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  • How to generate multiple levels with GraphViz (Image_Graphviz interface for PHP)

    - by ropstah
    Hi, i'm trying to generate the following diagram using Image_GraphViz for PEAR. However It only shows a top-level node (with the text "0") and childnodes "1", "2", "3" and "4" directly under the top-node. Am I missing something? This is the code: $gv = new Image_GraphViz(true); $gv->addEdge(array('1', '2')); $gv->addEdge(array('2', '3')); $gv->addEdge(array('2', '4')); $gv->addEdge(array('3', '5')); $gv->addEdge(array('3', '6')); $gv->addEdge(array('3', '7')); $gv->addEdge(array('4', '5')); echo $gv->fetch('svg'); I tried the following, but this is obviously wrong :). $gv->addEdge(array('1', '2')); $gv->addEdge(array('1', '2', '3')); $gv->addEdge(array('1', '2', '4')); $gv->addEdge(array('1', '2', '3', '5')); $gv->addEdge(array('1', '2', '3', '6')); $gv->addEdge(array('1', '2', '3', '7')); $gv->addEdge(array('1', '2', '4', '5')); I understand there are two ways to get to 5. Through (1, 2, 3, 5) and/or (1, 2, 4, 5). The image should just show two lines going to 5. I'm very confused, any suggestions?

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  • how to create paging in a dynamic gridview

    - by bharathi
    I am using C# ,here i attach my partial code for dynamic grid view its working fine . I need to set paging on the dynamic grid view how can i call the OnPageIndexChanging GridView gv = new GridView(); gv.AllowPaging = false; gv.AlternatingRowStyle.BackColor = System.Drawing.Color.WhiteSmoke; gv.GridLines = GridLines.Horizontal; gv.CellPadding = 2; gv.CellSpacing = 5; gv.HeaderStyle.BackColor=System.Drawing.Color.Black; gv.HeaderStyle.ForeColor = System.Drawing.Color.White; gv.AutoGenerateColumns = false; BoundField nameColumn = new BoundField(); nameColumn.DataField = "fld_id"; nameColumn.HeaderText = "First Name"; gv.Columns.Add(nameColumn); nameColumn = new BoundField(); nameColumn.DataField = "fld_name"; nameColumn.HeaderText = "Last Name"; gv.Columns.Add(nameColumn); nameColumn = new BoundField(); nameColumn.DataField = "fld_state"; nameColumn.HeaderText = "Age"; gv.Columns.Add(nameColumn); gv.DataSource = ds; gv.DataBind(); plangrid.Controls.Add(gv);

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  • bash completion processing gone bad, how to debug?

    - by msw
    It all started with a simple alias gv='gvim --remote-quiet' and now gv Space Tab gives nothing where it normally should give filenames. Oddly, alias gvi='gvim --remote-quiet' works as expected. I clearly have a workaround, but I'd like to know what is catching my gv for special processing. compopt is no help as gv shares the same settings as ls which does filename completion correctly. $compopt gv compopt +o bashdefault +o default +o dirnames -o filenames +o nospace +o plusdirs gv $ compopt ls compopt +o bashdefault +o default +o dirnames -o filenames +o nospace +o plusdirs ls The complete command is slightly more helpful but it doesn't tell me why my two characters got singled out for alteration: $ complete -p gv complete -o filenames -F _filedir_xspec gv $ complete -p ls complete -o filenames -F _longopt ls $ complete -p echo bash: complete: echo: no completion specification $ alias gvi='gvim --remote-silent' msw@tallguy:~/.gnupg$ complete -p gvi bash: complete: gvi: no completion specification Where did complete -o filenames -F _filedir_xpec gv come from?

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  • ???Past Image(pi)

    - by todd.bao(at)oracle.com
    Past Image???RAC??????????,????????????????????????????????,Past Image??????????,?????????????????,?????????????????,??????????????(pi)?????????????????Past Image,????????????:HR.EMPLOYEES??100????101?????5????88???????????????,???????????# ??1: ?????????SYS@RAC1//scripts> select inst_id,status from gv$bh where file#=5 and block#=88;no rows selected# ??1???(???Steve King, ????24000????)SYS@RAC1//scripts> update hr.employees set salary=1 where employee_id=100;1 row updated.# ??2: ????1??xcur????????????,?????????SYS@RAC1//scripts> select inst_id,dirty,status from gv$bh where file#=5 and  block#=88;   INST_ID + D + STATUS---------- + - + -------         1 + Y + xcur1 row selected.# ??2???SYS@RAC2//scripts> update hr.employees set salary=2 where employee_id=101;1 row updated.# ??3: ????2?,?????1??pi??Past Image,???????????????????????SYS@RAC1//scripts> select inst_id,dirty,status from gv$bh where file#=5 and  block#=88;   INST_ID + D + STATUS---------- + - + -------         1 + Y + pi         2 + Y + xcur2 rows selected.# ??1???SYS@RAC1//scripts> update hr.employees set salary=3 where employee_id=100;1 row updated.# ??4: ????1?,?????2???1???????2???????1???????SYS@RAC1//scripts> select inst_id,dirty,status from gv$bh where file#=5 and  block#=88;   INST_ID + D + STATUS---------- + - + -------         1 + Y + pi         1 + Y + xcur         2 + Y + pi3 rows selected.# ??2????SYS@RAC2//scripts> update hr.employees set salary=4 where employee_id=101;1 row updated.# ??5: ????2?,??????????????,DBWR??,??????,??(pi)?????????????(cr)??????????????????????????SYS@RAC1//scripts> select inst_id,dirty,status from gv$bh where file#=5 and  block#=88;   INST_ID + D + STATUS---------- + - + -------         1 + N + cr         1 + N + cr         2 + Y + xcur3 rows selected.# ?????1???SYS@RAC1//scripts> update hr.employees set salary=5 where employee_id=100;1 row updated.# ??6: ????1?,?????2????????????????,?????????SYS@RAC1//scripts> select inst_id,dirty,status from gv$bh where file#=5 and  block#=88;   INST_ID + D + STATUS---------- + - + -------         1 + Y + xcur         1 + N + cr         1 + N + cr         2 + Y + pi4 rows selected.# ??2???SYS@RAC2//scripts> update hr.employees set salary=6 where employee_id=101;1 row updated.# ??7: ????2?,?????1?2????1???????2?????????????4,????????????????SYS@RAC1//scripts> select inst_id,dirty,status from gv$bh where file#=5 and  block#=88;   INST_ID + D + STATUS---------- + - + -------         1 + Y + pi         2 + Y + pi         2 + Y + xcur3 rows selected.# ??1???SYS@RAC1//scripts> update hr.employees set salary=7 where employee_id=100;1 row updated.# ??8: ????1?,?????2?1????2???????1????????????2????????????????????????????????????(????????)????SYS@RAC1//scripts> select inst_id,dirty,status from gv$bh where file#=5 and  block#=88;   INST_ID + D + STATUS---------- + - + -------         1 + Y + pi         1 + Y + xcur         2 + Y + pi         2 + N + cr4 rows selected.??????????, ?xcur??????????:??????xcur????pi?????pi?(?????)???cr?,???cr?????,pi????????????????????????????:?????????????A?B?A:SYS@RAC1//scripts> run  1  begin  2  for i in 1..100000 loop  3  update hr.employees set salary=i where employee_id=100;  4  end loop;  5* end;B:SYS@RAC2//scripts> run  1  begin  2  for i in 1..100000 loop  3  update hr.employees set salary=i where employee_id=101;  4  end loop;  5* end;?????????,???5???88?????buffer cache???????:SYS@RAC2//scripts> select count(*) from gv$bh where file#=5 and block#=88;  COUNT(*)----------       4121 row selected.??409?????????(cur):SYS@RAC2//scripts> select count(*) from gv$bh where file#=5 and block#=88 where status='cr';  COUNT(*)----------       4091 row selected.1????????(xcur):SYS@RAC2//scripts> select count(*) from gv$bh where file#=5 and block#=88 where status='xcur';  COUNT(*)----------           11 row selected.??...2??????--????(pi)??????????SYS@RAC1//scripts> select inst_id,dirty,status from gv$bh where file#=5 and block#=88 and status='pi';   INST_ID + D + STATUS---------- + - + -------         1 + Y + pi         2 + Y + pi2 rows selected.????,???RAC??????????????(cr)?,????????????????????????xcur?pi??cr??????pi?????? ?????????,???????????pi???cr?,?????????cr???,???xcur???????,pi??????xcur?,[email protected]

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  • Using a WPF ListView as a DataGrid

    - by psheriff
    Many people like to view data in a grid format of rows and columns. WPF did not come with a data grid control that automatically creates rows and columns for you based on the object you pass it. However, the WPF Toolkit can be downloaded from CodePlex.com that does contain a DataGrid control. This DataGrid gives you the ability to pass it a DataTable or a Collection class and it will automatically figure out the columns or properties and create all the columns for you and display the data.The DataGrid control also supports editing and many other features that you might not always need. This means that the DataGrid does take a little more time to render the data. If you want to just display data (see Figure 1) in a grid format, then a ListView works quite well for this task. Of course, you will need to create the columns for the ListView, but with just a little generic code, you can create the columns on the fly just like the WPF Toolkit’s DataGrid. Figure 1: A List of Data using a ListView A Simple ListView ControlThe XAML below is what you would use to create the ListView shown in Figure 1. However, the problem with using XAML is you have to pre-define the columns. You cannot re-use this ListView except for “Product” data. <ListView x:Name="lstData"          ItemsSource="{Binding}">  <ListView.View>    <GridView>      <GridViewColumn Header="Product ID"                      Width="Auto"               DisplayMemberBinding="{Binding Path=ProductId}" />      <GridViewColumn Header="Product Name"                      Width="Auto"               DisplayMemberBinding="{Binding Path=ProductName}" />      <GridViewColumn Header="Price"                      Width="Auto"               DisplayMemberBinding="{Binding Path=Price}" />    </GridView>  </ListView.View></ListView> So, instead of creating the GridViewColumn’s in XAML, let’s learn to create them in code to create any amount of columns in a ListView. Create GridViewColumn’s From Data TableTo display multiple columns in a ListView control you need to set its View property to a GridView collection object. You add GridViewColumn objects to the GridView collection and assign the GridView to the View property. Each GridViewColumn object needs to be bound to a column or property name of the object that the ListView will be bound to. An ADO.NET DataTable object contains a collection of columns, and these columns have a ColumnName property which you use to bind to the GridViewColumn objects. Listing 1 shows a sample of reading and XML file into a DataSet object. After reading the data a GridView object is created. You can then loop through the DataTable columns collection and create a GridViewColumn object for each column in the DataTable. Notice the DisplayMemberBinding property is set to a new Binding to the ColumnName in the DataTable. C#private void FirstSample(){  // Read the data  DataSet ds = new DataSet();  ds.ReadXml(GetCurrentDirectory() + @"\Xml\Product.xml");    // Create the GridView  GridView gv = new GridView();   // Create the GridView Columns  foreach (DataColumn item in ds.Tables[0].Columns)  {    GridViewColumn gvc = new GridViewColumn();    gvc.DisplayMemberBinding = new Binding(item.ColumnName);    gvc.Header = item.ColumnName;    gvc.Width = Double.NaN;    gv.Columns.Add(gvc);  }   // Setup the GridView Columns  lstData.View = gv;  // Display the Data  lstData.DataContext = ds.Tables[0];} VB.NETPrivate Sub FirstSample()  ' Read the data  Dim ds As New DataSet()  ds.ReadXml(GetCurrentDirectory() & "\Xml\Product.xml")   ' Create the GridView  Dim gv As New GridView()   ' Create the GridView Columns  For Each item As DataColumn In ds.Tables(0).Columns    Dim gvc As New GridViewColumn()    gvc.DisplayMemberBinding = New Binding(item.ColumnName)    gvc.Header = item.ColumnName    gvc.Width = [Double].NaN    gv.Columns.Add(gvc)  Next   ' Setup the GridView Columns  lstData.View = gv  ' Display the Data  lstData.DataContext = ds.Tables(0)End SubListing 1: Loop through the DataTable columns collection to create GridViewColumn objects A Generic Method for Creating a GridViewInstead of having to write the code shown in Listing 1 for each ListView you wish to create, you can create a generic method that given any DataTable will return a GridView column collection. Listing 2 shows how you can simplify the code in Listing 1 by setting up a class called WPFListViewCommon and create a method called CreateGridViewColumns that returns your GridView. C#private void DataTableSample(){  // Read the data  DataSet ds = new DataSet();  ds.ReadXml(GetCurrentDirectory() + @"\Xml\Product.xml");   // Setup the GridView Columns  lstData.View =      WPFListViewCommon.CreateGridViewColumns(ds.Tables[0]);  lstData.DataContext = ds.Tables[0];} VB.NETPrivate Sub DataTableSample()  ' Read the data  Dim ds As New DataSet()  ds.ReadXml(GetCurrentDirectory() & "\Xml\Product.xml")   ' Setup the GridView Columns  lstData.View = _      WPFListViewCommon.CreateGridViewColumns(ds.Tables(0))  lstData.DataContext = ds.Tables(0)End SubListing 2: Call a generic method to create GridViewColumns. The CreateGridViewColumns MethodThe CreateGridViewColumns method will take a DataTable as a parameter and create a GridView object with a GridViewColumn object in its collection for each column in your DataTable. C#public static GridView CreateGridViewColumns(DataTable dt){  // Create the GridView  GridView gv = new GridView();  gv.AllowsColumnReorder = true;   // Create the GridView Columns  foreach (DataColumn item in dt.Columns)  {    GridViewColumn gvc = new GridViewColumn();    gvc.DisplayMemberBinding = new Binding(item.ColumnName);    gvc.Header = item.ColumnName;    gvc.Width = Double.NaN;    gv.Columns.Add(gvc);  }   return gv;} VB.NETPublic Shared Function CreateGridViewColumns _  (ByVal dt As DataTable) As GridView  ' Create the GridView  Dim gv As New GridView()  gv.AllowsColumnReorder = True   ' Create the GridView Columns  For Each item As DataColumn In dt.Columns    Dim gvc As New GridViewColumn()    gvc.DisplayMemberBinding = New Binding(item.ColumnName)    gvc.Header = item.ColumnName    gvc.Width = [Double].NaN    gv.Columns.Add(gvc)  Next   Return gvEnd FunctionListing 3: The CreateGridViewColumns method takes a DataTable and creates GridViewColumn objects in a GridView. By separating this method out into a class you can call this method anytime you want to create a ListView with a collection of columns from a DataTable. SummaryIn this blog you learned how to create a ListView that acts like a DataGrid. You are able to use a DataTable as both the source of the data, and for creating the columns for the ListView. In the next blog entry you will learn how to use the same technique, but for Collection classes. NOTE: You can download the complete sample code (in both VB and C#) at my website. http://www.pdsa.com/downloads. Choose Tips & Tricks, then "WPF ListView as a DataGrid" from the drop-down. Good Luck with your Coding,Paul Sheriff ** SPECIAL OFFER FOR MY BLOG READERS **Visit http://www.pdsa.com/Event/Blog for a free eBook on "Fundamentals of N-Tier".

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  • Making A Dynaically Created Excel Report Downloadable

    - by Nick LaMarca
    I have 2 blocks of code, if someone could help me put them together I would get the functionality I am looking for. The first block of code downloads a gridview to excel using the download dialog I am looking for: Public Overloads Overrides Sub VerifyRenderingInServerForm(ByVal control As Control) ' Verifies that the control is rendered End Sub Private Sub ExportToExcel(ByVal filename As String, ByVal gv As GridView, ByVal numOfCol As Integer) Response.Clear() Response.Buffer = True Response.AddHeader("content-disposition", String.Format("attachment; filename={0}", filename)) Response.Charset = "" Response.ContentType = "application/vnd.ms-excel" Dim sw As New StringWriter() Dim hw As New HtmlTextWriter(sw) gv.AllowPaging = False gv.DataBind() 'Change the Header Row back to white color gv.HeaderRow.Style.Add("background-color", "#FFFFFF") For i As Integer = 0 To numOfCol - 1 gv.HeaderRow.Cells(i).Style.Add("background-color", "blue") gv.HeaderRow.Cells(i).Style.Add("color", "#FFFFFF") Next For i As Integer = 0 To gv.Rows.Count - 1 Dim row As GridViewRow = gv.Rows(i) 'Change Color back to white row.BackColor = System.Drawing.Color.White For j As Integer = 0 To numOfCol - 1 row.Cells(j).Style.Add("text-align", "center") Next 'Apply text style to each Row row.Attributes.Add("class", "textmode") 'Apply style to Individual Cells of Alternating Row If i Mod 2 <> 0 Then For j As Integer = 0 To numOfCol - 1 row.Cells(j).Style.Add("background-color", "#CCFFFF") row.Cells(j).Style.Add("text-align", "center") '#C2D69B 'row.Cells(j).Style.Add("font-size", "12pt") Next End If Next gv.RenderControl(hw) 'style to format numbers to string Dim style As String = "<style> .textmode { mso-number-format:\@; } </style>" Response.Write(style) Response.Output.Write(sw.ToString()) Response.Flush() Response.End() End Sub The second block of code is a sample report I am wish to be downloaded. So instead of downloading a gridview I want this function to accept a worksheet object.

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  • dynamically created datagridview columns not accessible unless added to a form...why?

    - by deostroll
    We simply created a DataGridView control dynamically and bound it to a DataTable. We were tying to style certain columns. But, when we tried to access the columns we got a null reference. On further investigation we found that if we add the DataGridView control to the main form, and then try to access its columns, it works fine!!! Code which throws error: DataGridView gv = new DataGridView(); gv.DataSource = GetDataTable(); //binding it to datatable Debug.Assert(gv.Columns == null); Code which works fine: DataGridView gv = new DataGridView(); gv.DataSource = GetDataTable(); //binding it to datatable this.Controls.Add(gv); //adding to form Debug.Assert(gv.Columns == null); //the assertion fails! Why is this behaviour so? Is there a workaround for this?

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  • Will this class cause memory leaks, and does it need a dispose method? (asp.net vb)

    - by Phil
    Here is the class to export a gridview to an excel sheet: Imports System Imports System.Data Imports System.Configuration Imports System.IO Imports System.Web Imports System.Web.Security Imports System.Web.UI Imports System.Web.UI.WebControls Imports System.Web.UI.WebControls.WebParts Imports System.Web.UI.HtmlControls Namespace ExcelExport Public NotInheritable Class GVExportUtil Private Sub New() End Sub Public Shared Sub Export(ByVal fileName As String, ByVal gv As GridView) HttpContext.Current.Response.Clear() HttpContext.Current.Response.AddHeader("content-disposition", String.Format("attachment; filename={0}", fileName)) HttpContext.Current.Response.ContentType = "application/ms-excel" Dim sw As StringWriter = New StringWriter Dim htw As HtmlTextWriter = New HtmlTextWriter(sw) Dim table As Table = New Table table.GridLines = GridLines.Vertical If (Not (gv.HeaderRow) Is Nothing) Then GVExportUtil.PrepareControlForExport(gv.HeaderRow) table.Rows.Add(gv.HeaderRow) End If For Each row As GridViewRow In gv.Rows GVExportUtil.PrepareControlForExport(row) table.Rows.Add(row) Next If (Not (gv.FooterRow) Is Nothing) Then GVExportUtil.PrepareControlForExport(gv.FooterRow) table.Rows.Add(gv.FooterRow) End If table.RenderControl(htw) HttpContext.Current.Response.Write(sw.ToString) HttpContext.Current.Response.End() End Sub Private Shared Sub PrepareControlForExport(ByVal control As Control) Dim i As Integer = 0 Do While (i < control.Controls.Count) Dim current As Control = control.Controls(i) If (TypeOf current Is LinkButton) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, LinkButton).Text)) ElseIf (TypeOf current Is ImageButton) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, ImageButton).AlternateText)) ElseIf (TypeOf current Is HyperLink) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, HyperLink).Text)) ElseIf (TypeOf current Is DropDownList) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, DropDownList).SelectedItem.Text)) ElseIf (TypeOf current Is CheckBox) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, CheckBox).Checked)) End If If current.HasControls Then GVExportUtil.PrepareControlForExport(current) End If i = (i + 1) Loop End Sub End Class End Namespace Will this class cause memory leaks? And does anything here need to be disposed of? The code is working but I am getting frequent crashes of the app pool when it is in use. Thanks.

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  • Will this class cause memory leaks, and does anything need disposing of? (asp.net vb)

    - by Phil
    Here is the class to export a gridview to an excel sheet: Imports System Imports System.Data Imports System.Configuration Imports System.IO Imports System.Web Imports System.Web.Security Imports System.Web.UI Imports System.Web.UI.WebControls Imports System.Web.UI.WebControls.WebParts Imports System.Web.UI.HtmlControls Namespace ExcelExport Public NotInheritable Class GVExportUtil Private Sub New() End Sub Public Shared Sub Export(ByVal fileName As String, ByVal gv As GridView) HttpContext.Current.Response.Clear() HttpContext.Current.Response.AddHeader("content-disposition", String.Format("attachment; filename={0}", fileName)) HttpContext.Current.Response.ContentType = "application/ms-excel" Dim sw As StringWriter = New StringWriter Dim htw As HtmlTextWriter = New HtmlTextWriter(sw) Dim table As Table = New Table table.GridLines = GridLines.Vertical If (Not (gv.HeaderRow) Is Nothing) Then GVExportUtil.PrepareControlForExport(gv.HeaderRow) table.Rows.Add(gv.HeaderRow) End If For Each row As GridViewRow In gv.Rows GVExportUtil.PrepareControlForExport(row) table.Rows.Add(row) Next If (Not (gv.FooterRow) Is Nothing) Then GVExportUtil.PrepareControlForExport(gv.FooterRow) table.Rows.Add(gv.FooterRow) End If table.RenderControl(htw) HttpContext.Current.Response.Write(sw.ToString) HttpContext.Current.Response.End() End Sub Private Shared Sub PrepareControlForExport(ByVal control As Control) Dim i As Integer = 0 Do While (i < control.Controls.Count) Dim current As Control = control.Controls(i) If (TypeOf current Is LinkButton) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, LinkButton).Text)) ElseIf (TypeOf current Is ImageButton) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, ImageButton).AlternateText)) ElseIf (TypeOf current Is HyperLink) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, HyperLink).Text)) ElseIf (TypeOf current Is DropDownList) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, DropDownList).SelectedItem.Text)) ElseIf (TypeOf current Is CheckBox) Then control.Controls.Remove(current) control.Controls.AddAt(i, New LiteralControl(CType(current, CheckBox).Checked)) End If If current.HasControls Then GVExportUtil.PrepareControlForExport(current) End If i = (i + 1) Loop End Sub End Class End Namespace Will this class cause memory leaks? And does anything here need to be disposed of? The code is working but I am getting the app pool falling over frequently when it is in use. Thanks.

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  • Highlight Row in GridView with Colored Columns

    - by Vincent Maverick Durano
    I wrote a blog post a while back before here that demonstrate how to highlight a GridView row on mouseover and as you can see its very easy to highlight rows in GridView. One of my colleague uses the same technique for implemeting gridview row highlighting but the problem is that if a Column has background color on it that cell will not be highlighted anymore. To make it more clear then let's build up a sample application. ASPX:   1: <asp:GridView runat="server" id="GridView1" onrowcreated="GridView1_RowCreated" 2: onrowdatabound="GridView1_RowDataBound"> 3: </asp:GridView>   CODE BEHIND:   1: private DataTable FillData() { 2:   3: DataTable dt = new DataTable(); 4: DataRow dr = null; 5:   6: //Create DataTable columns 7: dt.Columns.Add(new DataColumn("RowNumber", typeof(string))); 8: dt.Columns.Add(new DataColumn("Col1", typeof(string))); 9: dt.Columns.Add(new DataColumn("Col2", typeof(string))); 10: dt.Columns.Add(new DataColumn("Col3", typeof(string))); 11:   12: //Create Row for each columns 13: dr = dt.NewRow(); 14: dr["RowNumber"] = 1; 15: dr["Col1"] = "A"; 16: dr["Col2"] = "B"; 17: dr["Col3"] = "C"; 18: dt.Rows.Add(dr); 19:   20: dr = dt.NewRow(); 21: dr["RowNumber"] = 2; 22: dr["Col1"] = "AA"; 23: dr["Col2"] = "BB"; 24: dr["Col3"] = "CC"; 25: dt.Rows.Add(dr); 26:   27: dr = dt.NewRow(); 28: dr["RowNumber"] = 3; 29: dr["Col1"] = "A"; 30: dr["Col2"] = "B"; 31: dr["Col3"] = "CC"; 32: dt.Rows.Add(dr); 33:   34: dr = dt.NewRow(); 35: dr["RowNumber"] = 4; 36: dr["Col1"] = "A"; 37: dr["Col2"] = "B"; 38: dr["Col3"] = "CC"; 39: dt.Rows.Add(dr); 40:   41: dr = dt.NewRow(); 42: dr["RowNumber"] = 5; 43: dr["Col1"] = "A"; 44: dr["Col2"] = "B"; 45: dr["Col3"] = "CC"; 46: dt.Rows.Add(dr); 47:   48: return dt; 49: } 50:   51: protected void Page_Load(object sender, EventArgs e) { 52: if (!IsPostBack) { 53: GridView1.DataSource = FillData(); 54: GridView1.DataBind(); 55: } 56: }   As you can see there's nothing fancy in the code above. It just contain a method that fills a DataTable with a dummy data on it. Now here's the code for row highlighting:   1: protected void GridView1_RowCreated(object sender, GridViewRowEventArgs e) { 2: //Set Background Color for Columns 1 and 3 3: e.Row.Cells[1].BackColor = System.Drawing.Color.Beige; 4: e.Row.Cells[3].BackColor = System.Drawing.Color.Red; 5:   6: //Attach onmouseover and onmouseout for row highlighting 7: e.Row.Attributes.Add("onmouseover", "this.style.backgroundColor='Blue'"); 8: e.Row.Attributes.Add("onmouseout", "this.style.backgroundColor=''"); 9: }   Running the code above will show something like this in the browser: On initial load: On mouseover of GridView row:   Noticed that Col1 and Col3 are not highlighted. Why? the reason is that Col1 and Col3 cells has background color set on it and we only highlight the rows (TR) and not the columns (TD) that's why on mouseover only the rows will be highlighted. To fix the issue we will create a javascript method that would remove the background color of the columns when highlighting a row and on mouseout set back the original color that is set on Col1 and Col3. Here are the codes below: JavaScript   1: <script type="text/javascript"> 2: function HighLightRow(rowIndex, colIndex,colIndex2, flag) { 3: var gv = document.getElementById("<%= GridView1.ClientID %>"); 4: var selRow = gv.rows[rowIndex]; 5: if (rowIndex > 0) { 6: if (flag == "sel") { 7: gv.rows[rowIndex].style.backgroundColor = 'Blue'; 8: gv.rows[rowIndex].style.color = "White"; 9: gv.rows[rowIndex].cells[colIndex].style.backgroundColor = ''; 10: gv.rows[rowIndex].cells[colIndex2].style.backgroundColor = ''; 11: } 12: else { 13: gv.rows[rowIndex].style.backgroundColor = ''; 14: gv.rows[rowIndex].style.color = "Black"; 15: gv.rows[rowIndex].cells[colIndex].style.backgroundColor = 'Beige'; 16: gv.rows[rowIndex].cells[colIndex2].style.backgroundColor = 'Red'; 17: } 18: } 19: } 20: </script>   The HighLightRow method is a javascript function that accepts four (4) parameters which are the rowIndex,colIndex,colIndex2 and the flag. The rowIndex is the current row index of the selected row in GridView. The colIndex is the index of Col1 and colIndex2 is the index of col3. We are passing these index because these columns has background color on it and we need to toggle its backgroundcolor when highlighting the row in GridView. Finally the flag is something that would determine if its selected or not. Now here's the code for calling the JavaScript function above.     1: protected void GridView1_RowCreated(object sender, GridViewRowEventArgs e) { 2:   3: //Set Background Color for Columns 1 and 3 4: e.Row.Cells[1].BackColor = System.Drawing.Color.Beige; 5: e.Row.Cells[3].BackColor = System.Drawing.Color.Red; 6:   7: //Attach onmouseover and onmouseout for row highlighting 8: //and call the HighLightRow method with the required parameters 9: int index = e.Row.RowIndex + 1; 10: e.Row.Attributes.Add("onmouseover", "HighLightRow(" + index + "," + 1 + "," + 3 + ",'sel')"); 11: e.Row.Attributes.Add("onmouseout", "HighLightRow(" + index + "," + 1 + "," + 3 + ",'dsel')"); 12: 13: }   Running the code above will display something like this: On initial load:   On mouseover of GridView row:   That's it! I hope someone find this post useful!

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  • WPF ListView as a DataGrid – Part 2

    - by psheriff
    In my last blog post I showed you how to create GridViewColumn objects on the fly from the meta-data in a DataTable. By doing this you can create columns for a ListView at runtime instead of having to pre-define each ListView for each different DataTable. Well, many of us use collections of our classes and it would be nice to be able to do the same thing for our collection classes as well. This blog post will show you one approach for using collection classes as the source of the data for your ListView.  Figure 1: A List of Data using a ListView Load Property NamesYou could use reflection to gather the property names in your class, however there are two things wrong with this approach. First, reflection is too slow, and second you may not want to display all your properties from your class in the ListView. Instead of reflection you could just create your own custom collection class of PropertyHeader objects. Each PropertyHeader object will contain a property name and a header text value at a minimum. You could add a width property if you wanted as well. All you need to do is to create a collection of property header objects where each object represents one column in your ListView. Below is a simple example: PropertyHeaders coll = new PropertyHeaders(); coll.Add(new PropertyHeader("ProductId", "Product ID"));coll.Add(new PropertyHeader("ProductName", "Product Name"));coll.Add(new PropertyHeader("Price", "Price")); Once you have this collection created, you could pass this collection to a method that would create the GridViewColumn objects based on the information in this collection. Below is the full code for the PropertyHeader class. Besides the PropertyName and Header properties, there is a constructor that will allow you to set both properties when the object is created. C#public class PropertyHeader{  public PropertyHeader()  {  }   public PropertyHeader(string propertyName, string headerText)  {    PropertyName = propertyName;    HeaderText = headerText;  }   public string PropertyName { get; set; }  public string HeaderText { get; set; }} VB.NETPublic Class PropertyHeader  Public Sub New()  End Sub   Public Sub New(ByVal propName As String, ByVal header As String)    PropertyName = propName    HeaderText = header  End Sub   Private mPropertyName As String  Private mHeaderText As String   Public Property PropertyName() As String    Get      Return mPropertyName    End Get    Set(ByVal value As String)      mPropertyName = value    End Set  End Property   Public Property HeaderText() As String    Get      Return mHeaderText    End Get    Set(ByVal value As String)      mHeaderText = value    End Set  End PropertyEnd Class You can use a Generic List class to create a collection of PropertyHeader objects as shown in the following code. C#public class PropertyHeaders : List<PropertyHeader>{} VB.NETPublic Class PropertyHeaders  Inherits List(Of PropertyHeader)End Class Create Property Header Objects You need to create a method somewhere that will create and return a collection of PropertyHeader objects that will represent the columns you wish to add to your ListView prior to binding your collection class to that ListView. Below is a sample method called GetProperties that builds a list of PropertyHeader objects with properties and headers for a Product object. C#public PropertyHeaders GetProperties(){  PropertyHeaders coll = new PropertyHeaders();   coll.Add(new PropertyHeader("ProductId", "Product ID"));  coll.Add(new PropertyHeader("ProductName", "Product Name"));  coll.Add(new PropertyHeader("Price", "Price"));   return coll;} VB.NETPublic Function GetProperties() As PropertyHeaders  Dim coll As New PropertyHeaders()   coll.Add(New PropertyHeader("ProductId", "Product ID"))  coll.Add(New PropertyHeader("ProductName", "Product Name"))  coll.Add(New PropertyHeader("Price", "Price"))   Return collEnd Function WPFListViewCommon Class Now that you have a collection of PropertyHeader objects you need a method that will create a GridView and a collection of GridViewColumn objects based on this PropertyHeader collection. Below is a static/Shared method that you might put into a class called WPFListViewCommon. C#public static GridView CreateGridViewColumns(  PropertyHeaders properties){  GridView gv;  GridViewColumn gvc;   // Create the GridView  gv = new GridView();  gv.AllowsColumnReorder = true;   // Create the GridView Columns  foreach (PropertyHeader item in properties)  {    gvc = new GridViewColumn();    gvc.DisplayMemberBinding = new Binding(item.PropertyName);    gvc.Header = item.HeaderText;    gvc.Width = Double.NaN;    gv.Columns.Add(gvc);  }   return gv;} VB.NETPublic Shared Function CreateGridViewColumns( _    ByVal properties As PropertyHeaders) As GridView  Dim gv As GridView  Dim gvc As GridViewColumn   ' Create the GridView  gv = New GridView()  gv.AllowsColumnReorder = True   ' Create the GridView Columns  For Each item As PropertyHeader In properties    gvc = New GridViewColumn()    gvc.DisplayMemberBinding = New Binding(item.PropertyName)    gvc.Header = item.HeaderText    gvc.Width = [Double].NaN    gv.Columns.Add(gvc)  Next   Return gvEnd Function Build the Product Screen To build the window shown in Figure 1, you might write code like the following: C#private void CollectionSample(){  Product prod = new Product();   // Setup the GridView Columns  lstData.View = WPFListViewCommon.CreateGridViewColumns(       prod.GetProperties());  lstData.DataContext = prod.GetProducts();} VB.NETPrivate Sub CollectionSample()  Dim prod As New Product()   ' Setup the GridView Columns  lstData.View = WPFListViewCommon.CreateGridViewColumns( _       prod.GetProperties())  lstData.DataContext = prod.GetProducts()End Sub The Product class contains a method called GetProperties that returns a PropertyHeaders collection. You pass this collection to the WPFListViewCommon’s CreateGridViewColumns method and it will create a GridView for the ListView. When you then feed the DataContext property of the ListView the Product collection the appropriate columns have already been created and data bound. Summary In this blog you learned how to create a ListView that acts like a DataGrid using a collection class. While it does take a little code to do this, it is an alternative to creating each GridViewColumn in XAML. This gives you a lot of flexibility. You could even read in the property names and header text from an XML file for a truly configurable ListView. NOTE: You can download the complete sample code (in both VB and C#) at my website. http://www.pdsa.com/downloads. Choose Tips & Tricks, then "WPF ListView as a DataGrid – Part 2" from the drop-down. Good Luck with your Coding,Paul Sheriff ** SPECIAL OFFER FOR MY BLOG READERS **Visit http://www.pdsa.com/Event/Blog for a free eBook on "Fundamentals of N-Tier".  

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  • How to make exported .XLS file Editable

    - by nCdy
    How to make exported .XLS file Editable Thid code makes .XLS File Read Only :( using System; using System.Data; using System.Configuration; using System.IO; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Web.UI.HtmlControls; public class GridViewExportUtil { /// <param name="fileName"></param> /// <param name="gv"></param> public static void Export(string fileName, GridView gv) { HttpContext.Current.Response.Clear(); HttpContext.Current.Response.AddHeader( "content-disposition", string.Format("content-disposition", "attachment; filename={0}", fileName)); HttpContext.Current.Response.ContentType = "application/ms-excel"; HttpContext.Current.Response.Cache.SetCacheability(HttpCacheability.NoCache); HttpContext.Current.Response.Charset = System.Text.Encoding.Unicode.EncodingName; HttpContext.Current.Response.ContentEncoding = System.Text.Encoding.Unicode; HttpContext.Current.Response.BinaryWrite(System.Text.Encoding.Unicode.GetPreamble()); using (StringWriter sw = new StringWriter()) { using (HtmlTextWriter htw = new HtmlTextWriter(sw)) { // Create a form to contain the grid Table table = new Table(); // add the header row to the table if (gv.HeaderRow != null) { GridViewExportUtil.PrepareControlForExport(gv.HeaderRow); table.Rows.Add(gv.HeaderRow); } // add each of the data rows to the table foreach (GridViewRow row in gv.Rows) { GridViewExportUtil.PrepareControlForExport(row); table.Rows.Add(row); } // add the footer row to the table if (gv.FooterRow != null) { GridViewExportUtil.PrepareControlForExport(gv.FooterRow); table.Rows.Add(gv.FooterRow); } // render the table into the htmlwriter table.RenderControl(htw); // render the htmlwriter into the response HttpContext.Current.Response.Write(sw.ToString()); HttpContext.Current.Response.End(); } } } /// <summary> /// Replace any of the contained controls with literals /// </summary> /// <param name="control"></param> private static void PrepareControlForExport(Control control) { for (int i = 0; i < control.Controls.Count; i++) { Control current = control.Controls[i]; if (current is LinkButton) { control.Controls.Remove(current); control.Controls.AddAt(i, new LiteralControl((current as LinkButton).Text)); } else if (current is ImageButton) { control.Controls.Remove(current); control.Controls.AddAt(i, new LiteralControl((current as ImageButton).AlternateText)); } else if (current is HyperLink) { control.Controls.Remove(current); control.Controls.AddAt(i, new LiteralControl((current as HyperLink).Text)); } else if (current is DropDownList) { control.Controls.Remove(current); control.Controls.AddAt(i, new LiteralControl((current as DropDownList).SelectedItem.Text)); } else if (current is CheckBox) { control.Controls.Remove(current); control.Controls.AddAt(i, new LiteralControl((current as CheckBox).Checked ? "True" : "False")); } if (current.HasControls()) { GridViewExportUtil.PrepareControlForExport(current); } } } }

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  • Export GridView to Excel

    - by nCdy
    using Matt's util code (a bit edited for Unicode text) public class GridViewExportUtil { /// <param name="fileName"></param> /// <param name="gv"></param> public static void Export(string fileName, GridView gv) { HttpContext.Current.Response.Clear(); HttpContext.Current.Response.ContentType = "application/ms-excel"; HttpContext.Current.Response.Cache.SetCacheability(HttpCacheability.NoCache); HttpContext.Current.Response.Charset = System.Text.Encoding.Unicode.EncodingName; HttpContext.Current.Response.ContentEncoding = System.Text.Encoding.Unicode; HttpContext.Current.Response.BinaryWrite(System.Text.Encoding.Unicode.GetPreamble()); HttpContext.Current.Response.AddHeader( "content-disposition", string.Format(//"content-disposition", "attachment; filename=Report.xml"));//, fileName)); // Need .XLS file using (StringWriter sw = new StringWriter()) { using (HtmlTextWriter htw = new HtmlTextWriter(sw)) { // Create a form to contain the grid Table table = new Table(); // add the header row to the table if (gv.HeaderRow != null) { GridViewExportUtil.PrepareControlForExport(gv.HeaderRow); table.Rows.Add(gv.HeaderRow); } // add each of the data rows to the table foreach (GridViewRow row in gv.Rows) { GridViewExportUtil.PrepareControlForExport(row); table.Rows.Add(row); } // add the footer row to the table if (gv.FooterRow != null) { GridViewExportUtil.PrepareControlForExport(gv.FooterRow); table.Rows.Add(gv.FooterRow); } // render the table into the htmlwriter table.RenderControl(htw); // render the htmlwriter into the response HttpContext.Current.Response.Write(sw.ToString()); HttpContext.Current.Response.End(); } } } /// <summary> /// Replace any of the contained controls with literals /// </summary> /// <param name="control"></param> private static void PrepareControlForExport(Control control) { for (int i = 0; i < control.Controls.Count; i++) { Control current = control.Controls[i]; if (current is LinkButton) { control.Controls.Remove(current); control.Controls.AddAt(i, new LiteralControl((current as LinkButton).Text)); } else if (current is ImageButton) { control.Controls.Remove(current); control.Controls.AddAt(i, new LiteralControl((current as ImageButton).AlternateText)); } else if (current is HyperLink) { control.Controls.Remove(current); control.Controls.AddAt(i, new LiteralControl((current as HyperLink).Text)); } else if (current is DropDownList) { control.Controls.Remove(current); control.Controls.AddAt(i, new LiteralControl((current as DropDownList).SelectedItem.Text)); } else if (current is CheckBox) { control.Controls.Remove(current); control.Controls.AddAt(i, new LiteralControl((current as CheckBox).Checked ? "True" : "False")); } if (current.HasControls()) { GridViewExportUtil.PrepareControlForExport(current); } } } Question : How to make downloaded file editable (not Read only) And ... XLS wont opens with Unicode format. When I changing format to UTF8 I can't see Russian words :S Second question : How to make Unicode for .xls Third question : How can I save table lines ? Thank you.

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  • How to refresh a GridView?

    - by Daniel
    Hello everyone, I have a GridView which is pretty similar to the Google tutorial, except that I want to add the ImageViews on runtime (via a subactivity). The results are okay, but the layout of the View is messed up: The GridView doesn't fill the content of its parent, what do I have to do to design it properly? Here the code of adding the children: public void initializeWorkbench(GridView gv, Vector<String> items) { Prototype.workbench.setDimension(screenWidth, divider.height()+workbenchArea.height()); Prototype.workbench.activateWorkbench(); // this measures the workbench correctly Log.d(Prototype.TAG, "workbench width: "+Prototype.workbench.getMeasuredWidth()); // 320 Log.d(Prototype.TAG, "workbench height: "+Prototype.workbench.getMeasuredHeight()); // 30 ImageAdapter imgAdapter = new ImageAdapter(this.getContext(), items); gv.setAdapter(imgAdapter); gv.measure(screenWidth, screenHeight); gv.requestLayout(); gv.forceLayout(); Log.d(Prototype.TAG, "gv width: "+gv.getMeasuredWidth()); // 22 Log.d(Prototype.TAG, "gv height: "+gv.getMeasuredHeight()); // 119 Prototype.workbench.setDimension(screenWidth, divider.height()+workbenchArea.height()); } } activateWorkbench, setDimension and measure in the workbench (LinearLayout above the GridView): public void activateWorkbench() { if(this.equals(Prototype.workbench)) { this.setOrientation(VERTICAL); show = true; measure(); } } public void setDimension(int w, int h) { width = w; height = h; this.setLayoutParams(new LinearLayout.LayoutParams(width, height)); this.invalidate(); } private void measure() { if (this.getOrientation() == LinearLayout.VERTICAL) { int h = 0; int w = 0; this.measureChildren(0, 0); for (int i = 0; i < this.getChildCount(); i++) { View v = this.getChildAt(i); h += v.getMeasuredHeight(); w = (w < v.getMeasuredWidth()) ? v.getMeasuredWidth() : w; } if (this.equals(Prototype.tagarea)) height = (h < height) ? height : h; if (this.equals(Prototype.tagarea)) width = (w < width) ? width : w; } this.setMeasuredDimension(width, height); } The ImageAdapter constructor: public ImageAdapter(Context c, Vector<String> items) { mContext = c; boolean mExternalStorageAvailable = false; boolean mExternalStorageWriteable = false; String state = Environment.getExternalStorageState(); if (Environment.MEDIA_MOUNTED.equals(state)) { // We can read and write the media mExternalStorageAvailable = mExternalStorageWriteable = true; } else if (Environment.MEDIA_MOUNTED_READ_ONLY.equals(state)) { // We can only read the media mExternalStorageAvailable = true; mExternalStorageWriteable = false; } else { // Something else is wrong. It may be one of many other states, but // all we need // to know is we can neither read nor write mExternalStorageAvailable = mExternalStorageWriteable = false; } if (mExternalStorageAvailable && mExternalStorageWriteable) { for (String item : items) { File f = new File(item); if (f.exists()) { try { FileInputStream fis = new FileInputStream(f); Bitmap b = BitmapFactory.decodeStream(fis); bitmaps.add(b); files.add(f); } catch (FileNotFoundException e) { Log.e(Prototype.TAG, "", e); } } } } } And the xml layout: <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical" android:gravity="bottom" android:paddingLeft="0px" android:paddingTop="0px" android:paddingRight="0px"> <com.unimelb.pt3.ui.TransparentPanel android:id="@+id/workbench" android:layout_width="fill_parent" android:layout_height="10px" android:paddingTop="0px" android:paddingLeft="0px" android:paddingBottom="0px" android:paddingRight="0px"> <GridView xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/gridview" android:layout_width="fill_parent" android:layout_height="fill_parent" android:columnWidth="90dp" android:numColumns="auto_fit" android:verticalSpacing="10dp" android:horizontalSpacing="10dp" android:stretchMode="columnWidth" android:gravity="center" /> </com.unimelb.pt3.ui.TransparentPanel> </LinearLayout>

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  • iphone compass tilt compensation

    - by m01d
    hi, has anybody already programmed a iphone compass heading tilt compensation? i have got some approaches, but some help or a better solution would be cool! FIRST i define a vector Ev, calculated out of the cross product of Gv and Hv. Gv is a gravity vector i build out of the accelerometer values and Hv is an heading vector built out the magnetometer values. Ev stands perpendicular on Gv and Hv, so it is heading to horizonatl East. SECOND i define a vector Rv, calculated out of the cross product Bv and Gv. Bv is my looking vector and it is defined as [0,0,-1]. Rv is perpendicular to Gv and Bv and shows always to the right. THIRD the angle between these two vectors, Ev and Rv, should be my corrected heading. to calculate the angle i build the dot product and thereof the arcos. phi = arcos ( Ev * Rv / |Ev| * |Rv| ) Theoretically it should work, but maybe i have to normalize the vectors?! Has anybody got a solution for this? Thanks, m01d

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  • graphviz segmentation fault

    - by LucaB
    Hi I'm building a graph with many nodes, around 3000. I wrote a simple python program to do the trick with graphviz, but it gives me segmentation fault and I don't know why, if the graph is too big or if i'm missing something. The code is: #!/usr/bin/env python # Import graphviz import sys sys.path.append('..') sys.path.append('/usr/lib/graphviz') import gv # Import pygraph from pygraph.classes.graph import graph from pygraph.classes.digraph import digraph from pygraph.algorithms.searching import breadth_first_search from pygraph.readwrite.dot import write # Graph creation gr = graph() file = open('nodes.dat', 'r') line = file.readline() while line: gr.add_nodes([line[0:-1]]) line = file.readline() file.close() print 'nodes finished, beginning edges' edges = open('edges_ok.dat', 'r') edge = edges.readline() while edge: gr.add_edge((edge.split()[0], edge.split()[1])) edge = edges.readline() edges.close() print 'edges finished' print 'Drawing' # Draw as PNG dot = write(gr) gvv = gv.readstring(dot) gv.layout(gvv,'dot') gv.render(gvv,'svg','graph.svg') and it crashes at the gv.layout() call. The files are somthing like: nodes: node1 node2 node3 edges_ok: node1 node2 node2 node3

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  • Simple question about image_graphviz

    - by garcon1986
    Hello, I'm trying to display the example of image_graphviz Here, but it doesn't display anything in my page. Here is my page: test.php <?php require_once 'Image/GraphViz.php'; $gv = new Image_GraphViz(); $gv->addEdge(array('wake up' => 'visit bathroom')); $gv->addEdge(array('visit bathroom' => 'make coffee')); $gv->image(); ?> I think there is something wrong with the path, and then i use the absolute path which is "C:/wamp/bin/php/php5.3.0/PEAR/Image/GraphViz.php". But it doesn't work too. Is there something wrong? Do you have any idea? Thanks a lot.

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  • Export GridView to Excel (not working)

    - by Chiramisu
    I've spent the last two days trying to get some bloody data to export to Excel. After much research I determined that the best and most common way is using HttpResponse headers as shown in my code below. After stepping through countless times in debug mode, I have confirmed that the data is in fact there and both filtered and sorted the way I want it. However, it does not download as an Excel file, or do anything at all for that matter. I suspect this may have something to do with my UpdatePanel or perhaps the ImageButton not posting back properly, but I'm not sure. What am I doing wrong? Please help me to debug this issue. I will be eternally grateful. Thank you. :) Markup <asp:UpdatePanel ID="statusUpdatePanel" runat="server" UpdateMode="Conditional"> <Triggers> <asp:AsyncPostBackTrigger ControlID="btnExportXLS" EventName="Click" /> </Triggers> <ContentTemplate> <asp:GridView ID="GridView1" runat="server" AllowPaging="True" PageSize="10" AllowSorting="True" DataSourceID="GridView1SDS" DataKeyNames="ID"> </asp:GridView> <span><asp:ImageButton ID="btnExportXLS" runat="server" /></span> </ContentTemplate> </asp:UpdatePanel> Codebehind Protected Sub ExportToExcel() Handles btnExportXLS.Click Dim dt As New DataTable() Dim da As New SqlDataAdapter(SelectCommand, ConnectionString) da.Fill(dt) Dim gv As New GridView() gv.DataSource = dt gv.DataBind() Dim frm As HtmlForm = New HtmlForm() frm.Controls.Add(gv) Dim sw As New IO.StringWriter() Dim hw As New System.Web.UI.HtmlTextWriter(sw) Response.ContentType = "application/vnd.ms-excel" Response.AddHeader("content-disposition", "attachment;filename=Report.xls") Response.Charset = String.Empty gv.RenderControl(hw) Response.Write(sw.ToString()) Response.End() End Sub

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  • What is the best WebControl to create this

    - by balexandre
    current output wanted output current code public partial class test : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { if (!Page.IsPostBack) populateData(); } private void populateData() { List<temp> ls = new List<temp>(); ls.Add(new temp { a = "AAA", b = "aa", c = "a", dt = DateTime.Now }); ls.Add(new temp { a = "BBB", b = "bb", c = "b", dt = DateTime.Now }); ls.Add(new temp { a = "CCC", b = "cc", c = "c", dt = DateTime.Now.AddDays(1) }); ls.Add(new temp { a = "DDD", b = "dd", c = "d", dt = DateTime.Now.AddDays(1) }); ls.Add(new temp { a = "EEE", b = "ee", c = "e", dt = DateTime.Now.AddDays(2) }); ls.Add(new temp { a = "FFF", b = "ff", c = "f", dt = DateTime.Now.AddDays(2) }); TemplateField tc = (TemplateField)gv.Columns[0]; // <-- want to assign here just day gv.Columns.Add(tc); // <-- want to assign here just day + 1 gv.Columns.Add(tc); // <-- want to assign here just day + 2 gv.DataSource = ls; gv.DataBind(); } } public class temp { public temp() { } public string a { get; set; } public string b { get; set; } public string c { get; set; } public DateTime dt { get; set; } } and in HTML <asp:GridView ID="gv" runat="server" AutoGenerateColumns="false"> <Columns> <asp:TemplateField> <ItemTemplate> <asp:Label ID="Label1" runat="server" Text='<%# Eval("a") %>' Font-Bold="true" /><br /> <asp:Label ID="Label2" runat="server" Text='<%# Eval("b") %>' Font-Italic="true" /><br /> <asp:Label ID="Label3" runat="server" Text='<%# Eval("dt") %>' /> </ItemTemplate> </asp:TemplateField> </Columns> </asp:GridView> What I'm trying to avoid is repeat code so I can only use one unique TemplateField I can accomplish this with 3 x GridView, one per each day, but I'm really trying to simplify code as the Grid will be exactly the same (as the HTML code goes), just the DataSource changes. Any help is greatly appreciated, Thank you.

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  • Combining two operators in Evil-mode Emacs

    - by Dyslexic Tangent
    In vim I've remapped > and < when in visual mode to >gv and <gv respectively, like so: vnoremap > >gv vnoremap < <gv Since my target for this question are folks experienced with emacs and not vim, what > and < do is indent/dedent visually selected text. What gv does is reselect the previously selected text. These maps cause > and < to indent/dedent and then reselect the previously selected text. I'm trying out emacs with evil-mode and I'd like to do the same, but I'm having some difficulty figuring out how, exactly, to accomplish the automatic reselection. It looks like I need to somehow call evil-shift-right and evil-visual-restore sequentially, but I don't know how to create a map that will do both, so I tried creating my own function which would call both sequentially and map that instead, but it didn't work, possibly due to the fact that both of them are defined, not as functions with defun but instead as operators with evil-define-operator. I tried creating my own operators: (evil-define-operator shift-left-reselect (beg end) (evil-shift-left beg end) (evil-visual-restore)) (evil-define-operator shift-right-reselect (beg end) (evil-shift-right beg end) (evil-visual-restore)) but that doesn't restore visual as expected. A stab in the dark gave me this: (evil-define-operator shift-left-reselect (beg end) (evil-shift-left beg end) ('evil-visual-restore)) (evil-define-operator shift-right-reselect (beg end) (evil-shift-right beg end) ('evil-visual-restore)) but that selects one additional line whenever it is supposed to reselect. For now I've been using the following, which only has the problem where it reselects an additional line in the < operator. (evil-define-operator shift-right-reselect (beg end) (evil-shift-right beg end) (evil-visual-make-selection beg end)) (evil-define-operator shift-left-reselect (beg end) (evil-shift-left beg end) (evil-visual-make-selection beg end)) and I've mapped them: (define-key evil-visual-state-map ">" 'shift-right-reselect) (define-key evil-visual-state-map "<" 'shift-left-reselect) any help / pointers / tips would be greatly appreciated. Thanks in advance.

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  • WPF ListView as a DataGrid – Part 3

    - by psheriff
    I have had a lot of great feedback on the blog post about turning the ListView into a DataGrid by creating GridViewColumn objects on the fly. So, in the last 2 parts, I showed a couple of different methods for accomplishing this. Let’s now look at one more and that is use Reflection to extract the properties from a Product, Customer, or Employee object to create the columns. Yes, Reflection is a slower approach, but you could create the columns one time then cache the View object for re-use. Another potential drawback is you may have columns in your object that you do not wish to display on your ListView. But, just because so many people asked, here is how to accomplish this using Reflection.   Figure 1: Use Reflection to create GridViewColumns. Using Reflection to gather property names is actually quite simple. First you need to pass any type (Product, Customer, Employee, etc.) to a method like I did in my last two blog posts on this subject. Below is the method that I created in the WPFListViewCommon class that now uses reflection. C#public static GridView CreateGridViewColumns(Type anyType){  // Create the GridView  GridView gv = new GridView();  GridViewColumn gvc;   // Get the public properties.  PropertyInfo[] propInfo =          anyType.GetProperties(BindingFlags.Public |                                BindingFlags.Instance);   foreach (PropertyInfo item in propInfo)  {    gvc = new GridViewColumn();    gvc.DisplayMemberBinding = new Binding(item.Name);    gvc.Header = item.Name;    gvc.Width = Double.NaN;    gv.Columns.Add(gvc);  }   return gv;} VB.NETPublic Shared Function CreateGridViewColumns( _  ByVal anyType As Type) As GridView  ' Create the GridView   Dim gv As New GridView()  Dim gvc As GridViewColumn   ' Get the public properties.   Dim propInfo As PropertyInfo() = _    anyType.GetProperties(BindingFlags.Public Or _                          BindingFlags.Instance)   For Each item As PropertyInfo In propInfo    gvc = New GridViewColumn()    gvc.DisplayMemberBinding = New Binding(item.Name)    gvc.Header = item.Name    gvc.Width = [Double].NaN    gv.Columns.Add(gvc)  Next   Return gvEnd Function The key to using Relection is using the GetProperties method on the type you pass in. When you pass in a Product object as Type, you can now use the GetProperties method and specify, via flags, which properties you wish to return. In the code that I wrote, I am just retrieving the Public properties and only those that are Instance properties. I do not want any static/Shared properties or private properties. GetProperties returns an array of PropertyInfo objects. You can loop through this array and build your GridViewColumn objects by reading the Name property from the PropertyInfo object. Build the Product Screen To populate the ListView shown in Figure 1, you might write code like the following: C#private void CollectionSample(){  Product prod = new Product();   // Setup the GridView Columns  lstData.View =      WPFListViewCommon.CreateGridViewColumns(typeOf(Product));  lstData.DataContext = prod.GetProducts();} VB.NETPrivate Sub CollectionSample()  Dim prod As New Product()   ' Setup the GridView Columns  lstData.View = WPFListViewCommon.CreateGridViewColumns( _       GetType(Product))  lstData.DataContext = prod.GetProducts()End Sub All you need to do now is to pass in a Type object from your Product class that you can get by using the typeOf() function in C# or the GetType() function in VB. That’s all there is to it! Summary There are so many different ways to approach the same problem in programming. That is what makes programming so much fun! In this blog post I showed you how to create ListView columns on the fly using Reflection. This gives you a lot of flexibility without having to write extra code as was done previously. NOTE: You can download the complete sample code (in both VB and C#) at my website. http://www.pdsa.com/downloads. Choose Tips & Tricks, then "WPF ListView as a DataGrid – Part 3" from the drop-down. Good Luck with your Coding,Paul Sheriff ** SPECIAL OFFER FOR MY BLOG READERS **Visit http://www.pdsa.com/Event/Blog for a free eBook on "Fundamentals of N-Tier".  

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  • Server Controls in ASP.NET MVC without ViewState

    - by imran_ku07
      Introduction :           ASP.NET Web Forms provides a development environment just like GUI or windows application and try to hide statelessness nature of HTTP protocol. For accomplishing this target, Web Forms uses ViewState (a hidden field) to remove the gap between HTTP statelessness and GUI applications. But the problem with this technique is that ViewState size which grows quickly and also go back and forth with every request, as a result it will degrade application performance. In this article i will try to use existing ASP.NET server controls without ViewState.   Description :           When you add a server control which needs viewstate, in the presentation view in ASP.NET MVC application without a form tag, for example,            <asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>            It will shows the following exception,            Control 'TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server             When you place this textbox inside a form tag with runat=server, this will add the following ViewState even when you disable ViewState by using EnableViewState="false"            <input type="hidden" value="/wEPDwUJMjgzMDgzOTgzZGQ6u9CwikhHEW39ObrHyLTPFSboPA==" id="__VIEWSTATE" name="__VIEWSTATE"/>             The solution to this problem is to use the RenderControl method of server control which is simply renders HTML without any ViewState hidden field.         <% TextBox txt = new TextBox();          txt.Text = "abc";          StringBuilder sb = new StringBuilder();          System.IO.StringWriter textwriter = new System.IO.StringWriter(sb);          HtmlTextWriter htmlwriter = new HtmlTextWriter(textwriter);          txt.RenderControl(htmlwriter);  %>        <%= sb.ToString() %>             This will render <input type="text" > without any View State. This technique become very useful when you are using rich server controls like GridView. For example, let's say you have List of Recalls in Model.Recalls, then you will show your tabular data as,     <%  GridView gv = new GridView();          gv.AutoGenerateColumns = true;          gv.DataSource = Model.Recalls;          gv.DataBind();         StringBuilder sb = new StringBuilder();         System.IO.StringWriter textwriter = new System.IO.StringWriter(sb);         HtmlTextWriter htmlwriter = new HtmlTextWriter(textwriter);         gv.RenderControl(htmlwriter);%>            <%= sb.ToString() %>             This code might looks odd in your presentation view. A more better approach is to create a HTML Helper method which contains the above code. Summary :        In some cases you might needs to use existing ASP.NET Web Forms server controls but also dislikes ViewState. In this article i try to solve this gap by using the RenderControl method of Control class. Hopefully you enjoyed and become ready to create HTML helpers for many of the existing server controls.

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  • Warning in image_graphviz

    - by garcon1986
    Hello, I have got a warning in image_graphviz, i have viewed a post, who has a similar error. I have installed pear image_graphviz package(Image_GraphViz-1.2.1), I also installed graphviz.msi(Graphviz2.25.msi) in windows(But i don't know if does something with image_graphviz and if it does have some effects when i use image_graphviz). Do i need to do something else? Here is my code from pear image_graphviz site. <?php require_once 'Image/GraphViz.php'; error_reporting(E_ALL ^ E_NOTICE); //Added E_NOTICE $gv = new Image_GraphViz(); $gv->addEdge(array('wake up' => 'visit bathroom')); $gv->addEdge(array('visit bathroom' => 'make coffee')); $gv->image(); ?> This is the warning: Warning: fopen(C:\WINDOWS\Temp\gra50.tmp.svg) [function.fopen]: failed to open stream: No such file or directory in C:\wamp\bin\php\php5.3.0\PEAR\Image\GraphViz.php on line 210 Notice: Undefined variable: data in C:\wamp\bin\php\php5.3.0\PEAR\Image\GraphViz.php on line 218 Thanks Pekka Gaiser, I used error_reporting(E_ALL ^ E_NOTICE);. I don't know how to change the temp directory, but c:/windows/temp exists in my computer. I haven't solve the problem. Thanks all for advice.

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  • How do I fetch a set of rows from data table

    - by cmrhema
    Hi, I have a dataset that has two datatables. In the first datatable I have EmpNo,EmpName and EmpAddress In the second datatable I have Empno,EmpJoindate, EmpSalary. I want a result where I should show EmpName as the label and his/her details in the gridview I populate a datalist with the first table, and have EmpNo as the datakeys. Then I populate the gridview inside the datatable which has EmpNo,EmpJoinDate and EmpAddress. My code is some what as below Datalist1.DataSource = dt; Datalist1.DataBind(); for (int i = 0; i < Datalist1.Items.Count; i++) { int EmpNo = Convert.ToInt32(Datalist1.DataKeys[i]); GridView gv = (GridView)Datalist1.FindControl("gv"); gv.DataSource = dt2; gv.DataBind(); } Now I have a problem, I have to bind the Details of the corresponding Employee to the gridview. Whereas the above code will display all the details of all employees in the gridview. If we use IEnumerable we give a condition where(a=a.eno=EmpNo), and bind that list to the gridview. How do I do this in datatable. kindly do not give me suggestions of altering the stored procedure which results the values in two tables, because that cannot be altered. I have to find a solution within the existing objects I have. Regards Hema

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