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  • How to test 500.html in (django) development env?

    - by lud0h
    I am using Django for a project and is already in production. In the production environment 500.html is rendered whenever a server error occurs. How do I test the rendering of 500.html in dev environment? Or how do I render 500.html in dev, if I turn-off debug I still get the errors and not 500.html background: I include some page elements based on a page and some are missing when 500.html is called and want to debug it in dev environment.

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  • How do I write a single-file Django application?

    - by obvio171
    I want to write a very small Django application in a single file, requiring all the appropriate modules and stuff, and then be able to run that as a normal Python script, like this: $ python myapp.py You can assume I won't render HTML, so I don't need templates (I'll return JSON or some other auto-generated string).

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  • How to configure multiple web site with django and tornado?

    - by mapcuk
    On my VDS I use nginx, django and tornado. I had just one project, Now i gonna deploy another one project with a different domain name. I want to use different databases and folders. I know how to configure nginx for serving static resourses , but what about tornado? Should i run separeted instance of tornado for each project or is there any better solution?

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  • Django: What's the correct way to get the requesting IP address?

    - by swisstony
    I'm trying to develop an app using Django 1.1 on Webfaction. I'd like to get the IP address of the incoming request, but when I use request.META['REMOTE_ADDR'] it returns 127.0.0.1. There seems to be a number of different ways of getting the address, such as using HTTP_X_FORWARDED_FOR or plugging in some middleware called SetRemoteAddrFromForwardedFor. Just wondering what the best approach was?

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  • Django/jquery: Address forms - dyamically adding state drop down list if country is United States?

    - by User
    I have a django html form for address information. There is standard street, city, state/province, postal code, country fields. The country field is a drop down list. How can I make the state/province field a drop down list if the selected country is united states and a free form text box if the country is anything else? I'd prefer not to have to do a round trip to the server so probably through jquery?

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  • Any reason not to use USE_ETAGS with CommonMiddleware in Django?

    - by allyourcode
    The only reason I can think of is that calculating ETag's might be expensive. If pages change very quickly, the browser's cache is likely to be invalidated by the ETag. In that case, calculating the ETag would be a waste of time. On the other hand, a giving a 304 response when possible minimizes the amount of time spent in transmission. What are some good guidelines for when ETag's are likely to be a net winner when implemented with Django's CommonMiddleware?

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  • I am currently serving my static files in Django. How do I use Apache2 to do this?

    - by alex
    (r'^media/(?P<path>.*)$', 'django.views.static.serve',{'document_root': settings.MEDIA_ROOT}), As you can see, I have a directory called "media" under my Django project. I would like to delete this line in my urls.py and instead us Apache to serve my static files. What do I do to my Apache configs (which files do I change) in order to do this? By the way, I installed Apache2 like normal: sudo aptitude install apache2

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  • What is good practice in .NET system architecture design concerning multiple models and aggregates

    - by BuzzBubba
    I'm designing a larger enterprise architecture and I'm in a doubt about how to separate the models and design those. There are several points I'd like suggestions for: - models to define - way to define models Currently my idea is to define: Core (domain) model Repositories to get data to that domain model from a database or other store Business logic model that would contain business logic, validation logic and more specific versions of forms of data retrieval methods View models prepared for specifically formated data output that would be parsed by views of different kind (web, silverlight, etc). For the first model I'm puzzled at what to use and how to define the mode. Should this model entities contain collections and in what form? IList, IEnumerable or IQueryable collections? - I'm thinking of immutable collections which IEnumerable is, but I'd like to avoid huge data collections and to offer my Business logic layer access with LINQ expressions so that query trees get executed at Data level and retrieve only really required data for situations like the one when I'm retrieving a very specific subset of elements amongst thousands or hundreds of thousands. What if I have an item with several thousands of bids? I can't just make an IEnumerable collection of those on the model and then retrieve an item list in some Repository method or even Business model method. Should it be IQueryable so that I actually pass my queries to Repository all the way from the Business logic model layer? Should I just avoid collections in my domain model? Should I void only some collections? Should I separate Domain model and BusinessLogic model or integrate those? Data would be dealt trough repositories which would use Domain model classes. Should repositories be used directly using only classes from domain model like data containers? This is an example of what I had in mind: So, my Domain objects would look like (e.g.) public class Item { public string ItemName { get; set; } public int Price { get; set; } public bool Available { get; set; } private IList<Bid> _bids; public IQueryable<Bid> Bids { get { return _bids.AsQueryable(); } private set { _bids = value; } } public AddNewBid(Bid newBid) { _bids.Add(new Bid {.... } } Where Bid would be defined as a normal class. Repositories would be defined as data retrieval factories and used to get data into another (Business logic) model which would again be used to get data to ViewModels which would then be rendered by different consumers. I would define IQueryable interfaces for all aggregating collections to get flexibility and minimize data retrieved from real data store. Or should I make Domain Model "anemic" with pure data store entities and all collections define for business logic model? One of the most important questions is, where to have IQueryable typed collections? - All the way from Repositories to Business model or not at all and expose only solid IList and IEnumerable from Repositories and deal with more specific queries inside Business model, but have more finer grained methods for data retrieval within Repositories. So, what do you think? Have any suggestions?

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  • Jinja2 returns "None" string for Google App Engine models

    - by Brian M. Hunt
    Google App Engine models, likeso: from google.appengine.ext.db import Model class M(): name = db.StringProperty() Then in a Jinja2 template called from a Django view with an in instance of M passed in as m: The name of this M is {{ m.name }}. When m is initialized without name being set, the following is printed: The name of this M is None. The preferable and expected output (and the output when using Django templates) would be/is: The name of this M is . Do you know why this is happening, and how to get the preferred & expected output?

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  • Dropdown dependent values to be fetch from multiple models using ajax in Yii

    - by newuser
    I searched all the documentation over Yii but not got the answer of it.So I came here finally. I have the following schema Table Schools +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_name | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ Table Students +------------------+--------------+------+-----+---------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------------------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | school_id | int(10) | NO | FK | | | | student_name | varchar(100) | NO | | | | | roll_no | varchar(80) | NO | | | | | class | varchar(20) | NO | | | | | | subjects | varchar(100) | NO | | | | +------------------+--------------+------+-----+---------------------+----------------+ I have made models and CRUD for the both models.In models my relation is like this In Students.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'School' => array(self::BELONGS_TO,'Schools','school_id'), ); } In Schools.php the relation is like public function relations() { // NOTE: you may need to adjust the relation name and the related // class name for the relations automatically generated below. return array( 'student' => array(self::HAS_MANY, 'Students', 'school_id'), ); } Now I made the two models rendered in a single page so that I can enter all the respective fields in a single form. In the _form.php file of Students I have made some change in student_name like this <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php echo $form->dropdownList($model,'student_name', CHtml::listData(Students::model()->findAll(), 'id', 'student_name'), array('empty'=>array('Select'=>'--Select One---'))); ?> <?php echo $form->error($model,'student_name'); ?> Now for this piece of code I got all the student name from the Student model. So my problem is when I am getting the student name from the dropdown list and going to select a student it will also fetch all the respective values of the student to be rendered in the _form.php without click on save button.So that user don't have to put it again manually. I think ajax and json encode will work here but don't know how to make them work here. [Update] Here is StudentsController code public function actionDisCoor() { $model = School::model()->findByPk($_POST['Students']['student_id']); $data=CHtml::listData($data,'id','name'); foreach($data as $value=>$name) { echo CHtml::tag('option',array('value'=>$value),CHtml::encode($name),true); } } Here is _form.php code for Students <div class="row"> <?php echo $form->labelEx($model,'student_name'); ?> <?php $List = CHtml::listData(Students::model()->findAll(), 'id', 'student_name'); ?> <?php echo $form->dropdownList($model,'student_name',$List, array('onChange'=>CHtml::ajax(array( 'url' => CController::createUrl('DisCoor'), 'type' => 'POST', 'update'=>'#school_id', )),'style'=>'width:180px;' ) )?> <?php echo $form->error($model,'student_name'); ?> </div> After all that when I saw in firebug I got the error.Here is the screen shot

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  • django on appengine

    - by aks
    I am impressed with django.Am am currenty a java developer.I want to make some cool websites for myself but i want to host it in some third pary environmet. Now the question is can i host the django application on appengine?If yes , how?? Are there any site built using django which are already hosted on appengine?

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  • what is this 'content_type' mean..

    - by zjm1126
    content_type = ContentType.objects.get_for_model(Map) maps = maps.extra(select=SortedDict([ ('member_count', MEMBER_COUNT_SQL), ('topic_count', TOPIC_COUNT_SQL), ]), select_params=(content_type.id,)) and the ContentType is: class ContentType(models.Model): name = models.CharField(max_length=100) app_label = models.CharField(max_length=100) model = models.CharField(_('python model class name'), max_length=100) objects = ContentTypeManager() class Meta: verbose_name = _('content type') verbose_name_plural = _('content types') db_table = 'django_content_type' ordering = ('name',) unique_together = (('app_label', 'model'),) def __unicode__(self): return self.name def model_class(self): "Returns the Python model class for this type of content." from django.db import models return models.get_model(self.app_label, self.model) def get_object_for_this_type(self, **kwargs): """ Returns an object of this type for the keyword arguments given. Basically, this is a proxy around this object_type's get_object() model method. The ObjectNotExist exception, if thrown, will not be caught, so code that calls this method should catch it. """ return self.model_class()._default_manager.using(self._state.db).get(**kwargs) def natural_key(self): return (self.app_label, self.model) i want to know: what is the 'content_type' used for ??

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  • FieldError when annotating over foreign keys

    - by X_9
    I have a models file that looks similar to the following: class WithDate(models.Model): adddedDate = models.DateTimeField(auto_now_add=True) modifiedDate = models.DateTimeField(auto_now=True) class Meta: abstract = True class Match(WithDate): ... class Notify(WithDate): matchId = models.ForeignKey(Match) headline = models.CharField(null=True, blank=True, max_length=10) For each Match I'm trying to get a count of notify records that have a headline. So my call looks like matchObjs = Match.objects.annotate(notifies_made=Count('notify__headline__isnull')) This keeps throwing a FieldError. I've simplified the query down to matchObjs = Match.objects.annotate(notifies_made=Count('notify')) And I still get the same FieldError... I've seen this work in other cases (other documentation, other SO questions like this one) but I can't figure out why I'm getting an error. The specific error that is returned is as follows: Cannot resolve keyword 'notify' into field. Choices are: (all fields from Match model) Does anyone have a clue as to why I can't get this annotation to work across tables? I'm baffled after looking at the other SO question and various Django docs where I've seen this done. Edit: I am using Django 1.1.1

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  • manyToManyField question

    - by dotty
    Hay guys, I'm writing a simple app which logs recipes. I'm working out my models and have stumbled across a problem My Dish models needs to have many Ingredients. This is no problem because i would do something like this ingredients = models.ManyToManyfield(Ingredient) No problems, my dish now can have many ingrendients. However, the problem is that the ingredient needs to come in different quantities. I.E 4 eggs, 7 tablespoons sugar My Ingredient Model is very simple at the moment class Ingredient(models.Model): name = models.TextField(blank=False) slug = models.SlugField(blank=True) How would i go about work out this problem? What fields would i need to add, would i need to use a 'through' attribute on my ManyToManyfield to solve this problem?

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