Search Results

Search found 13669 results on 547 pages for 'left handed'.

Page 10/547 | < Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >

  • double left MYSQL join?

    - by Haroldo
    I've been trying left joins but as there are 2 joins, i think the problem is the 2nd join roots from table_B not table_A. i am not getting any results where there is the required data in the db. I am not getting a query error the query (simplified) SELECT events.*, ven.*, events_genres.* FROM events LEFT JOIN ven //OPTIONAL JOIN ON events.ven_id = ven.ven_id //OPTIONAL JOIN LEFT JOIN events_genres //REQUIRED JOIN ON events.event_id = events_genres.event_id //REQUIRED JOIN WHERE events.date >= '$this->now' AND WHERE events_genres.g_id = $g_id //REQUIRED MATCH ORDER BY date ven = optional, i'll have the info if its there. events_genres = required, i dont want any results that do not have a genre

    Read the article

  • Programmatically press "Left" key in a text input

    - by Anurag
    I am trying to programmatically fire a key event to go left in a text box, but not having any luck. The input element has focus and the cursor is at the end. I'm trying to get the cursor to move left one step - before the letter "F". ABCDEF| Here's the code so far: HTML <input id="a" type="text" /> Javascript var keyEvent = document.createEvent("KeyboardEvent"); var keyLocation = '0x00'; var keyIdentifier = "Left"; keyEvent.initKeyboardEvent("keypress", true, true, window, keyIdentifier, keyLocation, false); $("a").dispatchEvent(keyEvent); Saved a quick demo on jsfiddle if you want to see the whole code - http://jsfiddle.net/Vsafv/ I am not interested in making this cross-browser (just get it working in Chrome). Thanks for any help.

    Read the article

  • How to make a shape with left-top round rounded corner and left-bottom rounded corner?

    - by kknight
    I want to make a shape with with left-top rounded corner and left-bottom rounded corner: <?xml version="1.0" encoding="UTF-8"?> <shape xmlns:android="http://schemas.android.com/apk/res/android"> <solid android:color="#555555"/> <stroke android:width="3dp" android:color="#555555" /> <padding android:left="1dp" android:top="1dp" android:right="1dp" android:bottom="1dp" /> <corners android:bottomRightRadius="0dp" android:bottomLeftRadius="2dp" android:topLeftRadius="2dp" android:topRightRadius="0dp"/> </shape> But the shape above didn't give me what I want. It gives me a rectangle without any rounded corners. Can anyone help? Thanks.

    Read the article

  • left-hand operand of comma has no effect?

    - by sil3nt
    Hello there, I'm having some trouble with this warning message, it is implemented within a template container class int k = 0, l = 0; for ( k =(index+1), l=0; k < sizeC, l < (sizeC-index); k++,l++){ elements[k] = arryCpy[l]; } delete[] arryCpy; this is the warning i get cont.h: In member function `void Container<T>::insert(T, int)': cont.h:99: warning: left-hand operand of comma has no effect cont.h: In member function `void Container<T>::insert(T, int) [with T = double]': a5testing.cpp:21: instantiated from here cont.h:99: warning: left-hand operand of comma has no effect cont.h: In member function `void Container<T>::insert(T, int) [with T = std::string]': a5testing.cpp:28: instantiated from here cont.h:99: warning: left-hand operand of comma has no effect >Exit code: 0

    Read the article

  • Shift browser contents to the left while viewing in wide screen

    - by Sathya
    I use a widescreen laptop. Many websites have their content centre aligned. On wider screens this means lot of empty space on left and right. As such this is not a botheration. Many a times, I read some instructions on the web page and type them out on the command prompt. I prefer to overlay the command prompt window on top of the browser and if the browser contents are left aligned (or right aligned), then I need not Alt-tab across these windows. I use Firefox on Ubuntu. I use the command line (konsole) heavily. I know compiz (and similar) tools provides transparent windows so that the content beneath is visible. But I don't want to install compiz or its equivalent because my graphics driver is not all that good. Any addon or simple trick that would shift the page content to the left (or right) would be very helpful (read productive).

    Read the article

  • How To Left Align List Items when Unordered List is Centered on the Page

    - by tonsils
    Hi, I have a div that holds an unordered list with several list items. I am using ie6 and am basically trying to center the unordered list on the screen but at the same time want the actual list item text aligned to the left. At the moment, I have my unordered list within the center tags, which has centered the list but I would actually like to now left align the actual list item text. Can someone pls assist as I am unable to left the align the text now? Thanks.

    Read the article

  • Use Margin Auto and Center to center Float Left Div

    - by Yan Cheng CHEOK
    I know this question had been asked many times. http://stackoverflow.com/questions/1740587/float-a-div-to-center However, I follow their suggestion : <center> <div style="margin : auto"> <a href="#" style="float: left; margin-right: 10px;">Menu Item 1</a> <a href="#" style="float: left; margin-right: 10px;">Menu Item 2</a> <a href="#" style="float: left; margin-right: 10px;">Menu Item 3</a> </div> </center> By using "Center" and "Margin Auto", I still unable to center the menu item.

    Read the article

  • detect if extended desktop is to the left or to the right

    - by bobobobo
    So, I have a screen capture utility (it takes full screen shots and saves it to png files) I've written, and it uses SM_CXVIRTUALSCREEN and SM_CYVIRTUALSCREEN to determine the width and height of the desktop. I then get the desktop DC and copy out the bits and save them as png. BitBlt( backDC, 0, 0, backBufferCX, backBufferCX, desktopDC, X_SRC, 0, SRCCOPY ); Here X_SRC is usually 0, UNLESS THE DESKTOP HAS BEEN EXTENDED "TO THE LEFT". In that case it needs to be -1280px, for example, if the left monitor measures 1280px. How can I determine if the desktop's starting point is negative (if the user has extended his desktop to the left?)

    Read the article

  • CSS Float left question

    - by Minghui Yu
    <div id="slideshow-prevnext" class="slideshow-prevnext"> <a id="prev" class="left" href="#"><span class="invisible">Prev</span></a> <a id="next" class="right" href="#"><span class="invisible">Next</span></a> <a href="#" class="dot">&nbsp;</a> <a href="#" class="dot">&nbsp;</a> <a href="#" class="dot">&nbsp;</a> </div> I want the three <a href="#" class="dot">&nbsp;</a> appear on the left of and the two ("Prev" and "Next") on the right. How can I do it? I tried float:left but does not work. Edit: CSS is too long to post. Development site is here at : http://site2.ewart.library.ubc.ca/

    Read the article

  • How to declare a div in @page @top-left

    - by icon911
    How do I declare that a DIV should be displayed in top-left corner of every page and not in its relative position. I have a div like: <div id=header>Document</div> and I would like to display it on every page in top left corner using css like: @page { size: 8.5in 11in; margin: 0.25in; border: thin solid black; padding: 1em; @top-left { content: ???? ; } } Thank you.

    Read the article

  • Left outer joins that don't return all the rows from T1

    - by Summer
    Left outer joins should return at least one row from the T1 table if it matches the conditions. But what if the left outer join performs a join successfully, then finds that another criterion is not satisfied? Is there a way to get the query to return a row with T1 values and T2 values set to NULL? Here's the specific query, in which I'm trying to return a list of candidates, and the user's support for those candidates IF such support exists. SELECT c.id, c.name, s.support FROM candidates c LEFT JOIN support s on s.candidate_id = c.id WHERE c.office_id = 5059 AND c.election_id = 92 AND (s.user_id = 2 OR s.user_id IS NULL) --This line seems like the problem ORDER BY c.last_name, c.name The query joins the candidates and support table, but finds that it's a different user who supported this candidate (user_id=3, say). Then the candidate disappears entirely from the result set.

    Read the article

  • Horizontal scroll in rich:panel to default right to left

    - by TaylorSmolik
    I have a rich:panel with a style="overflow: scroll" tag inside. By default, the scroll slides left to right. I am constantly adding a new dataTable to a dataGrid with the click of a button and I want the user to always see the most recent one, and since I have it set up so that each dataTable is added as a column to the dataGrid, the most recent one will always be on the right side of the dataGrid. Is there a way I can default the scroll to go right to left? Or maybe creating the columns from right to left?

    Read the article

  • MYSQL: COUNT with GROUP BY, LEFT JOIN and WHERE clause doesn't return zero values

    - by Paul Norman
    Hi guys, thanks in advance for any help on this topic! I'm sure this has a very simply answer, but I can't seem to find it (not sure what to search on!). A standard count / group by query may look like this: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` GROUP BY `t1`.`any_col` and this works as expected, returning 0 if no rows are found. So does: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 However: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 GROUP BY `t1`.`any_col` only works if there is at least one row in table_1 and fails miserably returning an empty result set if there are zero rows. I would really like this to return 0! Anyone enlighten me on this? Beer can be provided in exchange if you are in London ;-)

    Read the article

  • Next Div Does not appear correctly after floating two divs to right and left

    - by user3703669
    I have floated two divs to left and right...But the next div after those two divs does not appear correctly... My code is follows #Div1{ position: relative; float: left; } #Div2{ position: relative; float: right; } And the display as follows <div id="Div1">This is aligned to left on the same x axis</div> <div id="Div2">This is aligned to right on the same x axis</div> <div style="color: red;">After the alignment this div does not align</div> The output is as follows http://i.stack.imgur.com/8A6hz.png But I expect something like this http://i.stack.imgur.com/wVGN6.png Anyway to accomplish this task ?? Please HELP!! Urgent help needed!!!

    Read the article

  • How do I join these queries?

    - by GregoryD
    query1: SELECT category.id, category.name, category.level, category.description, category.cat1, category.cat2, category.cat3, category.cat4, category.pri_color, category.sec_color, category.last_report AS report_id FROM category, reports_category_layout WHERE category.id = reports_category_layout.catID AND reports_category_layout.site_code = 'las' query2: SELECT DISTINCT category.id, COUNT(forum.id) AS posts, SUM(forum.view) AS views FROM category, forum WHERE category.id = forum.catID AND forum.approved = 'yes' AND forum.site_code = 'las' GROUP BY category.id query3: SELECT forum.catID, forum.title, forum.paragraph, forum.created, users.alias, forum.userID FROM forum, users, forum_cache WHERE forum.catID = forum_cache.catID AND forum.id = forum_cache.last_report AND users.id = forum.userID AND forum.approved = 'yes' Essentially, I am unsure about the syntax to join these properly. I have written a query that simply joins them, but in the case that the forum cache table contains an unapproved forum id, it will simply not return the entire row. what I really need is for query1 and query2 to be left joined on the category id, and for query 3 to be left outer joined on id = catID.

    Read the article

  • SQL: Gather right hand values from a join

    - by Max Williams
    Let's say a question has many tags, via a join table called taggings. I do a join thus: SELECT DISTINCT `questions`.id FROM `questions` LEFT OUTER JOIN `taggings` ON `taggings`.taggable_id = `questions`.id LEFT OUTER JOIN `tags` ON `tags`.id = `taggings`.tag_id I want to order the results according to a particular tag name, eg 'piano', so that piano is at the top, then by all the other tags in alphabetical order. Currently i'm using this order clause: ORDER BY (tags.name = 'piano') desc, tags.name Which is going completely wrong - the first results i get back aren't even tagged with 'piano' at all. I think my problem is that i need to group the tag names somehow and do my ordering test against that: i think that doing it against the straight tags.name isn't working due to the structure of the resultant join table (it does work if i just do a simple select on the tags table) but i can't get my head around how to fix it. grateful for any advice, max

    Read the article

  • Feeding a Drill Down Menu with categories, subcategories and subSubcategories from a database

    - by Hassan
    Hi everyone, I have a Drill Down menu and I want to have it gets its elements from a database, I am using php and MySQL and the table (categories) looks like this : http://yfrog.com/jctablehsj I can't figure out how I can extract these information in a way I could put it inside the Drill Down Menu ! I found the recursive method (with LEFT JOINs) and the nested method which I barely understood and again I couldn't apply it to the Drill Down Menu. I found that some people found out a solution with left join and group by but couldn't understand or copy their example ! I would be more than gratefull if you could give me the extact of the query. Thanks a lot for your hard work, Hassan

    Read the article

  • SQL joins "going up" two tables

    - by blcArmadillo
    I'm trying to create a moderately complex query with joins: SELECT `history`.`id`, `parts`.`type_id`, `serialized_parts`.`serial`, `history_actions`.`action`, `history`.`date_added` FROM `history_actions`, `history` LEFT OUTER JOIN `parts` ON `parts`.`id` = `history`.`part_id` LEFT OUTER JOIN `serialized_parts` ON `serialized_parts`.`parts_id` = `history`.`part_id` WHERE `history_actions`.`id` = `history`.`action_id` AND `history`.`unit_id` = '1' ORDER BY `history`.`id` DESC I'd like to replace `parts`.`type_id` in the SELECT statement with `part_list`.`name` where the relationship I need to enforce between the two tables is `part_list`.`id` = `parts`.`type_id`. Also I have to use joins because in some cases `history`.`part_id` may be NULL which obviously isn't a valid part id. How would I modify the query to do this?

    Read the article

  • How to optimise MySQL query containing a subquery?

    - by aidan
    I have two tables, House and Person. For any row in House, there can be 0, 1 or many corresponding rows in Person. But, of those people, a maximum of one will have a status of "ACTIVE", the others will all have a status of "CANCELLED". e.g. SELECT * FROM House LEFT JOIN Person ON House.ID = Person.HouseID House.ID | Person.ID | Person.Status 1 | 1 | CANCELLED 1 | 2 | CANCELLED 1 | 3 | ACTIVE 2 | 1 | ACTIVE 3 | NULL | NULL 4 | 4 | CANCELLED I want to filter out the cancelled rows, and get something like this: House.ID | Person.ID | Person.Status 1 | 3 | ACTIVE 2 | 1 | ACTIVE 3 | NULL | NULL 4 | NULL | NULL I've achieved this with the following sub select: SELECT * FROM House LEFT JOIN ( SELECT * FROM Person WHERE Person.Status != "CANCELLED" ) Person ON House.ID = Person.HouseID ...which works, but breaks all the indexes. Is there a better solution that doesn't? I'm using MySQL and all relevant columns are indexed. EXPLAIN lists nothing in possible_keys. Thanks.

    Read the article

  • Help with MySQL Query?

    - by Devyn
    I have two tables rooms and users. I want to get only rooms.room_id, users.user_name with user_id = 1. I can get the result of all users with following sql... select rooms.room_id, rooms.user_id, users.user_name from rooms LEFT JOIN users ON rooms.user_id = users.user_id When I do like this to filter the result with user_id = 1 ... I got error. select rooms.room_id, rooms.user_id, users.user_name from rooms where rooms.user_id = 1 LEFT JOIN users ON rooms.user_id = users.user_id What should I do?

    Read the article

  • Want to avoid the particular rows from select join query... See description

    - by OM The Eternity
    I have a Select Left Join Query whis displays me the rows for the latest changedone(its a time) column name ("field" should not be equal) column name ("trackid" should not be equal), and column name "Operation should be "UPDATE" ", below is the query I am talking about... SELECT j1. * FROM jos_audittrail j1 LEFT OUTER JOIN jos_audittrail j2 ON ( j1.trackid != j2.trackid AND j1.field != j2.field AND j1.changedone < j2.changedone ) WHERE j1.operation = 'UPDATE' AND j2.id IS NULL Now here I don't want a row to be displayed with a two particular column's value i.e. "field's value" the value is "LastvisitDate" and "hits" Now if if append the condition in the above query that " AND j1.field != 'lastvistDate' AND j1.field != 'hits' " theni do not get any result... The table structure is jos_audittrail: id trackid operation oldvalue newvalue table_name live changedone(its a time) I hope i have given the details properly If u still find something missing I will try to provide it more better way... Pls help me to avoid those two rows with those to mentioned value of "field"

    Read the article

  • How can one-handed work in Emacs be eased?

    - by N.N.
    My right hand is temporarily immobilized and I would like to do some minor work in Emacs, mostly in Org-mode, but also in AUCTeX. Are there ways to ease one-handed work in Emacs, such as some mode or particular work flow? For instance I noticed that for undoing it is easier to press C-x u than C-_ and that it is easier to mark text with methods involving C-Space than with combinations of S- and movement commands. I have found http://stackoverflow.com/questions/2391805/how-can-i-remain-productive-with-one-hand-completely-immobilized but that is not exactly what I am asking for. I want to ease whatever little time spent one-handed in Emacs (not in general) and this is also interesting for situations where there is no injury involved, such as when one hand is occupied. I do realize that I should avoid unnecessary strain. I am using GNU Emacs 23.3.1 in Ubuntu 11.04.

    Read the article

  • How can one one-handed ease working in Emacs?

    - by N.N.
    My right hand is temporarily immobilized. I would like to do some minor work in Emacs, mostly in Org-mode, but also some in AUCTeX. Is there some way to ease one-handed work in Emacs such as some mode or particular work flow? For instance I noticed pressing C-x u is easier than C-_ for undoing and that it is easier to mark text with methods involving C-Space than with combinations of S- and movement commands. I have found http://stackoverflow.com/questions/2391805/how-can-i-remain-productive-with-one-hand-completely-immobilized but that is not what I am asking for. I want to ease whatever little time spent one-handed in Emacs and this is also interesting for situations where there is no injury involved, such as when one hand is occupied. I also do realize I should avoid unnecessary strain.

    Read the article

  • PHP bitwise left shifting 32 spaces problem and bad results with large numbers arithmetic operations

    - by Victor Stanciu
    Hello, I have the following problems: First: I am trying to do a 32-spaces bitwise left shift on a large number, and for some reason the number is always returned as-is. For example: echo(516103988<<32); // echoes 516103988 Because shifting the bits to the left one space is the equivalent of multiplying by 2, i tried multiplying the number by 2^32, and it works, it returns 2216649749795176448. Second: I have to add 9379 to the number from the above point: printf('%0.0f', 2216649749795176448 + 9379); // prints 2216649749795185920 Should print: 2216649749795185827

    Read the article

  • Regex: Search and replace left side = to right side

    - by ctrlShiftBryan
    How do I use regular expressions and search and replace to turn this [UserID] = <UserID, int,> [UserID] = 123123 [UserID] = asd123123 into [UserID] = [UserID] [UserID] = [UserID] [UserID] = [UserID] In other words I want to take everything from left side of the line up to the '=' character and replace everything on the right side of the '=' with the match from the left side. We can assume a line break at the end of each line. What are my Find what: and Replace with: values?

    Read the article

< Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >