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  • Ajax does not send the data to my php file [migrated]

    - by Mert METIN
    I try to send my data to php file but does not work. This my ajax file var artistIds = new Array(); $(".p16 input:checked").each(function(){ artistIds.push($(this).attr('id')); }); $.post('/json/crewonly/deleteDataAjax2', { artistIds: artistIds },function(response){ if(response == 'ok') alert('dolu'); elseif (response == 'error') alert('bos'); }); and this is my php public function deleteDataAjax2() { extract($_POST); if (isset($artistIds)) $this->sendJSONResponse('ok'); else $this->sendJSONResponse('error'); } However, my artistIds in php side is null. Why ?

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  • How to build a Singleton-like dependency injector replacement (Php)

    - by Erparom
    I know out there are a lot of excelent containers, even frameworks almost entirely DI based with good strong IoC classes. However, this doesn't help me to "define" a new pattern. (This is Php code but understandable to anyone) Supose we have: //Declares the singleton class bookSingleton { private $author; private static $bookInstance; private static $isLoaned = FALSE; //The private constructor private function __constructor() { $this->author = "Onecrappy Writer Ofcheap Novels"; } //Sets the global isLoaned state and also gets self instance public static function loanBook() { if (self::$isLoaned === FALSE) { //Book already taken, so return false return FALSE; } else { //Ok, not loaned, lets instantiate (if needed and loan) if (!isset(self::$bookInstance)) { self::$bookInstance = new BookSingleton(); } self::$isLoaned = TRUE; } } //Return loaned state to false, so another book reader can take the book public function returnBook() { $self::$isLoaned = FALSE; } public function getAuthor() { return $this->author; } } Then we get the singelton consumtion class: //Consumes the Singleton class BookBorrower() { private $borrowedBook; private $haveBookState; public function __construct() { this->haveBookState = FALSE; } //Use the singelton-pattern behavior public function borrowBook() { $this->borrowedBook = BookSingleton::loanBook(); //Check if was successfully borrowed if (!this->borrowedBook) { $this->haveBookState = FALSE; } else { $this->haveBookState = TRUE; } } public function returnBook() { $this->borrowedBook->returnBook(); $this->haveBookState = FALSE; } public function getBook() { if ($this->haveBookState) { return "The book is loaned, the author is" . $this->borrowedbook->getAuthor(); } else { return "I don't have the book, perhaps someone else took it"; } } } At last, we got a client, to test the behavior function __autoload($class) { require_once $class . '.php'; } function write ($whatever,$breaks) { for($break = 0;$break<$breaks;$break++) { $whatever .= "\n"; } echo nl2br($whatever); } write("Begin Singleton test", 2); $borrowerJuan = new BookBorrower(); $borrowerPedro = new BookBorrower(); write("Juan asks for the book", 1); $borrowerJuan->borrowBook(); write("Book Borrowed? ", 1); write($borrowerJuan->getAuthorAndTitle(),2); write("Pedro asks for the book", 1); $borrowerPedro->borrowBook(); write("Book Borrowed? ", 1); write($borrowerPedro->getAuthorAndTitle(),2); write("Juan returns the book", 1); $borrowerJuan->returnBook(); write("Returned Book Juan? ", 1); write($borrowerJuan->getAuthorAndTitle(),2); write("Pedro asks again for the book", 1); $borrowerPedro->borrowBook(); write("Book Borrowed? ", 1); write($borrowerPedro->getAuthorAndTitle(),2); This will end up in the expected behavior: Begin Singleton test Juan asks for the book Book Borrowed? The book is loaned, the author is = Onecrappy Writer Ofcheap Novels Pedro asks for the book Book Borrowed? I don't have the book, perhaps someone else took it Juan returns the book Returned Book Juan? I don't have the book, perhaps someone else took it Pedro asks again for the book Book Borrowed? The book is loaned, the author is = Onecrappy Writer Ofcheap Novels So I want to make a pattern based on the DI technique able to do exactly the same, but without singleton pattern. As far as I'm aware, I KNOW I must inject the book inside "borrowBook" function instead of taking a static instance: public function borrowBook(BookNonSingleton $book) { if (isset($this->borrowedBook) || $book->isLoaned()) { $this->haveBook = FALSE; return FALSE; } else { $this->borrowedBook = $book; $this->haveBook = TRUE; return TRUE; } } And at the client, just handle the book: $borrowerJuan = new BookBorrower(); $borrowerJuan-borrowBook(new NonSingletonBook()); Etc... and so far so good, BUT... Im taking the responsability of "single instance" to the borrower, instead of keeping that responsability inside the NonSingletonBook, that since it has not anymore a private constructor, can be instantiated as many times... making instances on each call. So, What does my NonSingletonBook class MUST be in order to never allow borrowers to have this same book twice? (aka) keep the single instance. Because the dependency injector part of the code (borrower) does not solve me this AT ALL. Is it needed the container with an "asShared" method builder with static behavior? No way to encapsulate this functionallity into the Book itself? "Hey Im a book and I shouldn't be instantiated more than once, I'm unique"

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  • best practice for initializing class members in php

    - by rgvcorley
    I have lots of code like this in my constructors:- function __construct($params) { $this->property = isset($params['property']) ? $params['property'] : default_val; } Is it better to do this rather than specify the default value in the property definition? i.e. public $property = default_val? Sometimes there is logic for the default value, and some default values are taken from other properties, which was why I was doing this in the constructor. Should I be using setters so all the logic for default values is separated?

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  • form_dropdown in codeigniter

    - by Patrick
    I'm getting a strange behaviour from form_dropdown - basically, when I reload the page after validation, the values are screwed up. this bit generates 3 drop downs with days, months and years: $days = array(0 => 'Day...'); for ($i = 1; $i <= 31; $i++) { $days[] = $i; } $months = array(0 => 'Month...', ); for ($i = 1; $i <= 12; $i++) { $months[] = $i; } $years = array(0 => 'Year...'); for ($i = 2010; $i <= 2012; $i++) { $years[$i] = $i; echo "<pre>"; print_r($years); echo "</pre>";//remove this } $selected_day = (isset($selected_day)) ? $selected_day : 0; $selected_month = (isset($selected_month)) ? $selected_month : 0; $selected_year = (isset($selected_year)) ? $selected_year : 0; echo "<p>"; echo form_label('Select date:', 'day', array('class' => 'left')); echo form_dropdown('day', $days, $selected_day, 'class="combosmall"'); echo form_dropdown('month', $months, $selected_month, 'class="combosmall"'); echo form_dropdown('year', $years, $selected_year, 'class="combosmall"'); echo "</p>"; ...and generates this: <p><label for="day" class="left">Select date:</label><select name="day" class="combosmall"> <option value="0" selected="selected">Day...</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> <option value="19">19</option> <option value="20">20</option> <option value="21">21</option> <option value="22">22</option> <option value="23">23</option> <option value="24">24</option> <option value="25">25</option> <option value="26">26</option> <option value="27">27</option> <option value="28">28</option> <option value="29">29</option> <option value="30">30</option> <option value="31">31</option> </select><select name="month" class="combosmall"> <option value="0" selected="selected">Month...</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> </select><select name="year" class="combosmall"> <option value="0" selected="selected">Year...</option> <option value="2010">2010</option> <option value="2011">2011</option> <option value="2012">2012</option> </select></p> however, when the form is reloaded after validation, the same code above generates this: <!-- days and months... --> <select name="year" class="combosmall"> <option value="0" selected="selected">Year...</option> <option value="1">2010</option> <option value="2">2011</option> <option value="3">2012</option> </select> So basically the value start from 1 instead of 2010. The same happens to days and months but obviously it doesn't make any difference in this particular case as the values would start from 1 anyway. How can I fix this - and why does it happen?

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  • How To Find Out If You are Using HTTPS Without $_SERVER['HTTPS']

    - by Chacha102
    I've seen many tutorials online that says you need to check $_SERVER['HTTPS'] if the server is connection is secured with HTTPS. My problem is that on some of the servers I use, $_SERVER['HTTPS'] is an undefined variable that results in an error. Is there another variable I can check that should always be defined? Just to be clear, I am currently using this code to resolve if it is an HTTPS connection: if(isset($_SERVER['HTTPS'])) { if ($_SERVER["HTTPS"] == "on") { $secure_connection = true; } }

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  • PHP Form: After getting results adding a new table row when entering new information.

    - by Chris
    Hello, Although probarly quite simple, i cannot seem to find the following. The form takes certain data, and then represents the data in a table. Next step i click the hyperlink that takes me back to the form. Now my question is how exactly do i make it possible when filling in the same form again so both results are displayed in the same table? Then filling in a other form with data adds another row and so on. Regards. The code below (pardon me that it is not english). <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-Strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>ExpoFormulier</title> <body> <?php if (!empty($_POST)) { $standnaam = $_POST["standnaam"]; $oppervlakte = $_POST["oppervlakte"]; //value in the form van checkboxes op 1 zetten! $verdieping = isset($_POST["verdieping"]) ? $_POST["verdieping"] : 0; //if checkbox checked value 1 anders 0 $telefoon = isset($_POST["telefoon"]) ? $_POST["telefoon"] : 0; $netwerk = isset($_POST["netwerk"]) ? $_POST["netwerk"] : 0; if (is_numeric($oppervlakte)) { $_SESSION["standnaam"]=$standnaam; $_SESSION["oppervlakte"]=$oppervlakte; $_SESSION["verdieping"]=$verdieping; $_SESSION["telefoon"]=$telefoon; $_SESSION["netwerk"]=$netwerk; header("Location:ExpoOverzicht.php"); //verzenden naar ExpoOverzicht.php dmv header } else { echo "<h1>Foute gegevens, Opnieuw invullen a.u.b</h1>"; } } ?> <form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" id="form1"> <h1>Vul de gegevens in</h1> <table> <tr> <td>Standnaam:</td> <td><input type="text" name="standnaam" size="18"/></td> </tr> <tr> <td>Oppervlakte (in m^2):</td> <td><input type="text" name="oppervlakte" size="6"/></td> </tr> <tr> <td>Verdieping:</td> <td><input type="checkbox" name="verdieping" value="1"/></td> <!--value op 1 zetten voor checkbox! indien checked is value 1 --> </tr> <tr> <td>Telefoon:</td> <td><input type="checkbox" name="telefoon" value="1"/></td> </tr> <tr> <td>Netwerk:</td> <td><input type="checkbox" name="netwerk" value="1"/></td> </tr> <tr> <td><input type="submit" name="verzenden" value="Verzenden"/></td> </tr> </table> </form> Second File: <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-Strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>ExpoOverzicht</title> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <link href="StyleSheetExpo.css" rel="stylesheet" type="text/css" /> </head> <body> <h1>Overzicht van de ingegeven standen in deze sessie</h1> <?php $standnaam = $_SESSION["standnaam"]; $oppervlakte = $_SESSION["oppervlakte"]; $verdieping = $_SESSION["verdieping"]; $telefoon = $_SESSION["telefoon"]; $netwerk = $_SESSION["netwerk"]; $result1 = 0; //telkens declaren anders fout "undefined variable" $result2 = 0; $result3 = 0; $prijsCom = 0; $prijsVerdieping = 0; for ($i=1; $i <= $oppervlakte; $i++) { if($i <= 10) { $tarief1 = 1 * 100; $result1 += $tarief1; } if($i > 10 && $i <= 30) { $tarief2 = 1 * 90; $result2 += $tarief2; } if($i > 30) { $tarief3 = 1 * 80; $result3 += $tarief3; } } $prijsOpp = $result1 + $result2 + $result3; if($verdieping == 1) { $prijsVerdieping = $oppervlakte * 120; } if(($telefoon == 1) || ($netwerk == 1)) // eerst deze OR conditie of anders gebruikt de code alleen nog maar 20 { $prijsCom = 20; } if(($telefoon == 1) && ($netwerk == 1)) { $prijsCom = 30; } $totalePrijs = $prijsOpp + $prijsVerdieping + $prijsCom; echo "<table class=\"tableExpo\">"; echo "<th>Standnaam</th>"; echo "<th>Oppervlakte</th>"; echo "<th>Verdieping</th>"; echo "<th>Telefoon</th>"; echo "<th>Netwerk</th>"; echo "<th>Totale prijs</th>"; echo "<tr>"; echo "<td>".$standnaam."</td>"; echo "<td>".$oppervlakte."</td>"; echo "<td>".$verdieping."</td>"; echo "<td>".$telefoon."</td>"; echo "<td>".$netwerk."</td>"; echo "<td>".$totalePrijs."</td>"; echo "</tr>"; echo "</table>"; ?> <a href="ExpoFormulier.php">Terug naar het formulier</a> </body> </html> </body> </html>

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  • php if array key exists inside multidimentional array

    - by Richard
    how can i check if logo exists in this array called $attachements print_r is below: Array ( [logo] = /home/richar2/public_html/ioagh/images/stories/jreviews/20100510115659_1_img.gif ) when theres no logo, the array print_r's Array ( ) i tried: if (isset($attachments['logo']) ) {..} but the conditional code runs when there is no logo

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  • change password code error.......

    - by shimaTun
    I've created a code to change a password. Now it seem contain an error. When before I fill in the form to change password.the error is: Warning: Cannot modify header information - headers already sent by (output started at C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php:7) in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 126 the code: <?php # userChangePass.php //this page allows logged in user to change their password. $page_title='Change Your Password'; //if no first_name variable exists, redirect the user if(!isset($_SESSION['userid'])){ header("Location: http://" .$_SERVER['HTTP_HOST']. dirname($_SERVER['PHP_SELF'])."/index.php"); ob_end_clean(); exit(); }else{ if(isset($_POST['submit'])) {//handle form. require_once('connectioncomplaint.php'); //connec to the database //check for a new password and match againts the confirmed password. if(eregi ("^[[:alnum:]]{4,20}$", stripslashes(trim($_POST['password1'])))){ if($_POST['password1'] == $_POST['password2']){ $p =escape_data($_POST['password1']); }else{ $p=FALSE; echo'<p><font color="red" size="+1"> Your password did not match the confirmed password!</font></p>'; } }else{ $p=FALSE; echo'<p><font color="red" size="+1"> Please Enter a valid password!</font></p>'; } if($p){ //if everything OK. //make the query $query="UPDATE access SET password=PASSWORD('$p') WHERE userid={$_SESSION['userid']}"; $result=@mysql_query($query);//run the query. if(mysql_affected_rows() == 1) {//if it run ok. //send an email,if desired. echo '<p><b>your password has been changed.</b></p>'; //include('templates/footer.inc');//include the HTML footer. exit(); }else{//if it did not run ok $message= '<p>Your password could not be change due to a system error.We apolpgize for any inconvenience.</p><p>' .mysql_error() .'</p>'; } mysql_close();//close the database connection. }else{//failed the validation test. echo '<p><font color="red" size="+1"> Please try again.</font></p>'; } }//end of the main Submit conditional. } ?> the error at this line:- header("Location: http://" .$_SERVER['HTTP_HOST']. dirname($_SERVER['PHP_SELF'])."/index.php"); please help me guy...

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  • when I click submit it should change the text and update the row something is wrong there

    - by Yousef Altaf
    good morning programers, I have this small code which content a news control panel and I made a submit button there to active or inactive the news row so if I click on this button it should change if it's active it will be inactive it worked but there's something wrong there when I click on item one it updates the last on the table not the first on as it should do. here is the code that I use <?php $getNewsData="select * from news"; $QgetNewsData=$db->query($getNewsData)or die($db->error); $count=mysqli_num_rows($QgetNewsData); while($newsRow = mysqli_fetch_array($QgetNewsData)) { $getActivityStatus=$newsRow['news_activity']; switch($getActivityStatus){ case 1: echo"<input style='color:red; font-weight:bold; background:none; border:0;' name='inactive' type='submit' value='?????' /><input name='inActive' type='hidden' value='".$newsRow['news_id']."'/>"; break; case 0: echo"<input style='color:green; font-weight:bold; background:none; border:0;' name='active' type='submit' value='?????' /><input name='Active' type='hidden' value='".$newsRow['news_id']."'/>"; break;} } if(isset($_POST['inactive'])){ $inActive=$_POST['inActive']; echo $inActive; $updateStatus="UPDATE news SET news_activity=0 WHERE news_id='".$inActive."' "; $QupdateStatus=$db->query($updateStatus)or die($db->error); if($QupdateStatus){ } } if(isset($_POST['active'])){ $Active=$_POST['Active']; echo $Active; $updateStatus="UPDATE news SET news_activity=1 WHERE news_id='".$Active."' "; $QupdateStatus=$db->query($updateStatus)or die($db->error); if($QupdateStatus){ header("Location:CpanelHome.php?id=7"); } } ?> please any idea to solve this problem. Thanks, regards

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  • Strange php problem

    - by M28
    The following code: print_r($_GET); echo '<br />'; echo isset($_GET['logout'])?'yes':'no'; prints: Array ( [logoout] => ) no Why is it printing "no" instend of "yes"?

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  • Wordpress: how to call a plugin function with an ajax call?

    - by Bee
    I'm writing a Wordpress MU plugin, it includes a link with each post and I want to use ajax to call one of the plugin functions when the user clicks on this link, and then dynamically update the link-text with output from that function. I'm stuck with the ajax query. I've got this complicated, clearly hack-ish, way to do it, but it is not quite working. What is the 'correct' or 'wordpress' way to include ajax functionality in a plugin? (My current hack code is below. When I click the generate link I don't get the same output I get in the wp page as when I go directly to sample-ajax.php in my browser.) I've got my code[1] set up as follows: mu-plugins/sample.php: <?php /* Plugin Name: Sample Plugin */ if (!class_exists("SamplePlugin")) { class SamplePlugin { function SamplePlugin() {} function addHeaderCode() { echo '<link type="text/css" rel="stylesheet" href="'.get_bloginfo('wpurl'). '/wp-content/mu-plugins/sample/sample.css" />\n'; wp_enqueue_script('sample-ajax', get_bloginfo('wpurl') . '/wp-content/mu-plugins/sample/sample-ajax.js.php', array('jquery'), '1.0'); } // adds the link to post content. function addLink($content = '') { $content .= "<span class='foobar clicked'><a href='#'>click</a></span>"; return $content; } function doAjax() { // echo "<a href='#'>AJAX!</a>"; } } } if (class_exists("SamplePlugin")) { $sample_plugin = new SamplePlugin(); } if (isset($sample_plugin)) { add_action('wp_head',array(&$sample_plugin,'addHeaderCode'),1); add_filter('the_content', array(&$sample_plugin, 'addLink')); } mu-plugins/sample/sample-ajax.js.php: <?php if (!function_exists('add_action')) { require_once("../../../wp-config.php"); } ?> jQuery(document).ready(function(){ jQuery(".foobar").bind("click", function() { var aref = this; jQuery(this).toggleClass('clicked'); jQuery.ajax({ url: "http://mysite/wp-content/mu-plugins/sample/sample-ajax.php", success: function(value) { jQuery(aref).html(value); } }); }); }); mu-plugins/sample/sample-ajax.php: <?php if (!function_exists('add_action')) { require_once("../../../wp-config.php"); } if (isset($sample_plugin)) { $sample_plugin->doAjax(); } else { echo "unset"; } ?> [1] Note: The following tutorial got me this far, but I'm stumped at this point. http://www.devlounge.net/articles/using-ajax-with-your-wordpress-plugin

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  • live search with Jquery

    - by user272899
    Hello! I am trying to implement a live search on my site. I am using a script somebody has already created. http://www.reynoldsftw.com/2009/03/live-mysql-database-search-with-jquery/ I have got the Jquery, css, html working correctly but am having troubles with the php. I need to change it to contain my database information but everytime I do I recieve an error: Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\wamp\www\search.php on line 33 These are the details of my database: database name: development table name: links Columns: id, sitename, siteurl, description, category This is the php script <?php $dbhost = "localhost"; $dbuser = "root"; $dbpass = "password"; $dbname = "links"; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); mysql_select_db($dbname); if(isset($_GET['query'])) { $query = $_GET['query']; } else { $query = ""; } if(isset($_GET['type'])) { $type = $_GET['type']; } else { $query = "count"; } if($type == "count") { $sql = mysql_query("SELECT count(url_id) FROM urls WHERE MATCH(url_url, url_title, url_desc) AGAINST('$query' IN BOOLEAN MODE)"); $total = mysql_fetch_array($sql); $num = $total[0]; echo $num; } if($type == "results") { $sql = mysql_query("SELECT url_url, url_title, url_desc FROM urls WHERE MATCH(url_url, url_title, url_desc) AGAINST('$query' IN BOOLEAN MODE)"); while($array = mysql_fetch_array($sql)) { $url_url = $array['url_url']; $url_title = $array['url_title']; $url_desc = $array['url_desc']; echo "<div class=\"url-holder\"><a href=\"" . $url_url . "\" class=\"url-title\" target=\"_blank\">" . $url_title . "</a> <div class=\"url-desc\">" . $url_desc . "</div></div>"; } } mysql_close($conn); ?> Can anybody help me input this database info correctly? I have tried many times but keep getting an error. Thanks in advance.

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  • Anyway that I can get the values of a PHP array through ajax?

    - by Jerry
    Hi All, I am trying to build a shopping cart site. When a user click add to cart image on the product page, The product title will show a "The product is in your cart" text without reloading the page. I am using session and ajax but no luck so far. I appreciate any helps. My html cold <table id="<?php echo $productId; ?>" width="594" border="0" cellpadding="5" cellspacing="0"> <tr> <td><img src="<?php echo "$brandImage"; ?></td> <td <?php echo $productName; ?> //The "The product is in your cart" will be showed here</td> </tr> <tr> <td><a class="addToCart" href="javascript:void(0);" onclick="addToCart(<?php echo $productId?>)"> </td> My Javascript file (addToCart.js) function addToCart(productId){ var url="addToCart.php"; url=url+"?productId="+productId; url=url+"&sid="+Math.random(); $.post( url, function(responseText){ alert(responseText); //I wish I can get productData value from addToCart.php }, "html" ) My php file (addToCart.php) <?php SESSION_START(); $productId=$_GET['productId']; $cart=$_SESSION['cart']; if(isset($cart)){ $cart.=",".$productId; $product=explode(',',$cart); $totalItem=count($product); }else{ $cart=$productId; $totalItem=1; }; $productData=array(); foreach($product as $id){ $productData[$id]=(isset($productData[$id])) ? $productData[$id]+1 :1; }; $_SESSION['cart']=$cart; //print_r($productData); echo $productData; //Not sure what to do to send $productData back to my addToCart.js variable ?> I tried to make the code look simple. Any suggestion will be a great help. Thanks

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  • Drupal 7: File field causes error with Dependable Dropdowns

    - by LoneWolfPR
    I'm building a Form in a module using the Form API. I've had a couple of dependent dropdowns that have been working just fine. The code is as follows: $types = db_query('SELECT * FROM {touchpoints_metric_types}') -> fetchAllKeyed(0, 1); $types = array('0' => '- Select -') + $types; $selectedType = isset($form_state['values']['metrictype']) ? $form_state['values']['metrictype'] : 0; $methods = _get_methods($selectedType); $selectedMethod = isset($form_state['values']['measurementmethod']) ? $form_state['values']['measurementmethod'] : 0; $form['metrictype'] = array( '#type' => 'select', '#title' => t('Metric Type'), '#options' => $types, '#default_value' => $selectedType, '#ajax' => array( 'event' => 'change', 'wrapper' => 'method-wrapper', 'callback' => 'touchpoints_method_callback' ) ); $form['measurementmethod'] = array( '#type' => 'select', '#title' => t('Measurement Method'), '#prefix' => '<div id="method-wrapper">', '#suffix' => '</div>', '#options' => $methods, '#default_value' => $selectedMethod, ); Here are the _get_methods and touchpoints_method_callback functions: function _get_methods($selected) { if ($selected) { $methods = db_query("SELECT * FROM {touchpoints_m_methods} WHERE mt_id=$selected") -> fetchAllKeyed(0, 2); } else { $methods = array(); } $methods = array('0' => "- Select -") + $methods; return $methods; } function touchpoints_method_callback($form, &$form_state) { return $form['measurementmethod']; } This all worked fine until I added a file field to the form. Here is the code I used for that: $form['metricfile'] = array( '#type' => 'file', '#title' => 'Attach a File', ); Now that the file is added if I change the first dropdown it hangs with the 'Please wait' message next to it without ever loading the contents of the second dropdown. I also get the following error in my JavaScript console: "Uncaught TypeError: Object function (a,b){return new p.fn.init(a,b,c)} has no method 'handleError'" What am I doing wrong here?

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  • Can't get message body of certain emails from inbox using the Zend framework?

    - by Ali
    Hi guys I'm trying to read through an email inbox for my application - I'm using the zend framework here. The problem is that I'm unable to retrieve the message body for certain emails. The following is my code as to how I'm doing this: $mail = new Zend_Mail_Storage_Imap($mail_options); $all_messages = array(); $page = isset($_GET['page'])?$_GET['page']:1; $limit = isset($_GET['limit'])?$_GET['limit']:20; $offset = (($page-1)*$limit)+1; $end = ($page*$limit)>$c?$c:($page*$limit); for ($i=$offset;$i<=$end;$i++){ $h2t = new html2text(); $h2t->set_allowed_tags('<a>'); if(!$mail[$i]) break; else{ $one_message = $mail->getMessage($i); $one_message->id = $i; $one_message->UID = $mail->getUniqueId($i); $one_message->parts = array(); $one_message->body = ''; $count = 1; foreach (new RecursiveIteratorIterator($mail->getMessage($i)) as $ii=>$part) { try { $tpart = $part; //$tpart->_content = ''; $one_message->parts[$count] = $tpart; $count++; // check for html body if (strtok($part->contentType, ';') == 'text/html') { $b = $part->getContent(); if($part->contentTransferEncoding == 'quoted-printable') $b = quoted_printable_decode($b); $one_message->html_body = $b; $h2t->set_html($b); $one_message->body = $h2t->get_text(); } //check for text body if (strtok($part->contentType, ';') == 'text/plain') { $b = $part->getContent(); if($part->contentTransferEncoding == 'quoted-printable') $b = quoted_printable_decode($b); $one_message->text_body = $b; $one_message->body = $b;//$part->getContent(); } } catch (Zend_Mail_Exception $e) { // ignore } } $all_messages[] = $one_message; } } The problem is that randomly some messages don't return even a textbody or an html body. Even though if I check using a webvmail client those emails have a message body as well. WHat am I missing here?

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  • PHP - stop calling on refresh

    - by Ross
    I need my class to create a new blank record when the page opens up the problem I am having is when the page refreshes it keeps incrementing by 1, if I write a session to keep the variable the next time I go back it does not increment. Any ideas? if(!isset($_POST['record_no'])) { echo $_POST['record_no'] = $projects->insert__blank_project(); } else { print "already Set"; }

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  • Dynamic Comparison Operators in PHP

    - by BenTheDesigner
    Hi All Is it possible, in any way, to pass comparison operators as variables to a function? I am looking at producing some convenience functions, for example (and I know this won't work): function isAnd($var, $value, $operator = '==') { if(isset($var) && $var $operator $value) return true; } if(isAnd(1, 1, '===')) echo 'worked'; Thanks in advance.

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  • Can't retrieve more than 2 gmail messages using Zend framework imap access - server dies - doens't r

    - by Ali
    Hi guys I'm working on a google apps application. Basically I've set it up so users can add multiple gmail addresses and check on their inboxes in the application. It works fine with a google apps email address however when I add a gmail address it just dies out. I'm using this code here: $mail = new Zend_Mail_Storage_Imap($mail_options); $all_messages = array(); $page = isset($_GET['page'])?$_GET['page']:1; $limit = isset($_GET['limit'])?$_GET['limit']:20; $offset = (($page-1)*$limit)+1; $end = ($page*$limit)>$c?$c:($page*$limit); for ($i=$offset;$i<=$end;$i++){ $h2t = new html2text(); $h2t->set_allowed_tags('<a>'); if(!$mail[$i]) break; else{ $one_message = $mail->getMessage($i); $one_message->id = $i; $one_message->UID = $mail->getUniqueId($i); $one_message->parts = array(); $one_message->body = ''; $count = 1; foreach (new RecursiveIteratorIterator($mail->getMessage($i)) as $ii=>$part) { try { $tpart = $part; //$tpart->_content = ''; $one_message->parts[$count] = $tpart; $count++; // check for html body if (strtok($part->contentType, ';') == 'text/html') { $b = $part->getContent(); if($part->contentTransferEncoding == 'quoted-printable') $b = quoted_printable_decode($b); $one_message->html_body = $b; $h2t->set_html($b); $one_message->body = $h2t->get_text(); } //check for text body if (strtok($part->contentType, ';') == 'text/plain') { $b = $part->getContent(); if($part->contentTransferEncoding == 'quoted-printable') $b = quoted_printable_decode($b); $one_message->text_body = $b; $one_message->body = $b;//$part->getContent(); } } catch (Zend_Mail_Exception $e) { // ignore } } $all_messages[] = $one_message; } } No matter what the emails it dies out on retrieving just 2 emails... whats going on here?

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  • Serialize checkbox array, also get checkboxes with off-value

    - by guzh
    Hi, I was wondering if this is possible. The serialize-string will be inserted in a mySQL-database, so it would be fine if all checkboxes would be inserted and not only the ones that is ticked(on). it's possible to make on column in the database for each of the checkboxes, and use this if/else-statement: if(isset($_GET['checkbox'])) { // It's checked! } else { // not checked! } but its a bit unappropriate...

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  • cleaner php code

    - by vick
    if (isset($_GET['sort_by']) && strlen($_GET['sort_by']) > 0) { $sort_by = $_GET['sort_by']; } else { $sort_by = 'desc'; } how can I rewrite that so it looks cleaner and has less lines.. I love one liners hehe

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  • change password code error

    - by ejah85
    I've created a code to change a password. Now it seem contain an error. When I fill in the form to change password, and click save the error message: Warning: mysql_real_escape_string() expects parameter 2 to be resource, null given in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 103 Warning: mysql_real_escape_string() expects parameter 2 to be resource, null given in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 103 I really don’t know what the error message means. Please guys. Help me fix it. Here's is the code: <?php session_start(); ?> <?php # change password.php //set the page title and include the html header. $page_title = 'Change Your Password'; //include('templates/header.inc'); if(isset($_POST['submit'])){//handle the form require_once('connectioncomplaint.php');//connect to the db. //include "connectioncomplaint.php"; //create a function for escaping the data. function escape_data($data){ global $dbc;//need the connection. if(ini_get('magic_quotes_gpc')){ $data=stripslashes($data); } return mysql_real_escape_string($data, $dbc); }//end function $message=NULL;//create the empty new variable. //check for a username if(empty($_POST['userid'])){ $u=FALSE; $message .='<p> You forgot enter your userid!</p>'; }else{ $u=escape_data($_POST['userid']); } //check for existing password if(empty($_POST['password'])){ $p=FALSE; $message .='<p>You forgot to enter your existing password!</p>'; }else{ $p=escape_data($_POST['password']); } //check for a password and match againts the comfirmed password. if(empty($_POST['password1'])) { $np=FALSE; $message .='<p> you forgot to enter your new password!</p>'; }else{ if($_POST['password1'] == $_POST['password2']){ $np=escape_data($_POST['password1']); }else{ $np=FALSE; $message .='<p> your new password did not match the confirmed new password!</p>'; } } if($u && $p && $np){//if everything's ok. $query="SELECT userid FROM access WHERE (userid='$u' AND password=PASSWORD('$p'))"; $result=@mysql_query($query); $num=mysql_num_rows($result); if($num == 1){ $row=mysql_fetch_array($result, MYSQL_NUM); //make the query $query="UPDATE access SET password=PASSWORD('$np') WHERE userid=$row[0]"; $result=@mysql_query($query);//run the query. if(mysql_affected_rows() == 1) {//if it run ok. //send an email,if desired. echo '<p><b>your password has been changed.</b></p>'; include('templates/footer.inc');//include the HTML footer. exit();//quit the script. }else{//if it did not run OK. $message= '<p>Your password could not be change due to a system error.We apolpgize for any inconvenience.</p><p>' .mysql_error() .'</p>'; } }else{ $message= '<p> Your username and password do not match our records.</p>'; } mysql_close();//close the database connection. }else{ $message .='<p>Please try again.</p>'; } }//end oh=f the submit conditional. //print the error message if there is one. if(isset($message)){ echo'<font color="red">' , $message, '</font>'; } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <body> <script language="JavaScript1.2">mmLoadMenus();</script> <table width="604" height="599" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td height="130" colspan="7"><img src="images/banner(E-Complaint)-.jpg" width="759" height="130" /></td> </tr> <tr> <td width="100" height="30" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="160" bgcolor="#ABD519"> <?php include "header.php"; ?>&nbsp;</td> </tr> <tr> <td colspan="7" bgcolor="#FFFFFF"> <fieldset><legend> Enter your information in the form below:</legend> <p><b>User ID:</b> <input type="text" name="username" size="10" maxlength="20" value="<?php if(isset($_POST['userid'])) echo $_POST['userid']; ?>" /></p> <p><b>Current Password:</b> <input type="password" name="password" size="20" maxlength="20" /></p> <p><b>New Password:</b> <input type="password" name="password1" size="20" maxlength="20" /></p> <p><b>Confirm New Password:</b> <input type="password" name="password2" size="20" maxlength="20" /></p> </fieldset> <div align="center"> <input type="submit" name="submit" value="Change My Password" /></div> </form><!--End Form--> </td> </tr> </table> </body> </html>

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  • How to Ignore query string in a URL?

    - by jartaud
    Hello I have something like this: if(isset($_POST['btnProm'])){ $idads = mysql_real_escape_string($_POST['idAds']); require_once("adPromFrm.php"); } When a button is pressed, a form will appear.... When i refresh the page, the form doesn't disappear, but when i click a link with a query string (thisPage.php?lang=fr...), the form disappears. I know i m asking the form only if the button is pressed, but how can i ignore the query string.

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