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  • How to display a flyout menu on clicking an image in Grid header in MVC?

    - by Vincent
    A grid is displayed using the following code in MVC. <%= this.Grid( "routes-" + mc , "Testing", Model.Routes, new GridBuilder<RouteModel>() .Column( "chk", () => Html.Image( Url.Content( "down.gif" ), "Select or deselect tests" ), (m) => "<input type='hidden' name='routeLinkId' value='"+ m.RouteLinkID +"' />" + Html.CheckBox( "drugRoute" + mc + m.RouteLinkID, m.IsChecked ) ) .Column( "route clip-text", "Route", (m) = Html.Encode( m.Route ) ) .Column( "groups clip-text", "Groups", (m) = "" + Html.Encode(m.Group) + "" ) .ToGrid() ) % On clicking the image in header I need to display a flyout menu. The code for the flyout menu is below. <div id="group-menu-<%= mc %>" class="flyout-menu" title="Select tests"> <div> <p>Select</p> <ul> <li><button type="button" name="one">One</button></li> <li><button type="button" name="two">two</button></li> </ul> <p>Unselect</p> <ul> <li><button type="button" name="unselect-one">one</button></li> <li><button type="button" name="unselect-two">two</button></li> </ul> </div> </div> Now how do I display this menu on clicking the image in header.

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  • AsyncPostBackTrigger disables buttons...

    - by afsharm
    I've a simple UpdatePanel and a button outside of it. I've introduced the button as an AsyncPostBackTrigger in the UpdatePanel. UpdatePanel itself works fine but the button does not. Whenever the button is clicked, its click handler does not run just like the button is not clicked at all! Why the button is not working and how can it be fixed? UPDATE: here is the markup: <asp:UpdatePanel ID="upGridView" runat="server" UpdateMode="Conditional"> <ContentTemplate> <asp:GridView ID="grdList" SkinID="SimpleGridView" DataKeyNames="Key" runat="server" AllowPaging="True" PageSize="15" AutoGenerateColumns="False" Caption="<%$ Resources: CommonResources, grdListCaption %>" EmptyDataText="<%$ Resources: CommonResources, grdListEmptyDataText %>" OnRowEditing="grdList_RowEditing" OnPageIndexChanging="grdList_PageIndexChanging" OnRowCreated="grdList_RowCreated"> <Columns> </Columns> </asp:GridView> </ContentTemplate> <Triggers> <asp:AsyncPostBackTrigger ControlID="btnDelete" EventName="Click" /> <asp:AsyncPostBackTrigger ControlID="btnNew" EventName="Click" /> <asp:AsyncPostBackTrigger ControlID="btnForward" EventName="Click" /> </Triggers> </asp:UpdatePanel> <asp:Button ID="btnDelete" runat="server" SkinID="Button" Text="<%$ Resources: CommonResources, btnDelete %>" OnClick="btnDelete_Click" /> <asp:Button ID="btnNew" runat="server" SkinID="Button" Text="<%$ Resources: CommonResources, btnNew %>" OnClick="btnNew_Click" /> <asp:Button ID="btnForward" runat="server" SkinID="Button" meta:resourcekey="btnForward" OnClick="btnForward_Click" />

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  • How do you align text so it is in the middle of a button in Silverlight?

    - by Roy
    Here is the current code I am using: <UserControl xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" x:Class="ButtonPrototype.MainPage" Width="640" Height="480"> <UserControl.Resources> <ControlTemplate x:Key="CellTemplate" TargetType="Button"> <Grid> <Border x:Name="CellBorderBrush" BorderBrush="Black" BorderThickness="1"> <ContentPresenter Content="{TemplateBinding Content}" HorizontalAlignment="Center" VerticalAlignment="Center"/> </Border> </Grid> </ControlTemplate> <Style x:Key="CellStyle" TargetType="Button"> <Setter Property="Template" Value="{StaticResource CellTemplate}"></Setter> <Setter Property="Foreground" Value="Black"></Setter> <Setter Property="FontSize" Value="80"></Setter> <Setter Property="Width" Value="100"></Setter> <Setter Property="Height" Value="100"></Setter> </Style> </UserControl.Resources> <Grid x:Name="LayoutRoot" Background="White"> <Button Content="A" Style="{StaticResource CellStyle}"></Button> </Grid> </UserControl> The Horizontal aligning works but the verticalalignment doesn't do anything. Thanks for your help.

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  • Android launches system settings instead of my app

    - by jsundin
    Hi, For some reason whenever I (try to) start my app the phone decides to launch system settings instead of my "main activity". And yes, I am referring to the "Android system settings", and not something from my app. This only happens on my phone, and I suppose it probably could be related to the fact that my app had just opened system settings when I decided to re-launch with a new version from Eclipse. It is possible to start the app from within Eclipse, but when I navigate back from the app it returns to the system settings rather than the home screen, as if the settings activity was started first and then my activity. If I then start the app from the phone all I get is system settings yet again. The app is listening to the VIEW-action for a specific URL substring, and when I start the app using a matching URL I get the same result as when I start it from Eclipse, app starts, but when I return I return to settings. I have tried googling for this problem, and all I could find was something about Android saving state when an app gets killed, but without any information on how to reset this state. I have tried uninstalling the app, killing system settings, rebooting the phone, reinstalling, clearing application data.. no luck.. For what it's worth, here's the definition of my main activity from the manifest, <activity android:name=".HomeActivity" android:label="@string/app_name" android:screenOrientation="portrait" android:clearTaskOnLaunch="true" android:launchMode="singleTop"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> <intent-filter> <action android:name="android.intent.action.VIEW"></action> <category android:name="android.intent.category.DEFAULT"></category> <category android:name="android.intent.category.BROWSABLE"></category> <data android:pathPrefix="/isak-web-mobile/smart/" android:scheme="http" android:host="*"></data> </intent-filter> </activity> And here is the logcat-line from when I try to start my app, nothing about any settings anywhere. I/ActivityManager( 1301): Starting activity: Intent { act=android.intent.action.MAIN cat=[android.intent.category.LAUNCHER] flg=0x10200000 cmp=se.opencare.isak/.HomeActivity } When I launch from Eclipse I also get this line (as one would expect), I/ActivityManager( 1301): Start proc se.opencare.isak for activity se.opencare.isak/.HomeActivity: pid=23068 uid=10163 gids={3003, 1007, 1015} If it matters the phone is a HTC Desire Z running 2.2.1. Currently, this is my HomeActivity, public class HomeActivity extends Activity { public static final String TAG = "HomeActivity"; @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { Log.d(TAG, "onActivityResult(" + requestCode + ", " + resultCode + ", " + data + ")"); super.onActivityResult(requestCode, resultCode, data); } @Override protected void onCreate(Bundle savedInstanceState) { Log.d(TAG, "onCreate(" + savedInstanceState + ")"); super.onCreate(savedInstanceState); } @Override protected void onDestroy() { Log.d(TAG, "onDestroy()"); super.onDestroy(); } @Override protected void onPause() { Log.d(TAG, "onPause()"); super.onPause(); } @Override protected void onPostCreate(Bundle savedInstanceState) { Log.d(TAG, "onPostCreate(" + savedInstanceState + ")"); super.onPostCreate(savedInstanceState); } @Override protected void onPostResume() { Log.d(TAG, "onPostResume()"); super.onPostResume(); } @Override protected void onRestart() { Log.d(TAG, "onRestart()"); super.onRestart(); } @Override protected void onRestoreInstanceState(Bundle savedInstanceState) { Log.d(TAG, "onRestoreInstanceState(" + savedInstanceState + ")"); super.onRestoreInstanceState(savedInstanceState); } @Override protected void onResume() { Log.d(TAG, "onResume()"); super.onResume(); } @Override protected void onStart() { Log.d(TAG, "onStart()"); super.onStart(); } @Override protected void onStop() { Log.d(TAG, "onStop()"); super.onStop(); } @Override protected void onUserLeaveHint() { Log.d(TAG, "onUserLeaveHint()"); super.onUserLeaveHint(); } } Nothing (of the above) is written to the log.

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  • Clicking sound on MacBook Pro 13" 2010 model when turning the laptop on it's horizontal axis

    - by roosteronacid
    When I leave my MacBook Pro 13" level for a minute or two (sometimes I only need to keep it level for a few seconds), and then pick it up and turn it on it's horizontal axis, I hear a single click, coming from either the hard drive or the Super Drive. Is the click I am hearing some sort of locking mechanism in the hard drive? Or in the Super Drive?.. And therefore nothing to worry about. Or is either my Super Drive or hard drive faulty?

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  • Setting WPF control background image using styles?

    - by aviv
    Hi, I have a set of buttons inside a stack panel. I want them all to have a background image. How can i do it using styles? since i don't want to set manually the Background image for each button. Here is a code snippet: <StackPanel Orientation="Horizontal" Height="100px" VerticalAlignment="Top"> <StackPanel.Resources> <Style TargetType="Button"> <Setter Property="Margin" Value="2,4" /> </Style> </StackPanel.Resources> <Button Width="127px" Height="79px" VerticalAlignment="Bottom"> <Button.Background> <ImageBrush ImageSource="images/Tab.png" /> </Button.Background> </Button> <Button>A</Button> <Button>R</Button> <Button>S</Button> </StackPanel> Thanks.

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  • How can I change the back button function in navigation toolbar?

    - by jackrobert
    I have developed a simple web application using JSP. It has a login page which contains username, password fields and sumbit button. It has a logout page which contains a link to the login page. And there are some pages like page1, page2, page3, page4, etc. Normal workflow is the following: After login comes page1. Then click some action and it will go to page2. Then click some action and it will go to page3. Then click some action and it will go to page4. So now I am in page4. Now click back button in navigation toolbar in browser, generally go to previous page (page3). But my requirement is, if you click back button in navigation toolbar from any page in the application, then you should go to logout page. For example: if you are in page4 and press the back button, then you should go to logout page and not to page3. How to achieve this? Is it anyway possible? Maybe with Javascript?

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  • Detect how many times the users have click the button...

    - by Jerry
    Hello guys. Just want to know if there is a way to detect how many times a user has clicked a button by using Jquery. My main application has a button that can add input fields depend on the users. He/She can adds as many input fields as they need. When they submit the form, The add page will add the data to my database. My current idea is to create a hidden input field and set the value to zero. Every time a user clicks the button, jquery would update the attribute of the hidden input field value. Then the "add page" can detect the loop time. See the example below. I just want to know if there are better practices to do this. Thanks for the helps. main page <form method='post' action='add.php'> //omit <input type="hidden" id="add" name="add" value="0"/> <input type="button" id="addMatch" value="Add a match"/> //omit </form> jquery $(document).ready(function(){ var a =0; $("#addMatch").live('click', function(){ $('#table').append("<input name='match"+a+"Name' />") //the input field will append //as many as the user wants. a++; $('#add').attr('value', 'a'); //pass the a value to hidden input field return false; }); Add Page $a=$_POST['a']; // for($k=0;$k<$a;$k++){ //get all matchName input field $matchName=$_POST['match'.$k.'Name']; //insert the match $updateQuery=mysql_query("INSERT INTO game (team) values('$matchName')",$connection); if(!$updateQuery){ DIE('mysql Error:'+mysql_error()); }

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  • how to link a java class to a image button in eclipse?

    - by Isabella Chan
    I am trying to create a application that includes a Imagebutton and by clicking on the imagebutton, the application will start to run another java class that is within the package itself. I try using this method, however the program stopped working immediately? how should i code the codes instead? can anyone help me? Thanks :D package com.fyp.gulliver; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.widget.Button; public class GulliverActivity extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); //---Map button--- Button btnMap = (Button) findViewById(R.id.map); btnMap.setOnClickListener(new View.OnClickListener() { Class ourClass; public void onClick(View v) { // TODO Auto-generated method stub try { ourClass = Class.forName ("com.fyp.gulliver.Maps"); Intent ourIntent = new Intent(GulliverActivity.this, ourClass); startActivity(ourIntent); } catch (ClassNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } } }); } }

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  • Java Package - To create a button and import one when needed.

    - by Zopyrus
    This is more like a package/import test. We'll start with my base folder at .../javaf/test.java My goal is to create subcategory and create a class with a button that I can import to test.java when I need a button. I feel like I've done it right, I know that the button doesn't do anything as of now, but I just want to make the whole thing work and expand the code thereafter. So here goes - This is test.java import paket.*; // importing classes from subcategory paket! import javax.swing.*; import java.awt.*; import java.awt.event.*; import java.util.*; public class test { public test() { JFrame myFrame; JPanel myPanel; myFrame = new JFrame("Hello FramWorld"); myPanel = new JPanel(); // Here I want to add the object created in paket/myButts.java // The problem is how to make these two lines work. myButts myButton = new myButts(); myPanel.add(myButton); myFrame.setVisible(true); myFrame.getContentPane().add(myPanel, BorderLayout.CENTER); myFrame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); myFrame.pack(); } public static void main(String args[]) { new test(); } } And here is my .../javaf/paket/myButts.java package paket; // Here is the package function (ought to work like a link) import javax.swing.*; import java.awt.*; import java.awt.event.*; // This class should only create a button. public class myButts { public myButts() { JButton myButt = new JButton(); } } I've compiled myButts.java with no errors. But then I compile test.java and it gives me the following error: test.java:19: cannot find symbol symbol : method add(paket.myButts) location: class javax.swing.JPanel myPanel.add(myButton); Thanks for reading, Z

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  • Emacs and windows manager keyboard shortcuts without Win key

    - by Little Bobby Tables
    I found a classic M-Series keyboard and I want to use it. However, it does not have the "Windows" key (a.k.a "Super"), only the Shift, Control and Alt modifiers. My keyboard shortcuts are cluttered as-is, since that I try to control both Emacs and the windows manager (Gnome) only from the keyboard. I rely on the "Super" key to identify the windows manager shortcuts. What it the best practice for keyboard-centric work without the "Super" key?

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  • How to detect how many time the users have click the button...

    - by Jerry
    Hello guys. Just want to know if there is a way to detect how many times a user has clicked a button by using Jquery. My main application has a button that can add input fields depend on the users. He/She can adds as many input fields as they need. When they submit the form, The add page will add the data to my database. My current idea is to create a hidden input field and set the value to zero. Every time a user clicks the button, jquery would update the attribute of the hidden input field value. Then the "add page" can detect the loop time. See the example below. I just want to know if there are better practices to do this. Thanks for the helps. main page <form method='post' action='add.php'> //omit <input type="hidden" id="add" name="add" value="0"/> <input type="button" id="addMatch" value="Add a match"/> //omit </form> jquery $(document).ready(function(){ var a =0; $("#addMatch").live('click', function(){ $('#table').append("<input name='match"+a+"Name' />") //the input field will append //as many as the user wants. a++; $('#add').attr('name', 'a'); //pass the a value to hidden input field return false; }); Add Page $a=$_POST['a']; // for($k=0;$k<$a;$k++){ //get all matchName input field $matchName=$_POST['match'.$k.'Name']; //insert the match $updateQuery=mysql_query("INSERT INTO game (team) values('$matchName')",$connection); if(!$updateQuery){ DIE('mysql Error:'+mysql_error()); }

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  • Synergy: Cannot send media keys from Linux to Mac

    - by CraftyThumber
    I have a Linux Synergy server (Si-Linux) serving just one Mac client (Macbook Pro UK) (SiBook-Pro.local). On my Linux server I am using a USB Apple keyboard with the exact layout of the laptops keyboard (the compact UK aluminium keyboard). I would like to send the media keys to the Mac client at all times and I have attempted the following in my synergy.conf: keystroke(AudioPlay) = keystroke(AudioPlay,SiBook-Pro.local) This did not seem to work so I ran both the server and client as foreground processes and with debugging enabled and observed the following: Server Log: DEBUG1: activate actions DEBUG1: hotkey: keyDown(AudioPlay,SiBook-Pro.local) DEBUG1: onKeyDown id=57523 mask=0x0000 button=0x0000 DEBUG1: send key down to "SiBook-Pro.local" id=57523, mask=0x0000, button=0x0000 DEBUG1: deactivate actions DEBUG1: hotkey: keyUp(AudioPlay,SiBook-Pro.local) DEBUG1: onKeyUp id=57523 mask=0x0000 button=0x0000 DEBUG1: send key up to "SiBook-Pro.local" id=57523, mask=0x0000, button=0x0000 Client Log: DEBUG1: recv key down id=0x0000e0b3, mask=0x0000, button=0x0000 DEBUG1: mapKey e0b3 (57523) with mask 0000, start state: 0000 DEBUG1: key e0b3 is not on keyboard DEBUG1: recv key up id=0x0000e0b3, mask=0x0000, button=0x0000 DEBUG1: recv enter, 1279,386 5 2000 As you can see, the client claims the key received is not on keyboard. I don't understand since it is the same key as is on the Macbook's keyboard. I tried to reverse the client-server config to see if I could capture the key being sent if I pressed the Play button on the Macbook but the key doesn't seem to even make it to Synergy. Almost all keyboard presses get logged but the media keys seem to bypass the logs and just execute their function locally. E.g. I press play on the Macbook (with the Macbook as the server) and the key plays music on the Macbook and the key is not logged to the debug log.

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  • Flash - Http service bound to a button can be used only once ?

    - by SAKIROGLU Koray
    I have a flex project, in one of the screen of my UI, I create a HTTP service that call a "doGet" J2EE servlet through the GET method; and I bind the service call to a button. The service print log to system.out so I know when it is run. The problem I have is, when I click said button the first time, the servlets do what it is supposed to do, and print the stack to system.out, but if I click another time, nothing happens. Any idea what might be the cause ? Here's the flex code (code and service has been generated by Eclipse flex plugin) <mx:Script> <![CDATA[ protected function button_clickHandler(event:MouseEvent):void { LaunchSimulResult.token = simulation.LaunchSimul(); } ]]> </mx:Script> <mx:Canvas> ... <mx:Button label="Simulation" id="button" click="button_clickHandler(event)"/> .. </mx:Canvas> <mx:CallResponder id="LaunchSimulResult"/> <simulation:Simulation id="simulation" fault="Alert.show(event.fault.faultString + '\n' + event.fault.faultDetail)" showBusyCursor="true"/>

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  • Where do I control the behavior of the "X" close button in the upper right of a winform?

    - by John at CashCommons
    I'm venturing into making my VB.NET application a little better to use by making some of the forms modeless. I think I've figured out how to use dlg.Show() and dlg.Hide() instead of calling dlg.ShowDialog(). I have an instance of my modeless dialog in my main application form: Public theModelessDialog As New dlgModeless To fire up the modeless dialog I call theModelessDialog.Show() and within the OK and Cancel button handlers in dlgModeless I have Private Sub OK_Button_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles OK_Button.Click Me.DialogResult = System.Windows.Forms.DialogResult.OK Me.Hide() End Sub Private Sub Cancel_Button_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Cancel_Button.Click Me.DialogResult = System.Windows.Forms.DialogResult.Cancel Me.Hide() End Sub and that seems to work fine. The "X" button in the upper right is getting me, though. When I close the form with that button, then try to reopen the form, I get ObjectDisposedException was unhandled. Cannot access a disposed object. I feel like I'm most of the way there but I can't figure out how to do either of the following: Hide that "X" button Catch the event so I don't dispose of the object (just treat it like I hit Cancel) Any ideas? The class of this dialog is System.Windows.Forms.Form. Thanks as always!

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  • How can I merge a Gmail account and OpenID account with Superuser?

    - by user61116
    I have recently created an account with Super User with a Gmail account Now that I'm trying to login in only find the OpenID login and when i login with my OpenID it seems Super User doesn't recognize it with my Gmail account The result is I have 2 accounts now an old one(Gmail) with reputation and a new one without (OpenID) When I First Signup I did it with Windows 7 now I'm working with Ubuntu 10.10 So my question is: How can i merge my previously superuser Gmail account and my OpenID account with Super User?

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  • How to trigger the specific controller action using a button?

    - by Eugene
    I'm creating a simple training project. I've implemented a controller method, which deletes an item from the list. The method is looking like this: @Controller @RequestMapping(value = "/topic") public class TopicController { @Autowired private TopicService service; ... @RequestMapping(value = "/deleteComment/{commentId}", method = RequestMethod.POST) public String deleteComment(@PathVariable int commentId, BindingResult result, Model model){ Comment deletedComment = commentService.findCommentByID(commentId); if (deletedComment != null) { commentService.deleteComment(deletedComment); } return "refresh:"; } } This method is called from the button-tag, which is looking in the following way: _form> _button formaction = "../deleteComment/1" formmethod = "post">delete_/button> _/form> Sorry, but in the form tag I've changed all the '<' characters with the '_', because the tag was invisible. In my project the form-tag is looking like a cliuckable button. But there is a serious problem: controller's method is never triggered. How can I trigger it, using a button-tag? P.S. the call is performed from the page with URI http://localhost:8080/simpleblog/topic/details/2 and controller's URI is the http://localhost:8080/simpleblog/topic/deleteComment/2

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  • How to avoid the refetch of records when paging button is clicked on the radgrid.

    - by Pravin
    Iam using the radgrid, in my web application. Iwant to avoid the refetch of records when paging button is clicked on the radgrid. I have a method SetTodaysAlerts which gets near about 100 records and binds to my radgrid. The page size of the radgrid is 10, hence First, Next, Previous and Last buttons are available. When I click the next button how can I avoid the re fetching of the records again. FYI: Iam using the radgrid_NeedDataSource event which does the datafetch again when any navigatin button is clicked on the radgrid.

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  • jQuery UI modal dialog box and the close button upper right: how to remove it.

    - by tahdhaze09
    I need to kill the close 'x' button at the top of the dialog box. I have a modal that opens with an OK button that redirects to the site. The site behind the modal is in an iframe. When the user agrees to the statement in the dialog box and clicks the 'OK' button, it redirects to the site that is outside the iframe. If the user clicks on the 'x', it goes to the iframe site, which I do not want to have happen. I need the modal to work as a one-way to the site it goes to. It basically forces the user to accept the user agreement. I would post code, but its an intranet site. Thanks everyone for your help!

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  • how to stop generating code on a particular button?

    - by coure06
    I am trying to create an input button for my own use in my web-application thats using jquery framework. But when I see the html code in browser, the framework is generating some wrapper code around that input, how to prevent that code to be not generated? my code: <input type="button" value="off" class="toggle-btn" id="toggle-btn1" /> Generated output: <div data-theme="c" class="ui-btn ui-btn-corner-all ui-shadow ui-btn-up-c"> <span class="ui-btn-inner ui-btn-corner-all"> <span class="ui-btn-text">off</span> </span> <input type="button" id="toggle-btn1" class="toggle-btn ui-btn-hidden" value="off"> </div>

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  • MVVM/WPF: Button is not disabled although the CanExecute says return value is FALSE ??

    - by msfanboy
    Hello, I have a detach and attach button with Command="..." bound to my ViewModel. Although I have only 1 selected pupil but have NOT selected a subject the detach button is not disabled, the attach button is ??? public RelayCommand AttachdSubjecstCommand { get { return _attachSubjectsCommand ?? (_attachSubjectsCommand = new RelayCommand(() => AttachSubjects(), () => CanAttachSubjects)); } } public RelayCommand DetachSubjectsCommand { get { return _detachSubjectsCommand ?? (_detachSubjectsCommand = new RelayCommand(() => DetachSubjects(), () => CanDetachSubjects)); } }

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  • WinForms: How do I simulate button behavior on an image?

    - by Cheeso
    I have an extension of the winforms TabControl, it's draws an X on each tab to allow the user to close the tab. How can I similate button look&feel on that image? It's not a button, it's not even an image control. It's just been drawn there. Is there a way to draw an inset border on MouseDown and Raised on MouseUp? Would I be better off generating another image, for the "inset" phase? anyone done this before? Related: Simulate Winforms Button Click Animation But this question is different because he actually has a PictureBox control. I don't.

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  • How can I play video by touching the button on the video thumnail of the video in tableviewcell ?

    - by srikanth rongali
    I have a table view in which if each cell is touched video plays. Each cell have image of the video cell.imageView.image. And on the image I have a button (UIButton) with play symbol. If I touch the play button the corresponding video should be played same like the when cell is touched. I have a selector for the play button. But I need (NSIndex*)indexPath to get the current row. But I can't access the indexPath in my selector. How can I make this? Thank You.

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  • How can I disable a button in a JQuery dialog from a function?

    - by Draco
    Hi, I have a JQuery dialog that requires the user to enter certain information. In this form I have a "continue" button. I would like this "continue" button to only be enabled once all the fields have content in them else it will remain disabled. I wrote a function that is called everytime a field status has changed however I don't know how to enable and disable the dialog button from this function. Any ideas? Oops and I forgot to mention that these buttons were created as follows: $(function() { $("#dialog").dialog({ bgiframe: true, height: 'auto', width: 700, show: 'clip', hide: 'clip', modal: true, buttons: { 'Add to request list': function() { $(this).dialog('close'); $('form').submit(); }, 'Cancel': function() { $(this).dialog('close'); } } });

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  • Any particular reason why FaceBook's Subscribe Button isn't showing on my web page?

    - by Axonn
    I got this FaceBook profile for my upcoming website and I can't get the Subscribe button to show, NOT EVEN ON FaceBook's page! http://www.facebook.com/profile.php?id=100003492130845 Now, if you go here on FaceBook's page where we build the Subscribe button: http://developers.facebook.com/docs/reference/plugins/subscribe/ And add the above link, it will show nothing. I enabled subscribing and I also created myself a page, linked to the same profile: http://www.facebook.com/pages/Axonn-Says/372194956141393 But not even the page works ::- /. LATER EDIT: I temporarily added 2 other Subscribe buttons on my website to demonstrate that it works for example for Mark Zuck's page and to demonstrate that there are no JS conflicts. The 2 buttons appeared ok, but my button still didn't show up.

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