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• XSLT apply templates in different order of xml reading.

  - by David

  I am new to this, so please bear with me... If we have the following xml fragment: <docXML> <PARRAFO orden='1' tipo='parrafo'> <dato> <etiqueta>Título</etiqueta> <tipo>TextBox</tipo> <valor>¿Cuándo solicitar el consejo genético?</valor> <longitud>1500</longitud> <comentario></comentario> <enlace></enlace> <target_enlace>I</target_enlace> </dato> <dato> <etiqueta>Texto</etiqueta> <tipo>Resumen</tipo> <valor>Resumen text</valor> <longitud>8000</longitud> <comentario></comentario> <enlace></enlace> <target_enlace></target_enlace> </dato> <dato> <etiqueta>Imagen</etiqueta> <tipo>TextBox</tipo> <valor>http://url/Imagenes/7D2BE6480CF4486CA288A75932606181.jpg</valor> <longitud>1500</longitud> <comentario></comentario> <enlace></enlace> <target_enlace>I</target_enlace> </dato> </PARRAFO> <PARRAFO orden='1' tipo='parrafo'> <dato> <etiqueta>Título</etiqueta> <tipo>TextBox</tipo> <valor>TextBox text</valor> <longitud>1500</longitud> <comentario></comentario> <enlace></enlace> <target_enlace>I</target_enlace> </dato> <dato> <etiqueta>Texto</etiqueta> <tipo>Resumen</tipo> <valor>Resumen text</valor> <longitud>8000</longitud> <comentario></comentario> <enlace></enlace> <target_enlace></target_enlace> </dato> </PARRAFO> </docXML> .. I am going to apply templates to each section depending on the value of the label "etiqueta" per node "dato" in "PARRAFO" by using the following XSLT: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xsl" exclude-result-prefixes="msxsl"> <xsl:output method="html" encoding="iso-8859-1"/> <xsl:template match="/"> <xsl:variable name="xml-doc-parrafo" select="documentoXML/PARRAFO"/> <!-- PARRAFOS --> <xsl:choose> <xsl:when test="count($xml-doc-parrafo)>0"> <div class="seccion_1"> <xsl:for-each select="$xml-doc-parrafo"> <xsl:choose> <xsl:when test="self::node()[@tipo = 'parrafo']"> <div class="parrafo"> <xsl:for-each select="self::node()[@tipo = 'parrafo']/dato"> <xsl:variable name="dato" select="self::node()[@tipo = 'parrafo']/dato"/> <xsl:variable name="nextdato" select="following::dato[1]/@etiqueta"/> <xsl:choose> <xsl:when test="etiqueta = 'Título'"> <xsl:call-template name="imprimeTituloParrafo"> <xsl:with-param name="etiqueta" select="etiqueta"></xsl:with-param> <xsl:with-param name="valor" select="valor"></xsl:with-param> <xsl:with-param name="longitud" select="longitud"></xsl:with-param> <xsl:with-param name="comentario" select="comentario"></xsl:with-param> <xsl:with-param name="enlace" select="enlace"></xsl:with-param> <xsl:with-param name="target_enlace" select="target_enlace"></xsl:with-param> </xsl:call-template> </xsl:when> <xsl:when test="etiqueta = 'Subtitulo'"> <xsl:call-template name="imprimeSubtituloParrafo"> <xsl:with-param name="etiqueta" select="etiqueta"></xsl:with-param> <xsl:with-param name="valor" select="valor"></xsl:with-param> <xsl:with-param name="longitud" select="longitud"></xsl:with-param> <xsl:with-param name="comentario" select="comentario"></xsl:with-param> <xsl:with-param name="enlace" select="enlace"></xsl:with-param> <xsl:with-param name="target_enlace" select="target_enlace"></xsl:with-param> </xsl:call-template> </xsl:when> <xsl:when test="etiqueta = 'Imagen'"> <xsl:call-template name="imprimeImagenParrafo"> <xsl:with-param name="etiqueta" select="etiqueta"></xsl:with-param> <xsl:with-param name="valor" select="valor"></xsl:with-param> <xsl:with-param name="longitud" select="longitud"></xsl:with-param> <xsl:with-param name="comentario" select="comentario"></xsl:with-param> <xsl:with-param name="enlace" select="enlace"></xsl:with-param> <xsl:with-param name="target_enlace" select="target_enlace"></xsl:with-param> </xsl:call-template> </xsl:when> <xsl:when test="etiqueta = 'Pie Imagen'"> <xsl:call-template name="imprimePieImagenParrafo"> <xsl:with-param name="etiqueta" select="etiqueta"></xsl:with-param> <xsl:with-param name="valor" select="valor"></xsl:with-param> <xsl:with-param name="longitud" select="longitud"></xsl:with-param> <xsl:with-param name="comentario" select="comentario"></xsl:with-param> <xsl:with-param name="enlace" select="enlace"></xsl:with-param> <xsl:with-param name="target_enlace" select="target_enlace"></xsl:with-param> </xsl:call-template> </xsl:when> <xsl:when test="etiqueta = 'Texto'"> <xsl:call-template name="imprimeTextoParrafo"> <xsl:with-param name="etiqueta" select="etiqueta"></xsl:with-param> <xsl:with-param name="valor" select="valor"></xsl:with-param> <xsl:with-param name="longitud" select="longitud"></xsl:with-param> <xsl:with-param name="comentario" select="comentario"></xsl:with-param> <xsl:with-param name="enlace" select="enlace"></xsl:with-param> <xsl:with-param name="target_enlace" select="target_enlace"></xsl:with-param> </xsl:call-template> </xsl:when> <xsl:when test="etiqueta = 'Pie Parrafo'"> <xsl:call-template name="imprimePieParrafo"> <xsl:with-param name="etiqueta" select="etiqueta"></xsl:with-param> <xsl:with-param name="valor" select="valor"></xsl:with-param> <xsl:with-param name="longitud" select="longitud"></xsl:with-param> <xsl:with-param name="comentario" select="comentario"></xsl:with-param> <xsl:with-param name="enlace" select="enlace"></xsl:with-param> <xsl:with-param name="target_enlace" select="target_enlace"></xsl:with-param> </xsl:call-template> </xsl:when> </xsl:choose> </xsl:for-each> </div> </xsl:when> </xsl:choose> </xsl:for-each> </div> </xsl:when> <!-- si no hay resultados --> <xsl:otherwise> <br></br> <p style="text-align:center;">El documento no contiene datos.</p> </xsl:otherwise> </xsl:choose> </xsl:template> <xsl:template name="imprimeTituloParrafo"> <xsl:param name="etiqueta"></xsl:param> <xsl:param name="valor"></xsl:param> <xsl:param name="longitud"></xsl:param> <xsl:param name="enlace"></xsl:param> <xsl:param name="target_enlace"></xsl:param> <h2 class="titulo"> <xsl:choose> <xsl:when test="string-length($enlace) > 0"> <xsl:call-template name="imprimeEnlace"> <xsl:with-param name="valor" select="valor"></xsl:with-param> <xsl:with-param name="longitud" select="longitud"></xsl:with-param> <xsl:with-param name="comentario" select="comentario"></xsl:with-param> <xsl:with-param name="enlace" select="enlace"></xsl:with-param> <xsl:with-param name="target_enlace" select="target_enlace"></xsl:with-param> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$valor"/> </xsl:otherwise> </xsl:choose> </h2> </xsl:template> <xsl:template name="imprimeSubtituloParrafo"> <xsl:param name="etiqueta"></xsl:param> <xsl:param name="valor"></xsl:param> <xsl:param name="longitud"></xsl:param> <xsl:param name="enlace"></xsl:param> <xsl:param name="target_enlace"></xsl:param> <h3 class="subtitulo"> <xsl:choose> <xsl:when test="string-length($enlace) > 0"> <xsl:call-template name="imprimeEnlace"> <xsl:with-param name="valor" select="valor"></xsl:with-param> <xsl:with-param name="longitud" select="longitud"></xsl:with-param> <xsl:with-param name="comentario" select="comentario"></xsl:with-param> <xsl:with-param name="enlace" select="enlace"></xsl:with-param> <xsl:with-param name="target_enlace" select="target_enlace"></xsl:with-param> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:value-of select="$valor"/> </xsl:otherwise> </xsl:choose> </h3> </xsl:template> <xsl:template name="imprimeTextoParrafo"> <xsl:param name="etiqueta"></xsl:param> <xsl:param name="valor"></xsl:param> <xsl:param name="longitud"></xsl:param> <xsl:param name="enlace"></xsl:param> <xsl:param name="target_enlace"></xsl:param> <div class="texto"> <p class="texto"> <xsl:copy-of select="$valor/node()"/> </p> </div> </xsl:template> <xsl:template name="imprimeImagenParrafo"> <xsl:param name="etiqueta"></xsl:param> <xsl:param name="valor"></xsl:param> <xsl:param name="longitud"></xsl:param> <xsl:param name="comentario"></xsl:param> <xsl:param name="enlace"></xsl:param> <xsl:param name="target_enlace"></xsl:param> <xsl:choose> <xsl:when test="string-length($enlace) = 0"> <xsl:call-template name="imprimeImagen"> <xsl:with-param name="etiqueta" select="etiqueta"></xsl:with-param> <xsl:with-param name="valor" select="valor"></xsl:with-param> <xsl:with-param name="longitud" select="longitud"></xsl:with-param> <xsl:with-param name="comentario" select="comentario"></xsl:with-param> <xsl:with-param name="enlace" select="enlace"></xsl:with-param> <xsl:with-param name="target_enlace" select="target_enlace"></xsl:with-param> </xsl:call-template> </xsl:when> <xsl:otherwise> <a> <xsl:choose> <xsl:when test="$target_enlace/node() = 'E'"> <xsl:attribute name="target"> <xsl:text>_blank</xsl:text> </xsl:attribute> </xsl:when> <xsl:when test="$target_enlace/node() = 'I'"> <xsl:attribute name="target"> <xsl:text>_self</xsl:text> </xsl:attribute> </xsl:when> </xsl:choose> <xsl:attribute name="href"> <xsl:value-of select="$enlace"/> </xsl:attribute> <xsl:call-template name="imprimeImagen"> <xsl:with-param name="etiqueta" select="etiqueta"></xsl:with-param> <xsl:with-param name="valor" select="valor"></xsl:with-param> <xsl:with-param name="longitud" select="longitud"></xsl:with-param> <xsl:with-param name="comentario" select="comentario"></xsl:with-param> <xsl:with-param name="enlace" select="enlace"></xsl:with-param> <xsl:with-param name="target_enlace" select="target_enlace"></xsl:with-param> </xsl:call-template> </a> </xsl:otherwise> </xsl:choose> </xsl:template> <xsl:template name="imprimeImagen"> <xsl:param name="etiqueta"></xsl:param> <xsl:param name="valor"></xsl:param> <xsl:param name="longitud"></xsl:param> <xsl:param name="comentario"></xsl:param> <xsl:param name="enlace"></xsl:param> <xsl:param name="target_enlace"></xsl:param> <div class="imagen_pie"> <img> <xsl:attribute name="src"> <xsl:value-of select="$valor"/> </xsl:attribute> <xsl:attribute name="alt"> <xsl:value-of select="$comentario"/> </xsl:attribute> </img> </div> </xsl:template> <xsl:template name="imprimeEnlace"> <xsl:param name="valor"></xsl:param> <xsl:param name="longitud"></xsl:param> <xsl:param name="comentario"></xsl:param> <xsl:param name="enlace"></xsl:param> <xsl:param name="target_enlace"></xsl:param> <a> <xsl:choose> <xsl:when test="$target_enlace/node() = 'E'"> <xsl:attribute name="target"> <xsl:text>_blank</xsl:text> </xsl:attribute> </xsl:when> <xsl:when test="$target_enlace/node() = 'I'"> </xsl:when> <xsl:when test="$target_enlace/node() = 'D'"> </xsl:when> </xsl:choose> <xsl:attribute name="href"> <xsl:value-of select="enlace"/> </xsl:attribute> <xsl:value-of select="$valor"/> </a> </xsl:template> .... </xsl:stylesheet> I need to first apply the template image (if exists in this "PARRAFO") "Imagen" just before the text "Texto" Now apply the template text first and then the image because it is before the text node before the image as shown in xml Thanks a lot!

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• Problem using OLEDBCOMMANDBUILDER.

  - by Lullly

  So, here it goes: I need to copy data from table in access database, in another table from another access database. Column names from tables are the same, except the fact that the FROM table has 5 columns, the TO table has 6. here is my code: dsFrom.Clear() dsTO.Clear() daFrom = Nothing daTO = Nothing conn_string1 = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source="etc.mdb;" conn_string2 = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source="database.mdb;" query1 = "Select * from nomenclator_produse" query2 = "Select * from nomenclator_produse" Conn1 = New OleDbConnection(conn_string1) conn2 = New OleDbConnection(conn_string2) Conn1.Open() conn2.Open() daFrom = New OleDbDataAdapter(query1, Conn1) daTO = New OleDbDataAdapter(query2, conn2) daFrom.AcceptChangesDuringFill = False dsFrom.HasChanges() daFrom.Fill(dsFrom, "nomenclator_Produse") dsFrom.HasChanges() Dim cb = New OleDbCommandBuilder(daFrom) dsTO = dsFrom.Copy daTO.UpdateCommand = cb.GetUpdateCommand daTO.InsertCommand = cb.GetInsertCommand daTO.Update(dsTO, "nomenclator_produse") Because the FROM table has 5 rows and the other has 6, i'm trying to use the InsertCommand generated by the DataAdapter of the first table. It works, only that it inserts the data from the FROMTABLE in the same FROMTABLE, instead of TOTABLE. :| please help me :(

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• [LINQ] Master &ndash; Detail Same Record(II)

  - by JTorrecilla

  In my previous post, I introduced my problem, but I didn’t explain the problem with Entity Framework When you try the solution indicated you will take the following error: LINQ to Entities don’t recognize the method 'System.String Join(System.String, System.Collections.Generic.IEnumerable`1[System.String])’ of the method, and this method can’t be translated into a stored expression. The query that produces that error was: 1: var consulta = (from TCabecera cab in 2: contexto_local.TCabecera 3: let Detalle = (from TDetalle detalle 4: in cab.TDetalle 5: select detalle.Nombre) 6: let Nombres = string.Join(",",Detalle ) 7: select new 8: { 9: cab.Campo1, 10: cab.Campo2, 11: Nombres 12: }).ToList(); 13: grid.DataSource=consulta;   Why is this error happening? This error happens when the query couldn’t be translated into T-SQL. Solutions? To quit that error, we need to execute the query on 2 steps: 1: var consulta = (from TCabecera cab in 2: contexto_local.TCabecera 3: let Detalle = (from TDetalle detalle 4: in cab.TDetalle 5: select detalle.Nombre) 6: select new 7: { 8: cab.Campo1, 9: cab.Campo2, 10: Detalle 11: }).ToList(); 12: var consulta2 = (from dato in consulta 13: let Nombes = string.Join(",",dato.Detalle) 14: select new 15: { 16: dato.Campo1, 17: dato.Campo2, 18: Nombres 19: }; 20: grid.DataSource=consulta2.ToList(); Curiously This problem happens with Entity Framework but, the same problem can’t be reproduced on LINQ – To – SQL, that it works fine in one unique step. Hope It’s helpful Best Regards

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• question about qsort in c++

  - by davit-datuashvili

  i have following code in c++ #include <iostream> using namespace std; void qsort5(int a[],int n){ int i; int j; if (n<=1) return; for (i=1;i<n;i++) j=0; if (a[i]<a[0]) swap(++j,i,a); swap(0,j,a); qsort5(a,j); qsort(a+j+1,n-j-1); } int main() { return 0; } void swap(int i,int j,int a[]) { int t=a[i]; a[i]=a[j]; a[j]=t; } i have problem 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(13) : error C2780: 'void std::swap(std::basic_string<_Elem,_Traits,_Alloc> &,std::basic_string<_Elem,_Traits,_Alloc> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\xstring(2203) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(13) : error C2780: 'void std::swap(std::pair<_Ty1,_Ty2> &,std::pair<_Ty1,_Ty2> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(76) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(13) : error C2780: 'void std::swap(_Ty &,_Ty &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(16) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(14) : error C2780: 'void std::swap(std::basic_string<_Elem,_Traits,_Alloc> &,std::basic_string<_Elem,_Traits,_Alloc> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\xstring(2203) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(14) : error C2780: 'void std::swap(std::pair<_Ty1,_Ty2> &,std::pair<_Ty1,_Ty2> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(76) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(14) : error C2780: 'void std::swap(_Ty &,_Ty &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(16) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(16) : error C2661: 'qsort' : no overloaded function takes 2 arguments 1>Build log was saved at "file://c:\Users\dato\Documents\Visual Studio 2008\Projects\qsort5\qsort5\Debug\BuildLog.htm" please help

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• Question about my sorting algorithm in C++

  - by davit-datuashvili

  i have following code in c++ #include <iostream> using namespace std; void qsort5(int a[],int n){ int i; int j; if (n<=1) return; for (i=1;i<n;i++) j=0; if (a[i]<a[0]) swap(++j,i,a); swap(0,j,a); qsort5(a,j); qsort(a+j+1,n-j-1); } int main() { return 0; } void swap(int i,int j,int a[]) { int t=a[i]; a[i]=a[j]; a[j]=t; } i have problem 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(13) : error C2780: 'void std::swap(std::basic_string<_Elem,_Traits,_Alloc> &,std::basic_string<_Elem,_Traits,_Alloc> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\xstring(2203) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(13) : error C2780: 'void std::swap(std::pair<_Ty1,_Ty2> &,std::pair<_Ty1,_Ty2> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(76) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(13) : error C2780: 'void std::swap(_Ty &,_Ty &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(16) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(14) : error C2780: 'void std::swap(std::basic_string<_Elem,_Traits,_Alloc> &,std::basic_string<_Elem,_Traits,_Alloc> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\xstring(2203) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(14) : error C2780: 'void std::swap(std::pair<_Ty1,_Ty2> &,std::pair<_Ty1,_Ty2> &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(76) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(14) : error C2780: 'void std::swap(_Ty &,_Ty &)' : expects 2 arguments - 3 provided 1> c:\program files\microsoft visual studio 9.0\vc\include\utility(16) : see declaration of 'std::swap' 1>c:\users\dato\documents\visual studio 2008\projects\qsort5\qsort5\qsort5.cpp(16) : error C2661: 'qsort' : no overloaded function takes 2 arguments 1>Build log was saved at "file://c:\Users\dato\Documents\Visual Studio 2008\Projects\qsort5\qsort5\Debug\BuildLog.htm" please help

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• Error inserting data in binary tree

  - by chepe263

  I copied this code (in spanish) http://www.elrincondelc.com/nuevorincon/index.php?pag=codigos&id=4 and wrote a new one. This is my code: #include <cstdlib> #include <conio.h> #include <iostream> using namespace std; struct nodoarbol { int dato; struct nodoarbol *izq; struct nodoarbol *der; }; typedef nodoarbol Nodo; typedef Nodo *Arbol; void insertar(Arbol *, int); void inorden(Arbol); void postorden(Arbol); void preorden(Arbol); void insertar(Arbol *raiz, int nuevo){ if (*raiz==NULL){ *raiz = (Nodo *)malloc(sizeof(Nodo)); if (*raiz != NULL){ (*raiz)->dato=nuevo; (*raiz)->der=NULL; (*raiz)->izq=NULL; } else{ cout<<"No hay memoria suficiente u ocurrio un error"; } } else{ if (nuevo < (*raiz)->dato) insertar( &((*raiz)->izq), nuevo ); else if (nuevo > (*raiz)->dato) insertar(&((*raiz)->der), nuevo); } }//inseertar void inorden(Arbol raiz){ if (raiz != NULL){ inorden(raiz->izq); cout << raiz->dato << " "; inorden(raiz->der); } } void preorden(Arbol raiz){ if (raiz != NULL){ cout<< raiz->dato << " "; preorden(raiz->izq); preorden(raiz->der); } } void postorden(Arbol raiz){ if (raiz!=NULL){ postorden(raiz->izq); postorden(raiz->der); cout<<raiz->dato<<" "; } } int main() { int i; i=0; int val; Arbol raiz = NULL; for (i=0; i<10; i++){ cout<<"Inserte un numero"; cin>>val; insertar( (raiz), val); } cout<<"\nPreorden\n"; preorden(raiz); cout<<"\nIneorden\n"; inorden(raiz); cout<<"\nPostorden\n"; postorden(raiz); return 0; } I'm using netbeans 7.1.1, mingw32 compiler This is the output: make[2]: Leaving directory `/q/netbeans c++/NetBeansProjects/treek' make[1]: Leaving directory `/q/netbeans c++/NetBeansProjects/treek' main.cpp: In function 'int main()': main.cpp:110:30: error: cannot convert 'Arbol {aka nodoarbol*}' to 'Nodo** {aka nodoarbol**}' for argument '1' to 'void insertar(Nodo**, int)' make[2]: *** [build/Release/MinGW-Windows/main.o] Error 1 make[1]: *** [.build-conf] Error 2 make: *** [.build-impl] Error 2 BUILD FAILED (exit value 2, total time: 11s) I don't understand what's wrong since i just copied the code (and rewrite it to my own code). I'm really good in php, asp.net (vb) and other languages but c is a headche for me. I've been struggling with this problem for about an hour. Could somebody tell me what could it be?

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• Gmail zend imap - latency when fetching messageids

  - by T.B Ygg

  i have this code to fetch emails from gmail using imap with the zend framework. i go back 2 days in my search (as i do not want all messages) all works well but it takes forever to load the messages and i need to do this for 5+ users, it seems like the search goes through the entire gmail message archive in getting the newest ones. my code looks like this: $dato = date('j-F-Y', strtotime($Date. ' - 2 days')); $dato = "SINCE ".$dato; $messageids = $imap->search(array($dato)); any ideas on how to make zend work faster?

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• How can I modified the value of a string defined in a struc?

  - by Eric

  Hi, I have the following code in c++: define TAM 4000 define NUMPAGS 512 struct pagina { bitset<12 direccion; char operacion; char permiso; string *dato; int numero; }; void crearPagina(pagina* pag[], int pos, int dir) { pagina * paginas = (pagina*)malloc(sizeof(char) * TAM); paginas - direccion = bitset<12 (dir); paginas - operacion = 'n'; paginas - permiso = 'n'; string **tempDato = &paginas - dato; char *temp = " "; **tempDato = temp; paginas - numero = 0; pag[pos] = paginas; } I want to modify the value of the variable called "string *dato" in the struct pagina but, everytime I want to assing a new value, the compiler throws a segmentation fault. In this case I'm using a pointer to string, but I have also tried with a string. In a few words I want to do the following: pagina - dato = "test"; Any idea? Thanks in advance!!!

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• How can I modify the value of a string defined in a struct?

  - by Eric

  Hi, I have the following code in c++: #define TAM 4000 #define NUMPAGS 512 struct pagina { bitset<12> direccion; char operacion; char permiso; string *dato; int numero; }; void crearPagina(pagina* pag[], int pos, int dir) { pagina * paginas = (pagina*)malloc(sizeof(char) * TAM); paginas -> direccion = bitset<12> (dir); paginas -> operacion = 'n'; paginas -> permiso = 'n'; string **tempDato = &paginas -> dato; char *temp = " "; **tempDato = temp; paginas -> numero = 0; pag[pos] = paginas; } I want to modify the value of the variable called "string *dato" in the struct pagina but, everytime I want to assing a new value, the compiler throws a segmentation fault. In this case I'm using a pointer to string, but I have also tried with a string. In a few words I want to do the following: pagina - dato = "test"; Any idea? Thanks in advance!!!

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• XCode iPhone Programming: Loading a jpg into a UIImageView from URL

  - by Antonio Murgia

  My app has to load an image from a http server and displaying it into an UIImageView How can i do that?? I tried this: NSString *temp = [NSString alloc]; [temp stringwithString:@"http://192.168.1.2x0/pic/LC.jpg"] temp=[(NSString *)CFURLCreateStringByAddingPercentEscapes( nil, (CFStringRef)temp, NULL, NULL, kCFStringEncodingUTF8) autorelease]; NSData *dato = [NSData alloc]; dato=[NSData dataWithContentsOfURL:[NSURL URLWithString:temp]]; pic = [pic initWithImage:[UIImage imageWithData:dato]]; This code is in viewdidload of the view but nothing is displayed! The server is working because i can load xml files from it. but i can't display that image! I need to load the image programmatically because it has to change depending on the parameter passed! Thank you in advance. Antonio

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• Reset disk does not work for different model of computer

  - by dato

  I've created a reset USB disk on my HP computer, with Windows 7 Ultimate 32-bit, and it works fine. However, it does not work for Acer computers (notebooks too), so what is the problem here? I've have created it for the same user named user, and the password is exactly the same as well. Is it possible to show the language bar with a keyboard shortcut at the logon screen in Windows 7? I know I can do it through Control Panel, but I can't log into the system. When I click Reset Passwword, it shows me my USB flash drive and says that the password hint is on this USB drive. Then I click Next and type the new passwword, then confirm this new password, but an error dialog is shown. It says that an error occured when trying to change the password for this user-

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• Converting a certain SQL query into relational algebra

  - by Fumler

  Just doing an assignment for my database course and I just want to double check that I've correctly wrapped my head around relational algebra. The SQL query: SELECT dato, SUM(pris*antall) AS total FROM produkt, ordre WHERE ordre.varenr = produkt.varenr GROUP BY dato HAVING total >= 10000 The relational algebra: stotal >= 10000( ?R(dato, total)( sordre.varenr = produkt.varenr( datoISUM(pris*antall(produkt x ordre)))) Is this the correct way of doing it?

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• determine if line segment is inside polygon

  - by dato

  suppose we have simple polygon(without holes) with vertices (v0,v1,....vn) my aim is to determine if for given point p(x,y) any line segment connecting this point and any vertices of polygon is inside polygon or even for given two point p(x0,y0) `p(x1,y1)` line segment connecting these two point is inside polygon? i have searched many sites about this ,but i am still confused,generally i think we have to compare coordinates of vertices and by determing coordinates of which point is less or greater to another point's coordinates,we could determine location of any line segment,but i am not sure how correct is this,please help me

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• Problem in linking an nasm code

  - by Stefano

  I'm using a computer with an Intel Core 2 CPU and 2GB of RAM. The SO is Ubuntu 9.04. When I try to compile this code: ;programma per la simulazione di un terminale su PC, ottenuto utilizzando l'8250 ;in condizione di loopback , cioè Tx=Rx section .code64 section .data TXDATA EQU 03F8H ;TRASMETTITORE RXDATA EQU 03F8H ;RICEVITORE BAUDLSB EQU 03F8H ;DIVISORE DI BAUD RATE IN LSB BAUDMSB EQU 03F9H ;DIVISORE DI BAUD RATE IN MSB INTENABLE EQU 03F9H ;REGISTRO DI ABILITAZIONE DELL'INTERRUZIONE INTIDENTIF EQU 03FAH ;REGISTRO DI IDENTIFICAZIONE DELL'INTERRUZIONE LINECTRL EQU 03FBH ;REGISTRO DI CONTROLLO DELLA LINEA MODEMCTRL EQU 03FCH ;REGISTRO DI CONTROLLO DEL MODEM LINESTATUS EQU 03FDH ;REGISTRO DI STATO DELLA LINEA MODEMSTATUS EQU 03FEH ;REGISTRO DI STATO DEL MODEM BAUDRATEDIV DW 0060H ;DIVISOR: LOW=60, HIGH=00 -BAUD =9600 COUNTERCHAR DB 0 ;CHARACTER COUNTER ;DW 256 DUP (?) section .text global _start _start: ;PROGRAMMAZIONE 8250 MOV DX,LINECTRL MOV AL,80H ;BIT 7=1 PER INDIRIZZARE IL BAUD RATE OUT DX,AL MOV DX,BAUDLSB MOV AX,BAUDRATEDIV ;DEFINISCO FATTORE DI DIVISIONE OUT DX,AL MOV DX,BAUDMSB MOV AL,AH OUT DX,AL ;MSB MOV DX,LINECTRL MOV AL,00000011B ;8 BIT DATO, 1 STOP, PARITA' NO OUT DX,AL MOV DX,MODEMCTRL MOV AL,00010011B ;BIT 4=0 PER NO LOOPBACK OUT DX,AL MOV DX,INTENABLE XOR AL,AL ;DISABILITO TUTTI GLI INTERRUPTS OUT DX,AL CICLO: MOV DX,LINESTATUS IN AL,DX ;LEGGO IL REGISTRO DI STATO DELLA LINEA TEST AL,00011110B ;VERIFICO GLI ERRORI (4 TIPI) JNE ERRORI TEST AL,01H ;VERIFICO Rx PRONTO JNE LEGGOCHAR TEST AL,20H ;VERIFICO Tx VUOTO JE CICLO ;SE SI ARRIVA A QUESTO PUNTO ALLORA L'8250 è PRONTO PER TRASMETTERE UN NUOVO CARATTERE MOV AH,1 INT 80H JE CICLO ;SE SI ARRIVA A QUESTO PUNTO SIGNIFICA CHE ESISTE UN CARATTERE DA TASTIERA MOV AH,0 INT 80H ;Al CONTIENE IL CARATTERE DELLA TASTIERA MOV DX,3F8H OUT DX,AL JMP CICLO LEGGOCHAR: MOV AL,[COUNTERCHAR] INC AL CMP AL,15 JE FINE MOV [COUNTERCHAR],AL MOV DX,TXDATA IN AL,DX ;AL CONTIENE IL CARATTERE RICEVUTO AND AL,7FH ;POICHè VI SONO 7 BIT DI DATO ;VISUALIZZAZIONE DEL CARATTERE MOV BX,0 MOV AH,14 INT 80H POP AX CMP AL,0DH ;CONTROLLO SE RETURN JNE CICLO ;CAMBIO RIGA DI VISUALIZZAZIONE MOV AL,0AH MOV BX,0 MOV AH,14 ;INT 10H INT 80H JMP CICLO ;GESTIONE ERRORI ERRORI: MOV DX,3F8H IN AL,DX MOV AL,'?' MOV BX,0 MOV AH,14 INT 80H JMP CICLO FINE: XOR AH,AH MOV AL,03 INT 80H When I compile this code "NASM -f bin UARTLOOP.asm", the compiler can create the UARTLOOP.o file without any error. When I try to link the .o file with "ld UARTLOOP.o" it tells: UARTLOOP.o: In function `_start': UARTLOOP.asm:(.text+0xd): relocation truncated to fit: R_X86_64_16 against `.data' Have u got some ideas to solve this problem? Thx =)

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• question about charAt function

  - by davit-datuashvili

  i know java API function charAt for example String s="dato" char r=s.charAt(0); r is equal d but my question is how realy it works or what function can i use instead of charAt function to get same result? thanks

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• float right image pushes down text in table below in IE9 [migrated]

  - by Cheers and hth. - Alf

  I'm not a webmaster, not even a web developer, but I'm tasked with adding content to a Wordpress site developed by Someone Else(TM). Here's a page illustrating the problem: http://www.reginedagan.no/program/fiskekonkurranse-i-hovden/. It shows up nice in Firefox: But in IE9 the floated picture pushed down the text in the table below, so that it looks rather awful: I found some related questions on the web, e.g. "CSS: Float right in IE doesn't work!" and "why does a floating DIV mess up table positioning?", and the suggestions there led me to set clear: none on the div around the table, the table itself, and then each individual tr and finally even on each individual td. I also set width="99%" on the table, and tried (but I don't know how correctly) to apply the IE6 quirk fix margin-right: -3px. So here's the content as written in Wordpress, including the unsuccessful attempted fixes: <h1><div style="float: right"><a href="http://www.reginedagan.no/?attachment_id=671"><img src="http://www.reginedagan.no/wp-content/uploads/2012/06/fiskekonkurranse-2011-bilde-3-nedskalert.jpg" alt="Fra fiskekonkurransen i 2011" title="Fra fiskekonkurransen i 2011" width="200" height="242" class="size-full wp-image-671"/></a></div>Fiskekonkurranse i Hovden!</h1> <div style="background-color: #FAF0F0; clear: none;"><table width="99%" style="clear: none; right-margin: -3px;"> <tr style=" clear: none;"> <td style="text-align: left; clear: none;">Dato:</td> <td style="text-align: left; clear: none;">Lørdag 21.juli</td> </tr> <tr style=" clear: none;"> <td style="text-align: left; padding-left: 2em"; clear: none;>/ barn, Flytebrygga</td> <td style="text-align: left; clear: none;">15.00 &ndash; 16.00</td> </tr> <tr style=" clear: none;"> <td style="text-align: left; padding-left: 2em; clear: none;">/ voksne (over 12 år), Moloen</td> <td style="text-align: left; clear: none;">15.00 &ndash; 17.00 </td> </tr> <tr style=" clear: none;"> <td style="text-align: left; clear: none;">Sted:</td> <td style="text-align: left; clear: none;">Hovden</td> </tr> <tr style=" clear: none;"> <td style="text-align: left; clear: none;">Pris:</td> <td style="text-align: left; clear: none;">voksen (over 12 år) kr. 50,-, barn kr. 30,-</td> </tr style=" clear: none;"> <tr> <td style="text-align: left; clear: none;">Arrangør:</td> <td style="text-align: left; clear: none;">Hovden Grendelag</td> </tr> </table></div> Velkommen til den årlige Fiskekonkurransen i Hovden lørdag 21. juli! <a href="http://www.reginedagan.no/program/fiskekonkurranse-i-hovden/fiskekonkurranse-2011-bilde-nedskalertjpg/" rel="attachment wp-att-672"><img src="http://www.reginedagan.no/wp-content/uploads/2012/03/fiskekonkurranse-2011-bilde-nedskalertjpg.jpg" alt="Fra fiskekonkurransen i 2011" title="Fra fiskekonkurransen i 2011" width="400" height="267" class="alignleft size-full wp-image-672" /></a>Det blir stangfiske fra moloen og egen barnekonkurranse fra flytebrygga. Premiering for størst fisk, størst antall kg og flest antall stk. Premiering for barn kl. 16:30 på moloen. Alle premieres. Premiering for voksne på festen om kvelden. Salg av pølser og brus, vafler og kaffe, samt sluker. <div style="clear: left; border: 1px dashed gray; padding: 1em;"> Fest på Hovden samfunnshus kl. 21 &ndash; 02. Musikk: «Mister West», Steinar Aarsnes, Andøya. CC. Salg av øl/vin og snacks. </div> VEL MØTT &mdash; SKITT FISKE! And the resulting HTML served to a browser (only the relevant first part): <div style="float: right;"><a href="http://www.reginedagan.no/?attachment_id=671"><img src="http://www.reginedagan.no/wp-content/uploads/2012/06/fiskekonkurranse-2011-bilde-3-nedskalert.jpg" alt="Fra fiskekonkurransen i 2011" title="Fra fiskekonkurransen i 2011" class="size-full wp-image-671" height="242" width="200"></a></div> <p>Fiskekonkurranse i Hovden!</p></h1> <div style="background-color: rgb(250, 240, 240); clear: none;"> <table style="clear: none;" width="99%"> <tbody><tr style="clear: none;"> <td style="text-align: left; clear: none;">Dato:</td> <td style="text-align: left; clear: none;">Lørdag 21.juli</td> </tr> The able to reproduce the effect with simpler code by setting clear: right on the table. However, I'm unable to reproduce the effect with default styling or with clear: none (as above). So it seems maybe it's something Wordpress does, or maybe it's something the theme thing or whatever it is does – but it's very similar to what others have observed, so there is strong indication that it's also a quirk in IE. Help?

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• Installazione ATI Mobility Radeon HD 5650 su Ubuntu 11.10

  - by Antonio

  Salve a tutti, possiedo un portatile HP Pavillion dv6 3110 con scheda video dedicata ATI Mobility Radeon HD 5650 da 1 Giga ed ho installato da poco Ubuntu 11.10 Versione 64 bit. Ho seguito molte guide su internet per installare i driver per la mia scheda video ma nessuna ha dato esito positivo. Nella finestra "driver aggiuntivi" sono riuscito ad installare i "Driver grafici fglrx proprietari ATI/AMD" ma dopo il riavvio non riesco ad utilizzare correttamente la scheda video. Mentre i "Driver grafici fglrx proprietari ATI/AMD (aggiornamenti post-release)" non me li fa proprio installare segnalando un errore che riporto di seguito "L'installazione di questo driver non è riuscita.Consultare i file di registro per maggiori informazioni: /var/log/jockey.log". Ho pensato allora di scaricare direttamente dal sito di AMD gli ultimi driver rilasciati attraverso il pacchetto "amd-driver-installer-12-3-x86.x86_64.run", l'ho lanciato, ho seguito il wizard di installazione, l'installazione viene completata, digito "sudo aticonfig --initial" per la configurazione iniziale, ma al riavvio del pc appaiono soltanto scritte su schermo nero con una serie di "OK" e qualche "FAIL". Ho provato questa procedura anche per le versioni precedenti dei driver, ma il risultato è sempre lo stesso. Sono disperato. Riuscirò mai ad utilizzare la mia scheda video? Vi incollo per completezza ciò che mi appare all'esecuzione del comando "lspci -nn | grep VGA" per visualizzare i processori grafici presenti sul mio pc: 00:02.0 VGA compatible controller [0300]: Intel Corporation Core Processor Integrated Graphics Controller [8086:0046] (rev 02) 01:00.0 VGA compatible controller [0300]: ATI Technologies Inc Madison [AMD Radeon HD 5000M Series] [1002:68c1] Grazie anticipatamente a coloro che potranno aiutarmi. Cordiali Saluti Antonio Giordano

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• CUOA Workshop: “L’evoluzione dei modelli e dei sistemi di analisi e reporting direzionale”

  - by Paolo Leveghi

  Il 26 Giugno scorso presso l’Aula Magna della Fondazione CUOA si è tentuo il workshop “L’evoluzione dei modelli e dei sistemi di analisi e reporting direzionale”, promosso dal Club Finance CUOA con la collaborazione di Oracle .  Una recente analisi di Gartner ha evidenziato che Executives Finance ed IT hanno identificato Business Intelligence, Analytics e Performance Management come tema prioritario su cui concentrare gli investimenti “tecnologici” nel 2013 confermando, se mai qualcuno ne avesse avuto bisogno, la continua e crescente attenzione delle aziende alla propria capacità di definire, produrre e gestire informazioni funzionali all’identificazione di opportunità, alla valutazione di rischi ed impatti, alla simulazione degli effetti di operazioni ordinarie e straordinarie...in un solo concetto, informazioni funzionali alla guida dell’azienda. Questo dato è ancora più interessante se incrociato con il risultato di una survey condotta da CFO Magazine e KPMG International nella quale il 48% dei CFO intervistati ha dichiarato di ritenere i propri sistemi datati ed poco flessibili, quindi un limite, se non proprio un freno, alla loro volontà di essere agenti del cambiamento. A fronte di tutto questo, le aziende dimostrano un crescente interesse a capire cosa fare, oggi e domani, per migliorare la propria capacità di sfruttare una risorsa aziendale estremamente pregiata quale l’informazione. L’    Obiettivo del workshop è quindi stato quello di analizzare in quale scenario stanno operando oggi le aziende del Nord Est Italiano verificando, grazie alle testimonianze di ITAL TBS e del Gruppo Carraro,  lo “stato di salute” dei processi di Business Analytics, il livello di cultura aziendale ed il grado di adozione di soluzioni da parte dei CFO, del Management e più in generale dei decisori aziendali, i percorsi evolutivi e prospettici per migliorare su questi temi

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• La Customer Satisfaction non basta più!

  - by Silvia Valgoi

  La partita per la conquista della fedeltà dei clienti si gioca sempre meno sul prodotto e sempre più sul servizio. Dal momento che il consumatore di oggi è molto più evoluto e autonomo nelle scelte, il servizio deve andare ben oltre la classica interazione da Customer Service: deve rappresentare una vera e propria esperienza d’acquisto positiva. Questo è il risultato, che poi è una conferma, di Oracle Customer Experience Index, una ricerca che Oracle ha commissionato alla società LoudHouse la quale ha raccolto le opinioni di 1400 consumatori europei, di cui 200 italiani. Addirittura, l'81% di chi fa acquisti sarebbe disposto a pagare di più per una migliore customer experience. Un risultato non banale che la dice lunga su quanto il consumatore oggi sia evoluto e pretenda molto dall’azienda con la quale sta interagendo. Il 70% di coloro che hanno risposto al questionario afferma che se l’esperienza d’acquisto fosse negativa smetterebbe di rivolgersi a una determinata azienda e il 92% di questi comprerebbe da un concorrente. Ecco perchè il Customer Service non è più sufficiente, l’esperienza d’acquisto deve essere a 360° a partire dall’approccio al sito web per acquisire informazioni, all’analisi delle interazioni sui social media, fino alla consistenza delle informazioni e delle risposte che vengono fornite attraverso tutti i canali sia fisici sia virtuali. Per far questo Oracle ha dato vita a un’insieme di soluzioni che ha chiamato proprio Customer Experience Suite e spaziano dalla creazione di siti web evoluti, alla possibilità di fare Intelligence sui Social Media, alla capacità di creare un proficuo dialogo con i clienti in fase di postvendita. Per leggere il comunicato stampa della ricerca clicca qui   Per approfondire i risultati della ricerca CX Index  clicca qui

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• Imageview in a listview - Height is bugged?

  - by Abdullah Gheith

  I am having a listview but i have problem i have the main.xml file, which contains a Listview: <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="@drawable/gradient" android:gravity="center" android:padding="1pt"> <ListView android:id="@+id/ListView01" android:layout_width="wrap_content" android:layout_height="fill_parent" android:background="@android:color/transparent" android:cacheColorHint="#00000000"/> </LinearLayout> Then, i have a custom listview file called listview.xml: <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="wrap_content" android:layout_height="wrap_content" android:orientation="vertical" android:background="@android:color/transparent" android:cacheColorHint="#00000000"> <TextView android:gravity="center" android:textColor="#ffffff" android:background="#0097D0" android:text="Overskrift" android:id="@+id/tvOverskrift" android:layout_width="fill_parent" android:layout_height="wrap_content" android:textStyle="bold" /> <ImageView android:id="@+id/ivBillede" android:scaleType="fitXY" android:padding="2px" android:gravity="fill" android:layout_width="wrap_content" android:layout_height="wrap_content" android:src="@drawable/test"/> <TextView android:gravity="center" android:textColor="#ED2025" android:text="Dato" android:id="@+id/tvDato" android:layout_width="wrap_content" android:layout_height="wrap_content" android:textStyle="normal"/> <TextView android:gravity="left" android:textColor="#000000" android:text="Indledning" android:id="@+id/tvIndledning" android:layout_width="wrap_content" android:layout_height="wrap_content" android:textStyle="normal"/> </LinearLayout> the bitmap in the imagview i am getting is from a URL. By that code, i am getting is this: http://img585.imageshack.us/img585/5665/unavngivetv.png I am getting too much space in the height as you see

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• codeigniter and JSON

  - by ole

  Hello all i having a problem that it only get 1 value in my database and its my title and i want to show content and username from the same table to. here is my JSON kode <script type="text/javascript"> $.getJSON( 'ajax/forumThreads', function(data) { alert(data[0].overskrift); alert(data[0].indhold); } ); </script> my controller <?php class ajax extends Controller { function forumThreads() { $this->load->model('ajax_model'); $data['forum_list'] = $this->ajax_model->forumList(); if ($data['forum_list'] !== false) { echo json_encode($data['forum_list']); } } } my model fle <?php class ajax_model extends Model { function forumList() { $this->db->select('overskrift', 'indhold', 'brugernavn', 'dato'); $this->db->order_by('id', 'desc'); $this->db->limit(5); $forum_list = $this->db->get('forum_traad'); if($forum_list->num_rows() > 0) { return $forum_list->result_array(); } else { return false; } } }

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