Search Results

Search found 3804 results on 153 pages for 'regex'.

Page 106/153 | < Previous Page | 102 103 104 105 106 107 108 109 110 111 112 113  | Next Page >

• Ruby Regexp methods?

  - by fjs6

  Is there a gem/example_code that allows to work with regexps? I am not looking for what a regexp can do, but what can be done to a Regexp object. For example: r = Regexp.new(...) r.min_length => the minimum length of a matching string r = Regexp.new("car(less)?") r.min_length => 3 for the string "car" Thanks!

  Read the article

• Is there a Windows utility that will let me do multiple programmatic find/replaces on text that I cu

  - by billmaya

  I've inherited some C# code that contains about a thousand lines of source that I need to modify, transforming it from this: newDataRow["to_dir"] = comboBox108.Text; To this: assetAttributes.Add("to_dir", comboBox108.Text); The lines occur in various places throughout the application in groups of 40 or 50. Modifying each line by hand in Visual Studio 2008 can be done but it's labor intensive and prone to errors. Is there a Windows utility out there that will let me cut and paste groups of code into it and then run some sort of reg-ex expression to transform the individual lines one-by-one? I'd also be willing to use some sort of VS 2008 add-in that performed the same set of reg-ex operations against a selection of code. Thanks in advance.

  Read the article

• Regular expression from font to span (size and colour) and back (VB.NET)

  - by chapmanio

  Hi, I am looking for a regular expression that can convert my font tags (only with size and colour attributes) into span tags with the relevant inline css. This will be done in VB.NET if that helps at all. I also need a regular expression to go the other way as well. To elaborate below is an example of the conversion I am looking for: <font size="10">some text</font> To then become: <span style="font-size:10px;">some text</span> So converting the tag and putting a "px" at the end of whatever the font size is (I don't need to change/convert the font size, just stick px at the end). The regular expression needs to cope with a font tag that only has a size attribute, only a color attribute, or both: <font size="10">some text</font> <font color="#000000">some text</font> <font size="10" color="#000000">some text</font> <font color="#000000" size="10">some text</font> I also need another regular expression to do the opposite conversion. So for example: <span style="font-size:10px;">some text</span> Will become: <font size="10">some text</font> As before converting the tag but this time removing the "px", I don't need to worry about changing the font size. Again this will also need to cope with the size styling, font styling, and a combination of both: <span style="font-size:10px;">some text</span> <span style="color:#000000;">some text</span> <span style="font-size:10px; color:#000000;">some text</span> <span style="color:#000000; font-size:10px;">some text</span> I apprecitate this is a lot to ask, I am hopeless with regular expressions and need to find a way of making these conversions in my code. Thanks so much to anyone that can/is willing to help me!

  Read the article

• Match Anything Except a Sub-pattern

  - by Tim Lytle

  I'd like to accomplish what this (invalid I believe) regular expression tries to do: <p><a>([^(<\/a>)]+?)<\/a></p>uniquestring Essentially match anything except a closing anchor tag. Simple non-greedy doesn't help here because `uniquestring' may very well be after another distant closing anchor tag: <p><a>text I don't <tag>want</tag> to match</a></p>random data<p><a>text I do <tag>want to</tag> match</a></p>uniquestring more matches <p><a>of <tag>text I do</tag> want to match</a></p>uniquestring So I have more tag in between the anchor tags. And I'm using the presence of uniquestring to determine if I want to match the data. So a simple non-greedy ends up matching everything from the start of the data I don't want to the end of the data I do want. I know I'm edging close to the problems regular expressions (or at least my knowledge of them) aren't good at solving. I could just through the data at an HTML/XML parser, but it is just one simple(ish) search. Is there some easy way to do this that I'm just missing?

  Read the article

• Regular Expression to match unlimited number of options

  - by Pekka

  I want to be able to parse file paths like this one: /var/www/index.(htm|html|php|shtml) into an ordered array: array("htm", "html", "php", "shtml") and then produce a list of alternatives: /var/www/index.htm /var/www/index.html /var/www/index.php /var/www/index.shtml Right now, I have a preg_match statement that can split two alternatives: preg_match_all ("/\(([^)]*)\|([^)]*)\)/", $path_resource, $matches); Could somebody give me a pointer how to extend this to accept an unlimited number of alternatives (at least two)? Just regarding the regular expression, the rest I can deal with. The rule is: The list needs to start with a ( and close with a ) There must be one | in the list (i.e. at least two alternatives) Any other occurrence(s) of ( or ) are to remain untouched.

  Read the article

• Java String replaceAll with conditions

  - by user1483570

  I am not good in regular expressions and I need help in replacing the string. String str = "Name_XYZ_"; str = "XYZ_NAME_"; So how can I replace "Name_" or "_NAME_" from above two strings with empty string? The conditions are "Name" can be in any case and it can be at index 0 or at any index but preceded by "_". So far I tried, String replacedString = str.replaceAll("(?i)Name_", ""); // This is not correct. This is not the homework. I am working on XML file that needs such kind of processing. Please help. Thank you.

  Read the article

• replacing the beginning and end but not the same chars within a string

  - by Jordan Trainor

  lines = "some stuff\"some other \"stuff\"\""; lines = lines.Replace("\"", "\""); lines = lines.Replace("\"", "\""); in its current context and in its simplest form these two actions seem absolutely pointless but when I put this into code it will be not be pointless and will have a purpose other than replacing itself with itself. OK so I have the String lines that has 4 escaped quotation marks and I wish to replace the first quote with a quote and the end quote with a quote how would I accomplish this without replacing any of the inner quotes?

  Read the article

• complex regular expression task

  - by Don Don

  Hi, What regular expressions do I need to extract section title(s) in a text file? So, in the following sample text, I'd like to extract "Communication and Leadership" "1.Self-Knowledge" "2. Humility" "(3) Clear Thinking". Many thanks. Communication and Leadership True leaders understand that, rather than forcing their followers into a preconceived mold, their job is to motivate and organize followers to collectively accomplish goals that are in everyone's interests. The ability to communicate this to co-workers and followers is critical to the effectiveness of leadership. 1.Self-Knowledge Superior leaders are able to devote their skills and energies to leadership of a group because they have worked through personal issues to the point where they know themselves thoroughly. A high level of self-knowledge is a prerequisite to effective communication skills, because the things that you communicate as a leader are coming from within. 2. Humility This subversion of personal preference requires a certain level of humility. Although popular definitions of leaders do not always see them as humble, the most effective leaders actually are. This humility may not be expressed in self-effacement, but in a total commitment to the goals of the organization. Humility requires an understanding of one's own relative unimportance in comparison to larger systems. (3) Clear Thinking Clarity of thinking translates into clarity of communication. A leader whose goals or personal analysis is muddled will tend to deliver unclear or ambiguous directions to followers, leading to confusion and dissatisfaction. A leader with a clear mind who is not ambivalent about her purposes will communicate what needs to be done in a s traightforward and unmistakable manner.

  Read the article

• How to get only a filename (not full path) into $1, using the PERL, regular expressions

  - by Scott

  I want to keep only the filenames (not full paths) and add the filename to some bbcode. Here is the HTML to be converted: <a href=/path/to/full/image.jpg rel=prettyPhoto><img rel=prettyPhoto src=/path/to/thumb/image.jpg /></a> Notice I cannot have rel="foo" (no double quotes).. Here is what I have in PERL, to perform the conversion: s/\<a href=(.+?)\ rel=prettyPhoto\>\<img rel=prettyPhoto src=(.+?) \/>\<\/a\>/\[box\]$1\[\/box\]/gi; This converts the HTML to: [box]/path/to/image.jpg[/box] But this is what I want as a result: [box]image.jpg[/box] The HTML must remain the same. So how do I change my PERL so that $1 contains only the filename?

  Read the article

• How to sub with matched groups and variables in Python

  - by Syed

  Hi, new to python. This is probably simple but I haven't found an answer. rndStr = "20101215" rndStr2 = "20101216" str = "Looking at dates between 20110316 and 20110317" outstr = re.sub("(.+)([0-9]{8})(.+)([0-9]{8})",r'\1'+rndStr+r'\2'+rndStr2,str) The output I'm looking for is: Looking at dates between 20101215 and 20101216 But instead I get: P101215101216 The values of the two rndStr's doesn't really matter. Assume its random or taken from user input (I put static vals here to keep it simple). Thanks for any help.

  Read the article

• Getting a date value in a postgres table column and check if it's bigger than todays date

  - by Roland

  I have a Postgres table called clients. The name column contains certain values eg. test23233 [987665432,2014-02-18] At the end of the value is a date, I need to compare this date, and return all records where this specific date is younger than today I tried select id,name FROM clients where name ~ '(\d{4}\-\d{1,2}\-\d{1,2})'; but this isn't returning any values. How would I go about to achieve the results I want?

  Read the article

• Match all directory names in file path with regular expression

  - by Jeremy

  Can someone give me the regular expression to match something like /this/is/the/path or /this/is/the/path/ and matches like: $1=this $2=is $3=the $4=path ([^/]+)/ matches one, but I'm not quite sure how to get it to repeat. FYI: this is for a mod rewrite RewriteRule match.

  Read the article

• Finding if a sentence contains a specific phrase in Ruby

  - by TenJack

  Right now I am seeing if a sentence contains a specific word by splitting the sentence into an array and then doing an include to see if it contains the word. Something like: "This is my awesome sentence.".split(" ").include?('awesome') But I'm wondering what the fastest way to do this with a phrase is. Like if I wanted to see if the sentence "This is my awesome sentence." contains the phrase "my awesome sentence". I am scraping sentences and comparing a very large number of phrases, so speed is somewhat important.

  Read the article

• ASP.NET MVC 2 Authorization Regex

  - by Hurricanepkt

  What i currently have is the following: namespace AzureCCCMVC.Controllers { [Authorize(Roles="Admin")] public class AdminController : Controller { //Stuff } } what I want to do is have roles for each client such as Roles { "DEMOAdmin", "GOOGAdmin" , "MSFTAdmin" } and be able to Authorize The Client name (from URL) and in that role I know I am doing a horrible job of explaining this... It is possible that I can have users that are users of several clients but only admin's of one ...

  Read the article

• JQuery - remove the chars not matching regEx

  - by JQueryBeginner

  Hi All, I am trying to use jquery for validating forms. This is the pattern that is allowed in a text box for a user. var pattern = /^[a-zA-Z0-9!#$&%*+,-./: ;=?@_]/g; If the user types anything else other than this then that has to be replaced with a "". $(document).ready(function() { $('#iBox').blur(function() { var jVal = $('#iBox').val(); if(jVal.match(pattern)) { alert("Valid"); } else { alert("New "+jVal.replace(!(pattern),"")); } }); }); }); But the replace function does not work this way.

  Read the article

• \w in PHP preg_replace covers only second byte of UTF-8 chars

  - by Andrey

  we have this code: $value = preg_replace("/[^\w]/", '', $value); where $value is in utf-8. After this transformation first byte of multibyte characters is stripped. How to make \w cover UTF-8 chars completely? Sorry, i am not very well in PHP

  Read the article

• Match a comma followed by a newline with a regular expression

  - by MarathonStudios

  I have a comma delimited list I want to import into a database, and in some cases the last item is blank: item1, item2, item3 item1, item2, item1, item2, I'd like to replace all of these empty columns with a placeholder value using a regexp item1, item2, item3 item1, item2, PLACEHOLDER item1, item2, PLACEHOLDER I tried preg_replace("/,\n/", ",PLACEHOLDER\n",$csv);, but this isn't working. Anyone know what regexp would work for this?

  Read the article

• PHP regular expression subpattern behaviour

  - by codecowboy

  I want to match both the src and title attributes of an image tag: pattern: <img [^>]*src=["|\']([^"|\']+["|\'])|title=["|\']([^"|\']+) target: <img src="http://someurl.jpg" class="quiz_caption" title="Caption goes here!"> This pattern gives me one unwanted match, title="content", and the match I actually want which is the value between the quotes after the word 'title', i.e 'content'. So, my matches are: <img src="http://someurl.jpg http://someurl.jpg title="Caption goes here!" Caption goes here! Is there a way to avoid the third of these matches? I'm using PCRE in PHP 5.2.x

  Read the article

• Getting a "summary" of a webpage

  - by MattiasK

  I have something of a a hairy problem, I'd like to generate a couple of paragraphs of "description" of a given url, normally the start of an article. The Meta description field is one way to go but it isn't always good or set properly. It's fair to say it's a bit problematic to accomplish this from the screenscraped HTML. I had a general idea that perhaps one could scan the HTML for the first "appropriate" segment but it's hard to say what that is, perhaps something like the first paragraph containing a certain amount of text... Anyone have any good ideas? :) It doesn't have to be foolproof

  Read the article

• Java Split not working as expected

  - by daaabears

  I am trying to use a simple split to break up the following string: 00-00000 My expression is: ^([0-9][0-9])(-)([0-9])([0-9])([0-9])([0-9])([0-9]) And my usage is: String s = "00-00000"; String pattern = "^([0-9][0-9])(-)([0-9])([0-9])([0-9])([0-9])([0-9])"; String[] parts = s.split(pattern); If I play around with the Pattern and Matcher classes I can see that my pattern does match and the matcher tells me my groupCount is 7 which is correct. But when I try and split them I have no luck.

  Read the article

• Convert Json date string to JavaScript date object

  - by dagda1

  Hi, I have the following JSON object which has a date field in the following format: { "AlertDate": "\/Date(1277334000000+0100)\/", "Progress": 1, "ReviewPeriod": 12 } I want to write a regular expression or a function to convert it to a javascript object so that it is in the form: { "AlertDate": "AlertDate":new Date(1277334000000), "Progress": 1, "ReviewPeriod": 12 } The above date format fails validation in the JQuery parseJSON method. I would like to convert the 1277334000000+0100 into the correct number of milliseconds to create the correct date when eval is called after validation. Can anyone help me out with a good approach to solving this? Cheers Paul

  Read the article

• Split by Caps in Javascript,

  - by user1294188

  I am trying to split up a string by caps using Javascript, Examples of what Im trying to do: "HiMyNameIsBob" -> "Hi My Name Is Bob" "GreetingsFriends" -> "Greetings Friends" I am aware of the str.split() function, however I am not sure how to make this function work with capital letters. I've tried: str.split("(?=\\p{Upper})") Unfortunately that doesn't work, any help would be great.

  Read the article

• How do I test against a large number of regular expressions quickly and know which one matched?

  - by Jack

  I'm writing a program in .net where the user may provide a large number of regular expressions. For a given string, I need to figure out which regular expression matches that string (if more than one matches, I just need the first one that matches). However, if there are a large number of regular expressions this operation can take a very long time. I was somewhat hoping there would be something similar to flex for .net that would allow me to specify a large number of regular expressions yet quickly (O(n) according to Wikipedia for n = len(input string)) figure out which regular expression matches. Also, I would prefer not to implement my own regular expression engine :).

  Read the article

• Are there any way to apply regexp in java ignoring letter case?

  - by Roman

  Simple example: we have string "Some sample string Of Text". And I want to filter out all stop words (i.e. "some" and "of") but I don't want to change letter case of other words which should be retained. If letter case was unimportant I would do this: str.toLowerCase().replaceAll ("a|the|of|some|any", ""); Is there an "ignore case" solution with regular expressions in java?

  Read the article

• java phone number validation....

  - by user69514

  Here is my problem: Create a constructor for a telephone number given a string in the form xxx-xxx-xxxx or xxx-xxxx for a local number. Throw an exception if the format is not valid. So I was thinking to validate it using a regular expression, but I don't know if I'm doing it correctly. Also what kind of exception would I have to throw? Do I need to create my own exception? public TelephoneNumber(String aString){ if(isPhoneNumberValid(aString)==true){ StringTokenizer tokens = new StringTokenizer("-"); if(tokens.countTokens()==3){ areaCode = Integer.parseInt(tokens.nextToken()); exchangeCode = Integer.parseInt(tokens.nextToken()); number = Integer.parseInt(tokens.nextToken()); } else if(tokens.countTokens()==2){ exchangeCode = Integer.parseInt(tokens.nextToken()); number = Integer.parseInt(tokens.nextToken()); } else{ //throw an excemption here } } } public static boolean isPhoneNumberValid(String phoneNumber){ boolean isValid = false; //Initialize reg ex for phone number. String expression = "(\\d{3})(\\[-])(\\d{4})$"; CharSequence inputStr = phoneNumber; Pattern pattern = Pattern.compile(expression); Matcher matcher = pattern.matcher(inputStr); if(matcher.matches()){ isValid = true; } return isValid; } Hi sorry, yes this is homework. For this assignments the only valid format are xxx-xxx-xxxx and xxx-xxxx, all other formats (xxx)xxx-xxxx or xxxxxxxxxx are invalid in this case. I would like to know if my regular expression is correct

  Read the article

< Previous Page | 102 103 104 105 106 107 108 109 110 111 112 113  | Next Page >