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  • I am using a regex snippet query string path

    - by Shelby Poston
    Using the following to load images base on two ids one is the and bookid and the out is the client. My folder structures is this. root path = flipbooks subfolders under flipbooks are books and clients in subfolder books I have and .net page title tablet. the tablet code behind checks the bookid of client and render a the tablet page with images in a flipbook fashion. because we have over 15000 records and flipbooks already created and stored in the database. I don't move the client folder under the books subfolders. I need the code below to get to the client subfolder in the query string and help to change this would be helpful. The result now is http://www.somewebsite.com/books/client/images/someimage1.jpg[^] I need the results to be http://www.somewebsite.com/client/images/someimage1.jpg[^]. I tried moving the tablet.aspx file to the root flipbooks and it works but i have provide a user name and password each time. This need to be access by the public and my root is protected. Don't want to have to change permission. I am trying to remove the /books function getParameterByName(name) { var results = RegExp('[?&]' + name + '=([^&]*)').exec(window.location.search); return results ? decodeURIComponent(results[1].replace(/\+/g, ' ')) : null; } Thanks Mission Critical

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  • Perl Strip Comments with Regex Unique Request

    - by YoDar
    Hello, I'm running a code that read files, do some parsing but need to ignore all comments. There are good explanations how to conduct it. like this link $/ = undef; $_ = <>; s#/\*[^*]*\*+([^/*][^*]*\*+)*/|("(\\.|[^"\\])*"|'(\\.|[^'\\])*'|.[^/"'\\]*)#defined $2 ? $2 : ""#gse; print; My first problem is that after run this line $/ = undef; my code doesn't work properly. Actually, I don't know what it does. But if I could turn it back after ignoring all comments it will be helpful. In general, What is the useful way to ignore all comments without changing the rest of the code ? Thanks, YoDar

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  • Regular expression: who's greedier?

    - by polygenelubricants
    My primary concern is with the Java flavor, but I'd also appreciate information regarding others. Let's say you have a subpattern like this: (.*)(.*) Not very useful as is, but let's say these two capture groups (say, \1 and \2) are part of a bigger pattern that matches with backreferences to these groups, etc. So both are greedy, in that they try to capture as much as possible, only taking less when they have to. My question is: who's greedier? Does \1 get first priority, giving \2 its share only if it has to? What about: (.*)(.*)(.*) Let's assume that \1 does get first priority. Let's say it got too greedy, and then spit out a character. Who gets it first? Is it always \2 or can it be \3? Let's assume it's \2 that gets \1's rejection. If this still doesn't work, who spits out now? Does \2 spit to \3, or does \1 spit out another to \2 first?

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  • Best way to correct garbled data caused by false encoding

    - by ercan
    Hi all, I have a set of data that contains garbled text fields because of encoding errors during many import/exports from one database to another. Most of the errors were caused by converting UTF-8 to ISO-8859-1. Strangely enough, the errors are not consistent: the word 'München' appears as 'München' in some place and as 'MÜnchen'. Is there a trick in SQL server to correct this kind of crap? The first thing that I can think of is to exploit the COLLATE clause, so that ü is interpreted as ü, but I don't exactly know how. If it isn't possible to make it in the DB level, do you know any tool that helps for a bulk correction? (no manual find/replace tool, but a tool that guesses the garbled text somehow and correct them)

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  • regular expression: extract last 2 characters

    - by dotnet-practitioner
    what is the best way to extract last 2 characters of a string using regular expression. For example, I want to extract state code from the following "A_IL" I want to extract IL as string.. please provide me C# code on how to get it.. string fullexpression = "A_IL"; string StateCode = some regular expression code.... thanks

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  • Regular Expression for username

    - by neobie
    I need help on regular expression on the condition (4) below: Begin with a-z End with a-z0-9 allow 3 special characters like ._- The characters in (3) must be followed by alphanumeric characters, and it cannot be followed by any characters in (3) themselves. Not sure how to do this. Any help is appreciated, with the sample and some explanations.

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  • How to detect what allowed character in current Regular Expression by using JavaScript?

    - by Soul_Master
    In my web application, I create some framework that use to bind model data to control on page. Each model property has some rule like string length, not null and regular expression. Before submit page, framework validate any binded control with defined rules. So, I want to detect what character that is allowed in each regular expression rule like the following example. "^[0-9]$" allow only digit characters like 1, 2, 3. "^[a-zA-Z_][a-zA-Z_-0-9]+$" allow only a-z, - and _ characters However, this function should not care about grouping, positioning of allowed character. It just tells about possible characters only. By the way, complex regular expression like find two words near(\bword1\W+(?:\w+\W+){1,6}?word2\b) must be ignore to verify and it should return any characters is possible. Do you have any idea for creating this function? PS. I know it easy to create specified function like numeric only for allowing only digit characters. But I need share/reuse same piece of code both data tier(contains all model validator) and UI tier without modify anything. Thanks

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  • PHP: Regular Expression to get a URL from a string

    - by Matthew Iselin
    I'm working on some PHP code which takes input from various sources and needs to find the URLs and save them somewhere. The kind of input that needs to be handled is as follows: http://www.youtube.com/watch?v=IY2j_GPIqRA Try google: http://google.com! (note exclamation mark is not part of the URL) Is http://somesite.com/ down for anyone else? Output: http://www.youtube.com/watch?v=IY2j_GPIqRA http://google.com http://somesite.com/ I've already borrowed one regular expression from the internet which works, but unfortunately wipes the query string out - not good! Any help putting together a regular expression, or perhaps another solution to this problem, would be appreciated.

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  • Help with this reg. exp. in PHP

    - by Jonathan
    Hi, i don't know about regular expressions, I asked here for one that: gets either anything up to the first parenthesis/colon or the first word inside the first parenthesis. This was the answer: preg_match('/(?:^[^(:]+|(?<=^\\()[^\\s)]+)/', $var, $match); I need an improvement, I need to get either anything up to the first parenthesis/colon/quotation marks or the first word inside the first parenthesis. So if I have something like: $var = 'story "The Town in Hell"s Backyard'; // I get this: $match = 'story'; $var = "screenplay (based on)"; // I get this: $match = 'screenplay'; $var = "(play)"; // I get this: $match = 'play'; $var = "original screen"; // I get this: $match = 'original screen'; Thanks!

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  • In C/C++ mode in Emacs, change face of code in #if 0...#endif block to comment face

    - by pogopop77
    I'm trying to add functionality found in some other code editors to my Emacs configuration, whereby C/C++ code within #if 0...#endif blocks is automatically set to the comment face/font. Based on my testing, cpp-highlight-mode does something like what I want, but requires user action. It seems like tying into the font-lock functionality is the correct option to make the behavior automatic. I have successfully followed examples in the GNU documentation to change the face of single-line regular expressions. For example: (add-hook 'c-mode-common-hook (lambda () (font-lock-add-keywords nil '(("\\<\\(FIXME\\|TODO\\|HACK\\|fixme\\|todo\\|hack\\)" 1 font-lock-warning-face t))))) works fine to highlight debug related keywords anywhere in a file. However, I am having problems matching #if 0...#endif as a multiline regular expression. I found some useful information in this post (How to compose region like ""), that suggested that Emacs must be told specifically to allow for multiline matches. But this code: (add-hook 'c-mode-common-hook (lambda () '(progn (setq font-lock-multiline t) (font-lock-add-keywords nil '(("#if 0\\(.\\|\n\\)*?#endif" 1 font-lock-comment-face t)))))) still does not work for me. Perhaps my regular expression is wrong (though it appears to work using M-x re-builder), I've messed up my syntax, or I'm following the wrong approach entirely. I'm using Aquamacs 2.1 (which is based on GNU Emacs 23.2.50.1) on OS X 10.6.5, if that makes a difference. Any assistance would be appreciated!

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  • Extract string that is delimited with constant and ends with two numbers (numbers have to be included)

    - by Edmon
    I have a text that contains string of a following structure: text I do not care about, persons name followed by two IDs. I know that: a person's name is always preceded by XYZ code and that is always followed by two, space separated numbers. Name is not always just a last name and first name. It can be multiple last or first names (think Latin american names). So, I am looking to extract string that follows the constant XYZ code and that is always terminated by two separate numbers. You can say that my delimiter is XYZ and two numbers, but numbers need to be part of the extracted value as well. From blah, blah XYZ names, names 122322 344322 blah blah I want to extract: names, names 122322 344322 Would someone please advise on the regular expression for this that would work with Python's re package.

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  • How do I process the largest match first in PHP?

    - by animuson
    Ok, so I tried searching around first but I didn't exactly know how to word this question or a search phrase. Let me explain. I have data that looks like this: <!-- data:start --> <!-- 0:start --> <!-- 0:start -->0,9<!-- 0:stop --> <!-- 1:start -->0,0<!-- 1:stop --> <!-- 2:start -->9,0<!-- 2:stop --> <!-- 3:start -->9,9<!-- 3:stop --> <!-- 4:start -->0,9<!-- 4:stop --> <!-- 0:stop --> <!-- 1:start --> <!-- 0:start -->1,5<!-- 0:stop --> <!-- 1:start -->1,6<!-- 1:stop --> <!-- 2:start -->3,6<!-- 2:stop --> <!-- 3:start -->3,8<!-- 3:stop --> <!-- 4:start -->4,8<!-- 4:stop --> <!-- 1:stop --> <!-- 2:start --> <!-- 0:start -->0,7<!-- 0:stop --> <!-- 1:start -->1,7<!-- 1:stop --> <!-- 2:stop --> <!-- data:stop --> So it's basically a bunch of points. Here is the code I'm currently using to try and parse it so that it would create an array like so: Array ( 0 => Array ( 0 => "0,9", 1 => "0,0", 2 => "9,0", 3 => "9,9", 4 => "0,9" ), 1 => Array ( 0 => "1,5", 1 => "1,6", 2 => "3,6", 3 => "3,8", 4 => "4,8" ), 2 => Array ( 0 => "0,7", 1 => "1,7" ) ) However, it is returning an array that looks like this: Array ( 0 => "0,9", 1 => "0,0", 2 => "9,0" ) Viewing the larger array that I have on my screen, you see that it's setting the first instance of that variable when matching. So how do I get it to find the widest match first and then process the insides. Here is the function I am currently using: function explosion($text) { $number = preg_match_all("/(<!-- ([\w]+):start -->)\n?(.*?)\n?(<!-- \\2:stop -->)/s", $text, $matches, PREG_SET_ORDER); if ($number == 0) return $text; else unset($item); foreach ($matches as $item) if (empty($data[$item[2]])) $data[$item[2]] = $this->explosion($item[3]); return $data; } I'm sure it will be something stupid and simple that I've overlooked, but that just makes it an easy answer for you I suppose.

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  • Way to partialy match a Ruby string using Regexp

    - by Fabiano PS
    I'm working on 2 cases: assume I have those var: a = "hello" b = "hello-SP" b = "not_hello" 1 - Any partial matches I want to accept any string that has the var a inside, so b and c would match. 2 - Patterned match I want to match a string that has a inside, followed by '-', so b would match, c does not. I am having problem, because I always used the syntax /expression/ to define Regexp, so how dinamicaly define an RegExp on Ruby??

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  • Reading a line backwards

    - by Jimmy
    Hi, I'm using regular expression to count the total spaces in a line (first occurrence). match(/^\s*/)[0].length; However this reads it from the start to end, How can I read it from end to start. Thanks

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  • What is the right method for parsing a blog post?

    - by Zedwal
    Hi guys, Need a guide line .... I am trying to write a personal blog. What is the standard structure for for input for the post. I am trying the format like: This is the simple text And I am [b] bold text[/b]. This is the code part: [code lang=java] public static void main (String args[]) { System.out.println("Hello World!"); } [/code] Is this the right way to store post in the database? And What is the right method to parse this kind of post? Shall I use regular expression to parse this or there is another standard for this. If the above mentioned format is not the right way for storage, then what it could be? Thanks

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  • Mod_rewrite works on local, not on remote, version?

    - by TylerT
    I have this site. Let's call it htp://www.mysite.com I have a rewrite rule to change htp://www.mysite.com/?q=words%20etc/0/10 into http://www.mysite.com/words%20etc/0/10 (or http://www.mysite.com//0/10 or http://www.mysite.com/0/10) .htaccess:ErrorDocument 404 htp://www.mysite.com/404.html options +FollowSymlinks rewriteEngine on rewriteCond %{REQUEST_URI} !-f rewriteCond %{REQUEST_URI} !-d rewriteCond %{REQUEST_URI} !index\.php rewriteRule ^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$ index.php/%{THE_REQUEST} [NC] Now, this works on my local apache 2.2.11 server, no errors. However on my host's apache 1.3.41 server, I get the following error: [Sat Mar 5 21:42:14 2011] [alert] [client [ip]] /home/_/public_html/mysite.com/.htaccess: RewriteRule: cannot compile regular expression '^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$'\n I imagine it's something quirky about the apache version as other sites on this host use mod_rewrite without a hitch. I've tried removing the +followSymlinks line, even the rewrite engine line. I haven't tried removing the conditions cause I don't think I should have to, I'm probably wrong.

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  • parse string with regular exression

    - by llamerr
    I trying to parse this string: $right = '34601)S(1,6)[2] - 34601)(11)[2] + 34601)(3)[2,4]'; with following regexp: const word = '(\d{3}\d{2}\)S{0,1}\([^\)]*\)S{0,1}\[[^\]]*\])'; preg_match('/'.word.'{1}(?:\s{1}([+-]{1})\s{1}'.word.'){0,}/', $right, $matches); print_r($matches); i want to return array like this: Array ( [0] => 34601)S(1,6)[2] - 34601)(11)[2] + 34601)(3)[2,4] [1] => 34601)S(1,6)[2] [2] => - [3] => 34601)(11)[2] [4] => + [5] => 34601)(3)[2,4] ) but i return only following: Array ( [0] => 34601)S(1,6)[2] - 34601)(11)[2] + 34601)(3)[2,4] [1] => 34601)S(1,6)[2] [2] => + [3] => 34601)(3)[2,4] ) i think, its becouse of [^)]* or [^]]* in the word, but how i should correct regexp for matching this in another way? i tryied to specify it: \d+(?:[,#]\d+){0,} so word become const word = '(\d{3}\d{2}\)S{0,1}\(\d+(?:[,#]\d+){0,}\)S{0,1}\[\d+(?:[,#]\d+){0,}\])'; but it gives nothing

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  • Removing whitespace in Java string?

    - by waitinforatrain
    Hi guys, I'm writing a parser for some LISP files. I'm trying to get rid of leading whitespace in a string. The string contents are along the lines of: :FUNCTION (LAMBDA (DELTA PLASMA-IN-0) (IF (OR (>= #61=(+ (* 1 DELTA) PLASMA-IN-0) 100) (<= #61# 0)) PLASMA-IN-0 #61#)) The tabs are all printed as 4 spaces in the file, so I want to get rid of these leading tabs. I tried to do this: string.replaceAll("\\s{4}", " ") - but it had no effect at all on the string. Does anyone know what I'm doing wrong? Is it because it is a multi-line string? Thanks

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  • User will input some filter criteria -- how can I turn it into a regular expression for String.match

    - by envinyater
    I have a program where the user will enter a string such as PropertyA = "abc_*" and I need to have the asterisk match any character. In my code, I'm grabbing the property value and replacing PropertyA with the actual value. For instance, it could be abc_123. I also pull out the equality symbol into a variable. It should be able to cover this type of criteria PropertyB = 'cba' PropertyC != '*-this' valueFromHeader is the lefthand side and value is the righthand side. if (equality.equals("=")) { result = valueFromHeader.matches(value); } else if (equality.equals("!=")) { result = !valueFromHeader.matches(value); } EDIT: The existing code had this type of replacement for regular expressions final String ESC = "\\$1"; final String NON_ALPHA = "([^A-Za-z0-9@])"; final String WILD = "*"; final String WILD_RE_TEMP = "@"; final String WILD_RE = ".*"; value = value.replace(WILD, WILD_RE_TEMP); value = value.replaceAll(NON_ALPHA,ESC); value = value.replace(WILD_RE_TEMP, WILD_RE); It doesn't like the underscore here... abcSite_123 != abcSite_123 (evaluates to true) abcSite_123$1.matches("abcSite$1123") It doesn't like the underscore...

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  • How to grep lines having specific format.

    - by Nitin
    I have got a file with following format. 1234, 'US', 'IN',...... 324, 'US', 'IN',...... ... ... 53434, 'UK', 'XX', .... ... ... 253, 'IN', 'UP',.... 253, 'IN', 'MH',.... Here I want to extract only those lines having 'IN' as 2nd keyword. i.e. 253, 'IN', 'UP',.... 253, 'IN', 'MH',.... Can any one please tell me a command to grep it.

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  • How would I create a VIM or Vi command to delete all text after a certain character for every line i

    - by Jason Down
    Scenario: I have a text file that has pipe (as in the "|" character) delimited data. Each field of data in the pipe delimited fields can be of variable length, so counting characters won't work (or using some sort of substring function... if that even exists in VIM). Is it possible, using VIM / Vi to delete all data from the second pipe to the end of the line for the entire file? There are approx 150,000 lines, so doing this manually would only be appealing to a masochist... e.g. Change the following lines from: 1111|random sized text 12345|more random data la la la|1111|abcde 2222|random sized text abcdefghijk|la la la la|2222|defgh 3333|random sized text|more random data|33333|ijklmnop to: 1111|random sized text 12345 2222|random sized text abcdefghijk 3333|random sized text I'm sure this can be done somehow... I hope. TIA UPDATE: I should have mentioned that I'm running this on Windows XP, so I don't have access to some of the mentioned *nix commands (CUT is not recognized on Windows).

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