be included in a good employment contract for a programm

    - by hamlin11
    My first employee's sub-contracting trial phase has gone extremely well. They become a full employee (programmer) next week. What are some non-obvious elements that should be included in the employment contract? I want the agreement to be as fair as possible to both the company and the new employee. Specific details: 40 hrs per week, except one 50 hour week per month Employee is Local Telecommuting allowed under certain circumstances already (as security allows) Benefits: 2 weeks paid vacation, full medical, year-end bonus Thanks

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  • Java RegEx API "Look-behind group does not have an obvious maximum length near index ..."

    - by Foo Inc
    Hello, I'm on to some SQL where clause parsing and designed a working RegEx to find a column outside string literals using "Rad Software Regular Expression Desginer" which is using the .NET API. To make sure the designed RegEx works with Java too, I tested it by using the API of course (1.5 and 1.6). But guess what, it won't work. I got the message "Look-behind group does not have an obvious maximum length near index 28". The string that I'm trying to get parsed is Column_1='test''the''stuff''all''day''long' AND Column_2='000' AND TheVeryColumnIWantToFind = 'Column_1=''test''''the''''stuff''''all''''day''''long'' AND Column_2=''000'' AND TheVeryColumnIWantToFind = '' TheVeryColumnIWantToFind = '' AND (Column_3 is null or Column_3 = ''Not interesting'') AND ''1'' = ''1''' AND (Column_3 is null or Column_3 = 'Still not interesting') AND '1' = '1' As you may have guessed, I tried to create some kind of worst case to ensure the RegEx won't fail on more complicated SQL where clauses. The RegEx itself looks like this (?i:(?<!=\s*'(?:[^']|(?:''))*)((?<=\s*)TheVeryColumnIWantToFind(?=(?:\s+|=)))) I'm not sure if there is a more elegant RegEx (there'll most likely be one), but that's not important right now as it does the trick. To explain the RegEx in a few words: If it finds the column I'm after, it does a negative look-behind to figure out if the column name is used in a string literal. If so, it won't match. If not, it'll match. Back to the question. As I mentioned before, it won't work with Java. What will work and result in what I want? I found out, that Java does not seem to support unlimited look-behinds but still I couldn't get it to work. Isn't it right that a look-behind is always putting a limit up on itself from the search offset to the current search position? So it would result in something like "position - offset"?

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  • How do I mock an object in this case? no obvious way to replace object with mock

    - by Tristan
    Hi there, Suppose I have this very simple method in Store's model: def geocode_address loc = Store.geocode(address) self.lat = loc.lat self.lng = loc.lng end If I want to write some test scripts that aren't affected by the geocoding service, which may be down, have limitations or depend on my internet connection, how do I mock out the geocoding service? If I could pass a geocoding object into the method, it would be easy, but I don't see how I could do it in this case. Thanks! Tristan

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  • inheritance confusion. Adding a special class for making errors obvious on form validation

    - by aslum
    So I've got a form... The relevant CSS is (I think): .libform input { background-color:transparent; color:#000; border-left:0; border-right:0; border-top:0; border-bottom: 1px solid #555; margin: 0 5px 1px 5px; display:inline-block; } .libform input:focus { border:0; border-bottom: 1px dotted #000; color:#939; background-color:#fed; } .error { border-bottom: 1px solid red; } Form field: <? if ($name=="") {$nameerror="error";}?> <input name="name" type="text" class="<?php echo $nameerror;?>" value="<?echo $name;?>" id="name"> I'd like for when they've left the field blank the input button's underline to change from black to red. But it doesn't seem to inherit right. What am I doing wrong?

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  • Rails validation count limit on has_many :through

    - by Jeremy
    I've got the following models: Team, Member, Assignment, Role The Team model has_many Members. Each Member has_many roles through assignments. Role assignments are Captain and Runner. I have also installed devise and CanCan using the Member model. What I need to do is limit each Team to have a max of 1 captain and 5 runners. I found this example, and it seemed to work after some customization, but on update ('teams/1/members/4/edit'). It doesn't work on create ('teams/1/members/new'). But my other validation (validates :role_ids, :presence = true ) does work on both update and create. Any help would be appreciated. Update: I've found this example that would seem to be similar to my problem but I can't seem to make it work for my app. It seems that the root of the problem lies with how the count (or size) is performed before and during validation. For Example: When updating a record... It checks to see how many runners there are on a team and returns a count. (i.e. 5) Then when I select a role(s) to add to the member it takes the known count from the database (i.e. 5) and adds the proposed changes (i.e. 1), and then runs the validation check. (Team.find(self.team_id).members.runner.count 5) This works fine because it returns a value of 6 and 6 5 so the proposed update fails without saving and an error is given. But when I try to create a new member on the team... It checks to see how many runners there are on a team and returns a count. (i.e. 5) Then when I select a role(s) to add to the member it takes the known count from the database (i.e. 5) and then runs the validation check WITHOUT factoring in the proposed changes. This doesn't work because it returns a value of 5 known runner and 5 = 5 so the proposed update passes and the new member and role is saved to the database with no error. Member Model: class Member < ActiveRecord::Base devise :database_authenticatable, :registerable, :recoverable, :rememberable, :trackable, :validatable attr_accessible :password, :password_confirmation, :remember_me attr_accessible :age, :email, :first_name, :last_name, :sex, :shirt_size, :team_id, :assignments_attributes, :role_ids belongs_to :team has_many :assignments, :dependent => :destroy has_many :roles, through: :assignments accepts_nested_attributes_for :assignments scope :runner, joins(:roles).where('roles.title = ?', "Runner") scope :captain, joins(:roles).where('roles.title = ?', "Captain") validate :validate_runner_count validate :validate_captain_count validates :role_ids, :presence => true def validate_runner_count if Team.find(self.team_id).members.runner.count > 5 errors.add(:role_id, 'Error - Max runner limit reached') end end def validate_captain_count if Team.find(self.team_id).members.captain.count > 1 errors.add(:role_id, 'Error - Max captain limit reached') end end def has_role?(role_sym) roles.any? { |r| r.title.underscore.to_sym == role_sym } end end Member Controller: class MembersController < ApplicationController load_and_authorize_resource :team load_and_authorize_resource :member, :through => :team before_filter :get_team before_filter :initialize_check_boxes, :only => [:create, :update] def get_team @team = Team.find(params[:team_id]) end def index respond_to do |format| format.html # index.html.erb format.json { render json: @members } end end def show respond_to do |format| format.html # show.html.erb format.json { render json: @member } end end def new respond_to do |format| format.html # new.html.erb format.json { render json: @member } end end def edit end def create respond_to do |format| if @member.save format.html { redirect_to [@team, @member], notice: 'Member was successfully created.' } format.json { render json: [@team, @member], status: :created, location: [@team, @member] } else format.html { render action: "new" } format.json { render json: @member.errors, status: :unprocessable_entity } end end end def update respond_to do |format| if @member.update_attributes(params[:member]) format.html { redirect_to [@team, @member], notice: 'Member was successfully updated.' } format.json { head :no_content } else format.html { render action: "edit" } format.json { render json: @member.errors, status: :unprocessable_entity } end end end def destroy @member.destroy respond_to do |format| format.html { redirect_to team_members_url } format.json { head :no_content } end end # Allow empty checkboxes # http://railscasts.com/episodes/17-habtm-checkboxes def initialize_check_boxes params[:member][:role_ids] ||= [] end end _Form Partial <%= form_for [@team, @member], :html => { :class => 'form-horizontal' } do |f| %> #... # testing the count... <ul> <li>Captain - <%= Team.find(@member.team_id).members.captain.size %></li> <li>Runner - <%= Team.find(@member.team_id).members.runner.size %></li> <li>Driver - <%= Team.find(@member.team_id).members.driver.size %></li> </ul> <div class="control-group"> <div class="controls"> <%= f.fields_for :roles do %> <%= hidden_field_tag "member[role_ids][]", nil %> <% Role.all.each do |role| %> <%= check_box_tag "member[role_ids][]", role.id, @member.role_ids.include?(role.id), id: dom_id(role) %> <%= label_tag dom_id(role), role.title %> <% end %> <% end %> </div> </div> #... <% end %>

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  • Invalid SSH key error in juju when using it with MAAS

    - by Captain T
    This is the output of juju from a clean install with 2 nodes all running 12.04 juju bootstrap - finishes with no errors and allocates the machine to the user but still no joy after juju environment-destroy and rebuild with different users and different nodes. root@cloudcontrol:/storage# juju -v status 2012-06-07 11:19:47,602 DEBUG Initializing juju status runtime 2012-06-07 11:19:47,621 INFO Connecting to environment... 2012-06-07 11:19:47,905 DEBUG Connecting to environment using node-386077143930... 2012-06-07 11:19:47,906 DEBUG Spawning SSH process with remote_user="ubuntu" remote_host="node-386077143930" remote_port="2181" local_port="57004". The authenticity of host 'node-386077143930 (10.5.5.113)' can't be established. ECDSA key fingerprint is 31:94:89:62:69:83:24:23:5f:02:70:53:93:54:b1:c5. Are you sure you want to continue connecting (yes/no)? yes 2012-06-07 11:19:52,102 ERROR Invalid SSH key 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@658: Client environment:zookeeper.version=zookeeper C client 3.3.5 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@662: Client environment:host.name=cloudcontrol 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@669: Client environment:os.name=Linux 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@670: Client environment:os.arch=3.2.0-23-generic 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@671: Client environment:os.version=#36-Ubuntu SMP Tue Apr 10 20:39:51 UTC 2012 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@log_env@679: Client environment:user.name=sysadmin 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@log_env@687: Client environment:user.home=/root 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@log_env@699: Client environment:user.dir=/storage 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@zookeeper_init@727: Initiating client connection, host=localhost:57004 sessionTimeout=10000 watcher=0x7feb11afc6b0 sessionId=0 sessionPasswd=<null> context=0x2dc7d20 flags=0 2012-06-07 11:19:52,429:18541(0x7feb0e856700):ZOO_ERROR@handle_socket_error_msg@1579: Socket [127.0.0.1:57004] zk retcode=-4, errno=111(Connection refused): server refused to accept the client 2012-06-07 11:19:55,765:18541(0x7feb0e856700):ZOO_ERROR@handle_socket_error_msg@1579: Socket [127.0.0.1:57004] zk retcode=-4, errno=111(Connection refused): server refused to accept the client I have tried numerous ways of creating the keys with ssh-keygen -t rsa -b 2048, ssh-keygen -t rsa, ssh-keygen, and i have tried adding those to MAAS web config page, but always get the same result. I have added the appropriate public key afterwards to the ~/.ssh/authorized_keys I can also ssh to the node, but as I have not been asked to give it a user name or password or set up any sort of account, I cannot manually ssh into the node. The setup of the node is all handled by maas server. It seems like a simple error of looking at the wrong key or looking in the wrong places, only other suggestions I can find are to destroy the environment and rebuild (but that didn't work umpteen times now) or leave it to build the instance once the node has powered up, but I have left for a few hours, and left overnight to build with no luck.

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  • Need for gksudo for "Install new software" in eclipse

    - by Captain Giraffe
    I have been developing for android on eclipse for a while now, and my experience with the eclipse environment on Ubuntu10.10 has not been a smooth one. With the repo install of eclipse I have had to sudo eclipse to install the required components for android development. (a big red flag for me) I tried today to install updates for the eclipse and android platform and my eclipse installation seems to have broken horribly. I can no longer find and of the urls for new software if i gksudo it, if I run it in user mode it fails (as it always has) with permissions problems. I have chowned user:user all my eclipse and android related private/user files. This is a system running ubuntu 10.10 with gnome2.x. On my kubuntu 11.10 install it work a lot better. Is there an easy fix to this? Is the repo version of eclipse broken? Should I do a clean install for just my user? (if so can I retain my previously installed software? the installation process is very time consuming) I saw there was a previous post here recommending this for new installations.

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  • juju -v status ERROR Invalid SSH key

    - by Captain T
    root@cloudcontrol:/storage# juju -v status 2012-06-07 11:19:47,602 DEBUG Initializing juju status runtime 2012-06-07 11:19:47,621 INFO Connecting to environment... 2012-06-07 11:19:47,905 DEBUG Connecting to environment using node-386077143930... 2012-06-07 11:19:47,906 DEBUG Spawning SSH process with remote_user="ubuntu" remote_host="node-386077143930" remote_port="2181" local_port="57004". The authenticity of host 'node-386077143930 (10.5.5.113)' can't be established. ECDSA key fingerprint is 31:94:89:62:69:83:24:23:5f:02:70:53:93:54:b1:c5. Are you sure you want to continue connecting (yes/no)? yes 2012-06-07 11:19:52,102 ERROR Invalid SSH key 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@658: Client environment:zookeeper.version=zookeeper C client 3.3.5 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@662: Client environment:host.name=cloudcontrol 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@669: Client environment:os.name=Linux 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@670: Client environment:os.arch=3.2.0-23-generic 2012-06-07 11:19:52,426:18541(0x7feb13b58700):ZOO_INFO@log_env@671: Client environment:os.version=#36-Ubuntu SMP Tue Apr 10 20:39:51 UTC 2012 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@log_env@679: Client environment:user.name=sysadmin 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@log_env@687: Client environment:user.home=/root 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@log_env@699: Client environment:user.dir=/storage 2012-06-07 11:19:52,428:18541(0x7feb13b58700):ZOO_INFO@zookeeper_init@727: Initiating client connection, host=localhost:57004 sessionTimeout=10000 watcher=0x7feb11afc6b0 sessionId=0 sessionPasswd= context=0x2dc7d20 flags=0 2012-06-07 11:19:52,429:18541(0x7feb0e856700):ZOO_ERROR@handle_socket_error_msg@1579: Socket [127.0.0.1:57004] zk retcode=-4, errno=111(Connection refused): server refused to accept the client 2012-06-07 11:19:55,765:18541(0x7feb0e856700):ZOO_ERROR@handle_socket_error_msg@1579: Socket [127.0.0.1:57004] zk retcode=-4, errno=111(Connection refused): server refused to accept the client This is from a clean install with 2 nodes all running 12.04 Precise juju bootstrap - finishes with no errors and allocates the machine to the user but still no joy after juju environment-destroy and rebuild with different users and different nodes. Anyone got any ideas

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