Search Results

Search found 1068 results on 43 pages for 'relation'.

Page 10/43 | < Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >

  • Dropdown dependent values to be fetch from multiple models using ajax in Yii

    - by newuser
    I searched all the documentation over Yii but not got the answer of it.So I came here finally. I have the following schema Table Schools +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_name | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ Table Students +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_id | int(10) | NO | FK | | | | student_name | varchar(100) | NO | | | | | roll_no | varchar(80) | NO | | | | | class | varchar(20) | NO | | | | | | subjects | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ I have made models and CRUD for the both models.In models my relation is like this In Students.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'School' => array(self::BELONGS_TO,'Schools','school_id'), ); } In Schools.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'student' => array(self::HAS_MANY, 'Students', 'school_id'), ); } Now I made the two models rendered in a single page so that I can enter all the respective fields in a single form. In the _form.php file of Students I have made some change in student_name like this <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php echo $form->dropdownList($model,'student_name', CHtml::listData(Students::model()->findAll(), 'id', 'student_name'), array('empty'=>array('Select'=>'--Select One---'))); ?> <?php echo $form->error($model,'student_name'); ?> Now for this piece of code I got all the student name from the Student model. So my problem is when I am getting the student name from the dropdown list and going to select a student it will also fetch all the respective values of the student to be rendered in the _form.php without click on save button.So that user don't have to put it again manually. I think ajax and json encode will work here but don't know how to make them work here. [Update] Here is StudentsController code public function actionDisCoor() { $model = School::model()->findByPk($_POST['Students']['student_id']); $data=CHtml::listData($data,'id','name'); foreach($data as $value=>$name) { echo CHtml::tag('option',array('value'=>$value),CHtml::encode($name),true); } } Here is _form.php code for Students <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php $List = CHtml::listData(Students::model()->findAll(), 'id', 'student_name'); ?> <?php echo $form->dropdownList($model,'student_name',$List, array('onChange'=>CHtml::ajax(array( 'url' => CController::createUrl('DisCoor'), 'type' => 'POST', 'update'=>'#school_id', )),'style'=>'width:180px;' ) )?> <?php echo $form->error($model,'student_name'); ?> </div> After all that when I saw in firebug I got the error.Here is the screen shot

    Read the article

  • How do bezier handles work?

    - by user146780
    On Wikipedia I found information about bezier curves and made a function to generate the inbetween points for a bezier polygon. I noticed that Expression Design uses bezier handles. This allows a circle to be made with 4 points each with a bezier handle. I'm just not sure mathematically how this works in relation with the formula for bezier point at time T. How do these handle vectors work to modify the shape? Basically what's there relation to the bezier formula? Thanks

    Read the article

  • Dataset to excel

    - by Ruben Monteiro
    Hi. I'm developing an application that as to export a dataset to excel, this dataset have 3 tables and the relation between them, I would like to export this to a single excel sheet where for each parent table there is a '+' sign that when expanded shows the child values related to it. To export a single table to excel I know how to do it, but to create this type of relation I have no idea how to do it, do I have to create a macro on the excel file?

    Read the article

  • Foreign key,local key?

    - by user198729
    CREATE TABLE products ( id integer unsigned auto_increment primary key ) ENGINE=INNODB; CREATE TABLE orders ( id integer PRIMARY KEY auto_increment, product_id integer unsigned, quantity integer, INDEX product_id_idx (product_id), FOREIGN KEY (product_id) REFERENCES products (id) ) ENGINE=INNODB; Here the products and orders obviously have some kind of relation--foreign key relation. Also a coin has two sides,so I'm doubting how do we say which table is the foreign key side or local key side?

    Read the article

  • Rails Joins and include columns from joins table

    - by seth.vargo
    I don't understand how to get the columns I want from rails. I have two models - A User and a Profile. A User :has_many Profile (because users can revert back to an earlier version of their profile): > DESCRIBE users; +----------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +----------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | username | varchar(255) | NO | UNI | NULL | | | password | varchar(255) | NO | | NULL | | | last_login | datetime | YES | | NULL | | +----------------+--------------+------+-----+---------+----------------+   > DESCRIBE profiles; +----------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +----------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | user_id | int(11) | NO | MUL | NULL | | | first_name | varchar(255) | NO | | NULL | | | last_name | varchar(255) | NO | | NULL | | | . . . . . . | | . . . . . . | | . . . . . . | +----------------+--------------+------+-----+---------+----------------+ In SQL, I can run the query: > SELECT * FROM profiles JOIN users ON profiles.user_id = users.id LIMIT 1; +----+-----------+----------+---------------------+---------+---------------+-----+ | id | username | password | last_login | user_id | first_name | ... | +----+-----------+----------+---------------------+---------+---------------+-----+ | 1 | john | ****** | 2010-12-30 18:04:28 | 1 | John | ... | +----+-----------+----------+---------------------+---------+---------------+-----+ See how I get all the columns for BOTH tables JOINED together? However, when I run this same query in Rails, I don't get all the columns I want - I only get those from Profile: # in rails console >> p = Profile.joins(:user).limit(1) >> [#<Profile ...>] >> p.first_name >> NoMethodError: undefined method `first_name' for #<ActiveRecord::Relation:0x102b521d0> from /Library/Ruby/Gems/1.8/gems/activerecord-3.0.1/lib/active_record/relation.rb:373:in `method_missing' from (irb):8 # I do NOT want to do this (AKA I do NOT want to use "includes") >> p.user >> NoMethodError: undefined method `user' for #<ActiveRecord::Relation:0x102b521d0> from /Library/Ruby/Gems/1.8/gems/activerecord-3.0.1/lib/active_record/relation.rb:373:in method_missing' from (irb):9 I want to (efficiently) return an object that has all the properties of Profile and User together. I don't want to :include the user because it doesn't make sense. The user should always be part of the most recent profile as if they were fields within the Profile model. How do I accomplish this?

    Read the article

  • Function pointers with default parameters in C++

    - by user308926
    How does C++ handle function pointers in relation to functions with defaulted parameters? If I have: void foo(int i, float f = 0.0f); void bar(int i, float f); void (*func_ptr1)(int); void (*func_ptr2)(int, float); void (*func_ptr3)(int, float = 10.0f); Which function pointers can I use in relation to which function?

    Read the article

  • How can I load a file into a DataBag from within a Yahoo PigLatin UDF?

    - by Cervo
    I have a Pig program where I am trying to compute the minimum center between two bags. In order for it to work, I found I need to COGROUP the bags into a single dataset. The entire operation takes a long time. I want to either open one of the bags from disk within the UDF, or to be able to pass another relation into the UDF without needing to COGROUP...... Code: # **** Load files for iteration **** register myudfs.jar; wordcounts = LOAD 'input/wordcounts.txt' USING PigStorage('\t') AS (PatentNumber:chararray, word:chararray, frequency:double); centerassignments = load 'input/centerassignments/part-*' USING PigStorage('\t') AS (PatentNumber: chararray, oldCenter: chararray, newCenter: chararray); kcenters = LOAD 'input/kcenters/part-*' USING PigStorage('\t') AS (CenterID:chararray, word:chararray, frequency:double); kcentersa1 = CROSS centerassignments, kcenters; kcentersa = FOREACH kcentersa1 GENERATE centerassignments::PatentNumber as PatentNumber, kcenters::CenterID as CenterID, kcenters::word as word, kcenters::frequency as frequency; #***** Assign to nearest k-mean ******* assignpre1 = COGROUP wordcounts by PatentNumber, kcentersa by PatentNumber; assignwork2 = FOREACH assignpre1 GENERATE group as PatentNumber, myudfs.kmeans(wordcounts, kcentersa) as CenterID; basically my issue is that for each patent I need to pass the sub relations (wordcounts, kcenters). In order to do this, I do a cross and then a COGROUP by PatentNumber in order to get the set PatentNumber, {wordcounts}, {kcenters}. If I could figure a way to pass a relation or open up the centers from within the UDF, then I could just GROUP wordcounts by PatentNumber and run myudfs.kmeans(wordcount) which is hopefully much faster without the CROSS/COGROUP. This is an expensive operation. Currently this takes about 20 minutes and appears to tack the CPU/RAM. I was thinking it might be more efficient without the CROSS. I'm not sure it will be faster, so I'd like to experiment. Anyway it looks like calling the Loading functions from within Pig needs a PigContext object which I don't get from an evalfunc. And to use the hadoop file system, I need some initial objects as well, which I don't see how to get. So my question is how can I open a file from the hadoop file system from within a PIG UDF? I also run the UDF via main for debugging. So I need to load from the normal filesystem when in debug mode. Another better idea would be if there was a way to pass a relation into a UDF without needing to CROSS/COGROUP. This would be ideal, particularly if the relation resides in memory.. ie being able to do myudfs.kmeans(wordcounts, kcenters) without needing the CROSS/COGROUP with kcenters... But the basic idea is to trade IO for RAM/CPU cycles. Anyway any help will be much appreciated, the PIG UDFs aren't super well documented beyond the most simple ones, even in the UDF manual.

    Read the article

  • Is the set of data always normalized in one form or the other in Databases

    - by manugupt1
    Suppose I have a set of data, given the data and the relation schemas can I assume that the set of data is normalized in one form or the other. In my opinion raw data given, has to be normalized into some form. However a discussion with a friend has led to ask me this question here. To expound more on the question, I would say given a set of functional dependencies for a relation or table, is it guaranteed that the table would atleast be in 1NF if not others

    Read the article

  • In SqlAlchemy, how to ignore m2m relationship attributes when merge?

    - by ablmf
    There is a m2m relation in my models, User and Role. I want to merge a role, but i DO NOT want this merge has any effect on user and role relation-ship. Unfortunately, for some complicate reason, role.users if not empty. I tried to set role.users = None, but SA complains None is not a list. At this moment, I use sqlalchemy.orm.attributes.del_attribute, but I don't know if it's provided for this purpose.

    Read the article

  • many-to-one with multiple columns

    - by Sly
    I have a legacy data base and a relation one-to-one between two tables. The thing is that relation uses two columns, not one. Is there some way to say in nhibernate that when getting a referenced entity it used two columns in join statement, not one? I'm trying to use this: References(x => x.Template) .Columns() .PropertyRef() But can't get how to map join on multiple columns, any ideas?

    Read the article

  • Two-pass multi way merge sort?

    - by Nimesh
    If I have a relation (SQL) that does not fit in memory and I want to sort the relation using TPMMS (Two-pass multi-way merge sort method). How would I divide the table in sub tables (and how many) that can fit in memory and than merge them? Let's say I am using C#.

    Read the article

  • Default subclass objects in Sqlalchemy?

    - by Timmy
    im using the example from the pylons book orm.mapper(Comment, comment_table) orm.mapper(Tag, tag_table) orm.mapper(Nav, nav_table, polymorphic_on=nav_table.c.type, polymorphic_identity='nav') orm.mapper(Section, section_table, inherits=Nav, polymorphic_identity='section') orm.mapper(Page, page_table, inherits=Nav, polymorphic_identity='page', properties={ 'comments':orm.relation(Comment, backref='page', cascade='all'), 'tags':orm.relation(Tag, secondary=pagetag_table) }) i am mostly copying from this, but is there a simple way have a default Page that gets referenced, but if users requests a change, create a new Page object? thanks i want something similar to this class DefaultPage(Page): __init__(self): self.a = a self.b = b self.c = c orm.mapper(DefaultPage, None, inherits=Nav, yada yada )

    Read the article

  • Trying to connect phpMyAdmin to remote mySQL server ( 2002: can't connect )

    - by Malcolm Jones
    Trying to get phpMyAdmin to talk to a remote mySQL server. The config is below and there is already a user set up in mySQL DB to be able to log in from the specified host that PMA sits on. Hosting is provided by Rackspace (Rightscale) and both cloud servers behind the same firewall. [config.inc.php] <?php $cfg['blowfish_secret'] = ''; $i = 0; $i++; $cfg['Servers'][$i]['host'] = 'XX.XX.XX.XX'; // MySQL hostname or IP address $cfg['Servers'][$i]['port'] = ''; // MySQL port - leave blank for default port $cfg['Servers'][$i]['socket'] = ''; // Path to the socket - leave blank for default socket $cfg['Servers'][$i]['connect_type'] = 'tcp'; // How to connect to MySQL server ('tcp' or 'socket') $cfg['Servers'][$i]['extension'] = 'mysql'; // The php MySQL extension to use ('mysql' or 'mysqli') $cfg['Servers'][$i]['compress'] = FALSE; // Use compressed protocol for the MySQL connection // (requires PHP >= 4.3.0) $cfg['Servers'][$i]['controluser'] = ''; // MySQL control user settings // (this user must have read-only $cfg['Servers'][$i]['controlpass'] = ''; // access to the "mysql/user" // and "mysql/db" tables). // The controluser is also // used for all relational // features (pmadb) $cfg['Servers'][$i]['auth_type'] = 'config'; // Authentication method (config, http or cookie based)? $cfg['Servers'][$i]['user'] = 'USERNAME'; // MySQL user $cfg['Servers'][$i]['password'] = 'PASSWORD'; // MySQL password (only needed // with 'config' auth_type) $cfg['Servers'][$i]['only_db'] = ''; // If set to a db-name, only // this db is displayed in left frame // It may also be an array of db-names, where sorting order is relevant. $cfg['Servers'][$i]['hide_db'] = ''; // Database name to be hidden from listings $cfg['Servers'][$i]['verbose'] = ''; // Verbose name for this host - leave blank to show the hostname $cfg['Servers'][$i]['pmadb'] = ''; // Database used for Relation, Bookmark and PDF Features // (see scripts/create_tables.sql) // - leave blank for no support // DEFAULT: 'phpmyadmin' $cfg['Servers'][$i]['bookmarktable'] = ''; // Bookmark table // - leave blank for no bookmark support // DEFAULT: 'pma_bookmark' $cfg['Servers'][$i]['relation'] = ''; // table to describe the relation between links (see doc) // - leave blank for no relation-links support // DEFAULT: 'pma_relation' $cfg['Servers'][$i]['table_info'] = ''; // table to describe the display fields // - leave blank for no display fields support // DEFAULT: 'pma_table_info' $cfg['Servers'][$i]['table_coords'] = ''; // table to describe the tables position for the PDF schema // - leave blank for no PDF schema support // DEFAULT: 'pma_table_coords' $cfg['Servers'][$i]['pdf_pages'] = ''; // table to describe pages of relationpdf // - leave blank if you don't want to use this // DEFAULT: 'pma_pdf_pages' $cfg['Servers'][$i]['column_info'] = ''; // table to store column information // - leave blank for no column comments/mime types // DEFAULT: 'pma_column_info' $cfg['Servers'][$i]['history'] = ''; // table to store SQL history // - leave blank for no SQL query history // DEFAULT: 'pma_history' $cfg['Servers'][$i]['verbose_check'] = TRUE; // set to FALSE if you know that your pma_* tables // are up to date. This prevents compatibility // checks and thereby increases performance. $cfg['Servers'][$i]['AllowRoot'] = TRUE; // whether to allow root login $cfg['Servers'][$i]['AllowDeny']['order'] // Host authentication order, leave blank to not use = ''; $cfg['Servers'][$i]['AllowDeny']['rules'] // Host authentication rules, leave blank for defaults = array(); Please let me know if you need anymore info. -- Malcolm

    Read the article

  • Django notification get date one accesses a link

    - by dana
    hi there, i'm making a notification system, so that a user in a virtual community to be announced when someone sends him a message, or starts following him (the follow relation is like a friend relation, but it is not necessarily reciprocal) my view function: def notification_view(request, last_checked): u = Relation.objects.filter(date_follow>Notification.objects.get(last_checked=last_checked)) v = Message.objects.filter(date>Notification.objects.get(last_checked=last_checked)) if u: notification_type = follow if notice_settings == receive_notification or notice_settings == only_follow following = u if v: notification_type = message if notice_settings == receive_notification or notice_settings == only_messages message = v return render_to_response('notification/notification.html', { 'following': following, 'message':message, }, context_instance=RequestContext(request)) the models.py: class NoticeType(models.Model): follow = models.ForeignKey(Relations, editable = False) message = models.ForeignKey(Messages) classroom_invitation = models.ForeignKey(Classroom) class Notification(models.Model): receiver = models.ForeignKey(User, editable=False) date = models.DateTimeField(auto_now=True, editable = False) notice_type = models.ForeignKey(NoticeType, editable = False, related_name = "notification_type") sent = models.BooleanField(default = True) last_checked = models.DateTimeField(auto_now=True, editable = False) class NotificationSettings(models.Model): user = models.ForeignKey(User) receive_notifications = models.BooleanField(default = True) only_follow = models.BooleanField(default = False) only_message = models.BooleanField(default = False) only_classroom = models.BooleanField(default = False) #receive_on_email = models.BooleanField(default = False) my problem is: i want last_checked to be the time when someone acceses a link (the notification link). How can i possibily save that time? how can i get it? thanks in avance!

    Read the article

  • Reverse mapping from a table to a model in SQLAlchemy

    - by Jace
    To provide an activity log in my SQLAlchemy-based app, I have a model like this: class ActivityLog(Base): __tablename__ = 'activitylog' id = Column(Integer, primary_key=True) activity_by_id = Column(Integer, ForeignKey('users.id'), nullable=False) activity_by = relation(User, primaryjoin=activity_by_id == User.id) activity_at = Column(DateTime, default=datetime.utcnow, nullable=False) activity_type = Column(SmallInteger, nullable=False) target_table = Column(Unicode(20), nullable=False) target_id = Column(Integer, nullable=False) target_title = Column(Unicode(255), nullable=False) The log contains entries for multiple tables, so I can't use ForeignKey relations. Log entries are made like this: doc = Document(name=u'mydoc', title=u'My Test Document', created_by=user, edited_by=user) session.add(doc) session.flush() # See note below log = ActivityLog(activity_by=user, activity_type=ACTIVITY_ADD, target_table=Document.__table__.name, target_id=doc.id, target_title=doc.title) session.add(log) This leaves me with three problems: I have to flush the session before my doc object gets an id. If I had used a ForeignKey column and a relation mapper, I could have simply called ActivityLog(target=doc) and let SQLAlchemy do the work. Is there any way to work around needing to flush by hand? The target_table parameter is too verbose. I suppose I could solve this with a target property setter in ActivityLog that automatically retrieves the table name and id from a given instance. Biggest of all, I'm not sure how to retrieve a model instance from the database. Given an ActivityLog instance log, calling self.session.query(log.target_table).get(log.target_id) does not work, as query() expects a model as parameter. One workaround appears to be to use polymorphism and derive all my models from a base model which ActivityLog recognises. Something like this: class Entity(Base): __tablename__ = 'entities' id = Column(Integer, primary_key=True) title = Column(Unicode(255), nullable=False) edited_at = Column(DateTime, onupdate=datetime.utcnow, nullable=False) entity_type = Column(Unicode(20), nullable=False) __mapper_args__ = {'polymorphic_on': entity_type} class Document(Entity): __tablename__ = 'documents' __mapper_args__ = {'polymorphic_identity': 'document'} body = Column(UnicodeText, nullable=False) class ActivityLog(Base): __tablename__ = 'activitylog' id = Column(Integer, primary_key=True) ... target_id = Column(Integer, ForeignKey('entities.id'), nullable=False) target = relation(Entity) If I do this, ActivityLog(...).target will give me a Document instance when it refers to a Document, but I'm not sure it's worth the overhead of having two tables for everything. Should I go ahead and do it this way?

    Read the article

  • Non-normalized association with legacy tables in Rails and ActiveRecord

    - by Thomas Holmström
    I am building a Rails application accessing a legacy system. The data model contains Customers which can have one or more Subscriptions. A Subscription always belong to one and only one Customer. Though not needed, this association is represented through a join table "subscribes", which do not have an id column: Column | Type | Modifiers -----------------+---------+----------- customer_id | integer | not null subscription_id | integer | not null I have this coded as a has_and_belongs_to_many declarations in both Customer and Subscription class Customer < Activerecord::Base has_and_belongs_to_many :subscriptions, :join_table => "subscribes", :foreign_key => "customer_id", :association_foreign_key => "subscription_id" end class Subscription < Activerecord::Base has_and_belongs_to_many :customers, :join_table => "subscribes", :foreign_key => "subscription_id", :association_foreign_key => "customer_id" end The problem I have is that there can only ever be one customer for each subscription, not many, and the join table will always contain at most one row with a certain customer_id. And thus, I don't want the association "customers" on a Subscription which returns an array of (at most one) Customer, I really do want the relation "customer" which returns the Customer associated. Is there any way to force ActiveRecord to make this a 1-to-N relation even though the join table itself seems to make it an N-to-M relation? --Thomas

    Read the article

  • Drawing chunks, and positioning the camera

    - by Troubleshoot
    I've seen many questions and answers regarding how to draw tiled maps but I can't really get my head around it. Many answers suggest either loading the visible part of the map, or loading and unloading chunks of the map. I've decided the best option would be to load chunks, but I'm slightly confused as to how this would be implemented. Currently I'm loading the full map to a 2D array of buffered images, then drawing it every time repaint is called. Q1: If I were to load chunks of the map, would I load the map as a whole then draw the necessary chunk(s), or load & unload the chunks as the player moves along, and if so, how? My second question regards the camera. I want the player to be in the centre of the X axis and the camera to follow it. I've thought of drawing everything in relation to the map and calculating the position of the camera in relation to the players coordinates on the map. So, to calculate the camera's X position I understand that I should use cameraX = playerX - (canvasWidth/2), but how should I calculate the Y position? I want the camera to only move up when the player reaches cameraHeight/2 but to move down when the player reaches 3/4(cameraHeight). Q2: Should I check for this in the same way I check for collision, and move the camera relative to the movement of the player until the player stops moving, or am I thinking about it in the wrong way?

    Read the article

  • Branching and Merging Improvements in TFS2010

    - by jehan
    Introducing the concept of “first class branches” is a significant improvement as part of the 2010 release with respect to version control.  Not only does it help to distinguish between folders and branches, but it enables branch visualizations. Let us see improvements in detail. ·         In TFS2008, you don’t know which of the folders are Branches: All folders looks the same, all have the folder icon. Now, In TFS 2010 there is a new icon that shows which of the folder is a Branch.       ·      There is no visual means to manage branches in TFS2008:   You dont have any means to identify which branches are related and the relation type. Now, In TFS 2010 you have visual tools to see the Branches Hierarchy. In order to see a Branch Hierarchy just Right Click the Branch and choose: Branching and Merging –> View Hierarchy     ·         In TFS2008, there is no option to track changes path between the Branches:  If you have made a merge in a Branch you can’t track from which Branch this Merge came from. Now, you have the tools that shows the path of change between the Branches, you can also see where change was added on a timeline.  In order to track a change do the following: Step1: Right click the Branch and click View History   Step 2: Choose a changeset to track and click the “Track Changeset” button.     Step 3: Choose the branches that will be in the view and click “Visualize”. In above visual, you can see that Changesets 108,109,110 and 119 where merged from Main to Release1.0 Branch and then “Release_1.0” Branched to “Dev1.0. Step4: You can also see the Merges on a Timeline by clicking on the “Timeline Tracking” button.   Creating New Branches: In TFS 2010, the creation of branches has been streamlined a bit from the process in 2008.  In 2008, creating a new branch was like every other action in the system – changes were pended on the client, and then checked in to the server. Because of this creating new branch in TFS2008 was time-consuming process.  In TFS2010, the step where changes are pended has been bypassed and now performing the branch creation is entirely on the server.  With this approach, the round trip time for downloading a copy of each file on the branch and then uploading each file again has been eliminated.  Note: In TFS2010, the new branch will be created and committed as a single operation on the server. Pending changes will not be created, it doesn’t require a check-in as it will be carried out as a single operation and it’s not possible to cancel.     Manage Branch Permissions: The properties view for branches is also different than that of ordinary folders or file, containing some metadata for the branch, relationship information, and permissions for the branch. In TFS2008, the users who have checkout and Check-in permissions can create a branch. But, In TFS2010 you can control the permissions for Branches using Manage Branch permissions.   Reparent option in TFS2010: In TFS2008, if we have two branches which don’t have parent-child relation and we want perform merge between these two branches then we have to perform baseless merge using tf.exe command line. I have two branches Release_1.0 and Dev1.0_F2 which don’t have any relation between them, that’s why when I click on merge option in Release_1.0, in Target Branch it’s not showing Dev1.0_F2 branch to perform the merges.     Let us see what can we do for this in TFS2010, first perform a TFS baseless merge to establish a relationship between the parent branch and the child branches.  It will only merge the folder, not its contents. TFS baseless merges are performed via the command line using VS2010 command prompt and do the following:   tf merge /baseless <ParentBranch> <childBranch> Check in your pending changes. It will create the link between the branches but the relationships are still not completed.  Now, select the child branch in Source Control Explorer and from the File menu choose Source Control –> Branching and Merging –> Reparent.      In the dialog box,  choose the appropriate branch as the new parent.   Click Reparent and then go to parent branch and click merge. Now, will see that in Target Branch option Dev1.0_F2 branch is added.         Converting Folders to Branches and Branches to Folders: You can convert any Folder as Branch from Context Menu by performing right click on the folderàBranching and MergingàConvert to Branch. In similar way, you can convert the Branches to Folder using Convert to Folder option available in File Menu (FileàSource ControlàBranching and MergingàConvert to Branch). This option is not available in context menu.

    Read the article

  • DataMapper and Codeigniter - how to fully manage a many-to-many relationship

    - by user252160
    I have the following relationship CType has many Field Field has many Ctype and of course the tables used are fields, ctypes, and ctypes_fields. Normally, the ctypes_fields table should contain only ids referencing the other two tables. However, i'd like to put there a "options" field that will contain some content for the concrete instance only. I walked through all DataMapper tuts but I could'n find relevant info on how I could extract these specific values (the ones in the relation table) Should I create a separate model for this relation table or there is a clever way to do this ?

    Read the article

  • Retrieving Data related to a top-level object from parse.com using PHP

    - by Albeert Tw
    I am retrieve related data using parse.com and PHP I get the top-leve object without problems but I can't access related data. ([myRelation] => stdClass Object ( [__type] => Relation [className] => other)) Please refer to my code below: $className = "myClass"; $url = 'https://api.parse.com/1/classes/' . $className; $appId = 'xxxxxx'; $restKey = 'xxxxxxx'; $relatedParams = urlencode('include=people'); $rest = curl_init(); curl_setopt($rest, CURLOPT_SSL_VERIFYPEER, false); curl_setopt($rest, CURLOPT_URL, $url .'/io1GzkzErH/'.$relatedParams); curl_setopt($rest, CURLOPT_HTTPGET, true); curl_setopt($rest, CURLOPT_RETURNTRANSFER, true); curl_setopt($rest, CURLOPT_HTTPHEADER, array("X-Parse-Application-Id: " . $appId, "X-Parse-REST-API-Key: " . $restKey, "Content-Type: application/json")); $response = curl_exec($rest); echo $response; I want to see related objects into myRelation. Current answer is: I get this answer: stdClass Object ( [Altres] => loremipsum. [Cartell] => stdClass Object ( [__type] => File [name] => f29efff4-5db1-451a-ab42-7569fbb955a7-cartell.jpg [url] => loremipsum.jpg ) [CartellURL] => [Categoria] => Comedia [Durada] => 120min [Estat] => Al teatre [Final] => stdClass Object ( [__type] => Date [iso] => 2014-06-18T22:00:00.000Z ) [Inici] => stdClass Object ( [__type] => Date [iso] => 2014-04-25T22:00:00.000Z ) [Nom] => Losers [Prioritat] => 0 [Sala] => loremipsum [Sinopsis] => loremipsum [TrailerURL] => loremipsum.com [URLEntrada] => loremipsum.com [URLProductora] => http://www.loremipsum.com [Visible] => 1 [createdAt] => 2014-05-20T12:01:06.094Z [objectId] => io1GzkzErH [people] => stdClass Object ( [__type] => Relation [className] => persones ) [updatedAt] => 2014-05-20T12:07:22.758Z ) loremipsum But I need to know what are in [people] = stdClass Object ( [__type] = Relation [className] = persones )

    Read the article

  • WCF DataContracts and underlying data structures

    - by Xerx
    I am wondering what makes sense in relation to what objects to expose through a WCF service - should I add WCF Serialization specifications to my business entities or should I implement a converter that maps my business entities to the DataContracts that I want to expose through my WCF service? Right now I have entities on different levels: DataAccess, Business and Contract. I have converters in place that can map entities from DataAccess to Business and from Business to Contract and vice versa. Implementing and Maintaining those is time consuming and pretty tedious. What are best practices in relation to this? If I were using an OR/M such as NHibernate or Entity Framework should I be exposing the entities from the ORM directly or should I abstract them the same way I am doing now? Thanks in advance.

    Read the article

  • Database with users design

    - by 1110
    I am in database design development phase. Application will work with large number of users (LARGE :)) I designed 80% of database but I have one Users table which is connected to everything else: Users {UserId, FirstName, LastName, Username, Password, PasswordQuestion, PasswordAnswer, Gender, RoleId, LastLoginDate etc etc} I saw asp.net membership database structure where Users and Membership are two tables. My questions are: Should I use one users table with all users data in it or more tables? If answer is 'more tables', what tables to use? Any advice on how to structure relation between those tables? This is sample relation that I have, and trying to improve. I don't understand why user and userChild are separated tables?

    Read the article

  • Inserting Rows in Relationship using a Strongly Typed DataSet

    - by Manuel Faux
    I'm using ADO.NET with a strongly typed dataset in C# (.NET 3.5). I want to insert a new row to two tables which are related in an 1:n relation. The table Attachments holds the primary key part of the relation and the table LicenseAttachments holds the foreign key part. AttachmentsDataSet.InvoiceRow invoice; // Set to a valid row, also referenced in InvoiceAttachments AttachmentsDataSet.AttachmentsRow attachment; attachment = attachmentsDataSet.Attachments.AddAttachmentsRow("Name", "Description"); attachmentsDataSet.InvoiceAttachments.AddInvoiceAttachmentsRow(invoice, attachment); Of course when I first update the InvoicesAttachments table, I'll get a foreign key violation from the SQL server, so I tried updating the Attachments table first, which will create the rows, but will remove the attachment association in the InvoiceAttachments table. Why? How do I solve this problem?

    Read the article

< Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >