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  • What's the simplest way to create a Zend_Form tabular display with each row having a radio button?

    - by RenderIn
    I've seen simple examples of rendering a Zend_Form using decorators, but I'm not sure they are able to handle the issue I'm facing very well. I query the database and get an array of user objects. I want to display these users as a form, with a radio button next to each of them and a submit button at the bottom of the page. Here's roughly what the form will look like: [user id] [email] [full name] ( ) 1 [email protected] Test user 1 (*) 2 [email protected] Test user 2 [SUBMIT] Is this something achievable in a reasonably straightforward way or do I need to use the ViewScript partial?

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  • row specific class

    - by stimpie
    How do I create a Zend_Db_Table which returns a different class for each row.? Example UserTable has id,name and type Type contains class names (admin,client,etc...) The classes admin, client are all subclasses of user If I call fetch I need to get a admin or client object depending on the corresponding value in the db.

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  • Inject filter into Zend_View

    - by chelmertz
    Hi! I wish to set some properties in MyFilter with constructor injection but it seems impossible with Zend_View::addFilter(string $filter_class_name) since it loads a new instance upon usage. MyFilter implements Zend_Filter_Interface. Can I somehow inject an instance of a filter to an instance of Zend_View?

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  • how to decorate the error message

    - by ulduz114
    this is the decorator code $mydecorate = array( 'ViewHelper', array('Errors', array('placement' => 'append','class' => 'error')), array('Label', array('separator' => '')), array('HtmlTag', array('tag' => 'p', 'class' => 'element-form')) ); html result of two input elements with the above decorator: <p class="element-form"> <label for="firstname" class="required">First Name:</label> <input name="firstname" id="firstname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> <p class="element-form"> <label for="lastname" class="required">Last Name:</label> <input name="lastname" id="lastname" value="" type="text"> </p><ul class="error"><li>required field!</li></ul> I'd like the error message to be placed inside the p.element-form tag, any idea pleas? thanks

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  • XML configuration of Zend_Form: child nodes and attributes not always equal?

    - by Cez
    A set of forms (using Zend_Form) that I have been working on were causing me some headaches trying to figure out what was wrong with my XML configuration, as I kept getting unexpected HTML output for a particular INPUT element. It was supposed to be getting a default value, but nothing appeared. It appears that the following 2 pieces of XML are not equal when used to instantiate Zend_Form: Snippet #1: <form> <elements> <test type="hidden"> <options ignore="true" value="foo"/> </test> </elements> </form> Snippet #2: <form> <elements> <test type="hidden"> <options ignore="true"> <value>foo</value> </options> </test> </elements> </form> The type of the element doesn't appear to make a difference, so it doesn't appear to be related to hidden fields. Is this expected or not?

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  • Zend_Db_Select where() and Zend_Db_Adapter quoteInto()

    - by Chris
    Are Zend_Db_Select's where() method, when including the optional value to quite into, and Zend_Db_Adapte's quoteInto() methods basically the same as far as escaping SQL? In other words, are these two pieces of quote identical and equally secure? $select->where($this->getAdapter()->quoteInto('id = ?', 3)); $select->where(id = ?, 3); Thanks!

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  • http://localhost does not work, http://127.0.0.1 works

    - by dskanth
    Iam running Zend with Apache and got to see a strange behaviour.... If i type http://127.0.0.1 in my browser url, it works fine, but after typing: http://localhost, i will get a file download window, saying file type as: application/x-httpd-php And in my httpd.conf file, i have the following under VirtualHost *:80 definition: ServerName localhost DocumentRoot E:\zend\Apache2\htdocs\my_project\public Directory E:\zend\Apache2\htdocs\my_project\public Perhaps some configuration problem... can anyone guide me..

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  • Is there any advantages to integrate Smarty with Zend?

    - by keisimone
    Hi, i am quite familiar with Smarty and recently decided to use Zend framework in implementation. because i am aware of the various advantages of Smarty, i insisted my contractor to integrate Smarty in. But now, i am questioning my assumptions. Should I integrate Smarty in with Zend framework? simply because I am familiar with Smarty syntax? I am also involved with the programming. I got the contractor to help in the architecture and with the prototype.

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  • Xammp and Zend Library Conflicts

    - by Kieran
    Im trying to use the Zend Frameworks ACL library in my code (in codeigniter) and after including the library in my controller I get this error: Fatal error: Cannot redeclare class Zend_Acl in C:\xampp\php\PEAR\Zend\Acl.php on line 48 If I remove the include to the Zend library I get this error instead Fatal error: Class 'Zend_Acl' not found in C:\xampp\htdocs\ISU-Cart\system\application\libraries\acl.php on line 3 Any help on this?

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  • Do you use zend tool if using xampp?

    - by Joel
    Like the question asks-I'm getting started with XAMPP, and I'm wanting to do some Zend tutorials, but I'm confused about whether you still use Zend tool to create the file structure as described here: http://akrabat.com/wp-content/uploads/Getting-Started-with-Zend-Framework.pdf or if you do something different in XAMPP? Any ideas or links anyone can point me to? Thanks!

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  • Xampp and Zend Library Conflicts

    - by Kieran
    Im trying to use the Zend Frameworks ACL library in my code (in codeigniter) and after including the library in my controller I get this error: Fatal error: Cannot redeclare class Zend_Acl in C:\xampp\php\PEAR\Zend\Acl.php on line 48 If I remove the include to the Zend library I get this error instead Fatal error: Class 'Zend_Acl' not found in C:\xampp\htdocs\ISU-Cart\system\application\libraries\acl.php on line 3 Any help on this?

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  • Zend framework controller action helper

    - by guptanikhilchandra
    I am getting fatal error after adding the action helper class. I am trying to load layout corresponding to called layout. Following is my code snippet: First of all i added a helper class under application/controller/helpers: class Zend_Controller_Action_Helper_Layout extends Zend_Controller_Action_Helper_Abstract { public $pluginLoader; public function __construct() { // TODO Auto-generated Constructor $this->pluginLoader = new Zend_Loader_PluginLoader (); } public function preDispatch() { $bootstrap = $this->getActionController()->getInvokeArg('bootstrap'); $config = $bootstrap->getOptions(); $module = $this->getRequest()->getModuleName(); if (isset($config[$module]['resources']['layout']['layout'])) { $layoutScript = $config[$module]['resources']['layout']['layout']; $this->getActionController()->getHelper('layout')->setLayout($layoutScript); } } } Then i added a loader in bootstrap.php: protected function _initLayoutHelper() { $this->bootstrap('frontController'); Zend_Controller_Action_HelperBroker::addPath(APPLICATION_PATH .'/controllers/helpers'); $layout = Zend_Controller_Action_HelperBroker::addHelper(new Zend_Controller_Action_Helper_Layout()); } Following is my application.ini: [production] autoloaderNamespaces.tree = "Tree_" phpSettings.display_startup_errors = 0 phpSettings.display_errors = 0 includePaths.library = APPLICATION_PATH "/../library" bootstrap.path = APPLICATION_PATH "/Bootstrap.php" bootstrap.class = "Bootstrap" resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers" resources.frontController.moduleDirectory = APPLICATION_PATH "/modules" resources.frontController.helperDirectory = APPLICATION_PATH "/controllers/helpers" resources.modules[] = "" contact.resources.frontController.defaultControllerName = "index" resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" resources.layout.layout = layout admin.resources.layout.layout = admin admin.resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" resources.view[] = [staging : production] [testing : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 [development : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 While running this code i am getting following errors: Warning: include(Zend\Controller\Action\Helper\LayoutLoader.php) [function.include]: failed to open stream: No such file or directory in D:\personal\proj\renovate\library\Zend\Loader.php on line 83 Warning: include() [function.include]: Failed opening 'Zend\Controller\Action\Helper\LayoutLoader.php' for inclusion (include_path='D:\personal\proj\renovate\application/../library;D:\personal\proj\renovate\library;.;C:\php5\pear') in D:\personal\proj\renovate\library\Zend\Loader.php on line 83 Fatal error: Class 'Zend_Controller_Action_Helper_LayoutLoader' not found in D:\personal\proj\renovate\application\Bootstrap.php on line 33 Kindly let me know, how can i come out from this issue. I am beginner in Zend Framework. Thanks Nikhil

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  • How to change ldap password using zend

    - by NAVEED
    I am working with zend framework, PHP , Ldap on Ubuntu. I am authenticating users from ldap using zend library. Now I want to change user's ldap passwords using zend. Any Idea? This is the method that I am using to get zend authentication adapter. It is working perfectly and users are authenticated using this adapter. public function getAuthAdapter(array $params) { $front = Zend_Controller_Front::getInstance(); $options = $front->getParam('bootstrap')->getOption('ldap'); $params['username'] = split( "@" , $params['username'] ); $username = 'cn=' . $params['username'][0] . ',' . $options['server1']['baseDn']; $adapter = new Zend_Auth_Adapter_Ldap( $options, $username, $params['password']); $adapter->setIdentity( $params['username'] ); $adapter->setCredential( $params['password'] ); return $adapter; } Now how to change ldap passwords? Thanks

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  • Unit Test json output in Zend Framework

    - by lyle
    The Zend Tutorial lists many assertions to check the output generated by a request. http://framework.zend.com/manual/en/zend.test.phpunit.html But they all seem to assume that the output is html. I need to test json output instead. Are there any assertions helpful to check json, or is there at least a generic way to make assertions against the output? Anything that doesn't rely on the request outputting html?

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  • php cache zend framework

    - by msaif
    server side is PHP + zend framework. problem: i have huge of data appox 5000 records and no of columns are 5 in input.txt file. i like to read all data into memory only once and send some data to the every browser request. but if i update that input.txt file then updated data must be auto synchronized to that memory location. so i need to solve that problem by using memory caching technique.but caching technique has expire time.but if input.txt is updated before cache expire then i need to auto synchronize to that memory location. now i am using zend framework 1.10.is it possible in zend framework. can anybody give me some line of code of zendfrmawork i have no option to use memchached server(distributed). Only zend framwork.

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  • cahoots - zend framework application is not running

    - by Gaurav Sharma
    hello everyone, I downloaded cahoots from sourceforge.net. It is a zend framework application. Very nicely done and I must say that it should be a nice tutorial for everyone who is struggling to learn Zend framework. But my problem is that even after reading the instructions this application is still not running. The application just doesn't run at all giving an error message. I have tried my best. no success :( Also I wanted to execute the application as "http://localhost/cahoots" but it runs by this URL "http://localhost/cahoots/public". why is it so.? I am using XAMPP v 1.7.1 with mod-rewrite enabled. Please guide me through the process. Any good tutorials on zend framework with zend tool would be appreciable. I want to learn this framework. Thanks

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  • Zend Framework Error:Invalid parameter number: no parameters were bound'

    - by roast_soul
    I'm using the Zend Frameworker 1.12. According to the help file, I used the Zend_Db_Statement to execute my sql. Below is my php code: $sql = "delete from options where id=?"; $stmt = new Zend_Db_Statement_Mysqli($this->getAdapter(), $sql); return $stmt->execute(array('1')); But the error is exception 'PDOException' with message 'SQLSTATE[HY093]: Invalid parameter number: no parameters were bound' in D:\Zend\workspaces\DefaultWorkspace.metadata.plugins\org.zend.php.framework.resource\resources\ZendFramework-1\library\Zend\Db\Statement\Mysqli.php:209 Stack trace: ......... ......... I googled for days, but nothing works. Any one know how to fix it?

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  • Zend Framework Autoloader question.

    - by Andre
    In zend framework I register my namespace like this (in application.php): 'autoloaderNamespaces' => array( 'Cms_' ) And after this - I'd expect that Zend would always check that path in addition to Zend and ZendX paths if unknown class is called. But for some reason this doesn't work with for example view helpers. I still have to register a separate path for my view helpers even though view helper scripts are named according to Zend coding standards and are located in: Cms/View/Helper/ And this is how I register helper path in config file: view' => array( 'charset' => 'UTF-8', 'doctype' => 'XHTML1_TRANSITIONAL', 'helperPath' => array( 'Cms_View_Helper_' => 'Cms/View/Helper' ) ), So - I'm not sure why I have to register "Cms" namespace twice first through 'autoloaderNamespaces' and then through View "helperPath"? Shouldn't Cms namespace include Cms/View/Helper namespace? can someone plz clarify this:)

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  • Zend Framework Installation

    - by theband
    I get this error after finishing the Zend Installation. Server error! The server encountered an internal error and was unable to complete your request. Either the server is overloaded or there was an error in a CGI script. If you think this is a server error, please contact the webmaster.

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  • Unattended Install of Zend Server license

    - by Zoop - Josh
    I have a Zend Server 5.6 development license and I wanted to know if there is a way to apply the license during install, rather than via the web interface after it has installed. I ask because I administer our server environment via Rightscale and have automated the creation of the server, however it still requires manual input for the license details. We regularly fire up a staging server to do final tests before pushing to production and it would be great if it were completely hands off.

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