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  • Wordpress plugin $post

    - by Jordan Pagaduan
    I have already get how to insert in the database. My only problem is to get the value of text box to insert in the database. Here is my code: function dbAdd() { global $wpdb; $new_title = $_POST['new_title']; $new_author = $_POST['new_author']; $new_url = $_POST['new_url']; if($wpdb->insert('wp_podcast_data', array( 'mp3_id' => '', 'title' => '$new_title', 'creator' => '$new_author', 'url' => '$new_url') )) { echo"<h1>Save Successfully!</h1>"; }else { echo mysql_error(); } } ---------------------------------------------------------- function player_manager_index() { if($_SERVER['REQUEST_METHOD']=='POST') { dbAdd(); } ?> <h3>Podcast Player Manager (This Plug is not yet finish)</h3><br /> <p>Note: This Player Manager needs the URL of mp3 file that you want to include in your podcast player.</p> <form method="post" action=""> <label for="new_title" style="display:block; padding-top: 5px; cursor: default;">Title</label><input type="text" id="new_title" name="new_title" size="50" /> <label for="new_author" style="display:block; padding-top: 5px; cursor: default;">Author</label><input type="text" id="new_author" name="new_author" size="50" /> <label for="new_url" style="display:block; padding-top: 5px; cursor: default;">URL</label><input type="text" id="new_url" name="new_url" size="50" /> <div><input type="submit" value="Add New" style="margin-left: 20px; margin-top: 15px;" /></div> </form> Please Help me. I'm newbie in wordpress. Thank you so much.

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  • How do I send an email from my webpage?

    - by Jordan S
    I am not a web developer but I do have a lot of programming experience in C# and Windows forms programming. On our company webpage my boss wants me to put in a textbox where visitors can submit a comment and press a submit button and that comment will be sent to an email address. Right now, our website uses just plain old html, no php or javascript or anything like that. I am wondering what is the simplest way to accomplish what I need? Can someone point me in the right direction? The website is hosted on an Apache server so I won't be able to use aspx.

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  • .Net LoginControls - User can't logout in Firefox

    - by Jordan Foreman
    Basically, the logout link doesn't do anything, but only in Firefox. (I can login and out freely from other browsers) There really isn't a whole lot of information I can really give other than that, since I'm still new to this project and .net as a whole, and know almost nothing about the login controls. So if someone else has experienced a similar issue in the past, and can recognize the issue with the little info I have, that would be great! If not, sorry for the lack of depth, but its all I have. If it helps, here is the code for where the logout link is: <LoggedInTemplate> ... <asp:LoginStatus ID="HeadLoginStatus" runat="server" LogoutAction="Redirect" LogoutText="Log Out" LogoutPageUrl="~/Anonymous/Login.aspx" /> </LoggedInTemplate>

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  • how to get files as they are added to a remote server

    - by Jordan
    I am using a bash script (below) on a remote server (so far using ssh to connect) to execute a python script that downloads a lot of pdf files one at a time (getting the download locations from a text file with the URL's) in a loop. I would like to move the files from the remote server to my local computer as they are downloaded, and then delete the file from the remote server. Is there a way that I can expand my bash script to do this? Or are there alternatives for completing this task? while read line; do python python_script.py -l $line; done < pdfURLs.txt

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  • I need HTML help. I am using the FRAMESET tag and its getting complicated.

    - by Jordan
    You will need to download a 4Shared file so that I can give you all the information necessary. Problem: I am using the FRAMESET tab and I have links put in the left hand column and when clicked, they only open in that column when I want them to open up the full screen, not with a new tab though. Here is where you can get a word file with all the writing that I put in notepad for my pages. Each Word page is a different Notepad file, and there are pictures on the bottom to help understand. www.4shared.com/get/299858562/2f5cf7dd/2_HTML_help.html THANK YOU!

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  • Why won't my Setup Project Perform my Custom Registration Process

    - by Jordan S
    I am trying to write an Setup Project/Installer for a class library driver that I wrote in C# using Visual Studio 2008. The driver project has a section of code that looks like this... [ComRegisterFunction] public static void RegisterASCOM(Type t) { Trace.WriteLine("Registration Started."); DoRegistration(true); } In the driver project Properties - "Assembly Information" I have set checked the box that says Make COM-Visible = true. I added a Setup Project to the solution in VS, added the output dll from the driver project so that it installs on the target machine and set the Register property of the dll to "vsdraCOM". So, my understanding is that when the installer runs it SHOULD execute the methods of the dll that are marked with [COMRegisterFunction]. Using SysInternals Debug View I can monitor when the above code snippet is hit by watching for the "Registration started" text to show up in the window. When I build the solution, I can see the text show up so I know the driver is registering properly. The problem is that when I run the installer, I don't think it is doing the registration bit. I see nothing show up in Debug View. And if i try to access my driver via another application I get an error saying it "Cannot create ActiveX object". Why does the registration not occur during the install process? The driver does register for COM but it does NOT call my custom registration method. Does anyone have and suggestions of what I could be missing? Is there another way I can debug this? (I can provide more code if anyone want's to take a look!!)

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  • PHP MySQL Select multiple tables

    - by Jordan Pagaduan
    Is it posibble to select 3 tables at a time in 1 database? Table 1: employee -- employee_id -- first_name -- last_name -- middle_name -- birthdate -- address -- gender -- image -- salary Table 2: logs -- log_id -- full_name -- employee_id -- date -- time -- status Table 2: logout -- log_id -- full_name -- employee_id -- date -- time -- status I wanted to get the value of employee table where $id of selected. Then the $id also get the value of log.time, log.date, logout.time, and logout.date. I already try using UNION but nothing happens.

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  • How do I create a generic method with a generic in the where clause? (Man that's clear as mud!)

    - by Jordan
    Is there a way of doing this: protected void SubscribeToEvent<TEvent, TPayload>(Action<TPayload> a_action) where TEvent : CompositePresentationEvent<TPayload> { TEvent newEvent = _eventAggregator.GetEvent<TEvent>(); SubscriptionToken eventToken = newEvent.Subscribe(a_action); _lstEventSubscriptions.Add(new KeyValuePair<EventBase, SubscriptionToken>(newEvent, eventToken)); } without requiring the user to specify a TPayload parameter?

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  • PHP Javascript catch link.

    - by Jordan Pagaduan
    Javascript <script type="text/javascript"> function Edit(id) { if(confirm("Are you sure to edit?")==true) { location.href='employee_set.php&edit='+id; } } </script> PHP <?php if(isset($_GET["edit"])==false){ echo "no response"; }else{ echo "link success"; } ?> My problem is the Javascript is OK. The location href example. http://localhost/employee_set.php&edit=30 ... The PHP code is not working. Error is not found.

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  • Xcode 4: nib files not loading when run, can't find UI elements

    - by Jordan
    So, I just downloaded Xcode 4 and installed it. I was actually quite looking forward to the single window and integrated IB... - However, when I open and run one of my projects, the nib files that the project uses don't seem to load. Instead I'm left looking at a blank white screen (iPhone). This project ran well and fine on Xcode 3.2. So I thought... this can't be that hard to fix. So I opened up a nib file, thinking that maybe editing or creating a new one from scratch could point me in the right direction. But I can't find the old resources panel from interface builder anywhere. How am I meant to create a new view or add buttons? I know I'm probably just missing something obvious :s Did anyone else have the same nib file problems - is there a fix (or something stupidly simple that I'm forgetting about)? - EDIT: Ok. If I background and un-background the app, the view loads fine. But this happens every time I build, on both iPhone and iOS simulator, i.e. the app doesn't work properly until it's been backgrounded. All the code for loading the view follows from - (void)applicationDidFinishLaunching:(UIApplication *)application. Now I am really confused. - Thanks :)

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  • Mac: How to see list of running network services?

    - by Jordan
    I am writing an application that needs to connect with a running network service on a Mac. Problem is, I have no idea what the service is called or even what port it uses. Is there a way to browse all running network services on my Mac? More info: I am connecting to a MIDI network session (found under 'Audio MIDI settings', present on all OSX installs). Am I correct in thinking this is a network service? I am planning to use NSNetServiceBrowser to locate all local computers running this service. (is this the best way to go about it?) Any help is much appreciated - thanks!

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  • REST client website login

    - by Jordan
    I have written a REST service that uses WSSE as an authentication method but i want to be able to use this rest service through a browser by creating a website around the service. I want the user to be able to log in on the website then when they view, for example the "view users" page an ajax request is made to test.com/users and back comes the list. The part i'm trying to get my head around is the logging in/out on the website and keeping the user logged in across pages. Since in a true REST implementation there's no state held on the server, i can't use $_SESSION and now i don't know where to start! What is the best way to go about this? Do i still need to store session information on the server then possibly use cURL to make the request? Thanks Jay

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  • How do you bind SQL Data to a .NET DataGridView?

    - by Jordan S
    I am trying to bind a table in an SQL database to a DataGridView Control. I would like to make it so that when the user enters a new line of data in the DataGridView that a record is automatically added to the database. Is there a way to do this using LINQ to SQL? I have tried using the code below but after I add a new entry I dont think the data gets added to the DB. Please Help! BOMClassesDataContext DB = new BOMClassesDataContext(); var mfrs = from m in DB.Manufacturers select m; BindingSource bs = new BindingSource(); bs.DataSource = mfrs; dataGridView1.DataSource = bs; I tried adding DB.SubmitChanges() to the CellValueChanged eventhandler and that partially works. If I click the bottom empty row it automatically fills in the ID (identity) column of the table with a "0" instead of the next unused value. If I change that value manually to the next available then it adds the new record fine but if I leave it at 0 it does nothing. How can i fix this?

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  • PHP readdir(): 3 is not a valid Directory resource

    - by Jordan
    <?php function convert(){ //enable error reporting for debugging error_reporting(E_ALL | E_STRICT); //convert pdf's to html using payroll.sh script and //pdftohtml command line tool $program = "payroll.sh"; $toexec="sh /var/www/html/tmp/" . $program . " 2>&1"; $exec=shell_exec($toexec); //display message from payroll.sh //echo $exec; //echo ('<br/>'); } function process(){ $dir = '/var/www/html/tmp/converted'; //echo ('one'); if (is_dir($dir)) { //echo ('two'); if ($dh = opendir($dir)) { //echo ('three'); while (($file = readdir($dh)) !== false) { //echo ('four'); if ($file != "." && $file != ".."){ echo 'opening file: '; echo $file; echo ("<br/>"); $fp = fopen('/var/www/html/tmp/converted/' . $file, 'r+'); $count = 0; //while file is not at the EOF marker while (!feof($fp)) { $line = fgets($fp); if($count==21) { $employeeID = substr($line,71,4); echo 'employee ID: '; echo $employeeID; echo ('<br/>'); //echo ('six'); $count++; } else if($count==30) { $employeeDate = substr($line,71,10); echo 'employee Date: '; echo $employeeDate; echo ('<br/>'); //echo ('seven'); $count++; } else { //echo ('eight'); //echo ('<br/>'); $count++; } } fclose($fp); closedir($dh); } } } } } convert(); process(); ?> I am setting up a php script that will take a paystub in pdf format, convert it to html, then import it into Drupal after getting the date and employee ID. The code only seems to process the first file in the directory then it gives me this: opening file: dd00000112_28_2010142011-1.html employee ID: 9871 employee Date: 12/31/2010 Warning: readdir(): 3 is not a valid Directory resource in /var/www/html/pay.mistequaygroup.com/payroll.php on line 29 The '3' in the error really confuses me, and google is not helping much. Could it be the 3rd iteration of the loop? The only files in the directory reddir() is scanning are the .html files waiting to be processed. Any ideas? Also, how does my code look? I'm fairly new to doing any real programming and I don't get too much input around work.

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  • Can you use #defined values in if statements (In C programs)?

    - by Jordan S
    I am new at C programming. I thought when you type something like #define Const 5000 that the compiler just replaces every instance of Const with 5000 at compile time. Is that wrong? I try doing this in my code and I get a syntax error. Why can't i do this? #define STEPS_PER_REV 12345 ... in some function if(CurrentPosition >= STEPS_PER_REV) { // do some stuff here } The compiler complains about the if statement with a syntax error that gives me no details.

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  • Hide Segemented Control on NavBar, then add Title

    - by Jordan Clark
    Basically I have a Segmented Controller on my NavBar right in the middle. What I want to be able to do is hide the Segmented Controller and add a title to the navigation bar. But with my code, the segmented controller is being hidden, but the title will not add, thus leaving a blank NavBar. This is my simple code in .h: IBOutlet UISegmentedControl *toggleDay; IBOutlet UINavigationBar *navBar; And this is my code in my .m: toggleDay.hidden = YES; navBar.topItem.title = @"Title"; Any help would be great thanks!

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  • calling same function on different buttons not loaded yet

    - by Jordan Faust
    I can not get this to work for every button and I cannot find anything explaining why. I guessing it is something small that I am missing $(document).ready(function() { // delete the selected row from the database $(document).on('click', '#business-area-delete-button', { model: "BusinessArea" }, deleteRow); $(document).on('click', '#business-type-delete-button', { model: "BusinessType" }, deleteRow); $(document).on('click', '#client-delete-button', { model: "Client" }, deleteRow); $(document).on('click', '#client-type-delete-button', { model: "ClientType" }, deleteRow); $(document).on('click', '#communication-channel-type', { model: "CommunicationChannelType" }, deleteRow); $(document).on('click', '#parameter-type-delete-button', { model: "ParameterType" }, deleteRow); $(document).on('click', '#validation-method-delete-button', { model: "ValidationMethod" }, deleteRow); } the event function deleteRow(event){ $.ajax( { type:'POST', data: { id: $(".delete-row").attr("id") }, url:"/mysite/admin/delete" + event.data.model, success:function(data,textStatus){ $('#main-content').html(data); }, error:function(XMLHttpRequest,textStatus,errorThrown){ jQuery('#alerts').html(XMLHttpRequest.responseText); }, complete:function(XMLHttpRequest,textStatus){ placeAlerts() } } ); return false }; This works only for a the button with id validation-method-delete-button. I use document and not the button its self because the button is contained in a template that is loaded later via ajax. I have this working for a similar function that is selecting a row in a table however I am not attempting to pass data in that scenario.

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  • SQL Binary Microsoft Access - Combining two tables if specific field values are equal

    - by Jordan
    I am new to Microsoft Access and SQL but have a decent programming background and I believe this problem should be relatively simple. I have two tables that I have imported into Access. I will give you a little context. One table is huge and contains generic, global data. The other table is still big but contains specific, regional data. There is only one common field (or column) between the two tables. Let’s call this common field CF. The other fields in both tables are different. I’ll take you through one iteration of what I need to do. I need to take each CF value in the regional, smaller table and find the common CF value in the larger, global table. After finding the match, I need to take the whole “record” or “row” from the global data and copy it over to the corresponding record in the smaller regional table (This should involve creating the new fields). I need to do this for all CF values in the regional, smaller table. I was recommended to use SQL and a binary search, but I am unfamiliar. Let me know if you have any questions. I appreciate the help!

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  • PHP hashing function not working properly

    - by Jordan Foreman
    So I read a quick PHP login system securing article, and was trying to sort of duplicate their hashing method, and during testing, am not getting the proper output. Here is my code: function decryptPassword($pw, $salt){ $hash = hash('sha256', $salt . hash('sha256', $pw)); return $hash; } function encryptPassword($pw){ $hash = hash('sha256', $pw); $salt = substr(md5(uniqid(rand(), true)), 0, 3); $hash = hash('sha265', $salt . $hash); return array( 'salt' => $salt, 'hash' => $hash ); } And here is my testing code: $pw = $_GET['pw']; $enc = encryptPassword($pw); $hash = $enc['hash']; $salt = $enc['salt']; echo 'Pass: ' . $pw . '<br />'; echo 'Hash: ' . $hash . '<br />'; echo 'Salt: ' . $salt . '<br />'; echo 'Decrypt: ' . decryptPassword($hash, $salt); Now, the output of this should be pretty obvious, but unfortunately, the $hash variable always comes out empty! I'm trying to figure out what the problem could be, and my only guess would be the second $hash assignment line in the encryptPassword(..) function. After a little testing, I've determined that the first assignment works smoothly, but the second does not. Any suggestions? Thanks SO!

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  • Revision Control System Recommendations

    - by Jordan Arsenault
    I've reached a point in my independent development work where I would like to start using Subversion techniques. Up to now, I've been simply making backups by exporting my current database, and zipping them together with my PHP project files. I've read some articles online and watched a video with Linus Torvalds - the general verdict seems to be that Git is in and old CVS techniques are out. I'm not currently operating under Linux, I do all PHP work out of Windows - Eclipse. Due to the fact that Eclipse runs on JVM, jumping into Linux - Eclipse will be more or less transparent - file system aside. What I would like to accomplish is being able to keep a constant revision history - But I want this to be almost entirely transparent. Also, I work in an MVC framework, and I would like to be able to release my views to Designers, and have them work from within the revision control system too. Will Egit accomplish what I need? Or is it too much overhead for a one-man workforce? What do you recommend I use so that I can keep a revision history? I also require the service to be free! Thank you all - StackOverflow ftw!

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  • jQuery ajax return value

    - by Jordan Pagaduan
    How can I return the value "pinNumber" from jquery ajax so I can append it outside of the ajax. Here is my code var x = pinLast + 1; for(i=x;i<=pinMany;i++) { var i = x++; var cardNumber = i.toPrecision(8).split('.').reverse().join(''); var pinNumber = ''; jQuery.ajax({ type: "POST", url: "data.php", data: "request_type=generator", async: false, success: function(msg){ var pinNumber = msg; return pinNumber; //pin number should return } }); jQuery('.pin_generated_table').append(cardNumber+' = '+pinNumber+''); // the variable pinNumber should be able to go here } Please ask me if you don't understand.. ^^ thanks

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  • Sencha Touch 2 - Can't get list to display // or load a store? [UPDATED X2]

    - by Jordan
    I have been trying to get a list to display for quite a while now. I have tried all sorts of tips from various people without success. Now I am running into a new problem. I have taken the exact code from an example and I can't seem to get it to work either. First of all, here is the code. Station.js Ext.define('Syl.model.Station', { extend: 'Ext.data.Model', config: { fields: [ { name: 'id', type: 'string' }, { name: 'stop', type: 'string' } ] } }); Stations.js Ext.define('Syl.store.Stations', { extend : 'Ext.data.Store', requires: ['Syl.model.Station'], id: 'stations', xtype: 'stations', config : { model : 'Syl.model.Station', //storeId: 'stationsStore', autoLoad : true, //sorters: 'stop', /* proxy: { type: 'ajax', url: 'stations.json' }*/ data: [ { "id": "129", "stop": "NY Station" }, { "id": "13", "stop": "Newark Station" } ] } }); MyService.js Ext.define('Syl.view.MyService', { extend: 'Ext.Panel', xtype: 'stationsformPage', requires: [ 'Syl.store.Stations', 'Ext.form.FieldSet', 'Ext.field.Password', 'Ext.SegmentedButton', 'Ext.List' ], config: { fullscreen: true, layout: 'vbox', //iconCls: 'settings', //title: 'My Service', items: [ { docked: 'top', xtype: 'toolbar', title: 'My Service' }, { [OLDER CODE BEGIN] xtype: 'list', title: 'Stations', //store: 'Stations', store: stationStore, //UPDATED styleHtmlContent: true, itemTpl: '<div><strong>{stop}</strong> {id}</div>' [OLDER CODE END] [UPDATE X2 CODE BEGIN] xtype: 'container', layout: 'fit', flex: 10, items: [{ xtype: 'list', title: 'Stations', width: '100%', height: '100%', store: stationStore, styleHtmlContent: true, itemTpl: '<div><strong>{stop}</strong> {id}</div>' }] [UPDATE X2 CODE END] }, ] } }); app.js (edited down to the basics) var stationStore; //UPDATED Ext.application({ name: 'Syl', views: ['MyService'], store: ['Stations'], model: ['Station'], launch: function() { stationStore = Ext.create('Syl.store.Stations');//UPDATED var mainPanel = Ext.Viewport.add(Ext.create('Syl.view.MyService')); }, }); Okay, now when I run this in the browser, I get this error: "[WARN][Ext.dataview.List#applyStore] The specified Store cannot be found". The app runs but there is no list. I can't understand how this code could work for the people who gave the example and not me. Could it be a difference in the Sencha Touch version? I am using 2.0.1.1. To add to this, I have been having problems in general with lists not displaying. I had originally tried a stripped down list without even having a store. I tried to just set the data property in the list's config. I didn't get this error, but I also didn't get a list to display. That is why I thought I would try someone else's code. I figured if I could at least get a working list up and running, I could manipulate it into doing what I want. Any help would be greatly appreciated. Thanks. [UPDATED] Okay, so I did some more hunting and someone told me I needed to have an instance of my store to load into the list, not the store definition. So I updated the code as you can see and the error went away. The problem is that I still don't get a list. I have no errors at all, but I can't see a list. Am I not loading the data correctly? Or am I not putting the list in the view correctly? [UPDATED X2] Okay, so I learned that the list should be in a container and that I should give it a width and a height. I'm not totally sure on this being correct, but I do now have a list that I can drag up and down. The problem is there is still nothing in it. Anyone have a clue why?

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  • replacing the beginning and end but not the same chars within a string

    - by Jordan Trainor
    lines = "some stuff\"some other \"stuff\"\""; lines = lines.Replace("\"", "\""); lines = lines.Replace("\"", "\""); in its current context and in its simplest form these two actions seem absolutely pointless but when I put this into code it will be not be pointless and will have a purpose other than replacing itself with itself. OK so I have the String lines that has 4 escaped quotation marks and I wish to replace the first quote with a quote and the end quote with a quote how would I accomplish this without replacing any of the inner quotes?

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  • Working with Java using methods and arrays [closed]

    - by jordan
    Hi i'm a newb at java and for one of my labs I have to create a instant messenger client with these requirements: add buddyList instance variable add IMClient constructor to create ArrayList addBuddy method removeBuddy method findBuddy method printBuddyList method what's the best way to go about this? so far I have this: public class IMClient { private String userId; // User id private String password; // Password private int status; // Status code for user: 1 - Online, 2 - Off-line, 3 - Away public IMClient(String userId, String password, int status) { super(); this.userId = userId; this.password = password; this.status = status; } // Returns true if password as a parameter matches password instance variable. public boolean checkPassword(String password) { return this.password.equals(password); } public String toString() { StringBuffer buf = new StringBuffer(100); buf.append(" User id: "); buf.append(userId); buf.append(" Password: "); buf.append(password); buf.append(" Status: "); buf.append(status); return buf.toString(); } public String getUserId() { return userId; } public void setUserId(String userId) { this.userId = userId; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public int getStatus() { return status; } public void setStatus(int status) { this.status = status; } public static void main(String[] args) { } }

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