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  • Javascript/Jquery - Reset text box view area after tab

    - by JK
    I don't know what this is called so its hard to google for it. If you have a plain html input type=text with a small width eg 20 and then type more characters than can be displayed, it shows the last characters you type. And the first ones are scrolled out of view: This is my long text // this is the whole string my long string // this is what is actually visible in the input box How do I make it so that when you hit tab, the view area resets so that the start of the string is visible and the end is hidden? my long string // this is what is visible in the input box when typing This is my // this is what is I want to be visible in the input box after you hit tab What do you call this, and how do you do it?

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  • Bind value between control in different view -- WPF / MVVM

    - by Tchoupi
    Hello! in my MVVM application (in wpf) i have two view and I want to bind the context of my label on my textbox value (in the other view) SelectorView.xaml contain this control: <TextBox x:Name="tbArt" value="XX"/> DescriptionView.xaml contain this control: <label context="{binding on the tbArt value????}"> Is that possible directly without going in code behing and viewmodels ? Will the label be refresh automatically ? Thanks !

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  • shouldAutorotateToInterfaceOrientation not working for detail view

    - by TheLearner
    I am using Xcode's SplitView template as the base for my project and I only want to accept Landscape mode. I have implemented the method in the RootViewController and DetailViewController: - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { switch (interfaceOrientation) { case UIInterfaceOrientationLandscapeLeft: return YES; } return NO; } However what happens is the app loads with in Landscape mode with the tableview on the left but the detail view is black / blank. How do I get the detailview to load properly and do I need to implement this method is all view controllers or just the root one?

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  • ASP.NET MVC 3 NOT showing appropriate view, action called using jquery

    - by TunAntun
    I have a small problem. My action is : public ViewResult SearchForRooms(int HotelDDL) { List<Room> roomsInHotel = bl.ReturnRoomsPerHotel(HotelDDL); return View(roomsInHotel); } Here is the jquery that is calling the action: <script type="text/javascript" language="javascript"> $(document).ready(function () { $("#HotelDDL").change(function () { var text = $("#HotelDDL option:selected").text(); var value = $("#HotelDDL option:selected").val(); alert("Selected text=" + text + " Selected value= " + value); $.post("/Home/SearchForRooms", { HotelDDL: $("#HotelDDL option:selected").val() }); }); }); </script> And finally, here is the View that should be called: @model IEnumerable<RoomReservation.Entities.Entities.Room> @{ ViewBag.Title = "Search"; } <h2>Result</h2> <table> <tr> <th> City </th> <th> Hotel </th> <th> Room label </th> <th> Number of beds </th> <th> Price per night </th> <th></th> </tr> @foreach (var item in Model) { <tr> <td> @Html.DisplayFor(modelitem=>item.Hotel.City.Name) </td> <td> @Html.DisplayFor(modelItem => item.Hotel.Name) </td> <td> @Html.DisplayFor(modelItem => item.Name) </td> <td> @Html.DisplayFor(modelItem => item.NumberOfBeds) </td> <td> @Html.DisplayFor(modelItem => item.PricePerNight) </td> </tr> } </table> Everthing is working ok (databse return all rooms correctly) except final view rendering. I have tried Phil's tool but it doesn't give me any suspicious hints: RouteDebug.RouteDebugger.RewriteRoutesForTesting(RouteTable.Routes); So, why is it not showing after jscript send it's post method to SearchForRooms()? Thank you P.S. If you need any other piece of code please just say so.

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  • Set cookie value before view loaded in MVC?

    - by James123
    I need to set a cookie value before my view called. otherwise I have to refresh the page to get cookie value in the view. The problem here is the value of cookie will get in controller. [HttpGet] [Route("Abstract/{meetingCode}")] [AllowAnonymous] public ActionResult Index(string meetingCode) { var meetingAbstract = new MeetingAbstract(); meetingAbstract.Meeting = _abstractContext.GetMeetingWithMeetingCode(meetingCode); if (meetingAbstract.Meeting != null) { var cookie = new HttpCookie("_culture"); cookie.Value = meetingAbstract.Meeting.language.language_locale_code;//"en-US"; cookie.Expires = DateTime.Now.AddDays(365); cookie.Path = "/"; this.ControllerContext.HttpContext.Response.Cookies.Add(cookie); ... Any other way without refresh the page again to set cookie value?

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  • To Switch To The Design View Of A Windows Form

    - by June
    Hi Friends I create new project in Windows Form Application using Visual Studio in VB.Net. I place some controls on my form. I don't write any code at this time. I close this project. When i open this project again , i found Form1.vb. I double-click that file , but the design view doesn't appear. I also find Form1.Designer.vb. What in this file is code. How can i switch to Design View of Form1 ? I need to write some codes for that form's objects like Button Click Event. June

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  • Removing item from a comma delimited string when removed from list view

    - by Yogender Siwach
    I'm using a combo box to select an item from a list of 25 items. The selected item is input in a text box in a comma delimited string. It is updating a list view and showing each item separately by breaking the comma delimited string. The text box is not visible to users but doing the work in back end. Now I want to remove any item from list view and want it so that the text box containing the comma delimited string should also change and remove that item from the string. Is it possible?

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  • how to view associated click function code

    - by llamerr
    For example, i associate following function with some element $('table#users tbody tr:first #save').click(function(){ $(this).closest('tr').remove(); }); Now, if i don't know where this function is stored, is there a way to view associated with click() code? In above example, i want a way to view that in firebug, or in another way $(this).closest('tr').remove(); If I'm writing in console following, i'm get a link to dom inspector >>> ($('table#users tbody tr:first #save').click) function() but link is for jquery library, not the code i want.

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  • When can I find out the width/height of my view

    - by michael
    When is the earliest I can find out the actual (after layout) width/height of my view? I tried to do that @Override protected void onFinishInflate() { super.onFinishInflate(); w = getWidth(); h = getHeight(); } But it gives me 0. I have cases in which the view is invisible in the beginning and that programmically become visible. I think I can do that in onDraw(), but i dont' want to do that in everything I draw() something.

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  • How to bring the mail composer view in between the view and tool bar in iphone?

    - by Warrior
    I am new to iphone development.I want a toolbar and a button in it.On clicking the button ,a mail compose view should open.I want the tool bar to be visible in the mail composer view.The mail composer should animate from back of the toolbar.How can i achieve that. Recently i saw a application,which implemented this.The mail emerges from back of the tool bar. In general which is more preferable for creating application like m need.Tabar or tool bar? any other method should i follow? Thanks.

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  • Looking for a mobile platform to view vector data and use it like a simple map

    - by Orchestrator
    I would like to develop or use an existing platform that will allow me to view custom vector data and use it as a map on mobile phones such as Android/IPhone (Maybe even WP7). I'm hoping that there's already a good infrastructure for what I need so I would not need to develop a whole infrastructure by myself. In Conclusion - Is there any existing platform that may answer my needs? If not, how would you guys suggest I should begin? How should I save my vector data? How could I read it? Should I view it with a graphics engine like OpenGL? Is there any chance this solution could be cross-platform? I know that it's possible since it was already done with apps like Waze. And it works the same on iOS and Android. Thanks!

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  • Python list recursion type error

    - by Jacob J Callahan
    I can't seem to figure out why the following code is giving me a TypeError: 'type' object is not iterable pastebin: http://pastebin.com/VFZYY4v0 def genList(self): #recursively generates a sorted list of child node values numList = [] if self.leftChild != 'none': numList.extend(self.leftChild.genList()) #error numList.extend(list((self.Value,))) if self.rightChild != 'none': numList.extend(self.rightChild.genList()) #error return numList code that adds child nodes (works correctly) def addChild(self, child): #add a child node. working if child.Value < self.Value: if self.leftChild == 'none': self.leftChild = child child.parent = self else: self.leftChild.addChild(child) elif child.Value > self.Value: if self.rightChild == 'none': self.rightChild = child child.parent = self else: self.rightChild.addChild(child) Any help would be appreciated. Full interpreter session: >>> import BinTreeNode as BTN >>> node1 = BTN.BinaryTreeNode(5) >>> node2 = BTN.BinaryTreeNode(2) >>> node3 = BTN.BinaryTreeNode(12) >>> node3 = BTN.BinaryTreeNode(16) >>> node4 = BTN.BinaryTreeNode(4) >>> node5 = BTN.BinaryTreeNode(13) >>> node1.addChild(node2) >>> node1.addChild(node3) >>> node1.addChild(node4) >>> node1.addChild(node5) >>> node4.genList() <class 'list'> >>> node1.genList() Traceback (most recent call last): File "<interactive input>", line 1, in <module> File "C:...\python\BinTreeNode.py", line 47, in genList numList.extend(self.leftChild.genList()) #error File "C:...\python\BinTreeNode.py", line 52, in genList TypeError: 'type' object is not iterable

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  • Avoiding sub-type selection in view code

    - by John Donoghue
    Hi, I have some code where the model contains some classes like (vb.net pseudocode, but could be any OO language): Enum AttributeType Boolean Date String End Enum MustInherit Class Attibute Must Override Function Type As AttributeType End Class Class BooleanAttribute: Attribute Function Type As AttributeType Return AttributeType.Boolean End Function End Class And the view contains some code like: Select Case AttributeType Case Boolean //Display checkbox control Case Date //Display date picker control Case String //Display textbox control End Select I don't really like the code in the view, for the hopefully obvious reasons (what happens when I get a new attribute type etc). My question is, how should I replace it? I could easily add a method to the concrete classes, but that pollutes the model with UI stuff so that's a horrible idea. I could move the select into a factory, but that seems to be just hiding the problem. Can anybody advise a better approach?

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  • Saving a modified object from ASP.NET MVC View Using Entity-Franework 4

    - by Dani
    I retrieve an object graph from DB using EF4. The context is closed as soon as the data retrieve and the data passes to the controller, and then to the view. in the view the data is modified, and then the controller gets it back. From the controller I run Repository.Update(MyEmp); and in my repository the code goes: using (var context = new mydb()) { if (myEmp.ID != 0) // Checking if it's modified or new { context.Emp.Attach(MyEmp); int result = context.SaveChanges(); return myEmp.ID; } } The problem - once attached, the object entityState goes to unchanged, and not modified, and of course - nothing is saved to the database. What am I doing wrong ?

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  • Get current user from View

    - by gosu kiwi
    So what I want to do is, in my main layout, have a menu for logged in users, and a different for anon users. THe layout will be used on every page, so I'm not sure how to do this, as I've seen, the Auth Component can only be used in the controller, this would be nice if I had to do this in only one view, but for every view, how can I do this? Do I have to do something on AppController? What I want to do is basically // layout <?php if(logged): ?> Welcome <?php echo $user; ?> <?php else: ?> Welcom anon, Log in? <?php endif; ?>

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  • How to release my view from stack ?

    - by aman-gupta
    Hi, In my application I m using following coding convention to open my default screen :-- AppDelegate *ptrDefaultScreen = (AppDelegate *)[[UIApplication sharedApplication]delegate]; [self.navigationController presentModalViewController:ptrDefaultScreen.FrmFlashScreenLink animated:YES]; but when I move to other screen after default screen ,my default screen is still exists even i used [self dismissModelViewController:YES]; to dimiss default screen from view. where I m wrong I want my default screen will be completely removed from view. Is any other way to call default screen before actual application. Please help me out.Thanks in advance

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  • iPhone - At user event create objects in the view

    - by insaneshow
    Hello, I am new to iPhone programming, so I think part of the problem is that I don't know what I really want to google to find my answer. I am looking for a method that allows a user to draw a line on the screen. There is no guarantee that it will be straight, it can be curved or whatever. I was thinking that I could create some small square image, and then as they draw, place them into a NSset. But I am not really sure how to communicate each new object up to the view. Up to this point, I've just been messing around with objects I put on the view and then assign movement to those, this is my first jump into on-the-fly object creation. It might be that I just need to jump into a class/object type or even a tutorial, any guidance would be great. Thanks!

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  • How to move to another view without using a button

    - by Will
    My first view displays an image and action indicator while web-servers and database function are run in that background. I want the application to go to my tab view when the functions have been completed. How do I do this? Here is what the views look like. What I have tried: TabBarViewController *tab = [[TabBarViewController alloc]init]; [self presentViewController:tab animated:NO completion:nil]; and [self performSegueWithIdentifier:@"first" sender:self]; Please can you help my to understand how to do this. I have spent many hours googling this problem and couldn't work out how to do it. Thanks EDIT: Added Code

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  • ERROR: there is no parameter $1 when creating view

    - by idlemoments
    When we try to create a view within a funcion we get ERROR: there is no parameter $1. This is the sample code. Begin CREATE VIEW artikelnr AS SELECT datum, 'uitgifte' as "type", CASE WHEN 'test'='test' THEN 0 END as "aantal ontvangen", aantal as "aantal uitgegeven" FROM uitgifteregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN uitgifte ON uitgifte.uitgiftenr = uitgifteregel.uitgiftenr UNION SELECT datum, 'ontvangst' as "type", aantal as "aantal ontvangen" , CASE WHEN 'test'='test' THEN 0 END as "aantal uitgegeven" FROM ontvangstregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN ontvangst ON ontvangst.ontvangstnr = ontvangstregel.ontvangstnr; Return new; end; When we replace new.artikelnr on line 7 with value 1 it works like it should, but the function needs to work with different artikelnr's. example line 7: JOIN artikel ON artikel.artikelnr = new.artikelnr Please point us in the right direction.

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  • A Map of View instances?

    - by user291701
    Is it possible to keep references to views keyed off of their hashCode? Something like: Map<Integer, View> views; views.put(view1.hashCode(), view1); views.put(view2.hashCode(), view2); views.put(viewN.hashCode(), viewN); I have a few in my view hierarchy and am downloading images for each. I want to be able to iterate over them quickly, or see if I've already previously added one (hence the map).

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  • Insertion into BST without header Node JAVA

    - by Petiatil
    I am working on a recursive insertion method for a BST. This function is suppose to be a recursive helper method and is in a private class called Node. The Node class is in a class called BinarySearchTree which contains an instance variable for the root. When I am trying to insert an element, I get a NullPointerException at : this.left = insert(((Node)left).element); I am unsure about why this occurs. If I understand correctly, in a BST, I am suppose to insert the item at the last spot on the path transversed. Any help is appreciated! private class Node implements BinaryNode<E> { E item; BinaryNode<E> left, right; public BinaryNode<E> insert(E item) { int compare = item.compareTo(((Node)root).item); if(root == null) { root = new Node(); ((Node)root).item = item; } else if(compare < 0) { this.left = insert(((Node)left).item); } else if(compare > 0) { this.right = insert(((Node)right).item); } return root; } }

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