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  • Problem connecting to MySQL with zend

    - by wheresrhys
    I've set up a virtual host on my local machine (windows xp with xampp installed), have installed zend there and am now trying to connect to the MySQLdatabase. I get the following error message: Message: SQLSTATE[HY000] [2003] Can't connect to MySQL server on ''myhost.com'' (10060) All the tips I've found via google haven't helped. I use kaspersky antivirus and have added port 3306 to the allowed list for MySQL and Apache. I've also pinged myhost.com:3306 and get a response (with ip address 67.63.50.51), though localhost:3306 and 127.0.0.1:3306 aren't found. I've checked that other apps can still access MySQL if the virtual host is pointed at them instead and my non zend apps do work. I guess I have to do something further to the port, or maybe force the app to use a different port, but am not sure how to do either. Any help appreciated.

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  • phpmyadmin throws a blank page after installing Zend CE server

    - by infotoknowledge
    I installed LAMP on Ubuntu 12.0.4 LTE. Then I installed phpmyadmin. Everything was good. I used phpadmin to do lots of DB administration.... Then I installed Zend CE server. Now, phpmyadmin throws a blank page. No login screen. So, I reinstalled my VPS in the same sequence again. No luck. Same behavior. This time, I installed Apache, Mysql, PHP and Zend server in that order. Then I installed phpmyadmin....Unfortunately, still blank page on phpmyadmin. Any help?...Thanks in advance.

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  • Display subform after validate main form

    - by bahamut100
    Hi, I want to display a new form after the validation of a form. I use Zend_Form_SubForm to do it (I Try to Zend_Form too), but this new form is not displaying. Why ?? This is the code in question : if ($this->_request->isPost()) { $formData = $this->_request->getPost(); if ($form->isValid($formData)) { $subForm = new Zend_Form_SubForm(); $subForm ->setAction('') ->setMethod('post'); $nom=new Zend_Form_Element_Text('nom'); $submit = new Zend_Form_Element_Submit('submit'); $submit->setLabel('OK'); $subForm->addElements(array($nom,$submit)); } else { $form->populate($formData); } }

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  • zend_form ViewScript decorator / passing arguments

    - by timpone
    I have a form that is extend from Zend_Form. I am placing the form into a ViewScript decorator like this: $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml')))); I'd like to pass in a variable to this ViewScript but am not sure how this could be done. Since the partial renders out as a Zend_View (allowing $this-app_store_icon for rendering), it seems like there should be a way to pass variables to be rendered. I tried the following but to no avail. $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml'),array('app_store_picon'=>$current_app_store_picon)))); Any help on how to get this done would be appreciated. thanks

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  • How to add CSS classes to Zend_Form_Element_Select option

    - by Jah Selassie
    Hi, I'm trying to add a CSS class to a Zend_Form_Element_Select option, but I just can't find a way to do it. The desired output would be something like this: <select name="hey" id="hey"> <option value="value1" style="parent">label1</option> <option value="value2" style="sibling">sublabel1</option> <option value="value3" style="sibling">sublabel2</option> <option value="value4" style="parent">label2</option> <option value="value5" style="sibling">sublabel3</option> <option value="value6" style="sibling">sublabel4</option> </select> But I'm getting this: <select name="hey" id="hey"> <option value="value1">label1</option> <option value="value2">sublabel1</option> <option value="value3">sublabel2</option> <option value="value4">label2</option> <option value="value5">sublabel3</option> <option value="value6">sublabel4</option> </select> I can't seem to pass a CSS class attribute to any of the options in the select element although I can style the select element itselft. My code: $sel = new Zend_Form_Element_Select('hey'); $sel->setRequired(true)->setLabel('Select an Option:'); $sel->addMultiOption('value1', 'label1', array('class' => 'parent')) ->addMultiOption('value2', 'sublabel1', array('class' => 'sibling')) (etc...); After researching a bit I found out that Element_Select doesn't have a method for adding CSS styles to the options in the select box, only for the select itself. So, how can I add them? Should I extend the form_element_select? Or would a custom decorator suffice? Can anyone give me a hint? I'm baffled with this. Thanks in advance!

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  • management users with Zend_Auth and Zend_Session

    - by user1400
    I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

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  • Some question about Zend_Auth and Zend_Session

    - by user1400
    I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

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  • row specific class

    - by stimpie
    How do I create a Zend_Db_Table which returns a different class for each row.? Example UserTable has id,name and type Type contains class names (admin,client,etc...) The classes admin, client are all subclasses of user If I call fetch I need to get a admin or client object depending on the corresponding value in the db.

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  • Inject filter into Zend_View

    - by chelmertz
    Hi! I wish to set some properties in MyFilter with constructor injection but it seems impossible with Zend_View::addFilter(string $filter_class_name) since it loads a new instance upon usage. MyFilter implements Zend_Filter_Interface. Can I somehow inject an instance of a filter to an instance of Zend_View?

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  • XML configuration of Zend_Form: child nodes and attributes not always equal?

    - by Cez
    A set of forms (using Zend_Form) that I have been working on were causing me some headaches trying to figure out what was wrong with my XML configuration, as I kept getting unexpected HTML output for a particular INPUT element. It was supposed to be getting a default value, but nothing appeared. It appears that the following 2 pieces of XML are not equal when used to instantiate Zend_Form: Snippet #1: <form> <elements> <test type="hidden"> <options ignore="true" value="foo"/> </test> </elements> </form> Snippet #2: <form> <elements> <test type="hidden"> <options ignore="true"> <value>foo</value> </options> </test> </elements> </form> The type of the element doesn't appear to make a difference, so it doesn't appear to be related to hidden fields. Is this expected or not?

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  • Zend_Db_Select where() and Zend_Db_Adapter quoteInto()

    - by Chris
    Are Zend_Db_Select's where() method, when including the optional value to quite into, and Zend_Db_Adapte's quoteInto() methods basically the same as far as escaping SQL? In other words, are these two pieces of quote identical and equally secure? $select->where($this->getAdapter()->quoteInto('id = ?', 3)); $select->where(id = ?, 3); Thanks!

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  • http://localhost does not work, http://127.0.0.1 works

    - by dskanth
    Iam running Zend with Apache and got to see a strange behaviour.... If i type http://127.0.0.1 in my browser url, it works fine, but after typing: http://localhost, i will get a file download window, saying file type as: application/x-httpd-php And in my httpd.conf file, i have the following under VirtualHost *:80 definition: ServerName localhost DocumentRoot E:\zend\Apache2\htdocs\my_project\public Directory E:\zend\Apache2\htdocs\my_project\public Perhaps some configuration problem... can anyone guide me..

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  • Is there any advantages to integrate Smarty with Zend?

    - by keisimone
    Hi, i am quite familiar with Smarty and recently decided to use Zend framework in implementation. because i am aware of the various advantages of Smarty, i insisted my contractor to integrate Smarty in. But now, i am questioning my assumptions. Should I integrate Smarty in with Zend framework? simply because I am familiar with Smarty syntax? I am also involved with the programming. I got the contractor to help in the architecture and with the prototype.

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  • Xammp and Zend Library Conflicts

    - by Kieran
    Im trying to use the Zend Frameworks ACL library in my code (in codeigniter) and after including the library in my controller I get this error: Fatal error: Cannot redeclare class Zend_Acl in C:\xampp\php\PEAR\Zend\Acl.php on line 48 If I remove the include to the Zend library I get this error instead Fatal error: Class 'Zend_Acl' not found in C:\xampp\htdocs\ISU-Cart\system\application\libraries\acl.php on line 3 Any help on this?

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  • Do you use zend tool if using xampp?

    - by Joel
    Like the question asks-I'm getting started with XAMPP, and I'm wanting to do some Zend tutorials, but I'm confused about whether you still use Zend tool to create the file structure as described here: http://akrabat.com/wp-content/uploads/Getting-Started-with-Zend-Framework.pdf or if you do something different in XAMPP? Any ideas or links anyone can point me to? Thanks!

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  • Xampp and Zend Library Conflicts

    - by Kieran
    Im trying to use the Zend Frameworks ACL library in my code (in codeigniter) and after including the library in my controller I get this error: Fatal error: Cannot redeclare class Zend_Acl in C:\xampp\php\PEAR\Zend\Acl.php on line 48 If I remove the include to the Zend library I get this error instead Fatal error: Class 'Zend_Acl' not found in C:\xampp\htdocs\ISU-Cart\system\application\libraries\acl.php on line 3 Any help on this?

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  • How to change ldap password using zend

    - by NAVEED
    I am working with zend framework, PHP , Ldap on Ubuntu. I am authenticating users from ldap using zend library. Now I want to change user's ldap passwords using zend. Any Idea? This is the method that I am using to get zend authentication adapter. It is working perfectly and users are authenticated using this adapter. public function getAuthAdapter(array $params) { $front = Zend_Controller_Front::getInstance(); $options = $front->getParam('bootstrap')->getOption('ldap'); $params['username'] = split( "@" , $params['username'] ); $username = 'cn=' . $params['username'][0] . ',' . $options['server1']['baseDn']; $adapter = new Zend_Auth_Adapter_Ldap( $options, $username, $params['password']); $adapter->setIdentity( $params['username'] ); $adapter->setCredential( $params['password'] ); return $adapter; } Now how to change ldap passwords? Thanks

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  • Zend framework controller action helper

    - by guptanikhilchandra
    I am getting fatal error after adding the action helper class. I am trying to load layout corresponding to called layout. Following is my code snippet: First of all i added a helper class under application/controller/helpers: class Zend_Controller_Action_Helper_Layout extends Zend_Controller_Action_Helper_Abstract { public $pluginLoader; public function __construct() { // TODO Auto-generated Constructor $this->pluginLoader = new Zend_Loader_PluginLoader (); } public function preDispatch() { $bootstrap = $this->getActionController()->getInvokeArg('bootstrap'); $config = $bootstrap->getOptions(); $module = $this->getRequest()->getModuleName(); if (isset($config[$module]['resources']['layout']['layout'])) { $layoutScript = $config[$module]['resources']['layout']['layout']; $this->getActionController()->getHelper('layout')->setLayout($layoutScript); } } } Then i added a loader in bootstrap.php: protected function _initLayoutHelper() { $this->bootstrap('frontController'); Zend_Controller_Action_HelperBroker::addPath(APPLICATION_PATH .'/controllers/helpers'); $layout = Zend_Controller_Action_HelperBroker::addHelper(new Zend_Controller_Action_Helper_Layout()); } Following is my application.ini: [production] autoloaderNamespaces.tree = "Tree_" phpSettings.display_startup_errors = 0 phpSettings.display_errors = 0 includePaths.library = APPLICATION_PATH "/../library" bootstrap.path = APPLICATION_PATH "/Bootstrap.php" bootstrap.class = "Bootstrap" resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers" resources.frontController.moduleDirectory = APPLICATION_PATH "/modules" resources.frontController.helperDirectory = APPLICATION_PATH "/controllers/helpers" resources.modules[] = "" contact.resources.frontController.defaultControllerName = "index" resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" resources.layout.layout = layout admin.resources.layout.layout = admin admin.resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" resources.view[] = [staging : production] [testing : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 [development : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 While running this code i am getting following errors: Warning: include(Zend\Controller\Action\Helper\LayoutLoader.php) [function.include]: failed to open stream: No such file or directory in D:\personal\proj\renovate\library\Zend\Loader.php on line 83 Warning: include() [function.include]: Failed opening 'Zend\Controller\Action\Helper\LayoutLoader.php' for inclusion (include_path='D:\personal\proj\renovate\application/../library;D:\personal\proj\renovate\library;.;C:\php5\pear') in D:\personal\proj\renovate\library\Zend\Loader.php on line 83 Fatal error: Class 'Zend_Controller_Action_Helper_LayoutLoader' not found in D:\personal\proj\renovate\application\Bootstrap.php on line 33 Kindly let me know, how can i come out from this issue. I am beginner in Zend Framework. Thanks Nikhil

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  • Unit Test json output in Zend Framework

    - by lyle
    The Zend Tutorial lists many assertions to check the output generated by a request. http://framework.zend.com/manual/en/zend.test.phpunit.html But they all seem to assume that the output is html. I need to test json output instead. Are there any assertions helpful to check json, or is there at least a generic way to make assertions against the output? Anything that doesn't rely on the request outputting html?

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  • cahoots - zend framework application is not running

    - by Gaurav Sharma
    hello everyone, I downloaded cahoots from sourceforge.net. It is a zend framework application. Very nicely done and I must say that it should be a nice tutorial for everyone who is struggling to learn Zend framework. But my problem is that even after reading the instructions this application is still not running. The application just doesn't run at all giving an error message. I have tried my best. no success :( Also I wanted to execute the application as "http://localhost/cahoots" but it runs by this URL "http://localhost/cahoots/public". why is it so.? I am using XAMPP v 1.7.1 with mod-rewrite enabled. Please guide me through the process. Any good tutorials on zend framework with zend tool would be appreciable. I want to learn this framework. Thanks

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  • php cache zend framework

    - by msaif
    server side is PHP + zend framework. problem: i have huge of data appox 5000 records and no of columns are 5 in input.txt file. i like to read all data into memory only once and send some data to the every browser request. but if i update that input.txt file then updated data must be auto synchronized to that memory location. so i need to solve that problem by using memory caching technique.but caching technique has expire time.but if input.txt is updated before cache expire then i need to auto synchronize to that memory location. now i am using zend framework 1.10.is it possible in zend framework. can anybody give me some line of code of zendfrmawork i have no option to use memchached server(distributed). Only zend framwork.

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  • Zend Framework Error:Invalid parameter number: no parameters were bound'

    - by roast_soul
    I'm using the Zend Frameworker 1.12. According to the help file, I used the Zend_Db_Statement to execute my sql. Below is my php code: $sql = "delete from options where id=?"; $stmt = new Zend_Db_Statement_Mysqli($this->getAdapter(), $sql); return $stmt->execute(array('1')); But the error is exception 'PDOException' with message 'SQLSTATE[HY093]: Invalid parameter number: no parameters were bound' in D:\Zend\workspaces\DefaultWorkspace.metadata.plugins\org.zend.php.framework.resource\resources\ZendFramework-1\library\Zend\Db\Statement\Mysqli.php:209 Stack trace: ......... ......... I googled for days, but nothing works. Any one know how to fix it?

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