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  • Converting binary to hexadecimal??

    - by Bobbert
    Hey guys, Just wondering on how I would go about converting binary to hexadecimal?? Would I first have to convert the binary to decimal and then to hexadecimal?? For example, 101101001.101110101010011 How would I go about converting a complex binary such as the above to hexadecimal? Thanks in advance

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  • Why suddenly DOS-type hexadecimal file names?

    - by Marvin Nicholson
    One of the fairly recent folders on my XP SATA data drive suddenly shows DOS-type hexadecimal file names (i.e., eight characters with three-character extensions) I deleted them and now my Recycle bin shows them with a tilde (i.e., 194ABE~1.JPG). The images are all valid but the file names I assigned are gone. (The 2-terabyte SATA data drive has no OS, if that matters.) The last time this happened on an IDE drive, I was able to back up all the remaining files just before the drive died. Am I facing the same scenario now with my 2-terabyte SATA data drive? It is only a couple of years old. Should I quickly buy another one and back up 20 years of files to it before my current drive dies?

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  • Read from file hexadecimal number and change their representation style

    - by user576844
    I want to write a program changing the notation of all hexadecimal numbers found in an assembly source file from traditional (h) to C-style (0x). I have started the coding part but am not sure how can I detect the hexadecimal numbers and eventually change the style and save it back in the file... I have started writing the program.. ## Mips program - .data fin: .ascii "" # filename for input msg0: .asciiz "aaaa" msg1: .asciiz "Please enter the input file name:" buffer: .asciiz "" .text #----------------------- li $v0, 4 la $a0, msg1 syscall li $v0, 8 la $a0, fin li $a1, 21 syscall jal fileRead #read from file move $s1, $v0 #$t0 = total number of bytes li $t0, 0 # Loop counter loop: bge $t0, $s1, end #if end of file reached OR if there is an error in the file lb $t5, buffer($t0) #load next byte from file jal checkhexa #check for hexadecimal numbers addi $t0, $t0, 1 #increment loop counter j loop end: jal output jal fileClose li $v0, 10 syscall fileRead: # Open file for reading li $v0, 13 # system call for open file la $a0, fin # input file name li $a1, 0 # flag for reading li $a2, 0 # mode is ignored syscall # open a file move $s0, $v0 # save the file descriptor # reading from file just opened li $v0, 14 # system call for reading from file move $a0, $s0 # file descriptor la $a1, buffer # address of buffer from which to read li $a2, 100000 # hardcoded buffer length syscall # read from file jr $ra Any help would be appreciated.

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  • Convert Hexadecimal String to Data

    - by AriX
    Hi Stack Overflow, I have found a whole lot of different solutions to this problem, but not all of them work, and a lot of them seem somewhat hacky and inefficient. Basically I have a string of hexadecimal data (i.e. "55 AA 41 2A 00 94 55 AA BB BB 00 FF") which I would like to convert to raw data. What is the best way to do this? UPDATE: Vicky's solution worked great for me, but I changed it to work with hexadecimal strings that don't have spaces in between and changed the style a bit. int i = 0; char *hexString = "55AA412A009455AABBBB00FF" char *hexPtr = hexString; unsigned int *result = calloc(strlen(hexString)/2 + 1, sizeof *result); while (sscanf(hexPtr, "%02x", &result[i++])) { hexPtr += 2; if (hexPtr >= hexString + strlen(hexString)) break; } return result;

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  • Java Regex for matching hexadecimal numbers in a file

    - by Ranman
    So I'm reading in a file (like java program < trace.dat) which looks something like this: 58 68 58 68 40 c 40 48 FA If I'm lucky but more often it has several whitespace characters before and after each line. These are hexadecimal addresses that I'm parsing and I basically need to make sure that I can get the line using a scanner, buffered reader... whatever and make sure I can then convert the hexadecimal to an integer. This is what I have so far: Scanner scanner = new Scanner(System.in); int address; String binary; Pattern pattern = Pattern.compile("^\\s*[0-9A-Fa-f]*\\s*$", Pattern.CASE_INSENSITIVE); while(scanner.hasNextLine()) { address = Integer.parseInt(scanner.next(pattern), 16); binary = Integer.toBinaryString(address); //Do lots of other stuff here } //DO MORE STUFF HERE... So I've traced all my errors to parsing input and stuff so I guess I'm just trying to figure out what regex or approach I need to get this working the way I want.

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  • [C] Signed Hexadecimal string to long int function

    - by Ben
    I am trying to convert a 24bit Hexadecimal string (6 characters) signed in two's complement to a long int in C. This is the function I have come up with: long int hex2li (char string[]) { char *pEnd; long int result = strtol (string, &pEnd, 16); if (strcmp (pEnd, "") == 0) { if (toupper (string[0]) == 'F') { return result - 16777216; } else { return result; } } return LONG_MIN; } Is it valid? Is there a better way of doing this?

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  • C#: How to parse a hexadecimal digit

    - by Biosci3c
    Okay, I am working on a card playing program, and I am storing card values as hexadecimal digits. Here is the array: public int[] originalCards = new int[54] { 0x11, 0x12, 0x13, 0x14, 0x15, 0x16, 0x17, 0x18, 0x19, 0x1A, 0x1B, 0x1C, 0x1D, 0x21, 0x22, 0x23, 0x24, 0x25, 0x26, 0x27, 0x28, 0x29, 0x2A, 0x2B, 0x2C, 0x2D, 0x31, 0x32, 0x33, 0x34, 0x35, 0x36, 0x37, 0x38, 0x39, 0x3A, 0x3B, 0x3C, 0x3D, 0x41, 0x42, 0x43, 0x44, 0x45, 0x46, 0x47, 0x48, 0x49, 0x4A, 0x4B, 0x4C, 0x4D, 0x50, 0x51 }; The first digit refers to the suit (1 = spades; 2 = clubs; .... 5 = Jokers) The second digit is the number of the card (1 = ace, 5 = 5; 13 = K, etc). I would like to do something like the following: Pseudocode: public int ReturnCard(int num) { int card = currentDeck[num]; int suit = card.firsthexdigit; int value = card.secondhexdigit; return 0; } I don't need a new method to work on ints, I just included it for clarity's sake. Anybody know how to do this in C#?

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  • Problem with writing a hexadecimal string

    - by quilby
    Here is my code /* gcc -c -Wall -g main.c gcc -g -lm -o main main.o */ #include <stdlib.h> #include <stdio.h> #include <string.h> void stringToHex(const char* string, char* hex) { int i = 0; for(i = 0; i < strlen(string)/2; i++) { printf("s%x", string[2*i]); //for debugging sprintf(&hex[i], "%x", string[2*i]); printf("h%x\n", hex[i]); //for debugging } } void writeHex(char* hex, int length, FILE* file, long position) { fseek(file, position, SEEK_SET); fwrite(hex, sizeof(char), length, file); } int main(int argc, char** argv) { FILE* pic = fopen("hi.bmp", "w+b"); const char* string = "f2"; char hex[strlen(string)/2]; stringToHex(string, hex); writeHex(hex, strlen(string)/2, pic, 0); fclose(pic); return 0; } I want it to save the hexadecimal number 0xf2 to a file (later I will have to write bigger/longer numbers though). The program prints out - s66h36 And when I use hexedit to view the file I see the number '36' in it. Why is my code not working? Thanks!

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  • Simple Hexadecimal color question

    - by M28
    I have a number between 0.0 and 1.0, I would like to convert it to a grayscale color. White = 0 Black = 1 You can show me how in any understandable language (I prefer actionscript 3) Please, don't just give a name of a function that a language have to do this, I want to know how it does.

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  • setBit java method using bit shifting and hexadecimal code - question

    - by somewhat_confused
    I am having trouble understanding what is happening in the two lines with the 0xFF7F and the one below it. There is a link here that explains it to some degree. http://www.herongyang.com/java/Bit-String-Set-Bit-to-Byte-Array.html I don't know if 0xFF7FposBit) & oldByte) & 0x00FF are supposed to be 3 values 'AND'ed together or how this is supposed to be read. If anyone can clarify what is happening here a little better, I would greatly appreciate it. private static void setBit(byte[] data, final int pos, final int val) { int posByte = pos/8; int posBit = pos%8; byte oldByte = data[posByte]; oldByte = (byte) (((0xFF7F>>posBit) & oldByte) & 0x00FF); byte newByte = (byte) ((val<<(8-(posBit+1))) | oldByte); data[posByte] = newByte; } passed into this method as parameters from a selectBits method was setBit(out,i,val); out = is byte[] out = new byte[numOfBytes]; (numOfBytes can be 7 in this situation) i = which is number [57], the original number from the PC1 int array holding the 56-integers. val = which is the bit taken from the byte array from the getBit() method.

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  • How do you remove invalid hexadecimal characters from an XML-based data source prior to constructing

    - by Oppositional
    Is there any easy/general way to clean an XML based data source prior to using it in an XmlReader so that I can gracefully consume XML data that is non-conformant to the hexadecimal character restrictions placed on XML? Note: The solution needs to handle XML data sources that use character encodings other than UTF-8, e.g. by specifying the character encoding at the XML document declaration. Not mangling the character encoding of the source while stripping invalid hexadecimal characters has been a major sticking point. The removal of invalid hexadecimal characters should only remove hexadecimal encoded values, as you can often find href values in data that happens to contains a string that would be a string match for a hexadecimal character. Background: I need to consume an XML-based data source that conforms to a specific format (think Atom or RSS feeds), but want to be able to consume data sources that have been published which contain invalid hexadecimal characters per the XML specification. In .NET if you have a Stream that represents the XML data source, and then attempt to parse it using an XmlReader and/or XPathDocument, an exception is raised due to the inclusion of invalid hexadecimal characters in the XML data. My current attempt to resolve this issue is to parse the Stream as a string and use a regular expression to remove and/or replace the invalid hexadecimal characters, but I am looking for a more performant solution.

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  • Delphi: how to efficently read a big binary file, converting it to hexadecimal for passing it as a v

    - by user193655
    I need to convert a binary file (a zip file) into hexadecimal representation, to then send it to sql-server as a varbinary(max) function parameter. A full example (using a very small file!) is: 1) my file contains the following bits 000011110000111 2) I need a procedure to QUICKLY convert it to 0F0F 3) I will call a sql server function passing 0x0F0F as parameter The problem is that I have large files (up to 100MB, even if average file size is 100KB files are possible), so I need the fastest way to do this. Otherwise stated: I need to create the string '0x'+BinaryDataInHexadecimalRepresentation in the most efficient way. Related question: passing hexadecimal data to sql server

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  • [C#] Improving method to read signed 8-bit integers from hexadecimal.

    - by JYelton
    Scenario: I have a string of hexadecimal characters which encode 8-bit signed integers. Each two characters represent a byte which employ the leftmost (MSB) bit as the sign (rather than two's complement). I am converting these to signed ints within a loop and wondered if there's a better way to do it. There are too many conversions and I am sure there's a more efficient method that I am missing. Current Code: string strData = "FFC000407F"; // example input data, encodes: -127, -64, 0, 64, 127 int v; for (int x = 0; x < strData.Length/2; x++) { v = HexToInt(strData.Substring(x * 2, 2)); Console.WriteLine(v); // do stuff with v } private int HexToInt(string _hexData) { string strBinary = Convert.ToString(Convert.ToInt32(_hexData, 16), 2).PadLeft(_hexData.Length * 4, '0'); int i = Convert.ToInt32(strBinary.Substring(1, 7), 2); i = (strBinary.Substring(0, 1) == "0" ? i : -i); return i; } Question: Is there a more streamlined and direct approach to reading two hex characters and converting them to an int when they represent a signed int (-127 to 127) using the leftmost bit as the sign?

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  • Improving method to read signed 8-bit integers from hexadecimal.

    - by JYelton
    Scenario: I have a string of hexadecimal characters which encode 8-bit signed integers. Each two characters represent a byte which employ the leftmost (MSB) bit as the sign (rather than two's complement). I am converting these to signed ints within a loop and wondered if there's a better way to do it. There are too many conversions and I am sure there's a more efficient method that I am missing. Current Code: string strData = "FFC000407F"; // example input data, encodes: -127, -64, 0, 64, 127 int v; for (int x = 0; x < strData.Length/2; x++) { v = HexToInt(strData.Substring(x * 2, 2)); Console.WriteLine(v); // do stuff with v } private int HexToInt(string _hexData) { string strBinary = Convert.ToString(Convert.ToInt32(_hexData, 16), 2).PadLeft(_hexData.Length * 4, '0'); int i = Convert.ToInt32(strBinary.Substring(1, 7), 2); i = (strBinary.Substring(0, 1) == "0" ? i : -i); return i; } Question: Is there a more streamlined and direct approach to reading two hex characters and converting them to an int when they represent a signed int (-127 to 127) using the leftmost bit as the sign?

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