Search Results

Search found 95 results on 4 pages for 'jj mcfly'.

Page 1/4 | 1 2 3 4  | Next Page >

• Networking- Wireless and Wired not working

  - by JJ White

  So everything in Ubuntu has been working great until networking stopped working. I've spent the better part of two days scouring for a fix with no luck. Here is my info...your help would so be appreciated. grep -i eth /var/log/syslog | tail Sep 25 16:31:59 jj-laptop NetworkManager[970]: <info> (eth0): cleaning up... Sep 25 16:31:59 jj-laptop NetworkManager[970]: <info> (eth0): taking down device. Sep 25 16:31:59 jj-laptop kernel: [23403.998837] sky2 0000:02:00.0: eth0: disabling interface Sep 25 16:35:54 jj-laptop NetworkManager[970]: <info> (eth0): now managed Sep 25 16:35:54 jj-laptop NetworkManager[970]: <info> (eth0): device state change: unmanaged -> unavailable (reason 'managed') [10 20 2] Sep 25 16:35:54 jj-laptop NetworkManager[970]: <info> (eth0): bringing up device. Sep 25 16:35:54 jj-laptop kernel: [23413.629424] sky2 0000:02:00.0: eth0: enabling interface Sep 25 16:35:54 jj-laptop kernel: [23413.635703] ADDRCONF(NETDEV_UP): eth0: link is not ready Sep 25 16:35:54 jj-laptop NetworkManager[970]: <info> (eth0): preparing device. Sep 25 16:35:54 jj-laptop NetworkManager[970]: <info> (eth0): deactivating device (reason 'managed') [2] and then ifconfig -a eth0 Link encap:Ethernet HWaddr 00:17:42:14:e9:e1 UP BROADCAST MULTICAST MTU:1500 Metric:1 RX packets:4605 errors:0 dropped:0 overruns:0 frame:0 TX packets:287 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:315161 (315.1 KB) TX bytes:63680 (63.6 KB) Interrupt:16 lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:13018 errors:0 dropped:0 overruns:0 frame:0 TX packets:13018 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:880484 (880.4 KB) TX bytes:880484 (880.4 KB) wlan0 Link encap:Ethernet HWaddr 00:13:02:d0:ee:13 BROADCAST MULTICAST MTU:1500 Metric:1 RX packets:0 errors:0 dropped:0 overruns:0 frame:0 TX packets:0 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:0 (0.0 B) TX bytes:0 (0.0 B) also iwconfig lo no wireless extensions. wlan0 IEEE 802.11abg ESSID:off/any Mode:Managed Access Point: Not-Associated Tx-Power=off Retry long limit:7 RTS thr:off Fragment thr:off Power Management:on eth0 no wireless extensions. and of course sudo lshw -C network *-network description: Ethernet interface product: 88E8055 PCI-E Gigabit Ethernet Controller vendor: Marvell Technology Group Ltd. physical id: 0 bus info: pci@0000:02:00.0 logical name: eth0 version: 12 serial: 00:17:42:14:e9:e1 size: 1Gbit/s capacity: 1Gbit/s width: 64 bits clock: 33MHz capabilities: pm vpd msi pciexpress bus_master cap_list rom ethernet physical tp 10bt 10bt-fd 100bt 100bt-fd 1000bt 1000bt-fd autonegotiation configuration: autonegotiation=on broadcast=yes driver=sky2 driverversion=1.30 duplex=full firmware=N/A latency=0 link=no multicast=yes port=twisted pair speed=1Gbit/s resources: irq:44 memory:f0000000-f0003fff ioport:2000(size=256) memory:c0a00000-c0a1ffff *-network DISABLED description: Wireless interface product: PRO/Wireless 3945ABG [Golan] Network Connection vendor: Intel Corporation physical id: 0 bus info: pci@0000:05:00.0 logical name: wlan0 version: 02 serial: 00:13:02:d0:ee:13 width: 32 bits clock: 33MHz capabilities: pm msi pciexpress bus_master cap_list ethernet physical wireless configuration: broadcast=yes driver=iwl3945 driverversion=3.2.0-31-generic firmware=15.32.2.9 latency=0 link=no multicast=yes wireless=IEEE 802.11abg resources: irq:45 memory:c0100000-c0100fff last but not least lsmod Module Size Used by nls_iso8859_1 12617 0 nls_cp437 12751 0 vfat 17308 0 fat 55605 1 vfat usb_storage 39646 0 uas 17828 0 dm_crypt 22528 0 rfcomm 38139 0 parport_pc 32114 0 bnep 17830 2 ppdev 12849 0 bluetooth 158438 10 rfcomm,bnep binfmt_misc 17292 1 snd_hda_codec_idt 60251 1 pcmcia 39791 0 joydev 17393 0 snd_hda_intel 32765 3 snd_hda_codec 109562 2 snd_hda_codec_idt,snd_hda_intel snd_hwdep 13276 1 snd_hda_codec snd_pcm 80845 2 snd_hda_intel,snd_hda_codec snd_seq_midi 13132 0 yenta_socket 27428 0 snd_rawmidi 25424 1 snd_seq_midi snd_seq_midi_event 14475 1 snd_seq_midi snd_seq 51567 2 snd_seq_midi,snd_seq_midi_event pcmcia_rsrc 18367 1 yenta_socket wacom_w8001 12906 0 irda 185517 0 arc4 12473 2 iwl3945 73111 0 iwl_legacy 71134 1 iwl3945 mac80211 436455 2 iwl3945,iwl_legacy cfg80211 178679 3 iwl3945,iwl_legacy,mac80211 snd_timer 28931 2 snd_pcm,snd_seq snd_seq_device 14172 3 snd_seq_midi,snd_rawmidi,snd_seq dm_multipath 22710 0 pcmcia_core 21511 3 pcmcia,yenta_socket,pcmcia_rsrc psmouse 96619 0 apanel 12718 0 serport 12808 1 serio_raw 13027 0 crc_ccitt 12595 1 irda mac_hid 13077 0 snd 62064 15 snd_hda_codec_idt,snd_hda_intel,snd_hda_codec,snd_hwdep,snd_pcm,snd_rawmidi,snd_seq,snd_t imer,snd_seq_device input_polldev 13648 1 apanel soundcore 14635 1 snd snd_page_alloc 14115 2 snd_hda_intel,snd_pcm lp 17455 0 fujitsu_laptop 18504 0 parport 40930 3 parport_pc,ppdev,lp dm_raid45 76451 0 xor 25987 1 dm_raid45 dm_mirror 21822 0 dm_region_hash 16065 1 dm_mirror dm_log 18193 3 dm_raid45,dm_mirror,dm_region_hash sdhci_pci 18324 0 sdhci 28241 1 sdhci_pci sky2 49545 0 i915 414939 3 drm_kms_helper 45466 1 i915 drm 197692 4 i915,drm_kms_helper i2c_algo_bit 13199 1 i915 video 19068 1 i915

  Read the article

• CUDA Kernel Not Updating Global Variable

  - by Taher Khokhawala

  I am facing the following problem in a CUDA kernel. There is an array "cu_fx" in global memory. Each thread has a unique identifier jj and a local loop variable ii and a local float variable temp. Following code is not working. It is not at all changing cu_fx[jj]. At the end of loop cu_fx[jj] remains 0. ii = 0; cu_fx[jj] = 0; while(ii < l) { if(cu_y[ii] > 0) cu_fx[jj] += (cu_mu[ii]*cu_Kernel[(jj-start_row)*Kernel_w + ii]); else cu_fx[jj] -= (cu_mu[ii]*cu_Kernel[(jj-start_row)*Kernel_w + ii]); ii++; } But when I rewrite it using a temporary variable temp, it works fine. ii = 0; temp = 0; while(ii < l) { if(cu_y[ii] > 0) temp += (cu_mu[ii]*cu_Kernel[(jj-start_row)*Kernel_w + ii]); else temp -= (cu_mu[ii]*cu_Kernel[(jj-start_row)*Kernel_w + ii]); ii++; } cu_fx[jj] = temp; Can somebody please help with this problem. Thanking in advance.

  Read the article

• Template Sort In C++

  - by wdow88

  Hey all, I'm trying to write a sort function but am having trouble figuring out how to initialize a value, and making this function work as a generic template. The sort works by: Find a pair =(ii,jj)= with a minimum value = ii+jj = such at A[ii]A[jj] If such a pair exists, then swap A[ii] and A[jj] else break; The function I have written is as follows: template <typename T> void sort(T *A, int size) { T min =453; T temp=0; bool swapper = true; while(swapper) { swapper = false; int index1 = 0, index2 = 0; for (int ii = 0; ii < size-1; ii++){ for (int jj = ii + 1; jj < size; jj++){ if((min >= (A[ii]+A[jj])) && (A[ii] > A[jj])){ min = (A[ii]+A[jj]); index1 = ii; index2 = jj; swapper = true; } } } if (!swapper) return; else { temp = A[index1]; A[index1] = A[index2]; A[index2] = temp; sort(A,size); } } } This function will successfully sort an array of integers, but not an array of chars. I do not know how to properly initialize the min value for the start of the comparison. I tried initializing the value by simply adding the first two elements of the array together (min = A[0] + A[1]), but it looks to me like for this algorithm it will fail. I know this is sort of a strange type of sort, but it is practice for a test, so thanks for any input.

  Read the article

• Performance in backpropagation algorithm

  - by Taban

  I've written a matlab program for standard backpropagation algorithm, it is my homework and I should not use matlab toolbox, so I write the entire code by myself. This link helped me for backpropagation algorithm. I have a data set of 40 random number and initial weights randomly. As output, I want to see a diagram that shows the performance. I used mse and plot function to see performance for 20 epochs but the result is this: I heard that performance should go up through backpropagation, so I want to know is there any problem with my code or this result is normal because local minimums. This is my code: Hidden_node=inputdlg('Enter the number of Hidden nodes'); a=0.5;%initialize learning rate hiddenn=str2num(Hidden_node{1,1}); randn('seed',0); %creating data set s=2; N=10; m=[5 -5 5 5;-5 -5 5 -5]; S = s*eye(2); [l,c] = size(m); x = []; % Creating the training set for i = 1:c x = [x mvnrnd(m(:,i)',S,N)']; end % target value toutput=[ones(1,N) zeros(1,N) ones(1,N) zeros(1,N)]; for epoch=1:20; %number of epochs for kk=1:40; %number of patterns %initial weights of hidden layer for ii=1 : 2; for jj=1 :hiddenn; whidden{ii,jj}=rand(1); end end initial the wights of output layer for ii=1 : hiddenn; woutput{ii,1}=rand(1); end for ii=1:hiddenn; x1=x(1,kk); x2=x(2,kk); w1=whidden{1,ii}; w2=whidden{2,ii}; activation{1,ii}=(x1(1,1)*w1(1,1))+(x2(1,1)*w2(1,1)); end %calculate output of hidden nodes for ii=1:hiddenn; hidden_to_out{1,ii}=logsig(activation{1,ii}); end activation_O{1,1}=0; for jj=1:hiddenn; activation_O{1,1} = activation_O{1,1}+(hidden_to_out{1,jj}*woutput{jj,1}); end %calculate output out{1,1}=logsig(activation_O{1,1}); out_for_plot(1,kk)= out{1,ii}; %calculate error for output node delta_out{1,1}=(toutput(1,kk)-out{1,1}); %update weight of output node for ii=1:hiddenn; woutput{ii,jj}=woutput{ii,jj}+delta_out{1,jj}*hidden_to_out{1,ii}*dlogsig(activation_O{1,jj},logsig(activation_O{1,jj}))*a; end %calculate error of hidden nodes for ii=1:hiddenn; delta_hidden{1,ii}=woutput{ii,1}*delta_out{1,1}; end %update weight of hidden nodes for ii=1:hiddenn; for jj=1:2; whidden{jj,ii}= whidden{jj,ii}+(delta_hidden{1,ii}*dlogsig(activation{1,ii},logsig(activation{1,ii}))*x(jj,kk)*a); end end a=a/(1.1);%decrease learning rate end %calculate performance e=toutput(1,kk)-out_for_plot(1,1); perf(1,epoch)=mse(e); end plot(perf); Thanks a lot.

  Read the article

• WCF Operations and Multidimensional Arrays

  - by JoshReuben

  You cant pass MultiD arrays accross the wire using WCF - you need to pass jagged arrays. heres 2 extension methods that will allow you to convert prior to serialzation and convert back after deserialization:         public static T[,] ToMultiD<T>(this T[][] jArray)         {             int i = jArray.Count();             int j = jArray.Select(x => x.Count()).Aggregate(0, (current, c) => (current > c) ? current : c);                         var mArray = new T[i, j];             for (int ii = 0; ii < i; ii++)             {                 for (int jj = 0; jj < j; jj++)                 {                     mArray[ii, jj] = jArray[ii][jj];                 }             }             return mArray;         }         public static T[][] ToJagged<T>(this T[,] mArray)         {             var cols = mArray.GetLength(0);             var rows = mArray.GetLength(1);             var jArray = new T[cols][];             for (int i = 0; i < cols; i++)             {                 jArray[i] = new T[rows];                 for (int j = 0; j < rows; j++)                 {                     jArray[i][j] = mArray[i, j];                 }             }             return jArray;         } enjoy!

  Read the article

• Multi Seat Ubuntu 10.10

  - by JJ Mcfly

  Hi I was hoping to have a 2 seat setup. One will be for my TV just going to run Boxee. The other is for my main Desktop. I've been looking for a good guide to help me navigate this, I'd like to use ubuntu 10.10. I am assuming it's just a case of getting a box + 2 graphics adaptors and 2 usb mice and keyboards, one of which will be bluetooth for the TV. I can't seem to find much documentation on this idea. Can anyone point me in the right direction? Also I am assuming that this is all possible with a standard ubuntu install, but with some additional configuration. Thank you in advance for any advice you can offer me JJ Mcfly

  Read the article

• How do I set up multi seat?

  - by JJ Mcfly

  Hi I was hoping to have a 2 seat setup. One will be for my TV just going to run Boxee. The other is for my main Desktop. I've been looking for a good guide to help me navigate this, I'd like to use ubuntu 10.10. I am assuming it's just a case of getting a box + 2 graphics adaptors and 2 usb mice and keyboards, one of which will be bluetooth for the TV. I can't seem to find much documentation on this idea. Can anyone point me in the right direction? Also I am assuming that this is all possible with a standard ubuntu install, but with some additional configuration. Thank you in advance for any advice you can offer me JJ Mcfly

  Read the article

• How would this code be refactored to use jQuery?

  - by C.W.Holeman II

  How would this code be refactored to use jQuery? var lu = function luf(aPrefix){ switch (aPrefix){ case 'xhtml': return 'http://www.w3.org/1999/xhtml'; case 'math': return 'http://www.w3.org/1998/Math/MathML'; case 'svg': return 'http://www.w3.org/2000/svg'; case 'emleo': return 'http://emle.sf.net/emle020000/emleo'; } return ''; }; function emleProcessOnLoad(aThis) { var result = document.evaluate("//xhtml:span[@class='emleOnLoad']", aThis.document, lu, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null); for (var jj=0; jj<result.snapshotLength; jj++){ var emleOnLoad = result.snapshotItem(jj).textContent; eval("var emleThis=result.snapshotItem(jj);" + emleOnLoad); } }

  Read the article

• Simplex Noise Help

  - by Alex Larsen

  Im Making A Minecraft Like Gae In XNA C# And I Need To Generate Land With Caves This Is The Code For Simplex I Have /// <summary> /// 1D simplex noise /// </summary> /// <param name="x"></param> /// <returns></returns> public static float Generate(float x) { int i0 = FastFloor(x); int i1 = i0 + 1; float x0 = x - i0; float x1 = x0 - 1.0f; float n0, n1; float t0 = 1.0f - x0 * x0; t0 *= t0; n0 = t0 * t0 * grad(perm[i0 & 0xff], x0); float t1 = 1.0f - x1 * x1; t1 *= t1; n1 = t1 * t1 * grad(perm[i1 & 0xff], x1); // The maximum value of this noise is 8*(3/4)^4 = 2.53125 // A factor of 0.395 scales to fit exactly within [-1,1] return 0.395f * (n0 + n1); } /// <summary> /// 2D simplex noise /// </summary> /// <param name="x"></param> /// <param name="y"></param> /// <returns></returns> public static float Generate(float x, float y) { const float F2 = 0.366025403f; // F2 = 0.5*(sqrt(3.0)-1.0) const float G2 = 0.211324865f; // G2 = (3.0-Math.sqrt(3.0))/6.0 float n0, n1, n2; // Noise contributions from the three corners // Skew the input space to determine which simplex cell we're in float s = (x + y) * F2; // Hairy factor for 2D float xs = x + s; float ys = y + s; int i = FastFloor(xs); int j = FastFloor(ys); float t = (float)(i + j) * G2; float X0 = i - t; // Unskew the cell origin back to (x,y) space float Y0 = j - t; float x0 = x - X0; // The x,y distances from the cell origin float y0 = y - Y0; // For the 2D case, the simplex shape is an equilateral triangle. // Determine which simplex we are in. int i1, j1; // Offsets for second (middle) corner of simplex in (i,j) coords if (x0 > y0) { i1 = 1; j1 = 0; } // lower triangle, XY order: (0,0)->(1,0)->(1,1) else { i1 = 0; j1 = 1; } // upper triangle, YX order: (0,0)->(0,1)->(1,1) // A step of (1,0) in (i,j) means a step of (1-c,-c) in (x,y), and // a step of (0,1) in (i,j) means a step of (-c,1-c) in (x,y), where // c = (3-sqrt(3))/6 float x1 = x0 - i1 + G2; // Offsets for middle corner in (x,y) unskewed coords float y1 = y0 - j1 + G2; float x2 = x0 - 1.0f + 2.0f * G2; // Offsets for last corner in (x,y) unskewed coords float y2 = y0 - 1.0f + 2.0f * G2; // Wrap the integer indices at 256, to avoid indexing perm[] out of bounds int ii = i % 256; int jj = j % 256; // Calculate the contribution from the three corners float t0 = 0.5f - x0 * x0 - y0 * y0; if (t0 < 0.0f) n0 = 0.0f; else { t0 *= t0; n0 = t0 * t0 * grad(perm[ii + perm[jj]], x0, y0); } float t1 = 0.5f - x1 * x1 - y1 * y1; if (t1 < 0.0f) n1 = 0.0f; else { t1 *= t1; n1 = t1 * t1 * grad(perm[ii + i1 + perm[jj + j1]], x1, y1); } float t2 = 0.5f - x2 * x2 - y2 * y2; if (t2 < 0.0f) n2 = 0.0f; else { t2 *= t2; n2 = t2 * t2 * grad(perm[ii + 1 + perm[jj + 1]], x2, y2); } // Add contributions from each corner to get the final noise value. // The result is scaled to return values in the interval [-1,1]. return 40.0f * (n0 + n1 + n2); // TODO: The scale factor is preliminary! } public static float Generate(float x, float y, float z) { // Simple skewing factors for the 3D case const float F3 = 0.333333333f; const float G3 = 0.166666667f; float n0, n1, n2, n3; // Noise contributions from the four corners // Skew the input space to determine which simplex cell we're in float s = (x + y + z) * F3; // Very nice and simple skew factor for 3D float xs = x + s; float ys = y + s; float zs = z + s; int i = FastFloor(xs); int j = FastFloor(ys); int k = FastFloor(zs); float t = (float)(i + j + k) * G3; float X0 = i - t; // Unskew the cell origin back to (x,y,z) space float Y0 = j - t; float Z0 = k - t; float x0 = x - X0; // The x,y,z distances from the cell origin float y0 = y - Y0; float z0 = z - Z0; // For the 3D case, the simplex shape is a slightly irregular tetrahedron. // Determine which simplex we are in. int i1, j1, k1; // Offsets for second corner of simplex in (i,j,k) coords int i2, j2, k2; // Offsets for third corner of simplex in (i,j,k) coords /* This code would benefit from a backport from the GLSL version! */ if (x0 >= y0) { if (y0 >= z0) { i1 = 1; j1 = 0; k1 = 0; i2 = 1; j2 = 1; k2 = 0; } // X Y Z order else if (x0 >= z0) { i1 = 1; j1 = 0; k1 = 0; i2 = 1; j2 = 0; k2 = 1; } // X Z Y order else { i1 = 0; j1 = 0; k1 = 1; i2 = 1; j2 = 0; k2 = 1; } // Z X Y order } else { // x0<y0 if (y0 < z0) { i1 = 0; j1 = 0; k1 = 1; i2 = 0; j2 = 1; k2 = 1; } // Z Y X order else if (x0 < z0) { i1 = 0; j1 = 1; k1 = 0; i2 = 0; j2 = 1; k2 = 1; } // Y Z X order else { i1 = 0; j1 = 1; k1 = 0; i2 = 1; j2 = 1; k2 = 0; } // Y X Z order } // A step of (1,0,0) in (i,j,k) means a step of (1-c,-c,-c) in (x,y,z), // a step of (0,1,0) in (i,j,k) means a step of (-c,1-c,-c) in (x,y,z), and // a step of (0,0,1) in (i,j,k) means a step of (-c,-c,1-c) in (x,y,z), where // c = 1/6. float x1 = x0 - i1 + G3; // Offsets for second corner in (x,y,z) coords float y1 = y0 - j1 + G3; float z1 = z0 - k1 + G3; float x2 = x0 - i2 + 2.0f * G3; // Offsets for third corner in (x,y,z) coords float y2 = y0 - j2 + 2.0f * G3; float z2 = z0 - k2 + 2.0f * G3; float x3 = x0 - 1.0f + 3.0f * G3; // Offsets for last corner in (x,y,z) coords float y3 = y0 - 1.0f + 3.0f * G3; float z3 = z0 - 1.0f + 3.0f * G3; // Wrap the integer indices at 256, to avoid indexing perm[] out of bounds int ii = i % 256; int jj = j % 256; int kk = k % 256; // Calculate the contribution from the four corners float t0 = 0.6f - x0 * x0 - y0 * y0 - z0 * z0; if (t0 < 0.0f) n0 = 0.0f; else { t0 *= t0; n0 = t0 * t0 * grad(perm[ii + perm[jj + perm[kk]]], x0, y0, z0); } float t1 = 0.6f - x1 * x1 - y1 * y1 - z1 * z1; if (t1 < 0.0f) n1 = 0.0f; else { t1 *= t1; n1 = t1 * t1 * grad(perm[ii + i1 + perm[jj + j1 + perm[kk + k1]]], x1, y1, z1); } float t2 = 0.6f - x2 * x2 - y2 * y2 - z2 * z2; if (t2 < 0.0f) n2 = 0.0f; else { t2 *= t2; n2 = t2 * t2 * grad(perm[ii + i2 + perm[jj + j2 + perm[kk + k2]]], x2, y2, z2); } float t3 = 0.6f - x3 * x3 - y3 * y3 - z3 * z3; if (t3 < 0.0f) n3 = 0.0f; else { t3 *= t3; n3 = t3 * t3 * grad(perm[ii + 1 + perm[jj + 1 + perm[kk + 1]]], x3, y3, z3); } // Add contributions from each corner to get the final noise value. // The result is scaled to stay just inside [-1,1] return 32.0f * (n0 + n1 + n2 + n3); // TODO: The scale factor is preliminary! } private static byte[] perm = new byte[512] { 151,160,137,91,90,15, 131,13,201,95,96,53,194,233,7,225,140,36,103,30,69,142,8,99,37,240,21,10,23, 190, 6,148,247,120,234,75,0,26,197,62,94,252,219,203,117,35,11,32,57,177,33, 88,237,149,56,87,174,20,125,136,171,168, 68,175,74,165,71,134,139,48,27,166, 77,146,158,231,83,111,229,122,60,211,133,230,220,105,92,41,55,46,245,40,244, 102,143,54, 65,25,63,161, 1,216,80,73,209,76,132,187,208, 89,18,169,200,196, 135,130,116,188,159,86,164,100,109,198,173,186, 3,64,52,217,226,250,124,123, 5,202,38,147,118,126,255,82,85,212,207,206,59,227,47,16,58,17,182,189,28,42, 223,183,170,213,119,248,152, 2,44,154,163, 70,221,153,101,155,167, 43,172,9, 129,22,39,253, 19,98,108,110,79,113,224,232,178,185, 112,104,218,246,97,228, 251,34,242,193,238,210,144,12,191,179,162,241, 81,51,145,235,249,14,239,107, 49,192,214, 31,181,199,106,157,184, 84,204,176,115,121,50,45,127, 4,150,254, 138,236,205,93,222,114,67,29,24,72,243,141,128,195,78,66,215,61,156,180, 151,160,137,91,90,15, 131,13,201,95,96,53,194,233,7,225,140,36,103,30,69,142,8,99,37,240,21,10,23, 190, 6,148,247,120,234,75,0,26,197,62,94,252,219,203,117,35,11,32,57,177,33, 88,237,149,56,87,174,20,125,136,171,168, 68,175,74,165,71,134,139,48,27,166, 77,146,158,231,83,111,229,122,60,211,133,230,220,105,92,41,55,46,245,40,244, 102,143,54, 65,25,63,161, 1,216,80,73,209,76,132,187,208, 89,18,169,200,196, 135,130,116,188,159,86,164,100,109,198,173,186, 3,64,52,217,226,250,124,123, 5,202,38,147,118,126,255,82,85,212,207,206,59,227,47,16,58,17,182,189,28,42, 223,183,170,213,119,248,152, 2,44,154,163, 70,221,153,101,155,167, 43,172,9, 129,22,39,253, 19,98,108,110,79,113,224,232,178,185, 112,104,218,246,97,228, 251,34,242,193,238,210,144,12,191,179,162,241, 81,51,145,235,249,14,239,107, 49,192,214, 31,181,199,106,157,184, 84,204,176,115,121,50,45,127, 4,150,254, 138,236,205,93,222,114,67,29,24,72,243,141,128,195,78,66,215,61,156,180 }; private static int FastFloor(float x) { return (x > 0) ? ((int)x) : (((int)x) - 1); } private static float grad(int hash, float x) { int h = hash & 15; float grad = 1.0f + (h & 7); // Gradient value 1.0, 2.0, ..., 8.0 if ((h & 8) != 0) grad = -grad; // Set a random sign for the gradient return (grad * x); // Multiply the gradient with the distance } private static float grad(int hash, float x, float y) { int h = hash & 7; // Convert low 3 bits of hash code float u = h < 4 ? x : y; // into 8 simple gradient directions, float v = h < 4 ? y : x; // and compute the dot product with (x,y). return ((h & 1) != 0 ? -u : u) + ((h & 2) != 0 ? -2.0f * v : 2.0f * v); } private static float grad(int hash, float x, float y, float z) { int h = hash & 15; // Convert low 4 bits of hash code into 12 simple float u = h < 8 ? x : y; // gradient directions, and compute dot product. float v = h < 4 ? y : h == 12 || h == 14 ? x : z; // Fix repeats at h = 12 to 15 return ((h & 1) != 0 ? -u : u) + ((h & 2) != 0 ? -v : v); } private static float grad(int hash, float x, float y, float z, float t) { int h = hash & 31; // Convert low 5 bits of hash code into 32 simple float u = h < 24 ? x : y; // gradient directions, and compute dot product. float v = h < 16 ? y : z; float w = h < 8 ? z : t; return ((h & 1) != 0 ? -u : u) + ((h & 2) != 0 ? -v : v) + ((h & 4) != 0 ? -w : w); } This Is My World Generation Code Block[,] BlocksInMap = new Block[1024, 256]; public bool IsWorldGenerated = false; Random r = new Random(); private void RunThread() { for (int BH = 0; BH <= 256; BH++) { for (int BW = 0; BW <= 1024; BW++) { Block b = new Block(); if (BH >= 192) { } BlocksInMap[BW, BH] = b; } } IsWorldGenerated = true; } public void GenWorld() { new Thread(new ThreadStart(RunThread)).Start(); } And This Is A Example Of How I Set Blocks Block b = new Block(); b.BlockType = = Block.BlockTypes.Air; This Is A Example Of How I Set Models foreach (Block b in MyWorld) { switch(b.BlockType) { case Block.BlockTypes.Dirt: b.Model = DirtModel; break; ect. } } How Would I Use These To Generate To World (The Block Array) And If Possible Thread It More? btw It's 1024 Wide And 256 Tall

  Read the article

• Should you create a class within a method?

  - by Amndeep7

  I have made a program using Java that is an implementation of this project: http://nifty.stanford.edu/2009/stone-random-art/sml/index.html. Essentially, you create a mathematical expression and, using the pixel coordinate as input, make a picture. After I initially implemented this in serial, I then implemented it in parallel due to the fact that if the picture size is too large or if the mathematical expression is too complex (especially considering the fact that I made the expression recursively), it takes a really long time. During this process, I realized that I needed two classes which implemented the Runnable interface as I had to put in parameters for the run method, which you aren't allowed to do directly. One of these classes ended up being a medium sized static inner class (not large enough to make an independent class file for it though). The other though, just needed a few parameters to determine some indexes and the size of the for loop that I was making run in parallel - here it is: class DataConversionRunnable implements Runnable { int jj, kk, w; DataConversionRunnable(int column, int matrix, int wid) { jj = column; kk = matrix; w = wid; } public void run() { for(int i = 0; i < w; i++) colorvals[kk][jj][i] = (int) ((raw[kk][jj][i] + 1.0) * 255 / 2.0); increaseCounter(); } } My question is should I make it a static inner class or can I just create it in a method? What is the general programming convention followed in this case?

  Read the article

• how to use iterator in c++?

  - by tsubasa

  I'm trying to calculate distance between 2 points. The 2 points I stored in a vector in c++: (0,0) and (1,1). I'm supposed to get results as 0 1.4 1.4 0 but the actual result that I got is 0 1 -1 0 I think there's something wrong with the way I use iterator in vector. Could somebody help? I posted the code below. typedef struct point { float x; float y; } point; float distance(point *p1, point *p2) { return sqrt((p1->x - p2->x)*(p1->x - p2->x) + (p1->y - p2->y)*(p1->y - p2->y)); } int main() { vector <point> po; point p1; p1.x=0; p1.y=0; point p2; p2.x=1; p2.y=1; po.push_back(p1); po.push_back(p2); vector <point>::iterator ii; vector <point>::iterator jj; for (ii=po.begin(); ii!=po.end(); ii++) { for (jj=po.begin(); jj!=po.end(); jj++) { cout<<distance(ii,jj)<<" "; } } return 0; }

  Read the article

• Radar chart color inner circles

  - by JJ

  Hello, Is it possible to color the inner circles of a radar chart. I want to color each section differently The image below should clarify: Wanted radar chart Thanks in advance! Kind Regards, JJ

  Read the article

• Open Cl.I just need to convert the code to using two work items in the for loop .Currentlly it uses one

  - by user1660282

  spmv_csr_scalar_kernel(const int num_rows , const int * ptr , const int * indices , const float * data , const float * x, float * y) { int row = get_global_id(0); if(row < num_rows) { float dot = 0; int row_start = ptr[row]; int row_end = ptr[row+1]; for (int jj = row_start; jj < row_end; jj++) { dot += data[jj] * x[indices[jj]]; } y[row] += dot; } } Above is the Open Cl code for multiplying a sparse matrix in CSR format with a Column vector.It uses one global work item per for loop.Can anybody help me in using two work items in each for loop.I am new to open cl and get a lot of issues if I modify even the smallest thing.Please help me.This a part of my project.I made it this parallel but I wanna make it more parallel.Please help me if you can.plzzzz A single work item executes the for loop from row_start to row_end.I want that this row or for loop is further divided into two parts each executed by a single work item.How do I go on accomplishing that? This is what I could come up with but its returning the wrong output.plzz help __kernel void mykernel(__global int* colvector,__global int* val,__global int* result,__global int* index,__global int* rowptr,__global int* sync) { __global int vals[8]={0,0,0,0,0,0,0,0}; for(int i=0;i<4;i++) { result[i]=0; } barrier(CLK_GLOBAL_MEM_FENCE); int thread_id=get_global_id(0); int warp_id=thread_id/2; int lane=(thread_id)&1; int row=warp_id; if(row<4) { int row_start = rowptr[row]; int row_end = rowptr[row+1]; vals[thread_id]=0; for (int i = row_start+lane; i<row_end; i+=2) { vals[thread_id]+=val[i]*colvector[index[i]]; } vals[thread_id]+=vals[thread_id+1]; if(lane==0){ result[row] += vals[thread_id]; } } }

  Read the article

• jquery dynatree class methods

  - by Jj Zhang

  I'm a new user of dynatree plugin. When I read the documentation, I found the list of tree and node class member functions, such as tree.getRoot(), node.countChildren(). However, when I tried to use them, it complained that no such methods were found. Here is a sample code I am testing with: var tree = ("#test").dynatree(treeData); var rootNode = tree.getRoot(); //not working var rootNode2 = ("#test").dynatree("getRoot"); //this works var numChildren = rootNode2.countChildren(); //not working Help please. Thanks. -JJ

  Read the article

• Rotate two dimensional array 90 degrees clockwise

  - by user69514

  I have a two dimensional array that I need to rotate 90 degrees clockwise, however I keep getting arrayindexoutofbounds... public int[][] rorateArray(int[][] arr){ //first change the dimensions vertical length for horizontal length //and viceversa int[][] newArray = new int[arr[0].length][arr.length]; //invert values 90 degrees clockwise by starting from button of //array to top and from left to right int ii = 0; int jj = 0; for(int i=0; i<arr[0].length; i++){ for(int j=arr.length-1; j>=0; j--){ newArray[ii][jj] = arr[i][j]; jj++; } ii++; } return newArray; }

  Read the article

• Rotate array clockwise

  - by user69514

  I have a two dimensional array that I need to rotate 90 degrees clockwise, however I keep getting arrayindexoutofbounds... public int[][] rorateArray(int[][] arr){ //first change the dimensions vertical length for horizontal length //and viceversa int[][] newArray = new int[arr[0].length][arr.length]; //invert values 90 degrees clockwise by starting from button of //array to top and from left to right int ii = 0; int jj = 0; for(int i=0; i<arr[0].length; i++){ for(int j=arr.length-1; j>=0; j--){ newArray[ii][jj] = arr[i][j]; jj++; } ii++; } return newArray; }

  Read the article

• why it throws java.lang.classCastException

  - by matin1234

  Hi this is my class and I want to sort my stack but it will throw an exception please help me thanks! public class jj { public static void main(String[] args){ Stack<Integer> s = new ImplimentingAStackUsingAnArrayOfAGivenSizeN(5); s.push(1); s.push(3); s.push(5); s.push(2); s.push(4); Collections.sort((List<Integer>) (s)); System.out.println(s); while (!s.isEmpty()) { System.out.println(s.pop()); } } } the stack traces: run: Exception in thread "main" java.lang.ClassCastException: datastructurechapter5.ImplimentingAStackUsingAnArrayOfAGivenSizeN cannot be cast to java.util.List at datastructurechapter5.jj.main(jj.java:24) `Collections.sort((List<Integer>) (s));` Java Result: 1 BUILD SUCCESSFUL (total time: 2 seconds)

  Read the article

• PHP MYSQL FPDF retrieving pdf string stored as blob.

  - by jj.amonit

  Using the above technologies, I want to create a PDF, store it in my db, and email it. All with the click of one button. I also want to call it up and have it be able to display with a hyperlink. I am very new to FPDF. Therefore, I am trying to start off very slowly. I began with this link stackoverflow Q I put both parts of his code into the same page and tried with separate pages. I made the suggested changes/additions and even did a line by line comparison. I still get the message, "format error: not a PDF or corrupted" If I just $pdf-Output(); I get the pdf to display. It's either the way the string is being Output, or it's the header() function. It's not the storage method, unless my column setup is incorrect. BUt a blob is a blob, right? If you want, I can upload the sanitized code. Just let me know what would help answer this. Thanks JJ

  Read the article

• how to redirect terminal contents to a jtextpane?

  - by sonu thomas

  hi.. I was trying to run a java class file using java code.The aim was to direct the executing sequence of the terminal of fedora 10 into a frame with a textpane. My code is: import java.io.DataInputStream; import java.io.IOException; import javax.swing.JDialog; import javax.swing.JFrame; import javax.swing.JOptionPane; import javax.swing.JPanel; import javax.swing.JTextArea; import javax.swing.JTextPane; //import sun.reflect.ReflectionFactory.GetReflectionFactoryAction; public class file { /** * @param args */ /** * @param args * @throws IOException */ public static void main(String[] args) throws IOException{ // TODO Auto-generated method stub JDialog jj = new JDialog(); jj.setTitle("helllo"); String sssub1,sssub2,sssub3; String ss="C:/Users/sonu/Desktop/ourIDE/src/src/nn.java"; JPanel n = new JPanel(); jj.setContentPane(n); JTextPane tpn2=new JTextPane(); jj.getContentPane().add(tpn2); jj.setVisible(true); Runtime runtime; Process process; if(ss.indexOf(" ")==-1) { try { runtime= Runtime.getRuntime(); sssub1="/home/ss/Desktop/src/"; sssub2="nn"; process=runtime.exec("sh jrun.sh "+sssub1+" "+sssub2); DataInputStream data=new DataInputStream(process.getInputStream()); DataInputStream data_data=new DataInputStream(process.getErrorStream()); String s="",t=""; int ch; while((ch=data.read())!=-1){ s=s+(char)ch; } data.close(); while((ch=data_data.read())!=-1){ t=t+(char)ch; } data_data.close(); if(t.equals("")) { s+="\nNormal Termination."; tpn2.setText(s); } else tpn2.setText(t); }catch(Exception e){ System.out.println("Error executing file==>"+e);} } } } The content of **jrun.sh** is cd $1 java $2 When the content of **nn.java** was this: import java.io.*; class nn { public static void main(String[] ar)throws IOException { int i=90; BufferedReader dt = new BufferedReader(new InputStreamReader(System.in)); System.out.println("Enter"); //i=Integer.parseInt(dt.readLine()); line--notable System.out.println("i="+i); } } It worked smoothly But when I remove the comment on line--notable,it gave me Textpane with no content. The problem is : I cant read an input from nn.java Kindly give me a solution... If i am able to: get the terminal pop up with executing the nn.class,and i am able to enter the input,then it will do... Thanks in advance...

  Read the article

• trying to center a css menu made on purecssmenu.com

  - by Party Mcfly

  i have a menu that i generated on purecssmenu.com and im having trouble trying to center it on my page here is the code... <!-- Start PureCSSMenu.com STYLE --> <style> #pcm{display:none;} ul.pureCssMenu ul{display:none} ul.pureCssMenu li:hover>ul{display:block} ul.pureCssMenu ul{position: absolute;left:-1px;top:98%;} ul.pureCssMenu ul ul{position: absolute;left:98%;top:-2px;} ul.pureCssMenu,ul.pureCssMenu ul { margin:0px; list-style:none; padding:0px 2px 2px 0px; background-color:#000000; background-repeat:repeat; border-color:#000000; border-width:1px; border-style:solid; } ul.pureCssMenu table {border-collapse:collapse}ul.pureCssMenu { display:block; zoom:1; float: left; } ul.pureCssMenu ul{ width:80.85000000000001px; } ul.pureCssMenu li{ display:block; margin:2px 0px 0px 2px; font-size:0px; } ul.pureCssMenu a:active, ul.pureCssMenu a:focus { outline-style:none; } ul.pureCssMenu a, ul.pureCssMenu li.dis a:hover, ul.pureCssMenu li.sep a:hover { display:block; vertical-align:middle; background-color:#000000; border-width:1px; border-color:#000000; border-style:solid; text-align:left; text-decoration:none; padding:2px 5px 2px 10px; _padding-left:0; font:11px Arial; color: #969696; text-decoration:none; cursor:default; } ul.pureCssMenu span{ overflow:hidden; } ul.pureCssMenu li { float:left; } ul.pureCssMenu ul li { float:none; } ul.pureCssMenu ul a { text-align:left; white-space:nowrap; } ul.pureCssMenu li.sep{ text-align:left; padding:0px; line-height:0; height:100%; } ul.pureCssMenu li.sep span{ float:none; padding-right:0; width:3px; height:100%; display:inline-block; background-color:#cccccc #111111 #111111 #cccccc; background-image:none;} ul.pureCssMenu ul li.sep span{ width:100%; height:3px; } ul.pureCssMenu li:hover{ position:relative; } ul.pureCssMenu li:hover>a{ background-color:#000000; border-color:#000000; border-style:solid; font:11px Arial; color: #ffa500; text-decoration:none; } ul.pureCssMenu li a:hover{ position:relative; background-color:#000000; border-color:#000000; border-style:solid; font:11px Arial; color: #ffa500; text-decoration:none; } ul.pureCssMenu li.dis a { color: #666 !important; } ul.pureCssMenu img {border: none;float:left;_float:none;margin-right:2px;width:16px; height:16px; } ul.pureCssMenu ul img {width:16px; height:16px; } ul.pureCssMenu img.over{display:none} ul.pureCssMenu li.dis a:hover img.over{display:none !important} ul.pureCssMenu li.dis a:hover img.def {display:inline !important} ul.pureCssMenu li:hover > a img.def {display:none} ul.pureCssMenu li:hover > a img.over {display:inline} ul.pureCssMenu a:hover img.over,ul.pureCssMenu a:hover ul img.def,ul.pureCssMenu a:hover a:hover img.over{display:inline} ul.pureCssMenu a:hover img.def,ul.pureCssMenu a:hover ul img.over,ul.pureCssMenu a:hover a:hover img.def{display:none} ul.pureCssMenu a:hover ul{display:block} ul.pureCssMenu span{ display:block; background-image:url(./images/arr_white.gif); background-position:right center; background-repeat: no-repeat; padding-right:12px;} ul.pureCssMenu li:hover>a>span{ background-image:url(./images/arrv_white.gif); } ul.pureCssMenu a:hover span{ _background-image:url(./images/arrv_white.gif)} ul.pureCssMenu ul span,ul.pureCssMenu a:hover table span{background-image:url(./images/arr_white.gif)} </style> <!-- End PureCSSMenu.com STYLE --> and here is the html, witch is probably not even needed in this posted but i figure i would include it.. i just want that menu centered inside my website. <!-- Start PureCSSMenu.com MENU --> <ul class="pureCssMenu pureCssMenum"> <li class="pureCssMenui"><a class="pureCssMenui" href="home.html" target="scare">home</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">about</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#"><span>haunts</span><![if gt IE 6]></a><![endif]><!--[if lte IE 6]><table><tr><td><![endif]--> <ul class="pureCssMenum"> <li class="pureCssMenui"><a class="pureCssMenui" href="#">2009</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">2010</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">2011</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">2012</a></li> </ul> <!--[if lte IE 6]></td></tr></table></a><![endif]--></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">studio</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#"><span>products</span><![if gt IE 6]></a><![endif]><!--[if lte IE 6]><table><tr><td><![endif]--> <ul class="pureCssMenum"> <li class="pureCssMenui"><a class="pureCssMenui" href="#">nightmares</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">hauntworks</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">atmosfears</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">frightwears</a></li> </ul> <!--[if lte IE 6]></td></tr></table></a><![endif]--></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#"><span>links</span><![if gt IE 6]></a><![endif]><!--[if lte IE 6]><table><tr><td><![endif]--> <ul class="pureCssMenum"> <li class="pureCssMenui"><a class="pureCssMenui" href="#">haunts</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">suppliers</a></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">resources</a></li> </ul> <!--[if lte IE 6]></td></tr></table></a><![endif]--></li> <li class="pureCssMenui"><a class="pureCssMenui" href="#">contact</a></li> </ul> <a id="pcm" href="http://www.purecssmenu.com/">CSS Drop Down Menu by PureCSSMenu.com</a> <!-- End PureCSSMenu.com MENU --> thanks in advance for your time.

  Read the article

• See former key sequences in vim

  - by Vasiliy Sharapov

  Sometimes I share screen shots and clips of vim usage with others. It would be nice to expand on the part of the status bar highlighted in this picture: I would like some way to make previous key sequences visible as well, such as: y2w jj f[ p 2d - You can see the key sequences leading up to the current one. I'll elaborate on my wish list at the bottom. Is something like this is available as a plugin or vim script? The sheer number of scripts available on vim online makes this hard to find by keyword. Some features I would hope for (but seem improbable): Delimit key sequences with a non-keyboard character instead of space, and a different one for the current command, so y2w jj f[ p 2d might become y2w¦jj¦f[¦p » 2d Replace keys that have a letter alternative with the alternative, such as the right arrow key - ^[[C with the equivalent l. Edit: To clarify, the right arrow key is a valid key in vim, but has no character to represent it, the l key preforms the same function and could/should substitute it. Have previous keystrokes run all the way to the beginning of the line (instead of just one or two), and just have vim's command prompt overwrite it when necessary. Replace some keystrokes with a more elegant alternative, for example hhhhh with 5h or more impressively d2f) with d% (in the appropriate situation).

  Read the article

• Const operator overloading problems in C++

  - by steigers

  Hello everybody, I'm having trouble with overloading operator() with a const version: #include <iostream> #include <vector> using namespace std; class Matrix { public: Matrix(int m, int n) { vector<double> tmp(m, 0.0); data.resize(n, tmp); } ~Matrix() { } const double & operator()(int ii, int jj) const { cout << " - const-version was called - "; return data[ii][jj]; } double & operator()(int ii, int jj) { cout << " - NONconst-version was called - "; if (ii!=1) { throw "Error: you may only alter the first row of the matrix."; } return data[ii][jj]; } protected: vector< vector<double> > data; }; int main() { try { Matrix A(10,10); A(1,1) = 8.8; cout << "A(1,1)=" << A(1,1) << endl; cout << "A(2,2)=" << A(2,2) << endl; double tmp = A(3,3); } catch (const char* c) { cout << c << endl; } } This gives me the following output: NONconst-version was called - - NONconst-version was called - A(1,1)=8.8 NONconst-version was called - Error: you may only alter the first row of the matrix. How can I achieve that C++ call the const-version of operator()? I am using GCC 4.4.0. Thanks for your help! Sebastian

  Read the article

• SQL 2005 AD Group permission levels

  - by jj.

  I'm trying to give permissions to a (sql 2005) database app based on AD groups. The general idea is to require a user to have a membership to "app_users" to view anything, and membership to other groups gives them write access to that group. "app_customers" gives write access to the customers module, "app_sales" to sales, etc. I've listed an example below: user1: AD member of app_users user2: AD member of app_users, app_customers For dbo.customers table: app_users - Granted: Select permission - Denied: Insert, Update, Delete app_customers - Granted: Select permission - Granted: Insert, Update, Delete I would expect user1 to be able to view the dbo.customers table, but will not be allowed to modify anything (insert/update/delete) - which works. In the same vein, I would expect user2 to be able to view AND modify the dbo.customers table, since they are a member of app_customers. However, this is not the case. Instead, user2 is denied any modifications just like user1. I seem to remember something about deny permissions winning if there was a conflict, but it's honestly been too long since I've dealt with them. Am I going about this the right way? Thanks for your time!

  Read the article

• Exchange 2010 SP2 Not Allowing Logon for Users with Expired Passwords

  - by JJ.

  When we provision users we set the "User must change password at next logon" flag and instruct them to go to OWA to login for the first time and change their password. Using the registry setting ChangeExpiredPasswordEnabled as explained here: http://technet.microsoft.com/en-us/library/bb684904.aspx worked well prior to SP2 installation. This allows users with 'expired' passwords to logon and forces a password change before they can access OWA. We just installed Exchange 2010 Service Pack 2 and now it's no longer working. Users with this flag set ('expired' passwords) can't login in at all unless we clear the flag. FYI here's the registry key configuration as set now with SP2 installed: Any suggestions as to how I might fix this? Or did MS break this feature in Service Pack 2?

  Read the article

• What are the Best Practices and tools for managing Windows Desktops from a linux sever ?

  - by JJ

  I know this is a loaded question! What are the best ways to manage Windows (2000, XP, Vista, Win7) workstation from a centralized linux server. I would like to replace the fuctionaility of MS SBS Server with a linux box. The following issues would need to be addressed. File Sharing Authentication, Authorization, and Access Control Software Installation Centralized Login Script Centralized Backup

  Read the article

1 2 3 4  | Next Page >