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  • how to pass session_id() throught out the php pages?

    - by Piyush
    when user clicks on login button(index.php) I am calling chechlogin.php where I am checking loginId an password as- if($count==1) { // Register $myusername, $mypassword and redirect to file "login_success.php" session_register("myusername"); session_register("mypassword"); $_SESSION['UserId'] = $myusername; $_session['SessionId'] = session_id(); header("location:LoggedUser.php"); } in LiggedUser.php <?php session_start(); //starting session if (!isset($_SESSION['SessionId']) || $_SESSION['SessionId'] == '') { header("location:index.php"); } ? Problem: It is always going back to index.php page although I am entering right userid and password.I think session_id() is not working properly or ??

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  • SQL: Using a CASE Statement to update 1000 rows at once

    - by SoLoGHoST
    Ok, I would like to use a CASE STATEMENT for this, but I am lost with this. Basically, I need to update a ton of rows, but just on the "position" column. I need to update all "position" values from 0 - count(position) for each id_layout_position column per id_layout column. OK, here is a pic of what the table looks like: Now let's say I delete the circled row, this will remove position = 2 and give me: 0, 1, 3, 5, 6, 7, and 4. But I want to add something at the end now and make sure that it has the last possible position, but the positions are already messed up, so I need to reorder them like so before I insert the new row: 0, 1, 2, 3, 4, 5, 6. But it must be ordered by lowest first. So 0 stays at 0, 1 stays at 1, 3 gets changed to 2, the 4 at the end gets changed to a 3, 5 gets changed to 4, 6 gets changed to 5, and 7 gets changed to 6. Hopefully you guys get the picture now. I'm completely lost here. Also, note, this table is tiny compared to how fast it can grow in size, so it needs to be able to do this FAST, thus I was thinking on the CASE STATEMENT for an UPDATE QUERY. Here's what I got for a regular update, but I don't wanna throw this into a foreach loop, as it would take forever to do it. I'm using SMF (Simple Machines Forums), so it might look a little different, but the idea is the same, and CASE statements are supported... $smcFunc['db_query']('', ' UPDATE {db_prefix}dp_positions SET position = {int:position} WHERE id_layout_position = {int:id_layout_position} AND id_layout = {int:id_layout}', array( 'position' => $position++, 'id_layout_position' => (int) $id_layout_position, 'id_layout' => (int) $id_layout, ) ); Anyways, I need to apply some sort of CASE on this so that I can auto-increment by 1 all values that it finds and update to the next possible value. I know I'm doing this wrong, even in this QUERY. But I'm totally lost when it comes to CASES. Here's an example of a CASE being used within SMF, so you can see this and hopefully relate: $conditions = ''; foreach ($postgroups as $id => $min_posts) { $conditions .= ' WHEN posts >= ' . $min_posts . (!empty($lastMin) ? ' AND posts <= ' . $lastMin : '') . ' THEN ' . $id; $lastMin = $min_posts; } // A big fat CASE WHEN... END is faster than a zillion UPDATE's ;). $smcFunc['db_query']('', ' UPDATE {db_prefix}members SET id_post_group = CASE ' . $conditions . ' ELSE 0 END' . ($parameter1 != null ? ' WHERE ' . (is_array($parameter1) ? 'id_member IN ({array_int:members})' : 'id_member = {int:members}') : ''), array( 'members' => $parameter1, ) ); Before I do the update, I actually have a SELECT which throws everything I need into arrays like so: $disabled_sections = array(); $positions = array(); while ($row = $smcFunc['db_fetch_assoc']($request)) { if (!isset($disabled_sections[$row['id_group']][$row['id_layout']])) $disabled_sections[$row['id_group']][$row['id_layout']] = array( 'info' => $module_info[$name], 'id_layout_position' => $row['id_layout_position'] ); // Increment the positions... if (!is_null($row['position'])) { if (!isset($positions[$row['id_layout']][$row['id_layout_position']])) $positions[$row['id_layout']][$row['id_layout_position']] = 1; else $positions[$row['id_layout']][$row['id_layout_position']]++; } else $positions[$row['id_layout']][$row['id_layout_position']] = 0; } Thanks, I know if anyone can help me here it's definitely you guys and gals... Anyways, here is my question: How do I use a CASE statement in the first code example, so that I can update all of the rows in the position column from 0 - total # of rows found, that have that id_layout value and that id_layout_position value, and continue this for all different id_layout values in that table? Can I use the arrays above somehow? I'm sure I'll have to use the id_layout and id_layout_position values for this right? But how can I do this? Ok, guy, I get an error, saying "Hacking Attempt" with the following code: // Updating all positions in here. $smcFunc['db_query']('', ' SET @pos = 0; UPDATE {db_prefix}dp_positions SET position=@pos:=@pos+1 ORDER BY id_layout_position, position', array( ) ); Am I doing something wrong? Perhaps SMF has safeguards against this approach?? Perhaps I need to use a CASE STATEMENT instead?

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  • how read data from file and execute to MYSQL?

    - by Mahran Elneel
    i create form to load sql file and used fopen function top open file and read this but when want to execute this data to database not work? what is wrong in my code????????????? $ofile = trim(basename($_FILES['sqlfile']['name'])); $path = "sqlfiles/".$ofile; //$data = settype($data,"string"); $file = ""; $connect = mysql_connect('localhost','root',''); $selectdb = mysql_select_db('files'); if(isset($_POST['submit'])) { if(!move_uploaded_file($_FILES['sqlfile']['tmp_name'],"sqlfiles/".$ofile)) { $path = ""; } $file = fopen("sqlfiles/".$ofile,"r") or exit("error open file!"); while (!feof($file)) { $data = fgetc($file); settype($data,"string"); $rslt = mysql_query($data); print $data; } fclose($file); }

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  • How to refresh site if $_SESSION variable has changed

    - by 4ndro1d
    I'm writing in my $_SESSION variable from a database, when i clicked a link. public function getProjectById($id){ $query="SELECT * FROM projects WHERE id=\"$id\""; $result=mysql_query($query); $num=mysql_numrows($result); while ($row = mysql_fetch_object($result)) { $_SESSION['projectid'] = $row->id; $_SESSION['projecttitle'] = $row->title; $_SESSION['projectinfo'] = $row->info; $_SESSION['projecttext'] = $row->text; $_SESSION['projectcategory'] = $row->category; } } Now my variable is overwritten and I want to show these variables in my index.php like this: <div id="textContent"> <?php if(isset($_SESSION['projecttext']) && !empty($_SESSION['projecttext'])) { echo $_SESSION['projecttext']; }else { echo 'No text'; } ?></div> But of course, my page will not refresh automatically. How can I do that?

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  • php session_start() warning

    - by Eniasharmila Karunakaran
    I'm new to php.. Im trying to get value from session. Below is my code. Set session in login page session_start(); $_SESSION["username"] = $username ; $_SESSION["password"] = $password ; $_SESSION["companycode"] = $companycode; Get the session if(! isset($_SESSION)) session_start(); $a=$_SESSION["companycode"]; echo $a; But i got the warning in my page: Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at C:\xampp\htdocs\lucent\clientlogin.php:216) in C:\xampp\htdocs\lucent\clientlogin.php on line 219 Please help. Thanks

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  • uploading different types of files mostly pdfs

    - by Anders Kitson
    I would like to upload different types of files pressumably pdfs to a certain directory I am currently trying to get this one script working that I found on snipplr but it is not working as I assumed it would, here is my code. <?php if( isset($_POST['submit']) ) { $target_path = "../downloads/"; $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name'])." has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } } ?> <form action="<?php echo $_SERVER['PHP_SELF'];?>" method="post" enctype="multipart/form-data"> <input type="file"> <input type="submit" name="submit" value="submit" /> </form>

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  • Any ideas why this wont print out

    - by stan
    Revising for php and cant seem to get this to print the values out that i want Any ideas? Thanks <form action="revision.php" method="GET"> <input type=“text” name=“number[]”/> <input type=“text” name=“number[]”/> <input type=“text” name=“number[]”/> <input type=“text” name=“number[]”/> <input type=“text” name=“number[]”/> <input type="Submit" name="Calcuate"/> </form> <?php if(isset($_GET['number'])){ $amount = count($number); for($i=0; $i < $amount; $i++){ echo $number[$i]; } } ?>

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  • Help Fix a bug - Unexpected T_STRING

    - by thecoshman
    So I have just rebuilt my server, just on local network. Stick my site back on it, try to run the code, and I get a anice T_STRING error. This is all very strange, as I have not changed the code :S <?php $window_ID = -1; if(isset($_POST["window_ID"]) AND $_POST["window_ID"] != null){ $window_ID = trim($_POST["window_ID"]); } ?> This is the start of the file, apter this rather loverly snipit of PHP the rest is just XMl, yet on line 6 appertnlty there is an unexpected T_STRING, which is strange considering all that is on that line is the ?>, then the XML starts up... Any one got any ideas what has gone wrong here? Any chance it ould be magic quotes? I had turned it of before, but I want to now update my code to check for the magic quotes and avoid its stupid actions.

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  • Jquery and CSS switching - is this possible?

    - by Joe
    I build a css file using PHP which allows me to easily customize the color of many elements. Is it possible for me to "rebuild" the stylesheet and apply it to the page in the DOM using Jquery? eg. <?php if (isset($_POST['mycolor'])){ $myColor = $_POST['mycolor']; } else { $myColor = "blue"; } ?> <style type='text/css'> .style1{ color:<?php $myColor;?>; } </style> Now on my page I have a link you can click called "change color to red" and when you click "red" it does a $.post to my php script, which rebuilds the css including .style1 - and allows the page to change the stylesheet. I haven't tested this but would it even work? If I echo'ed out the new stylesheet after the post into the dom... would it even apply to the page?

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  • Cannot add or update a child row: a foreign key constraint fails

    - by myaccount
    // Getting the id of the restaurant to which we are uploading the pictures $restaurant_id = intval($_GET['restaurant-id']); if(isset($_POST['submit'])) { $tmp_files = $_FILES['rest_pics']['tmp_name']; $target_files = $_FILES['rest_pics']['name']; $tmp_target = array_combine($tmp_files, $target_files); $upload_dir = $rest_pics_path; foreach($tmp_target as $tmp_file => $target_file) { if(move_uploaded_file($tmp_file, $upload_dir."/".$target_file)) { $sql = sprintf(" INSERT INTO rest_pics (branch_id, pic_name) VALUES ('%s', '%s')" , mysql_real_escape_string($restaurant_id) , mysql_real_escape_string(basename($target_file))); $result = mysql_query($sql) or die(mysql_error()); } I get the next error: Cannot add or update a child row: a foreign key constraint fails (rest_v2.rest_pics, CONSTRAINT rest_pics_ibfk_1 FOREIGN KEY (branch_id) REFERENCES rest_branches (branch_id) ON DELETE CASCADE ON UPDATE CASCADE However, this error totally disappears and everything goes well when I put directly the restaurant id (14 for example) instead of $restaurant_id variable in the sql query. The URL am getting the id from is: http://localhost/rest_v2/public_html/admin/add-delete-pics.php?restaurant-id=2 Any help please?

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  • How to get the age from a birthdate using PHP & MySQL?

    - by TaG
    I ask my users for their birthdate and store it in my database in the following way $month $day $year output May 6 1901 but I was wondering how can I get the age from the stored birthdate using PHP & MySQL? Here is the PHP code. if (isset($_POST['submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $month_options = array("Month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"); $day_options = array("Day", "1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23", "24", "25", "26", "27", "28", "29", "30", "31"); $month = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['month']))); $day = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['day']))); $year = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['year']))); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, month, day, year) VALUES ('$user_id', '$month', '$day', '$year')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET month = '$month', day = '$day', year = '$year' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } Here is the html. <form method="post" action="index.php"> <fieldset> <ul> <li><label>Date of Birth: </label> <label for="month" class="hide">Month: </label> <?php // month options echo '<select name="month" id="month">' . "\n"; foreach($month_options as $option) { if ($option == $month) { echo '<option value="' . stripslashes(htmlentities(strip_tags($option))) . '" selected="selected">' . stripslashes(htmlentities(strip_tags($option))) . '</option>' . "\n"; } else { echo '<option value="'. stripslashes(htmlentities(strip_tags($option))) . '">' . stripslashes(htmlentities(strip_tags($option))) . '</option>'."\n"; } } echo '</select>'; ?> <label for="day" class="hide">Day: </label> <?php // day options echo '<select id="day" name="day">' . "\n"; foreach($day_options as $option) { if ($option == $day) { echo '<option value="' . stripslashes(htmlentities(strip_tags($option))) . '" selected="selected">' . stripslashes(htmlentities(strip_tags($option))) . '</option>' . "\n"; } else { echo '<option value="'. stripslashes(htmlentities(strip_tags($option))) . '">' . stripslashes(htmlentities(strip_tags($option))) . '</option>'."\n"; } } echo '</select>'; ?> <label for="year" class="hide">Year: </label><input type="text" name="year" id="year" size="4" maxlength="4" value="<?php if (isset($_POST['year'])) { echo stripslashes(htmlentities(strip_tags($_POST['year']))); } else if(!empty($year)) { echo stripslashes(htmlentities(strip_tags($year))); } ?>" /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • form Validation white page not showing errors

    - by Jess McKenzie
    In the example below I am wanting to do all of the 'safety' checks on the $_POST variables but it seems when I click submit I get a white page why? I am wanting it to show the errors etc Form Process: /* check if the form is submitted */ if (isset($_POST['submitButton'])) { $fullName = $_POST['fullname']; if($_SERVER['REQUEST_METHOD'] == 'POST' && !empty($fullName)) { if (!ctype_alpha(str_replace(array("'", "-"), "",$fullName))) { $errorfullName .= '<span class="errorfullName">*First name should be alpha characters only.</span>'; } if (strlen($fullName) < 3 OR strlen($fullName) > 40) { $errorfullName .= '<span class="errorfullName">*First name should be within 3-40 characters long.</span>'; } } }

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  • session set for some Actions in Zend framework

    - by user202127
    I'm working on a website , in CV part users have some articles that only logged in users can download them.I want to make changes to the log in Action or preDispatch() to set session for guess users to download the articles, can some one tell me how it can be or give me some reference links. here is my preDispatch(): public function preDispatch() { $userInfo=$this->_auth->getStorage()->read(); $identity= $this->_auth->getIdentity(); if(!$this->_auth->hasIdentity()) { return $this->_helper->redirector('login','login'); } if(!isset($userInfo["member_id"]) || strlen($userInfo["member_id"])==0) { return $this->_helper->redirector('forbidden','login'); } $this->_accessType=2; }

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  • What's the best way to debug AJAX to PHP calls?

    - by Jascha
    I'm having a miserable time debugging one small function on my new project. Essentially I'm having a user log out via an AJAX call to my log out script on my server called "userfFunctions.php" I'm using AJAX so that I don't have the headache of writing more regex to match my mod_rewrites. Anyway, every so often, it seems as though my Post data just flat out dies and since the PHP is running behind the scenes, I feel like I have no way of finding out where the data flow is being disrupted. BTW This function works 19 hrs of the day. Here is the javascript function: function logOut(){ var data = new Object; data.log_out = true; $.ajax({ type: 'POST', url: 'http://www.mydomain.com/User_Validator', //<-- redirects to userFunctions.php data: data, success: function(data) { alert(data); // <-- a response is triggered but with no response data! } }); } the php side: if(isset($_POST['log_out'])){ echo 'alert this!'; } here is my awesome response:

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  • How to detect padding on an integer and treat it as a string?

    - by Sirber
    I have this function to prepare variable to be used in a SQL query: function sqlize($mInput) { if (!isset($mInput)) $mInput = "null"; elseif (strtolower($mInput) == "null") { } elseif (is_numeric($mInput)) { } elseif (is_string($mInput)) { $mInput = trim($mInput); $mInput = addslashes($mInput); $mInput = '"' . $mInput . '"'; } else $mInput = "null"; return $mInput; } I have a string "0004", which is going in a "varchar field", is cought by is_numeric, and is saved as "4" and not "0004". Is there a way to detect the padding and process it as a string? Thank you!

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  • form not showing for empty records

    - by Chris Hodges
    I have a relatively simple PHP page called editcustomers with 3 columns. The problem I'm having is that the form will show when there is a record in the database and the fields will be populated with that info. When no such records exists, the form is not even shown, eliminating the possibility to insert a record. My page layout is as follows: Column 1 shows a form containing customer information, allowing it to be edited. Column 2 allows ordering of products and showing how many products were ordered Column 3 shows the total paid so far, and the total owing. The code for the page I have at present: <html> <?php $id = $_GET['id']; require_once('connect.php'); $sth = $dbh->query("SELECT * FROM users where id = '$id';"); $sth->setFetchMode(PDO::FETCH_ASSOC); $eth = $dbh->query("SELECT * FROM purchases where id = '$id';"); $eth->setFetchMode(PDO::FETCH_ASSOC); ?> <div id="main"> <div id="left"> <form name="custInfo" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custInfo"/> <?php while($row = $sth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="mid"> <form name="custCosts" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custCosts"/> <?php while($row = $eth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="amountOwed" size ="30" value=" <?php echo $row["amountOwed"]?>"/> <p><input type = "text" name ="numAaa" size ="30" value="<?php echo $row["numAaa"]?>"/> <p><input type = "text" name ="numBbb" size ="30" value="<?php echo $row["numBbb"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="right"> <b>Total Balance</b> <p> Money owed: </p> <p> aaa total: </p> <p> bbb total: </p> <p> Total: </p> <input type = "text" name ="pay" size ="20" /></p> <input type="submit" value="Make Payment" /> </div> <?php $dbh =null; ?> </body> </html> And the code for all the database trickery: <?php require_once 'connect.php'; $formType = $_POST['formType']; $id = $_POST['id']; $firstName = $_POST['firstName']; $lastName = $_POST['lastName']; $country = $_POST['country']; $amountOwed = $_POST['amountOwed ']; $numAaa = $_POST['numAaa']; $numBbb = $_POST['numBbb']; if(empty($_POST['id'])) { $sth = $dbh->prepare("INSERT INTO customers (firstName, lastName, country) VALUES ('$firstName', '$lastName', '$country')"); $sth->execute(); } elseif(!empty($_POST['id']) && !isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("UPDATE customers SET firstName = '$firstName', lastName = '$lastName', country = '$country' WHERE id = '$id'"); $sth->execute(); }elseif(!empty($_POST['id']) && isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("INSERT INTO purchases (id, amountOwed, numAaa, numBbb) VALUES ('$id', '$amountOwed', '$numAaa', '$numBbb'"); $sth->execute(); }elseif(!empty($_POST['id']) && $_POST['formType'] == 'guestCosts'){ $sth = $dbh->prepare("UPDATE purchases SET amountOwed= '$amountOwed', numAaa = '$numAaa', numBbb= '$numBbb' WHERE id = '$id'"); $sth->execute(); } $dbh =null; ?> Why does the form not even display if there is no record? An error or something I might understand....but the form is still in the HTML and should still be being output, from what I can see. Why is this not the case?

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  • The way to send duplicate email to the user?

    - by Josephine
    I made simple email in wordpress but it would only send email to the administrator email. I need to find the way to send duplicate email with Thanks to the user. $emailTo = get_option('tz_email'); if (!isset($emailTo) || ($emailTo == '') ){ $emailTo = get_option('admin_email'); } $subject = 'I Have A Question to Ask from '.$name; $body = "Name: $name \n\nEmail: $email \n\nPhone: $phone \n\nComments: $comments"; $headers = 'From: '.$name.' ' . "\r\n" . 'Reply-To: ' . $email; wp_mail($emailTo, $subject, $body, $headers); $emailSent = true; } Insight is appreciated. Thank you.

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  • A beginner's question...How do I use $_POST instead of $_GET? (PHP)

    - by ggfan
    Okay, for all my coding so far I been using GETs and only $_POST on the same script. Ex: profile.php would show all the posts an user made and under each of their post, they can edit their post. The way I been using it is through $_GETs. So.. //this is the link users click to edit their post echo '<td><a href="editad.php?posting_id='.$row3['posting_id'].' ">Edit</a>'; //on the editad.php $posting_id=$_GET['posting_id']; if (isset($posting_id)){ //show all the forms, sqls to do the editing } else{ //if the $_GET hasn't been set echo "You have not specified which ad to edit. Please go back"; } How do I do this via POST? Thanks :)

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  • If-statement: how to pull 2nd GET variable

    - by arsoneffect
    How do I get this to pull my 2nd variable? (I already have a switch setup) <body id="<?php if (! isset($_GET['page'])) { echo "home"; } else { $_GET['page']; echo $page; } ?>"> I have a switch statement that pulls the pages from index.php?page=##### and I have just added this part to my switch: index.php?page=####&section=##### Right now, if I am on page=photos, my code ends up being: <body id="photos"> I need to make it so that if any link has the "sections" variable on it like this page=photos&section=cars it uses the same ID: <body id="photos">

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  • Creating files on a time (hourly) basis

    - by Yaniv
    Hi there, I experimenting with twitter streaming API, I use Phirehose to connect to twitter and fetch the data but having problems storing it in files for further processing. Basically what I want to do is to create a file named date("YmdH")."."txt" for every hour of connection. Here is how my code looks like right now (not handling the hourly change of files) public function enqueueStatus($status) $data = json_decode($status,true); if(isset($data['text'])/*more conditions here*/) { $fp = fopen("/tmp/$time.txt"); fwirte ($status,$fp); fclose($fp); } Help is as always much appreciated :)

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  • PHP form validation submit problem?

    - by TaG
    My code is suppose to save a year like 1999 to the mysql database but it wont. It will check to see if the user has entered only numbers and is at least 4 numbers long or if nothing has been entered correctly but it wont save the correct year? How can I fix this problem. Here is the PHP code. if(isset($_POST['year']) && intval($_POST['year']) && strlen($_POST['year']) == 4) { $year = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['year'])))); } else if($_POST['year'] && strlen($_POST['year']) < 4) { echo '<p class="error">year is not correct!</p>'; } else if($_POST['year'] == NULL) { // do something }

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  • Passing NULL values into mysql Stored procedure

    - by McNabbToSkins
    I am trying to pass a few NULL values to a stroed procedure but PHP always retains the varaibles to be empty strings '' and not NULL. My DB insert function looks like this. (I am using a Framework and ADODB so if it looks weird thats why). function insert_emp($f_name, $last_name, $dob) { if(!isset($dob)){ $dob = NULL; } $this->DB->setConnection("CALL insert_emp('$f_name', '$l_name', '$dob')"); } I have ensured that $dob is being passed an empty string ''. But for some reason when it calls the stored proc it is not changed to NULL. dob is a datetime field and mysql complains that you can not enter an empty string as a DATETIME. If I hard code the insert such as this $this->DB->setConnection("CALL insert_emp('Test1', 'Test2', 'NULL')"); it will work. Thanks for the help.

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  • How do I make a multiple file upload?

    - by Bluemagica
    I am trying to make a multiple image uploader. The file upload fields are being added in the form dynamically using jquery. I tried making an array of the fields since I don't want to have a hidden field. so my generated upload fields look like <input type="file" id="img0" name="img[]"/> <input type="file" id="img1" name="img[]"/> <input type="file" id="img2" name="img[]"/> ..... .. And on the php side I did something like if(isset($_FILES['img'])) { foreach($_FILES['img'] as $k=>$v) { if($v!="") { uploadImage($k,0,0,0,"content/gallery/"); } } } Now I know I am way too wrong, since in that code I am looping through the 'img' file's properties instead of all images....but I have no idea how to fix this. PS: uploadImage is a function I wrote which expects the file input field's name as the first parameter.

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  • ajax how to read out $_post variable

    - by alex
    Hi, I am trying to filter/search a database with ajax $.ajax({ type: "POST", url: "filterSearch.php", queryString: qry, success: function(data){ alert( "Data Saved: " + data ); $('#searchResult').html(data); // Fill the search results box } }); Now in filterSearch.php i have the following test codes if(isset($_POST['queryString'])) { echo "TEST"; } if($_POST['runquery']==1) { $sql = "SELECT * FROM fs_vacatures WHERE here-the-like-query?"; $msg = $sql; echo $msg; die(); } die(); But nor TEST or the $sql is return in the alert??

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  • PHP - MySQL how to delete an image when a user submits a new image problem.

    - by pc-wiki
    I'm trying to delete the current image that is already set on the server when a user submits a new image to the server, but I don't know how to do add this to my current code can some one please help me? Here is my PHP & MySQL code. if(isset($_FILES["thumb"]["name"])) { if (file_exists("/images/" . $_FILES["thumb"]["name"])) { $thumb != $_FILES["thumb"]["name"]; } else if($_FILES["thumb"]["name"] == TRUE) { move_uploaded_file($_FILES["thumb"]["tmp_name"], "/images/" . mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["thumb"]["name"]))))); $thumb = mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["thumb"]["name"])))); } if($thumb == TRUE) { //create thumb code here... } }

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