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  • How to check for a dynamically created file in Java?

    - by Moev4
    I have an application where I need to check for a file which may be created dynamically during my execution, I will give up after some MAX time where the file has yet to show up. I wanted to know if there was a more efficient method in Java of checking for the file other than polling for it and then sleeping every X seconds? If not what would be the most efficient manner of doing this?

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  • invalid file name in matlab when using file split

    - by klijo
    here jj will be the value of FN, but the trouble is iam getting a error message ??? Error using == fopen Invalid filename. DirName = 'Samples\mattest\jj'; FileName = split('\\',DirName); [a,b] = size(FileName); FN = FileName(b); file_1 = fopen(FN,'w'); split method was found at http://www.mathworks.com/matlabcentral/fileexchange/4873 Doesnt the code seem correct ? Could someone please help me ?

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  • Automark model names/attributes for translation

    - by Saosin
    Is there any way one could automatically mark all model names and attributes for translation, without specifying verbose_name/_plural on each one of them? Doesn't feel very DRY to do this every time: class Profile(models.Model): length = models.IntegerField(_('length')) weight = models.IntegerField(_('weight')) favorite_movies = models.CharField(_('favorite movies'), max_length=100) favorite_quote = models.CharField(_('favorite quote'), max_length=30) religious_views = models.CharField(_('religious views'), max_length=30) political_views = models.CharField(_('political views'), max_length=30) class Meta: verbose_name = _('profile') verbose_name_plural = _('profiles')

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  • Apache and linux file permissions can't browse file or directories

    - by dardub
    I just copied my magento site over to a local server running CentOS 5.4. The browser said it can't locate the location of the stylesheets. The stylesheets are within /skin/frontend/my_new_interface/design2/css. I tried to view in the browser and I can't view any of the files within the css directory. I verified a million times that I'm typing in the correct location. I can view files within /skin/frontend/my_new_interface/design2. Can't browse directories within browser however. I typed in ls -l css and get: -rwxr-xr-x 1 apache apache listed for all the files I tried chmod -R 755 and the directories I changed the apache conf Options Indexes But still when I browse the directories I get Forbidden. However, in another fresh installation of magento in the same www dir, I am able to browse directories. As far as I can tell both installations have same ownership and permissions. I also tried find . -type f -exec chmod 644 {} \; find . -type d -exec chmod 755 {} \; which was recommended in the magento wiki I've just run out of ideas.

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  • PHP - Open or copy a file when knowing only part of its name?

    - by Gary Willoughby
    I have a huge repository of files that are ordered by numbered folders. In each folder is a file which starts with a unique number then an unknown string of characters. Given the unique number how can i open or copy this file? for example: I have been given the number '7656875' and nothing more. I need to interact with a file called '\server\7656800\7656875 foobar 2x4'. how can i achieve this using PHP?

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  • How to read a file line using php in a javascript variable without the breakline character ?

    - by coolboycsaba
    I have a txt file on the server which contains 10 lines of text. The text file is rewritten sometimes, and I get new lines using "\r\n". My problem shows when I want to load the lines in javascript variables. I do it like this, but this work only for numbers or for the last line of the file, because its not using the breakline tag: var x = '<?php echo $file[0]; ?>'; Ive tried to alert(x) but it`s not working.... (working only if I read the last line) Any idead ?

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  • In java can i have more than one class/object in a file?

    - by David
    So the way i've been told to do things is you have your file and the file name is Classname.java and then the code is something like this: class ClassName { SOME METHODS main {} } and then thats all. I'd like to have two objects defined and used within the same .java file. (i don't want to have to put the other class in a difernt file just because i'd like to send this to someone and i want to avoid hasstle of atatching multiple files to an email [the lazy do make good programers though if you think about it]) is it possible to do this? do i have to do anything special and if so what? what are some mistakes i'm likely to make or that you have made in the past when doing this?

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  • How to add authentication property for login to directory path when running batch file in WCF?

    - by blankon91
    I have class in my WCF service to execute batch file. when I test to run the batch file in shared directory, everything is fine, the batch was executed, but when I try to run the batch file from secure diretory, I get error "ACCESS DENIED". How to add login property so I can access my secured directory to execute my batch file? here is my code: public string ExecuteBat() { string hasil = ""; ProcessStartInfo processInfo = new ProcessStartInfo(@"D:\Rpts\SSIS_WeeklyFlash_AAF_1.bat"); processInfo.CreateNoWindow = true; processInfo.UseShellExecute = false; Process process = Process.Start(processInfo); process.WaitForExit(); if (process.ExitCode == 0) { hasil = "BAT EXECUTED!"; } else { hasil = "EXECUTE BAT FAILED"; } return hasil; }

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  • Linux file names & file globbing

    - by John Lelos
    I have a list of files named: file000 file001 file002 file003 ... file1100 How can I match all files that have a number greater than 800 but less than 1000 ? I am using linux bash Thank you Edit Actually, my files are named like: ab869.enc cp936.enc g122345.enc x2022.enc abc8859-14.enc aax5601.enc cp936-1.enc so the first solution dont match the correct files :( How can I match files that have number between 800-999 ?

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  • Using Variables for Class Names in Python?

    - by Sam McAfee
    I want to know how to use variables for objects and function names in Python. In PHP, you can do this: $className = "MyClass"; $newObject = new $className(); How do you do this sort of thing in Python? Or, am I totally not appreciating some fundamental difference with Python, and if so, what is it?

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  • CopyFileEx and 8.3 file names

    - by Lobuno
    Suppose you have 2 files in the same directory: New File Name.txt and NewFil~1.txt If you use CopyFileEx to copy both files to the same destination, maintaining the same names, you will end up having only ONE file (the second one replaces the first one) which can be sometimes not a good thing. Any workaround for this behavior?

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  • Is O_LARGEFILE needed just to write a large file?

    - by Daniel Trebbien
    Is the O_LARGEFILE flag needed if all that I want to do is write a large file (O_WRONLY) or append to a large file (O_APPEND | O_WRONLY)? From a thread that I read titled "Cannot write 2gb index file" on the CLucene-dev mailing list, it appears that O_LARGEFILE might be needed to write large files, but participants in that discussion are using O_RDWR, not O_WRONLY, so I am not sure.

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  • Could I return a FileStream as a generic interface to a file?

    - by Eric
    I'm writing a class interface that needs to return references to binary files. Typically I would provide a reference to a file as a file path. However, I'm considering storing some of the files (such as a small thumbnail) in a database directly rather then on a file system. In this case I don't want to add the extra step of reading the thumbnail out of the database onto the disc and then returning a path to the file for my program to read. I'd want to stream the image directly out of the database into my program and avoid writing anything to the disc unless the user explicit wants to save something. Would having my interface return a FileStreamor even a Imagemake sense? Then it would be up to the implementing class to determine if the source of the FileStream or Image is a file on a disc or binary data in a database. public interface MyInterface { string Thumbnail {get;} string Attachment {get;} } vs public interface MyInterface { Image Thumbnail {get;} FileStream Attachment {get;} }

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  • How do I create an empty file in emacs?

    - by Singletoned
    How can I create an empty file from emacs, ideally from within a dired buffer? For example, I've just opened a Python module in dired mode, created a new directory, opened that in dired, and now need to add an empty __init__.py file in the directory. If I use C-x C-f __init__.py RET C-x C-s then emacs doesn't create the file because no changes have been made to it. I would have to type in the file, save it, delete my typing and then save it again for that to work. Thanks

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  • Python library to detect if a file has changed between different runs?

    - by Stefano Borini
    Suppose I have a program A. I run it, and performs some operation starting from a file foo.txt. Now A terminates. New run of A. It checks if the file foo.txt has changed. If the file has changed, A runs its operation again, otherwise, it quits. Does a library function/external library for this exists ? Of course it can be implemented with an md5 + a file/db containing the md5. I want to prevent reinventing the wheel.

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  • How do I find out which process is locking a file using .NET?

    - by AJ
    I've seen several of answers about using Handle or Process Monitor, but I would like to be able to find out in my own code (C#) which process is locking a file. I have a nasty feeling that I'm going to have to spelunk around in the win32 API, but if anyone has already done this and can put me on the right track, I'd really appreciate the help. Update Links to similar questions How does one figure out what process locked a file using c#? Command line tool Across a Network Locking a USB device Unit test fails with locked file deleting locked file

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  • Save all file names in a directory to a vector

    - by Bobby
    I need to save all ".xml" file names in a directory to a vector. To make a long story short, I cannot use the dirent API. It seems as if C++ does not have any concept of "directories". Once I have the filenames in a vector, I can iterate through and "fopen" these files. Is there an easy way to get these filenames at runtime?

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