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  • IASA South East Florida Chapter Meeting Recap - June 2011

    - by Sam Abraham
    Erik Russell and Giles Marino were our speakers for the June 2011 IASA South East Florida Chapter meeting.    Attendees filled all available seats at the Microsoft office conference room where the event was held. This highlights the high interest in Enterprise Architecture as a career track and chartered project role. Also in attendance were our Board of Directors and Alex Funkhouser, President, Sherlock Technology.   Rainer Habermann, Chapter President, kicked off the meeting by introducing our speakers and Board of Directors.   Alex Funkhouser, President of South Florida’s staffing firm Sherlock Technology spoke briefly about available Software Architect positions in the area. Alex also congratulated and presented this week’s Sherlock Raffle winner with $500 in cash.   Our speakers Giles and Erik then proceeded with their talk. Erik presented a business case in the government sector where Enterprise Architecture helped a government entity cut costs and streamline its various business operations. Technologies leveraged in Erik’s demonstrated project were Java-based.   Giles then followed with a thorough demonstration of the Architecture patterns he used to migrate a complete backend system for an insurance company to the .Net Platform.   Audience was very engaged with our speakers as evidenced by the large number of follow-up questions asked at the end of the talk.   We greatly enjoyed Giles and Erik’s talk and look forward to having them share with us more of their adventures as Enterprise Architects in the near future.   Below are some photos of the event.   Sam Abraham Secretary- IASA South East Florida Chapter. http://www.iasaglobal.org/iasa/South_East_Florida.asp Chapter President - Rainer Habermann kicks off our meeting.   Sherlock Technology President Alex Funkhouser holding Sherlock's weekly cash prize. Alex shares available Software Architect opportunities with our members Erik Russell addressing our membership Giles Marino sharing his architecture experience in the insurance industry In this photo: Dave Noderer, Rainer Habermann, Quent Herschelman and Alex Funkhouser. Event attracted a large audience and filled the Microsoft conference room where it was held

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  • jQuery not and classes

    - by Giles B
    Hi Guys, I have 2 anchor links (a.selector) and when one is clicked it has a class applied to it of 'active-arrow' and the click also removes the class of the same name from the other anchor as well as lowering the opacity to 0.2. I then want to have a fade effect when the user hovers over the anchor that doesn't have 'active-arrow' applied to it so that it goes to full opacity when mouseenters and back to 0.2 when mouseleaves. The problem im having is that both .not and :not don't seem to be working as expected, the hover effect works but if I click on the anchor whilst hovering the 'active-arrow' class is applied but when mouseleaves the opacity is faded down to 0.2 again even though the 'active-arrow' class is applied. Also the hover then doesn't work for the other a link which has had 'active-arrow' removed. Bit of a hard one to explain so heres some code that hopefully helps a bit. *//If a.selector doesn't have the class 'active-arrow' then run the hoverFade function* $("a.selector").not(".active-arrow").hoverFade(); //Functions for first element $('a.selector-1').click(function () { $('a.selector-2').removeClass('active-arrow'); //Remove background image from corresponding element $('ul#storage-items-2').fadeOut(1200).addClass('hide'); //Fade out then hide corresponding list $(this).addClass('active-arrow', 'fast'); //Add background image to current element $('ul#storage-items-1').removeClass('hide').fadeIn(1800); //Unhide and fade in the list $('a.selector-2').fadeTo(500, 0.2); //Fade corresponding element $(this).fadeTo(800, 1);//Fade this element to full opacity }); I only included the code for teh first anchor (a.selector-1) as the code for the second anchor is identical but just changes the class names to a.selector-2. Also the hoverFade function is in a seperate file so we can re-use it. jQuery.fn.hoverFade = function() { return this.each(function(){ $(this).hover( function () { $(this).fadeTo(500, 0.8); }, function () { $(this).fadeTo(500, 0.2); }); }); } Each anchor link fades in and fades out a UL as well. Any help is most appreciated Thanks Giles

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  • Scrollable list items in jQuery

    - by Giles B
    Hi Guys, I have a list of 4 items and the ul has a background image that makes the second item look as though it has an arrow behind it. I want to be able to scroll the items up or down when they are clicked to the second items position so for example when I click the fourth item the whole list scrolls up so the fourth item is then postioned over the top of the background image and all the other items will be sitting in the same order above it. I have tried using jQuery Tools with the circular option selected but it clones the first an last item and i end up with a gap when i get to the bottom and I also cant make each item selectable to scroll the list up or down. Here is the code for the list <div id="priceGuide"> <ul id="priceRegion"> <li><a href="#">North & Midlands</a></li> <li><a href="#">London, north of the river</a></li> <li><a href="#">London, south of the river</a></li> <li><a href="#">South & South East</a></li> </ul><!-- /priceRegion --> </div><!-- /priceGuide --> Any help is most appreciated. Thanks Giles

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  • What is the effect of this order_by clause?

    - by bread
    I don't understand what this order_by clause is doing and whether I need it or not: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date order by i.order_date desc; This produces this data: 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10101 John Gray 30-Jun-1999 Raft 58.00 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10101 John Gray 02-Jan-2000 Lantern 16.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 While if I remove the order_by clause completely, as in this query: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date; I get these results: 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10101 John Gray 02-Jan-2000 Lantern 16.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10101 John Gray 30-Jun-1999 Raft 58.00 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 I'm not sure what the order_by is doing here and if it's having the intended effects.

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  • RDS installation failure on 2012 R2 Server Core VM in Hyper-V Server

    - by Giles
    I'm currently installing a test-bed for my firms Infrastructure replacement. 10 or so Windows/Linux servers will be replaced by 2 physical servers running Hyper-V server. All services (DC, RDS, SQL) will be on Windows 2012 R2 Server Core VMs, Exchange on Server 2012 R2 GUI, and the rest are things like Elastix, MailArchiver etc, which aren't part of the equation thus far. I have installed Hyper-V server on a test box, and sucessfully got two virtual DC's running, SQL 2014 running, and 8.1 which I use for the RSAT tools. When trying to install RDS (The old fashioned kind, not the newer VDI(?) style), I get a failed installation due to the server not being able to reboot. A couple of articles have said not to do it locally, so I've moved on. Sitting at the Powershell prompt on the Domain Controller or SQL server (Both Server Core), I run the following commands: Import-Module RemoteDesktop New-SessionDeployment -ConnectionBroker "AlstersTS.Alsters.local" -SessionHost "AlstersTS.Alsters.local" The installation begins, carries on for 2 or 3 minutes, then I receive the following error message: New-SessionDeployment : Validation failed for the "RD Connection Broker" parameter. AlstersTS.Alsters.local Unable to connect to the server by using WindowsPowerShell remoting. Verify that you can connect to the server. At line:1 char:1 + NewSessionDeployment -ConnectionBroker "AlstersTS.Alsters.local" -SessionHost " ... + + CategoryInfo : NotSpecified: (:) [Write-Error], WriteErrorException + FullyQualifiedErrorID : Microsoft.PowerShell.Commands.WriteErrorException,New-SessionDeployment So far, I have: Triple, triple checked syntax. Tried various other commands, and a script to accomplish the same task. Checked DNS is functioning as it should. Checked to the best of my knowledge that AD is working as it should. Checked that the Network Service has the needed permissions. Created another VM and placed the two roles on different servers. Deleted all VMs, started again with a new domain name (Lather, rinse, repeat) Performed the whole installation on a second physical box running Hyper-V Server Pleaded with it Interestingly, if I perform the installation via a GUI installation, the thing just works! Now I know I could convert this to a Server Core role after installation, but this wouldn't teach me what was wrong in the first instance. I've probably got 10 pages through various Google searches, each page getting a little less relevant. The closest matches seem to have good information, but it doesn't seem to be the fix for my set-up. As a side note, I expected to be able to "tee" or "out-file" the error message into a text file, but couldn't get that to work either, so I've typed in the error message manually. Chaps, any suggestions, from the glaringly obvious, to the long-winded and complex? Thanks!

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  • Advantages of multiple SQL Server files with a single RAID array

    - by Dr Giles M
    Originally posted on stack overflow, but re-worded. Imagine the scenario : For a database I have RAID arrays R: (MDF) T: (transaction log) and of course shared transparent usage of X: (tempDB). I've been reading around and get the impression that if you are using RAID then adding multiple SQL Server NDF files sitting on R: within a filegroup won't yeild any more improvements. Of course, adding another raid array S: and putting an NDF file on that would. However, being a reasonably savvy software person, it's not unthinkable to hypothesise that, even for smaller MDFs sitting on one RAID array that SQL Server will perform growth and locking operations (for writes) on the MDF, so adding NDFs to the filegroup even if they sat on R: would distribute the locking operations and growth operations allowing more throughput? Or does the time taken to reconstruct the data from distributed filegroups outweigh the benefits of reduced locking? I'm also aware that the behaviour and benefits may be different for tables/indeces/log. Is there a good site that distinguishes the benefits of multiple files when RAID is already in place?

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  • Does multiple files in SQL Server when using RAID help reduce conflicts in growth and file-locking?

    - by Dr Giles M
    I've been reading around and get the impression that if you are using RAID then using multiple SQL Server files within a filegroup won't yeild any more improvements, and the benefits are purely administrative (if you started to run out of space or wanted to partition off data into managable chunks for backups/balancing the data around your big server room). However, being a reasonably savvy software person, it's not unthinkable to hypothesise that, even for smaller databases that SQL Server will perform growth and locking operations (for writes) on a LOGICAL file basis, so even if you are using RAID, it seems to make sense to have multiple files in a file group to balance I/O, or does the time taken to reconstruct the data from distributed filegroups outweigh the benefits of reduced locking? I'm also aware that the behaviour and benefits may be different for tables/indeces/log. Is there a good site that distinguishes the benefits of multiple files when RAID is already in place?

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  • Unknown user in terminal

    - by Giles B
    Im having a strange problem with the terminal in OS X. When I open the terminal the username at the command prompt is: unknown-04-0c-ce-e3-0d-c2: ~ I can't pinpoint when this first started or why unfortunately. I usually use iTerm for web development purposes but this also occurs in the normal OS X Terminal app. Any ideas/help would be really appreciated. Thanks Update: Thanks to @fayadfami and @aliasgar for the correct answers and steering me in the right direction. Also this forum post helped http://forums.macrumors.com/showthread.php?t=152407 The extract from the right post: Having run into the exact same issue myself, and having come across this thread while attempting to figure it out, I thought I'd post the answer. OS X is initially setting your hostname to what's set for your Computer Name in Sharing; however, if you're set up for DHCP and you match a current lease on your DHCP server (i.e., match the IP address of another recent user), OS X will then set your hostname to whatever the DHCP server currently has for that lease. This freaked me out incredibly at first, as I had just reformatted (having just purchased my first Mac and wanting to see how the installer worked) and knew I had not yet changed the Computer Name in Sharing -- yet my system hostname at the Terminal prompt was indeed changed to what I had previously set, pre-format. I grepped around, not finding the name anywhere save log entries; I thought either the format didn't actually properly wipe everything, or I was losing my mind. Finally I logged into my router (it's a Linksys WRT54GS running OpenWRT), and found the hostname in the current leases file. I then manually set my Mac's IP to something different, and volia! -- the hostname was back to what I expected. I hope this helps save someone from the same paranoia I went through.

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  • Scottish Visual Studio 2010 Launch event with Jason Zander

    - by Martin Hinshelwood
    Microsoft are hosting a launch event for Visual Studio 2010 on Friday 16th April in Edinburgh. The have managed to convince one of the head honchos from the Visual Studio product team to come to Scotland. With Scott Guthrie last week in Glasgow and now Jason Zander, Global General Manager for Visual Studio will be arriving in Edinburgh for the Launch event. There will be two speakers for the event, Jason will be up first and will be doing a session on Windows, Web, Cloud and Windows Phone 7 development with Visual Studio 2010. Second up is Giles Davis the UK’s Technical Specialist for Visual Studio ALM (formally Visual Studio Team System) who will be introducing the new Visual Studio 2010 Developer and tester collaboration features. LAUNCH AGENDA: 9.30am – 10.00am Arrival 10.00am - 11.30am Keynote & Q&A - Jason Zander, Global GM for Visual Studio 11.30am - 12.00pm Break 12.00pm - 1.00pm Developer & Tester Collaboration with Visual Studio 2010 - Giles Davies, Technical Specialist 1.00pm - 1.30pm Lunch DATE:              Friday, 16th April 2010 LOCATION: Microsoft Edinburgh, Waverley Gate, 2-4 Waterloo Place, Edinburgh, EH1 3EG I think Jason will be hanging out for the afternoon to answer questions and meet everyone. f you would like to attend, please email Nathan Davies on [email protected] with your name, company and email address   Technorati Tags: VS2010,TFS2010,Visual Studio,Visual Studio 2010

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  • Hide/ change width/ change position of UIButton based on device type

    - by Giles Van Gruisen
    I'm using the new in-app SMS features in my iPhone app, but obviously iPod Touches aren't able to send and receive SMS without support of a third party app. I know all well how to detect the device and how to hide a UIButton, but what I do not know is how to change the width of the others. Above are the three icons. The one on the far rights needs to be hidden on an iPod Touch, and the other two need to adjust size/ position to fill the remaining space. Any tips on programatically changing the position and width of a UIButton is greatly appreciated. Thanks!

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  • Replacement relevance sorting for MySQL fulltext in InnoDB tables?

    - by Giles Smith
    I am using MySQL InnoDB and want to do fulltext style searches on certain columns. What is the best way of sorting the results in order of relevance? I am trying to do something like: SELECT columns, (LENGTH(column_name) - LENGTH(REPLACE(column_name, '%searchterm%', ''))) AS score FROM table WHERE column_name LIKE '%searchterm%' ORDER BY score However this will become quite complicated once I start searching more than 1 column or using more than one keyword. I already have several joins happening so have simplified the query above. Can anyone suggest a better way? I don't want to use any 3rd party software like Sphinx etc

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  • simplest way to confirm payment via PayPal?

    - by Giles Bowkett
    Hi - what's the best way to simply get feedback from PayPal to confirm that your customer paid? It looks as if the answer is IPN - if so, my followup question is, can I enable IPN for only specific buttons? I don't want PayPal pinging my IPN listener for purchases that don't require any kind of IPN integration. I'm all about Agile and YAGNI, I don't want to do ANYTHING unnecessary.

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  • racket scheme get-argb-pixels

    - by Giles Roberts
    I have a 32 by 32 pixel png file. I'm trying to read the values within it using get-argb-pixels. My code is as follows: #lang racket/gui (require racket/gui/base) (define floor (make-object bitmap% "C:\\floortile.png")) (define pixels (make-bytes (* 32 32 4))) (send floor get-argb-pixels 0 0 32 32 pixels) After executing the code I was expecting a series of 8 bit values to be contained within pixels. Examining pixels gives me the following output: > pixels #"\377\2148\30\377\214<\30\377\234E\30\377\245I\30\377\245I\30\377\234E\30\377\234A\30\377\224A\30\377\224A\30\377\234A\30\377\245E\30\377\255M\30\377\224A\30\377\234E\30\377\245I\30\377\224A\30\377\234E\30\377\234E\30\377\255I\30\377\245I\30\377\245E\30\377\234A\30\377\234E\30\377\234A\30\377\245I\30\377\265Q\30\377\306]\30\377\306Y\30\377\275U\30\377\265Q\30\377\306a!\377\306]!\377\214<\30\377\224A\30\377\224A\30\377\245I\30\377\255M\30\377\255M\30\377\245I\30\377\234E\30\377\234E\30\377\245I\30\377\245I\30\377\255M\30\377\234A\30\377\245E\30\377\265M\30\377\234A\30\377\245I\30\377\245E\30\377\245E\30\377\255M\30\377\245I\30\377\245E\30\377\234A\30\377\234E\30\377\255I\30\377\275U\30\377\306]\30\377\326e!\377\336e!\377\265Q\30\377\326e!\377\326a!\377{8\30\377\224E\30\377\224A\30\377\245I\30\377\245I\30\377\255M\30\377\255M\30\377\255I\30\377\245I\30\377\245I\30\377\245I\30\377\265Q\30\377\214<\30\377\245I\30\377\255M\30\377\265M\30\377\255M\30\377\265M\30\377\265M\30\377\245I\30\377\234E\30\377\234E\30\377\234E\30\377\245E\30\377\275Q\30\377\306]!\377\316a!\377\336i!\377\357q!\377\275Y\30\377\316e!\377\347i!\377k0\20\377\2048\30\377\224A\30\377\265U!\377\234E\30\377\234E\30\377\245M\30\377\255M\30\377\255M\30\377\255I\30\377\255M\30\377\265M\30\377\2048\20\377\245I\30\377\245I\30\377\306Y!\377\265Q\30\377\255M\30\377\265Q\30\377\265M\30\377\265M\30\377\255I\30\377\265Q\30\377\265M\30\377\275U\30\377\316a!\377\326i!\377\347m!\377\367\216)\377\347y)\377\336m)\377\326]!\377s0\20\377{8\30\377{4\20\377\2048\30\377s4\20\377\2048\30\377{4\20\377\214<\30\377\224A\30\377\234A\30\377\224A\30\377\224A\30\377\214<\30\377\2148\30\377\224<\30\377\234A\30\377\214<\30\377\234E\30\377\245I\30\377\265Q\30\377\255M\30\377\265U\30\377\306Y\30\377\265Q\30\377\275U\30\377\326a!\377\336i!\377\347u!\377\357\206)\377\326q)\377\326i)\377\347i!\377s0\20\377{4\20\377{4\30\377\214<\30\377s4\20\377\2048\30\377s4\20\377\224A\30\377\224A\30\377\224<\30\377\234A\30\377\245E\30\377\234E\30\377\234I\30\377\234E\30\377\245I\30\377\245I\30\377\245I\30\377\265Q\30\377\306]\30\377\255M\30\377\255M\30\377\255M\30\377\255M\30\377\275U\30\377\255M\30\377\275U\30\377\316a!\377\306]!\377\326i!\377\367\206)\377\377})\377s4\30\377k,\20\377k,\20\377s4\30\377{4\20\377\2048\30\377c(\20\377\2048\20\377\234A\30\377\245E\30\377\245E\30\377\255I\30\377\245I\30\377\245I\30\377\245I\30\377\265Q\30\377\275U!\377\255M\30\377\255M\30\377\255M\30\377\255M\30\377\275U\30\377\306]!\377\275U\30\377\255M\30\377\306Y!\377\306]!\377\316e!\377\316a!\377\326i!\377\347y)\377\367y)\377c(\20\377c,\20\377k,\20\377s0\20\377s4\20\377\2048\30\377\214<\30\377{4\20\377\214<\30\377\234E\30\377\234A\30\377\245I\30\377\255M\30\377\255M\30\377\255M\30\377\265Q\30\377\265M\30\377\265Q\30\377\265Q\30\377\255M\30\377\265U\30\377\255M\30\377\265Q\30\377\265U\30\377\265U\30\377\265Q\30\377\306Y\30\377\316a!\377\306a!\377\326i!\377\347y)\377\367\202)\377c,\20\377k,\20\377s0\20\377s0\20\377{8\30\377\214<\30\377s,\20\377s0\20\377\214<\30\377\234A\30\377\245E\30\377\255M\30\377\255M\30\377\245I\30\377\255M\30\377\275U\30\377\265U\30\377\265Q\30\377\265Q\30\377\275Y\30\377\255M\30\377\255I\30\377\275U\30\377\275Y!\377\275Y\30\377\265U\30\377\306Y!\377\326e!\377\336m!\377\336q!\377\347})\377\357\202)\377s0\20\377s4\30\377s4\30\377\2048\30\377\234E\30\377\2048\20\377\2148\30\377c(\20\377\2048\30\377\214<\30\377\234E\30\377\265Q\30\377\265Q\30\377\255M\30\377\265M\30\377\316a!\377\275U\30\377\275Y\30\377\265Q\30\377\265Q\30\377\265Q\30\377\265Q\30\377\255M\30\377\275Y\30\377\275Y!\377\275Y\30\377\275U\30\377\316a!\377\347q)\377\367\202)\377\357})\377\347y)\377k0\20\377\2048\30\377{4\30\377\2048\30\377\214A\30\377\2048\30\377\2044\30\377s4\20\377k,\20\377\2048\30\377\224A\30\377\245I\30\377\234A\30\377\234E\30\377\255Q\30\377\275U\30\377\306Y!\377\265Q\30\377\255Q\30\377\265U\30\377\265U\30\377\265Q\30\377\265Q\30\377\316e!\377\316a!\377\306]!\377\275Y!\377\306]!\377\336i!\377\357})\377\367\202)\377\336u)\377k0\20\377s0\30\377\2048\30\377\204<\30\377\204<\30\377\2048\30\377\2048\30\377\214<\30\377s4\20\377\2048\30\377\214A\30\377\224A\30\377\224E\30\377\234E\30\377\265Q\30\377\275U\30\377\306Y\30\377\255M\30\377\265Q\30\377\265Q\30\377\316]!\377\326e!\377\316]!\377\336m)\377\336i)\377\316e!\377\306a!\377\326e!\377\367y)\377\367})\377\367\2061\377\367\2061\377s4\30\377{8\30\377{8\30\377\214<\30\377\214<\30\377\204<\30\377{4\20\377\214<\30\377\214<\30\377\214<\30\377\234E\30\377\234E\30\377\224E\30\377\234E\30\377\245M\30\377\275U\30\377\275U!\377\275U\30\377\306]!\377\306]!\377\316a!\377\326i)\377\347u)\377\326e!\377\347q)\377\336q)\377\326i)\377\326i)\377\347q)\377\367\202)\377\367})\377\367\2061\377{8\30\377s4\30\377{8\30\377\214<\30\377\224A\30\377\234E\30\377\214<\30\377\214<\30\377\224A\30\377\224<\30\377\234E\30\377\255M\30\377\245I\30\377\245I\30\377\255M\30\377\265U\30\377\306]!\377\306]!\377\316a!\377\316e!\377\326e!\377\347m)\377\316e!\377\306]!\377\347u)\377\347u)\377\336m)\377\316e)\377\336q)\377\357y)\377\367\202)\377\367\2021\377{4\30\377s4\30\377\2048\30\377\214A\30\377\224A\30\377\224A\30\377\224E\30\377\214<\30\377\214<\30\377\245I\30\377\234A\30\377\255M\30\377\255M\30\377\245I\30\377\255M\30\377\255Q\30\377\306]!\377\306]!\377\316a!\377\316a!\377\316a!\377\347u)\377\326e!\377\275Y!\377\265Y!\377\336m)\377\306a)\377\336m)\377\336m)\377\326e)\377\347q)\377\336q)\377s0\30\377s0\30\377\204<\30\377\224A\30\377\224E\30\377\234I\30\377\234E\30\377\234E\30\377\255M\30\377\234E\30\377{4\30\377\224<\30\377\245M\30\377\255I\30\377\234A\30\377\255M\30\377\245E\30\377\255M\30\377\265Q\30\377\245I\30\377\275U\30\377\255I\30\377\234A\30\377\224E\30\377\265U\30\377\234I\30\377\224E\30\377\245M\30\377\234M!\377\224A\30\377\234I\30\377\224E\30\377k0\20\377s0\20\377{4\30\377\214<\30\377\224E\30\377\234E\30\377\245I\30\377\234I\30\377\245I\30\377\214<\30\377\214<\30\377\255M\30\377\265Q!\377\265Q!\377\255M\30\377\306]!\377\316a)\377\326e)\377\326a!\377\316]!\377\265Q\30\377\326a!\377\255M\30\377\204<\20\377\245M\30\377\234I\30\377\245M\30\377\275]!\377\234I\30\377\255U!\377\265Y!\377\245M!\377c(\20\377k,\20\377k0\20\377\2048\30\377\224A\30\377\224E\30\377\234I\30\377\245I\30\377\275Y!\377\234E\30\377\245I\30\377\245I\30\377\265U!\377\265Q!\377\265Q!\377\306]!\377\306]!\377\316a!\377\316a!\377\336e)\377\326a!\377\316]!\377\265Q\30\377\224A\30\377\234I\30\377\275]!\377\265Y!\377\275Y!\377\275Y!\377\265U!\377\265])\377\275])\377s4\30\377c(\20\377k,\20\377s0\20\377\214A\30\377\224E\30\377\234E\30\377\306]!\377\234I\30\377\224A\30\377\265U!\377\245I\30\377\265Q!\377\265Q!\377\265M!\377\255M\30\377\306]!\377\306Y!\377\306]!\377\306]!\377\326a)\377\336i)\377\275U!\377\224A\30\377\224A\30\377\306a!\377\275]!\377\275Y!\377\275]!\377\275])\377\275Y!\377\275Y!\377s0\20\377k,\20\377s0\20\377\2048\30\377\214<\30\377\224E\30\377\234E\30\377\245M\30\377\224A\30\377\214A\30\377\245M\30\377\265Q!\377\275U!\377\255I\30\377\245I\30\377\245I\30\377\275U!\377\306Y!\377\275Y!\377\306]!\377\306]!\377\265Q\30\377\255M\30\377\224A\30\377\204<\30\377\255Q\30\377\245M\30\377\255Q!\377\265Y!\377\275]!\377\265Y!\377\275Y!\377s0\20\377k0\20\377{0\20\377\2048\30\377\204<\30\377\204<\30\377\214<\30\377\224A\30\377\316a!\377\245I\30\377\234E\30\377\245I\30\377\265U!\377\265Q!\377\265Q!\377\255M!\377\275U!\377\275U!\377\275U!\377\275Q!\377\255I\30\377\255M\30\377\255Q\30\377\234E\30\377{4\30\377\224A\30\377\214<\30\377\275Y!\377\275Y!\377\275]!\377\255Q!\377\255Q!\377k,\20\377k,\20\377s0\20\377\2044\30\377{4\20\377{4\30\377\2048\30\377\245M\30\377\265U!\377\245I\30\377\214A\30\377\275Y!\377\234A\30\377\255M\30\377\265Q!\377\245M!\377\265U!\377\275Q!\377\245I\30\377\245I\30\377\245M\30\377\265Q!\377\255Q!\377\255M\30\377\214<\30\377\245I\30\377\255Q!\377\306]!\377\306]!\377\275U!\377\265U!\377\255Q!\377c(\20\377Z(\20\377c(\20\377k,\20\377{8\30\377{4\30\377\214<\30\377\214A\30\377\234E\30\377\245I\30\377\245M\30\377\214<\30\377s0\30\377\255M!\377\255I!\377\255M!\377\255M!\377\265Q!\377\265Q!\377\255M!\377\265Q\30\377\245I\30\377\255I\30\377\306Y!\377\275Y!\377\214A\30\377\255Q\30\377\275]!\377\306])\377\306]!\377\255U!\377\255Q!\377k0\30\377k0\20\377k,\20\377s0\20\377s0\20\377s4\30\377{4\30\377\214<\30\377\245I\30\377\224A\30\377\306Y!\377\234A\30\377s0\20\377\245I\30\377\255M!\377\255M!\377\255M!\377\255M!\377\255Q!\377\265M!\377\316]!\377\245E\30\377\316]!\377\306Y!\377\275U!\377{8\30\377\255Q!\377\265Y!\377\275]!\377\275Y!\377\275Y!\377\255Q!\377k0\20\377c,\20\377k,\20\377s0\20\377{4\30\377s0\20\377{4\30\377{4\30\377\2048\30\377\245I\30\377\234E\30\377\234E\30\377k,\20\377\214<\30\377\224A\30\377\245M\30\377\214<\30\377\224E\30\377\214<\30\377\214<\30\377\214<\30\377\245I\30\377\234E\30\377\224A\30\377\224A\30\377k,\20\377\224A\30\377\265Q!\377\265Y!\377\265U!\377\265Y!\377\275Y!\377c(\20\377c,\20\377k,\20\377s0\20\377k,\20\377k0\20\377\2048\30\377\234A\30\377\214<\30\377\224A\30\377\245I\30\377\245I\30\377k0\20\377{4\20\377\214<\30\377\214A\30\377\214<\30\377\204<\30\377\2048\30\377\234I\30\377\224A\30\377\214<\30\377\234E\30\377\234E\30\377\255M\30\377\224A\30\377{8\30\377\255Q!\377\265U!\377\255U!\377\255U!\377\265U!\377c(\20\377k,\20\377s0\20\377s0\20\377{4\20\377\2048\30\377\2048\30\377\2048\30\377\224A\30\377\245M\30\377\245E\30\377\234E\30\377{4\20\377Z(\20\377k0\30\377{8\30\377\2048\30\377\214A\30\377\224A\30\377\234I\30\377\214<\30\377\224A\30\377\224A\30\377\234E\30\377\245I\30\377\255M\30\377{8\30\377\214A\30\377\255U!\377\255U!\377\245Q!\377\265U!\377c,\20\377c(\20\377k,\20\377Z$\20\377Z$\20\377Z(\20\377c(\20\377k,\20\377k,\20\377c(\20\377c(\20\377c,\20\377k0\20\377R \20\377c,\20\377s4\30\377{4\30\377\204<\30\377\2048\30\377\214A\30\377\224A\30\377\224A\30\377\234I\30\377\234I\30\377\224A\30\377\245I\30\377\224E\30\377\2048\30\377\255U!\377\255Q!\377\265U!\377\265Y)\377J \20\377J\34\20\377Z(\20\377k,\20\377k(\20\377c(\20\377R \20\377c(\20\377k,\20\377s0\20\377k0\20\377k0\20\377c,\20\377Z(\20\377c,\20\377s4\20\377s4\20\377\2048\30\377\2048\20\377\2048\30\377\224A\30\377\214A\30\377\234I\30\377\245I\30\377\234I\30\377\245M!\377\245M\30\377\204<\30\377\234M!\377\245Q!\377\265U!\377\255U!\377c,\20\377c,\20\377c(\20\377c(\20\377c(\20\377c(\20\377c(\20\377k,\20\377k,\20\377k,\20\377k0\20\377s4\20\377s0\30\377\204<\30\377c(\20\377s4\20\377s4\30\377{4\20\377{4\30\377\204<\30\377\224A\30\377\234E\30\377\234E\30\377\234E\30\377\234E\30\377\245I\30\377\245I\30\377\224E\30\377\204<\30\377\245Q!\377\255Q!\377\347\327\326\377R$\20\377k,\20\377c(\20\377c(\20\377c(\20\377c(\20\377Z$\20\377c(\20\377c(\20\377k,\20\377k,\20\377k,\20\377s0\20\377{4\30\377\204<\30\377k,\20\377s4\20\377s4\20\377{8\30\377\2048\20\377\214<\30\377\214<\30\377\214A\30\377\234E\30\377\234E\30\377\224A\30\377\224E\30\377\224E\30\377s4\30\377\214A\30\377\265\206s\377\377\377\377\377c,\20\377k,\30\377k0\20\377k,\20\377c(\20\377Z$\20\377Z(\20\377Z$\20\377c(\20\377c(\20\377c(\20\377k,\20\377k0\20\377{4\30\377{8\30\377k,\20\377c,\20\377k0\20\377s0\20\377{8\30\377\2048\30\377\2048\30\377\214<\30\377\224A\30\377\224E\30\377\214<\30\377\214A\30\377\234I\30\377{8!\377\214M1\377\377\373\377\377\377\377\377" This doesn't look like a series of 8 bit values to me. Have I done something wrong or am I misinterpreting the results?

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  • External API function calls AS3 control timeline

    - by giles
    I have function problem using this code (below), the embedded flash movieclip disappears or completely prevents the scrollto.js query to function in DW cs3. Communication between Flash and JavaScript is without problems, it is the call back I can't find to work and more frustratingly, should be simple, as no values are not required. So far, this has been hours of scouring the net without a workable end in sight...ahrr. What is a function for this to work? JavaScript – to call Flash event from HTML button link, placed between head tags function callExternalInterface() var flashMovie = window.document.menu; flashMovie.menu_up(value); menu_up is the string. Does anyone know of workable function for callback?? HTML <div id="btn_up"><a href="#top" name="charDev" id="charDev" onclick="">top</a></div> Pane navigation div that uses Scrollto.js query, and it's this link I need calling back to the embedded "menubtns.swf" (nested in "AS3Menu_javascript.swf") to play 5 frames of this movieclip, via a JS function. Embedded .swf code, using swfobject.js with allowScriptAccess=always <object classid="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" name="menu"<br/> width="251" height="251" id="menu"> <param name="movie" value="../~Assets/Flash/AS3Menu_javascript.swf" /> <param name="allowScriptAccess" value="always" /> <param name="movie" value="ExternalInterfaceScript.swf" /> <param name="quality" value="high" /> <object type="application/x-shockwave-flash" data="../~Assets/Flash/AS3Menu_javascript.swf" width="250" height="250"> <p>Alternative content</p> </object> </object> AS3 / Flash import flash.external.ExternalInterface;flash.system.Security.allowDomain(/sourceDomain/); ExternalInterface.addCallBack("menu_up", this, resetmenu); function resetmenu(){ gotoAndPlay:("frame label" / "number") }

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  • Animating list items with jQuery

    - by Giles B
    Hi Guys, Im trying to find the best way of animating a list of items one by one. So for example I have a UL with 7 items in it and when my trigger element is clicked I want each item to fade in one below the other with a slight delay between each item. Any ideas would be most appreciated. Thanks

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  • Hot Java Content

    - by Tori Wieldt
    It's August, summertime in the United States, and time for many of us to go on vacation. (You'll have to find my personal account to see more photos of the Monterey Bay Aquarium.) Here's some great Java content that you may have missed while I was gone: Blogs  Project Jigsaw: Late for the train: The Q&A JSR 355 Final Release, and moves JCP to version 2.9Oracle releases JDK for Linux ARM, JRE for Mac OS XArchitects and Architecture at JavaOne 2012Java Champions at JavaOne 2012 Podcasts & Videos Java Spotlight Episode 96: Johan Vos on Glassfish and JavaFXJava Spotlight Episode 94: Kirk Pepperdine on Java Performance TuningJava Spotlight Episode 93: Jonathan Giles on JavaFX 2.2 UI ControlsVideo: JavaFX Canvas Node July/August Java Magazine (free subscription) Developer Power: Web-based Development ToolsFork/Join Framework for Client Java ApplicationsIntro to Web Service SecurityHow to Modify javacOracle's Berkeley DB Java Edition's Java API and more. Java Magazine is available on the App Store and the Android Market. Get all this great Java content while it's as hot as a North American (non-San Franciscian) summer. 

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  • Vista failing to load after apparently being repaired

    - by Joomaz
    Hi, I apologise if I'm a litre vague and can give more info if needed. My vista machine has been working fine until today when I tried booting it. Vista loads showing the loading bar then goes to a black screen with the cursor on which you can move. It then remains like this for several minutes, during this time the computer doesn't sound like it's doing much, it is relatively quiet. Finally the welcome screen appears. It stays on this for several minutes again and the computer reboots. This keeps happening and the machine fails to load in safe mode - the same happens. I booted the pc with the vista disk in and ran repair your computer and used the system repair. It took about 20 minutes saying it was repairing damaged giles. I booted the pc again and the same happened. I loaded the pc with yeh vista disk again and chose repair my computer again. System repair seemed to run automatically this time and agian it did the same. I rebooted and the problem persisted. I then tried system restore to a few days ago. After half a hour as it finished it said it failed due to a portion being corrupt. I am really not sure what to do now. Any advice appreciated!

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  • What was scientifically shown to support productivity when organizing/accessing file and folders?

    - by Tom Wijsman
    I have gathered terabytes of data but it has became a habit to store files and folders to the same folder, that folder could be kind of seen as a Inbox where most files (non-installations) enter my system. This way I end up with a big collections of files that are hard to organize properly, I mostly end up making folders that match their file type but then I still have several gigabytes of data per folder which doesn't make it efficient such that I can productively use the folder. I'd rather do a few clicks than having to search through the files, whether that's by some software product or by looking through the folder. Often the file names themselves are not proper so it would be easier to recognize them if there were few in a folder, rather than thousands of them. Scaling in the structure of directory trees in a computer cluster summarizes this problem as following: The processes of storing and retrieving information are rapidly gaining importance in science as well as society as a whole [1, 2, 3, 4]. A considerable effort is being undertaken, firstly to characterize and describe how publicly available information, for example in the world wide web, is actually organized, and secondly, to design efficient methods to access this information. [1] R. M. Shiffrin and K. B¨orner, Proc. Natl. Acad. Sci. USA 101, 5183 (2004). [2] S. Lawrence, C.L. Giles, Nature 400, 107–109 (1999). [3] R.F.I. Cancho and R.V. Sol, Proc. R. Soc. London, Ser. B 268, 2261 (2001). [4] M. Sigman and G. A. Cecchi, Proc. Natl. Acad. Sci. USA 99, 1742 (2002). It goes further on explaining how the data is usually organized by taking general looks at it, but by looking at the abstract and conclusion it doesn't come with a conclusion or approach which results in a productive organization of a directory hierarchy. So, in essence, this is a problem for which I haven't found a solution yet; and I would love to see a scientific solution to this problem. Upon searching further, I don't seem to find anything useful or free papers that approach this problem so it might be that I'm looking in the wrong place. I've also noted that there are different ways to term this problem, which leads out to different results of papers. Perhaps a paper is out there, but I'm not just using the same terms as that paper uses? They often use more scientific terms. I've once heard a story about an advocate with a laptop which has simply outperformed an advocate with had tons of papers, which shows how proper organization leads to productivity; but that story didn't share details on how the advocate used the laptop or how he had organized his data. But in any case, it was way more useful than how most of us organize our data these days... Advice me how I should organize my data, I'm not looking for suggestions here. I would love to see statistics or scientific measurement approaches that help me confirm that it does help me reach my goal.

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  • Remove/squash entries in a vertical hash

    - by Forkrul Assail
    I have a grid that represents an X, Y matrix, stored as a hash here. Some points on the X Y matrix may have values (as type string), and some may not. A typical grid could look like this: {[9, 5]=>"Alaina", [10, 3]=>"Courtney", [11, 1]=>"Gladys", [8, 7]=>"Alford", [14, 11]=>"Lesley", [17, 2]=>"Lawson", [0, 5]=>"Katrine", [2, 1]=>"Tyra", [3, 3]=>"Fredy", [1, 7]=>"Magnus", [6, 9]=>"Nels", [7, 11]=>"Kylie", [11, 0]=>"Kellen", [10, 2]=>"Johan", [14, 10]=>"Justice", [0, 4]=>"Barton", [2, 0]=>"Charley", [3, 2]=>"Magnolia", [1, 6]=>"Maximo", [7, 10]=>"Olga", [19, 5]=>"Isadore", [16, 3]=>"Delfina", [17, 1]=>"Noe", [20, 11]=>"Francis", [10, 5]=>"Creola", [9, 3]=>"Bulah", [8, 1]=>"Lempi", [11, 7]=>"Raquel", [13, 11]=>"Jace", [1, 5]=>"Garth", [3, 1]=>"Ernest", [2, 3]=>"Malcolm", [0, 7]=>"Alejandrin", [7, 9]=>"Marina", [6, 11]=>"Otilia", [16, 2]=>"Hailey", [20, 10]=>"Brandt", [8, 0]=>"Madeline", [9, 2]=>"Leanne", [13, 10]=>"Jenifer", [1, 4]=>"Humberto", [3, 0]=>"Nicholaus", [2, 2]=>"Nadia", [0, 6]=>"Abigail", [6, 10]=>"Zola", [20, 5]=>"Clementina", [23, 3]=>"Alvah", [19, 11]=>"Wallace", [11, 5]=>"Tracey", [8, 3]=>"Hulda", [9, 1]=>"Jedidiah", [10, 7]=>"Annetta", [12, 11]=>"Nicole", [2, 5]=>"Alison", [0, 1]=>"Wilma", [1, 3]=>"Shana", [3, 7]=>"Judd", [4, 9]=>"Lucio", [5, 11]=>"Hardy", [19, 10]=>"Immanuel", [9, 0]=>"Uriel", [8, 2]=>"Milton", [12, 10]=>"Elody", [5, 10]=>"Alexanne", [1, 2]=>"Lauretta", [0, 0]=>"Louvenia", [2, 4]=>"Adelia", [21, 5]=>"Erling", [18, 11]=>"Corene", [22, 3]=>"Haskell", [11, 11]=>"Leta", [10, 9]=>"Terrence", [14, 1]=>"Giuseppe", [15, 3]=>"Silas", [12, 5]=>"Johnnie", [4, 11]=>"Aurelie", [5, 9]=>"Meggie", [2, 7]=>"Phoebe", [0, 3]=>"Sister", [1, 1]=>"Violet", [3, 5]=>"Lilian", [18, 10]=>"Eusebio", [11, 10]=>"Emma", [15, 2]=>"Theodore", [14, 0]=>"Cassidy", [4, 10]=>"Edmund", [2, 6]=>"Claire", [0, 2]=>"Madisen", [1, 0]=>"Kasey", [3, 4]=>"Elijah", [17, 11]=>"Susana", [20, 1]=>"Nicklaus", [21, 3]=>"Kelsie", [10, 11]=>"Garnett", [11, 9]=>"Emanuel", [15, 1]=>"Louvenia", [14, 3]=>"Otho", [13, 5]=>"Vincenza", [3, 11]=>"Tate", [2, 9]=>"Beau", [5, 7]=>"Jason", [6, 1]=>"Jayde", [7, 3]=>"Lamont", [4, 5]=>"Curt", [17, 10]=>"Mack", [21, 2]=>"Lilyan", [10, 10]=>"Ruthe", [14, 2]=>"Georgianna", [4, 4]=>"Nyasia", [6, 0]=>"Sadie", [16, 11]=>"Emil", [21, 1]=>"Melba", [20, 3]=>"Delia", [3, 10]=>"Rosalee", [2, 8]=>"Myrtle", [7, 2]=>"Rigoberto", [14, 5]=>"Jedidiah", [13, 3]=>"Flavie", [12, 1]=>"Evie", [8, 9]=>"Olaf", [9, 11]=>"Stan", [20, 2]=>"Judge", [5, 5]=>"Cassie", [7, 1]=>"Gracie", [6, 3]=>"Armando", [4, 7]=>"Delia", [3, 9]=>"Marley", [16, 10]=>"Robyn", [2, 11]=>"Richie", [12, 0]=>"Gilberto", [13, 2]=>"Dedrick", [9, 10]=>"Liam", [5, 4]=>"Jabari", [7, 0]=>"Enola", [6, 2]=>"Lela", [3, 8]=>"Jade", [2, 10]=>"Johnson", [15, 5]=>"Willow", [12, 3]=>"Fredrick", [13, 1]=>"Beau", [9, 9]=>"Carlie", [8, 11]=>"Daisha", [6, 5]=>"Declan", [4, 1]=>"Carolina", [5, 3]=>"Cruz", [7, 7]=>"Jaime", [0, 9]=>"Anthony", [1, 11]=>"Esta", [13, 0]=>"Shaina", [12, 2]=>"Alec", [8, 10]=>"Lora", [6, 4]=>"Emely", [4, 0]=>"Rodger", [5, 2]=>"Cedrick", [0, 8]=>"Collin", [1, 10]=>"Armani", [16, 5]=>"Brooks", [19, 3]=>"Eleanora", [18, 1]=>"Alva", [7, 5]=>"Melissa", [5, 1]=>"Tabitha", [4, 3]=>"Aniya", [6, 7]=>"Marc", [1, 9]=>"Marjorie", [0, 11]=>"Arvilla", [19, 2]=>"Adela", [7, 4]=>"Zakary", [5, 0]=>"Emely", [4, 2]=>"Alison", [1, 8]=>"Lorenz", [0, 10]=>"Lisandro", [17, 5]=>"Aylin", [18, 3]=>"Giles", [19, 1]=>"Kyleigh", [8, 5]=>"Mary", [11, 3]=>"Claire", [10, 1]=>"Avis", [9, 7]=>"Manuela", [15, 11]=>"Chesley", [18, 2]=>"Kristopher", [24, 3]=>"Zola", [8, 4]=>"Pietro", [10, 0]=>"Delores", [11, 2]=>"Timmy", [15, 10]=>"Khalil", [18, 5]=>"Trudie", [17, 3]=>"Rafael", [16, 1]=>"Anthony"} What I need to do though, is basically remove all the empty entries. Let's say [17,3] = Raphael does not have an element in front of if (let's say - no [16,3] exists) then [17,3] should become [16,3] etc. So basically all empty items will be popped off the vertical (row) structure of the hash. Are there functions I should have a look at or is there an easy squash-like method that would just remove blanks and adjust and move other items? Thanks in advance for your help.

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  • ubuntu: sem_timedwait not waking (C)

    - by gillez
    I have 3 processes which need to be synchronized. Process one does something then wakes process two and sleeps, which does something then wakes process three and sleeps, which does something and wakes process one and sleeps. The whole loop is timed to run around 25hz (caused by an external sync into process one before it triggers process two in my "real" application). I use sem_post to trigger (wake) each process, and sem_timedwait() to wait for the trigger. This all works successfully for several hours. However at some random time (usually after somewhere between two and four hours), one of the processes starts timing out in sem_timedwait(), even though I am sure the semaphore is being triggered with sem_post(). To prove this I even use sem_getvalue() immediately after the timeout, and the value is 1, so the timedwait should have been triggered. Please see following code: #include <stdio.h> #include <time.h> #include <string.h> #include <errno.h> #include <semaphore.h> sem_t trigger_sem1, trigger_sem2, trigger_sem3; // The main thread process. Called three times with a different num arg - 1, 2 or 3. void *thread(void *arg) { int num = (int) arg; sem_t *wait, *trigger; int val, retval; struct timespec ts; struct timeval tv; switch (num) { case 1: wait = &trigger_sem1; trigger = &trigger_sem2; break; case 2: wait = &trigger_sem2; trigger = &trigger_sem3; break; case 3: wait = &trigger_sem3; trigger = &trigger_sem1; break; } while (1) { // The first thread delays by 40ms to time the whole loop. // This is an external sync in the real app. if (num == 1) usleep(40000); // print sem value before we wait. If this is 1, sem_timedwait() will // return immediately, otherwise it will block until sem_post() is called on this sem. sem_getvalue(wait, &val); printf("sem%d wait sync sem%d. val before %d\n", num, num, val); // get current time and add half a second for timeout. gettimeofday(&tv, NULL); ts.tv_sec = tv.tv_sec; ts.tv_nsec = (tv.tv_usec + 500000); // add half a second if (ts.tv_nsec > 1000000) { ts.tv_sec++; ts.tv_nsec -= 1000000; } ts.tv_nsec *= 1000; /* convert to nanosecs */ retval = sem_timedwait(wait, &ts); if (retval == -1) { // timed out. Print value of sem now. This should be 0, otherwise sem_timedwait // would have woken before timeout (unless the sem_post happened between the // timeout and this call to sem_getvalue). sem_getvalue(wait, &val); printf("!!!!!! sem%d sem_timedwait failed: %s, val now %d\n", num, strerror(errno), val); } else printf("sem%d wakeup.\n", num); // get value of semaphore to trigger. If it's 1, don't post as it has already been // triggered and sem_timedwait on this sem *should* not block. sem_getvalue(trigger, &val); if (val <= 0) { printf("sem%d send sync sem%d. val before %d\n", num, (num == 3 ? 1 : num+1), val); sem_post(trigger); } else printf("!! sem%d not sending sync, val %d\n", num, val); } } int main(int argc, char *argv[]) { pthread_t t1, t2, t3; // create semaphores. val of sem1 is 1 to trigger straight away and start the whole ball rolling. if (sem_init(&trigger_sem1, 0, 1) == -1) perror("Error creating trigger_listman semaphore"); if (sem_init(&trigger_sem2, 0, 0) == -1) perror("Error creating trigger_comms semaphore"); if (sem_init(&trigger_sem3, 0, 0) == -1) perror("Error creating trigger_vws semaphore"); pthread_create(&t1, NULL, thread, (void *) 1); pthread_create(&t2, NULL, thread, (void *) 2); pthread_create(&t3, NULL, thread, (void *) 3); pthread_join(t1, NULL); pthread_join(t2, NULL); pthread_join(t3, NULL); } The following output is printed when the program is running correctly (at the start and for a random but long time after). The value of sem1 is always 1 before thread1 waits as it sleeps for 40ms, by which time sem3 has triggered it, so it wakes straight away. The other two threads wait until the semaphore is received from the previous thread. [...] sem1 wait sync sem1. val before 1 sem1 wakeup. sem1 send sync sem2. val before 0 sem2 wakeup. sem2 send sync sem3. val before 0 sem2 wait sync sem2. val before 0 sem3 wakeup. sem3 send sync sem1. val before 0 sem3 wait sync sem3. val before 0 sem1 wait sync sem1. val before 1 sem1 wakeup. sem1 send sync sem2. val before 0 [...] However, after a few hours, one of the threads begins to timeout. I can see from the output that the semaphore is being triggered, and when I print the value after the timeout is is 1. So sem_timedwait should have woken up well before the timeout. I would never expect the value of the semaphore to be 1 after the timeout, save for the very rare occasion (almost certainly never but it's possible) when the trigger happens after the timeout but before I call sem_getvalue. Also, once it begins to fail, every sem_timedwait() on that semaphore also fails in the same way. See the following output, which I've line-numbered: 01 sem3 wait sync sem3. val before 0 02 sem1 wakeup. 03 sem1 send sync sem2. val before 0 04 sem2 wakeup. 05 sem2 send sync sem3. val before 0 06 sem2 wait sync sem2. val before 0 07 sem1 wait sync sem1. val before 0 08 !!!!!! sem3 sem_timedwait failed: Connection timed out, val now 1 09 sem3 send sync sem1. val before 0 10 sem3 wait sync sem3. val before 1 11 sem3 wakeup. 12 !! sem3 not sending sync, val 1 13 sem3 wait sync sem3. val before 0 14 sem1 wakeup. [...] On line 1, thread 3 (which I have confusingly called sem1 in the printf) waits for sem3 to be triggered. On line 5, sem2 calls sem_post for sem3. However, line 8 shows sem3 timing out, but the value of the semaphore is 1. thread3 then triggers sem1 and waits again (10). However, because the value is already 1, it wakes straight away. It doesn't send sem1 again as this has all happened before control is given to thread1, however it then waits again (val is now 0) and sem1 wakes up. This now repeats for ever, sem3 always timing out and showing that the value is 1. So, my question is why does sem3 timeout, even though the semaphore has been triggered and the value is clearly 1? I would never expect to see line 08 in the output. If it times out (because, say thread 2 has crashed or is taking too long), the value should be 0. And why does it work fine for 3 or 4 hours first before getting into this state? This is using Ubuntu 9.4 with kernel 2.6.28. The same procedure has been working properly on Redhat and Fedora. But I'm now trying to port to ubuntu! Thanks for any advice, Giles

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