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  • TSQL Shred XML - Is this right or is there a better way (newbie @ shredding XML)

    - by drachenstern
    Ok, I'm a C# ASP.NET dev following orders: The orders are to take a given dataset, shred the XML and return columns. I've argued that it's easier to do the shredding on the ASP.NET side where we already have access to things like deserializers, etc, and the entire complex of known types, but no, the boss says "shred it on the server, return a dataset, bind the dataset to the columns of the gridview" so for now, I'm doing what I was told. This is all to head off the folks who will come along and say "bad requirements". Task at hand: Here's my code that works and does what I want it to: DECLARE @table1 AS TABLE ( ProductID VARCHAR(10) , Name VARCHAR(20) , Color VARCHAR(20) , UserEntered VARCHAR(20) , XmlField XML ) INSERT INTO @table1 SELECT '12345','ball','red','john','<sizes><size name="medium"><price>10</price></size><size name="large"><price>20</price></size></sizes>' INSERT INTO @table1 SELECT '12346','ball','blue','adam','<sizes><size name="medium"><price>12</price></size><size name="large"><price>25</price></size></sizes>' INSERT INTO @table1 SELECT '12347','ring','red','john','<sizes><size name="medium"><price>5</price></size><size name="large"><price>8</price></size></sizes>' INSERT INTO @table1 SELECT '12348','ring','blue','adam','<sizes><size name="medium"><price>8</price></size><size name="large"><price>10</price></size></sizes>' INSERT INTO @table1 SELECT '23456','auto','black','ann','<auto><type>car</type><wheels>4</wheels><doors>4</doors><cylinders>3</cylinders></auto>' INSERT INTO @table1 SELECT '23457','auto','black','ann','<auto><type>truck</type><wheels>4</wheels><doors>2</doors><cylinders>8</cylinders></auto><auto><type>car</type><wheels>4</wheels><doors>4</doors><cylinders>6</cylinders></auto>' DECLARE @x XML SELECT @x = ( SELECT ProductID , Name , Color , UserEntered , XmlField.query(' for $vehicle in //auto return <auto type = "{$vehicle/type}" wheels = "{$vehicle/wheels}" doors = "{$vehicle/doors}" cylinders = "{$vehicle/cylinders}" />') FROM @table1 table1 WHERE Name = 'auto' FOR XML AUTO ) SELECT @x SELECT ProductID = T.Item.value('../@ProductID', 'varchar(10)') , Name = T.Item.value('../@Name', 'varchar(20)') , Color = T.Item.value('../@Color', 'varchar(20)') , UserEntered = T.Item.value('../@UserEntered', 'varchar(20)') , VType = T.Item.value('@type' , 'varchar(10)') , Wheels = T.Item.value('@wheels', 'varchar(2)') , Doors = T.Item.value('@doors', 'varchar(2)') , Cylinders = T.Item.value('@cylinders', 'varchar(2)') FROM @x.nodes('//table1/auto') AS T(Item) SELECT @x = ( SELECT ProductID , Name , Color , UserEntered , XmlField.query(' for $object in //sizes/size return <size name = "{$object/@name}" price = "{$object/price}" />') FROM @table1 table1 WHERE Name IN ('ring', 'ball') FOR XML AUTO ) SELECT @x SELECT ProductID = T.Item.value('../@ProductID', 'varchar(10)') , Name = T.Item.value('../@Name', 'varchar(20)') , Color = T.Item.value('../@Color', 'varchar(20)') , UserEntered = T.Item.value('../@UserEntered', 'varchar(20)') , SubName = T.Item.value('@name' , 'varchar(10)') , Price = T.Item.value('@price', 'varchar(2)') FROM @x.nodes('//table1/size') AS T(Item) So for now, I'm trying to figure out if there's a better way to write the code than what I'm doing now... (I have a part 2 I'm about to go key in)

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  • What is the fastest way to Initialize a multi-dimensional array to non-default values in .NET?

    - by AMissico
    How do I initialize a multi-dimensional array of a primitive type as fast as possible? I am stuck with using multi-dimensional arrays. My problem is performance. The following routine initializes a 100x100 array in approx. 500 ticks. Removing the int.MaxValue initialization results in approx. 180 ticks just for the looping. Approximately 100 ticks to create the array without looping and without initializing to int.MaxValue. Routines similiar to this are called a few hundred-thousand to several million times during a "run". The array size will not change during a run and arrays are created one-at-a-time, used, then discarded, and a new array created. A "run" which may last from one minute (using 10x10 arrays) to forty-five minutes (100x100). The application creates arrays of int, bool, and struct. There can be multiple "runs" executing at same time, but are not because performance degrades terribly. I am using 100x100 as a base-line. I am open to suggestions on how to optimize this non-default initialization of an array. One idea I had is to use a smaller primitive type when available. For instance, using byte instead of int, saves 100 ticks. I would be happy with this, but I am hoping that I don't have to change the primitive data type. public int[,] CreateArray(Size size) { int[,] array = new int[size.Width, size.Height]; for (int x = 0; x < size.Width; x++) { for (int y = 0; y < size.Height; y++) { array[x, y] = int.MaxValue; } } return array; } Down to 450 ticks with the following: public int[,] CreateArray1(Size size) { int iX = size.Width; int iY = size.Height; int[,] array = new int[iX, iY]; for (int x = 0; x < iX; x++) { for (int y = 0; y < iY; y++) { array[x, y] = int.MaxValue; } } return array; } Down to approximately 165 ticks after a one-time initialization of 2800 ticks. (See my answer below.) If I can get stackalloc to work with multi-dimensional arrays, I should be able to get the same performance without having to intialize the private static array. private static bool _arrayInitialized5; private static int[,] _array5; public static int[,] CreateArray5(Size size) { if (!_arrayInitialized5) { int iX = size.Width; int iY = size.Height; _array5 = new int[iX, iY]; for (int x = 0; x < iX; x++) { for (int y = 0; y < iY; y++) { _array5[x, y] = int.MaxValue; } } _arrayInitialized5 = true; } return (int[,])_array5.Clone(); } Down to approximately 165 ticks without using the "clone technique" above. (See my answer below.) I am sure I can get the ticks lower, if I can just figure out the return of CreateArray9. public unsafe static int[,] CreateArray8(Size size) { int iX = size.Width; int iY = size.Height; int[,] array = new int[iX, iY]; fixed (int* pfixed = array) { int count = array.Length; for (int* p = pfixed; count-- > 0; p++) *p = int.MaxValue; } return array; }

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  • How to store generated eigen faces for future face recognition?

    - by user3237134
    My code works in the following manner: 1.First, it obtains several images from the training set 2.After loading these images, we find the normalized faces,mean face and perform several calculation. 3.Next, we ask for the name of an image we want to recognize 4.We then project the input image into the eigenspace, and based on the difference from the eigenfaces we make a decision. 5.Depending on eigen weight vector for each input image we make clusters using kmeans command. Source code i tried: clear all close all clc % number of images on your training set. M=1200; %Chosen std and mean. %It can be any number that it is close to the std and mean of most of the images. um=60; ustd=32; %read and show images(bmp); S=[]; %img matrix for i=1:M str=strcat(int2str(i),'.jpg'); %concatenates two strings that form the name of the image eval('img=imread(str);'); [irow icol d]=size(img); % get the number of rows (N1) and columns (N2) temp=reshape(permute(img,[2,1,3]),[irow*icol,d]); %creates a (N1*N2)x1 matrix S=[S temp]; %X is a N1*N2xM matrix after finishing the sequence %this is our S end %Here we change the mean and std of all images. We normalize all images. %This is done to reduce the error due to lighting conditions. for i=1:size(S,2) temp=double(S(:,i)); m=mean(temp); st=std(temp); S(:,i)=(temp-m)*ustd/st+um; end %show normalized images for i=1:M str=strcat(int2str(i),'.jpg'); img=reshape(S(:,i),icol,irow); img=img'; end %mean image; m=mean(S,2); %obtains the mean of each row instead of each column tmimg=uint8(m); %converts to unsigned 8-bit integer. Values range from 0 to 255 img=reshape(tmimg,icol,irow); %takes the N1*N2x1 vector and creates a N2xN1 matrix img=img'; %creates a N1xN2 matrix by transposing the image. % Change image for manipulation dbx=[]; % A matrix for i=1:M temp=double(S(:,i)); dbx=[dbx temp]; end %Covariance matrix C=A'A, L=AA' A=dbx'; L=A*A'; % vv are the eigenvector for L % dd are the eigenvalue for both L=dbx'*dbx and C=dbx*dbx'; [vv dd]=eig(L); % Sort and eliminate those whose eigenvalue is zero v=[]; d=[]; for i=1:size(vv,2) if(dd(i,i)>1e-4) v=[v vv(:,i)]; d=[d dd(i,i)]; end end %sort, will return an ascending sequence [B index]=sort(d); ind=zeros(size(index)); dtemp=zeros(size(index)); vtemp=zeros(size(v)); len=length(index); for i=1:len dtemp(i)=B(len+1-i); ind(i)=len+1-index(i); vtemp(:,ind(i))=v(:,i); end d=dtemp; v=vtemp; %Normalization of eigenvectors for i=1:size(v,2) %access each column kk=v(:,i); temp=sqrt(sum(kk.^2)); v(:,i)=v(:,i)./temp; end %Eigenvectors of C matrix u=[]; for i=1:size(v,2) temp=sqrt(d(i)); u=[u (dbx*v(:,i))./temp]; end %Normalization of eigenvectors for i=1:size(u,2) kk=u(:,i); temp=sqrt(sum(kk.^2)); u(:,i)=u(:,i)./temp; end % show eigenfaces; for i=1:size(u,2) img=reshape(u(:,i),icol,irow); img=img'; img=histeq(img,255); end % Find the weight of each face in the training set. omega = []; for h=1:size(dbx,2) WW=[]; for i=1:size(u,2) t = u(:,i)'; WeightOfImage = dot(t,dbx(:,h)'); WW = [WW; WeightOfImage]; end omega = [omega WW]; end % Acquire new image % Note: the input image must have a bmp or jpg extension. % It should have the same size as the ones in your training set. % It should be placed on your desktop ed_min=[]; srcFiles = dir('G:\newdatabase\*.jpg'); % the folder in which ur images exists for b = 1 : length(srcFiles) filename = strcat('G:\newdatabase\',srcFiles(b).name); Imgdata = imread(filename); InputImage=Imgdata; InImage=reshape(permute((double(InputImage)),[2,1,3]),[irow*icol,1]); temp=InImage; me=mean(temp); st=std(temp); temp=(temp-me)*ustd/st+um; NormImage = temp; Difference = temp-m; p = []; aa=size(u,2); for i = 1:aa pare = dot(NormImage,u(:,i)); p = [p; pare]; end InImWeight = []; for i=1:size(u,2) t = u(:,i)'; WeightOfInputImage = dot(t,Difference'); InImWeight = [InImWeight; WeightOfInputImage]; end noe=numel(InImWeight); % Find Euclidean distance e=[]; for i=1:size(omega,2) q = omega(:,i); DiffWeight = InImWeight-q; mag = norm(DiffWeight); e = [e mag]; end ed_min=[ed_min MinimumValue]; theta=6.0e+03; %disp(e) z(b,:)=InImWeight; end IDX = kmeans(z,5); clustercount=accumarray(IDX, ones(size(IDX))); disp(clustercount); QUESTIONS: 1.It is working fine for M=50(i.e Training set contains 50 images) but not for M=1200(i.e Training set contains 1200 images).It is not showing any error.There is no output.I waited for 10 min still there is no output. I think it is going infinite loop.What is the problem?Where i was wrong? 2.Instead of running the training set everytime how eigen faces generated are stored so that stored eigen faces are used for future face recoginition for a new input image.So it reduces wastage of time.

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  • Vectorization of matlab code for faster execution

    - by user3237134
    My code works in the following manner: 1.First, it obtains several images from the training set 2.After loading these images, we find the normalized faces,mean face and perform several calculation. 3.Next, we ask for the name of an image we want to recognize 4.We then project the input image into the eigenspace, and based on the difference from the eigenfaces we make a decision. 5.Depending on eigen weight vector for each input image we make clusters using kmeans command. Source code i tried: clear all close all clc % number of images on your training set. M=1200; %Chosen std and mean. %It can be any number that it is close to the std and mean of most of the images. um=60; ustd=32; %read and show images(bmp); S=[]; %img matrix for i=1:M str=strcat(int2str(i),'.jpg'); %concatenates two strings that form the name of the image eval('img=imread(str);'); [irow icol d]=size(img); % get the number of rows (N1) and columns (N2) temp=reshape(permute(img,[2,1,3]),[irow*icol,d]); %creates a (N1*N2)x1 matrix S=[S temp]; %X is a N1*N2xM matrix after finishing the sequence %this is our S end %Here we change the mean and std of all images. We normalize all images. %This is done to reduce the error due to lighting conditions. for i=1:size(S,2) temp=double(S(:,i)); m=mean(temp); st=std(temp); S(:,i)=(temp-m)*ustd/st+um; end %show normalized images for i=1:M str=strcat(int2str(i),'.jpg'); img=reshape(S(:,i),icol,irow); img=img'; end %mean image; m=mean(S,2); %obtains the mean of each row instead of each column tmimg=uint8(m); %converts to unsigned 8-bit integer. Values range from 0 to 255 img=reshape(tmimg,icol,irow); %takes the N1*N2x1 vector and creates a N2xN1 matrix img=img'; %creates a N1xN2 matrix by transposing the image. % Change image for manipulation dbx=[]; % A matrix for i=1:M temp=double(S(:,i)); dbx=[dbx temp]; end %Covariance matrix C=A'A, L=AA' A=dbx'; L=A*A'; % vv are the eigenvector for L % dd are the eigenvalue for both L=dbx'*dbx and C=dbx*dbx'; [vv dd]=eig(L); % Sort and eliminate those whose eigenvalue is zero v=[]; d=[]; for i=1:size(vv,2) if(dd(i,i)>1e-4) v=[v vv(:,i)]; d=[d dd(i,i)]; end end %sort, will return an ascending sequence [B index]=sort(d); ind=zeros(size(index)); dtemp=zeros(size(index)); vtemp=zeros(size(v)); len=length(index); for i=1:len dtemp(i)=B(len+1-i); ind(i)=len+1-index(i); vtemp(:,ind(i))=v(:,i); end d=dtemp; v=vtemp; %Normalization of eigenvectors for i=1:size(v,2) %access each column kk=v(:,i); temp=sqrt(sum(kk.^2)); v(:,i)=v(:,i)./temp; end %Eigenvectors of C matrix u=[]; for i=1:size(v,2) temp=sqrt(d(i)); u=[u (dbx*v(:,i))./temp]; end %Normalization of eigenvectors for i=1:size(u,2) kk=u(:,i); temp=sqrt(sum(kk.^2)); u(:,i)=u(:,i)./temp; end % show eigenfaces; for i=1:size(u,2) img=reshape(u(:,i),icol,irow); img=img'; img=histeq(img,255); end % Find the weight of each face in the training set. omega = []; for h=1:size(dbx,2) WW=[]; for i=1:size(u,2) t = u(:,i)'; WeightOfImage = dot(t,dbx(:,h)'); WW = [WW; WeightOfImage]; end omega = [omega WW]; end % Acquire new image % Note: the input image must have a bmp or jpg extension. % It should have the same size as the ones in your training set. % It should be placed on your desktop ed_min=[]; srcFiles = dir('G:\newdatabase\*.jpg'); % the folder in which ur images exists for b = 1 : length(srcFiles) filename = strcat('G:\newdatabase\',srcFiles(b).name); Imgdata = imread(filename); InputImage=Imgdata; InImage=reshape(permute((double(InputImage)),[2,1,3]),[irow*icol,1]); temp=InImage; me=mean(temp); st=std(temp); temp=(temp-me)*ustd/st+um; NormImage = temp; Difference = temp-m; p = []; aa=size(u,2); for i = 1:aa pare = dot(NormImage,u(:,i)); p = [p; pare]; end InImWeight = []; for i=1:size(u,2) t = u(:,i)'; WeightOfInputImage = dot(t,Difference'); InImWeight = [InImWeight; WeightOfInputImage]; end noe=numel(InImWeight); % Find Euclidean distance e=[]; for i=1:size(omega,2) q = omega(:,i); DiffWeight = InImWeight-q; mag = norm(DiffWeight); e = [e mag]; end ed_min=[ed_min MinimumValue]; theta=6.0e+03; %disp(e) z(b,:)=InImWeight; end IDX = kmeans(z,5); clustercount=accumarray(IDX, ones(size(IDX))); disp(clustercount); Running time for 50 images:Elapsed time is 103.947573 seconds. QUESTIONS: 1.It is working fine for M=50(i.e Training set contains 50 images) but not for M=1200(i.e Training set contains 1200 images).It is not showing any error.There is no output.I waited for 10 min still there is no output. I think it is going infinite loop.What is the problem?Where i was wrong?

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  • MaxClients in apache. How to know the size of my proccess?

    - by Larry
    From http://httpd.apache.org/docs/2.2/misc/perf-tuning.html The single biggest hardware issue affecting webserver performance is RAM. A webserver should never ever have to swap, as swapping increases the latency of each request beyond a point that users consider "fast enough". This causes users to hit stop and reload, further increasing the load. You can, and should, control the MaxClients setting so that your server does not spawn so many children it starts swapping. This procedure for doing this is simple: determine the size of your average Apache process, by looking at your process list via a tool such as top, and divide this into your total available memory, leaving some room for other processes. The main issue is that I can't understand how to know the size, because, well i have the size of httpd on no more of 3888 But, if we need to determine the number for MaxClients, and I have 4GB of RAM, so I get: 972, so I should use like 900 in the MaxClients?

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  • How to know the root device size of some public AMI?

    - by red23jordan
    Since I do not want to pay money for my testing, the free limit size is 10G. I can know the root device root for some default AMI such as Amazon Linux AMI 2012.03 The Amazon Linux AMI 2012.03 is an EBS-backed, PV-GRUB image. It includes Linux 3.2, AWS tools, and repository access to multiple versions of MySQL, PostgreSQL, Python, Ruby, and Tomcat. Root Device Size: 8 GB And the last row displayed 8GB. However, if I find AMI in Community Page, it does not show the root device size. Can anyone know how to use the instance such as centOS that is not provided by default but it is under 10GB so that I can still free use?

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  • Midnight Commander Woes: Output while panels are active, and tab completion.

    - by Eddie Parker
    I'm trying out midnight commander (loved Norton back in the day!) and I'm finding two things hard to work out. I'm curious if there's ways around this or not however. 1) If the panels are active and I issue a command that has a lot of output, it appears to be lost forever. i.e., if the panels are visible and I cat something (i.e., cat /proc/cpuinfo), that info is gone forever once the panels get redrawn. Is there anyway to see the output? I've tried 'ctrl-o', but it appears to just give me a fresh sub-shell and wipes the previous output away. Pausing after every invocation is a bit irritating, so I'd rather not use that option. 2) Tab completion for commands When mc is running, it consumes the tab character for switching panels. Is there any way to get around this so I can still type in paths and what not on the command line? I'm running cygwin if that matters at all.

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  • Maximum disk size for a Debian 6 VMware installation?

    - by Mohamed Abobakr
    I'm planning to install a variety of Linux distributions on VMware Player to get more experience with Linux (I've only used Fedora back in university). I'm starting with Debian 6.0.5 Squeeze, and have already downloaded the small CD i386 netinst image. In the new virtual machine wizard, it's asking me for the maximum disk size of the image. It says that the recommended size for Debian 6 is 8 GB. However, I'm trying to figure out what is the absolute minimal size that I can get away with, since I'm only testing it out with very few software installations (mainly testing web server applications).

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  • May the file size returned by stat be compromised?

    - by codeholic
    I want to make sure that nobody changed a file. In order to accomplish that, I want not only to check MD5 sum of the file, but also check its size, since as far as I understand this additional simple check can sophisticate falsification by several digits. May I trust the size that stat returns? I don't mean if changes were made to stat itself. I don't go that deep. But, for instance, may one compromise the file size that stat returns by hacking the directory file? Or by similar means, that do not require superuser privileges? It's Linux.

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  • File property information (last write time and file size) in explorer out of date by hours over netw

    - by David L Morris
    An application is running on a windows XP prof machine picking up file from a network share from another windows machine. It detects that the file has been updated (by date and time or optionally file size) and reads it for any new data. Most of the time the last write time and file size, seems to be up to date. Occasionally, this information stops being updated, even though the file is growing (intermittently during the day) with appended content, so that the last write time and file size remain fixed at some arbitrary moment. This is visible in explorer, where it shows a fixed last write time on the reading machine. Just opening the file to edit it in notepad, immediately refreshes the file properties, and the other application picks up where it left of. The file location can't be changed, nor the location of the relevant applications. Any solutions to resolve this problem?

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  • How to de-dupe identical photos that have a slightly different file size?

    - by GJ.
    I imported many photos using the new "camera import" feature of Dropbox. Many of those were duplicates of photos previously imported by direct copying from the camera. Strangely, the Dropbox import appears to slightly reduce the file size. E.g. here on the right is the file imported through Dropbox: Comparison of the two files using pdiff returns "Images are binary identical", but tools such as fdupes or even the Picasa "show duplicate files" feature, consider them as unique. What can be the cause of this file size change? Is there any way to undo it? Most importantly: how can I de-dupe efficiently without regard to file size comparison? (running pdiff comparison over all photo pairs in my library is obviously impractical...) A solution for either OS X or Windows would do.

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  • terminal-window viewer for tab-delimited files in *nix?

    - by khedron
    I work with a lot of tab-delimited data files, with varying columns of uncertain length. Typically, the way people view these files is to bring them down from the server to their Windows or Mac machine, and then open them up in Excel. This is certainly fully-featured, allowing filtering and other nice options. But sometimes, you just want to look at something quickly on the command line. I wrote a bare-bones utility to display the first<n>lines of a file like so: --- line 1 --- 1:{header-1} 2:{header-2} 3:... --- line 2 --- 1:{data-1} 2:{data-2} 3:... This is, obviously, very lame, but it's enough to pipe through grep, or figure out which header columns to use "cut -f" on. Is there a *nix-based viewer for a terminal session which will display rows and columns of a tab-delimited file and let you move the viewing window over the file, or otherwise look at data? I don't want to write this myself; instead, I'd just make a reformatter which would replace tabs with spaces for padding so I could open the file up in emacs and see aligned columns. But if there's already a tool out there to do something like this, that'd be great! (Or, I could just live with Excel.)

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  • How can I get the size of an Amazon S3 bucket?

    - by Garret Heaton
    I'd like to graph the size (in bytes, and # of items) of an Amazon S3 bucket and am looking for an efficient way to get the data. The s3cmd tools provide a way to get the total file size using s3cmd du s3://bucket_name, but I'm worried about its ability to scale since it looks like it fetches data about every file and calculates its own sum. Since Amazon charges users in GB-Months it seems odd that they don't expose this value directly. Although Amazon's REST API returns the number of items in a bucket, [s3cmd] doesn't seem to expose it. I could do s3cmd ls -r s3://bucket_name | wc -l but that seems like a hack. The Ruby AWS::S3 library looked promising, but only provides the # of bucket items, not the total bucket size. Is anyone aware of any other command line tools or libraries (prefer Perl, PHP, Python, or Ruby) which provide ways of getting this data?

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  • Can't find partition tab in disk utility osX ver. 10.6.8

    - by John W
    I just got a used Mac Book Pro. I created a new admin account and deleted the old one as well as one other user. This is an older late 2007 MBP... the osX upgrade to 10.6.8 was just performed. My Macintosh HD is showing up as Partition 2. I ran disk utility (not from install disk), but there was no partition tab. I have a 160GB drive with only 53GB of space left on it. Since I am the only user and have no files on the laptop yet, I don't understand why there is so little space left. Surely the OS can't use up over 100GB. I wanted to run disk utility to see if there were any recovery partitions or other partition left over from the previous owner that could be erased to make room for expanding the main partition. Unfortunately, there is no partition tab in disk utility. The documentation I have found on line states that this version of osX includes that utility. The osX disks I have are for an older version so I wasn't sure if they would be of any use in solving this problem. Also, I was afraid if using the disks, would I lose the little bit of data/apps that I have assembled. I would rather not do a fresh install and have to do all the updates again to achieve this. The previous owner had some apps that I don't want to lose as I would have to pay handsomely to get them back. Simply, if all the previous users data is backed up on here after deleting user is still taking up space on a recovery partition (that I can't see)... I need to locate it erase it and expand the primary partition to re-aquire disk space for my files. I am new to Mac, so please be as descriptive as possible. Thanks.

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  • Ubuntu 12.04 3.2 Kernel showing incorrect "cache size" in cpuinfo?

    - by Tom G
    2x Xeon E5620 . 16 Cores altogether. /proc/cpuinfo shows cache is only @ 4096kb According to intel this should have 12MB of "smart cache". Doing searched for E5620 and CPUinfo shows the correct number: cache size : 12288 KB However mine shows this: processor : 15 v endor_id : GenuineIntel cpu family : 6 model : 44 model name : Intel(R) Xeon(R) CPU E5620 @ 2.40GHz stepping : 2 microcode : 0x1 cpu MHz : 2400.104 cache size : 4096 KB fpu : yes fpu_exception : yes cpuid level : 11 wp : yes flags : fpu vme de pse tsc msr pae mce cx8 apic mtrr pge mca cmov pat pse36 clflush mmx bogomips : 4800.20 clflush size : 64 cache_alignment : 64 address sizes : 40 bits physical, 48 bits virtual Any idea on why it shows like it's missing 8MB in CPU cache? .

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  • How can I print legible text in a font size <1.5?

    - by user330372
    For biological research, I need to print characters so tiny that 2 of them fit in less than 0.5 mm, which I will read under a microscope. I am currently printing from Excel at font size of 1.5, using a HP LaserJet 400M. The result is slightly larger than what I need it to be, but printing at size 1 produces unreadable results. How can I print a smaller font size but still get readable results? Are there specialized printers for that? Where could I find one?

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  • Re-encoding a video file and increasing the size -- does this improve the quality?

    - by Josh
    If I have a video file at 320x240 resolution which I want to re-encode (because I don't like the encoding it's in now) and I also want to play it at double size (640x480), will I get higher quality if I scale it up to 640x480 when I convert it to a new format, verses keeping it at 320x240 in the new format and playing it at double size? This probably depends on the program used to convert, and if so, please let me know any program which might increase the quality. Here's my thinking. If I play a 320x240 file at double size, the system has to scale up each frame in real time, whereas if I scale up while recompressing the system may be able to use a more intensive algorythm like Bicubic interpolation . However I am not sure if this is true or not.

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  • How can I increase the size of the hard disk used by my Virtual Machine Manager (VMM) vm?

    - by Scott Langham
    In Virtual Machine Manager admin console, I used the 'New virtual machine' wizard and created a machine from an existing template. When I got to the Configure Hardware step, I selected the primary hard disk (which is a dynamic) disk and tried to increase it's maximum size, but this control is disabled so I can't increase it. It's not big enough for my purposes. how do I increase the maximum size of the hard-disk? Thanks. Edit: I am able to add a second hard disk of a size I specify. That's not useful though as I'm trying to install some software, some of which insists on being on drive C.

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  • Streaming desktop with avconv - severe sound issues

    - by Tommy Brunn
    I'm trying to do some live streaming in Ubuntu 12.10, but I'm having some problems with audio. More specifically, the quality is complete garbage and it's at least 10 seconds out of sync with the video. I'm using an excellent guide found here to set up my loopback devices so that I can combine the desktop audio with the microphone input. It seems to work, as I'm able to stream both audio and video to Twitch.tv. But, as I said, the audio quality is terrible. The microphone audio is very, very low, but if I increase it, I get a horrible garbled sound that is absolutely unbearable. Nothing like that is present during VoIP calls or when recording sound alone with the sound recorder, so it's not an issue with the microphone itself. The entire audio stream is also delayed about 10-15 seconds compared to the video stream. I put together an imgur album of my settings. Here is some example output from when I'm streaming: avconv version 0.8.4-6:0.8.4-0ubuntu0.12.10.1, Copyright (c) 2000-2012 the Libav developers built on Nov 6 2012 16:51:11 with gcc 4.7.2 [x11grab @ 0x162fd80] device: :0.0+570,262 -> display: :0.0 x: 570 y: 262 width: 1280 height: 720 [x11grab @ 0x162fd80] shared memory extension found [x11grab @ 0x162fd80] Estimating duration from bitrate, this may be inaccurate Input #0, x11grab, from ':0.0+570,262': Duration: N/A, start: 1353181686.735113, bitrate: 884736 kb/s Stream #0.0: Video: rawvideo, bgra, 1280x720, 884736 kb/s, 30 tbr, 1000k tbn, 30 tbc [alsa @ 0x163fce0] capture with some ALSA plugins, especially dsnoop, may hang. [alsa @ 0x163fce0] Estimating duration from bitrate, this may be inaccurate Input #1, alsa, from 'pulse': Duration: N/A, start: 1353181686.773841, bitrate: N/A Stream #1.0: Audio: pcm_s16le, 48000 Hz, 2 channels, s16, 1536 kb/s Incompatible pixel format 'bgra' for codec 'libx264', auto-selecting format 'yuv420p' [buffer @ 0x1641ec0] w:1280 h:720 pixfmt:bgra [scale @ 0x1642480] w:1280 h:720 fmt:bgra -> w:852 h:480 fmt:yuv420p flags:0x4 [libx264 @ 0x165ae80] VBV maxrate unspecified, assuming CBR [libx264 @ 0x165ae80] using cpu capabilities: MMX2 SSE2Fast SSSE3 FastShuffle SSE4.2 [libx264 @ 0x165ae80] profile Main, level 3.1 [libx264 @ 0x165ae80] 264 - core 123 r2189 35cf912 - H.264/MPEG-4 AVC codec - Copyleft 2003-2012 - http://www.videolan.org/x264.html - options: cabac=1 ref=2 deblock=1:0:0 analyse=0x1:0x111 me=hex subme=6 psy=1 psy_rd=1.00:0.00 mixed_ref=0 me_range=16 chroma_me=1 trellis=1 8x8dct=0 cqm=0 deadzone=21,11 fast_pskip=1 chroma_qp_offset=-2 threads=4 sliced_threads=0 nr=0 decimate=1 interlaced=0 bluray_compat=0 constrained_intra=0 bframes=3 b_pyramid=0 b_adapt=1 b_bias=0 direct=1 weightb=0 open_gop=1 weightp=1 keyint=250 keyint_min=25 scenecut=40 intra_refresh=0 rc_lookahead=30 rc=cbr mbtree=1 bitrate=712 ratetol=1.0 qcomp=0.60 qpmin=0 qpmax=69 qpstep=4 vbv_maxrate=712 vbv_bufsize=512 nal_hrd=none ip_ratio=1.25 aq=1:1.00 Output #0, flv, to 'rtmp://live.justin.tv/app/live_23011330_Pt1plSRM0z5WVNJ0QmCHvTPmpUnfC4': Metadata: encoder : Lavf53.21.0 Stream #0.0: Video: libx264, yuv420p, 852x480, q=-1--1, 712 kb/s, 1k tbn, 30 tbc Stream #0.1: Audio: libmp3lame, 44100 Hz, 2 channels, s16, 712 kb/s Stream mapping: Stream #0:0 -> #0:0 (rawvideo -> libx264) Stream #1:0 -> #0:1 (pcm_s16le -> libmp3lame) Press ctrl-c to stop encoding frame= 17 fps= 0 q=0.0 size= 0kB time=10000000000.00 bitrate= 0.0kbitframe= 32 fps= 31 q=0.0 size= 0kB time=10000000000.00 bitrate= 0.0kbitframe= 40 fps= 23 q=29.0 size= 44kB time=0.03 bitrate=13786.2kbits/s dup=frame= 47 fps= 21 q=31.0 size= 93kB time=2.73 bitrate= 277.7kbits/s dup=0frame= 62 fps= 23 q=29.0 size= 160kB time=3.23 bitrate= 406.2kbits/s dup=0frame= 77 fps= 24 q=23.0 size= 209kB time=3.71 bitrate= 462.5kbits/s dup=0frame= 92 fps= 25 q=20.0 size= 267kB time=4.91 bitrate= 445.2kbits/s dup=0frame= 107 fps= 25 q=20.0 size= 318kB time=5.41 bitrate= 482.1kbits/s dup=0frame= 123 fps= 26 q=18.0 size= 368kB time=5.96 bitrate= 505.7kbits/s dup=0frame= 139 fps= 26 q=16.0 size= 419kB time=6.48 bitrate= 529.7kbits/s dup=0frame= 155 fps= 27 q=15.0 size= 473kB time=7.00 bitrate= 553.6kbits/s dup=0frame= 170 fps= 27 q=14.0 size= 525kB time=7.52 bitrate= 571.7kbits/s dup=0 frame= 180 fps= 25 q=-1.0 Lsize= 652kB time=7.97 bitrate= 670.0kbits/s dup=0 drop=32 //Here I stop the streaming video:531kB audio:112kB global headers:0kB muxing overhead 1.345945% [libx264 @ 0x165ae80] frame I:1 Avg QP:30.43 size: 39748 [libx264 @ 0x165ae80] frame P:45 Avg QP:11.37 size: 11110 [libx264 @ 0x165ae80] frame B:134 Avg QP:15.93 size: 27 [libx264 @ 0x165ae80] consecutive B-frames: 0.6% 0.0% 1.7% 97.8% [libx264 @ 0x165ae80] mb I I16..4: 7.3% 0.0% 92.7% [libx264 @ 0x165ae80] mb P I16..4: 0.1% 0.0% 0.1% P16..4: 49.1% 1.2% 2.1% 0.0% 0.0% skip:47.4% [libx264 @ 0x165ae80] mb B I16..4: 0.0% 0.0% 0.0% B16..8: 0.1% 0.0% 0.0% direct: 0.0% skip:99.9% L0:42.5% L1:56.9% BI: 0.6% [libx264 @ 0x165ae80] coded y,uvDC,uvAC intra: 82.3% 87.4% 71.9% inter: 7.1% 8.4% 7.0% [libx264 @ 0x165ae80] i16 v,h,dc,p: 27% 29% 16% 28% [libx264 @ 0x165ae80] i4 v,h,dc,ddl,ddr,vr,hd,vl,hu: 22% 21% 14% 8% 8% 8% 7% 5% 7% [libx264 @ 0x165ae80] i8c dc,h,v,p: 47% 22% 20% 11% [libx264 @ 0x165ae80] Weighted P-Frames: Y:0.0% UV:0.0% [libx264 @ 0x165ae80] ref P L0: 96.4% 3.6% [libx264 @ 0x165ae80] kb/s:474.19 Received signal 2: terminating. Any ideas on how I can resolve this? The video delay is perfectly acceptable, so I wouldn't think that it's a network issue that's causing the delay in the audio. Any help would be appreciated.

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  • Coherence Warnings in WLS

    - by john.graves(at)oracle.com
    With 11g (10.3.4 WLS), coherence is now built into many applications.  I’ve been noticing errors in my OSB logs like these:####<10/03/2011 10:45:40 AM EST> <Warning> <Coherence> <osb-jeos> <osb_server1> <Logger@324239121 3.6.0.4> <<anonymous>> <> <583c1 0bfdbd326ba:-8c38159:12e9d02c829:-8000-0000000000000003> <1299714340643> <BEA-000000> <Oracle Coherence 3.6.0.4 (member=n/a): Unic astUdpSocket failed to set receive buffer size to 714 packets (1023KB); actual size is 12%, 89 packets (127KB). Consult your OS do cumentation regarding increasing the maximum socket buffer size. Proceeding with the actual value may cause sub-optimal performanc e.> ####<10/03/2011 10:45:40 AM EST> <Warning> <Coherence> <osb-jeos> <osb_server1> <Logger@324239121 3.6.0.4> <<anonymous>> <> <583c1 0bfdbd326ba:-8c38159:12e9d02c829:-8000-0000000000000003> <1299714340650> <BEA-000000> <Oracle Coherence 3.6.0.4 (member=n/a): Pref erredUnicastUdpSocket failed to set receive buffer size to 1428 packets (1.99MB); actual size is 6%, 89 packets (127KB). Consult y our OS documentation regarding increasing the maximum socket buffer size. Proceeding with the actual value may cause sub-optimal p erformance.> ####<10/03/2011 10:45:40 AM EST> <Warning> <Coherence> <osb-jeos> <osb_server1> <Logger@324239121 3.6.0.4> <<anonymous>> <> <583c1 0bfdbd326ba:-8c38159:12e9d02c829:-8000-0000000000000003> <1299714340659> <BEA-000000> <Oracle Coherence 3.6.0.4 (member=n/a): Mult icastUdpSocket failed to set receive buffer size to 714 packets (1023KB); actual size is 12%, 89 packets (127KB). Consult your OS documentation regarding increasing the maximum socket buffer size. Proceeding with the actual value may cause sub-optimal performa nce.> I was able to “fix” this on my ubuntu system by adding the following lines to the /etc/sysctl.conf file:# Setup networking for coherence # maximum receive socket buffer size, default 131071 net.core.rmem_max = 2000000 # maximum send socket buffer size, default 131071 net.core.wmem_max = 1000000 # default receive socket buffer size, default 65535 net.core.rmem_default = 2524287 # default send socket buffer size, default 65535 net.core.wmem_default = 2524287 .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }   .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; }

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  • Ruby: Passing optional objects to method

    - by Sam
    Class TShirt def size(suggested_size) if suggested_size == nil size = "please choose a size" else size = suggested end end end tshirt = TShirt.new tshirt.size("M") == "M" tshirt = TShirt.new size = tshirt.size(nil) == "please choose a size" What is a better way to have optional objects in a method? Procs?

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  • [iPhone Obj-C] How to move a label with the wave of the iPhone?

    - by Didi
    The code below is from the book Beginning iPhone 3 Development, chapter 15, using the accelerometer to control a ball. I want to use a label instead of the ball, and only move in the x direction. However, I donno how to revise the code to achieve this goal. Can anyone please help me? THX so much!!!! (id)initWithCoder:(NSCoder *)coder { if (self = [super initWithCoder:coder]) { self.image = [UIImage imageNamed:@"ball.png"]; self.currentPoint = CGPointMake((self.bounds.size.width / 2.0f) + (image.size.width / 2.0f), (self.bounds.size.height / 2.0f) + (image.size.height / 2.0f)); ballXVelocity = 0.0f; ballYVelocity = 0.0f; } return self; } (id)initWithFrame:(CGRect)frame { if (self = [super initWithFrame:frame]) { // Initialization code } return self; } (void)drawRect:(CGRect)rect { // Drawing code [image drawAtPoint:currentPoint]; } (void)dealloc { [image release]; [acceleration release]; [super dealloc]; } //#pragma mark - - (CGPoint)currentPoint { return currentPoint; } - (void)setCurrentPoint:(CGPoint)newPoint { previousPoint = currentPoint; currentPoint = newPoint; if (currentPoint.x < 0) { currentPoint.x = 0; //ballXVelocity = 0; ballXVelocity = - (ballXVelocity / 2.0); } if (currentPoint.y < 0){ currentPoint.y = 0; //ballYVelocity = 0; ballYVelocity = - (ballYVelocity / 2.0); } if (currentPoint.x > self.bounds.size.width - image.size.width) { currentPoint.x = self.bounds.size.width - image.size.width; //ballXVelocity = 0; ballXVelocity = - (ballXVelocity / 2.0); } if (currentPoint.y > self.bounds.size.height - image.size.height) { currentPoint.y = self.bounds.size.height - image.size.height; //ballYVelocity = 0; ballYVelocity = - (ballYVelocity / 2.0); } CGRect currentImageRect = CGRectMake(currentPoint.x, currentPoint.y, currentPoint.x + image.size.width, currentPoint.y + image.size.height); CGRect previousImageRect = CGRectMake(previousPoint.x, previousPoint.y, previousPoint.x + image.size.width, currentPoint.y + image.size.width); [self setNeedsDisplayInRect:CGRectUnion(currentImageRect, previousImageRect)]; } (void)draw { static NSDate *lastDrawTime; if (lastDrawTime != nil) { NSTimeInterval secondsSinceLastDraw = -([lastDrawTime timeIntervalSinceNow]); ballYVelocity = ballYVelocity + -(acceleration.y * secondsSinceLastDraw); ballXVelocity = ballXVelocity + acceleration.x * secondsSinceLastDraw; CGFloat xAcceleration = secondsSinceLastDraw * ballXVelocity * 500; CGFloat yAcceleration = secondsSinceLastDraw * ballYVelocity * 500; self.currentPoint = CGPointMake(self.currentPoint.x + xAcceleration, self.currentPoint.y +yAcceleration); } // Update last time with current time [lastDrawTime release]; lastDrawTime = [[NSDate alloc] init]; }

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  • How to configure VPN in Windows XP

    - by SAMIR BHOGAYTA
    VPN Overview A VPN is a private network created over a public one. It’s done with encryption, this way, your data is encapsulated and secure in transit – this creates the ‘virtual’ tunnel. A VPN is a method of connecting to a private network by a public network like the Internet. An internet connection in a company is common. An Internet connection in a Home is common too. With both of these, you could create an encrypted tunnel between them and pass traffic, safely - securely. If you want to create a VPN connection you will have to use encryption to make sure that others cannot intercept the data in transit while traversing the Internet. Windows XP provides a certain level of security by using Point-to-Point Tunneling Protocol (PPTP) or Layer Two Tunneling Protocol (L2TP). They are both considered tunneling protocols – simply because they create that virtual tunnel just discussed, by applying encryption. Configure a VPN with XP If you want to configure a VPN connection from a Windows XP client computer you only need what comes with the Operating System itself, it's all built right in. To set up a connection to a VPN, do the following: 1. On the computer that is running Windows XP, confirm that the connection to the Internet is correctly configured. • You can try to browse the internet • Ping a known host on the Internet, like yahoo.com, something that isn’t blocking ICMP 2. Click Start, and then click Control Panel. 3. In Control Panel, double click Network Connections 4. Click Create a new connection in the Network Tasks task pad 5. In the Network Connection Wizard, click Next. 6. Click Connect to the network at my workplace, and then click Next. 7. Click Virtual Private Network connection, and then click Next. 8. If you are prompted, you need to select whether you will use a dialup connection or if you have a dedicated connection to the Internet either via Cable, DSL, T1, Satellite, etc. Click Next. 9. Type a host name, IP or any other description you would like to appear in the Network Connections area. You can change this later if you want. Click Next. 10. Type the host name or the Internet Protocol (IP) address of the computer that you want to connect to, and then click Next. 11. You may be asked if you want to use a Smart Card or not. 12. You are just about done, the rest of the screens just verify your connection, click Next. 13. Click to select the Add a shortcut to this connection to my desktop check box if you want one, if not, then leave it unchecked and click finish. 14. You are now done making your connection, but by default, it may try to connect. You can either try the connection now if you know its valid, if not, then just close it down for now. 15. In the Network Connections window, right-click the new connection and select properties. Let’s take a look at how you can customize this connection before it’s used. 16. The first tab you will see if the General Tab. This only covers the name of the connection, which you can also rename from the Network Connection dialog box by right clicking the connection and selecting to rename it. You can also configure a First connect, which means that Windows can connect the public network (like the Internet) before starting to attempt the ‘VPN’ connection. This is a perfect example as to when you would have configured the dialup connection; this would have been the first thing that you would have to do. It's simple, you have to be connected to the Internet first before you can encrypt and send data over it. This setting makes sure that this is a reality for you. 17. The next tab is the Options Tab. It is The Options tab has a lot you can configure in it. For one, you have the option to connect to a Windows Domain, if you select this check box (unchecked by default), then your VPN client will request Windows logon domain information while starting to work up the VPN connection. Also, you have options here for redialing. Redial attempts are configured here if you are using a dial up connection to get to the Internet. It is very handy to redial if the line is dropped as dropped lines are very common. 18. The next tab is the Security Tab. This is where you would configure basic security for the VPN client. This is where you would set any advanced IPSec configurations other security protocols as well as requiring encryption and credentials. 19. The next tab is the Networking Tab. This is where you can select what networking items are used by this VPN connection. 20. The Last tab is the Advanced Tab. This is where you can configure options for configuring a firewall, and/or sharing. Connecting to Corporate Now that you have your XP VPN client all set up and ready, the next step is to attempt a connection to the Remote Access or VPN server set up at the corporate office. To use the connection follow these simple steps. To open the client again, go back to the Network Connections dialog box. 1. One you are in the Network Connection dialog box, double-click, or right click and select ‘Connect’ from the menu – this will initiate the connection to the corporate office. 2. Type your user name and password, and then click Connect. Properties bring you back to what we just discussed in this article, all the global settings for the VPN client you are using. 3. To disconnect from a VPN connection, right-click the icon for the connection, and then click “Disconnect” Summary In this article we covered the basics of building a VPN connection using Windows XP. This is very handy when you have a VPN device but don’t have the ‘client’ that may come with it. If the VPN Server doesn’t use highly proprietary protocols, then you can use the XP client to connect with. In a future article I will get into the nuts and bolts of both IPSec and more detail on how to configure the advanced options in the Security tab of this client. 678: The remote computer did not respond. 930: The authentication server did not respond to authentication requests in a timely fashion. 800: Unable to establish the VPN connection. 623: The system could not find the phone book entry for this connection. 720: A connection to the remote computer could not be established. More on : http://www.windowsecurity.com/articles/Configure-VPN-Connection-Windows-XP.html

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  • Put Unused Tabs on Hold in Firefox

    - by Asian Angel
    If you have a lot of content heavy webpages open in Firefox, it soon adds up on memory usage. The BarTab extension puts unused tabs on hold and keeps them unloaded until you are ready to access them. Before When you have a few tabs open things are not so bad. But if you have something like 30+ tabs open then Firefox is definitely going to have a much larger memory footprint. For the moment all six tabs are active in our example… After Once the extension is installed you can see quite a difference in the tab bar. Five of the six websites are literally on hold and display as about:blank. In the screenshot above all six tabs were restored from a previous session, but to put new tabs on hold the preferences will have to be modified. Notice that you can have active tabs placed on hold if you do not access them within a set time (“x” seconds, minutes, hours, or days). You may also add your favorite websites as exclusions. Newly opened tabs can now be placed on hold until you are ready for them. Need to place a currently accessed tab on hold? Use the tab context menu to unload the page. Once you use the tab context menu to place a tab on hold your browser will shift over to the closest active tab. You will notice the difference in memory usage when you put a lot of intensive pages on hold. Conclusion If you keep a high number of content heavy webpages open in Firefox then the BarTab extension will help reduce memory usage while browsing. Links Download the BarTab extension (Mozilla Add-ons) Similar Articles Productive Geek Tips Quick Tip: Use Tab Characters in Textarea Boxes in FirefoxYou Really Want to Completely Disable Tabs in Firefox?Quick Hits: 11 Firefox Tab How-TosQuick Tip: Save Windows and Tabs When Restarting FirefoxMake Firefox Use Multiple Rows of Tabs TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips CloudBerry Online Backup 1.5 for Windows Home Server Snagit 10 VMware Workstation 7 Acronis Online Backup Gmail Button Addon (Firefox) Hyperwords addon (Firefox) Backup Outlook 2010 Daily Motivator (Firefox) FetchMp3 Can Download Videos & Convert Them to Mp3 Use Flixtime To Create Video Slideshows

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  • LVM mirror attempt results in "Insufficient free space"

    - by MattK
    Attempting to add a disk to mirror an LVM volume on CentOS 7 always fails with "Insufficient free space: 1 extents needed, but only 0 available". Having searched for a solution, I have tried specifying disks, multiple logging options, adding 3rd log partition, but have not found a solution Not sure if I am making a rookie mistake, or there is something more subtle wrong (I am more familiar with ZFS, new to using LVM): # lvconvert -m1 centos_bi/home Insufficient free space: 1 extents needed, but only 0 available # lvconvert -m1 --corelog centos_bi/home Insufficient free space: 1 extents needed, but only 0 available # lvconvert -m1 --corelog --alloc anywhere centos_bi/home Insufficient free space: 1 extents needed, but only 0 available # lvconvert -m1 --mirrorlog mirrored --alloc anywhere centos_bi/home /dev/sda2 Insufficient free space: 1 extents needed, but only 0 available # lvconvert -m1 --corelog --alloc anywhere centos_bi/home /dev/sdi2 /dev/sda2 Insufficient free space: 1 extents needed, but only 0 available The two disks are of the same size, and have identical partition layouts via "sfdisk -d /dev/sdi part_table; sfdisk /dev/sda < part_table". The current configuration is detailed below. # pvs PV VG Fmt Attr PSize PFree /dev/sda1 centos_bi lvm2 a-- 496.00m 496.00m /dev/sda2 centos_bi lvm2 a-- 465.27g 465.27g /dev/sdi2 centos_bi lvm2 a-- 465.27g 0 # vgs VG #PV #LV #SN Attr VSize VFree centos_bi 3 3 0 wz--n- 931.02g 465.75g # lvs -a -o +devices LV VG Attr LSize Pool Origin Data% Move Log Cpy%Sync Convert Devices home centos_bi -wi-ao---- 391.64g /dev/sdi2(6050) root centos_bi -wi-ao---- 50.00g /dev/sdi2(106309) swap centos_bi -wi-ao---- 23.63g /dev/sdi2(0) # pvdisplay --- Physical volume --- PV Name /dev/sdi2 VG Name centos_bi PV Size 465.27 GiB / not usable 3.00 MiB Allocatable yes (but full) PE Size 4.00 MiB Total PE 119109 Free PE 0 Allocated PE 119109 --- Physical volume --- PV Name /dev/sda2 VG Name centos_bi PV Size 465.27 GiB / not usable 3.00 MiB Allocatable yes PE Size 4.00 MiB Total PE 119109 Free PE 119109 Allocated PE 0 --- Physical volume --- PV Name /dev/sda1 VG Name centos_bi PV Size 500.00 MiB / not usable 4.00 MiB Allocatable yes PE Size 4.00 MiB Total PE 124 Free PE 124 Allocated PE 0 # vgdisplay --- Volume group --- VG Name centos_bi System ID Format lvm2 Metadata Areas 3 Metadata Sequence No 10 VG Access read/write VG Status resizable MAX LV 0 Cur LV 3 Open LV 3 Max PV 0 Cur PV 3 Act PV 3 VG Size 931.02 GiB PE Size 4.00 MiB Total PE 238342 Alloc PE / Size 119109 / 465.27 GiB Free PE / Size 119233 / 465.75 GiB # lvdisplay --- Logical volume --- LV Path /dev/centos_bi/swap LV Name swap VG Name centos_bi LV Write Access read/write LV Creation host, time localhost, 2014-08-07 16:34:34 -0400 LV Status available # open 2 LV Size 23.63 GiB Current LE 6050 Segments 1 Allocation inherit Read ahead sectors auto - currently set to 256 Block device 253:1 --- Logical volume --- LV Path /dev/centos_bi/home LV Name home VG Name centos_bi LV Write Access read/write LV Creation host, time localhost, 2014-08-07 16:34:35 -0400 LV Status available # open 1 LV Size 391.64 GiB Current LE 100259 Segments 1 Allocation inherit Read ahead sectors auto - currently set to 256 Block device 253:2 --- Logical volume --- LV Path /dev/centos_bi/root LV Name root VG Name centos_bi LV Write Access read/write LV Creation host, time localhost, 2014-08-07 16:34:37 -0400 LV Status available # open 1 LV Size 50.00 GiB Current LE 12800 Segments 1 Allocation inherit Read ahead sectors auto - currently set to 256 Block device 253:0

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