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Search found 4 results on 1 pages for 'openargs'.

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• OpenArgs Problem in Access

  - by kkbondo

  I have a code like this: Dim strResponses As String strResponses = Forms!frmResponses.QstnID.OpenArgs If Len(strResponses) 0 Then Me![QstnID].DefaultValue = Me.OpenArgs End If When I run it, its gives error 438. Can someone help me to know where the error is?

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• F# constructor syntax - overiding and augmenting new

  - by Benjol

  I have a non-disposable class with Open/Close syntax that I'd like to be able to use, so I'm trying to inherit from it, and work the Open into the new and the Close into Dispose. The second part is ok, but I can't work out how to do the Open: type DisposableOpenCloseClass(openargs) = inherit OpenCloseClass() //do this.Open(openargs) <-- compiler no like interface IDisposable with member this.Dispose() = this.Close() (cf. this question which I asked a long time ago, but I can't join the dots to this one)

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• MS-Access: What could cause one form with a join query to load right and another not?

  - by Daniel Straight

  Form1 Form1 is bound to Table1. Table1 has an ID field. Form2 Form2 is bound to Table2 joined to Table1 on Table2.Table1_ID=Table1.ID Here is the SQL (generated by Access): SELECT Table2.*, Table1.[FirstFieldINeed], Table1.[SecondFieldINeed], Table1.[ThirdFieldINeed] FROM Table1 INNER JOIN Table2 ON Table1.ID = Table2.[Table1_ID]; Form2 is opened with this code in Form1: DoCmd.RunCommand acCmdSaveRecord DoCmd.OpenForm "Form2", , , , acFormAdd, , Me.[ID] DoCmd.Close acForm, "Form1", acSaveYes And when loaded runs: Me.[Table1_ID] = Me.OpenArgs When Form2 is loaded, fields bound to columns from Table1 show up correctly. Form3 Form3 is bound to Table3 joined to Table2 on Table3.Table2_ID=Table2.ID Here is the SQL (generated by Access): SELECT Table3.*, Table2.[FirstFieldINeed], Table2.[SecondFieldINeed] FROM Table2 INNER JOIN Table3 ON Table2.ID = Table3.[Table2_ID]; Form3 is opened with this code in Form2: DoCmd.RunCommand acCmdSaveRecord DoCmd.OpenForm "Form3", , , , acFormAdd, , Me.[ID] DoCmd.Close acForm, "Form2", acSaveYes And when loaded runs: Me.[Table2_ID] = Me.OpenArgs When Form3 is loaded, fields bound to columns from Table2 do not show up correctly. WHY? UPDATES I tried making the join query into a separate query and using that as my record source, but it made no difference at all. If I go to the query for Form3 and view it in datasheet view, I can see that the information that should be pulled into the form is there. It just isn't showing up on the form.

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• MS Access form_current() firing multiple times

  - by Eric G

  I have a form with two subforms (on separate tab pages). It's an MDB project in Access 2003. When it initially opens, Form_Current on the active subform fires once, as it should. But when you move to another record (ie. from the main form), it fires Form_Current on the active subform 4 times. Then subsequent record-moves result in Form_Current firing 2 times. This is a pain, because the subforms have a lot of fields that get moved and/or hidden and so it jumps around for every Form_Current, not to mention being slow. I am opening the form with a filter via DoCmd.OpenForm (actually it sends the filter in via OpenArgs). FilterOn is only set once, in Form_Open on the main form, never in the subforms. Form_Current is not called explicitly anywhere else in the code. When I look at the call stack when Form_Current fires moving the first time, it looks like: my_subform.Form_Current [<Debug Window>] my_subform.Form_Current So it seems like something in Form_Current is triggering another Form_Current event. But only on the first record move. The code in Form_Current is somewhat complex, involving custom classes and event callbacks, but generally does not touch the table data. The only thing I can think might be triggering a Form_Current is that it checks OldValue on form controls - could this be causing it? Or anything else come to mind? Thanks. Eric

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