Search Results

Search found 3921 results on 157 pages for 'partner ordering portal'.

Page 104/157 | < Previous Page | 100 101 102 103 104 105 106 107 108 109 110 111  | Next Page >

• How extension methods work in background ?

  - by Freshblood

  I am just cuirous about behind of extension method mechanism.Some questions and answer appear in my mind. MyClass.OrderBy(x=>x.a).OrderBy(x=>x.b); I was guessing that mechanism was first orderby method works and order them by a member then returns sorted items in IEnumarable interface then next Orderby method of IEnumarable Order them for b paramater.But i am wrong when i look at this linq query. MyClass.Orderby(x=>x.a).ThenOrderBy(x=>x.b); this is slightly different and tells me that i am wrong.Because this is not ordering by a then b and not possible to have such result if i was right.This get me confuse enough... Similiar structure is possible to write withot extension methods as first query but second is not possible.This prove i am wrong . Can u explain it ?

  Read the article

• Get a queryset of objects through an intermediary model

  - by skyl

  I want get all of the Geom objects that are related to a certain content_object (see the function I'm trying to build at the bottom, get_geoms_for_obj() class Geom(models.Model): ... class GeomRelation(models.Model): ''' For tagging many objects to a Geom object and vice-versa''' geom = models.ForeignKey(Geom) content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey() def get_geoms_for_object(obj): ''' takes an object and gets the geoms that are related ''' ct = ContentType.objects.get_for_model(obj) id = obj.id grs = GeomRelation.objects.filter( content_type=ct, object_id=id ) # how with django orm magic can I build the queryset instead of list # like below to get all of the Geom objects for a given content_object geoms = [] for gr in grs: geoms.append(gr.geom) return set(geoms) # A set makes it so that I have no redundant entries but I want the # queryset ordering too .. need to make it a queryset for so many reasons...

  Read the article

• MySQL query for initial filling of order column

  - by Sejanus

  Sorry for vague question title. I've got a table containing huge list of, say, products, belonging to different categories. There's a foreign key column indicating which category that particular product belongs to. I.e. in "bananas" row category might be 3 which indicates "fruits". Now I added additional column "order" which is for display order within that particular category. I need to do initial ordering. Since the list is big, I dont wanna change every row by hand. Is it possible to do with one or two queries? I dont care what initial order is as long as it starts with 1 and goes up. I cant do something like SET order = id because id counts from 1 up regardless of product category and order must start anew from 1 up for every different category.

  Read the article

• DB function failed with error number 1 in joomla admin panel

  - by sabuj

  When i access joomla article manager or module manager then i had faced the bellow output: 500 - An error has occurred! DB function failed with error number 1 Can't create/write to file '/tmp/#sql_57c0_0.MYD' (Errcode: 17) SQL=SELECT c.*, g.name AS groupname, cc.title AS name, u.name AS editor, f.content_id AS frontpage, s.title AS section_name, v.name AS author FROM jos_content AS c LEFT JOIN jos_categories AS cc ON cc.id = c.catid LEFT JOIN jos_sections AS s ON s.id = c.sectionid LEFT JOIN jos_groups AS g ON g.id = c.access LEFT JOIN jos_users AS u ON u.id = c.checked_out LEFT JOIN jos_users AS v ON v.id = c.created_by LEFT JOIN jos_content_frontpage AS f ON f.content_id = c.id WHERE c.state != -2 ORDER BY section_name , section_name, cc.title, c.ordering LIMIT 0, 20

  Read the article

• Django. default=datetime.now() problem

  - by Shamanu4

  Hello. I've such db model: from datetime import datetime class TermPayment(models.Model): dev_session = models.ForeignKey(DeviceSession, related_name='payments') user_session = models.ForeignKey(UserSession, related_name='payment') date = models.DateTimeField(default=datetime.now(),blank=True) sum = models.FloatField(default=0) cnt = models.IntegerField(default=0) class Meta: db_table = 'term_payments' ordering = ['-date'] and here new instance is added: # ... tp = TermPayment() tp.dev_session = self.conn.session # device session hash tp.user_session = self.session # user session hash tp.sum = sum tp.cnt = cnt tp.save() But i've a problem: all records in database have the same value in date field - the date of the first payment. After server restart - one record have new date and others have the same as first after restart. It's look like some data cache is using but I can't found where. database: mysql 5.1.25 django v1.1.1

  Read the article

• SQL query to print mirror labels

  - by Eric

  I want to print labels in words as returned by a SQL query such as follow. 1 2 3 4 5 6 When I want to print the reverse of those labels, I have to print them as follow 3 2 1 6 5 4 In my real case, I have 5 colums by 2 rows, how can I formulate my query so that my records are ordered like the second one. The normal ordering is handled by word, so my query is like SELECT * FROM Products ORDER BY Products.id I'm using MS Access =( EDIT : Just to make it clear I'd like my records to be ordered such as 3 2 1 6 5 4 9 8 7 12 11 10 EDIT2 : my table looks like this ID ProductName 1 Product1 2 Product2 3 Product3 n Product[n] I want the ids to be returned as I mentioned above

  Read the article

• Divide numpy array

  - by BandGap

  Hi all I have some data represented in a 1300x1341 matrix. I would like to split this matrix in several pieces (e.g. 9) so that I can loop over and process them. The data needs to stay ordered in the sense that x[0,1] stays below (or above if you like) x[0,0] and besides x[1,1]. Just like if you had imaged the data, you could draw 2 vertical and 2 horizontal lines over the image to illustrate the 9 parts. If I use numpys reshape (eg. matrix.reshape(9,260,745) or any other combination of 9,260,745) it doesn't yield the required structure since the above mentioned ordering is lost... Did I misunderstand the reshape method or can it be done this way? What other pythonic/numpy way is there to do this?

  Read the article

• Side effects of reordering columns in PostgreSQL

  - by Summer

  I sometimes re-order the columns in my Postgres DB. Since Postgres can only add columns at the end of tables, I end up re-ordering by adding new columns at the end of the table, setting them equal to existing columns, and then dropping the original columns. My question is: what does PostgreSQL do with the memory that's freed by dropped columns? Does it automatically re-use the memory, so a single record consumes the same amount of space as it did beforehand? But that would require a re-write of the whole table, so to avoid that, does it just keep a bunch of blank space around in each record? Thanks! ~S

  Read the article

• Django admin page dropdowns

  - by zen

  I am building a high school team application using Django. Here is my working models file: class Directory(models.Model): school = models.CharField(max_length=60) website = models.URLField() district = models.SmallIntegerField() conference = models.ForeignKey(Conference) class Conference(models.Model): conference_name = models.CharField(max_length=50) url = models.URLField() class Meta: ordering = ['conference_name'] When I open my admin pages and go to edit a school's conference the drop down looks like this: <select> <option value="1">Conference Object</option> <option value="2">Conference Object</option> <select> How do I replace "Conference Object" with the conference_name?

  Read the article

• heirarchial data from self referencing table in tree form

  - by Beta033

  Ii looks like this has been asked and answered in all the simple cases, excluding the one that i'm having trouble with. I've tried using a recursive CTE to generate this, however maybe a cursor would be better? or maybe a set of recursive functions will do the trick? Can this be done in a cte? consider the following table PrimaryKey ParentKey 1 NULL 2 1 3 6 4 7 5 2 6 1 7 NULL should yield PK 1 -2 --5 -6 --3 7 -4 where the number of - marks equal the depth, my primary difficulty is the ordering.

  Read the article

• django - order query set by postgres function

  - by thebiglife

  My initial question was here and was related to the postgres backend. http://stackoverflow.com/questions/2408965/postgres-subquery-ordering-by-subquery Now my problem has moved onwards to the Django ORM layer. I essentially want to order a query by a postgres function ('idx', taken from the above stackoverflow work) I've gone through trying to use model.objects.extra(order_by ) or simply order_by but I believe both of these need the order_by parameter to be an attribute or a field known to Django. I'm trying to think how to solve this without having to revert to using an entirely raw SQL query through a model manager.

  Read the article

• Cocoa - Localized string from NSDate, NSCalendarDate...

  - by SirRatty

  I'm using NSDate to get a string such as "18 Jun 09", with code: NSDate *theDate = [NSDate date]; NSString *dateString = [theDate descriptionWithCalendarFormat:@"%d %b %y" timeZone:nil locale: nil]; This works, but only results in an English output. I need the output to be localized in the user's default language. Does Cocoa (Mac OS X 10.4, 10.5 in this case) provide a facility for this localization or do I have to manually localize for each case of day and & month names my self? (I have provided a locale, but although that does provide a locale-specific ordering of the date, it does not appear to do any localization of day-month names.)

  Read the article

• Jquery UI Sortable Item Contents

  - by bluedaniel

  So I have this shopping list coded in php and js: http://www.whatcouldicook.com/recipes/planner So people can add, delete or sort the list and thats fine, I dont want multiple lists and instead just have a list item containing a heading tag to represent a new list. All this works and then using serialize I can save the ordering/modifying of the list. I don't know how to get the list contents however as these will be dynamic from the user. All the code is on that url so hopefully you can examine the code there. Thanks everyone

  Read the article

• second sorting with php usort

  - by bluedaniel

  So Ive got a pretty big array of data and need to sort them by two criteria. There is variable $data['important'] and $data['basic']. They are simple numbers and I am using uasort to sort $data firstly by important and then by basic. So Important | Basic 10 | 8 9 | 9 9 | 7 7 | 9 The usort function is a simple public function sort_by_important($a, $b) { if ($a[important] > $b[important]) { return -1; } elseif ($b[important] > $a[important]) { return 1; } else { return 0; } } How can I re-sort the array to the second variable and keep the Important ordering? Thanks everyone. EDIT How about adding a third sorting option after this even? So Important Basic Less

  Read the article

• Is it possible to override a property and return a derived type in VB.NET?

  - by Casey

  Consider the following classes representing an Ordering system: Public Class OrderBase Public MustOverride Property OrderItem() as OrderItemBase End Class Public Class OrderItemBase End Class Now, suppose we want to extend these classes to a more specific set of order classes, keeping the aggregate nature of OrderBase: Public Class WebOrder Inherits OrderBase Public Overrides Property OrderItem() as WebOrderItem End Property End Class Public Class WebOrderItem Inherits OrderItemBase End Class The Overriden property in the WebOrder class will cause an error stating that the return type is different from that defined in OrderBase... however, the return type is a subclass of the type defined in OrderBase. Why won't VB allow this?

  Read the article

• Ruby w/ Postgres & Sinatra - Query won't order right with parameter??

  - by alleywayjack

  So I set a variable in my main ruby file that's handling all my post and get requests and then use ERB templates to actually show the pages. I pass the database handler itself into the erb templates, and then run a query in the template to get all (for this example) grants. In my main ruby file: grants_main_order = "id_num" get '/grants' do erb :grants, :locals => {:db=>db, :order=>grants_main_order, :message=>params[:message]} end In the erb template: db = locals[:db] getGrants = db.exec("SELECT * FROM grants ORDER BY $1", [locals[:order]]) This produces some very random ordering, however if I replace the $1 with id_num, it works as it should. Is this a typing issue? How can I fix this? Using string replacement with #{locals[:order]} also gives funky results.

  Read the article

• Jquery prettyPhoto and star conflict....DOM not loading?

  - by Dustin

  I'm working on an online ordering system for photography clients: Here. (Forgive the requirement of having to sign in). After signing in, the user is able to rate pictures using the stars listed below each picture, then subsequently view 3 star pics, or 4 star pics, etc. However, when the user clicks on an image, a lightbox expands (prettyPhoto namely) which contains the picture as well as the stars listed below. I want users to be able to star a picture within the lightbox, but the javascript is not being passed after the prettyPhoto lightbox is initialized. Consequently, they can't rate pictures within the lightbox. I've heard of something similar to this, but have no idea about how to go about tackling the problem. Any help would be appreciated. Thanks!

  Read the article

• Setting a preferred item of a many-to-one in Django

  - by Mike DeSimone

  I'm trying to create a Django model that handles the following: An Item can have several Names. One of the Names for an Item is its primary Name, i.e. the Name displayed given an Item. (The model names were changed to protect the innocent.) The models.py I've got looks like: class Item(models.Model): primaryName = models.OneToOneField("Name", verbose_name="Primary Name", related_name="_unused") def __unicode__(self): return self.primaryName.name class Name(models.Model): item = models.ForeignKey(Item) name = models.CharField(max_length=32, unique=True) def __unicode__(self): return self.name class Meta: ordering = [ 'name' ] The admin.py looks like: class NameInline(admin.TabularInline): model = Name class ItemAdmin(admin.ModelAdmin): inlines = [ NameInline ] admin.site.register(Item, ItemAdmin) It looks like the database schema is working fine, but I'm having trouble with the admin, so I'm not sure of anything at this point. My main questions are: How do I explain to the admin that primaryName needs to be one of the Names of the item being edited? Is there a way to automatically set primaryName to the first Name found, if primaryName is not set, since I'm using inline admin for the names?

  Read the article

• One account, multiple users, multiple shopping cart in a web application

  - by lemotdit

  I received a somewhat unusual request (imo) for a transactional web site. I have to implement the possibility of having multiple shopping cart for the same user. Those really are shopping carts, not order templates. I.E: A store with several departments ordering under the same account, but with a different person placing orders for a specific department only. Having more than one user per account is not an option since it would involve 'too much' management from the stores owner and the admins. Anyone had to deal with this before? The option so far is to have names for shopping cart, and a dropdown list or something alike after login to choose the cart with some kind of 'busy flag' to lock the cart if it's in use in another session.

  Read the article

• What is the effect on record size of reordering columns in PostgreSQL?

  - by Summer

  Since Postgres can only add columns at the end of tables, I end up re-ordering by adding new columns at the end of the table, setting them equal to existing columns, and then dropping the original columns. So, what does PostgreSQL do with the memory that's freed by dropped columns? Does it automatically re-use the memory, so a single record consumes the same amount of space as it did before? But that would require a re-write of the whole table, so to avoid that, does it just keep a bunch of blank space around in each record? Thanks! ~S

  Read the article

• What wiki tools exist to generate shippable user doc from a wiki?

  - by tletnes

  I am looking into using a wiki (prefer mediawiki, but not a req.) as the repository for developer generated documentation (User Guides, Release Notes, Application Notes, Errata, etc.) from a collaborative/easy-to-update point of view a wiki seems like a good match, however since this documentation will ultimately ship to customers we want to be able to export the documents in their final state (e.g. during the release cycle) to static versions that no longer include histories. Ideally the export would leave the document n a form where errors could be easily fixed by a non-programmer It would be good if niceties like section ordering and table of contents were available, or easy to add after the fact. Are any tools with features like these avalible?

  Read the article

• Linq To SQL: Retain list order when using .Contains

  - by rockinthesixstring

  I'm using Lucene.net to build a MyListOfIds As List(Of Integer) which I then pass on to my Linq service. I then search the database as follows Return _EventRepository.Read().Where(Function(e) MyListOfIds.Contains(e.ID)).ToList Now I know that Lucene is already ordering MyListOfIds based on the weight it gave each term. What sucks is that Linq is losing that order in it's SQL search. My Question: How can I retain that sort order when building my Lambda expression? I tried using LINQPad to see how the query is being built, but because I had to declare a variable LINQPad didn't show me the resultant SQL :-( Here's what I tried in LINQPad Dim i As New List(Of Integer) i.Add(1) i.Add(100) i.Add(15) i.Add(3) i.Add(123) Dim r = (From e In Events Where i.Contains(e.ID) Select e) note: my example is in VB.NET, but I don't mind if responses are in C#

  Read the article

• Is there a single query that can update a "sequence number" across multiple groups?

  - by Drarok

  Given a table like below, is there a single-query way to update the table from this: | id | type_id | created_at | sequence | |----|---------|------------|----------| | 1 | 1 | 2010-04-26 | NULL | | 2 | 1 | 2010-04-27 | NULL | | 3 | 2 | 2010-04-28 | NULL | | 4 | 3 | 2010-04-28 | NULL | To this (note that created_at is used for ordering, and sequence is "grouped" by type_id): | id | type_id | created_at | sequence | |----|---------|------------|----------| | 1 | 1 | 2010-04-26 | 1 | | 2 | 1 | 2010-04-27 | 2 | | 3 | 2 | 2010-04-28 | 1 | | 4 | 3 | 2010-04-28 | 1 | I've seen some code before that used an @ variable like the following, that I thought might work: SET @seq = 0; UPDATE `log` SET `sequence` = @seq := @seq + 1 ORDER BY `created_at`; But that obviously doesn't reset the sequence to 1 for each type_id. If there's no single-query way to do this, what's the most efficient way? Data in this table may be deleted, so I'm planning to run a stored procedure after the user is done editing to re-sequence the table.

  Read the article

• Sorting a value pair in Javascript

  - by Bradley M. Davis

  I must be missing the proper term or else I'm sure I could find the answer by searching... in any case, here's what I want to do. Through javascript, I get four variables (A, B, C, and D) that I would like to sort, and still keep track of the variable name (since it's encoded with meaning information). Sample Data: A = 2; B = 1; C = 4; D = 3; What I need to do now is sort them in value order (4,3,2,1) such that I can actually know the variable name ordering (C,D,A,B).

  Read the article

• Does this have anything to do with endian-ness?

  - by eSKay

  This piece of code: #include<stdio.h> void hello() { printf("hello\n"); } void bye() { printf("bye\n"); } int main() { printf("%p\n", hello); printf("%p\n", bye); return 0; } output on my machine: 0x80483f4 0x8048408 [second address is bigger in value] on Codepad 0x8048541 0x8048511 [second address is smaller in value] Does this have anything to do with endian-ness of the machines? If not, Why the difference in the ordering of the addresses? Also, Why the difference in the difference? 0x8048541 - 0x8048511 = 0x30 0x8048408 - 0x80483f4 = 0x14 Btw, I just checked. This code (taken from here) says that both the machines are Little-Endian #include<stdio.h> int main() { int num = 1; if(*(char *)&num == 1) printf("Little-Endian\n"); else printf("Big-Endian\n"); return 0; }

  Read the article

< Previous Page | 100 101 102 103 104 105 106 107 108 109 110 111  | Next Page >