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• spoof mac address

  - by Cold-Blooded

  // macaddress.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include <windows.h> #include <iostream> using namespace std; void readregistry(); void spoofmac(); void main(int argc, char* argv[]) { readregistry(); spoofmac(); } void spoofmac() { ////////////////////// ////////Write to Registry char buffer[60]; unsigned long size = sizeof(buffer); HKEY software; LPCTSTR location; char adapternum[10]=""; char numbers[11]="0123456789"; char editlocation[]="System\\CurrentControlSet\\Control\\Class\\{4D36E972-E325-11CE-BFC1-08002bE10318}\\0000"; char macaddress[60]; cout << "\n//////////////////////////////////////////////////////////////////\nPlease Enter Number of Network Adapter to Spoof or type 'E' to Exit.\nE.g. 18\n\nNumber: "; cin >> adapternum; if (adapternum[0]=='E') { exit(0); } if (strlen(adapternum)==2) { editlocation[strlen(editlocation)-2]=adapternum[0]; editlocation[strlen(editlocation)-1]=adapternum[1]; } if (strlen(adapternum)==1) { editlocation[strlen(editlocation)-1]=adapternum[0]; } if (strlen(adapternum)!=1 && strlen(adapternum)!=2) { cout << "Invaild Network Adapter Chosen\n\n"; exit(0); } cout << "Please Enter the Desired Spoofed Mac Address Without Dashes\nE.g. 00123F0F6D7F\n\nNew Mac: "; cin >> macaddress; location = editlocation; //error line strcpy(buffer,macaddress); size=sizeof(buffer); RegCreateKey(HKEY_LOCAL_MACHINE,location,&software); //RegSetValueEx(software,"NetworkAddress",NULL,REG_SZ,(LPBYTE)buffer,size); RegCloseKey(software); cout << "\nMac Address Successfully Spoofed.\n\nWritten by Lyth0s\n\n"; } void readregistry () { //////////////////////////////////// // Read From Registry char driver[60]=""; char mac[60]=""; char numbers[11]="0123456789"; char editlocation[]="System\\CurrentControlSet\\Control\\Class\\{4D36E972-E325-11CE-BFC1-08002bE10318}\\0000"; unsigned long driversize = sizeof(driver); unsigned long macsize = sizeof(mac); DWORD type; HKEY software; LPCTSTR location; int tenscount=0; int onescount=0; for (int x =0;x<=19; x+=1) { strcpy(driver,""); driversize=sizeof(driver); strcpy(mac,""); macsize=sizeof(mac); if (editlocation[strlen(editlocation)-1]=='9') { tenscount+=1; onescount=0; editlocation[strlen(editlocation)-2]=numbers[tenscount]; } editlocation[strlen(editlocation)-1]=numbers[onescount]; location=editlocation; //error line // cout << location << "\n"; // cout << "Checking 00" << location[strlen(location)-2] << location[strlen(location)-1] << "\n\n"; RegCreateKey(HKEY_LOCAL_MACHINE,location,&software); RegQueryValueEx(software,"DriverDesc",NULL,&type,(LPBYTE)driver,&driversize); //RegCloseKey(software); //RegCreateKey(HKEY_LOCAL_MACHINE,location,&software); RegQueryValueEx(software,"NetworkAddress",NULL,&type,(LPBYTE)mac,&macsize); RegCloseKey(software); cout << x << ": " << driver << "| Mac: " << mac << "\n"; onescount+=1; } } this program gives error as follows error C2440: '=' : cannot convert from 'char [83]' to 'LPCTSTR' why this error coming please explain

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• Question about char input

  - by DomX23

  This is what I'm trying to do... char input[4]; cin >> input; cout << "Input[0]: " << input[0] << "Input[1]: " << input[1] << "Input[2]: " << input[2] << "Input[3] " << input[3]<< "Input[4] " << input[4] <<endl; However, when I enter "P F" I get an out of this: Input[0]:P Input[1]: Input[2]: Input[3] Input[4] Why do I get that weird character instead of F?

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• C++ Beginner - Best way to read 3 consecutive values from the command line?

  - by Francisco P.

  Hello everyone, I am writing a text-based Scrabble implementation for a college project. The specification states that the user's position input must be read from single line, like this: Coordinates of the word's first letter and orientation (<A – P> <1 – 15> <H ou V>): G 5 H G 5 H is the user's input for that particular example. The order, as shown, must be char int char. What is the best way to read the user's input? cin >> row >> column >> orientation will cause crashes if the user screws up. A getline and a subsequent string parser are a valid solution, but represent a bit of work. Is there another, better, way to do this, that I am missing? Thanks for your time!

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• read pair of characters separated by \t c++

  - by Kiran

  Friends, I want to read a pair of characters separated by \t. I want to continue reading the input until user enters z for any of the characters. Here are the options I thought: while (cinch1ch2) { // process ch1 & ch2 } std::string str; while (getline(cin, str) ){ //split string } Also, I want to validate the input to make sure that it is correct. Please suggest the best way. If this is a duplicate, please point me to the right one. Thanks.

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• Using pow() for large number

  - by g4ur4v

  I am trying to solve a problem, a part of which requires me to calculate (2^n)%1000000007 , where n<=10^9. But my following code gives me output "0" even for input like n=99. Is there anyway other than having a loop which multilplies the output by 2 every time and finding the modulo every time (this is not I am looking for as this will be very slow for large numbers). #include<stdio.h> #include<math.h> #include<iostream> using namespace std; int main() { unsigned long long gaps,total; while(1) { cin>>gaps; total=(unsigned long long)powf(2,gaps)%1000000007; cout<<total<<endl; } }

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• Why does C++ allow variable length arrays that aren't dynamically allocated?

  - by Maulrus

  I'm relatively new to C++, and from the beginning it's been drilled into me that you can't do something like int x; cin >> x; int array[x]; Instead, you must use dynamic memory. However, I recently discovered that the above will compile (though I get a -pedantic warning saying it's forbidden by ISO C++). I know that it's obviously a bad idea to do it if it's not allowed by the standard, but I previously didn't even know this was possible. My question is, why does g++ allow variable length arrays that aren't dynamically allocated if it's not allowed by the standard? Also, if it's possible for the compiler to do it, why isn't it in the standard?

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• arrays declaration and addressing

  - by avinash

  I have a few straightforward questions:- Is the following correct according to a normal c++ compiler? int arr[3][4]; void func(int *a, int m, int n) { int i,j; cin>>i>>j; cout<< a[i*n + j]; //is this way of addressing correct provided 0<=i<m and 0<=j<n } int main() { func((int*)arr, 3,4); } If the bounds of an array strictly has to be a constant expression, why doesn't the following generate compiler errors? int func(int m, int n) { int arr[m][n]; //m and n are not known until run time }

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• Why is 'using namespace std;' considered a bad practice in C++?

  - by Mana

  Okay, sorry for the simplistic question, but this has been bugging me ever since I finished high school C++ last year. I've been told by others on numerous occasions that my teacher was wrong in saying that we should have "using namespace std;" in our programs, and that std::cout and std::cin are more proper. However, they would always be vague as to why this is a bad practice. So, I'm asking now: Why is "using namespace std;" considered bad? Is it really that inefficient, or risk declaring ambiguous vars(variables that share the same name as a function in std namespace) that much? Or does this impact program performance noticeably as you get into writing larger applications? I'm sorry if this is something I should have googled to solve; I figured it would be nice to have this question on here regardless in case anyone else was wondering.

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• which is time consuming construct in following program?

  - by user388338

  while submitting a solution for practise problem 6(odd) i got TLE error but while using using print and scanf in place cin and cout my sol was submitted successfully with 0.77s time..i want to know how can i make it more efficient link to problem is codechef problem 6 #include<iostream> #include<cstdio> using namespace std; int main() {int n,N; scanf("%d",&n); for(int l=0;l<n;l++) { scanf("%d",&N); int i=0,x; if(N<=0) continue; for(;N>=(x=(2<<i));i++); printf("%d",x/2); cout<<"\n"; } }

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• Convert a number from string to integer without using inbuilt function

  - by Raja

  I am trying this technique but error is coming. Please help me to convert a number from string to integer. #include<iostream> using namespace std; int main() { char *buffer[80]; int a; cout<<"enter the number"; cin.get(buffer,79); char *ptr[80] = &buffer; while(*ptr!='\0') { a=(a*10)+(*ptr-48); } cout<<"the value"<<a; delete ptr[]; return 0; } Errors are: error C2440: 'initializing' : cannot convert from 'char ()[80]' to 'char *[80]' error C2440: '=' : cannot convert from 'char *' to 'int'

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• how do I check if a c++ string is an int?

  - by user342231

  when I use getline, I would input a bunch of strings or numbers, but I only want the while loop to output the "word" if it is not a number. so is there any way to check if "word" is a number or not, I know I could use atoi() for c-strings but how about for strings of the string class int main () { stringstream ss (stringstream::in | stringstream::out); string word; string str; getline(cin,str); ss<<str; while(ss>>word) { //if( ) cout<<word<<endl; } }

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• C++ split string

  - by Mike

  I am trying to split a string using spaces as a delimiter. I would like to store each token in an array or vector. I have tried. string tempInput; cin >> tempInput; string input[5]; stringstream ss(tempInput); // Insert the string into a stream int i=0; while (ss >> tempInput){ input[i] = tempInput; i++; } The problem is that if i input "this is a test", the array only seems to store input[0] = "this". It does not contain values for input[2] through input[4]. I have also tried using a vector but with the same result.

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• can we write this in C++ switch ?

  - by jellly

  #include <iostream> using namespace std; int main(){ char i; cin >>i; switch (i){ case ('e'||'i'||'o'||'u'||'a'): cout<<"Vowel"; break; case ('+'||'-'||'/'||'*'||'%'): cout<<"Op"; break; } return 0; } if not than how can we use comparison or logical operators in switch ? & why cant we declare and initialize variable in single case without using scope ?

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• Receiving integers, but also want to test for char.

  - by Wayne Haworth

  Say I am looking to receive a series of numeric values and read them into an int, but I also want to test if the user hit key 'x'. I am sure I am missing something obvious, and have tried a few things but seem to be stuck. This is what I have so far... cout << endl << "Enter key (or 'x' to exit): "; cin key; if (key == 'x') { cout << "exiting";} // continue on...

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• index was outside the bounds of the array because of \n (new line) in richTextBox

  - by revvs

  If i go into the next line with richTextBox1.Text + "\n" you can't use richTextBox with anything anymore normally. Why not ? because index will be outside the bounds of the array and you won't be able to transport the data into database or work with it normally...it will be all messed up. It is like the story with cin and getline in C++, but much worse. Here you won't see errors, not until you'll try to transport it into database. If you use "\n" to write new lines into txt, your txt will be also unusable. It will look like up to the byte the same as if you would write it by hand same sentences but "\n" will fuck it up. So how do i go into the next line and not have this "\n" screwing up my program ??! How do i go into the new line ?

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• C++ open() fails for no apparant reason

  - by jondoe

  The following code: char filename[64]; ifstream input; cout << "Please enter the filename: " << endl; cin >> filename; input.open(filename); if (!input.is_open()) { cout << "Opening file " << filename << " failed." << endl; exit(1); } fails, it enters the if() and exits. What could possibly be the cause for this? I'm using Microsoft Visual C++. When I hardcoded the filename as a constant it instead ended up garbled: http://pici.se/pictures/CNQEnwhgo.png Suggestions?

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• Why does this C++ char array seem to be able to hold more than its size?

  - by Phenom

  #include <iostream> using namespace std; typedef struct { char streetName[5]; } RECORD; int main() { RECORD r; cin >> r.streetName; cout << r.streetName << endl; } When I run this program, if I enter in more than 5 characters, the output will show the whole string I entered. It does not truncate at 5 characters. Why is that? How can I get this to work correctly?

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• Getting input in system() function (Mac)

  - by Alex

  #include <iostream> using namespace std; int main() { short int enterVal; cout << "enter a number to say: " << endl; cin >> enterVal; system("say "%d"") << enterVal; return 0; } Is what I am currently trying. I want the user to enter a number and the system() function says it basically. The code above has an error which says " 'd' was not declared in this scope ". Thanks in advance.

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• How do I open a terminal window with C++ in Ubuntu?

  - by Epic Jakelor

  I recently decided to start teaching myself C++ and thought a simple encryption project would be a good place to start, since it covers most of the basics (cout, cin, opening files, etc). Is there a way to have the code open a terminal window similar to the one opened when I compile and run from sublime text? I have tried this so far, but it hasn't changed anything. string cmd = "gnome-terminal-x sh-c 'ls-l; exec bash'"; system(cmd.c_str()); Essentially, I would like to be able to run the program by clicking the .exe, and have the terminal where all of the input and output goes pop up.

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• How to compare string with const char*?

  - by arzeth

  #include <stdlib.h> #include <stdio.h> #include <iostream> #include <string.h> using namespace std; int main() { string cmd; while(strcmp(cmd.c_str(),"exit")==0 && strcmp(cmd.c_str(),"\exit")==0) { cin>>cmd; cout<<cmd; } return 0; } I am stuck.

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• Extract inputs from a pointer to array of characters in C / C++

  - by user2066884

  I am writing a command line utility but I cannot find a way to store the commands and arguments. so far I have the following but I get a Segmentation fault: int main(void) { char *command; char *args[MAX_LINE/2 + 1]; int should_run = 1; do{ cout << "cmd> "; int counter = 0; while(cin >> command) { strcpy(args[counter],command); counter++; } cout << args[0] << "\n"; } }

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• equivalent to getch(), mac/linux crash

  - by acidzombie24

  Hey guys. So I am using getch() and my app crashes instantly. Including when doing: int main() { getch(); } I can't find the link but supposedly the problem is, it needs to turn off buffering or something strange along those lines and I still want cout to work along with cross platform code. I was told to use std::cin.get(), but I'd like the app to quit when a key is pressed, not when the user typed in a letter or number then press enter to quit. Is there any function for this? The code must work under Mac (my os) and Windows.

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• Why is my simple recusive method for this game always off by 1?

  - by FrankTheTank

  I'm attempting to create a text-based version of this game: http://www.cse.nd.edu/java/SameGame.html Here is the code I have so far: #include <iostream> #include <vector> #include <ctime> class Clickomania { public: Clickomania(); std::vector<std::vector<int> > board; int move(int, int); bool isSolved(); void print(); void pushDown(); bool isValid(); }; Clickomania::Clickomania() : board(12, std::vector<int>(8,0)) { srand((unsigned)time(0)); for(int i = 0; i < 12; i++) { for(int j = 0; j < 8; j++) { int color = (rand() % 3) + 1; board[i][j] = color; } } } void Clickomania::pushDown() { for(int i = 0; i < 8; i++) { for(int j = 0; j < 12; j++) { if (board[j][i] == 0) { for(int k = j; k > 0; k--) { board[k][i] = board[k-1][i]; } board[0][i] = 0; } } } } int Clickomania::move(int row, int col) { bool match = false; int totalMatches = 0; if (row > 12 || row < 0 || col > 8 || col < 0) { return 0; } int currentColor = board[row][col]; board[row][col] = 0; if ((row + 1) < 12) { if (board[row+1][col] == currentColor) { match = true; totalMatches++; totalMatches += move(row+1, col); } } if ((row - 1) >= 0) { if (board[row-1][col] == currentColor) { match = true; totalMatches++; totalMatches += move(row-1, col); } } if ((col + 1) < 8) { if (board[row][col+1] == currentColor) { match = true; totalMatches++; totalMatches += move(row, col+1); } } if ((col - 1) >= 0) { if (board[row][col-1] == currentColor) { match = true; totalMatches++; totalMatches += move(row, col-1); } } return totalMatches; } void Clickomania::print() { for(int i = 0; i < 12; i++) { for(int j = 0; j < 8; j++) { std::cout << board[i][j]; } std::cout << "\n"; } } int main() { Clickomania game; game.print(); int row; int col; std::cout << "Enter row: "; std::cin >> row; std::cout << "Enter col: "; std::cin >> col; int numDestroyed = game.move(row,col); game.print(); std::cout << "Destroyed: " << numDestroyed << "\n"; } The method that is giving me trouble is my "move" method. This method, given a pair of coordinates, should delete all the squares at that coordinate with the same number and likewise with all the squares with the same number connected to it. If you play the link I gave above you'll see how the deletion works on a click. int Clickomania::move(int row, int col) { bool match = false; int totalMatches = 0; if (row > 12 || row < 0 || col > 8 || col < 0) { return 0; } int currentColor = board[row][col]; board[row][col] = 0; if ((row + 1) < 12) { if (board[row+1][col] == currentColor) { match = true; totalMatches++; totalMatches += move(row+1, col); } } if ((row - 1) >= 0) { if (board[row-1][col] == currentColor) { match = true; totalMatches++; totalMatches += move(row-1, col); } } if ((col + 1) < 8) { if (board[row][col+1] == currentColor) { match = true; totalMatches++; totalMatches += move(row, col+1); } } if ((col - 1) >= 0) { if (board[row][col-1] == currentColor) { match = true; totalMatches++; totalMatches += move(row, col-1); } } return totalMatches; } My move() method above works fine, as in, it will delete the appropriate "blocks" and replace them with zeros. However, the number of destroyed (value returned) is always one off (too small). I believe this is because the first call of move() isn't being counted but I don't know how to differentiate between the first call or subsequent calls in that recursive method. How can I modify my move() method so it returns the correct number of destroyed blocks?

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• Why is my simple recusive method's final return value always off by 1?

  - by FrankTheTank

  I'm attempting to create a text-based version of this game: http://www.cse.nd.edu/java/SameGame.html Here is the code I have so far: #include <iostream> #include <vector> #include <ctime> class Clickomania { public: Clickomania(); std::vector<std::vector<int> > board; int move(int, int); bool isSolved(); void print(); void pushDown(); bool isValid(); }; Clickomania::Clickomania() : board(12, std::vector<int>(8,0)) { srand((unsigned)time(0)); for(int i = 0; i < 12; i++) { for(int j = 0; j < 8; j++) { int color = (rand() % 3) + 1; board[i][j] = color; } } } void Clickomania::pushDown() { for(int i = 0; i < 8; i++) { for(int j = 0; j < 12; j++) { if (board[j][i] == 0) { for(int k = j; k > 0; k--) { board[k][i] = board[k-1][i]; } board[0][i] = 0; } } } } int Clickomania::move(int row, int col) { bool match = false; int totalMatches = 0; if (row > 12 || row < 0 || col > 8 || col < 0) { return 0; } int currentColor = board[row][col]; board[row][col] = 0; if ((row + 1) < 12) { if (board[row+1][col] == currentColor) { match = true; totalMatches++; totalMatches += move(row+1, col); } } if ((row - 1) >= 0) { if (board[row-1][col] == currentColor) { match = true; totalMatches++; totalMatches += move(row-1, col); } } if ((col + 1) < 8) { if (board[row][col+1] == currentColor) { match = true; totalMatches++; totalMatches += move(row, col+1); } } if ((col - 1) >= 0) { if (board[row][col-1] == currentColor) { match = true; totalMatches++; totalMatches += move(row, col-1); } } return totalMatches; } void Clickomania::print() { for(int i = 0; i < 12; i++) { for(int j = 0; j < 8; j++) { std::cout << board[i][j]; } std::cout << "\n"; } } int main() { Clickomania game; game.print(); int row; int col; std::cout << "Enter row: "; std::cin >> row; std::cout << "Enter col: "; std::cin >> col; int numDestroyed = game.move(row,col); game.print(); std::cout << "Destroyed: " << numDestroyed << "\n"; } The method that is giving me trouble is my "move" method. This method, given a pair of coordinates, should delete all the squares at that coordinate with the same number and likewise with all the squares with the same number connected to it. If you play the link I gave above you'll see how the deletion works on a click. int Clickomania::move(int row, int col) { bool match = false; int totalMatches = 0; if (row > 12 || row < 0 || col > 8 || col < 0) { return 0; } int currentColor = board[row][col]; board[row][col] = 0; if ((row + 1) < 12) { if (board[row+1][col] == currentColor) { match = true; totalMatches++; totalMatches += move(row+1, col); } } if ((row - 1) >= 0) { if (board[row-1][col] == currentColor) { match = true; totalMatches++; totalMatches += move(row-1, col); } } if ((col + 1) < 8) { if (board[row][col+1] == currentColor) { match = true; totalMatches++; totalMatches += move(row, col+1); } } if ((col - 1) >= 0) { if (board[row][col-1] == currentColor) { match = true; totalMatches++; totalMatches += move(row, col-1); } } return totalMatches; } My move() method above works fine, as in, it will delete the appropriate "blocks" and replace them with zeros. However, the number of destroyed (value returned) is always one off (too small). I believe this is because the first call of move() isn't being counted but I don't know how to differentiate between the first call or subsequent calls in that recursive method. How can I modify my move() method so it returns the correct number of destroyed blocks?

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• Improving the running time of Breadth First Search and Adjacency List creation

  - by user45957

  We are given an array of integers where all elements are between 0-9. have to start from the 1st position and reach end in minimum no of moves such that we can from an index i move 1 position back and forward i.e i-1 and i+1 and jump to any index having the same value as index i. Time Limit : 1 second Max input size : 100000 I have tried to solve this problem use a single source shortest path approach using Breadth First Search and though BFS itself is O(V+E) and runs in time the adjacency list creation takes O(n2) time and therefore overall complexity becomes O(n2). is there any way i can decrease the time complexity of adjacency list creation? or is there a better and more efficient way of solving the problem? int main(){ vector<int> v; string str; vector<int> sets[10]; cin>>str; int in; for(int i=0;i<str.length();i++){ in=str[i]-'0'; v.push_back(in); sets[in].push_back(i); } int n=v.size(); if(n==1){ cout<<"0\n"; return 0; } if(v[0]==v[n-1]){ cout<<"1\n"; return 0; } vector<int> adj[100001]; for(int i=0;i<10;i++){ for(int j=0;j<sets[i].size();j++){ if(sets[i][j]>0) adj[sets[i][j]].push_back(sets[i][j]-1); if(sets[i][j]<n-1) adj[sets[i][j]].push_back(sets[i][j]+1); for(int k=j+1;k<sets[i].size();k++){ if(abs(sets[i][j]-sets[i][k])!=1){ adj[sets[i][j]].push_back(sets[i][k]); adj[sets[i][k]].push_back(sets[i][j]); } } } } queue<int> q; q.push(0); int dist[100001]; bool visited[100001]={false}; dist[0]=0; visited[0]=true; int c=0; while(!q.empty()){ int dq=q.front(); q.pop(); c++; for(int i=0;i<adj[dq].size();i++){ if(visited[adj[dq][i]]==false){ dist[adj[dq][i]]=dist[dq]+1; visited[adj[dq][i]]=true; q.push(adj[dq][i]); } } } cout<<dist[n-1]<<"\n"; return 0; }

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