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  • How to process this string via regular expression

    - by iiduce
    my string style like this: expression1/field1+expression2*expression3+expression4/field2*expression5*expression6/field3 a real style mybe like this: computer/(100)+web*mail+explorer/(200)*bbs*solution/(300) "+" and "*" represent operator "computer","web"...represent expression (100),(200) represent field num . field num may not exist. I want process the string to this: /(100)+web*+explorer/(200)bbs/(300) rules like this: if expression length is more than 3 and its field is not (200), then add brackets to it.

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  • How can I execute a bunch of editor commands stored in a file in VIM?

    - by LES2
    I have read the other posts, e.g., http://stackoverflow.com/questions/1830886/vim-executing-a-list-of-editor-commands and others. The answer isn't clear to me for my case. I have some editor commands that I generated from an SQL query. It uses :s/foo/bar to change country codes (from FIPS to a non-standard code set). Here's a sample of the file: :s/CB/CAMBO :s/CQ/NMARI :s/KV/KOSOV :s/PP/PAPUA ... I have saved that in a file called fipsToNonStd.vim (unsure about the correct extension). I want to run those commands one after another. What's the easiest way to do so? Thanks a bunch! SO Rocks!

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  • Reading a line backwards

    - by Jimmy
    Hi, I'm using regular expression to count the total spaces in a line (first occurrence). match(/^\s*/)[0].length; However this reads it from the start to end, How can I read it from end to start. Thanks

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  • Trying to create a Reg Ex for the following patterns

    - by Travis
    Here are the patterns: Red,Green (and so on...) Red (+5.00),Green (+6.00) (and so on...) Red (+5.00,+10.00),Green (+6.00,+20.00) (and so on...) Red (+5.00),Green (and so on...) Each attribute ("Red,"Green") can have 0, 1, or 2 modifiers (shown as "+5.00,+10.00", etc.). I need to capture each of the attributes and their modifiers as a single string (i.e. "Red (+5.00,+10.00)", "Green (+6.00,+20.00)". Help?

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  • Perl Regular expression remove double tabs, line breaks, white spaces

    - by Scoox
    Hi guys, I want to write a perl script that removes double tabs, line breaks and white spaces. What I have so far is: $txt=~s/\r//gs; $txt=~s/ +/ /gs; $txt=~s/\t+/\t/gs; $txt=~s/[\t\n]*\n/\n/gs; $txt=~s/\n+/\n/gs; But, 1. It's not beautiful. Should be possible to do that with far less regexps. 2. It just doesn't work and I really do not know why. It leaves some double tabs, white spaces and empty lines (i.e. lines with only a tab or whitespace) I could solve it with a while, but that is very slow and ugly. Any suggestions?

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  • How do I convert text to hyperlinks in C#?

    - by EmilyM
    I am very very very new to C# and ASP.NET development. What I'd like to do is a find-and-replace for certain words appearing in the body text of a web page. Every time a certain word appears in the body text, I'd like to convert that word into a hyperlink that links to another page on our site. I have no idea where to even start with this. I've found code for doing find-and-replace in C#, but I haven't found any help for just reading through a document, finding certain strings, and changing them into different strings.

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  • Regular Expression to isolate an html tag

    - by orit cohen
    I'm looking for a regular expression to isolate an html tag. This includes the TAG the ATTRIBUTES and the CONTNET inside. Let's say I have this: <html> <body> aajsdfkjaskd <TAGNAME name="bla" context="non">hfdfhdj </TAGNAME> </body> </html> I need a regular expression that would return: <TAGNAME name="bla" context="non">hfdfhdj </TAGNAME> Thank, Joe

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  • Regular Expression .net flavor

    - by user1440109
    Dont ask how this works but currently it does ("^\|(.?)\|*$")....kinda. This removes all extra pipes...part one....I have searched all over no anwser yet. I am using VB2011 beta...asp web form......vb coding though! I want to capture special character pipe (|) which is used to seperate words...i.e. car|truck|van|cycle problem is users lead with, trail with, use multiple, and use spaces before and after...i.e. |||car||truck | van || cycle. another example: george bush|micheal jordon|bill gates|steve jobs <-- this would be correct but when I do remove space it takes correct space out. so I want to get rid of whitespace leading, trailing, any space before | and space after | and only allow one pipe (|)....in between alphanumeric of course.

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  • Regular Expression Sanitize (PHP)

    - by atif089
    Hello, I would like to sanitize a string in to a URL so this is what I basically need. Everything must be removed except alphanumeric characters and spaces and dashed. Spaces should be converter into dashes. Eg. This, is the URL! must return this-is-the-url Thanks

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  • Dealing with regular expressions, Python

    - by Gusto
    I want to remove some symbols from a string using a regular expression, for example: == (that occur both at the beginning and at the end of a line), * (at the beginning of a line ONLY). def some_func(): clean = re.sub(r'= {2,}', '', clean) #Removes 2 or more occurrences of = at the beg and at the end of a line. clean = re.sub(r'^\* {1,}', '', clean) #Removes 1 or more occurrences of * at the beginning of a line. What's wrong with my code? It seems like expressions are wrong. How do I remove a character/symbol if it's at the beginning or at the end of the line (with one or more occurrences)?

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  • sed - trying to replace first occurrence after a match

    - by wakkaluba
    I am facing a situation that drives me nuts. I am setting up an update server which uses a json file. Don't ask why or how, it sucks and is my only possibility to achieve it. I have been trying and researching for HOURS (many) because I went ballistic and wanted to crack this on my own. But I have to realize I got stuck and need help. So sorry for this chunk but I think it is somewhat important to see... The file is a one liner and repeating the following sequence with changing values (of course). "plugin_name_foo_bar": {"buildDate": "bla", "dependencies": [{"name": "bla", "optional": true, "version": "1.00"}], "developers": [{"developerId": "bla", "email": "[email protected]", "name": "Bla bla2nd"}], "excerpt": "some text {excerpt} !bla.png|thumbnail,border=1! ", "gav": "bla", "labels": ["report", "scm-related"], "name": "plugin_name_foo_bar", "previousTimestamp": "bla", "previousVersion": "1.0", "releaseTimestamp": "bla", "requiredCore": "1", "scm": "github.com", "sha1": "ynnBM2jWo25ZLDdP3ybBOnV/Pio=", "title": "bla", "url": "http://bla.org", "version": "1.0", "wiki": "https://bla.org"}, "Exclusion": {"buildDate": "bla", "dependencies": [], and the next plugin block is glued straight afterwards. What I now want to do is to search for "plugin_foo_bar": {" as this is the unique identifier for a new plugin description block. I want to replace the first sha1 value occuring afterwards. That's where I keep failing. I always grab the first,last or any occurrence in the entire file and not the block :( "title" is the unique identifier after the sha1 value. So I tried to make the .* less greedy but it ain't working out. last attempt was heading towards: sed -i 's/("name": "plugin_name_foo_bar.*sha1": ")([a-zA-Z0-9!@#\$%^&*()\[\]]*)(", "title"\)/\1blablabla\2/1' default.json to find the sha1 value of that plugin but still no joy. I hope someone knows - preferably a simpler approach - before I now continue with trial and error until I have to puke and freakout. I am working with SED on Windows, so Unix approach might help me to figure out how to achieve this in batch but please make it as one-liner if possible. Scripts are a real pain to convert. And I just need SED and no other solution with other tools like AWK. That is absolutely out of discussion. Any help is appreciated :) Cheers Jan

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  • Java: calculate linenumber from charwise position according to the number of "\n"

    - by HH
    I know charwise positions of matches like 1 3 7 8. I need to know their corresponding line number. Example: file.txt Match: X Mathes: 1 3 7 8. Want: 1 2 4 4 $ cat file.txt X2 X 4 56XX [Added: does not notice many linewise matches, there is probably easier way to do it with stacks] $ java testt 1 2 4 $ cat testt.java import java.io.*; import java.util.*; public class testt { public static String data ="X2\nX\n4\n56XX"; public static String[] ar = data.split("\n"); public static void main(String[] args){ HashSet<Integer> hs = new HashSet<Integer>(); Integer numb = 1; for(String s : ar){ if(s.contains("X")){ hs.add(numb); numb++; }else{ numb++; } } for (Integer i : hs){ System.out.println(i); } } }

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  • How to find which delimiter was used during string split (VB.NET)

    - by typoknig
    Hi all, lets say I have a string that I want to split based on several characters, like ".", "!", and "?". How do I figure out which one of those characters split my string so I can add that same character back on to the end of the split segments in question? Dim linePunctuation as Integer = 0 Dim myString As String = "some text. with punctuation! in it?" For i = 1 To Len(myString) If Mid$(entireFile, i, 1) = "." Then linePunctuation += 1 Next For i = 1 To Len(myString) If Mid$(entireFile, i, 1) = "!" Then linePunctuation += 1 Next For i = 1 To Len(myString) If Mid$(entireFile, i, 1) = "?" Then linePunctuation += 1 Next Dim delimiters(3) As Char delimiters(0) = "." delimiters(1) = "!" delimiters(2) = "?" currentLineSplit = myString.Split(delimiters) Dim sentenceArray(linePunctuation) As String Dim count As Integer = 0 While linePunctuation > 0 sentenceArray(count) = currentLineSplit(count)'Here I want to add what ever delimiter was used to make the split back onto the string before it is stored in the array.' count += 1 linePunctuation -= 1 End While

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  • Regular Expression for username

    - by neobie
    I need help on regular expression on the condition (4) below: Begin with a-z End with a-z0-9 allow 3 special characters like ._- The characters in (3) must be followed by alphanumeric characters, and it cannot be followed by any characters in (3) themselves. Not sure how to do this. Any help is appreciated, with the sample and some explanations.

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  • validation of special characters

    - by jpallavi
    I want to validate login name with special characters !@#S%^*()+_-?/<:"';. space using regular expression in ruby on rails. These special characters should not be acceptable. What is the code for that? Thanks, Pallavi

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  • Need help parsing HTML with a regex in python

    - by laspal
    Hi, My string is mystring = "<tr><td><span class='para'><b>Total Amount : </b>INR (Indian Rupees) 100.00</span></td></tr>" My problem here is I have to search and get the total amount test = re.search("(Indian Rupees)(\d{2})(?:\D|$)", mystring) but my test give me None. How can I get the values and values can be 10.00, 100.00, 1000.00 Thanks

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  • Regexs in Ruby getting filename

    - by user1290757
    i am extracting file names of html files using line: filename = File.basename(input_filename, ".*") which currently prints full file name excluding .html extension All files are stored in the form of http^x.x.edu^1^2 all file names begin with http^ and contain edu^ what i want is to extract 2 (which changes) but it is always the second element after .edu I have attempted destructive gsub! but i m weak with regular expressions.

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  • replace <br> to new line between pre tag

    - by saturngod
    I want to convert <p>Code is following</p> <pre> &lt;html&gt;<br>&lt;/html&gt; </pre> to <p>Code is following</p> <pre> &lt;html&gt; &lt;/html&gt; </pre> I don't know how to write regular expression for replace between pre tag in PHP. I tried this code http://stackoverflow.com/questions/1517102/replace-newlines-with-br-tags-but-only-inside-pre-tags but it's not working for me.

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  • How Do I grep For non-ASCII Characters in UNIX

    - by Peter Conrey
    I have several very large XML files and I'm trying to find the lines that contain non-ASCII characters. I've tried the following: grep -e "[\x{00FF}-\x{FFFF}]" file.xml But this returns every line in the file, regardless of whether the line contains a character in the range specified. Do I have the syntax wrong or am I doing something else wrong? I've also tried: egrep "[\x{00FF}-\x{FFFF}]" file.xml (with both single and double quotes surrounding the pattern).

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  • regular expression: extract last 2 characters

    - by dotnet-practitioner
    what is the best way to extract last 2 characters of a string using regular expression. For example, I want to extract state code from the following "A_IL" I want to extract IL as string.. please provide me C# code on how to get it.. string fullexpression = "A_IL"; string StateCode = some regular expression code.... thanks

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