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• How do I write a single-file Django application?

  - by obvio171

  I want to write a very small Django application in a single file, requiring all the appropriate modules and stuff, and then be able to run that as a normal Python script, like this: $ python myapp.py You can assume I won't render HTML, so I don't need templates (I'll return JSON or some other auto-generated string).

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• How do you use Django forms when receiving JSON Ajax requests from an iPad?

  - by MikeN

  I'm sending a lot of JSON requests from an iPad application to my Django web server. How do I translate forms I use on my website to handle an iPad web service? Am I trying to solve the wrong problem, should a web service used from the iPad be redesigned to use REST-ful requests?

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• Django: What's the correct way to get the requesting IP address?

  - by swisstony

  I'm trying to develop an app using Django 1.1 on Webfaction. I'd like to get the IP address of the incoming request, but when I use request.META['REMOTE_ADDR'] it returns 127.0.0.1. There seems to be a number of different ways of getting the address, such as using HTTP_X_FORWARDED_FOR or plugging in some middleware called SetRemoteAddrFromForwardedFor. Just wondering what the best approach was?

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• How do I do multiple processes for Django, on my WSGI apache?

  - by alex

  My friend says that Django only has 1 thread or something? And I have to edit my 000-default in order to add more processes? He suggests 4 or 5. What exactly is this, and what do I have to do? Thanks, I'm a noob.

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• How to send html email with django with dynamic content in it?

  - by Ankit Jaiswal

  Hi all, Can anyone please help me sending html email with dynamic contents. One way is to copy the entire html code into a variable and populate the dynamic code within it in Django views, but that does not seem to be a good idea, as its a very large html file. I would appreciate any suggestions. Thanks.

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• Django/jquery: Address forms - dyamically adding state drop down list if country is United States?

  - by User

  I have a django html form for address information. There is standard street, city, state/province, postal code, country fields. The country field is a drop down list. How can I make the state/province field a drop down list if the selected country is united states and a free form text box if the country is anything else? I'd prefer not to have to do a round trip to the server so probably through jquery?

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• Are django sessisons safe to use for mission critical signup forms?

  - by Gattster

  What is the best practice when designing a mission critical signup form when it comes to using django-powered sessions? Is it generally considered ok to require the user to accept the session cookie? Are there any tips to maximize the percent of users who can accept the session cookie?

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• How do I collect a bunch of Django abstract models in a QuerySet?

  - by Thierry Lam

  I have the following abstract Django models: class Food(models.Model): name = models.CharField(max_length=100) class Meta: abstract = True In one of my view, I created a bunch of Food model: panino = Food(name='Panino') poutine = Food(name='Poutine') food = [panino, poutine] From the above, I'm not saving the model and storing the Food model in a regular Python list. I want to store the above food models in a QuerySet object. How can I do that without storing any data to the database?

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• What are PHP's advantages over Ruby on Rails and Django?

  - by flybywire

  PHP was the undisputed king of easy webapp development, until Ruby on Rails, Django, and other dynamic programming frameworks appeared. What are, in your opinion, PHP's strengths against the newcomers?

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• Any reason not to use USE_ETAGS with CommonMiddleware in Django?

  - by allyourcode

  The only reason I can think of is that calculating ETag's might be expensive. If pages change very quickly, the browser's cache is likely to be invalidated by the ETag. In that case, calculating the ETag would be a waste of time. On the other hand, a giving a 304 response when possible minimizes the amount of time spent in transmission. What are some good guidelines for when ETag's are likely to be a net winner when implemented with Django's CommonMiddleware?

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• How to process database writes asynchronously (maybe with a message queue) from Django?

  - by Continuation

  After a user submitted data to my app, I'd like to write to the database asynchronously, possibly through a message queue. How do I set up such a system? Are there any pluggable Django apps that do such message queue-based database writes? Also how do i handle errors that happens during the async processing? Would really appreciate any pointers you can give me. Thank you.

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• MySQL vs PostgreSQL? Which should I choose for my Django project?

  - by rmh

  My Django project is going to be backed by a large database with several hundred thousand entries, and will need to support searching (I'll probably end up using djangosearch or a similar project.) Which database backend is best suited to my project and why? Can you recommend any good resources for further reading?

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• How can I send variables to my forms on init in Django?

  - by blackrobot

  I want to send variables to a form in my Django project so that my form's save method associates the correct object with the foreign key in the model. I tried setting it in the init method, but that doesn't seem to work.

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• django 1.2.1: Override model name in admin interface?

  - by Paul Sanwald

  I have a model called "Activity" in my django app. in the admin interface, it appears on the screen as "Activitys". how can I override the label on the admin page to make it "Activities" instead? I see in the archives how to do this for a field, but not for a model itself. thanks!

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• How do I sort a list of python Django objects?

  - by alex

  In Django, I have a model object in a list. [object, object, object] Each object has ".name" which is the title of the thing. How do I sort alphabetically by this title? This doesn't work: catlist.sort(key=lambda x.name: x.name.lower())

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• I am currently serving my static files in Django. How do I use Apache2 to do this?

  - by alex

  (r'^media/(?P<path>.*)$', 'django.views.static.serve',{'document_root': settings.MEDIA_ROOT}), As you can see, I have a directory called "media" under my Django project. I would like to delete this line in my urls.py and instead us Apache to serve my static files. What do I do to my Apache configs (which files do I change) in order to do this? By the way, I installed Apache2 like normal: sudo aptitude install apache2

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• iphone PDF view CGPDFDocument

  - by i.novice

  I am developing an app where I need to show PDF documents. After many hours of googling I was able to build up a view to show the PDF document fetched from a URL. I know only to display a single page. using CGPDFDocumentGetPage(ref, pageNumber). What I would like to have. Pagination function. Zoom Scrolling

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• Ordering columns in Rails, cakephp style.

  - by Smickie

  CakePHP's built in pagination helpers automatically allow column ordering in the view. If you bake the view you get a link on each column to order it by that data. Is there a way to get this functionality in Rails? The standard will paginate doesn't offer it, anyone know any good ones?

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• Need tips for better usability for tabular data with pagination

  - by Anil Namde

  Hi all, Just another day i found myself writing code to show data on the UI. I am again using DataGrid/GridView (ASP.NET), User Id as link button (clickable) to redirect user to another page. User having hard time to find where to click(Though the link has underline and hand pointer as usual on hover) just another common table like structure Following are the columns for example, User ID (Link button), User Name, First Name, Last Name, Date Of Birth Now i would like to make it better form the usability point of view. Can someone suggest a good link, example or suggestions to make it better. Thanks all,

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• problem in accessing the path involving pagination using display tag

  - by sarah

  Hi All, I am using display tag for pagiantion and display of the data in table format the code is like <display:column title="Select" style="width: 90px;"> <input type="checkbox" name="optionSelected" value="<c:out value='${userList.loginName}'/>"/> </display:column> <display:column property="loginName" sortable="false" title="UserName" paramId="loginName" style="width: 150px; text-align:center" href="./editUser.do?method=editUser"/> the pagesize is one it will display one in a page and eidt page will be dispaly on click of login name,but when i go to the second page i get an error saying /views/editUser path not found.How exactly should i define the path ? the struts-config is like <!-- action for edit user --> <action path="/editUser" name="editUserForm" type="com.actions.UserManagementAction" parameter="method" input="/EditUser.jsp" scope="request"> <forward name="success" path="/views/EditUser.jsp" /> <forward name="failure" path="/views/failure.jsp" /> </action> Pleas tell me how should i define the access path for display tag as on click of edit link the first page works but not the second edit

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• Applying pagination options to a one-to-many list in Grails

  - by UltraVi01

  I have a User class that hasMany = [friends:User] Now I am trying to display the friends list - ${user.friends} However, I'd like to be able to apply parameters like I can with, for example, User.findAllBy(user, [max:10, sort: 'dateCreated', order: 'desc"]) Can someone kindly tell me how to do this on a one-to-many in Grails / Groovy ?

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• php / mysql pagination

  - by arrgggg

  Hi, I have a table with 58 records in mysql database. I was able to connect to my database and retrive all records and made 5 pages with links to view each pages using php script. webpage will look like this: name number john 1232343456 tony 9878768544 jack 3454562345 joe 1232343456 jane 2343454567 andy 2344560987 marcy 9873459876 sean 8374623534 mark 9898787675 nancy 8374650493 1 2 3 4 5 that's the first page of 58 records and those 5 numbers at bottom are links to each page that will display next 10 records. I got all that. but what I want to do is display the links in this way: 1-10 11-20 21-30 31-40 41-50 51-58 note: since i have 58 records, last link will display upto 58, instead of 60. Since I used the loop to create this link, depending on how many records i have, the link will change according to the number of records in my table. How can i do this? Thanks.

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• XSLT: a variation on the pagination problem

  - by MarcoS

  I must transform some XML data into a paginated list of fields. Here is an example. Input XML: <?xml version="1.0" encoding="UTF-8"?> <data> <books> <book title="t0"/> <book title="t1"/> <book title="t2"/> <book title="t3"/> <book title="t4"/> </books> <library name="my library"/> </data> Desired output: <?xml version="1.0" encoding="UTF-8"?> <pages> <page number="1"> <field name="library_name" value="my library"/> <field name="book_1" value="t0"/> <field name="book_2" value="t1"/> </page> <page number="2"> <field name="book_1" value="t2"/> <field name="book_2" value="t3"/> </page> <page number="3"> <field name="book_1" value="t4"/> </page> </pages> In the above example I assume that I want at most 2 fields named book_n (with n ranging between 1 and 2) per page. Tags <page> must have an attribute number. Finally, the field named library_name must appear only the first <page>. Here is my current solution using XSLT: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" exclude-result-prefixes="trx xs"> <xsl:output method="xml" indent="yes" omit-xml-declaration="no" /> <xsl:variable name="max" select="2"/> <xsl:template match="//books"> <xsl:for-each-group select="book" group-ending-with="*[position() mod $max = 0]"> <xsl:variable name="pageNum" select="position()"/> <page number="{$pageNum}"> <xsl:for-each select="current-group()"> <xsl:variable name="idx" select="if (position() mod $max = 0) then $max else position() mod $max"/> <field value="{@title}"> <xsl:attribute name="name">book_<xsl:value-of select="$idx"/> </xsl:attribute> </field> </xsl:for-each> <xsl:if test="$pageNum = 1"> <xsl:call-template name="templateFor_library"/> </xsl:if> </page> </xsl:for-each-group> </xsl:template> <xsl:template name="templateFor_library"> <xsl:for-each select="//library"> <field name="library_name" value="{@name}" /> </xsl:for-each> </xsl:template> </xsl:stylesheet> Is there a better/simpler way to perform this transformation?

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• Pagination - Twitter's people you follow

  - by anselmophil

  Hi guys, im developing an Android application for twitter that will sync data coming from the people you follow. The problem is that: http://api.twitter.com/1/statuses/friends.json provides me the last 100 persons ive followed and i wanted to display only 20 for each 'page'. I believe that the 'cursor' parameter doesnt do what i need, so i'm trying to figure out a way to store it. Can you guys give me enlightenment? Thanks in advance

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• How to skip footer page numbering for the first 4 pages in Word 2007?

  - by Pentium10

  How to skip footer page numbering for the first 4 pages in Word 2007?

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