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  • Improved Performance on PeopleSoft Combined Benchmark using SPARC T4-4

    - by Brian
    Oracle's SPARC T4-4 server running Oracle's PeopleSoft HCM 9.1 combined online and batch benchmark achieved a world record 18,000 concurrent users experiencing subsecond response time while executing a PeopleSoft Payroll batch job of 500,000 employees in 32.4 minutes. This result was obtained with a SPARC T4-4 server running Oracle Database 11g Release 2, a SPARC T4-4 server running PeopleSoft HCM 9.1 application server and a SPARC T4-2 server running Oracle WebLogic Server in the web tier. The SPARC T4-4 server running the application tier used Oracle Solaris Zones which provide a flexible, scalable and manageable virtualization environment. The average CPU utilization on the SPARC T4-2 server in the web tier was 17%, on the SPARC T4-4 server in the application tier it was 59%, and on the SPARC T4-4 server in the database tier was 47% (online and batch) leaving significant headroom for additional processing across the three tiers. The SPARC T4-4 server used for the database tier hosted Oracle Database 11g Release 2 using Oracle Automatic Storage Management (ASM) for database files management with I/O performance equivalent to raw devices. Performance Landscape Results are presented for the PeopleSoft HRMS Self-Service and Payroll combined benchmark. The new result with 128 streams shows significant improvement in the payroll batch processing time with little impact on the self-service component response time. PeopleSoft HRMS Self-Service and Payroll Benchmark Systems Users Ave Response Search (sec) Ave Response Save (sec) Batch Time (min) Streams SPARC T4-2 (web) SPARC T4-4 (app) SPARC T4-4 (db) 18,000 0.988 0.539 32.4 128 SPARC T4-2 (web) SPARC T4-4 (app) SPARC T4-4 (db) 18,000 0.944 0.503 43.3 64 The following results are for the PeopleSoft HRMS Self-Service benchmark that was previous run. The results are not directly comparable with the combined results because they do not include the payroll component. PeopleSoft HRMS Self-Service 9.1 Benchmark Systems Users Ave Response Search (sec) Ave Response Save (sec) Batch Time (min) Streams SPARC T4-2 (web) SPARC T4-4 (app) 2x SPARC T4-2 (db) 18,000 1.048 0.742 N/A N/A The following results are for the PeopleSoft Payroll benchmark that was previous run. The results are not directly comparable with the combined results because they do not include the self-service component. PeopleSoft Payroll (N.A.) 9.1 - 500K Employees (7 Million SQL PayCalc, Unicode) Systems Users Ave Response Search (sec) Ave Response Save (sec) Batch Time (min) Streams SPARC T4-4 (db) N/A N/A N/A 30.84 96 Configuration Summary Application Configuration: 1 x SPARC T4-4 server with 4 x SPARC T4 processors, 3.0 GHz 512 GB memory Oracle Solaris 11 11/11 PeopleTools 8.52 PeopleSoft HCM 9.1 Oracle Tuxedo, Version 10.3.0.0, 64-bit, Patch Level 031 Java Platform, Standard Edition Development Kit 6 Update 32 Database Configuration: 1 x SPARC T4-4 server with 4 x SPARC T4 processors, 3.0 GHz 256 GB memory Oracle Solaris 11 11/11 Oracle Database 11g Release 2 PeopleTools 8.52 Oracle Tuxedo, Version 10.3.0.0, 64-bit, Patch Level 031 Micro Focus Server Express (COBOL v 5.1.00) Web Tier Configuration: 1 x SPARC T4-2 server with 2 x SPARC T4 processors, 2.85 GHz 256 GB memory Oracle Solaris 11 11/11 PeopleTools 8.52 Oracle WebLogic Server 10.3.4 Java Platform, Standard Edition Development Kit 6 Update 32 Storage Configuration: 1 x Sun Server X2-4 as a COMSTAR head for data 4 x Intel Xeon X7550, 2.0 GHz 128 GB memory 1 x Sun Storage F5100 Flash Array (80 flash modules) 1 x Sun Storage F5100 Flash Array (40 flash modules) 1 x Sun Fire X4275 as a COMSTAR head for redo logs 12 x 2 TB SAS disks with Niwot Raid controller Benchmark Description This benchmark combines PeopleSoft HCM 9.1 HR Self Service online and PeopleSoft Payroll batch workloads to run on a unified database deployed on Oracle Database 11g Release 2. The PeopleSoft HRSS benchmark kit is a Oracle standard benchmark kit run by all platform vendors to measure the performance. It's an OLTP benchmark where DB SQLs are moderately complex. The results are certified by Oracle and a white paper is published. PeopleSoft HR SS defines a business transaction as a series of HTML pages that guide a user through a particular scenario. Users are defined as corporate Employees, Managers and HR administrators. The benchmark consist of 14 scenarios which emulate users performing typical HCM transactions such as viewing paycheck, promoting and hiring employees, updating employee profile and other typical HCM application transactions. All these transactions are well-defined in the PeopleSoft HR Self-Service 9.1 benchmark kit. This benchmark metric is the weighted average response search/save time for all the transactions. The PeopleSoft 9.1 Payroll (North America) benchmark demonstrates system performance for a range of processing volumes in a specific configuration. This workload represents large batch runs typical of a ERP environment during a mass update. The benchmark measures five application business process run times for a database representing large organization. They are Paysheet Creation, Payroll Calculation, Payroll Confirmation, Print Advice forms, and Create Direct Deposit File. The benchmark metric is the cumulative elapsed time taken to complete the Paysheet Creation, Payroll Calculation and Payroll Confirmation business application processes. The benchmark metrics are taken for each respective benchmark while running simultaneously on the same database back-end. Specifically, the payroll batch processes are started when the online workload reaches steady state (the maximum number of online users) and overlap with online transactions for the duration of the steady state. Key Points and Best Practices Two PeopleSoft Domain sets with 200 application servers each on a SPARC T4-4 server were hosted in 2 separate Oracle Solaris Zones to demonstrate consolidation of multiple application servers, ease of administration and performance tuning. Each Oracle Solaris Zone was bound to a separate processor set, each containing 15 cores (total 120 threads). The default set (1 core from first and third processor socket, total 16 threads) was used for network and disk interrupt handling. This was done to improve performance by reducing memory access latency by using the physical memory closest to the processors and offload I/O interrupt handling to default set threads, freeing up cpu resources for Application Servers threads and balancing application workload across 240 threads. A total of 128 PeopleSoft streams server processes where used on the database node to complete payroll batch job of 500,000 employees in 32.4 minutes. See Also Oracle PeopleSoft Benchmark White Papers oracle.com SPARC T4-2 Server oracle.com OTN SPARC T4-4 Server oracle.com OTN PeopleSoft Enterprise Human Capital Managementoracle.com OTN PeopleSoft Enterprise Human Capital Management (Payroll) oracle.com OTN Oracle Solaris oracle.com OTN Oracle Database 11g Release 2 oracle.com OTN Disclosure Statement Copyright 2012, Oracle and/or its affiliates. All rights reserved. Oracle and Java are registered trademarks of Oracle and/or its affiliates. Other names may be trademarks of their respective owners. Results as of 8 November 2012.

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  • How to crop the UIImage?

    - by Rajendra Bhole
    Hi, I develop an application in which i process the image using its pixels but in that image processing it takes a lot of time. Therefore i want to crop UIImage (Only middle part of image i.e. removing/croping bordered part of image).I have the develop code are, - (NSInteger) processImage1: (UIImage*) image { CGFloat width = image.size.width; CGFloat height = image.size.height; struct pixel* pixels = (struct pixel*) calloc(1, image.size.width * image.size.height * sizeof(struct pixel)); if (pixels != nil) { // Create a new bitmap CGContextRef context = CGBitmapContextCreate( (void*) pixels, image.size.width, image.size.height, 8, image.size.width * 4, CGImageGetColorSpace(image.CGImage), kCGImageAlphaPremultipliedLast ); if (context != NULL) { // Draw the image in the bitmap CGContextDrawImage(context, CGRectMake(0.0f, 0.0f, image.size.width, image.size.height), image.CGImage); NSUInteger numberOfPixels = image.size.width * image.size.height; NSMutableArray *numberOfPixelsArray = [[[NSMutableArray alloc] initWithCapacity:numberOfPixelsArray] autorelease]; } How i take(croping outside bordered) the middle part of UIImage?????????

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  • How do I set the default size of /dev/shm?

    - by Richard
    I'd like to change the default size of /dev/shm in Lubuntu 11.10 (also known as /run/shm now, I guess). It doesn't seem to appear in my fstab: # / was on /dev/sdb5 during installation UUID=66ac63f0-45fa-4766-9d20-7c56bcd0460d / ext3 noatime,errors=remount-ro 0 1 # /home was on /dev/sdb7 during installation UUID=227f1b29-5d04-4c28-9c9c-ea70b1726434 /home ext3 noatime 0 2 # swap was on /dev/sdb6 during installation #UUID=9e13b7cc-1f75-4b4e-9e79-c0f7368de353 none swap sw 0 0 /dev/mapper/cryptswap1 none swap sw 0 0 tmpfs /tmp tmpfs defaults,noexec,nosuid 0 0 tmpfs /var/tmp tmpfs defaults,noexec,nosuid 0 0

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  • How to calculate the size of a project in the days-person unit of measurement?

    - by Will Marcouiller
    Once in a while I have read here and there the size of a project expressed in a matter of days-person or person-day. I may understand what this means, but I don't know on what do people base themselves to calculate it. What are the variables considered into this calculation? How these variables are used in the calculation formula? Otherwise, how to estimate it grossly, when something is missing from the formula's variables? Thanks! =)

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  • Is it possible to shrink the size of an HP Smart Array logical drive?

    - by ewwhite
    I know extension is quite possible using the hpacucli utility, but is there an easy way to reduce the size of an existing logical drive (not array)? The controller is a P410i in a ProLiant DL360 G6 server. I'd like to reduce logicaldrive 1 from 72GB to 40GB. => ctrl all show config detail Smart Array P410i in Slot 0 (Embedded) Bus Interface: PCI Slot: 0 Serial Number: 5001438006FD9A50 Cache Serial Number: PAAVP9VYFB8Y RAID 6 (ADG) Status: Disabled Controller Status: OK Chassis Slot: Hardware Revision: Rev C Firmware Version: 3.66 Rebuild Priority: Medium Expand Priority: Medium Surface Scan Delay: 3 secs Surface Scan Mode: Idle Queue Depth: Automatic Monitor and Performance Delay: 60 min Elevator Sort: Enabled Degraded Performance Optimization: Disabled Inconsistency Repair Policy: Disabled Wait for Cache Room: Disabled Surface Analysis Inconsistency Notification: Disabled Post Prompt Timeout: 15 secs Cache Board Present: True Cache Status: OK Accelerator Ratio: 25% Read / 75% Write Drive Write Cache: Enabled Total Cache Size: 512 MB No-Battery Write Cache: Disabled Cache Backup Power Source: Batteries Battery/Capacitor Count: 1 Battery/Capacitor Status: OK SATA NCQ Supported: True Array: A Interface Type: SAS Unused Space: 412476 MB Status: OK Logical Drive: 1 Size: 72.0 GB Fault Tolerance: RAID 1+0 Heads: 255 Sectors Per Track: 32 Cylinders: 18504 Strip Size: 256 KB Status: OK Array Accelerator: Enabled Unique Identifier: 600508B1001C132E4BBDFAA6DAD13DA3 Disk Name: /dev/cciss/c0d0 Mount Points: /boot 196 MB, / 12.0 GB, /usr 8.0 GB, /var 4.0 GB, /tmp 2.0 GB OS Status: LOCKED Logical Drive Label: AE438D6A5001438006FD9A50BE0A Mirror Group 0: physicaldrive 1I:1:1 (port 1I:box 1:bay 1, SAS, 146 GB, OK) physicaldrive 1I:1:2 (port 1I:box 1:bay 2, SAS, 146 GB, OK) Mirror Group 1: physicaldrive 1I:1:3 (port 1I:box 1:bay 3, SAS, 146 GB, OK) physicaldrive 1I:1:4 (port 1I:box 1:bay 4, SAS, 146 GB, OK) SEP (Vendor ID PMCSIERA, Model SRC 8x6G) 250 Device Number: 250 Firmware Version: RevC WWID: 5001438006FD9A5F Vendor ID: PMCSIERA Model: SRC 8x6G

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  • How can I format an SD card with a more robust Linux-usable filesystem with a specific cluster size for better write performace?

    - by Harvey
    Goal: microSD card formatted... for best write performance for use only with embedded Linux for better reliability (random power failures may occur) using an 64kB cluster size I'm using an 8GB microSD card for data storage inside an embedded Linux/ARM device. The SD card is not removable. I've been using ext3 instead of the pre-installed FAT32 because it seems to better handle random power failures during writes. However, I kept noticing that my write performance is always best with the pre-installed FAT32 from Kingston. If I reformat the card with FAT32, the performance still suffers. After browsing wikipedia, I stumbled upon the following comment saying that some cards are optimized for specific cluster sizes. In my case, the Kingston comes pre-formatted for an 64kB cluster size. Risks of reformatting Reformatting an SD card with a different file system, or even with the same one, may make the card slower, or shorten its lifespan. Some cards use wear leveling, in which frequently modified blocks are mapped to different portions of memory at different times, and some wear-leveling algorithms are designed for the access patterns typical of the file allocation table on a FAT16 or FAT32 device.[60] In addition, the preformatted file system may use a cluster size that matches the erase region of the physical memory on the card; reformatting may change the cluster size and make writes less efficient.

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  • On linux, what does it mean when a directory has size 0 instead of 4096?

    - by kdt
    Here's a strange thing I haven't seen before -- a directory whose size is reported by ls as 0 instead of 4096, and I can't create any files within it. # ls -ld lib home drwxr-xr-x. 2 root root 0 Feb 7 03:10 home <-- it has zero size dr-xr-xr-x. 11 root root 4096 Feb 4 09:28 lib # touch home/foo touch: cannot touch `home/foo': No such file or directory <-- and I can't create files in it # rm home rm: cannot remove `home': Is a directory <-- look, it really is a dir So what does it mean for a directory to have size 0 instead of 4096? Filesystem is ext4 on fedora core 14. The output of mount is: /dev/mapper/vg_dev-lv_root on / type ext4 (rw) proc on /proc type proc (rw) sysfs on /sys type sysfs (rw) devpts on /dev/pts type devpts (rw,gid=5,mode=620) tmpfs on /dev/shm type tmpfs (rw,rootcontext="system_u:object_r:tmpfs_t:s0") /dev/vda1 on /boot type ext4 (rw) none on /proc/sys/fs/binfmt_misc type binfmt_misc (rw) sunrpc on /var/lib/nfs/rpc_pipefs type rpc_pipefs (rw) Output of du -s /home: 0 /home Output of stat /home: File: `/home' Size: 0 Blocks: 0 IO Block: 1024 directory Device: 15h/21d Inode: 34913 Links: 2 Access: (0755/drwxr-xr-x) Uid: ( 0/ root) Gid: ( 0/ root) Access: 2011-02-07 03:45:46.188995765 -0800 Modify: 2011-02-07 03:11:59.980995019 -0800 Change: 2011-02-06 07:58:45.874995002 -0800

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  • libgdx intersection problem between rectangle and circle

    - by Chris
    My collision detection in libgdx is somehow buggy. player.png is 20*80px and ball.png 25*25px. Code: @Override public void create() { // ... batch = new SpriteBatch(); playerTex = new Texture(Gdx.files.internal("data/player.png")); ballTex = new Texture(Gdx.files.internal("data/ball.png")); player = new Rectangle(); player.width = 20; player.height = 80; player.x = Gdx.graphics.getWidth() - player.width - 10; player.y = 300; ball = new Circle(); ball.x = Gdx.graphics.getWidth() / 2; ball.y = Gdx.graphics.getHeight() / 2; ball.radius = ballTex.getWidth() / 2; } @Override public void render() { Gdx.gl.glClearColor(1, 1, 1, 1); Gdx.gl.glClear(GL10.GL_COLOR_BUFFER_BIT); camera.update(); // draw player, ball batch.setProjectionMatrix(camera.combined); batch.begin(); batch.draw(ballTex, ball.x, ball.y); batch.draw(playerTex, player.x, player.y); batch.end(); // update player position if(Gdx.input.isKeyPressed(Keys.DOWN)) player.y -= 250 * Gdx.graphics.getDeltaTime(); if(Gdx.input.isKeyPressed(Keys.UP)) player.y += 250 * Gdx.graphics.getDeltaTime(); if(Gdx.input.isKeyPressed(Keys.LEFT)) player.x -= 250 * Gdx.graphics.getDeltaTime(); if(Gdx.input.isKeyPressed(Keys.RIGHT)) player.x += 250 * Gdx.graphics.getDeltaTime(); // don't let the player leave the field if(player.y < 0) player.y = 0; if(player.y > 600 - 80) player.y = 600 - 80; // check collision if (Intersector.overlaps(ball, player)) Gdx.app.log("overlaps", "yes"); }

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  • libgdx loading textures fails [duplicate]

    - by Chris
    This question already has an answer here: Why do I get this file loading exception when trying to draw sprites with libgdx? 4 answers I'm trying to load my texture with playerTex = new Texture(Gdx.files.internal("player.jpg")); player.jpg is located under my-gdx-game-android/assets/data/player.jpg I get an exception like this: Full Code: @Override public void create() { camera = new OrthographicCamera(); camera.setToOrtho(false, Gdx.graphics.getWidth(), Gdx.graphics.getHeight()); batch = new SpriteBatch(); FileHandle file = Gdx.files.internal("player.jpg"); playerTex = new Texture(file); player = new Rectangle(); player.x = 800-20; player.y = 250; player.width = 20; player.height = 80; } @Override public void dispose() { // dispose of all the native resources playerTex.dispose(); batch.dispose(); } @Override public void render() { Gdx.gl.glClearColor(1, 1, 1, 1); Gdx.gl.glClear(GL10.GL_COLOR_BUFFER_BIT); camera.update(); batch.setProjectionMatrix(camera.combined); batch.begin(); batch.draw(playerTex, player.x, player.y); batch.end(); if(Gdx.input.isKeyPressed(Keys.DOWN)) player.y -= 50 * Gdx.graphics.getDeltaTime(); if(Gdx.input.isKeyPressed(Keys.UP)) player.y += 50 * Gdx.graphics.getDeltaTime(); }

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  • Failing Screen Resize Method

    - by StrongJoshua
    So I want my game to draw to a specific "optimal" size and then be stretched to fit screens that are a different size. I'm using LibGDX and figured that I could just draw everything to a FrameBuffer and then resize that buffer to the appropriate size when drawing it to the actual display. However, my method does not work, it just results in a black screen with the top right quarter of the screen white.Intermediary is the FBO, interMatrix is a Matrix4 object, and camera is an OrthographicCamera. @Override public void render() { // update actors currentStage.act(); //render to intermediary buffer batch.setProjectionMatrix(interMatrix); intermediary.begin(); batch.begin(); currentStage.draw(); batch.flush(); intermediary.end(); //resize to actual width and height Sprite s = new Sprite(intermediary.getColorBufferTexture()); s.flip(true, false); batch.setProjectionMatrix(camera.combined); batch.draw(s.getTexture(), 0, 0, width, height); batch.end(); } These are the constructors for the above mentioned objects (GAME_WIDTH and HEIGHT are the "optimal" settings, width and height are the actual sizes, which are the same when running on desktop). intermediary = new FrameBuffer(Format.RGBA8888, GAME_WIDTH, GAME_HEIGHT, false); interMatrix = new Matrix4(); camera = new OrthographicCamera(width, height); interMatrix.setToOrtho2D(0, 0, GAME_WIDTH, GAME_HEIGHT); Is there a better way of doing this or can is this a viable option and how do I fix what I have?

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  • My linux server takes more than an hour to boot. Suggestions?

    - by jamieb
    I am building a CentOS 5.4 system that boots off a compact flash card using a card reader that emulates an IDE drive. It literally takes about an hour to boot. The ultra-slow part occurs when Grub is loading the kernel. Once that's done, the rest of the boot process only takes about a minute to get to a login prompt. Does anyone have any suggestions? I suspect that it may have to do with UDMA. Everything IDE-related in my BIOS seems to checkout. The read performance hdparm is telling me 1.77 MB/s. Ouch! (But even at that rate, it still shouldn't take an hour to decompress and load the kernel) [root@server ~]# hdparm -tT /dev/hdc /dev/hdc: Timing cached reads: 2444 MB in 2.00 seconds = 1222.04 MB/sec Timing buffered disk reads: 6 MB in 3.39 seconds = 1.77 MB/sec Trying to enable DMA is a no-go though: [root@server ~]# hdparm -d1 /dev/hdc /dev/hdc: setting using_dma to 1 (on) HDIO_SET_DMA failed: Operation not permitted using_dma = 0 (off) Here's some command outputs that might help: System [root@server ~]# uname -a Linux server.localdomain 2.6.18-164.el5xen #1 SMP Thu Sep 3 04:47:32 EDT 2009 i686 i686 i386 GNU/Linux PCI info: [root@server ~]# lspci -v 00:00.0 Host bridge: Intel Corporation 82945G/GZ/P/PL Memory Controller Hub (rev 02) Subsystem: Intel Corporation 82945G/GZ/P/PL Memory Controller Hub Flags: bus master, fast devsel, latency 0 Capabilities: [e0] Vendor Specific Information 00:02.0 VGA compatible controller: Intel Corporation 82945G/GZ Integrated Graphics Controller (rev 02) (prog-if 00 [VGA controller]) Subsystem: Intel Corporation 82945G/GZ Integrated Graphics Controller Flags: bus master, fast devsel, latency 0, IRQ 10 Memory at fdf00000 (32-bit, non-prefetchable) [size=512K] I/O ports at ff00 [size=8] Memory at d0000000 (32-bit, prefetchable) [size=256M] Memory at fdf80000 (32-bit, non-prefetchable) [size=256K] Capabilities: [90] Message Signalled Interrupts: 64bit- Queue=0/0 Enable- Capabilities: [d0] Power Management version 2 00:1d.0 USB Controller: Intel Corporation 82801G (ICH7 Family) USB UHCI Controller #1 (rev 01) (prog-if 00 [UHCI]) Subsystem: Intel Corporation 82801G (ICH7 Family) USB UHCI Controller #1 Flags: bus master, medium devsel, latency 0, IRQ 16 I/O ports at fe00 [size=32] 00:1d.1 USB Controller: Intel Corporation 82801G (ICH7 Family) USB UHCI Controller #2 (rev 01) (prog-if 00 [UHCI]) Subsystem: Intel Corporation 82801G (ICH7 Family) USB UHCI Controller #2 Flags: bus master, medium devsel, latency 0, IRQ 17 I/O ports at fd00 [size=32] 00:1d.2 USB Controller: Intel Corporation 82801G (ICH7 Family) USB UHCI Controller #3 (rev 01) (prog-if 00 [UHCI]) Subsystem: Intel Corporation 82801G (ICH7 Family) USB UHCI Controller #3 Flags: bus master, medium devsel, latency 0, IRQ 18 I/O ports at fc00 [size=32] 00:1d.3 USB Controller: Intel Corporation 82801G (ICH7 Family) USB UHCI Controller #4 (rev 01) (prog-if 00 [UHCI]) Subsystem: Intel Corporation 82801G (ICH7 Family) USB UHCI Controller #4 Flags: bus master, medium devsel, latency 0, IRQ 19 I/O ports at fb00 [size=32] 00:1d.7 USB Controller: Intel Corporation 82801G (ICH7 Family) USB2 EHCI Controller (rev 01) (prog-if 20 [EHCI]) Subsystem: Intel Corporation 82801G (ICH7 Family) USB2 EHCI Controller Flags: bus master, medium devsel, latency 0, IRQ 16 Memory at fdfff000 (32-bit, non-prefetchable) [size=1K] Capabilities: [50] Power Management version 2 Capabilities: [58] Debug port 00:1e.0 PCI bridge: Intel Corporation 82801 PCI Bridge (rev e1) (prog-if 01 [Subtractive decode]) Flags: bus master, fast devsel, latency 0 Bus: primary=00, secondary=01, subordinate=01, sec-latency=32 I/O behind bridge: 0000d000-0000dfff Memory behind bridge: fde00000-fdefffff Prefetchable memory behind bridge: 00000000fdd00000-00000000fdd00000 Capabilities: [50] #0d [0000] 00:1f.0 ISA bridge: Intel Corporation 82801GB/GR (ICH7 Family) LPC Interface Bridge (rev 01) Subsystem: Intel Corporation 82801GB/GR (ICH7 Family) LPC Interface Bridge Flags: bus master, medium devsel, latency 0 Capabilities: [e0] Vendor Specific Information 00:1f.2 IDE interface: Intel Corporation 82801GB/GR/GH (ICH7 Family) SATA IDE Controller (rev 01) (prog-if 80 [Master]) Subsystem: Intel Corporation 82801GB/GR/GH (ICH7 Family) SATA IDE Controller Flags: bus master, 66MHz, medium devsel, latency 0, IRQ 17 I/O ports at <unassigned> I/O ports at <unassigned> I/O ports at <unassigned> I/O ports at <unassigned> I/O ports at f800 [size=16] Capabilities: [70] Power Management version 2 00:1f.3 SMBus: Intel Corporation 82801G (ICH7 Family) SMBus Controller (rev 01) Subsystem: Intel Corporation 82801G (ICH7 Family) SMBus Controller Flags: medium devsel, IRQ 17 I/O ports at 0500 [size=32] 01:04.0 Ethernet controller: Realtek Semiconductor Co., Ltd. RTL-8139/8139C/8139C+ (rev 10) Subsystem: Realtek Semiconductor Co., Ltd. RTL-8139/8139C/8139C+ Flags: bus master, medium devsel, latency 32, IRQ 18 I/O ports at de00 [size=256] Memory at fdeff000 (32-bit, non-prefetchable) [size=256] Capabilities: [50] Power Management version 2 01:06.0 Ethernet controller: Realtek Semiconductor Co., Ltd. RTL-8139/8139C/8139C+ (rev 10) Subsystem: Realtek Semiconductor Co., Ltd. RTL-8139/8139C/8139C+ Flags: bus master, medium devsel, latency 32, IRQ 17 I/O ports at dc00 [size=256] Memory at fdefe000 (32-bit, non-prefetchable) [size=256] Capabilities: [50] Power Management version 2 01:07.0 Ethernet controller: Realtek Semiconductor Co., Ltd. RTL-8139/8139C/8139C+ (rev 10) Subsystem: Realtek Semiconductor Co., Ltd. RTL-8139/8139C/8139C+ Flags: bus master, medium devsel, latency 32, IRQ 19 I/O ports at da00 [size=256] Memory at fdefd000 (32-bit, non-prefetchable) [size=256] Capabilities: [50] Power Management version 2 hdparm ouput: [root@server ~]# hdparm /dev/hdc /dev/hdc: multcount = 0 (off) IO_support = 0 (default 16-bit) unmaskirq = 0 (off) using_dma = 0 (off) keepsettings = 0 (off) readonly = 0 (off) readahead = 256 (on) geometry = 8146/16/63, sectors = 8211168, start = 0 [root@server ~]# hdparm -I /dev/hdc /dev/hdc: ATA device, with non-removable media Model Number: InnoDisk Corp. - iCF4000 4GB Serial Number: 20091023AACA70000753 Firmware Revision: 081107 Standards: Supported: 5 Likely used: 6 Configuration: Logical max current cylinders 8146 8146 heads 16 16 sectors/track 63 63 -- CHS current addressable sectors: 8211168 LBA user addressable sectors: 8211168 device size with M = 1024*1024: 4009 MBytes device size with M = 1000*1000: 4204 MBytes (4 GB) Capabilities: LBA, IORDY(can be disabled) Standby timer values: spec'd by Vendor R/W multiple sector transfer: Max = 2 Current = 2 DMA: mdma0 mdma1 mdma2 udma0 udma1 *udma2 udma3 udma4 Cycle time: min=120ns recommended=120ns PIO: pio0 pio1 pio2 pio3 pio4 Cycle time: no flow control=120ns IORDY flow control=120ns Commands/features: Enabled Supported: * Power Management feature set * WRITE_BUFFER command * READ_BUFFER command * NOP cmd * CFA feature set * Mandatory FLUSH_CACHE HW reset results: CBLID- above Vih Device num = 0 CFA power mode 1: enabled and required by some commands Maximum current = 100ma Checksum: correct

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  • FFMPEG Segfault Solutions

    - by Brentley_11
    I'm trying to convert a bunch of movies into h.264 mp4's using FFMPEG. These movies are sourced from various portable camcorders such as the Flip Mino HD and the Kodak ZI8. One issue I'm having with video from the ZI8 is it seems to be causing FFMPEG to segfault. Here is my command: ffmpeg -i 'XmasSailor720p60fps.MOV' -threads 2 -acodec libfaac -ab 96kb -vcodec libx264 -vpre hq -b 500kb -s 484x272 XmasSailor.mp4 Here is the output: FFmpeg version SVN-r20668, Copyright (c) 2000-2009 Fabrice Bellard, et al. built on Dec 2 2009 18:37:34 with gcc 4.2.4 (Ubuntu 4.2.4-1ubuntu4) configuration: --enable-libfaac --enable-libfaad --enable-libmp3lame --enable-libx264 --enable-gpl --enable-nonfree --enable-postproc --enable-pthreads --enable-shared libavutil 50. 5. 1 / 50. 5. 1 libavcodec 52.42. 0 / 52.42. 0 libavformat 52.39. 2 / 52.39. 2 libavdevice 52. 2. 0 / 52. 2. 0 libswscale 0. 7. 2 / 0. 7. 2 libpostproc 51. 2. 0 / 51. 2. 0 Seems stream 0 codec frame rate differs from container frame rate: 59.94 (60000/1001) -> 29.97 (30000/1001) Input #0, mov,mp4,m4a,3gp,3g2,mj2, from 'XmasSailor720p60fps.MOV': Duration: 00:00:05.37, start: 0.000000, bitrate: 12021 kb/s Stream #0.0(eng): Video: h264, yuv420p, 1280x720 [PAR 1:1 DAR 16:9], 11994 kb/s, 29.97 tbr, 90k tbn, 59.94 tbc Stream #0.1(eng): Audio: aac, 48000 Hz, stereo, s16, 128 kb/s Metadata major_brand : qt minor_version : 0 compatible_brands: qt comment : KODAK Zi8 Pocket Video Camera comment-eng : KODAK Zi8 Pocket Video Camera [libx264 @ 0x99e1020]using SAR=1/1 [libx264 @ 0x99e1020]using cpu capabilities: MMX2 SSE2Fast SSSE3 FastShuffle SSE4.1 Cache64 [libx264 @ 0x99e1020]profile High, level 2.1 Output #0, mp4, to 'XmasSailor.mp4': Stream #0.0(eng): Video: libx264, yuv420p, 484x272 [PAR 1:1 DAR 121:68], q=10-51, 500 kb/s, 30k tbn, 29.97 tbc Stream #0.1(eng): Audio: aac, 48000 Hz, stereo, s16, 96 kb/s Metadata comment : Encoded with the Statusfirm Video Transcoder Stream mapping: Stream #0.0 -> #0.0 Stream #0.1 -> #0.1 Press [q] to stop encoding [h264 @ 0x99de950]B picture before any references, skipping [h264 @ 0x99de950]decode_slice_header error [h264 @ 0x99de950]no frame! Error while decoding stream #0.0 [h264 @ 0x99de950]B picture before any references, skipping [h264 @ 0x99de950]decode_slice_header error [h264 @ 0x99de950]no frame! Error while decoding stream #0.0 frame= 20 fps= 0 q=13797729.0 size= 0kB time=0.66 bitrate= 0.6kbits/s frame= 39 fps= 37 q=13797729.0 size= 0kB time=1.30 bitrate= 0.3kbits/s frame= 48 fps= 30 q=33.0 size= 11kB time=0.10 bitrate= 903.0kbits/s frame= 58 fps= 27 q=31.0 size= 22kB time=0.43 bitrate= 421.0kbits/s frame= 67 fps= 25 q=29.0 size= 41kB time=0.73 bitrate= 462.6kbits/s frame= 75 fps= 23 q=29.0 size= 59kB time=1.00 bitrate= 486.7kbits/s frame= 83 fps= 22 q=29.0 size= 81kB time=1.27 bitrate= 521.9kbits/s frame= 90 fps= 21 q=29.0 size= 97kB time=1.50 bitrate= 530.1kbits/s frame= 98 fps= 20 q=29.0 size= 114kB time=1.77 bitrate= 526.9kbits/s frame= 106 fps= 20 q=29.0 size= 134kB time=2.04 bitrate= 537.7kbits/s frame= 114 fps= 19 q=29.0 size= 150kB time=2.30 bitrate= 533.7kbits/s frame= 122 fps= 19 q=29.0 size= 172kB time=2.57 bitrate= 547.8kbits/s frame= 130 fps= 19 q=29.0 size= 193kB time=2.84 bitrate= 557.5kbits/s frame= 136 fps= 18 q=29.0 size= 211kB time=3.04 bitrate= 570.0kbits/s frame= 144 fps= 18 q=29.0 size= 242kB time=3.30 bitrate= 599.5kbits/s frame= 152 fps= 17 q=30.0 size= 261kB time=3.57 bitrate= 598.6kbits/s frame= 157 fps= 15 q=-1.0 Lsize= 368kB time=5.21 bitrate= 579.3kbits/s video:302kB audio:61kB global headers:0kB muxing overhead 1.416371% [libx264 @ 0x99e1020]frame I:1 Avg QP:27.22 size: 8720 [libx264 @ 0x99e1020]frame P:48 Avg QP:25.15 size: 3759 [libx264 @ 0x99e1020]frame B:108 Avg QP:30.10 size: 1105 [libx264 @ 0x99e1020]consecutive B-frames: 0.6% 11.5% 28.8% 59.0% [libx264 @ 0x99e1020]mb I I16..4: 28.5% 47.6% 23.9% [libx264 @ 0x99e1020]mb P I16..4: 0.8% 1.3% 0.5% P16..4: 50.6% 17.7% 13.1% 0.0% 0.0% skip:15.9% [libx264 @ 0x99e1020]mb B I16..4: 0.2% 0.3% 0.1% B16..8: 44.0% 1.2% 2.6% direct: 5.1% skip:46.5% L0:45.5% L1:51.0% BI: 3.5% [libx264 @ 0x99e1020]final ratefactor: 23.51 [libx264 @ 0x99e1020]8x8 transform intra:49.9% inter:67.9% [libx264 @ 0x99e1020]direct mvs spatial:98.1% temporal:1.9% [libx264 @ 0x99e1020]coded y,uvDC,uvAC intra: 54.7% 76.1% 41.4% inter: 17.1% 24.4% 7.8% [libx264 @ 0x99e1020]i16 v,h,dc,p: 18% 52% 5% 25% [libx264 @ 0x99e1020]i8 v,h,dc,ddl,ddr,vr,hd,vl,hu: 12% 22% 9% 7% 10% 10% 9% 8% 13% [libx264 @ 0x99e1020]i4 v,h,dc,ddl,ddr,vr,hd,vl,hu: 13% 18% 8% 8% 10% 13% 10% 9% 12% [libx264 @ 0x99e1020]Weighted P-Frames: Y:10.4% [libx264 @ 0x99e1020]ref P L0: 60.2% 15.3% 11.0% 7.6% 5.2% 0.7% [libx264 @ 0x99e1020]ref B L0: 72.6% 15.6% 11.8% [libx264 @ 0x99e1020]kb/s:471.17 Segmentation fault I'm wondering if anyone else has ran into similar issues. I wasn't able to find anything helpful via Google. Another question I have is if anyone knows of a company that offers paid support for FFMPEG. Thank you for your time.

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  • FFMPEG Segfault Solutions

    - by Brentley_11
    I'm trying to convert a bunch of movies into h.264 mp4's using FFMPEG. These movies are sourced from various portable camcorders such as the Flip Mino HD and the Kodak ZI8. One issue I'm having with video from the ZI8 is it seems to be causing FFMPEG to segfault. Here is my command: ffmpeg -i 'XmasSailor720p60fps.MOV' -threads 2 -acodec libfaac -ab 96kb -vcodec libx264 -vpre hq -b 500kb -s 484x272 XmasSailor.mp4 Here is the output: FFmpeg version SVN-r20668, Copyright (c) 2000-2009 Fabrice Bellard, et al. built on Dec 2 2009 18:37:34 with gcc 4.2.4 (Ubuntu 4.2.4-1ubuntu4) configuration: --enable-libfaac --enable-libfaad --enable-libmp3lame --enable-libx264 --enable-gpl --enable-nonfree --enable-postproc --enable-pthreads --enable-shared libavutil 50. 5. 1 / 50. 5. 1 libavcodec 52.42. 0 / 52.42. 0 libavformat 52.39. 2 / 52.39. 2 libavdevice 52. 2. 0 / 52. 2. 0 libswscale 0. 7. 2 / 0. 7. 2 libpostproc 51. 2. 0 / 51. 2. 0 Seems stream 0 codec frame rate differs from container frame rate: 59.94 (60000/1001) -> 29.97 (30000/1001) Input #0, mov,mp4,m4a,3gp,3g2,mj2, from 'XmasSailor720p60fps.MOV': Duration: 00:00:05.37, start: 0.000000, bitrate: 12021 kb/s Stream #0.0(eng): Video: h264, yuv420p, 1280x720 [PAR 1:1 DAR 16:9], 11994 kb/s, 29.97 tbr, 90k tbn, 59.94 tbc Stream #0.1(eng): Audio: aac, 48000 Hz, stereo, s16, 128 kb/s Metadata major_brand : qt minor_version : 0 compatible_brands: qt comment : KODAK Zi8 Pocket Video Camera comment-eng : KODAK Zi8 Pocket Video Camera [libx264 @ 0x99e1020]using SAR=1/1 [libx264 @ 0x99e1020]using cpu capabilities: MMX2 SSE2Fast SSSE3 FastShuffle SSE4.1 Cache64 [libx264 @ 0x99e1020]profile High, level 2.1 Output #0, mp4, to 'XmasSailor.mp4': Stream #0.0(eng): Video: libx264, yuv420p, 484x272 [PAR 1:1 DAR 121:68], q=10-51, 500 kb/s, 30k tbn, 29.97 tbc Stream #0.1(eng): Audio: aac, 48000 Hz, stereo, s16, 96 kb/s Metadata comment : Encoded with the Statusfirm Video Transcoder Stream mapping: Stream #0.0 -> #0.0 Stream #0.1 -> #0.1 Press [q] to stop encoding [h264 @ 0x99de950]B picture before any references, skipping [h264 @ 0x99de950]decode_slice_header error [h264 @ 0x99de950]no frame! Error while decoding stream #0.0 [h264 @ 0x99de950]B picture before any references, skipping [h264 @ 0x99de950]decode_slice_header error [h264 @ 0x99de950]no frame! Error while decoding stream #0.0 frame= 20 fps= 0 q=13797729.0 size= 0kB time=0.66 bitrate= 0.6kbits/s frame= 39 fps= 37 q=13797729.0 size= 0kB time=1.30 bitrate= 0.3kbits/s frame= 48 fps= 30 q=33.0 size= 11kB time=0.10 bitrate= 903.0kbits/s frame= 58 fps= 27 q=31.0 size= 22kB time=0.43 bitrate= 421.0kbits/s frame= 67 fps= 25 q=29.0 size= 41kB time=0.73 bitrate= 462.6kbits/s frame= 75 fps= 23 q=29.0 size= 59kB time=1.00 bitrate= 486.7kbits/s frame= 83 fps= 22 q=29.0 size= 81kB time=1.27 bitrate= 521.9kbits/s frame= 90 fps= 21 q=29.0 size= 97kB time=1.50 bitrate= 530.1kbits/s frame= 98 fps= 20 q=29.0 size= 114kB time=1.77 bitrate= 526.9kbits/s frame= 106 fps= 20 q=29.0 size= 134kB time=2.04 bitrate= 537.7kbits/s frame= 114 fps= 19 q=29.0 size= 150kB time=2.30 bitrate= 533.7kbits/s frame= 122 fps= 19 q=29.0 size= 172kB time=2.57 bitrate= 547.8kbits/s frame= 130 fps= 19 q=29.0 size= 193kB time=2.84 bitrate= 557.5kbits/s frame= 136 fps= 18 q=29.0 size= 211kB time=3.04 bitrate= 570.0kbits/s frame= 144 fps= 18 q=29.0 size= 242kB time=3.30 bitrate= 599.5kbits/s frame= 152 fps= 17 q=30.0 size= 261kB time=3.57 bitrate= 598.6kbits/s frame= 157 fps= 15 q=-1.0 Lsize= 368kB time=5.21 bitrate= 579.3kbits/s video:302kB audio:61kB global headers:0kB muxing overhead 1.416371% [libx264 @ 0x99e1020]frame I:1 Avg QP:27.22 size: 8720 [libx264 @ 0x99e1020]frame P:48 Avg QP:25.15 size: 3759 [libx264 @ 0x99e1020]frame B:108 Avg QP:30.10 size: 1105 [libx264 @ 0x99e1020]consecutive B-frames: 0.6% 11.5% 28.8% 59.0% [libx264 @ 0x99e1020]mb I I16..4: 28.5% 47.6% 23.9% [libx264 @ 0x99e1020]mb P I16..4: 0.8% 1.3% 0.5% P16..4: 50.6% 17.7% 13.1% 0.0% 0.0% skip:15.9% [libx264 @ 0x99e1020]mb B I16..4: 0.2% 0.3% 0.1% B16..8: 44.0% 1.2% 2.6% direct: 5.1% skip:46.5% L0:45.5% L1:51.0% BI: 3.5% [libx264 @ 0x99e1020]final ratefactor: 23.51 [libx264 @ 0x99e1020]8x8 transform intra:49.9% inter:67.9% [libx264 @ 0x99e1020]direct mvs spatial:98.1% temporal:1.9% [libx264 @ 0x99e1020]coded y,uvDC,uvAC intra: 54.7% 76.1% 41.4% inter: 17.1% 24.4% 7.8% [libx264 @ 0x99e1020]i16 v,h,dc,p: 18% 52% 5% 25% [libx264 @ 0x99e1020]i8 v,h,dc,ddl,ddr,vr,hd,vl,hu: 12% 22% 9% 7% 10% 10% 9% 8% 13% [libx264 @ 0x99e1020]i4 v,h,dc,ddl,ddr,vr,hd,vl,hu: 13% 18% 8% 8% 10% 13% 10% 9% 12% [libx264 @ 0x99e1020]Weighted P-Frames: Y:10.4% [libx264 @ 0x99e1020]ref P L0: 60.2% 15.3% 11.0% 7.6% 5.2% 0.7% [libx264 @ 0x99e1020]ref B L0: 72.6% 15.6% 11.8% [libx264 @ 0x99e1020]kb/s:471.17 Segmentation fault I'm wondering if anyone else has ran into similar issues. I wasn't able to find anything helpful via Google. Another question I have is if anyone knows of a company that offers paid support for FFMPEG. Thank you for your time.

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  • Problems with SAT Collision Detection

    - by DJ AzKai
    I'm doing a project in one of my modules for college in C++ with SFML and I was hoping someone may be able to help me. I'm using a vector of squares and triangles and I am using the SAT collision detection method to see if objects collide and to make the objects respond to the collision appropriately using the MTV(minimum translation vector) Below is my code: //from the main method int main(){ // Create the main window sf::RenderWindow App(sf::VideoMode(800, 600, 32), "SFML OpenGL"); // Create a clock for measuring time elapsed sf::Clock Clock; srand(time(0)); //prepare OpenGL surface for HSR glClearDepth(1.f); glClearColor(0.3f, 0.3f, 0.3f, 0.f); //background colour glEnable(GL_DEPTH_TEST); glDepthMask(GL_TRUE); //// Setup a perspective projection & Camera position glMatrixMode(GL_PROJECTION); glLoadIdentity(); //set up a 3D Perspective View volume //gluPerspective(90.f, 1.f, 1.f, 300.0f);//fov, aspect, zNear, zFar //set up a orthographic projection same size as window //this mease the vertex coordinates are in pixel space glOrtho(0,800,0,600,0,1); // use pixel coordinates // Finally, display rendered frame on screen vector<BouncingThing*> triangles; for(int i = 0; i < 10; i++) { //instantiate each triangle; triangles.push_back(new BouncingTriangle(Vector2f(rand() % 700, rand() % 500), 3)); } vector<BouncingThing*> boxes; for(int i = 0; i < 10; i++) { //instantiate each box; boxes.push_back(new BouncingBox(Vector2f(rand() % 700, rand() % 500), 4)); } CollisionDetection * b = new CollisionDetection(); // Start game loop while (App.isOpen()) { // Process events sf::Event Event; while (App.pollEvent(Event)) { // Close window : exit if (Event.type == sf::Event::Closed) App.close(); // Escape key : exit if ((Event.type == sf::Event::KeyPressed) && (Event.key.code == sf::Keyboard::Escape)) App.close(); } //Prepare for drawing // Clear color and depth buffer glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); // Apply some transformations glMatrixMode(GL_MODELVIEW); glLoadIdentity(); for(int i = 0; i < 10; i++) { triangles[i]->draw(); boxes[i]->draw(); triangles[i]->update(Vector2f(800,600)); boxes[i]->draw(); boxes[i]->update(Vector2f(800,600)); } for(int j = 0; j < 10; j++) { for(int i = 0; i < 10; i++) { triangles[j]->setCollision(b->CheckCollision(*(triangles[j]),*(boxes[i]))); } } for(int j = 0; j < 10; j++) { for(int i = 0; i < 10; i++) { boxes[j]->setCollision(b->CheckCollision(*(boxes[j]),*(triangles[i]))); } } for(int i = 0; i < triangles.size(); i++) { for(int j = i + 1; j < triangles.size(); j ++) { triangles[j]->setCollision(b->CheckCollision(*(triangles[j]),*(triangles[i]))); } } for(int i = 0; i < triangles.size(); i++) { for(int j = i + 1; j < triangles.size(); j ++) { boxes[j]->setCollision(b->CheckCollision(*(boxes[j]),*(boxes[i]))); } } App.display(); } return EXIT_SUCCESS; } (ignore this line) //from the BouncingThing.cpp BouncingThing::BouncingThing(Vector2f position, int noSides) : pos(position), pi(3.14), radius(3.14), nSides(noSides) { collided = false; if(nSides ==3) { Vector2f vert1 = Vector2f(-12.0f,-12.0f); Vector2f vert2 = Vector2f(0.0f, 12.0f); Vector2f vert3 = Vector2f(12.0f,-12.0f); verts.push_back(vert1); verts.push_back(vert2); verts.push_back(vert3); } else if(nSides == 4) { Vector2f vert1 = Vector2f(-12.0f,12.0f); Vector2f vert2 = Vector2f(12.0f, 12.0f); Vector2f vert3 = Vector2f(12.0f,-12.0f); Vector2f vert4 = Vector2f(-12.0f, -12.0f); verts.push_back(vert1); verts.push_back(vert2); verts.push_back(vert3); verts.push_back(vert4); } velocity.x = ((rand() % 5 + 1) / 3) + 1; velocity.y = ((rand() % 5 + 1) / 3 ) +1; } void BouncingThing::update(Vector2f screenSize) { Transform t; t.rotate(0); for(int i=0;i< verts.size(); i++) { verts[i]=t.transformPoint(verts[i]); } if(pos.x >= screenSize.x || pos.x <= 0) { velocity.x *= -1; } if(pos.y >= screenSize.y || pos.y <= 0) { velocity.y *= -1; } if(collided) { //velocity.x *= -1; //velocity.y *= -1; collided = false; } pos += velocity; } void BouncingThing::setCollision(bool x){ collided = x; } void BouncingThing::draw() { glBegin(GL_POLYGON); glColor3f(0,1,0); for(int i = 0; i < verts.size(); i++) { glVertex2f(pos.x + verts[i].x,pos.y + verts[i].y); } glEnd(); } vector<Vector2f> BouncingThing::getNormals() { vector<Vector2f> normalVerts; if(nSides == 3) { Vector2f ab = Vector2f((verts[1].x + pos.x) - (verts[0].x + pos.x), (verts[1].y + pos.y) - (verts[0].y + pos.y)); ab = flip(ab); ab.x *= -1; normalVerts.push_back(ab); Vector2f bc = Vector2f((verts[2].x + pos.x) - (verts[1].x + pos.x), (verts[2].y + pos.y) - (verts[1].y + pos.y)); bc = flip(bc); bc.x *= -1; normalVerts.push_back(bc); Vector2f ac = Vector2f((verts[2].x + pos.x) - (verts[0].x + pos.x), (verts[2].y + pos.y) - (verts[0].y + pos.y)); ac = flip(ac); ac.x *= -1; normalVerts.push_back(ac); return normalVerts; } if(nSides ==4) { Vector2f ab = Vector2f((verts[1].x + pos.x) - (verts[0].x + pos.x), (verts[1].y + pos.y) - (verts[0].y + pos.y)); ab = flip(ab); ab.x *= -1; normalVerts.push_back(ab); Vector2f bc = Vector2f((verts[2].x + pos.x) - (verts[1].x + pos.x), (verts[2].y + pos.y) - (verts[1].y + pos.y)); bc = flip(bc); bc.x *= -1; normalVerts.push_back(bc); return normalVerts; } } Vector2f BouncingThing::flip(Vector2f v){ float vyTemp = v.x; float vxTemp = v.y * -1; return Vector2f(vxTemp, vyTemp); } (Ignore this line) CollisionDetection::CollisionDetection() { } vector<float> CollisionDetection::bubbleSort(vector<float> w) { int temp; bool finished = false; while (!finished) { finished = true; for (int i = 0; i < w.size()-1; i++) { if (w[i] > w[i+1]) { temp = w[i]; w[i] = w[i+1]; w[i+1] = temp; finished=false; } } } return w; } class Vector{ public: //static int dp_count; static float dot(sf::Vector2f a,sf::Vector2f b){ //dp_count++; return a.x*b.x+a.y*b.y; } static float length(sf::Vector2f a){ return sqrt(a.x*a.x+a.y*a.y); } static Vector2f add(Vector2f a, Vector2f b) { return Vector2f(a.x + b.y, a.y + b.y); } static sf::Vector2f getNormal(sf::Vector2f a,sf::Vector2f b){ sf::Vector2f n; n=a-b; n/=Vector::length(n);//normalise float x=n.x; n.x=n.y; n.y=-x; return n; } }; bool CollisionDetection::CheckCollision(BouncingThing & x, BouncingThing & y) { vector<Vector2f> xVerts = x.getVerts(); vector<Vector2f> yVerts = y.getVerts(); vector<Vector2f> xNormals = x.getNormals(); vector<Vector2f> yNormals = y.getNormals(); int size; vector<float> xRange; vector<float> yRange; for(int j = 0; j < xNormals.size(); j++) { Vector p; for(int i = 0; i < xVerts.size(); i++) { xRange.push_back(p.dot(xNormals[j], Vector2f(xVerts[i].x, xVerts[i].x))); } for(int i = 0; i < yVerts.size(); i++) { yRange.push_back(p.dot(xNormals[j], Vector2f(yVerts[i].x , yVerts[i].y))); } yRange = bubbleSort(yRange); xRange = bubbleSort(xRange); if(xRange[xRange.size() - 1] < yRange[0] || yRange[yRange.size() - 1] < xRange[0]) { return false; } float x3 = Min(xRange[0], yRange[0]); float y3 = Max(xRange[xRange.size() - 1], yRange[yRange.size() - 1]); float length = Max(x3, y3) - Min(x3, y3); } for(int j = 0; j < yNormals.size(); j++) { Vector p; for(int i = 0; i < xVerts.size(); i++) { xRange.push_back(p.dot(yNormals[j], xVerts[i])); } for(int i = 0; i < yVerts.size(); i++) { yRange.push_back(p.dot(yNormals[j], yVerts[i])); } yRange = bubbleSort(yRange); xRange = bubbleSort(xRange); if(xRange[xRange.size() - 1] < yRange[0] || yRange[yRange.size() - 1] < xRange[0]) { return false; } } return true; } float CollisionDetection::Min(float min, float max) { if(max < min) { min = max; } else return min; } float CollisionDetection::Max(float min, float max) { if(min > max) { max = min; } else return min; } On the screen the objects will freeze for a small amount of time before moving off again. However the problem is is that when this happens there are no collisions actually happening and I would really love to find out where the flaw is in the code. If you need any more information/code please don't hesitate to ask and I'll reply as soon as possible Regards, AzKai

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  • PHP/GD - Cropping and Resizing Images

    - by Alix Axel
    I've coded a function that crops an image to a given aspect ratio and finally then resizes it and outputs it as JPG: <?php function Image($image, $crop = null, $size = null) { $image = ImageCreateFromString(file_get_contents($image)); if (is_resource($image) === true) { $x = 0; $y = 0; $width = imagesx($image); $height = imagesy($image); /* CROP (Aspect Ratio) Section */ if (is_null($crop) === true) { $crop = array($width, $height); } else { $crop = array_filter(explode(':', $crop)); if (empty($crop) === true) { $crop = array($width, $height); } else { if ((empty($crop[0]) === true) || (is_numeric($crop[0]) === false)) { $crop[0] = $crop[1]; } else if ((empty($crop[1]) === true) || (is_numeric($crop[1]) === false)) { $crop[1] = $crop[0]; } } $ratio = array ( 0 => $width / $height, 1 => $crop[0] / $crop[1], ); if ($ratio[0] > $ratio[1]) { $width = $height * $ratio[1]; $x = (imagesx($image) - $width) / 2; } else if ($ratio[0] < $ratio[1]) { $height = $width / $ratio[1]; $y = (imagesy($image) - $height) / 2; } /* How can I skip (join) this operation with the one in the Resize Section? */ $result = ImageCreateTrueColor($width, $height); if (is_resource($result) === true) { ImageSaveAlpha($result, true); ImageAlphaBlending($result, false); ImageFill($result, 0, 0, ImageColorAllocateAlpha($result, 255, 255, 255, 127)); ImageCopyResampled($result, $image, 0, 0, $x, $y, $width, $height, $width, $height); $image = $result; } } /* Resize Section */ if (is_null($size) === true) { $size = array(imagesx($image), imagesy($image)); } else { $size = array_filter(explode('x', $size)); if (empty($size) === true) { $size = array(imagesx($image), imagesy($image)); } else { if ((empty($size[0]) === true) || (is_numeric($size[0]) === false)) { $size[0] = round($size[1] * imagesx($image) / imagesy($image)); } else if ((empty($size[1]) === true) || (is_numeric($size[1]) === false)) { $size[1] = round($size[0] * imagesy($image) / imagesx($image)); } } } $result = ImageCreateTrueColor($size[0], $size[1]); if (is_resource($result) === true) { ImageSaveAlpha($result, true); ImageAlphaBlending($result, true); ImageFill($result, 0, 0, ImageColorAllocate($result, 255, 255, 255)); ImageCopyResampled($result, $image, 0, 0, 0, 0, $size[0], $size[1], imagesx($image), imagesy($image)); header('Content-Type: image/jpeg'); ImageInterlace($result, true); ImageJPEG($result, null, 90); } } return false; } ?> The function works as expected but I'm creating a non-required GD image resource, how can I fix it? I've tried joining both calls but I must be doing some miscalculations. <?php /* Usage Examples */ Image('http://upload.wikimedia.org/wikipedia/commons/4/47/PNG_transparency_demonstration_1.png', '1:1', '600x'); Image('http://upload.wikimedia.org/wikipedia/commons/4/47/PNG_transparency_demonstration_1.png', '2:1', '600x'); Image('http://upload.wikimedia.org/wikipedia/commons/4/47/PNG_transparency_demonstration_1.png', '2:', '250x300'); ?> Any help is greatly appreciated, thanks.

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  • TSQL Shred XML - Is this right or is there a better way (newbie @ shredding XML)

    - by drachenstern
    Ok, I'm a C# ASP.NET dev following orders: The orders are to take a given dataset, shred the XML and return columns. I've argued that it's easier to do the shredding on the ASP.NET side where we already have access to things like deserializers, etc, and the entire complex of known types, but no, the boss says "shred it on the server, return a dataset, bind the dataset to the columns of the gridview" so for now, I'm doing what I was told. This is all to head off the folks who will come along and say "bad requirements". Task at hand: Here's my code that works and does what I want it to: DECLARE @table1 AS TABLE ( ProductID VARCHAR(10) , Name VARCHAR(20) , Color VARCHAR(20) , UserEntered VARCHAR(20) , XmlField XML ) INSERT INTO @table1 SELECT '12345','ball','red','john','<sizes><size name="medium"><price>10</price></size><size name="large"><price>20</price></size></sizes>' INSERT INTO @table1 SELECT '12346','ball','blue','adam','<sizes><size name="medium"><price>12</price></size><size name="large"><price>25</price></size></sizes>' INSERT INTO @table1 SELECT '12347','ring','red','john','<sizes><size name="medium"><price>5</price></size><size name="large"><price>8</price></size></sizes>' INSERT INTO @table1 SELECT '12348','ring','blue','adam','<sizes><size name="medium"><price>8</price></size><size name="large"><price>10</price></size></sizes>' INSERT INTO @table1 SELECT '23456','auto','black','ann','<auto><type>car</type><wheels>4</wheels><doors>4</doors><cylinders>3</cylinders></auto>' INSERT INTO @table1 SELECT '23457','auto','black','ann','<auto><type>truck</type><wheels>4</wheels><doors>2</doors><cylinders>8</cylinders></auto><auto><type>car</type><wheels>4</wheels><doors>4</doors><cylinders>6</cylinders></auto>' DECLARE @x XML SELECT @x = ( SELECT ProductID , Name , Color , UserEntered , XmlField.query(' for $vehicle in //auto return <auto type = "{$vehicle/type}" wheels = "{$vehicle/wheels}" doors = "{$vehicle/doors}" cylinders = "{$vehicle/cylinders}" />') FROM @table1 table1 WHERE Name = 'auto' FOR XML AUTO ) SELECT @x SELECT ProductID = T.Item.value('../@ProductID', 'varchar(10)') , Name = T.Item.value('../@Name', 'varchar(20)') , Color = T.Item.value('../@Color', 'varchar(20)') , UserEntered = T.Item.value('../@UserEntered', 'varchar(20)') , VType = T.Item.value('@type' , 'varchar(10)') , Wheels = T.Item.value('@wheels', 'varchar(2)') , Doors = T.Item.value('@doors', 'varchar(2)') , Cylinders = T.Item.value('@cylinders', 'varchar(2)') FROM @x.nodes('//table1/auto') AS T(Item) SELECT @x = ( SELECT ProductID , Name , Color , UserEntered , XmlField.query(' for $object in //sizes/size return <size name = "{$object/@name}" price = "{$object/price}" />') FROM @table1 table1 WHERE Name IN ('ring', 'ball') FOR XML AUTO ) SELECT @x SELECT ProductID = T.Item.value('../@ProductID', 'varchar(10)') , Name = T.Item.value('../@Name', 'varchar(20)') , Color = T.Item.value('../@Color', 'varchar(20)') , UserEntered = T.Item.value('../@UserEntered', 'varchar(20)') , SubName = T.Item.value('@name' , 'varchar(10)') , Price = T.Item.value('@price', 'varchar(2)') FROM @x.nodes('//table1/size') AS T(Item) So for now, I'm trying to figure out if there's a better way to write the code than what I'm doing now... (I have a part 2 I'm about to go key in)

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  • What is the fastest way to Initialize a multi-dimensional array to non-default values in .NET?

    - by AMissico
    How do I initialize a multi-dimensional array of a primitive type as fast as possible? I am stuck with using multi-dimensional arrays. My problem is performance. The following routine initializes a 100x100 array in approx. 500 ticks. Removing the int.MaxValue initialization results in approx. 180 ticks just for the looping. Approximately 100 ticks to create the array without looping and without initializing to int.MaxValue. Routines similiar to this are called a few hundred-thousand to several million times during a "run". The array size will not change during a run and arrays are created one-at-a-time, used, then discarded, and a new array created. A "run" which may last from one minute (using 10x10 arrays) to forty-five minutes (100x100). The application creates arrays of int, bool, and struct. There can be multiple "runs" executing at same time, but are not because performance degrades terribly. I am using 100x100 as a base-line. I am open to suggestions on how to optimize this non-default initialization of an array. One idea I had is to use a smaller primitive type when available. For instance, using byte instead of int, saves 100 ticks. I would be happy with this, but I am hoping that I don't have to change the primitive data type. public int[,] CreateArray(Size size) { int[,] array = new int[size.Width, size.Height]; for (int x = 0; x < size.Width; x++) { for (int y = 0; y < size.Height; y++) { array[x, y] = int.MaxValue; } } return array; } Down to 450 ticks with the following: public int[,] CreateArray1(Size size) { int iX = size.Width; int iY = size.Height; int[,] array = new int[iX, iY]; for (int x = 0; x < iX; x++) { for (int y = 0; y < iY; y++) { array[x, y] = int.MaxValue; } } return array; } Down to approximately 165 ticks after a one-time initialization of 2800 ticks. (See my answer below.) If I can get stackalloc to work with multi-dimensional arrays, I should be able to get the same performance without having to intialize the private static array. private static bool _arrayInitialized5; private static int[,] _array5; public static int[,] CreateArray5(Size size) { if (!_arrayInitialized5) { int iX = size.Width; int iY = size.Height; _array5 = new int[iX, iY]; for (int x = 0; x < iX; x++) { for (int y = 0; y < iY; y++) { _array5[x, y] = int.MaxValue; } } _arrayInitialized5 = true; } return (int[,])_array5.Clone(); } Down to approximately 165 ticks without using the "clone technique" above. (See my answer below.) I am sure I can get the ticks lower, if I can just figure out the return of CreateArray9. public unsafe static int[,] CreateArray8(Size size) { int iX = size.Width; int iY = size.Height; int[,] array = new int[iX, iY]; fixed (int* pfixed = array) { int count = array.Length; for (int* p = pfixed; count-- > 0; p++) *p = int.MaxValue; } return array; }

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  • How to store generated eigen faces for future face recognition?

    - by user3237134
    My code works in the following manner: 1.First, it obtains several images from the training set 2.After loading these images, we find the normalized faces,mean face and perform several calculation. 3.Next, we ask for the name of an image we want to recognize 4.We then project the input image into the eigenspace, and based on the difference from the eigenfaces we make a decision. 5.Depending on eigen weight vector for each input image we make clusters using kmeans command. Source code i tried: clear all close all clc % number of images on your training set. M=1200; %Chosen std and mean. %It can be any number that it is close to the std and mean of most of the images. um=60; ustd=32; %read and show images(bmp); S=[]; %img matrix for i=1:M str=strcat(int2str(i),'.jpg'); %concatenates two strings that form the name of the image eval('img=imread(str);'); [irow icol d]=size(img); % get the number of rows (N1) and columns (N2) temp=reshape(permute(img,[2,1,3]),[irow*icol,d]); %creates a (N1*N2)x1 matrix S=[S temp]; %X is a N1*N2xM matrix after finishing the sequence %this is our S end %Here we change the mean and std of all images. We normalize all images. %This is done to reduce the error due to lighting conditions. for i=1:size(S,2) temp=double(S(:,i)); m=mean(temp); st=std(temp); S(:,i)=(temp-m)*ustd/st+um; end %show normalized images for i=1:M str=strcat(int2str(i),'.jpg'); img=reshape(S(:,i),icol,irow); img=img'; end %mean image; m=mean(S,2); %obtains the mean of each row instead of each column tmimg=uint8(m); %converts to unsigned 8-bit integer. Values range from 0 to 255 img=reshape(tmimg,icol,irow); %takes the N1*N2x1 vector and creates a N2xN1 matrix img=img'; %creates a N1xN2 matrix by transposing the image. % Change image for manipulation dbx=[]; % A matrix for i=1:M temp=double(S(:,i)); dbx=[dbx temp]; end %Covariance matrix C=A'A, L=AA' A=dbx'; L=A*A'; % vv are the eigenvector for L % dd are the eigenvalue for both L=dbx'*dbx and C=dbx*dbx'; [vv dd]=eig(L); % Sort and eliminate those whose eigenvalue is zero v=[]; d=[]; for i=1:size(vv,2) if(dd(i,i)>1e-4) v=[v vv(:,i)]; d=[d dd(i,i)]; end end %sort, will return an ascending sequence [B index]=sort(d); ind=zeros(size(index)); dtemp=zeros(size(index)); vtemp=zeros(size(v)); len=length(index); for i=1:len dtemp(i)=B(len+1-i); ind(i)=len+1-index(i); vtemp(:,ind(i))=v(:,i); end d=dtemp; v=vtemp; %Normalization of eigenvectors for i=1:size(v,2) %access each column kk=v(:,i); temp=sqrt(sum(kk.^2)); v(:,i)=v(:,i)./temp; end %Eigenvectors of C matrix u=[]; for i=1:size(v,2) temp=sqrt(d(i)); u=[u (dbx*v(:,i))./temp]; end %Normalization of eigenvectors for i=1:size(u,2) kk=u(:,i); temp=sqrt(sum(kk.^2)); u(:,i)=u(:,i)./temp; end % show eigenfaces; for i=1:size(u,2) img=reshape(u(:,i),icol,irow); img=img'; img=histeq(img,255); end % Find the weight of each face in the training set. omega = []; for h=1:size(dbx,2) WW=[]; for i=1:size(u,2) t = u(:,i)'; WeightOfImage = dot(t,dbx(:,h)'); WW = [WW; WeightOfImage]; end omega = [omega WW]; end % Acquire new image % Note: the input image must have a bmp or jpg extension. % It should have the same size as the ones in your training set. % It should be placed on your desktop ed_min=[]; srcFiles = dir('G:\newdatabase\*.jpg'); % the folder in which ur images exists for b = 1 : length(srcFiles) filename = strcat('G:\newdatabase\',srcFiles(b).name); Imgdata = imread(filename); InputImage=Imgdata; InImage=reshape(permute((double(InputImage)),[2,1,3]),[irow*icol,1]); temp=InImage; me=mean(temp); st=std(temp); temp=(temp-me)*ustd/st+um; NormImage = temp; Difference = temp-m; p = []; aa=size(u,2); for i = 1:aa pare = dot(NormImage,u(:,i)); p = [p; pare]; end InImWeight = []; for i=1:size(u,2) t = u(:,i)'; WeightOfInputImage = dot(t,Difference'); InImWeight = [InImWeight; WeightOfInputImage]; end noe=numel(InImWeight); % Find Euclidean distance e=[]; for i=1:size(omega,2) q = omega(:,i); DiffWeight = InImWeight-q; mag = norm(DiffWeight); e = [e mag]; end ed_min=[ed_min MinimumValue]; theta=6.0e+03; %disp(e) z(b,:)=InImWeight; end IDX = kmeans(z,5); clustercount=accumarray(IDX, ones(size(IDX))); disp(clustercount); QUESTIONS: 1.It is working fine for M=50(i.e Training set contains 50 images) but not for M=1200(i.e Training set contains 1200 images).It is not showing any error.There is no output.I waited for 10 min still there is no output. I think it is going infinite loop.What is the problem?Where i was wrong? 2.Instead of running the training set everytime how eigen faces generated are stored so that stored eigen faces are used for future face recoginition for a new input image.So it reduces wastage of time.

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  • Vectorization of matlab code for faster execution

    - by user3237134
    My code works in the following manner: 1.First, it obtains several images from the training set 2.After loading these images, we find the normalized faces,mean face and perform several calculation. 3.Next, we ask for the name of an image we want to recognize 4.We then project the input image into the eigenspace, and based on the difference from the eigenfaces we make a decision. 5.Depending on eigen weight vector for each input image we make clusters using kmeans command. Source code i tried: clear all close all clc % number of images on your training set. M=1200; %Chosen std and mean. %It can be any number that it is close to the std and mean of most of the images. um=60; ustd=32; %read and show images(bmp); S=[]; %img matrix for i=1:M str=strcat(int2str(i),'.jpg'); %concatenates two strings that form the name of the image eval('img=imread(str);'); [irow icol d]=size(img); % get the number of rows (N1) and columns (N2) temp=reshape(permute(img,[2,1,3]),[irow*icol,d]); %creates a (N1*N2)x1 matrix S=[S temp]; %X is a N1*N2xM matrix after finishing the sequence %this is our S end %Here we change the mean and std of all images. We normalize all images. %This is done to reduce the error due to lighting conditions. for i=1:size(S,2) temp=double(S(:,i)); m=mean(temp); st=std(temp); S(:,i)=(temp-m)*ustd/st+um; end %show normalized images for i=1:M str=strcat(int2str(i),'.jpg'); img=reshape(S(:,i),icol,irow); img=img'; end %mean image; m=mean(S,2); %obtains the mean of each row instead of each column tmimg=uint8(m); %converts to unsigned 8-bit integer. Values range from 0 to 255 img=reshape(tmimg,icol,irow); %takes the N1*N2x1 vector and creates a N2xN1 matrix img=img'; %creates a N1xN2 matrix by transposing the image. % Change image for manipulation dbx=[]; % A matrix for i=1:M temp=double(S(:,i)); dbx=[dbx temp]; end %Covariance matrix C=A'A, L=AA' A=dbx'; L=A*A'; % vv are the eigenvector for L % dd are the eigenvalue for both L=dbx'*dbx and C=dbx*dbx'; [vv dd]=eig(L); % Sort and eliminate those whose eigenvalue is zero v=[]; d=[]; for i=1:size(vv,2) if(dd(i,i)>1e-4) v=[v vv(:,i)]; d=[d dd(i,i)]; end end %sort, will return an ascending sequence [B index]=sort(d); ind=zeros(size(index)); dtemp=zeros(size(index)); vtemp=zeros(size(v)); len=length(index); for i=1:len dtemp(i)=B(len+1-i); ind(i)=len+1-index(i); vtemp(:,ind(i))=v(:,i); end d=dtemp; v=vtemp; %Normalization of eigenvectors for i=1:size(v,2) %access each column kk=v(:,i); temp=sqrt(sum(kk.^2)); v(:,i)=v(:,i)./temp; end %Eigenvectors of C matrix u=[]; for i=1:size(v,2) temp=sqrt(d(i)); u=[u (dbx*v(:,i))./temp]; end %Normalization of eigenvectors for i=1:size(u,2) kk=u(:,i); temp=sqrt(sum(kk.^2)); u(:,i)=u(:,i)./temp; end % show eigenfaces; for i=1:size(u,2) img=reshape(u(:,i),icol,irow); img=img'; img=histeq(img,255); end % Find the weight of each face in the training set. omega = []; for h=1:size(dbx,2) WW=[]; for i=1:size(u,2) t = u(:,i)'; WeightOfImage = dot(t,dbx(:,h)'); WW = [WW; WeightOfImage]; end omega = [omega WW]; end % Acquire new image % Note: the input image must have a bmp or jpg extension. % It should have the same size as the ones in your training set. % It should be placed on your desktop ed_min=[]; srcFiles = dir('G:\newdatabase\*.jpg'); % the folder in which ur images exists for b = 1 : length(srcFiles) filename = strcat('G:\newdatabase\',srcFiles(b).name); Imgdata = imread(filename); InputImage=Imgdata; InImage=reshape(permute((double(InputImage)),[2,1,3]),[irow*icol,1]); temp=InImage; me=mean(temp); st=std(temp); temp=(temp-me)*ustd/st+um; NormImage = temp; Difference = temp-m; p = []; aa=size(u,2); for i = 1:aa pare = dot(NormImage,u(:,i)); p = [p; pare]; end InImWeight = []; for i=1:size(u,2) t = u(:,i)'; WeightOfInputImage = dot(t,Difference'); InImWeight = [InImWeight; WeightOfInputImage]; end noe=numel(InImWeight); % Find Euclidean distance e=[]; for i=1:size(omega,2) q = omega(:,i); DiffWeight = InImWeight-q; mag = norm(DiffWeight); e = [e mag]; end ed_min=[ed_min MinimumValue]; theta=6.0e+03; %disp(e) z(b,:)=InImWeight; end IDX = kmeans(z,5); clustercount=accumarray(IDX, ones(size(IDX))); disp(clustercount); Running time for 50 images:Elapsed time is 103.947573 seconds. QUESTIONS: 1.It is working fine for M=50(i.e Training set contains 50 images) but not for M=1200(i.e Training set contains 1200 images).It is not showing any error.There is no output.I waited for 10 min still there is no output. I think it is going infinite loop.What is the problem?Where i was wrong?

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  • MaxClients in apache. How to know the size of my proccess?

    - by Larry
    From http://httpd.apache.org/docs/2.2/misc/perf-tuning.html The single biggest hardware issue affecting webserver performance is RAM. A webserver should never ever have to swap, as swapping increases the latency of each request beyond a point that users consider "fast enough". This causes users to hit stop and reload, further increasing the load. You can, and should, control the MaxClients setting so that your server does not spawn so many children it starts swapping. This procedure for doing this is simple: determine the size of your average Apache process, by looking at your process list via a tool such as top, and divide this into your total available memory, leaving some room for other processes. The main issue is that I can't understand how to know the size, because, well i have the size of httpd on no more of 3888 But, if we need to determine the number for MaxClients, and I have 4GB of RAM, so I get: 972, so I should use like 900 in the MaxClients?

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  • How to know the root device size of some public AMI?

    - by red23jordan
    Since I do not want to pay money for my testing, the free limit size is 10G. I can know the root device root for some default AMI such as Amazon Linux AMI 2012.03 The Amazon Linux AMI 2012.03 is an EBS-backed, PV-GRUB image. It includes Linux 3.2, AWS tools, and repository access to multiple versions of MySQL, PostgreSQL, Python, Ruby, and Tomcat. Root Device Size: 8 GB And the last row displayed 8GB. However, if I find AMI in Community Page, it does not show the root device size. Can anyone know how to use the instance such as centOS that is not provided by default but it is under 10GB so that I can still free use?

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  • Maximum disk size for a Debian 6 VMware installation?

    - by Mohamed Abobakr
    I'm planning to install a variety of Linux distributions on VMware Player to get more experience with Linux (I've only used Fedora back in university). I'm starting with Debian 6.0.5 Squeeze, and have already downloaded the small CD i386 netinst image. In the new virtual machine wizard, it's asking me for the maximum disk size of the image. It says that the recommended size for Debian 6 is 8 GB. However, I'm trying to figure out what is the absolute minimal size that I can get away with, since I'm only testing it out with very few software installations (mainly testing web server applications).

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  • May the file size returned by stat be compromised?

    - by codeholic
    I want to make sure that nobody changed a file. In order to accomplish that, I want not only to check MD5 sum of the file, but also check its size, since as far as I understand this additional simple check can sophisticate falsification by several digits. May I trust the size that stat returns? I don't mean if changes were made to stat itself. I don't go that deep. But, for instance, may one compromise the file size that stat returns by hacking the directory file? Or by similar means, that do not require superuser privileges? It's Linux.

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  • File property information (last write time and file size) in explorer out of date by hours over netw

    - by David L Morris
    An application is running on a windows XP prof machine picking up file from a network share from another windows machine. It detects that the file has been updated (by date and time or optionally file size) and reads it for any new data. Most of the time the last write time and file size, seems to be up to date. Occasionally, this information stops being updated, even though the file is growing (intermittently during the day) with appended content, so that the last write time and file size remain fixed at some arbitrary moment. This is visible in explorer, where it shows a fixed last write time on the reading machine. Just opening the file to edit it in notepad, immediately refreshes the file properties, and the other application picks up where it left of. The file location can't be changed, nor the location of the relevant applications. Any solutions to resolve this problem?

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