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  • "Deep Fried Bytes Podcast": Lars on SQL Server Modeling

    Here's how the Deep Fried guys describe episode 45: "At PDC 2009, 'Oslo' was renamed to SQL Modeling and it left a lot of developers scratching their heads. What better way to sort it all out than to talk with someone deep into the stack. We sat down with Lars Corneliussen to see how this is all going to turn out and it what it means for developers. Definitely an interesting show as it paints a different picture about where things are going with 'M', 'M' Grammar, SQL modeling, Entity Framework, Quadrant...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • "Deep Fried Bytes Podcast": Lars on SQL Server Modeling

    Here's how the Deep Fried guys describe episode 45: "At PDC 2009, 'Oslo' was renamed to SQL Modeling and it left a lot of developers scratching their heads. What better way to sort it all out than to talk with someone deep into the stack. We sat down with Lars Corneliussen to see how this is all going to turn out and it what it means for developers. Definitely an interesting show as it paints a different picture about where things are going with 'M', 'M' Grammar, SQL modeling, Entity Framework, Quadrant...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • the carry flag issue!

    - by Zia ur Rahman
    Suppose AX =FFFE and BX=1234 now if we write cmp ax,bx (bx will be subtracted from ax and the approprite flages will be updated) now the binary representation of the numbers in ax and bx is given by AX = 1111 1111 1111 1110 BX= 0001 0010 0011 0100 As bx will be subtracted from ax so we have to negate bx (as Result= ax+(-bx)) so the negated bx (2's complement of bx ) is given by. BX= 1110 1101 1100 1100 Now we add both ax and bx (as subtraction is implemented by addition in computer) AX= 1111 1111 1111 1110 BX= 1110 1101 1100 1100 ------------------------------------ 1 1110 1101 1100 1010 Now as you can see the result is of 17 bits now the 17th bit should go into carry flage, but when i checked it the carry flag is 0 that is CF=0 why?

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  • Assembly Language bug with space character

    - by Bobby
    Having a bit of difficulty getting my input to print once a white space character is inputted. So far, i have it to display the uppercase/lowercase of the input but once i enter a string it doesnt read whats after the white space character. any suggestions? EDIT: intel x86 processor and im using EMU8086 org 100h include 'emu8086.inc' printn "Enter string to convert" mov dx,20 call get_string printn mov bx,di mov ah,0eh mov al,[ds+bx] cmp al, 41h cmp al, 5Ah jle ToLower1 cmp al, 61h cmp al, 7ah jle ToUpper1 ToLower1: add al, 20h int 10h jmp stop1 ToUpper1: sub al, 20h int 10h stop1: inc bx mov al,[ds+bx] cmp al, 41h cmp al, 5Ah jle ToLower2 cmp al, 61h cmp al, 7ah jle ToUpper2 ToLower2: add al, 20h int 10h jmp stop2 ToUpper2: sub al, 20h int 10h stop2: inc bx mov al,[ds+bx] cmp al, 41h cmp al, 5Ah jle ToLower3 cmp al, 61h cmp al, 7ah jle ToUpper3 ToLower3: add al, 20h int 10h jmp stop3 ToUpper3: sub al, 20h int 10h stop3: inc bx mov al,[ds+bx] cmp al, 41h cmp al, 5Ah jle ToLower4 cmp al, 61h cmp al, 7ah jle ToUpper4 ToLower4: add al, 20h int 10h jmp stop4 ToUpper4: sub al, 20h int 10h stop4: inc bx mov al,[ds+bx] cmp al, 41h cmp al, 5Ah jle ToLower5 cmp al, 61h cmp al, 7ah jle ToUpper5 ToLower5: add al, 20h int 10h jmp stop5 ToUpper5: sub al, 20h int 10h stop5: printn hlt define_get_string define_print_string end

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  • En direct des Qt DevDays 2012 : keynote de Lars Knoll sur les objectifs du Qt Project et Qt 5

    Bonjour à tous, Actuellement, je suis à Berlin, au Cafe Moskau pour assister aux Qt DevDays 2012. Comme chaque année, la première journée est réservée aux formations. J'assiste à la formation appelée "Modern OpenGL with Qt5" réalisée par Sean Harmer de KDAB. Nous avons passé les deux heures de la matinée à voir la création et l'initialisation d'une fenêtre OpenGL dans Qt 5 (il y a quelques changements mineurs par rapport à Qt 4) et l'affichage d'un joli triangle en OpenGL moderne.

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  • How to setup nginx and a subdomain

    - by Evolutio
    i have gitlab installed on my server and it works on all domains eg: git.lars-dev.de, lars-dev.de and *.lars-dev.de how I can run gitlab only on git.lars-dev.de and another subdomain on files.lars-dev.de? my lars-dev conf: server { listen *:80; ## listen for ipv4; this line is default and implied #listen [::]:80 default_server ipv6only=on; ## listen for ipv6 root /var/www/webdata/lars-dev.de/htdocs; index index.html index.htm; server_name lars-dev.de; location / { try_files $uri $uri/ /index.html; } #error_page 500 502 503 504 /50x.html; #location = /50x.html { # root /usr/share/nginx/www; #} # deny access to .htaccess files, if Apache's document root # concurs with nginx's one # #location ~ /\.ht { # deny all; #} } and the gitlab configuration: upstream gitlab { server unix:/home/git/gitlab/tmp/sockets/gitlab.socket; } server { listen *:80; # e.g., listen 192.168.1.1:80; In most cases *:80 is a good idea server_name git.lars-dev.de; # e.g., server_name source.example.com; server_tokens off; # don't show the version number, a security best practice root /home/git/gitlab/public; # individual nginx logs for this gitlab vhost access_log /var/log/nginx/gitlab_access.log; error_log /var/log/nginx/gitlab_error.log; location / { # serve static files from defined root folder;. # @gitlab is a named location for the upstream fallback, see below try_files $uri $uri/index.html $uri.html @gitlab; } # if a file, which is not found in the root folder is requested, # then the proxy pass the request to the upsteam (gitlab unicorn) location @gitlab { proxy_read_timeout 300; # https://github.com/gitlabhq/gitlabhq/issues/694 proxy_connect_timeout 300; # https://github.com/gitlabhq/gitlabhq/issues/694 proxy_redirect off; proxy_set_header X-Forwarded-Proto $scheme; proxy_set_header Host $http_host; proxy_set_header X-Real-IP $remote_addr; proxy_pass http://gitlab; } }

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  • Visual Studio expression containing a term named "by" cannot be evaluated in the watch window

    - by Andrei Pana
    Consider my C++ code below: int _tmain(int argc, _TCHAR* argv[]) { int by = 10; printf("%d\n", by); int bx = 20; printf("%d\n", (by + bx)); return 0; } which works fine. The funny thing is with the "by" variable. If I try to add a watch for a simple expression that contains by, the result will be CXX0030: Error: expression cannot be evaluated. For example, on a breakpoint on return 0, if I add the following watches I get the results mentioned: by : 10 bx : 20 by + 5 : CXX0030: Error: expression cannot be evaluated bx + 5 : 25 by + bx : CXX0030: Error: expression cannot be evaluated (by) + bx : 30 by + (bx) : CXX0030: Error: expression cannot be evaluated bx + (by) : CXX0014: Error: missing operrand This happens on VS2010, VS2008 on multiple computers. So, more out of curiosity, what is happening with "by"? Is it some kind of strange operator? Why doesn't bx get the same treatment? (I've tried google on this but it is quite difficult to get some relevant hits with terms like "by")

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  • Installing 12.04 within 11.04

    - by user288752
    I recently installed 11.04 from an installation disk (overwriting Windows in the process). I know 11.04 is no longer supported but I had no problems subsequently upgrading it to 12.04 (via 11.10) a couple of months ago on another device. This time though, things are different. I can't upgrade through update manager because Ubuntu then tells me I have no internet connection, which is (obviously incorrect). I have tried to circumvent the problem by downloading the 12:04 iso from ubuntu.com directly but now I'm troubled by something else. The download is succesfull but after mounting the iso I can't interact with it. When I try to access the Wubi it gives me the following message: Archive: /home/lars/.cache/.fr-7g75Fe/wubi.exe [/home/lars/.cache/.fr-7g75Fe/wubi.exe] End-of-central-directory signature not found. Either this file is not a zipfile, or it constitutes one disk of a multi-part archive. In the latter case the central directory and zipfile comment will be found on the last disk(s) of this archive. zipinfo: cannot find zipfile directory in one of /home/lars/.cache/.fr-7g75Fe/wubi.exe or /home/lars/.cache/.fr-7g75Fe/wubi.exe.zip, and cannot find /home/lars/.cache/.fr-7g75Fe/wubi.exe.ZIP, period. What am I doing wrong here?

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  • What is required to use LODSB in assembly?

    - by Harvey
    What is the minimum set of steps required to use LODSB to load a relative address to a string in my code? I have the following test program that I'm using PXE to boot. I boot it two ways: via pxelinux.0 and directly. If I boot it directly, my program prints both strings. If I boot via pxelinux.0, it only prints the first string. Why? Working technique (for both): Set the direction flag to increment, cld Set ds to cs Put the address (from start) of string in si Add the starting offset to si Non-working technique (just for pxelinux): Calculate a new segment address based on (((cs << 4) + offset) >> 4) Set ds to that. (either A000 or 07C0) text here to fix bug in markdown // Note: If you try this code, don't forget to set // the "#if 0" below appropriately! .text .globl start, _start start: _start: _start1: .code16 jmp real_start . = _start1 + 0x1fe .byte 0x55, 0xAA // Next sector . = _start1 + 0x200 jmp real_start test1_str: .asciz "\r\nTest: 9020:fe00" test2_str: .asciz "\r\nTest: a000:0000" real_start: cld // Make sure %si gets incremented. #if 0 // When loaded by pxelinux, we're here: // 9020:fe00 ==> a000:0000 // This works. movw $0x9020, %bx movw %bx, %ds movw $(test1_str - _start1), %si addw $0xfe00, %si call print_message // This does not. movw $0xA000, %bx movw %bx, %ds movw $(test2_str - _start1), %si call print_message #else // If we are loaded directly without pxelinux, we're here: // 0000:7c00 ==> 07c0:0000 // This works. movw $0x0000, %bx movw %bx, %ds movw $(test1_str - _start1), %si addw $0x7c00, %si call print_message // This does, too. movw $0x07c0, %bx movw %bx, %ds movw $(test2_str - _start1), %si call print_message #endif // Hang the computer sti 1: jmp 1b // Prints string DS:SI (modifies AX BX SI) print_message: pushw %ax jmp 2f 3: movb $0x0e, %ah /* print char in AL */ int $0x10 /* via TTY mode */ 2: lodsb (%si), %al /* get token */ cmpb $0, %al /* end of string? */ jne 3b popw %ax ret .balign 0x200 Here's the compilation: /usr/bin/ccache gcc -Os -fno-stack-protector -fno-builtin -nostdinc -DSUPPORT_SERIAL=1 -DSUPPORT_HERCULES=1 -DSUPPORT_GRAPHICS=1 -DHAVE_CONFIG_H -I. -Wall -ggdb3 -Wmissing-prototypes -Wunused -Wshadow -Wpointer-arith -falign-jumps=1 -falign-loops=1 -falign-functions=1 -Wundef -g -c -o ds_teststart_exec-ds_teststart.o ds_test.S /usr/bin/ccache gcc -g -o ds_teststart.exec -nostdlib -Wl,-N -Wl,-Ttext -Wl,8000 ds_teststart_exec-ds_teststart.o objcopy -O binary ds_teststart.exec ds_teststart

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  • lost the vertical scroll function in touchpad after upgrading from 13.04 to 13.10

    - by Lars Lundblad
    just upgraded from Ubuntu 13.04 to Ubuntu 13.10, my Laptop is a Sony SVE1512c6ew, scrolling worked perfectly in Ubuntu 13.04, doesnt work at all in 13.10 Runs Ubuntu 13.10 64bits (btw, tested it i Windows 8 environment works there)Hardware OK, have seen a number of other users with the same problem, well for starters have followed the tip on using the dconf editor, following the path: org gnome settings-daemon peripherals touchpad boxed in all for sure... still cant get vertical scroll...... Any ideas??? Thanks in advance Lars Lundblad / please feel free to mail answers to [email protected] Input device information according to Udev: Input device Subsystem: input Devtype: n/a Name: input7 Number: 7 Sysfs_path: /sys/devices/platform/i8042/serio1/input/input7 Driver: n/a Action: n/a Seqnum: n/a Device type: n/a Device number: 0 Device file: n/a Device file symlinks: n/a Touchpad device Subsystem: input Devtype: n/a Name: mouse1 Number: 1 Sysfs_path: /sys/devices/platform/i8042/serio1/input/input7/mouse1 Driver: n/a Action: n/a Seqnum: n/a Device type: char Device number: 3361 Device file: /dev/input/mouse1 Device file symlinks: /dev/input/by-path/platform-i8042-serio-1-mouse

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  • Linq Query Performance , comparing Compiled query vs Non-Compiled.

    - by AG.
    Hello Guys, I was wondering if i extract the common where clause query into a common expression would it make my query much faster, if i have say something like 10 linq queries on a collection with exact same 1st part of the where clause. I have done a small example to explain a bit more . public class Person { public string First { get; set; } public string Last { get; set; } public int Age { get; set; } public String Born { get; set; } public string Living { get; set; } } public sealed class PersonDetails : List<Person> { } PersonDetails d = new PersonDetails(); d.Add(new Person() {Age = 29, Born = "Timbuk Tu", First = "Joe", Last = "Bloggs", Living = "London"}); d.Add(new Person() { Age = 29, Born = "Timbuk Tu", First = "Foo", Last = "Bar", Living = "NewYork" }); Expression<Func<Person, bool>> exp = (a) => a.Age == 29; Func<Person, bool> commonQuery = exp.Compile(); var lx = from y in d where commonQuery.Invoke(y) && y.Living == "London" select y; var bx = from y in d where y.Age == 29 && y.Living == "NewYork" select y; Console.WriteLine("All Details {0}, {1}, {2}, {3}, {4}", lx.Single().Age, lx.Single().First , lx.Single().Last, lx.Single().Living, lx.Single().Born ); Console.WriteLine("All Details {0}, {1}, {2}, {3}, {4}", bx.Single().Age, bx.Single().First, bx.Single().Last, bx.Single().Living, bx.Single().Born); So can some of the guru's here give me some advice if it would be a good practice to write query like var lx = "Linq Expression " or var bx = "Linq Expression" ? Any inputs would be highly appreciated. Thanks, AG

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  • Problem with stack based implementation of function 0x42 of int 0x13

    - by IceCoder
    I'm trying a new approach to int 0x13 (just to learn more about the way the system works): using stack to create a DAP.. Assuming that DL contains the disk number, AX contains the address of the bootable entry in PT, DS is updated to the right segment and the stack is correctly set, this is the code: push DWORD 0x00000000 add ax, 0x0008 mov si, ax push DWORD [ds:(si)] push DWORD 0x00007c00 push WORD 0x0001 push WORD 0x0010 push ss pop ds mov si, sp mov sp, bp mov ah, 0x42 int 0x13 As you can see: I push the dap structure onto the stack, update DS:SI in order to point to it, DL is already set, then set AX to 0x42 and call int 0x13 the result is error 0x01 in AH and obviously CF set. No sectors are transferred. I checked the stack trace endlessly and it is ok, the partition table is ok too.. I cannot figure out what I'm missing... This is the stack trace portion of the disk address packet: 0x000079ea: 10 00 adc %al,(%bx,%si) 0x000079ec: 01 00 add %ax,(%bx,%si) 0x000079ee: 00 7c 00 add %bh,0x0(%si) 0x000079f1: 00 00 add %al,(%bx,%si) 0x000079f3: 08 00 or %al,(%bx,%si) 0x000079f5: 00 00 add %al,(%bx,%si) 0x000079f7: 00 00 add %al,(%bx,%si) 0x000079f9: 00 a0 07 be add %ah,-0x41f9(%bx,%si) I'm using qemu latest version and trying to read from hard drive (0x80), have also tried with a 4bytes alignment for the structure with the same result (CF 1 AH 0x01), the extensions are present.

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  • invalid effective address calculation!

    - by Zia ur Rahman
    Hay Dear! Please look at the following program, the error is invalid effective address calculation and i have mentioned that line please tell me why its invalid effective address calculation here is the program [org 0x100] jmp start array1: dw 10,15,20,25,30,35,40,45,50,55 array2: dw 15,10,20,35,40,30,55,50,25,45 start: mov bx,0 mov dx,0 loop: mov ax,[array2+bx] cmp ax,[array1+cx]//here is the error invalid effective address calculation jne NextElementOfArray1 NextElementOfArray2: add bx,2 cmp bx,20 je end mov cx,0 jmp loop NextElementOfArray1: add cx,2 cmp cx,20 je NextElementOfArray2 jmp loop end: mov ax,0x4c00 int 0x21

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  • USB To Serial under OpenSuse 11.3

    - by Lars
    I have a LogiLink USB-To-Serial adapter. This has the PL2303 chip inside. When I insert the device: [26064.927083] usb 7-1: new full speed USB device using uhci_hcd and address 9 [26065.076090] usb 7-1: New USB device found, idVendor=067b, idProduct=2303 [26065.076099] usb 7-1: New USB device strings: Mfr=1, Product=2, SerialNumber=0 [26065.076105] usb 7-1: Product: USB-Serial Controller [26065.076110] usb 7-1: Manufacturer: Prolific Technology Inc. [26065.079181] pl2303 7-1:1.0: pl2303 converter detected [26065.091296] usb 7-1: pl2303 converter now attached to ttyUSB0 So the device is recognized and the converter is attached to ttyUSB0. When I do screen /dev/ttyUSB0 9600 I get the error: bash: /dev/ttyUSB0: Permission denied So I went looking in the file permissions. ls -l from the /dev folder reports: crw-rw---- 1 root dialout 188, 0 2011-04-26 15:47 ttyUSB0 I added my user lars to the dialout group. When I use the commands groups under lars it shows that I'm in the group. Though I still recieve the permissions denied error, as lars, and as root. I'm trying to connect to a console cable to configure some Cisco switches. My OS is OpenSuse 11.3 x86_64 with kernel version 2.6.34.7-0.7-desktop.

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  • Getting at fsid under Linux? Or an alternate way of identifying filesystems?

    - by larsks
    In an environment with automounted home directories, such that the same filesystem exported by a fileserver may be mounted multiple times on the client, I would like to authoritatively be able to identify whether two mountpoints are in fact the same filesystem. That is, if the remote server exports: /home And the local client has: # mount fileserver:/home/l/lars on /home/lars type nfs (rw...) fileserver:/home/b/bob on /home/bob type nfs (rw...) I am looking for a way to identify that both /home/lars and /home/bob are in fact the same filesystem. In theory this is what the fsid result of the statvfs structure is for, but in all cases, for both local and remote filesystems, I am finding that the value of this structure member is 0. Is this some sort of client-side issue? Or do most modern NFS servers simply decline to provide a useful fsid? The end goal of all of this is to robustly interpret the output from the quota command for NFS filesystems. For example, given the example above, running quota as myself may return something like: Disk quotas for user lars (uid 6580): Filesystem blocks quota limit grace files quota limit grace otherserver:/vol/home0/a/alice 12 52428800 52428800 4 4294967295 4294967295 fileserver:/home/l/lars 9353032 9728000 10240000 124018 0 0 ...the problem here being that there exists a quota for me on otherserver which is visible in the results of the quota command, even though my home directory is actually on a different device. My plan was to look up the fsid for each mountpoint listed in the quota output and check to see if it matched the fsid associated with my home directory. It looks like this won't work, so...any suggestions?

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  • Help finding time of collision

    - by WannaBe
    I am making a simple game right now and am struggling with collision response. My goal is to someday be able to turn it into a 2D platformer but I have a long way to go. I am currently making this in JavaScript and using the canvas element so (0,0) is in the top left and positive X is to the right and positive Y is down. I read a helpful post on StackExchange that got me started on this but I can't seem to get the algorithm 100% correct. How to deal with corner collisions in 2D? I can detect the collision fine but I can't seem to get the response right. The goal is to detect which side the player hit first since minimum displacement doesn't always work. The X response seems to work fine but the Y only works when I am far from the corners. Here is a picture showing what happens Here is the code var bx = box.x; var by = box.y; var bw = box.width; var bh = box.height; var boxCenterX = bx + (bw/2); var boxCenterY = by + (bh/2); var playerCenterX = player.x + player.xvel + (player.width/2); var playerCenterY = player.y + player.yvel + (player.height/2); //left = negative and right = positve, 0 = middle var distanceXin = playerCenterX - boxCenterX; var distanceYin = playerCenterY - boxCenterY; var distanceWidth = Math.abs(distanceXin); var distanceHeight = Math.abs(distanceYin); var halfWidths = (bw/2) + (player.width/2); var halfHeights = (bh/2) + (player.height/2); if(distanceWidth < halfWidths){ //xcollision if(distanceHeight < halfHeights){ //ycollision if(player.xvel == 0){ //adjust y if(distanceYin > 0){ //bottom player.y = by + bh; player.yvel = 0; }else{ player.y = by - player.height; player.yvel = 0; } }else if(player.yvel == 0){ //adjust x if(distanceXin > 0){ //right player.x = bx + bw; player.xvel = 0; }else{ //left player.x = bx - player.width; player.xvel = 0; } }else{ var yTime = distanceYin / player.yvel; var xTime = distanceXin / player.xvel; if(xTime < yTime){ //adjust the x it collided first if(distanceXin > 0){ //right player.x = bx + bw; player.xvel = 0; }else{ //left player.x = bx - player.width; player.xvel = 0; } }else{ //adjust the y it collided first if(distanceYin > 0){ //bottom player.y = by + bh; player.yvel = 0; }else{ player.y = by - player.height; player.yvel = 0; } } } } } And here is a JSFiddle if you would like to see the problem yourself. http://jsfiddle.net/dMumU/ To recreate this move the player to here And press up and left at the same time. The player will jump to the right for some reason. Any advice? I know I am close but I can't seem to get xTime and yTime to equal what I want every time.

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  • Java EE Summit December 3rd-5th Cologne, Germany

    - by JuergenKress
    16 Java EE Workshops in 3 days: Track: Java EE Core Technologies · Core – JPA 2.x - Arne Limburg · Core – EJB 3.1 und 3.2 - Jens Schumann · Core – CDI 1.0 & 1.1 - Mark Struberg · Core – JSF 2.x - Lars Röwekamp Track: Best Practices · Pitfalls in Java EE - Mark Struberg · Java EE UI - Adam Bien · Modeling meets Code - Arne Limburg · Java EE Security - Adam Bien Track: Java EE Kickstart · Kickstart – Java-EE-Architekturen - Jens Schumann · Kickstart – Java Web Profile - Lars Röwekamp · Kickstart – Events und Messaging - Thilo Frotscher · Kickstart – Services: REST und WS-* Thilo Frotscher “Do it yourself” – Workshop Day · Java EE Core – Putting together - Jens Schumann, Lars Röwekamp · Java EE Core – Putting together: Extended Edition · Java EE 6/7 – Productivity with Joy: Development - Adam Bien · Java EE 6/7 – Productivity with Joy: Testing - Adam Bien >> Night Session mit Matthias Weßendorf: · Future: New School Web Apps For more information and registration please visit www.java-ee-summit.de/zeitplaner. WebLogic Partner Community For regular information become a member in the WebLogic Partner Community please visit: http://www.oracle.com/partners/goto/wls-emea ( OPN account required). If you need support with your account please contact the Oracle Partner Business Center. BlogTwitterLinkedInMixForumWiki Technorati Tags: Java EE,Adam Bien,Java EE Summit,WebLogic Community,Oracle,OPN,Jürgen Kress

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  • Per Pixel Collision Detection

    - by CJ Cohorst
    Just a quick question, I have this collision detection code: public bool PerPixelCollision(Player player, Game1 dog) { Matrix atob = player.Transform * Matrix.Invert(dog.Transform); Vector2 stepX = Vector2.TransformNormal(Vector2.UnitX, atob); Vector2 stepY = Vector2.TransformNormal(Vector2.UnitY, atob); Vector2 iBPos = Vector2.Transform(Vector2.Zero, atob); for(int deltax = 0; deltax < player.playerTexture.Width; deltax++) { Vector2 bpos = iBPos; for (int deltay = 0; deltay < player.playerTexture.Height; deltay++) { int bx = (int)bpos.X; int by = (int)bpos.Y; if (bx >= 0 && bx < dog.dogTexture.Width && by >= 0 && by < dog.dogTexture.Height) { if (player.TextureData[deltax + deltay * player.playerTexture.Width].A > 150 && dog.TextureData[bx + by * dog.Texture.Width].A > 150) { return true; } } bpos += stepY; } iBPos += stepX; } return false; } What I want to know is where to put in the code where something happens. For example, I want to put in player.playerPosition.X -= 200 just as a test, but I don't know where to put it. I tried putting it under the return true and above it, but under it, it said unreachable code, and above it nothing happened. I also tried putting it by bpos += stepY; but that didn't work either. Where do I put the code? Any help is appreciated. Thanks in advance!

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  • Where should I place my reaction code in Per-Pixel Collision Detection?

    - by CJ Cohorst
    I have this collision detection code: public bool PerPixelCollision(Player player, Game1 dog) { Matrix atob = player.Transform * Matrix.Invert(dog.Transform); Vector2 stepX = Vector2.TransformNormal(Vector2.UnitX, atob); Vector2 stepY = Vector2.TransformNormal(Vector2.UnitY, atob); Vector2 iBPos = Vector2.Transform(Vector2.Zero, atob); for(int deltax = 0; deltax < player.playerTexture.Width; deltax++) { Vector2 bpos = iBPos; for (int deltay = 0; deltay < player.playerTexture.Height; deltay++) { int bx = (int)bpos.X; int by = (int)bpos.Y; if (bx >= 0 && bx < dog.dogTexture.Width && by >= 0 && by < dog.dogTexture.Height) { if (player.TextureData[deltax + deltay * player.playerTexture.Width].A > 150 && dog.TextureData[bx + by * dog.Texture.Width].A > 150) { return true; } } bpos += stepY; } iBPos += stepX; } return false; } What I want to know is where to put in the code where something happens. For example, I want to put in player.playerPosition.X -= 200 just as a test, but I don't know where to put it. I tried putting it under the return true and above it, but under it, it said unreachable code, and above it nothing happened. I also tried putting it by bpos += stepY; but that didn't work either. Where do I put the code?

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  • Merge 2 XML files with xslt

    - by MADAL
    Hello, I try to merge 2 XML-Files. I use XSLT: [http://www2.informatik.hu-berlin.de/...erge.xslt.html] I need to change this XSLT-File in order to have another result. My first file, which needs to be merged: <A1> <A2> <A3> <b>a</b> <c>b</c> </A3> </A2> </A1> <A1> <A2> <A3> <b>1</b> <c>2</c> </A3> </A2> </A1> ... My 2. file, which needs to be merged whithe the first one: <A1> <A2> <A3> <b>x</b> <c>y</c> </A3> </A2> </A1> <A1> <A2> <A3> <b>8</b> <c>9</c> </A3> </A2> </A1> The result should be: <A1> <A2> <A3> <b>a</b><bx><b>a</b></bx><bx><b>x</b></bx> <c>by</c> </A3> </A2> </A1> <A1> <A2> <A3> <b>1</b><bx><b>1</b></bx><bx><b>18</b></bx> <c>29</c> </A3> </A2> </A1> Could anybody help me with that?!!!! Regards

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  • Four New Java Champions

    - by Tori Wieldt
    Four luminaries in the Java community have been selected as new Java Champions. The are Agnes Crepet, Lars Vogel, Yara Senger and Martijn Verburg. They were selected for their technical knowledge, leadership, inspiration, and tireless work for the community. Here is how they rock the Java world: Agnes Crepet Agnes Crepet (France) is a passionate technologist with over 11 years of software engineering experience, especially in the Java technologies, as a Developer, Architect, Consultant and Trainer. She has been using Java since 1999, implementing multiple kinds of applications (from 20 days to 10000 men days) for different business fields (banking, retail, and pharmacy). Currently she is a Java EE Architect for a French pharmaceutical company, the homeopathy world leader. She is also the co-founder, with other passionate Java developers, of a software company named Ninja Squad, dedicated to Software Craftsmanship. Agnes is the leader of two Java User Groups (JUG), the Lyon JUG Duchess France and the founder of the Mix-IT Conferenceand theCast-IT Podcast, two projects about Java and Agile Development. She speaks at Java and JUG conferences around the world and regularly writes articles about the Java Ecosystem for the French print Developer magazine Programmez! and for the Duchess Blog. Follow Agnes @agnes_crepet. Lars Vogel Lars Vogel (Germany) is the founder and CEO of the vogella GmbH and works as Java, Eclipse and Android consultant, trainer and book author. He is a regular speaker at international conferences, such as EclipseCon, Devoxx, Droidcon and O'Reilly's Android Open. With more than one million visitors per month, his website vogella.com is one of the central sources for Java, Eclipse and Android programming information. Lars is committer in the Eclipse project and received in 2010 the "Eclipse Top Contributor Award" and 2012 the "Eclipse Top Newcomer Evangelist Award." Follow Lars on Twitter @vogella. Yara Senger Yara Senger (Brazil) has been a tireless Java activist in Brazil for many years. She is President of SouJava and she is an alternate representative of the group on the JCP Executive Committee. Yara has led SouJava in many initiatives, from technical events to social activities. She is co-founder and director of GlobalCode, which trains developers throughout Brazil.  Last year, she was recipient of the Duke Choice's Award, for the JHome embedded environment.  Yara is also an active speaker, giving presentations in many countries, including JavaOne SF, JavaOne Latin Ameria, JavaOne India, JFokus, and JUGs throughout Brazil. Yara is editor of InfoQ Brasil and also frequently posts at http://blog.globalcode.com.br/search/label/Yara. Follow Yara @YaraSenger. Martijn Verburg Martijn Verburg (UK) is the CTO of jClarity (a Java/JVM performance cloud tooling start-up) and has over 12 years experience as a Java/JVM technology professional and OSS mentor in a variety of organisations from start-ups to large enterprises. He is the co-leader of the London Java Community (~2800 developers) and leads the global effort for the Java User Group "Adopt a JSR" and "Adopt OpenJDK" programmes. These programmes encourage day to day Java developer involvement with OpenJDK, Java standards (JSRs), an important relationship for keeping the Java ecosystem relevant to the 9 million Java developers out there today. As a leading expert on technical team optimisation, his talks and presentations are in high demand by major conferences (JavaOne, Devoxx, OSCON, QCon) where you'll often find him challenging the industry status quo via his alter ego "The Diabolical Developer." You can read more in the OTN ariticle "Challenging the Diabolical Developer: A Conversation with JavaOne Rock Star Martijn Verburg." Follow Martijn @karianna. The Java Champions are an exclusive group of passionate Java technology and community leaders who are community-nominated and selected under a project sponsored by Oracle. Java Champions get the opportunity to provide feedback, ideas, and direction that will help Oracle grow the Java Platform. Congratulations to these new Java Champions!

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  • Matlab - plot multiple data sets on a scatter plot

    - by Mark
    Hey all, I have 2 sets of data (Ax, Ay; Bx, By) - I'd like to plot both of these data sets on a scatter plot with different colors, but can't seem to get it to work because it seems scatter() does not work like plot(). Is it possible to do this? I've tried... scatter(Ax, Ay, 'g', Bx, By, 'b') And scatter(Ax, Ay, 'g') scatter(Bx, By, 'b') The first way returns an error. The latter only plots the Bx/By data. Many thanks!

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  • Delay On Assembler?

    - by Norm
    Hey, I want to know how i can do delay (Timer) on assembler 16 bit on PC. Thank You for helping, Norm. OS: Windows CODE: delay: inc bx cmp bx,WORD ptr[time] je delay2 jmp delay delay2: inc dx cmp dx,WORD ptr[time2] je delay3 jmp delay mov bx,0 delay3: inc cx cmp cx,WORD ptr[time3] je Finish_delay jmp delay its not work good i need less complicated code

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