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  • How to develop JSP/Servlets Web App using MVC pattern?

    - by A.S al-shammari
    I'm developing a JSP/Servlets web app (no frameworks). I want to use MVC pattern. I designed my project like this : Controller :a servlet that reads a request, extracts the values,communicates with model objects and gives information to a JSP page. View : JSP Pages. Model : Java Classes / Java Beans .. etc . The problem : Index.jsp is the starting point (default page) in my web site. So, the Index.jsp becomes the controller to parse the request! .For example , the following request : index.jsp?section=article&id=10 parsed in index.jsp as following : <div class="midcol"> <!-- Which section? --> <%String fileName = request.getParameter("section"); if (fileName == null) { fileName = "WEB-INF/jspf/frontpage.jsp"; } else { fileName = "WEB-INF/jspf/" + fileName + ".jsp"; } %> <jsp:include page='<%= fileName%>' /> </div> Here, I can't force the servlet to be a controller .. because the index.jsp is the controller here since it's the starting point! Is there any solution to forward the request from index.jsp to the servlet and then go back to index.jsp ? Or any solution that achieves the MVC goal - the servlet should be the controller - ? I'm thinking of making a FrontPageController servlet as default page instead of index.jsp ! but I don't know if it's a perfect idea ?!

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  • Why is setting HTML5's CanvasPixelArray values is ridiculously slow and how can I do it faster?

    - by Nixuz
    I am trying to do some dynamic visual effects using the HTML 5 canvas' pixel manipulation, but I am running into a problem where setting pixels in the CanvasPixelArray is ridiculously slow. For example if I have code like: imageData = ctx.getImageData(0, 0, 500, 500); for (var i = 0; i < imageData.length; i += 4){ imageData.data[index] = buffer[i]; imageData.data[index + 1] = buffer[i]; imageData.data[index + 2] = buffer[i]; } ctx.putImageData(imageData, 0, 0); Profiling with Chrome reveals, it runs 44% slower than the following code where CanvasPixelArray is not used. tempArray = new Array(500 * 500 * 4); imageData = ctx.getImageData(0, 0, 500, 500); for (var i = 0; i < imageData.length; i += 4){ tempArray[index] = buffer[i]; tempArray[index + 1] = buffer[i]; tempArray[index + 2] = buffer[i]; } ctx.putImageData(imageData, 0, 0); My guess is that the reason for this slowdown is due to the conversion between the Javascript doubles and the internal unsigned 8bit integers, used by the CanvasPixelArray. Is this guess correct? Is there anyway to reduce the time spent setting values in the CanvasPixelArray?

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  • Regex to add CDATA for mal formed XML

    - by AntonioCS
    Hey guys! I have this huge xml file (13 mb) and it has some malformed values. Here is a sample of the xml: <propertylist> <adprop index="0" proptype="type" value="Ft"/> <adprop index="0" proptype="category" value="Bs"/> <adprop index="0" proptype="subcategory" value="Bsm"/> <adprop index="0" proptype="description" value="MOONEN CUSTOM 58"/> </propertylist> Now this is ok. But I many other nodes that are not encapsulated in CDATA that need to be. The node that gives me problems is the <adprop index="0" proptype="description" value=""/> I created this regular expression: <adprop index="0" proptype="description" value="(.+)"\/> to catch that node and replace it with this: <adprop index="0" proptype="description" value="<![CDATA[\1]]>"\/> I run this in notepad++ and it works. The only problem is when the value="" is multi lined like: <adprop index="0" proptype="description" value="cutter that has demonstrated her offshore capabiliti from there to the Canaries with her current owner. Spacious homely interior with over 2m headroom and heaps of" /> It fails with this one, and there are plenty like this one. Can anyone help me out in the regular expression so that I can catch the value when it's multi lined? Thanks

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  • help on ejb stateless datagram and message driven beans

    - by Kemmal
    i have a client thats sending a message to the ejbserver using UDP, i want the server(stateless bean) to echo back this message to the client but i cant seem to do this. or can i implement the same logic by using JMS? please help and enlighten. this is just a test, in the end i want a midp to be sending the message to the ejb using datagrams. here is my code. @Stateless public class SessionFacadeBean implements SessionFacadeRemote { public SessionFacadeBean() { } public static void main(String[] args) { DatagramSocket aSocket = null; byte[] buffer = null; try { while(true) { DatagramPacket request = new DatagramPacket(buffer, buffer.length); aSocket.receive(request); DatagramPacket reply = new DatagramPacket(request.getData(), request.getLength(), request.getAddress(), request.getPort()); aSocket.send(reply); } } catch (SocketException e) { System.out.println("Socket: " + e.getMessage()); } catch (IOException e) { System.out.println("IO: " + e.getMessage()); } finally { if(aSocket != null) aSocket.close(); } } } and the client: public static void main(String[] args) { DatagramSocket aSocket = null; try { aSocket = new DatagramSocket(); byte [] m = "Test message!".getBytes(); InetAddress aHost = InetAddress.getByName("localhost"); int serverPort = 6789; DatagramPacket request = new DatagramPacket(m, m.length, aHost, serverPort); aSocket.send(request); byte[] buffer = new byte[1000]; DatagramPacket reply = new DatagramPacket(buffer, buffer.length); aSocket.receive(reply); System.out.println("Reply: " + new String(reply.getData())); } catch (SocketException e) { System.out.println("Socket: " + e.getMessage()); } catch (IOException e) { System.out.println("IO: " + e.getMessage()); } finally { if(aSocket != null) aSocket.close(); } } please help.

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  • Not able to display the progress bar using threading concept?

    - by Rakesh
    I am trying to show a progress bar while my process is going on...in my application there will be a situation where I gotta read files and manipulate them(it will take some time to complete)..want to display a progress bar during this operation..the particular function I am calling is an win 32 ...so if you check my code below ...I am able to display the progressbar but it doesnt show any progress..actually its not doing any further process...Please help me..thanks in advance //my function int Myfunction(....) { MSG msg; HWND dialog = CreateWindowEx(0,WC_DIALOG,L"Proccessing...",WS_OVERLAPPEDWINDOW|WS_VISIBLE, 600,300,280,120,NULL,NULL,NULL,NULL); HWND pBar = CreateWindowEx(NULL,PROGRESS_CLASS,NULL,WS_CHILD|WS_VISIBLE,40,20,200, 20, dialog,(HMENU)IDD_PROGRESS,NULL,NULL); SendMessage(pBar,PBM_SETRANGE,0,MAKELPARAM(0,noOfFile)); while(GetMessage(&msg,NULL,0,0)) { TranslateMessage(&msg); Dispatch(&message); } HANDLE getHandle = CreateThread(NULL,NULL,(LPTHREAD_START_ROUTINE)SetFilesForOperation(...), NULL,NULL,0); } LPARAM SetFilesForOperation(...) { for(int index = 0;index < noOfFiles; index++) { *checkstate = *(checkState + index); if(*checkstate == -1) { *(getFiles+i) = new TCHAR[MAX_PATH]; wcscpy(*(getFiles+i),*(dataFiles +index)); i++; } else { (*tempDataFiles)->Add(*(dataFiles+index)); *(checkState + localIndex) = *(checkState + index); localIndex++; } PostMessage(pBar,PBM_SETPOS,(WPARAM)index,0); } }

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  • Apache RewriteRule: it is possible to 'detect' the first and second path segment?

    - by DaNieL
    Im really really a newbie in regexp and I can’t figure out how to do that. My goal is to have the RewriteRule to 'slice' the request URL path in 3 parts: example.com/foo #should return: index.php?a=foo&b=&c= example.com/foo/bar #should return: index.php?a=foo&b=bar&c= example.com/foo/bar/baz #should return: index.php?a=foo&b=bar&c=baz example.com/foo/bar/baz/bee #should return: index.php?a=foo&b=bar&c=baz/bee example.com/foo/bar/baz/bee/apple #should return: index.php?a=foo&b=bar&c=baz/bee/apple example.com/foo/bar/baz/bee/apple/and/whatever/else/no/limit/in/those/extra/parameters #should return: index.php?a=foo&b=bar&c=baz/bee/apple/and/whatever/else/no/limit/in/those/extra/parameters In short, the first segment in the URL path (foo) should be given to a, the second segment (bar) to b, and the rest of the string in c I wroted this one <IfModule mod_rewrite.c> RewriteEngine on RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_URI} !=/favicon.ico RewriteRule ^(([a-z0-9/]))?(([a-z0-9/]+))?(([a-z0-9]+))(.*)$ index.php?a=$1&b=$2&c=$3 [L,QSA] </IfModule> But obviously doesn’t work, and I don’t even know if what I want is possible. Any suggestion? EDIT: After playing with coach manager, I got this one working too: RewriteRule ^([^/]*)?/?([^/]*)?/?(.*)?$ index.php?a=$1&b=$2&c=$3 [L,QSA]

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  • how to hide ssh expect user/password

    - by raindrop18
    my perl cgi script I have the password/user on clear text and want to hide it or the user enter the credential interactively.is that possible? here is my code. please any help!! i am very new for perl. #!/usr/local/bin/expect ####################################################################################################### # Input: It will handle two arguments -> a device and a show command. ####################################################################################################### # ######### Start of Script ###################### # #### Set up Timeouts - Debugging Variables log_user 0 set timeout 10 set userid "USER" set password "PASS" # ############## Get two arguments - (1) Device (2) Command to be executed set device [lindex $argv 0] set command [lindex $argv 1] spawn /usr/local/bin/ssh -l $userid $device match_max [expr 32 * 1024] expect { -re "RSA key fingerprint" {send "yes\r"} timeout {puts "Host is known"} } expect { -re "username: " {send "$userid\r"} -re "(P|p)assword: " {send "$password\r"} -re "Warning:" {send "$password\r"} -re "Connection refused" {puts "Host error -> $expect_out(buffer)";exit} -re "Connection closed" {puts "Host error -> $expect_out(buffer)";exit} -re "no address.*" {puts "Host error -> $expect_out(buffer)";exit} timeout {puts "Timeout error. Is device down or unreachable?? ssh_expect";exit} } expect { -re "\[#>]$" {send "term len 0\r"} timeout {puts "Error reading prompt -> $expect_out(buffer)";exit} } expect { -re "\[#>]$" {send "$command\r"} timeout {puts "Error reading prompt -> $expect_out(buffer)";exit} } expect -re "\[#>]$" set output $expect_out(buffer) send "exit\r" puts "$output\r\n"

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  • after .htaccess url rewrite, cannot perform logoff in some of the url rewrited page

    - by Patrick
    Recently, I was doing .htaccess url rewrite, make all my php url into html, in some page, the logout button wont work properly. for example, in page ‘quotedetails/Q9999.html’ (rewrited from ‘quotedetails.php?quoteID=Q9999'), when I click logout button in this page, it wont do the trick, but when i use the old php url of this page, it works again, other rewrited pages like index.html (index.php), search.html(search.php), all works perfectly. I use firebug to debug, after I click the logout button, it stays in the same page without redirect me to the index.html, but I saw the the ‘logoff’ params has been passed through, but just dont let me logout and redirect to index page. I’ve changed all the relavent file path to absolute path, still no luck…..help please. I’ve also noticed from firebug, that page cannot get the redirect ‘location’ as I tried in other pages, their response headers come with ‘location: index.html’, but in that no-workin-page, there is no such line called ‘location: index.html’ in its response headers. Here is my .htaccess file, no-workin-pages are related to the first four ReweiteRules Options +FollowSymlinks RewriteEngine on RewriteRule ^reps/all,all.html$ rep.php?repID=all&repName=all RewriteRule ^reps/([A-Z]+),([A-Za-z\sA-Za-z]+).html$ rep.php?repID=$1&repName=$2 RewriteRule ^reps/([A-Za-z]+),([A-Za-z\sA-Za-z]+),([0-9]+).html$ rep.php?repID=$1repName=$2&page=$3 RewriteRule ^quotedetails/(Q[0-9]+).html$ quotedetails.php?quoteID=$1 RewriteRule ^index.html$ index.php RewriteRule ^addquote.html$ addquote.php RewriteRule ^search.html$ search.php RewriteRule ^viewall.html$ viewall.php RewriteRule ^howto.html$ howto.php

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  • About redirected stdout in System.Diagnostics.Process

    - by sforester
    I've been recently working on a program that convert flac files to mp3 in C# using flac.exe and lame.exe, here are the code that do the job: ProcessStartInfo piFlac = new ProcessStartInfo( "flac.exe" ); piFlac.CreateNoWindow = true; piFlac.UseShellExecute = false; piFlac.RedirectStandardOutput = true; piFlac.Arguments = string.Format( flacParam, SourceFile ); ProcessStartInfo piLame = new ProcessStartInfo( "lame.exe" ); piLame.CreateNoWindow = true; piLame.UseShellExecute = false; piLame.RedirectStandardInput = true; piLame.RedirectStandardOutput = true; piLame.Arguments = string.Format( lameParam, QualitySetting, ExtractTag( SourceFile ) ); Process flacp = null, lamep = null; byte[] buffer = BufferPool.RequestBuffer(); flacp = Process.Start( piFlac ); lamep = new Process(); lamep.StartInfo = piLame; lamep.OutputDataReceived += new DataReceivedEventHandler( this.ReadStdout ); lamep.Start(); lamep.BeginOutputReadLine(); int count = flacp.StandardOutput.BaseStream.Read( buffer, 0, buffer.Length ); while ( count != 0 ) { lamep.StandardInput.BaseStream.Write( buffer, 0, count ); count = flacp.StandardOutput.BaseStream.Read( buffer, 0, buffer.Length ); } Here I set the command line parameters to tell lame.exe to write its output to stdout, and make use of the Process.OutPutDataRecerved event to gather the output data, which is mostly binary data, but the DataReceivedEventArgs.Data is of type "string" and I have to convert it to byte[] before put it to cache, I think this is ugly and I tried this approach but the result is incorrect. Is there any way that I can read the raw redirected stdout stream, either synchronously or asynchronously, bypassing the OutputDataReceived event? PS: the reason why I don't use lame to write to disk directly is that I'm trying to convert several files in parallel, and direct writing to disk will cause severe fragmentation. Thanks a lot!

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  • Help with GetGlyphOutline function(WinAPI)

    - by user146780
    I want to use this function to get contours and within these contours, I want to get cubic bezier. I think I have to call it with GGO_BEZIER. What puzzles me is how the return buffer works. "A glyph outline is returned as a series of one or more contours defined by a TTPOLYGONHEADER structure followed by one or more curves. Each curve in the contour is defined by a TTPOLYCURVE structure followed by a number of POINTFX data points. POINTFX points are absolute positions, not relative moves. The starting point of a contour is given by the pfxStart member of the TTPOLYGONHEADER structure. The starting point of each curve is the last point of the previous curve or the starting point of the contour. The count of data points in a curve is stored in the cpfx member of TTPOLYCURVE structure. The size of each contour in the buffer, in bytes, is stored in the cb member of TTPOLYGONHEADER structure. Additional curve definitions are packed into the buffer following preceding curves and additional contours are packed into the buffer following preceding contours. The buffer contains as many contours as fit within the buffer returned by GetGlyphOutline." I'm really not sure how to access the contours. I know that I can change a pointer another type of pointer but i'm not sure how I go about getting the contours based on this documentation. Thanks

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  • Need an explanation on this code - c#

    - by ltech
    I am getting familiar with C# day by day and I came across this piece of code public static void CopyStreamToStream( Stream source, Stream destination, Action<Stream,Stream,Exception> completed) { byte[] buffer = new byte[0x1000]; AsyncOperation asyncOp = AsyncOperationManager.CreateOperation(null); Action<Exception> done = e => { if (completed != null) asyncOp.Post(delegate { completed(source, destination, e); }, null); }; AsyncCallback rc = null; rc = readResult => { try { int read = source.EndRead(readResult); if (read > 0) { destination.BeginWrite(buffer, 0, read, writeResult => { try { destination.EndWrite(writeResult); source.BeginRead( buffer, 0, buffer.Length, rc, null); } catch (Exception exc) { done(exc); } }, null); } else done(null); } catch (Exception exc) { done(exc); } }; source.BeginRead(buffer, 0, buffer.Length, rc, null); } From this article Article What I fail to follow is that how does the delegate get notified that the copy is done? Say after the copy is done I want to perform an operation on the copied file.

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  • assembly of pdp-11(simulator)

    - by lego69
    I have this code on pdp-11 tks = 177560 tkb = 177562 tps = 177564 tpb = 177566 lcs = 177546 . = torg + 2000 main: mov #main, sp mov #kb_int, @#60 mov #200, @#62 mov #101, @#tks mov #clock, @#100 mov #300, @#102 mov #100, @#lcs loop: mov @#tks,r2 aslb r2 bmi loop halt clock: tst bufferg beq clk_end mov #msg,-(sp) jsr pc, print_str tst (sp)+ clr bufferg bic #100,@#tks clr @#lcs clk_end:rti kb_int: mov r1,-(sp) jsr pc, read_char movb r1,@buff_ptr inc buff_ptr bis #1,@#tks cmpb r1,#'q bne next_if mov #0, @#tks next_if:cmpb r1,#32. bne end_kb_int clrb @buff_ptr mov #buffer,-(sp) jsr pc, print_str tst (sp)+ mov #buffer,buff_ptr end_kb_int: mov (sp)+,r1 rti ;############################# read_char: tstb @#tks bpl read_char movb @#tkb, r1 rts pc ;############################# print_char: tstb @#tps bpl print_char movb r1, @#tpb rts pc ;############################# print_str: mov r1,-(sp) mov r2,-(sp) mov 6(sp),r2 str_loop: movb (r2)+,r1 beq pr_str_end jsr pc, print_char br str_loop pr_str_end: mov (sp)+,r2 mov (sp)+,r1 rts pc . = torg + 3000 msg:.ascii<Something is wrong!> .byte 0 .even buff_ptr: .word buffer buffer: .blkw 3 bufferg: .word 0 Can somebody please explain how this part is working, thanks in advance movb r1,@buff_ptr inc buff_ptr bis #1,@#tks cmpb r1,#'q bne next_if mov #0, @#tks next_if:cmpb r1,#32. bne end_kb_int clrb @buff_ptr mov #buffer,-(sp) jsr pc, print_str tst (sp)+ mov #buffer,buff_ptr

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  • What is the proper way to code a read-while loop in Scala?

    - by ARKBAN
    What is the "proper" of writing the standard read-while loop in Scala? By proper I mean written in a Scala-like way as opposed to a Java-like way. Here is the code I have in Java: MessageDigest md = MessageDigest.getInstance( "MD5" ); InputStream input = new FileInputStream( "file" ); byte[] buffer = new byte[1024]; int readLen; while( ( readLen = input.read( buffer ) ) != -1 ) md.update( buffer, 0, readLen ); return md.digest(); Here is the code I have in Scala: val md = MessageDigest.getInstance( hashInfo.algorithm ) val input = new FileInputStream( "file" ) val buffer = new Array[ Byte ]( 1024 ) var readLen = 0 while( readLen != -1 ) { readLen = input.read( buffer ) if( readLen != -1 ) md.update( buffer, 0, readLen ) } md.digest The Scala code is correct and works, but feels very un-Scala-ish. For one it is a literal translation of the Java code, taking advantage of none of the advantages of Scala. Further it is actually longer than the Java code! I really feel like I'm missing something, but I can't figure out what. I'm fairly new to Scala, and so I'm asking the question to avoid falling into the pitfall of writing Java-style code in Scala. I'm more interested in the Scala way to solve this kind of problem than in any specific helper method that might be provided by the Scala API to hash a file. (I apologize in advance for my ad hoc Scala adjectives throughout this question.)

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  • Handling user interface in a multi-threaded application (or being forced to have a UI-only main thre

    - by Patrick
    In my application, I have a 'logging' window, which shows all the logging, warnings, errors of the application. Last year my application was still single-threaded so this worked [quite] good. Now I am introducing multithreading. I quickly noticed that it's not a good idea to update the logging window from different threads. Reading some articles on keeping the UI in the main thread, I made a communication buffer, in which the other threads are adding their logging messages, and from which the main thread takes the messages and shows them in the logging window (this is done in the message loop). Now, in a part of my application, the memory usage increases dramatically, because the separate threads are generating lots of logging messages, and the main thread cannot empty the communication buffer quickly enough. After the while the memory decreases again (if the other threads have finished their work and the main thread gradually empties the communication buffer). I solved this problem by having a maximum size on the communication buffer, but then I run into a problem in the following situation: the main thread has to perform a complex action the main thread takes some parts of the action and let's separate threads execute this while the seperate threads are executing their logic, the main thread processes the results from the other threads and continues with its work if the other threads are finished Problem is that in this situation, if the other threads perform logging, there is no UI-message loop, and so the communication buffer is filled, but not emptied. I see two solutions in solving this problem: require the main thread to do regular polling of the communication buffer only performing user interface logic in the main thread (no other logic) I think the second solution seems the best, but this may not that easy to introduce in a big application (in my case it performs mathematical simulations). Are there any other solutions or tips? Or is one of the two proposed the best, easiest, most-pragmatic solution? Thanks, Patrick

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  • How to handle image/gif type response on client side using GWT

    - by user200340
    Hi all, I have a question about how to handle image/gif type response on client side, any suggestion will be great. There is a service which responds for retrieving image (only one each time at the moment) from database. The code is something like, JDBC Connection Construct MYSQL query. Execute query If has ResultSet, retrieve first one { //save image into Blob image, “img” is the only entity in the image table. image = rs.getBlob("img"); } response.setContentType("image/gif"); //set response type InputStream in = image.getBinaryStream(); //output Blob image to InputStream int bufferSize = 1024; //buffer size byte[] buffer = new byte[bufferSize]; //initial buffer int length =0; //read length data from inputstream and store into buffer while ((length = in.read(buffer)) != -1) { out.write(buffer, 0, length); //write into ServletOutputStream } in.close(); out.flush(); //write out The code on client side .... imgform.setAction(GWT.getModuleBaseURL() + "serviceexample/ImgRetrieve"); .... ClickListener { OnClick, then imgform.submit(); } formHandler { onSubmit, form validation onSubmitComplete ??????? //handle response, and display image **Here is my question, i had tried Image img = new Image(GWT.getHostPageBaseURL() +"serviceexample/ImgRetrieve"); mg.setSize("300", "300"); imgpanel.add(img); but i only got a non-displayed image with 300X300 size.** } So, how should i handle the responde in this case? Thanks,

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  • Implementation problem. Htaccess in php

    - by Irwan
    I have a problem to fix the URL on my website at http://www.abelputra.com I need a solution: I want to change www.abelputra.com/software.php into www.abelputra.com/software I have read a tutorial like this: For .htaccess: RewriteEngine On RewriteRule ^ ([a-zA-Z0-9_-] +) $ index.php? Key = $ 1 RewriteRule ^ ([a-zA-Z0-9_-]+)/$ index.php? Key = $ 1 Then in php: index.php --- $Key=$ _GET ['key']; if ($key == 'home') { include ('index.php'); // Home page } else if ($ key == 'software') { include ('software.php'); // } else if ($ key == 'webdesign') { include ('webdesign.php'); // } The problem is: When I implemented the menu software.php index.php to call the page: www.abelputra.com/index.php?key=software what happens is the page that is shown is two pages later software.php index.php page underneath. Is it because calling functions "include ()"? index.php structures: Header Content - contains the opening words Footer software.php structure: Header Content - contains an explanation of my software Footer Sorry my english bad. im from Indonesia. Please solution .. thanks

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  • ReWriteRule is redirecting rather rewriting

    - by James Doc
    At the moment I have two machines that I do web development on; an iMac for work at the office and a MacBook for when I have to work on the move. They both running OS X 10.6 have the same version of PHP, Apache, etc running on them. Both computers have the same files of the website, including the .htaccess file (see below). On the MacBook the URLs are rewritten nicely, masking the URL they are pointing to (eg site/page/page-name), however on the iMac they simply redirect to the page (eg site/index.php?method=page&value=page-name) which is making switching back and forth between machines a bit of a pain! I'm sure it must be a config setting somewhere, but I can't for the life of me find it. Has anyone got a remedy? Many thanks. I'm fairly convinced there is a much nice way of writing this htaccess file without loosing access several key folders as well! Options +FollowSymlinks RewriteEngine on RewriteBase /In%20Progress/Vila%20Maninga/ RewriteRule ^page/([a-z|0-9_&;=-]+) index.php?method=page&value=$1 [NC] RewriteRule ^tag/([a-z|0-9_]+) index.php?method=tag&value=$1 [NC] RewriteRule ^search/([a-z|0-9_"]+) index.php?method=search&value=$1 [NC] RewriteRule ^modpage/([con0-9-]+) index.php?method=modpage&value=$1 [NC] RewriteRule ^login index.php?method=login [NC] RewriteRule ^logout index.php?method=logout [NC] RewriteRule ^useraccounts index.php?method=useraccounts [NC]

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  • how to change type of value in an php array and sorting it..is it possible ?

    - by justjoe
    hi, i got problem with my code and hopefully someone able to figure it out. The main purpose is to sort array based on its value (then reindex its numerical key). i got this sample of filename : $filename = array("index 198.php", "index 192.php", "index 144.php", "index 2.php", "index 1.php", "index 100.php", "index 111.php"); $alloutput = array(); //all of index in array foreach ($filename as $name) { preg_match('#(\d+)#', $name, $output); // take only the numerical from file name array_shift($output); // cleaned. the last code create duplicate numerical in $output, if (is_array($hasilku)) { $alloutput = array_merge($alloutput, $output); } } //try to check the type of every value in array foreach ($alloutput as $output) { if (is_array($hasil)) { echo "array true </br>"; } elseif (is_int($hasil)) { echo "integer true </br>"; } elseif (is_string($hasil)) { //the numerical taken from filename always resuld "string". echo "string true </br>"; } } the output of this code will be : Array ( [0] = 198 [1] = 192 [2] = 144 [3] = 2 [4] = 1 [5] = 100 [6] = 111 ) i have test every output in array. It's all string (and not numerical), So the question is how to change this string to integer, so i can sort it from the lowest into the highest number ? the main purpose of this code is how to output array where it had been sort from lowest to highest ?

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  • When is a try catch not a try catch?

    - by Dearmash
    I have a fun issue where during application shutdown, try / catch blocks are being seemingly ignored in the stack. I don't have a working test project (yet due to deadline, otherwise I'd totally try to repro this), but consider the following code snippet. public static string RunAndPossiblyThrow(int index, bool doThrow) { try { return Run(index); } catch(ApplicationException e) { if(doThrow) throw; } return ""; } public static string Run(int index) { if(_store.Contains(index)) return _store[index]; throw new ApplicationException("index not found"); } public static string RunAndIgnoreThrow(int index) { try { return Run(index); } catch(ApplicationException e) { } return ""; } During runtime this pattern works famously. We get legacy support for code that relies on exceptions for program control (bad) and we get to move forward and slowly remove exceptions used for program control. However, when shutting down our UI, we see an exception thrown from "Run" even though "doThrow" is false for ALL current uses of "RunAndPossiblyThrow". I've even gone so far as to verify this by modifying code to look like "RunAndIgnoreThrow" and I'll still get a crash post UI shutdown. Mr. Eric Lippert, I read your blog daily, I'd sure love to hear it's some known bug and I'm not going crazy. EDIT This is multi-threaded, and I've verified all objects are not modified while being accessed

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  • Have Microsoft changed how ASP.NET MVC deals with duplicate action method names?

    - by Jason Evans
    I might be missing something here, but in ASP.NET MVC 4, I can't get the following to work. Given the following controller: public class HomeController : Controller { public ActionResult Index() { return View(); } [HttpPost] public ActionResult Index(string order1, string order2) { return null; } } and it's view: @{ ViewBag.Title = "Home"; } @using (Html.BeginForm()) { @Html.TextBox("order1")<br /> @Html.TextBox("order2") <input type="submit" value="Save"/> } When start the app, all I get is this: The current request for action 'Index' on controller type 'HomeController' is ambiguous between the following action methods: System.Web.Mvc.ActionResult Index() on type ViewData.Controllers.HomeController System.Web.Mvc.ActionResult Index(System.String, System.String) on type ViewData.Controllers.HomeController Now, in ASP.NET MVC 3 the above works fine, I just tried it, so what's changed in ASP.NET MVC 4 to break this? OK there could be a chance that I'm doing something silly here, and not noticing it. EDIT: I notice that in the MVC 4 app, the Global.asax.cs file did not contain this: public static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = UrlParameter.Optional } // Parameter defaults ); } which the MVC 3 app does, by default. So I added the above to the MVC 4 app but it fails with the same error. Note that the MVC 3 app does work fine with the above route. I'm passing the "order" data via the Request.Form. EDIT: In the file RouteConfig.cs I can see RegisterRoutes is executed, with the following default route: routes.MapRoute( name: "Default", url: "{controller}/{action}/{id}", defaults: new { controller = "Home", action = "Index", id = UrlParameter.Optional }); I still get the original error, regards ambiguity between which Index() method to call.

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  • Grails - ElasticSearch - QueryParsingException[[index] No query registered for [query]]; with elasticSearchHelper; JSON via curl works fine though

    - by v1p
    I have been working on a Grails project, clubbed with ElasticSearch ( v 20.6 ), with a custom build of elasticsearch-grails-plugin(to support geo_point indexing : v.20.6) have been trying to do a filtered Search, while using script_fields (to calculate distance). Following is Closure & the generated JSON from the GXContentBuilder : Closure records = Domain.search(searchType:'dfs_query_and_fetch'){ query { filtered = { query = { if(queryTxt){ query_string(query: queryTxt) }else{ match_all {} } } filter = { geo_distance = { distance = "${userDistance}km" "location"{ lat = latlon[0]?:0.00 lon = latlon[1]?:0.00 } } } } } script_fields = { distance = { script = "doc['location'].arcDistanceInKm($latlon)" } } fields = ["_source"] } GXContentBuilder generated query JSON : { "query": { "filtered": { "query": { "match_all": {} }, "filter": { "geo_distance": { "distance": "5km", "location": { "lat": "37.752258", "lon": "-121.949886" } } } } }, "script_fields": { "distance": { "script": "doc['location'].arcDistanceInKm(37.752258, -121.949886)" } }, "fields": ["_source"] } The JSON query, using curl-way, works perfectly fine. But when I try to execute it from Groovy Code, I mean with this : elasticSearchHelper.withElasticSearch { Client client -> def response = client.search(request).actionGet() } It throws following error : Failed to execute phase [dfs], total failure; shardFailures {[1][index][3]: SearchParseException[[index][3]: from[0],size[60]: Parse Failure [Failed to parse source [{"from":0,"size":60,"query_binary":"eyJxdWVyeSI6eyJmaWx0ZXJlZCI6eyJxdWVyeSI6eyJtYXRjaF9hbGwiOnt9fSwiZmlsdGVyIjp7Imdlb19kaXN0YW5jZSI6eyJkaXN0YW5jZSI6IjVrbSIsImNvbXBhbnkuYWRkcmVzcy5sb2NhdGlvbiI6eyJsYXQiOiIzNy43NTIyNTgiLCJsb24iOiItMTIxLjk0OTg4NiJ9fX19fSwic2NyaXB0X2ZpZWxkcyI6eyJkaXN0YW5jZSI6eyJzY3JpcHQiOiJkb2NbJ2NvbXBhbnkuYWRkcmVzcy5sb2NhdGlvbiddLmFyY0Rpc3RhbmNlSW5LbSgzNy43NTIyNTgsIC0xMjEuOTQ5ODg2KSJ9fSwiZmllbGRzIjpbIl9zb3VyY2UiXX0=","explain":true}]]]; nested: QueryParsingException[[index] No query registered for [query]]; } The above Closure works if I only use filtered = { ... } script_fields = { ... } but it doesn't return the calculated distance. Anyone had any similar problem ? Thanks in advance :) It's possible that I might have been dim to point out the obvious here :P

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  • Why does mmap() fail with ENOMEM on a 1TB sparse file?

    - by metadaddy
    I've been working with large sparse files on openSUSE 11.2 x86_64. When I try to mmap() a 1TB sparse file, it fails with ENOMEM. I would have thought that the 64 bit address space would be adequate to map in a terabyte, but it seems not. Experimenting further, a 1GB file works fine, but a 2GB file (and anything bigger) fails. I'm guessing there might be a setting somewhere to tweak, but an extensive search turns up nothing. Here's some sample code that shows the problem - any clues? #include <errno.h> #include <fcntl.h> #include <stdio.h> #include <stdlib.h> #include <string.h> #include <sys/mman.h> #include <sys/types.h> #include <unistd.h> int main(int argc, char *argv[]) { char * filename = argv[1]; int fd; off_t size = 1UL << 40; // 30 == 1GB, 40 == 1TB fd = open(filename, O_RDWR | O_CREAT | O_TRUNC, 0666); ftruncate(fd, size); printf("Created %ld byte sparse file\n", size); char * buffer = (char *)mmap(NULL, (size_t)size, PROT_READ | PROT_WRITE, MAP_SHARED, fd, 0); if ( buffer == MAP_FAILED ) { perror("mmap"); exit(1); } printf("Done mmap - returned 0x0%lx\n", (unsigned long)buffer); strcpy( buffer, "cafebabe" ); printf("Wrote to start\n"); strcpy( buffer + (size - 9), "deadbeef" ); printf("Wrote to end\n"); if ( munmap(buffer, (size_t)size) < 0 ) { perror("munmap"); exit(1); } close(fd); return 0; }

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  • Gtk: How can I get a part of a file in a textview with scrollbars relating to the full file

    - by badgerman1
    I'm trying to make a very large file editor (where the editor only stores a part of the buffer in memory at a time), but I'm stuck while building my textview object. Basically- I know that I have to be able to update the text view buffer dynamically, and I don't know hot to get the scrollbars to relate to the full file while the textview contains only a small buffer of the file. I've played with Gtk.Adjustment on a Gtk.ScrolledWindow and ScrollBars, but though I can extend the range of the scrollbars, they still apply to the range of the buffer and not the filesize (which I try to set via Gtk.Adjustment parameters) when I load into textview. I need to have a widget that "knows" that it is looking at a part of a file, and can load/unload buffers as necessary to view different parts of the file. So far, I believe I'll respond to the "change_view" to calculate when I'm off, or about to be off the current buffer and need to load the next, but I don't know how to get the scrollbars to have the top relate to the beginning of the file, and the bottom relate to the end of the file, rather than to the loaded buffer in textview. Any help would be greatly appreciated, thanks!

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  • Sha256 is giving junk output

    - by user1746617
    hey can u be more specific on how to convert to bin to hex. bool HashStatus::calculate_digest_value(char * path,unsigned char * output) { FILE* file = fopen(path, "rb"); if(!file) { g_message("SignatureValidator::VerifyReferences,file not opened"); return -1; } unsigned char hash[SHA256_DIGEST_LENGTH]; SHA256_CTX sha256; SHA256_Init(&sha256); const int bufSize = 32768; unsigned char* buffer = malloc(bufSize); int bytesRead = 0; if(!buffer) return NULL; while((bytesRead = fread(buffer, 1, bufSize, file))) { g_message("calculate digest value,verify.cpp::%s",buffer); SHA256_Update(&sha256, buffer, bytesRead); } SHA256_Final(hash, &sha256); g_message("verify.cpp,after final"); sha256_hash_string(hash, output); g_message("verify.cpp,after sha256_hash_string %s",hash); fclose(file); free(buffer); return true; } this is my code to convert file data into hash using sha256 openssl function o/p is :1d54e12333988471354907a760b9cde861423615bb5255ee837e3b27b32366 but actual o/p is:HVThAjM5iEcTVJB6dgC5zehhQjYVu1JV7oN+OyezI2Y= can you guys please help me with whatz wrong with this code,ASAP and i'm new to this please guide me step by step and in detail..

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  • Problem with reading and writing to binary file in C++

    - by Reem
    I need to make a file that contains "name" which is a string -array of char- and "data" which is array of bytes -array of char in C++- but the first problem I faced is how to separate the "name" from the "data"? newline character could work in this case (assuming that I don't have "\n" in the name) but I could have special characters in the "data" part so there's no way to know when it ends so I'm putting an int value in the file before the data which has the size of the "data"! I tried to do this with code as follow: if((fp = fopen("file.bin","wb")) == NULL) { return false; } char buffer[] = "first data\n"; fwrite( buffer ,1,sizeof(buffer),fp ); int number[1]; number[0]=10; fwrite( number ,1,1, fp ); char data[] = "1234567890"; fwrite( data , 1, number[0], fp ); fclose(fp); but I didn't know if the "int" part was right, so I tried many other codes including this one: char buffer[] = "first data\n"; fwrite( buffer ,1,sizeof(buffer),fp ); int size=10; fwrite( &size ,sizeof size,1, fp ); char data[] = "1234567890"; fwrite( data , 1, number[0], fp ); I see 4 "NULL" characters in the file when I open it instead of seeing an integer. Is that normal? The other problem I'm facing is reading that again from the file! The code I tried to read didn't work at all :( I tried it with "fread" but I'm not sure if I should use "fseek" with it or it just read the other character after it. Forgive me but I'm a beginner :(

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