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  • SU, SUDO and Upgrade problem

    - by DigitalDaigor
    i have a big problem with my Ubuntu PC. When i try sometigng need sudo or su, nothing is working and the OS Upgrade too, when i write the root password to the su command i have a "autentication error", same in the upgrades and when i try the sudo command to install something i don't have error message and nothing happen. I was tring to make samba work when all goes wrong. Some help!? Thanks! Edit SSH connection refused and connection closed if i try to login from secondary PC I can't access recovery mode... With the autologin i can access the system, if i logout and try to login again return the autentication error

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  • su: Authentication failure

    - by user166999
    I have downloaded the Eset Nod32 Antivirus from its website, and I got a eset_nod32av_64bit_en.linux file. I have right-clicked on it, Properties - Permissions, and checked the Allow executing file as program option. Then I was able to run the program. The Installer starts and it asks for my root password. I enter it correctly, but then I get the following error message: "su: Authentication failure". What can I do with this to install the Nod32? Thanks!

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  • What is the difference between "su --command" and "su --session-command"?

    - by oliver
    Running # su - oliver --command bash gives a shell but also prints the warning bash: no job control in this shell, and indeed Ctrl+Z and fg/bg don't work in that shell. Running # su - oliver --session-command bash gives a shell without printing the warning, and job control indeed works. The suggestion to use --session-command comes from Starting a shell from scripts using su results in "no job control in this shell" which states "[a security fix for su] changed the behavior of the -c option and disables job control inside the called shell". But I still don't quite understand this. When should one use --command and when should one use --session-command? Is --command (aka -c) more secure? Or should one always use --session-command, and --command is just left in for backwards compatibility? FWIW, I'm using RHEL 6.4.

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  • centos: su silently fails

    - by matteo
    On a CentOS server where I'm logged via SSH as root, I do: su otherusername where 'otherusername' is the user name of another user, which exists. It does nothing. After that, I'm still root. whoami returns root, any file I create belongs to root, that is, su just doesn't su. However it does not give any error message. If I try to su with an invalid user name it does give an error message. What am I missing??

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  • running a command as root with /bin/su and without gives different results

    - by n00bInCpp
    Some background: I have a machine with SLES 11 installed. I am running a bash script that one of its lines is /bin/su $USER -c SOME_CMD. Unfortunately, the SOME_CMD that comes after the -c keeps failing, no matter if USER=root or any different user. However, if /bin/su $USER -c part is omitted then everything runs smoothly. Moreover, I have run the script on RHEL5 and it worked fine. Anyway, my question is why does it happen? If it is a permissions problems then why when I run this as root with /bin/su and without I get different results? P.S. apologize if somebody else has asked it before, I have done many googling and got nothing that satisfies. Thanks in advance, n00bInCpp EDIT Okay, I figured it out, I hope so. Instead of running /bin/su I used /user/bin/sudo -u $MY_USER_1 MY_ENV_VAR="/home/user1" SOME_CMD. I don't understand why I have to use sudo, though. I am used to run a command as a different user using su and not worrying about permissions problems, but I guess it doesn't work like that on SLES 11/SuSE. Anyhow, thanks to everyone who wanted to or helped me.

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  • How can I create an “su” only user (no SSH or SFTP) and limit who can “su” into that account in RHEL5? [closed]

    - by Beaming Mel-Bin
    Possible Duplicate: How can I allow one user to su to another without allowing root access? We have a user account that our DBAs use (oracle). I do not want to set a password on this account and want to only allow users in the dba group to su - oracle. How can I accomplish this? I was thinking of just giving them sudo access to the su - oracle command. However, I wouldn't be surprised if there was a more polished/elegant/secure way.

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  • Getting the index of the returned max or min item using max()/min() on a list

    - by KevinGriffin
    I'm using Python's max and min functions on lists for a minimax algorithm, and I need the index of the value returned by max() or min(). In other words, I need to know which move produced the max (at a first player's turn) or min (second player) value. for i in range(9): newBoard = currentBoard.newBoardWithMove([i / 3, i % 3], player) if newBoard: temp = minMax(newBoard, depth + 1, not isMinLevel) values.append(temp) if isMinLevel: return min(values) else: return max(values) I need to be able to return the actual index of the min or max value, not just the value.

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  • Can not su to normal user

    - by Summer Nguyen
    I have a centos 5.8 box with gitolite installed . It worked fine until I yesterday my gitolite didn't work. ( fatal the remote end hung up unexpectedly) I logged to the box using root account. and then su to git user but I can't. I test again by creating a new user , but I also can not su to that user. Any idea ?, thank you very much. P.S: I installed postfix the day before , but I'm not sure if postfix cause the problem.

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  • Can't login as root but I can SU while logged with another user

    - by Rhyuk
    What I was doing before this happened?: I was tinkering trying to setup X server so I can open an app's GUI remotely so I installed "X Window System", "xclock" and uncommented "# ForwardX11 yes" from my "/etc/ssh/ssh_config". (never got it working but thats a whole other question) Since that moment I'm not able to login as root from Putty (I get Access Denied). I can login as another user and I can "su" successfully so I know the password is right. How can have direct access with root again?

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  • script to su with password in script without root

    - by Triplell89
    I have scripted a process that involves updating symbolic links on files located on 3 different machines. On those machines exists 4 users each, who each need to have these links updated. Using su, is there a way to pass the password argument to the command on a single line, without invoking sudo as the users will not have admin rights? My only alternative solution at this point is to ssh around, however I would like to be able to do this without hardcoding in a bunch of hosts/ips.

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  • Tae Kwon Do in Overland Park

    - by [C.B.W]
    If you are in the Overland Park area and are in need of some physical recreation (and who isn’t) I have to recommend Master’s Tae Kwon Do in Overland Park KS . Master Tom is an 8th Dan teaching Tae Kwon Do and Hapkido. Yah, he teaches almost all of the classes himself. I used to take ishin ryu but stopped some 12 years ago (seems like yesterday. God I am getting old.)    I had wanted to get back into some type of Martial Arts training and I wanted to get my son involved as well – Master’s Tae Kwon Do has the best schedule.   My son and I can go to any of the classes together. Tae Kwon Do is a pretty good work out, lots of kicks so gets the blood pumping. Work out and learn how to defend yourself all at one time. Great for those of us short on time.

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  • What's the difference between sudo su - postgres and sudo -u postgres?

    - by Craig Ringer
    PostgreSQL users peer authentication on unix sockets by default, where the unix user must be the same as the PostgreSQL user. So people frequently use su or sudo to become the postgres superuser. I often see people using constructs like: sudo su - postgres rather than sudo -u postgres -i and I'm wondering why. Similarly, I've seen: sudo su - postgres -c psql instead of sudo -u postgres psql Without the leading sudo the su versions would make some sense if you were on an old platform without sudo. But why on a less than prehisoric UNIX or Linux would you use sudo su ?

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  • Desigual Extiende Uso de Oracle ® ATG Web Commerce para potenciar su expansión internacional en línea

    - by Noelia Gomez
    Normal 0 21 false false false ES X-NONE X-NONE MicrosoftInternetExplorer4 Desigual, la empresa de moda internacional, ha extendido el uso de Oracle® ATG Web Commerce para dar soporte a su expansión creciente de sus capacidades comerciales de manera internacional y para ayudar a ofrecer un servicio de compra más personalizado a más clientes de manera global. Desigual eligió primero Oracle ATG Web Commerce en 2006 para lanzar su plataforma B2B y automatizar sus ventas a su negocio completo de ventas, Entonces, en Octubre de 2010, Desigual lanzó su plataforma B2C usando Oracle ATG Web Commerce, y ahora ofrece operaciones online en nueve países y 11 lenguas diferentes. Para dar soporte a esta creciente expansión de sus operaciones comerciales y de merchandising en otras geografías, Desigual decidió completar su arquitectura existente con Oracle ATG Web Commerce Merchandising y Oracle ATG Web Commerce Service Center. Además, Desigual implementará Oracle Endeca Guided Search para permitir a los clientes adaptarse de manera más eficiente con su entorno comercial y encontrar rápidamente los productos más relevantes y deseados. Desigual usará las aplicaciones de Oracle para permitir a los usuarios del negocio ganar el control sobre cómo ofrece la compañía una experiencia al cliente más personalizada y conectada a través de los diferentes canales, promoviendo ofertas personalizadas a cada cliente, priorizando los resultados de búsqueda e integrando las operaciones de la web con el contact center sin problemas para aumentar la satisfacción y mejorar los resultados de las conversaciones. Desde que se lanzara en 2002, el minorista español ha crecido rápidamente y ahora ofrece su original moda en sus 200 tiendas propias , 7000 minoristas autorizados y 1700 tiendas de concesión en 55 países. Infórmese con mayor profundidad de nuestras soluciones Oracle Customer Experience aquí. /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif"; mso-ascii- mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi- mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;}

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  • Print ssh and su chain

    - by user1824885
    Is there a way to show the complete ssh and su chain in bash? For example. In Server A as user aa: su - ab ssh ba@B su - bb Thus, I would like a command that prints something like this: 1 bash aa in A 2 su ab in A 3 ssh ba in B 4 su bb in B I tried pstree but it does not print the users and only works with the processes of the last ssh'ed server: $ pstree | grep -C 5 pstree serversshd---sshd---sshd---bash---su---bash-+-grep | `-pstree Thanks and regards.

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  • Finding min and max values

    - by user01
    I am trying to write a simple program that reads integers from a data file and outputs the minimum and maximum value. The first integer of the input file will indicate how many more integers will be read, and then the integers will be listed. My program compiles without any problem, however, it returns values that are not part of the set in my test data file. Could anyone help with diagnose this issue? int main(){ FILE *fp = fopen("data.txt", "r"); int count; int num; int i; int min = 0; int max = 0; fscanf (fp, "%d", &count); for (i = 0; i < count; i++) fscanf( fp, "%d", &i); { if (num < min) min = num; if (num > max) max = num; } fclose (fp); printf("Of the %d integers, the minimum value is %d and the maximum value is %d \n", count, min, max);}

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  • min.js to clear source

    - by dole
    Hi there As far i know until now, the min version of a .js(javascript) file is obtaining by removing the unncessary blank spaces and comments, in order to reduce the file size. My questions are: How can I convert a min.js file into a clear, easy readable .js file Besides, size(&and speed) are there any other advtages of the min.js file. the js files can be encripted? can js be infected. I think the answer is yes, so the question is how to protect the .js files from infections? Only the first question is most important and I'm looking for help on it. TY

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  • How to occupy all the space in a div when working with min-height header / footer

    - by javacoder
    I believe this is a beginner's CSS question. I am utilizing the method described in http://www.xs4all.nl/~peterned/examples/csslayout1.html to fix a header to the top and a footer to the bottom. What I'd like to achieve now is two columns inside the content div. A left one of 200px and a right one that takes up the rest of the width. Unfortunately, I can't get the left and right divs to display correctly: they just don't grow vertically, and if I make the right div "width: 100%" it positions itself underneath the left one. What is the trick to make the left and right div take up all the space within the content div? The layout1.css is the original one. I just added two entries: #left and #right layout1.css: /** * 100% height layout with header and footer * ---------------------------------------------- * Feel free to copy/use/change/improve */ html,body { margin: 0; padding: 0; height: 100%; /* needed for container min-height */ background: gray; font-family: arial, sans-serif; font-size: small; color: #666; } h1 { font: 1.5em georgia, serif; margin: 0.5em 0; } h2 { font: 1.25em georgia, serif; margin: 0 0 0.5em; } h1,h2,a { color: orange; } p { line-height: 1.5; margin: 0 0 1em; } div#container { position: relative; /* needed for footer positioning*/ margin: 0 auto; /* center, not in IE5 */ width: 750px; background: #f0f0f0; height: auto !important; /* real browsers */ height: 100%; /* IE6: treaded as min-height*/ min-height: 100%; /* real browsers */ } div#header { padding: 1em; background: #ddd url("../csslayout.gif") 98% 10px no-repeat; border-bottom: 6px double gray; } div#header p { font-style: italic; font-size: 1.1em; margin: 0; } div#content { padding: 1em 1em 5em; /* bottom padding for footer */ } div#content p { text-align: justify; padding: 0 1em; } div#footer { position: absolute; width: 100%; bottom: 0; /* stick to bottom */ background: #ddd; border-top: 6px double gray; } div#footer p { padding: 1em; margin: 0; } // added the following: div#left { border: 1px solid red; width: 200px; float: left; min-height: 100%; height: 100%; padding-left: 10px; margin-right: 10px; } div#right { border: 1px solid blue; float: left; min-height: 100%; height: 100%; padding-left: 10px; margin-right: 10px; } layout.html: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>CSS Layout - 100% height</title> <link rel="stylesheet" type="text/css" href="layout1.css" /> </head> <body> <div id="container"> <div id="header"> <h1>header</h1> </div> <div id="content"> <div id="left"> left column </div> <div id="right"> right column </div> </div> <div id="footer"> <p> footer </p> </div> </div> </body>

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  • C++ min heap with user-defined type.

    - by bsg
    Hi, I am trying to implement a min heap in c++ for a struct type that I created. I created a vector of the type, but it crashed when I used make_heap on it, which is understandable because it doesn't know how to compare the items in the heap. How do I create a min-heap (that is, the top element is always the smallest one in the heap) for a struct type? The struct is below: struct DOC{ int docid; double rank; }; I want to compare the DOC structures using the rank member. How would I do this? I tried using a priority queue with a comparator class, but that also crashed, and it also seems silly to use a data structure which uses a heap as its underlying basis when what I really need is a heap anyway. Thank you very much, bsg

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  • css + first load bug + min-height

    - by Henry
    We forked an editor for upcoming release of our CMS. See: http://tinyurl.com/ylbtns2 The editor uses the css of the current template and loads an additional fix.css (inside the iframe) to override some rules: * { background-image: none !important; min-height: 0px !important; } #breadcrumbs, #content .sidebar, #footer, #header, #search_form { display: none; } #content { margin: 0px; width: 100%; } The problem: on first load the "min-height: 0px !important;" seems not to work - on second load the height of the editor iframe is 100px like it should be. Other rules like no background (fix.css) are working on first load and get overridden.

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  • How to grant su access to wheel without asking for password on FreeBSD?

    - by cstamas
    I would like to grant users of the wheel group (other sysadmins) su access without being asked for password. I know how to do it with pam in linux, but the question now is for FreeBSD. I am not familiar with the syntax for FreeBSD's PAM subsystem. What shall I enter in /etc/pam.d/su instead of the default: auth sufficient pam_rootok.so no_warn auth sufficient pam_self.so no_warn auth requisite pam_group.so no_warn group=wheel root_only fail_safe ruser auth include system # account account include system # session session required pam_permit.so

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  • Hello World Problem in Eclipse with Android 2.3 used min 7 instead of min 9

    - by Gnev
    */I am Having a Similar Problem.......... Any Suggestions/ package com.example.helloandroid6; import android.app.Activity; import android.os.Bundle; import android.widget.TextView; public class HelloAndroid extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); TextView tv = new TextView(this); tv.setText("Hello, Android Developers"); setContentView(tv); } }

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  • ScrollTo - toggle between min-height/fixed height

    - by Skoder
    Hi everyone, I'm trying to use the ScrollTo plugin, but I can't seem to get it working properly. I tried to view the source at the site I linked to but I'm trying to achieve something slightly different. I would like the window pane to change size according to the content (so the height would increase for longer text and would decrease for shorter text). However, when I supply a min-height (as opposed to a fixed height), the pane automatically changes to the maximum height when the page is loaded. So if I have something set to margin-top:1000px;, the pane will be 1000px in size regardless of what tab is currently displaying. The fix would be to use height instead, but that would mean that the window won't expand in height and the user would have to scroll. I got my code from viewing the source on the ScrollTo page, but I also tried this tutorial code. Thanks for any help

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  • Successful su for user by root in /var/log/auth.log

    - by grs
    I have this sorts of entries in my /var/log/auth.log: Apr 3 12:32:23 machine_name su[1521]: Successful su for user1 by root Apr 3 12:32:23 machine_name su[1654]: Successful su for user2 by root Apr 3 12:32:24 machine_name su[1772]: Successful su for user3 by root Situation: All users are real accounts in /etc/passwd; None of the users has its own crontab; All of those users are logged in the machine some time ago via SSH or No Machine - time varies from few minutes to few hours; no cron jobs are scheduled to run at that time, anacron is removed; I can see similar entries for other days and other times. The common part is the users are logged in when it appears. It does not appear during login, but some time afterwards. This machine has similar setup with few others but it is the only one where I see these entries. What causes them? Thanks

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  • Using recursion to to trim a binary tree based on a given min and max value

    - by Justin
    As the title says, I have to trim a binary tree based on a given min and max value. Each node stores a value, and a left/right node. I may define private helper methods to solve this problem, but otherwise I may not call any other methods of the class nor create any data structures such as arrays, lists, etc. An example would look like this: overallRoot _____[50]____________________ / \ __________[38] _______________[90] / \ / _[14] [42] [54]_____ / \ \ [8] [20] [72] \ / \ [26] [61] [83] trim(52, 65); should return: overallRoot [54] \ [61] My attempted solution has three methods: public void trim(int min, int max) { rootFinder(overallRoot, min, max); } First recursive method finds the new root perfectly. private void rootFinder(IntTreeNode node, int min, int max) { if (node == null) return; if (overallRoot.data < min) { node = overallRoot = node.right; rootFinder(node, min, max); } else if (overallRoot.data > max) { node = overallRoot = node.left; rootFinder(node, min, max); } else cutter(overallRoot, min, max); } This second method should eliminate any further nodes not within the min/max, but it doesn't work as I would hope. private void cutter(IntTreeNode node, int min, int max) { if (node == null) return; if (node.data <= min) { node.left = null; } if (node.data >= max) { node.right = null; } if (node.data < min) { node = node.right; } if (node.data > max) { node = node.left; } cutter(node.left, min, max); cutter(node.right, min, max); } This returns: overallRoot [54]_____ \ [72] / [61] Any help is appreciated. Feel free to ask for further explanation as needed.

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