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  • How to check if something is stored in CoreData

    - by Terrel Gibson
    Hi I want to be able to tore some information in core data and but i am unsure of how to check if the file was saved properly. I tried using NSLog but it returns null when its called. I have a dictionary which has a uniqueID and a title which I want to save. I pass this in along with the context of the database. I then sort the database to check if it has any duplicates or not, if not then I add the file. +(VacationPhoto*) photoWithFlickrInfo: (NSDictionary*) flickrInfo inManagedObjectContext: (NSManagedObjectContext*) context{ //returns the dictionary NSLog(@"Photo To Store =%@", flickrInfo); VacationPhoto * photo = nil; NSFetchRequest *request = [NSFetchRequest fetchRequestWithEntityName:@"VacationPhoto"]; request.predicate = [NSPredicate predicateWithFormat:@"uniqueID = %@", [flickrInfo objectForKey:FLICKR_PHOTO_ID]]; NSSortDescriptor * descriptor = [NSSortDescriptor sortDescriptorWithKey:@"title" ascending:YES]; request.sortDescriptors = [NSArray arrayWithObject:descriptor]; NSError *error = nil; NSArray *matches = [context executeFetchRequest:request error:&error]; if (!matches || [matches count] > 1) { // handle error } else if ( [matches count] == 0){ photo.title = [flickrInfo objectForKey:FLICKR_PHOTO_TITLE]; //Returns NULL when called NSLog(@"title = %@", photo.title); photo.uniqueID = [flickrInfo objectForKey:FLICKR_PHOTO_ID]; //Returns NULL when called NSLog(@"ID = %@", photo.uniqueID); } else { //If photo already exists this is called photo = [matches lastObject]; } return photo; }

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  • JSP template inheritance

    - by Ryan
    Coming from a background in Django, I often use "template inheritance", where multiple templates inherit from a common base. Is there an easy way to do this in JSP? If not, is there an alternative to JSP that does this (besides Django on Jython that is :) base template <html> <body> {% block content %} {% endblock %} </body> <html> basic content {% extends "base template" %} {% block content %} <h1>{{ content.title }} <-- Fills in a variable</h1> {{ content.body }} <-- Fills in another variable {% endblock %} Will render as follows (assuming that conten.title is "Insert Title Here", and content.body is "Insert Body Here") <html> <body> <h1>Insert title Here <-- Fills in a variable</h1> Insert Body Here <-- Fills in another variable </body> <html>

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  • custom rss feed suddenly does not work anymore

    - by krike
    I just don't understand what's happening, I haven't change anything to the site for a few months but now suddenly the rss feed doesn't work anymore. I create a php file with the following code: header('Content-type: text/xml'); include("config/config.inc.php"); $result = mysqli_query($link, "SELECT * FROM tutorials ORDER BY tutorial_id DESC LIMIT 50"); ?> <rss version="2.0"> <channel> <title>CMS tutorial site</title> <description>Bringing you the best CMS tutorials from the web</description> <link>http://cmstutorials.org</link> <?php while($row = mysqli_fetch_object($result)) { $user = mysqli_fetch_object(mysqli_query($link, "SELECT * FROM user_extra WHERE userid=".$row->user_id."")); ?> <item> <title><?php echo $row->title; ?></title> <author><?php echo $user->username; ?></author> <description><?php echo $row->description; ?></description> <pubDate><?php echo $row->date; ?></pubDate> <link>http://cmstutorials.org/view_tutorial.php?tutorial_id=<?php echo $row->tutorial_id; ?></link> </item> <?php } ?> </channel> </rss> I checked the query by executing it in phpmyadmin and it works, doesn't give any error. When I delete the header content type and the rss tag it will print out each line from the query but the feed won't display anything this is the link of the feed http://cmstutorials.org/rss (or http://cmstutorials.org/rss.php)

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  • constructing a recursive function returning an array

    - by Admiral Kunkka
    I'm developing a function that has a random chance to loop through itself and put it's results in one array for me to use later in my PHP class. Is there a better way to do this more organized, specifically case 5. The array becomes sloppy if it rolls 5, after 5, after 5 looking unpleasant. private function dice($sides) { return mt_rand(1, $sides); } private function randomLoot($dice) { switch($dice) { case 1: $array[] = "A fancy mug."; break; case 2: $array[] = "A buckler."; break; case 3: $array[] = "A sword."; break; case 4: $array[] = "A jewel."; break; case 5: $array[] = "A treasure chest with contents:"; $count = $this->dice(3); $i = 1; while($i <= $count) { $array[] = $this->randomLoot($this->dice(5)); $i++; } break; } return $array; }

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  • how to remove repeated record's from results linq to sql

    - by Sadegh
    hi, i want to remove repeated record's from results but distinct don't do this for me! why??? var results = (from words in _Xplorium.Words join wordFiles in _Xplorium.WordFiles on words.WordId equals wordFiles.WordId join files in _Xplorium.Files on wordFiles.FileId equals files.FileId join urls in _Xplorium.Urls on files.UrlId equals urls.UrlId where files.Title.Contains(query) || files.Description.Contains(query) orderby wordFiles.Count descending select new SearchResultItem() { Title = files.Title, Url = urls.Address, Count = wordFiles.Count, CrawledOn = files.CrawledOn, Description = files.Description, Lenght = files.Lenght, UniqueKey = words.WordId + "-" + files.FileId + "-" + urls.UrlId }).Distinct();

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  • Rails belongs_to issue in the views

    - by Jacobo Tibaquira
    Hi, Im having problems with an association in rails: Currently I have Post and User models, and the relationship is set this way: class User < ActiveRecord::Base attr_accessible :username, :name, :lastname has_many :posts end class Post < ActiveRecord::Base attr_accessible :title, :body belongs_to :user end However, in my app/views/posts/index.html.haml when Im trying to access the username for the post I get this error: undefined method `name' for nil:NilClass This is my view: - title "Posts" %table %tr %th Title %th Body %th Author - for post in @posts %tr %td= h post.title %td= h post.body %td= h post.user.name %td= link_to 'Show', post %td= link_to 'Edit', edit_post_path(post) %td= link_to 'Destroy', post, :confirm => 'Are you sure?', :method => :delete %p= link_to "New Post", new_post_path Any thoughts of what Im doing wrong will be appretiated

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  • iphone how to customize UITableViewCell cell.textlabel and cell.detailtextlabel programmatically

    - by Prerak
    Hi! In my iPhone App In table view cell I want to dispaly one main title and 5 subtitlessubtitles suppose item1 as main title and item2 , item3 , item4 , item5 and item6 as subtitles, for that i have saperate two arrays for passing the values in table view cell one for cell.textLabel.text= second for cell.detailTextLabel.text now I want the flexibility to make item2 as maintitle and want to add item1 to subtitle How can I set title and subtitle programmatically from single array? and any of them as Please Help and Suggest, Thank You.

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  • Parsing XML wont display all items.

    - by Nauman A
    I have this code but the toast wont display any message what is wrong with my code.. I can get the value from link, linknext but title wont bring out any value. ( I am not very bright with writing code so please suggest anything you may feel like. final Button button = (Button) findViewById(R.id.Button01); button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { // Perform action on click try { URL url = new URL( "http://somelink.com=" + Link.setFirst_link); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.parse(new InputSource(url.openStream())); doc.getDocumentElement().normalize(); NodeList nodeList = doc.getElementsByTagName("item"); /** Assign textview array lenght by arraylist size */ for (int i = 0; i < nodeList.getLength(); i++) { Node node = nodeList.item(i); Element fstElmnt = (Element) node; NodeList nameList = fstElmnt.getElementsByTagName("link"); Element nameElement = (Element) nameList.item(0); nameList = nameElement.getChildNodes(); String img = (((Node) nameList.item(0)).getNodeValue()); NodeList websiteList = fstElmnt.getElementsByTagName("linknext"); Element websiteElement = (Element) websiteList.item(0); websiteList = websiteElement.getChildNodes(); String nextlink = (((Node) websiteList.item(0)).getNodeValue()); Link.setFirst_link = nextlink; Drawable drawable = LoadImageFromWebOperations(img); imgView.setImageDrawable(drawable); NodeList titleList = fstElmnt.getElementsByTagName("title"); Element titleElement = (Element) titleList.item(0); websiteList = titleElement.getChildNodes(); String title = (((Node) titleList.item(0)).getNodeValue()); Context context = getApplicationContext(); CharSequence text = title; int duration = Toast.LENGTH_SHORT; Toast toast = Toast.makeText(context, text, duration); toast.show(); } } catch (Exception e) { System.out.println("XML Pasing Excpetion = " + e); } } }); /** Set the layout view to display */ } Here is the xml file <?xml version="1.0"?> <maintag> <item> <link>http://image.com/357769.jpg?40</link> <linknext>http://www.image.com</linknext> <title>imagename</title> </item> </maintag>

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  • Generating 8000 text files from xml files

    - by Ray
    Hi all, i need to generate the same number of text files as the xml files i have. Within the text files, i need the title and maybe some other tags of it. I can generate text files with the elements i wanted but not all xml files can be generated. Only some of them are generated. Something might be wrong with my parser so help out please thanks. This is my code. Please have a look and give me suggestions. Thanks in advance. import java.io.File; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import org.w3c.dom.*; import java.io.*; public class AccessingXmlFile1 { public static void main(String argv[]) { try { //File file = new File("C:\\MyFile.xml"); // create a file that is really a directory File aDirectory = new File("C:/Documents and Settings/I2R/Desktop/test"); // get a listing of all files in the directory String[] filesInDir = aDirectory.list(); System.out.println(""+filesInDir.length); // sort the list of files (optional) // Arrays.sort(filesInDir); //////////////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////////////// // have everything i need, just print it now for ( int a=0; a<filesInDir.length; a++ ) { String xmlFile = filesInDir[a]; String newLine = System.getProperty("line.separator"); File file = new File(xmlFile); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document document = db.parse(file); document.getDocumentElement().normalize(); //System.out.println("Root element " + document.getDocumentElement().getNodeName()); NodeList node = document.getElementsByTagName("metadata"); System.out.println("Information of Xml File"); System.out.println(xmlFile.substring(0, xmlFile.length() - 4)); //////////////////////////////////////////////////////////////////////////////////// String titleStoreText = ""; String descriptionStoreText = ""; String collectionStoreText = ""; String textToWrite = ""; //////////////////////////////////////////////////////////////////////////////////// for (int i = 0; i < node.getLength(); i++) { Node firstNode = node.item(i); if (firstNode.getNodeType() == Node.ELEMENT_NODE) { Element element = (Element) firstNode; NodeList titleElementList = element.getElementsByTagName("title"); Element titleElement = (Element) titleElementList.item(0); NodeList title = titleElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(titleElement == null) titleStoreText = " There is no title for this file."+ newLine; else titleStoreText = titleStoreText+((Node) title.item(0)).getNodeValue() + newLine; //titleStoreText = titleStoreText+((Node) title.item(0)).getNodeValue()+ newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Title : " + titleStoreText); NodeList collectionElementList = element.getElementsByTagName("collection"); Element collectionElement = (Element) collectionElementList.item(0); NodeList collection = collectionElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(collectionElement == null) collectionStoreText = " There is no collection for this file."+ newLine; else collectionStoreText = collectionStoreText+((Node) collection.item(0)).getNodeValue() + newLine; //collectionStoreText = collectionStoreText+((Node) collection.item(0)).getNodeValue()+ newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Collection : " + collectionStoreText); NodeList descriptionElementList = element.getElementsByTagName("description"); Element descriptionElement = (Element) descriptionElementList.item(0); NodeList description = descriptionElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(descriptionElement == null) descriptionStoreText = " There is no description for this file."+ newLine; else descriptionStoreText = descriptionStoreText+((Node) description.item(0)).getNodeValue() + newLine; //descriptionStoreText = descriptionStoreText+((Node) description.item(0)).getNodeValue() + newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Description : " + descriptionStoreText); //////////////////////////////////////////////////////////////////////////////////// textToWrite = "=====Title=====" + newLine + titleStoreText + newLine + "=====Collection=====" + newLine + collectionStoreText + newLine + "=====Description=====" + newLine + descriptionStoreText;// + newLine + "=====Subject=====" + newLine + subjectStoreText; //////////////////////////////////////////////////////////////////////////////////// } } ///////////////////////////////////////////write to file part is here///////////////////////////////////////// Writer output = null; File file2 = new File(xmlFile.substring(0, xmlFile.length() - 4)+".txt"); output = new BufferedWriter(new FileWriter(file2)); output.write(textToWrite); output.close(); System.out.println("Your file has been written"); //////////////////////////////////////////////////////////////////////////////////// } } catch (Exception e) { e.printStackTrace(); } } }

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  • Noob - Cycle through stored names and skip blanks

    - by ActiveJimBob
    NOOB trying to make my code more efficient. On scroll button push, the function 'SetName' stores a number to integer 'iName' which is index against 5 names stored in memory. If a name is not set in memeory, it skips to the next. The code works, but takes up a lot of room. Any advice appreciated. Code: #include <string.h> int iName = 0; int iNewName = 0; BYTE GetName () { return iName; } void SetName (int iNewName) { while (iName != iNewName) { switch (byNewName) { case 1: if (strlen (memory.m_nameA) == 0) new_name++; else iName = iNewName; break; case 2: if (strlen (memory.m_nameB) == 0) new_name++; else iName = iNewName; break; case 3: if (strlen (memory.m_nameC) == 0) new_name++; else iName = iNewName; break; case 4: if (strlen (memory.m_nameD) == 0) new_name++; else iName = iNewName; break; case 5: if (strlen (memory.m_nameE) == 0) new_name++; else iName = iNewName; break; default: iNewName = 1; break; } // end of case } // end of loop } // end of SetName function void main () { while(1) { if (Button_pushed) SetName(GetName+1); } // end of infinite loop } // end of main

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  • Getting started with workflows in sharepoint 2010

    - by Thomas Stock
    Hi, I'm a beginning sharepoint developer asked to implement the following scenario in sharepoint 2010. We're a bit lost on the best approach to get started.. I'm really struggling to find the best practise solution. This is the flow: A user can make a request with a title and a description. A mail gets sent to the representative with a link to a form. A representative can approve or reject the request. If approved: A mail gets sent to Board with a link to form If rejected: A mail gets sent to the user with the message that it has been rejected. when the request was approved by the representative, the board can approve or reject the request. A mail gets sent to the user and the representative with the descision of the board. So the list has the following fields: Request title Request description Representative approval Representative description Board approval Board description The user should see the following form: Request title (editable) Request description (editable) The representative should see the following form: Request title (read-only) Request description (read-only) Representative approval (editable) Representative description (editable) The Board should see the following form: Request title (read-only) Request description (read-only) Representative approval (read-only) Representative description (read-only) Board approval (editable) Board description (editable) My questions: What tool is most appropriate for making the forms? Infopath? SPD? VS2010? How do I handle rights to make sure only the board can access the board edit form? What kind of workflow do I use? When do I start the workflow(s)? What do I use to develop the workflow(s)? How do I handle rights when showing the listview with all requests? How can I build the links in the mails sent to the different groups. Thanks in advance for any advice.

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  • Overloading generic implicit conversions

    - by raichoo
    Hi I'm having a little scala (version 2.8.0RC1) problem with implicit conversions. Whenever importing more than one implicit conversion the first one gets shadowed. Here is the code where the problem shows up: // containers class Maybe[T] case class Nothing[T]() extends Maybe[T] case class Just[T](value: T) extends Maybe[T] case class Value[T](value: T) trait Monad[C[_]] { def >>=[A, B](a: C[A], f: A => C[B]): C[B] def pure[A](a: A): C[A] } // implicit converter trait Extender[C[_]] { class Wrapper[A](c: C[A]) { def >>=[B](f: A => C[B])(implicit m: Monad[C]): C[B] = { m >>= (c, f) } def >>[B](b: C[B])(implicit m: Monad[C]): C[B] = { m >>= (c, { (x: A) => b } ) } } implicit def extendToMonad[A](c: C[A]) = new Wrapper[A](c) } // instance maybe object maybemonad extends Extender[Maybe] { implicit object MaybeMonad extends Monad[Maybe] { override def >>=[A, B](a: Maybe[A], f: A => Maybe[B]): Maybe[B] = { a match { case Just(x) => f(x) case Nothing() => Nothing() } } override def pure[A](a: A): Maybe[A] = Just(a) } } // instance value object identitymonad extends Extender[Value] { implicit object IdentityMonad extends Monad[Value] { override def >>=[A, B](a: Value[A], f: A => Value[B]): Value[B] = { a match { case Value(x) => f(x) } } override def pure[A](a: A): Value[A] = Value(a) } } import maybemonad._ //import identitymonad._ object Main { def main(args: Array[String]): Unit = { println(Just(1) >>= { (x: Int) => MaybeMonad.pure(x) }) } } When uncommenting the second import statement everything goes wrong since the first "extendToMonad" is shadowed. However, this one works: object Main { implicit def foo(a: Int) = new { def foobar(): Unit = { println("Foobar") } } implicit def foo(a: String) = new { def foobar(): Unit = { println(a) } } def main(args: Array[String]): Unit = { 1 foobar() "bla" foobar() } } So, where is the catch? What am I missing? Regards, raichoo

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  • Json to treeview (<ul>)

    - by Pieter
    Hi I get the following data back from my WCF Data Service (I cut out the metadata) { "d" : [ {"CodeId": 6, "Title": "A Child Sub Item", "Parent":}, {"CodeId": 5, "Title": "Another Root Item", "Parent": -1}, {"CodeId": 4, "Title": "Child Item", "Parent": 2}, {"CodeId": 2, "Title": "Root Item", "Parent": -1} ] } I am trying to get this into a <ul> style tree with Parent = -1 as root and then the rest as sub items of their parent id's. Can anyone help me please, preferably in jQuery? I will use this in jstree if someone knows of a better way to do this. Thanks

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  • Styling an Input Field

    - by John
    Hello When I try to alter the CSS for the input field named "title" below, which is classed by "submissionfield", the position changes, but the height, length, and font of the field do not change. How could I make the height of the input field "title" 22 px, the length 550 px, and the font Times New Roman? The CSS below does not do it. Thanks in advance, John echo '<form action="http://www...com/.../submit2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <div class="submissiontitle"><label for="title">Story Title:</label></div> <div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div> <div class="urltitle"><label for="url">Link:</label></div> <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> <div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; The CSS: .submissiontitle { position:absolute; width:100px; left:30px; top:200px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; } .submissionfield { position:absolute; width:550px; left:50px; top:230px; text-align: left; margin-bottom:3px; padding:0px; font-family: "Times New Roman", Times, serif; font-size: 22px; color:#000000; } .urltitle { position:absolute; width:250px; left:30px; top:300px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; } .urlfield { position:absolute; width:550px; left:30px; top:330px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 11px; color:#000000; } .submissionbutton { position:absolute; width:250px; left:30px; top:380px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 11px; color:#000000; } .submittitle { position:absolute; width:250px; left:30px; top:150px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; }

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  • How to add a WHERE clause on the second table of a 1-to-1 join in Fluent NHibernate?

    - by daddywoodland
    I'm using a legacy database that was 'future proofed' to keep track of historical changes. It turns out this feature is never used so I want to map the tables into a single entity. My tables are: CodesHistory (CodesHistoryID (pk), CodeID (fk), Text) Codes (CodeID (pk), CodeName) To add an additional level of complexity, these tables hold the content for the drop down lists throughout the application. So, I'm trying to map a Title entity (Mr, Mrs etc.) as follows: Title ClassMap - Public Sub New() Table("CodesHistory") Id(Function(x) x.TitleID, "CodesHistoryID") Map(Function(x) x.Text) 'Call into the other half of the 1-2-1 join in order to merge them in 'this single domain object Join("Codes", AddressOf AddTitleDetailData) Where("CodeName like 'C.Title.%'") End Sub ' Method to merge two tables with a 1-2-1 join into a single entity in VB.Net Public Sub AddTitleDetailData(ByVal m As JoinPart(Of Title)) m.KeyColumn("CodeID") m.Map(Function(x) x.CodeName) End Sub From the above, you can see that my 'CodeName' field represents the select list in question (C.Title, C.Age etc). The problem is that the WHERE clause only applies to the 'CodesHistory' table but the 'CodeName' field is in the 'Codes' table. As I'm sure you can guess there's no scope to change the database. Is it possible to apply the WHERE clause to the Codes table?

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  • Macro and array crossing

    - by Thomas
    I am having a problem with a lisp macro. I would like to create a macro which generate a switch case according to an array. Here is the code to generate the switch-case: (defun split-elem(val) `(,(car val) ',(cdr val))) (defmacro generate-switch-case (var opts) `(case ,var ,(mapcar #'split-elem opts))) I can use it with a code like this: (generate-switch-case onevar ((a . A) (b . B))) But when I try to do something like this: (defparameter *operators* '((+ . OPERATOR-PLUS) (- . OPERATOR-MINUS) (/ . OPERATOR-DIVIDE) (= . OPERATOR-EQUAL) (* . OPERATOR-MULT))) (defmacro tokenize (data ops) (let ((sym (string->list data))) (mapcan (lambda (x) (generate-switch-case x ops)) sym))) (tokenize data *operators*) I got this error: *** - MAPCAR: A proper list must not end with OPS. But I don't understand why. When I print the type of ops I get SYMBOL I was expecting CONS, is it related? Also, for my function tokenize how many times the lambda is evaluated (or the macro expanded)?

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  • jquery child element as trigger

    - by Dan w
    When "forum-title" is clicked, I want "subtopic-frame" within the parent "forum-topics-head" to expand. There are multiple "forum-topics-head" (with all associated children) on this page. The way I have it now, the "forum-topics-head" is the trigger, but I want the "forum-title" to be the trigger. html: <div class="forum-topic-head"> <div class="forum-title">Forum Title</div> <div class="subtopic-frame"> subtopic 1 subtopic 2 </div> </div>

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  • Help needed in AdventureWorks in a sql query.

    - by vaibhav
    I was just playing with adventureworks database in sqlserver. I got stuck in a query. I wanted to Select all titles from HumanResources.Employee which are either 'Male' or 'Female' but not both. i.e if title Accountant is Male and Female both I want to leave that title. I need only those titles where Gender is either Male or Female. I have done this till yet. select distinct(title) from humanresources.employee where gender='M' select distinct(title) from humanresources.employee where gender='F' Probably a join between these two queries, would work. But If you have any other solution, please let me know. It is not a homework. :) Thanks in advance.

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  • pywinauto: taking more than one app windows

    - by Denis Barmenkov
    I have a GUI application which can create many similar windows on desktop. All windows have same title. I have to enumerate all dialogs with same title and make some tests against each of such dialogs. If I call: dialog = app['Window Name'] pywinauto returns a WindowSpecification object which is useful along with accessing controls by name. When I call: dialogs = app.windows_(title='Window Name') pywinauto returns me a list of HwndWrapper instances which are not so useful. How to obtain a list of windows with specified title but as WindowSpecification objects?

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  • Breadcrumbs in Fusebox 4/5

    - by Jordan Reiter
    I'm wondering if anyone has come up with a clean way to generate a breadcrumbs trail in Fusebox. Specifically, is there a way of keeping track of "where you are" and having that somehow generate the breadcrumbs for you? So, for example, if you're executing /index.cfm?fuseaction=Widgets.ViewWidget&widget=1 and the circuit structure is something like /foo/bar/widgets/ then somehow the system automatically creates an array like: [ { title: 'Foo', url: '#self#?fuseaction=Foo.Main' }, { title: 'Bar', url: '#self#?fuseaction=Bar.Main' }, { title: 'Widgets', url: '#self#?fuseaction=Widgets.Main' }, { title: 'Awesome Widget', url: '' } ] Which can then be rendered as Foo Bar Widgets Awesome Widget Right now it seems the only way to really do this is to create the structure for each fuseaction in a fuse of some kind (either the display fuse or a fuse dedicated to creating the crumbtrail).

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  • PHP write file... need help

    - by Jordan Pagaduan
    <?php $title = $_POST['title']; $filename = $title , ".php"; $fh = fopen($filename, 'w') or die ("can't open file"); $stringData = $title; fwrite($fh, $stringData); $stringData = $blog; fwrite($fh, $stringData); fclose($fh); ?> This is only a sample. What is the correct code for that?

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