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  • best way to statistically detect anomalies in data

    - by reinier
    Hi, our webapp collects huge amount of data about user actions, network business, database load, etc etc etc All data is stored in warehouses and we have quite a lot of interesting views on this data. if something odd happens chances are, it shows up somewhere in the data. However, to manually detect if something out of the ordinary is going on, one has to continually look through this data, and look for oddities. My question: what is the best way to detect changes in dynamic data which can be seen as 'out of the ordinary'. Are bayesan filters (I've seen these mentioned when reading about spam detection) the way to go? Any pointers would be great! EDIT: To clarify the data for example shows a daily curve of database load. This curve typically looks similar to the curve from yesterday In time this curve might change slowly. It would be nice that if the curve from day to day changes say within some perimeters, a warning could go off. R

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  • Avoid being blocked by web mail companies for mass/bulk emailing ?

    - by Johannes
    Our company is sending out a lot of emails per day and planning to send even more in future. (thousands) Also there are mass mailouts as well in the ten thousands every now and then. Anybody has experience with hotmail, yahoo (web.de, gmx.net) and similar webmail companies blocking your emails because "too many from the same source in a period of time" have been sent to them? What can be done about it? Spreading email mailouts over a whole day/night? At what rate? (we are talking about legal emailing just to make sure...)

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  • Speech Recognition Server Does Not Stay Open

    - by Waffle
    I am trying to create a simple program that loops for user speech input using com.apple.speech.recognitionserver. My code thus far is as follows: set user_response to "start" repeat while user_response is not equal to "Exit" tell application id "com.apple.speech.recognitionserver" set user_response to listen for {"Time", "Weather", "Exit"} with prompt "Good Morning" end tell if user_response = "Time" then set curr_time to time string of (the current date) set curr_day to weekday of (the current date) say "It is" say curr_time say "on" say curr_day say "day" else if user_response = "Weather" then say "It is hot outside. What do you expect?" end if end repeat say "Have a good day" If the above is run on my system it says good morning and it then pops up with the speech input system and waits for either Time, Weather, or Exit. They all do what they say they are going to do, but instead of looping if I say Time and Weather and asking again until I say exit the speechserver times out and never pops up again. Is there a way of either keeping that application open until the program ends or is applescript not capable of looping for user speech input?

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  • Can ActionScript tell when a SWF was published?

    - by spiralganglion
    I'd like to write a little class that adds a Day/Month box showing the date a SWF was published from Flash. The company I work for regularly produces many, many SWFs and many versions of each, iterating over the course of months. A version-tracking system we've been using to communicate with our clients is a Day/Month date-box that gives the date the SWF was published. Up until now, we've been filling in the publish date by hand. If there's any way I can do this programatically with ActionScript that'd be fantastic. Any insight? Basically, all I need is the call that gives me the publish date, or even.. anything about the circumstances under which a SWF was published that I could use to roll into some form of.. automated version identification, unique to this SWF. So, can ActionScript tell when a SWF was published?

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  • Whats wrong with this task queue setup?

    - by Peter Farmer
    I've setup this task queue implementation on a site I host for a customer, it has a cron job which runs each morning at 2am "/admin/tasks/queue", this queues up emails to be sent out, "/admin/tasks/email", and uses cursors so as to do the queuing in small chunks. For some reason last night /admin/tasks/queue kept getting run by this code and so sent out my whole quota of emails :/. Have I done something wrong with this code? class QueueUpEmail(webapp.RequestHandler): def post(self): subscribers = Subscriber.all() subscribers.filter("verified =", True) last_cursor = memcache.get('daily_email_cursor') if last_cursor: subscribers.with_cursor(last_cursor) subs = subscribers.fetch(10) logging.debug("POST - subs count = %i" % len(subs)) if len(subs) < 10: logging.debug("POST - Less than 10 subscribers in subs") # Subscribers left is less than 10, don't reschedule the task for sub in subs: task = taskqueue.Task(url='/admin/tasks/email', params={'email': sub.emailaddress, 'day': sub.day_no}) task.add("email") memcache.delete('daily_email_cursor') else: logging.debug("POST - Greater than 10 subscibers left in subs - reschedule") # Subscribers is 10 or greater, reschedule for sub in subs: task = taskqueue.Task(url='/admin/tasks/email', params={'email': sub.emailaddress, 'day': sub.day_no}) task.add("email") cursor = subscribers.cursor() memcache.set('daily_email_cursor', cursor) task = taskqueue.Task(url="/admin/tasks/queue", params={}) task.add("queueup")

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  • Finding the time to program in your spare time?

    - by Omar Kooheji
    I've got about a dozen programming projects bouncing about my head, and I'd love to contribute to some open source projects, the problem I have is that having spent the entire day staring at Visual Studio and or Eclipse (Sometimes both at the same time...) the last thing I feel like doing when I go home is program. How do you build up the motivation/time to work on your own projects after work? I'm not saying that I don't enjoy programming, it's just that I enjoy other things to and it can be hard to even do something you enjoy if you've spent all day already doing it. I think that if I worked at a chocolate factory the last thing I'd want to see when I got home was a Wonka bar.... Related: How do you keep a balance between working, training, health and family?

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  • Display continuous dates in Pivot Chart

    - by Douglas
    I have a set of data in a pivot table with date times and events. I've made a pivot chart with this data, and grouped the data by day and year, then display a count of events for each day. So, my horizontal axis goes from 19 March 2007 to 11 May 2010, and my vertical axis is numeric, going from zero to 140. For some days, I have zero events. These days don't seem to be shown on the horizontal axis, so 2008 is narrower than 2009. How do I display a count of zero for days with no events? I'd like my horizontal axis to be continuous, so that it does not miss any days, and every month ends up taking up the same amount of horizontal space. (This question is similar to the unanswered question here, but I'd rather not generate a table of all the days in the last x number of years just to get a smooth plot!)

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  • How can a Windows program temporarily change its time zone?

    - by Rob Kennedy
    I've written a function to return the time_t value corresponding to midnight on a given day. When there is no midnight for a given day, it returns the earliest time available; that situation can occur, for example, when Egypt enters daylight-saving time. This year, the time change takes effect at midnight on the night of April 29, so the clock goes directly from 23:59 to 01:00. Now I'm writing unit tests for this function, and one of the tests should replicate the Egypt scenario. In Unix, I can accomplish it like this: putenv("TZ", "Egypt", true); tzset(); After doing that, further calls to localtime behave as if they're in Egypt instead of Minnesota, and my tests pass. Merely setting the environment variable doesn't have any effect on Windows, though. What can I do to make the unit test think it's somewhere else without affecting the rest of the programs running on the system?

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  • How is your mac setup for windows development?

    - by Matt Brailsford
    Hi Guys, I'm looking at buying a MacBook Pro to replace my tiring laptop. My day to day job is as a .NET web developer so I am looking to use VMWare Fusion to run VS and SQL server etc. As I've not run my dev environment in a VM before, I would like to know how others are setup. What apps to you have installed? In which environment? Where do you store your files? Within each environment, or some shared drive? Are there any gotchas? Or essentials I should know. Many thanks Matt

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  • Do you feel underappreciated or resent the geek/nerd stigma?

    - by dotnetdev
    At work we have a piece of A4 paper with the number of everyone in the office. The structure of this document is laid out in rectangles, by department. I work for the department that does all the technical stuff. That includes support—bear in mind that the support staff isn't educated in IT but just has experience in PC maintenance and providing support to a system we resell but don't have source code access to, project manager, team leader, a network administrator, a product manager, and me, a programmer. Anyway, on this paper, we are labelled as nerds and geeks. I did take a little offence to this, as much as it is light hearted (but annoying and old) humour. I have a vivid image that a geek is someone who doesn't go out but codes all day. I code all day at home and at work (when I have something to code...), but I keep balance by going out. I don't know why it is only people who work with computers that get such a stigma. No other profession really gets the same stigma—skilled, technical, or whatever. An account manager (and this is hardly a skilled job) says, "Perhaps [MY NAME HERE] could write some geeky code tomorrow to add this functionality to the website." It is funny how I get such an unfair stigma but I am so pivotal. In fact, if it wasn't for me, the company would have nothing to sell so the account managers would be redundant! I make systems, they get sold, and this is what pays the wages. It's funny how the account managers get a commission for how many systems they sell, or manage to make clients resubscribe to. Yet I built the thing in the first place! On top of that, my brother says all I do is type stuff on a keyboard all day. Surely if I did, I'd be typing at my normal typing speed of 100wpm+ as if I am writing a blog entry. Instead, I plan as I code along on the fly if commercial pressures and time prohibit proper planning. I never type as if I'm writing normal English. There is more to our jobs than just typing code. And my brother is a pipe fitter with no formal qualifications in his name. I could easily, and perhaps more justifiably, say he just manipulates a spanner or something. Does you feel underappreciated or that a geek/nerd stigma is undeserved or unfair?

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  • Grouping with operands question

    - by Filip
    I have a table: mysql> desc kursy_bid; +-----------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-----------+-------------+------+-----+---------+-------+ | datetime | datetime | NO | PRI | NULL | | | currency | varchar(6) | NO | PRI | NULL | | | value | varchar(10) | YES | | NULL | | +-----------+-------------+------+-----+---------+-------+ 3 rows in set (0.01 sec) I would like to select some rows from a table, grouped by some time interval (can be one day) where I will have the first row and the last row of the group, the max(value) and min(value). I tried: select datetime, (select value order by datetime asc limit 1) open, (select value order by datetime desc limit 1) close, max(value), min(value) from kursy_bid_test where datetime > '2009-09-14 00:00:00' and currency = 'eurpln' group by month(datetime), day(datetime), hour(datetime); but the output is: | open | close | datetime | max(value) | min(value) | +--------+--------+---------------------+------------+------------+ | 1.4581 | 1.4581 | 2009-09-14 00:00:05 | 4.1712 | 1.4581 | | 1.4581 | 1.4581 | 2009-09-14 01:00:01 | 1.4581 | 1.4581 | As you see open and close is the same (but they shouldn't be). What should be the query to do what I want?

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  • How to transfer SQLite db to web server on android phone

    - by Shane
    Hi, I have an application that creates an SQLite database and saves information to it over the course of a day. At the end of the day i want to export this database to a web server. Could anyone point me in the right direction for this? Should I use httppost or put. I have researched this myself online but there seems to be so many different ways to explore. The server side does not exist yet either. I have access to an apache server so i am hoping to use that. Could anyone advise me the best/most simple way to do this? Thanks

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  • executing named_scoped only when there are present params

    - by Luca Romagnoli
    Hi have a model like this: class EventDate < ActiveRecord::Base belongs_to :event named_scope :named, lambda { | name | { :joins => { :event => :core}, :conditions => ["name like ?", "%#{ name }%"] }} named_scope :date_range, lambda { | start, length | { :conditions => ["day >= ? AND day <= ?", start, date + (length || 30) ] }} it works correctly if i launch name = "ba" start = Date.today EventDate.named(name).date_range(start , start + 2) But if the name or the start is nil i don't want execute the named_scope like name = nil EventDate.named(name).date_range(start , start + 2) Is possible to set a condition inner the named_scope ? thanks

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  • How do I select the number of distinct days in a date range?

    - by isme
    I'm trying to use the T-SQL function DATEDIFF to select the number of distinct dates in a time period. The following query: SELECT DATEDIFF(DAY, '2012-01-01 01:23:45', '2012-01-02 01:23:45') selects 1, which is one less than I want. There are two distinct dates in the range: 2012-01-01 and 2012-01-02. It is not correct to add one to the result in the general case. The following query: SELECT DATEDIFF(DAY, '2012-01-01 00:00:00', '2012-01-02 00:00:00') selects 1, which is correct, because there is only one distinct date in the range. I'm sure there is a simple bit of arithmetic that I'm missing to calculate this. Can someone help me?

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  • Need help with SQL table structure transformation

    - by Arnis L.
    I need to perform update/insert simultaneously changing structure of incoming data. Think about Shops that have defined work time for each day of the week. Hopefully, this might explain better what I'm trying to achieve: worktimeOrigin table: columns: shop_id day val data: 123 | "monday" | "9:00 AM - 18:00" 123 | "tuesday" | "9:00 AM - 18:00" 123 | "wednesday" | "9:00 AM - 18:00" shop table: columns: id worktimeDestination.id worktimeDestination table: columns: id monday tuesday wednesday My aim: I would like to insert data from worktimeOrigin table into worktimeDestination and specify appropriate worktimeDestination for shop. shop table data: 123 1 (updated) worktimeDestination table data: 1 | "9:00 AM - 18:00" | "9:00 AM - 18:00" | "9:00 AM - 18:00" (inserted) Any ideas how to do that?

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  • How to convert an HTML table to an array in python

    - by user345660
    I have an html document, and I want to pull the tables out of this document and return them as arrays. I'm picturing 2 functions, one that finds all the html tables in a document, and a second one that turns html tables into 2-dimensional arrays. Something like this: htmltables = get_tables(htmldocument) for table in htmltables: array=make_array(table) There's 2 catches: 1. The number tables varies day to day 2. The tables have all kinds of weird extra formatting, like bold and blink tags, randomly thrown in. Thanks!

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  • Perl Math::Business::EMA help

    - by Dustin
    Script pulls data from mysql: $DBI::result = $db->prepare(qq{ SELECT close FROM $table WHERE day <= '$DATE' ORDER BY day DESC LIMIT $EMA }); $DBI::result->execute(); while($row = $DBI::result->fetchrow) { print "$row\n"; }; with the following example results: 1.560 1.560 1.550... But I need to work out the EMA using Math::Business::EMA; and I'm not sure how to calculate this while maintaining the accuracy. EMA is weighted and My lack of Perl knowledge is not helping.

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  • Scripts help FIND command via atime output to multiple files

    - by sswagner
    here is a script I have wrote that I need help with. in the script I do a find for any file that has not been access for over 30 days, 60, 90, 180, 270 & 365 days. This works just fine. however, this takes a few days just to finish the 30 day portion. it is scanning a NAS. (millions and millions of files) as you see, the 30 day information really holds all the data need for the rest of the scripts. the 60, 90, etc. portion of the script are just redoing the same effort as the 30 day portion, except for an extended time frame. it would save in this case weeks worth of re-scanning if some how the 60, 90 180, etc.. portions could just get its data from the 30 day output. this is where I am asking for help. the output is just like an ls -l command. and you can also see from the output below, there are multiple years in this output. the script is attached and printed below. total 24 -rw-r--r-- 1 root bin 60 Apr 12 13:07 config_file -rw-r--r-- 1 root bin 9 Apr 12 13:07 config_file.InProgress -rw-r--r-- 1 root bin 0 Apr 12 13:07 config_file.sids -rw-r--r-- 1 root bin 1284 Apr 19 10:41 rpt_file -rw-r--r-- 1 16074 5003 20083 Apr 26 2002 /nas/quota/slot_2/CR_APP002/eb_ora_bin1/sun8/product/9.2s/oem_webstage/oracle/sysman/qtour/console/dat1_01.gif -rw-r--r-- 1 16074 5003 20088 Apr 26 2002 /nas/quota/slot_2/CR_APP002/eb_ora_bin1/sun8/product/9.2s/oem_webstage/oracle/sysman/qtour/console/set1_04.gif -rw-r--r-- 1 16074 5003 2008 Apr 26 2002 /nas/quota/slot_2/CR_APP002/eb_ora_bin1/sun8/product/9.2s/oem_webstage/oracle/sysman/qtour/oapps/get2_03.htm -rw-r--r-- 1 16074 5003 20083 Apr 26 2002 /nas/quota/slot_2/CR_APP002/eb_ora_bin1/sun8/product/9.2s/oem_webstage/oracle/sysman/qtour/oapps/per1_01.gif any help is appreciated. these are linux distro boxes, so I am sure perl is on there too if needed.. Thanks! !/bin/ksh # search shares for files that have not been accessed for a certain time. NOTE: $IN = input search $OUT = output directory for text file # TESTS Numeric arguments can be specified as # +n for greater than n, -n for less than n, n for exactly n. # -atime n File was last accessed n*24 hours ago. # # IN1=/nas/quota/slot_2/CR* IN2=/nas/quota/slot_3/CR* IN3=/nas/quota/slot_4/CR* IN4=/nas/quota/slot_5/CR* OUT=/nas/quota/slot_3/CR_PRJ144/steve mkdir ${OUT} for dir in ${IN1}; do find $dir -atime +30 -exec ls -l '{}' \; ${OUT}/30days.txt; done for dir in ${IN2}; do find $dir -atime +30 -exec ls -l '{}' \; ${OUT}/30days.txt; done for dir in ${IN3}; do find $dir -atime +30 -exec ls -l '{}' \; ${OUT}/30days.txt; done for dir in ${IN4}; do find $dir -atime +30 -exec ls -l '{}' \; ${OUT}/30days.txt; done for dir in ${IN1}; do find $dir -atime +60 -exec ls -l '{}' \; ${OUT}/60days.txt; done for dir in ${IN2}; do find $dir -atime +60 -exec ls -l '{}' \; ${OUT}/60days.txt; done for dir in ${IN3}; do find $dir -atime +60 -exec ls -l '{}' \; ${OUT}/60days.txt; done for dir in ${IN4}; do find $dir -atime +60 -exec ls -l '{}' \; ${OUT}/60days.txt; done for dir in ${IN1}; do find $dir -atime +90 -exec ls -l '{}' \; ${OUT}/90days.txt; done for dir in ${IN2}; do find $dir -atime +90 -exec ls -l '{}' \; ${OUT}/90days.txt; done for dir in ${IN3}; do find $dir -atime +90 -exec ls -l '{}' \; ${OUT}/90days.txt; done for dir in ${IN4}; do find $dir -atime +90 -exec ls -l '{}' \; ${OUT}/90days.txt; done for dir in ${IN1}; do find $dir -atime +180 -exec ls -l '{}' \; ${OUT}/180days.txt; done for dir in ${IN2}; do find $dir -atime +180 -exec ls -l '{}' \; ${OUT}/180days.txt; done for dir in ${IN3}; do find $dir -atime +180 -exec ls -l '{}' \; ${OUT}/180days.txt; done for dir in ${IN4}; do find $dir -atime +180 -exec ls -l '{}' \; ${OUT}/180days.txt; done for dir in ${IN1}; do find $dir -atime +270 -exec ls -l '{}' \; ${OUT}/270days.txt; done for dir in ${IN2}; do find $dir -atime +270 -exec ls -l '{}' \; ${OUT}/270days.txt; done for dir in ${IN3}; do find $dir -atime +270 -exec ls -l '{}' \; ${OUT}/270days.txt; done for dir in ${IN4}; do find $dir -atime +270 -exec ls -l '{}' \; ${OUT}/270days.txt; done for dir in ${IN1}; do find $dir -atime +365 -exec ls -l '{}' \; ${OUT}/365days.txt; done for dir in ${IN2}; do find $dir -atime +365 -exec ls -l '{}' \; ${OUT}/365days.txt; done for dir in ${IN3}; do find $dir -atime +365 -exec ls -l '{}' \; ${OUT}/365days.txt; done for dir in ${IN4}; do find $dir -atime +365 -exec ls -l '{}' \; ${OUT}/365days.txt; done

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  • Visual Studio Optimizations

    - by lomaxx
    Visual studio is a pretty awesome IDE, but sometimes you just wish it would go faster. I was wondering if people have any tips or tricks to help speed up visual studio in day to day use. Things that I'm particularly interested in are speeding up build times and switching aspx files from source to design view seem to bring it to a grinding halt. Having said that, I'd be keen to hear anything that anyone uses to make VS run that little bit faster. Edit: Merged answers from related question, covering VS2008SP1. Please include any optimisations specific to the latest IDE.

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  • Need to work out database structure

    - by jim smith
    Hi, Just need a little kickstart with this. I have Mysql/PHP, and I have 5,000 products. I have 30 companies I need to store some data for those 30 companies for each product as follows: a) prices b) stock qty I also need to store data historically on a daily basis. So the table... It makes sense that the records will be the products because there's 5000, and if I put the companies as the columns, I can store the prices, but what about the stock quantities? I could create two columns for each compoany, one for prices, one for qty. Then make the tablename the date for that day...so theer would be a new table for every day with 5000 products in it? is this the correct way? Some idea on how I'll be retreiving data the top 5 lowest prices (and the company) by product for a certain date the price and stock changes in the past 7 days by product

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  • Dealing with uncertainty in ORM - Entity Framework CodeOnly

    - by Simon Fox
    This is a bit of a strange one but I've just seen something on twitter which kind of baffled me and I'm interested to know more. Rob Conery tweeted the following a couple of hours ago: Class name of the day: "Maybe<T>". Method of the day: "ToMaybe<T>()". He then went on to offer a Tekpub coupon to anyone who could guess where it came from. He linked to a further tweet which had a clue and from that I worked out that it was Entity Framework Code-Only but while trying to determine the usage someone else answered to which Rob replied ...EF CodeOnly - dealing with uncertainty.... So my question boils down to what exactly is he referring to with uncertainty and how does this fit in to Entity Framework Code-Only?

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  • "Dealing with uncertainty" - Entity Framework CodeOnly

    - by Simon Fox
    This is a bit of a strange one but I've just seen something on twitter which kind of baffled me and I'm interested to know more. Rob Conery tweeted the following a couple of hours ago: Class name of the day: "Maybe<T>". Method of the day: "ToMaybe<T>()". He then went on to offer a Tekpub coupon to anyone who could guess where it came from. He linked to a further tweet which had a clue and from that I worked out that it was Entity Framework Code-Only but while trying to determine the usage someone else answered to which Rob replied ...EF CodeOnly - dealing with uncertainty.... So my question boils down to what exactly is he referring to with uncertainty and how does this fit in to Entity Framework Code-Only?

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  • jQuery UI - Datepicker - Hide year

    - by David
    Hi, I'm using jQuery UI 1.8 and I would like to hide the year from the user in both the popup and the textbox. Essentially instead of picking the day, month and year I want the user to just pick the day and month. Hiding the year in the textbox is easy enough, the code shown below will do that. I'm stumped on how to hide the year from the popup - so it would say "April" instead of "April 2010". $(function() { $("#beginDateRange").datepicker({ dateFormat: 'mm/dd' }); }); <input type="text" name="beginDateRange" id="beginDateRange" /> Any help would be greatly appreciated.

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  • How to display a DateTime with chosen date parts, but in the order of the FormatProvider?

    - by Stephane
    I want to display the date in the order that the culture provides, but with the elements I want only. The DateTime.Tostring() method has a list of patterns that are very useful but I would like a very small change in it. The CultureInfo used in the following the following code are chosen as example, I don't want to rely on a specific list of CultureInfo, if possible var now = DateTime.Now; string nowString = now.ToString("m", CultureInfo.GetCultureInfo("en-us")); Console.WriteLine(nowString); nowString = now.ToString("m", CultureInfo.GetCultureInfo("fr-FR")); Console.WriteLine(nowString); displays : April 12 12 avril I would like a pattern that display the abbreviation of the month and the day, but that keeps the correct order from the specified CultureInfo. using the pattern "MMM dd" will always display the month's abbreviation first, followed by the day, breaking the french order for example. Any way to achieve that without too much custom code?

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