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  • Parsing secure entries XML file with jquery

    - by user573131
    Apologies if this is elementary. I'm primarily a front end designer/dev. I have webform through a form service called wufoo. Wufoo generates a lovely XML (or json) file that can be grabed and parsed. I'm trying to grab the entries xml feed that is associated with the form and parse it via jquery to show who has entered. Im using the following code (which works with a local xml file). http://bostonwebsitemakeover.com/2/test <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.js"></script> <script> $(document).ready(function () { $.ajax({ type: "GET", url: "people.xml", dataType: "xml", success: xmlParser }); }); function xmlParser(xml) { $('#load').fadeOut(); $(xml).find("Entry").each(function () { $(".main").append('<div class="entry">' + $(this).find("Field1").text() + ' ' + $(this).find("Field2").text() + ' http://twitter.com/' + $(this).find("Field17").text() + '</div>'); $(".entry").fadeIn(1000); }); } </script> My XML file contains the following: <?xml version="1.0"?> <Entries> <Entry> <EntryId>1</EntryId> <Field1>Meaghan</Field1> <Field2>Severson</Field2> <Field17/> </Entry> <Entry> <EntryId>2</EntryId> <Field1>Michael</Field1> <Field2>Flint</Field2> <Field17>michaelflint</Field17> </Entry> <Entry> <EntryId>3</EntryId> <Field1>Niki</Field1> <Field2>Brown</Field2> <Field17>nikibrown</Field17> </Entry> <Entry> <EntryId>4</EntryId> <Field1>Niki</Field1> <Field2>Brown</Field2> <Field17>nikibrown</Field17> </Entry> </Entries> I'm wondering how I would do this with the xml file hosted on the wufoo (which is https) So I guess Im asking how do I authenticate the feed via jquery? Or do i need to do this via json? Could someone explain how?

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  • what does "dead beef" mean?

    - by Xi
    Hi there: What does the word "dead beef" mean? I read it from a interview question. It has something to do with ipv6. I figured it could be a random hex number used for examples, like "The quick brown fox jumps over the lazy dog". Is my understanding correct? Or it has more significant meaning? Thanks!

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  • Function that converts hex color values to an approximate color name?

    - by dclowd9901
    I don't suppose anyone knows of a function (PHP, preferably) that can take a hex color code and give an approximate color name for that hex value. I don't need a solution with 100s of colors. Even if it just amounted to the colors white, black, red, green blue, brown orange and yellow, I'd be pretty well in shape. If you don't know of an existing resource, does anyone know of a good way to approach this problem? Thanks in advance for the help.

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  • Please help on multiple match replacement

    - by duenguyen
    I have a perl code: my $s = "The+quick+brown+fox+jumps+over+the+lazy+dog+that+is+my+dog"; what I want is to replace every + with space and dog with cat i have this regular expression $s =~ s/+(.*)dog/ ${1}cat/g; But it only match first occurrence of + and last dog. Please help

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  • PHP - Checking whether a string exists in an entire array?

    - by RC
    Hi all, Basic array question: $string = "The quick brown cat"; $check1 = "apple"; $check2 = "ball"; $check3 = "cat"; if ( (stripos($string, $check1) === false) || (stripos($string, $check2) === false) || (stripos($string, $check3) === false) ) { echo "Fail"; } How do I condense the above using an array ($check[])? Thanks!

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  • How do I center my navigation bar and background?

    - by user2892958
    nav-wrap { background:url(nav-bg-blue.png) no-repeat top center; height:39px; padding-top:3px; } .no-header-page #nav-wrap { background:url(nav-bg-nobanner-blue.png) no-repeat top center; height:43px; padding-top:4px; margin-bottom:30px; } #nav-wrap .container { clear: both; overflow: hidden; position:center; width:100%; } #nav-wrap .container ul { list-style: none; float: center; } #nav-wrap .container ul li { list-style: none; float: left; background:url(nav-right-last.png) no-repeat top right; padding-right:20px; margin-left:-10px; position:auto; } #nav-wrap .container ul span li { background:url(nav-right-last.png) no-repeat top right; } #nav-wrap .container ul li a { float: center; display: block; font-family: 'News Cycle', sans-serif; color: #fff; text-decoration: none; padding: 5px 10px 8px 20px; border: 0; outline: 0; list-style-type: none; font-size: 14px; text-transform:uppercase; letter-spacing:2px; background:url(nav-left-first.png) no-repeat top left; line-height:25px; text-shadow:0 -1px 2px rgba(0,0,0,0.3); } #nav-wrap .container ul li#active, #nav-wrap .container ul li:hover{ background:url(nav-hover-right-last-brown-red.png) no-repeat topright; z-index:1; } #nav-wrap .container ul li:hover a, #nav-wrap .container ul li#active a, #nav-wrap .container ul li a:hover { border: 0; background:url(nav-hover-left-brown-red.png) no-repeat top left; } .wsite-nav-0 { margin-left:0 !important`` }

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  • changing the color of scroll bar?

    - by udaya
    Hi In a div I gave overflow auto to have a scroll bar to display the content that exceeds the limit My scroll bar appears in blue color that doesn't suit my layout how can i change the color div#navigation{background:#efe9b9; overflow:auto} This is the css i am using ... I want brown colored scrll bar How to get it

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  • function not working R

    - by user3722828
    I've never programmed before and am trying to learn. I'm following that "coursera" course that I've seen other people post about — a course offered by Johns Hopkins on R programming. Anyway, this was supposed to be my first function. Yet, it doesn't work! But when I type out all the steps individually, it runs just fine... Can anyone tell me why? > pollutantmean <- function(directory, pollutant, id = 1:332){ + x<- list.files("/Users/mike******/Desktop/directory", full.names=TRUE) + y<- lapply(x, read.csv) + z<- do.call(rbind.data.frame, y[id]) + + mean(z$pollutant, na.rm=TRUE) + } > pollutantmean(specdata,nitrate,1:10) [1] NA Warning message: In mean.default(z$pollutant, na.rm = TRUE) : argument is not numeric or logical: returning NA #### > x<- list.files("/Users/mike******/Desktop/specdata",full.names=TRUE) > y<- lapply(x,read.csv) > z<- do.call(rbind.data.frame,y[1:10]) > mean(z$nitrate,na.rm=TRUE) [1] 0.7976266

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  • Delete duplicate records from a SQL table without a primary key

    - by Shyju
    I have the below table with the below records in it create table employee ( EmpId number, EmpName varchar2(10), EmpSSN varchar2(11) ); insert into employee values(1, 'Jack', '555-55-5555'); insert into employee values (2, 'Joe', '555-56-5555'); insert into employee values (3, 'Fred', '555-57-5555'); insert into employee values (4, 'Mike', '555-58-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6, 'Lisa', '555-70-5555'); insert into employee values (1, 'Jack', '555-55-5555'); insert into employee values (4, 'Mike', '555-58-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6 ,'Lisa', '555-70-5555'); insert into employee values (5, 'Cathy', '555-59-5555'); insert into employee values (6, 'Lisa', '555-70-5555'); I dont have any primary key in this table .But i have the above records in my table already. I want to remove the duplicate records which has the same value in EmpId and EmpSSN fields. Ex : Emp id 5 Can any one help me to frame a query to delete those duplicate records Thanks in advance

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  • Sql Query - Selecting rows where user can be both friend and user

    - by Gublooo
    Hey Sorry the title is not very clear. This is a follow up to my earlier question where one of the members helped me with a query. I have a following friends Table Friend friend_id - primary key user_id user_id_friend status The way the table is populated is - when I send a friend request to John - my userID appears in user_id and Johns userID appears in user_id_friend. Now another scenario is say Mike sends me a friend request - in this case mike's userID will appear in user_id and my userID will appear in user_id_friend So to find all my friends - I need to run a query to find where my userID appears in both user_id column as well as user_id_friend column What I am trying to do now is - when I search for user say John - I want all users Johns listed on my site to show up along with the status of whether they are my friend or not and if they are not - then show a "Add Friend" button. Based on the previous post - I got this query which does part of the job - My example user_id is 1: SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id = u.user_id and f.user_id_friend = 1 where u.name like '%' So this only shows users with whom I am friends where they have sent me request ie my userID appears in user_id_friend. Although I am friends with others (where my userID appears in user_id column) - this query will return that as null To get those I need another query like this SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id_friend = u.user_id and f.user_id = 1 where u.name like '%' So how do I combine these queries to return 1 set of users and what my friendship status with them is. I hope my question is clear Thanks

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  • ASP, sorting database with conditions using multiple columns...

    - by Mitch
    First of all, I'm still working in classic ASP (vbScript) with an MS Access Database. And, yes I know its archaic, but I'm still hopeful I can do this! So now to my problem: Take the following table as an example: PROJECTS ContactName StartDate EndDate Complete Mitch 2009-02-13 2011-04-23 No Eric 2006-10-01 2008-11-15 Yes Mike 2007-05-04 2009-03-30 Yes Kyle 2009-03-07 2012-07-08 No Using ASP (with VBScript), and an MS Access Database as the backend, I’d like to be able to sort this table with the following logic: I would like to sort this table by date, however, depending on whether a given project is complete or not I would like it to use either the “StartDate” or “EndDate” as the reference for a particular row. So to break it down further, this is what I’m hoping to achieve: For PROJECTS where Complete = “Yes”, reference “EndDate” for the purpose of sorting. For PROJECTS where Complete = “No”, reference “StartDate” for the purpose of sorting. So, if I were to sort the above table following these rules, the output would be: PROJECTS ContactName StartDate EndDate Complete 1 Eric 2006-10-01 2008-11-15* Yes 2 Mitch 2009-02-13* 2011-04-23 No 3 Kyle 2009-03-07* 2012-07-08 No 4 Mike 2007-05-04 2009-03-30* Yes *I’ve put a star next to the date that should be used for the sort in the table above. NOTE: This is actually a simplified version of what I really need to do, but I think that if I could just figure this out, I’ll be able to do the rest on my own. ANY HELP IS GREATLY APPRECIATED; I’VE BEEN STRUGGLING WITH THIS FOR FAR TOO LONG NOW! Thank you!

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  • can I make this select follower/following script more organized? (PHP/Mysql)

    - by ggfan
    In this script, it gets the followers of a user and the people the user is following. Is there a better relationship/database structure to get a user's followers and who they are following? All I have right now is 2 columns to determine their relationship. I feel this is "too simple"? (MYSQL) USER | FRIEND avian gary cend gary gary avian mike gary (PHP) $followers = array(); $followings = array(); $view = $_SESSION['user']; //view is the person logged in $query = "SELECT * FROM friends WHERE user='$view'"; $result = $db->query($query); while($row=$result->fetch_array()) { $follower=$row['friend']; $followers[] = $follower; } print_r($followers); echo "<br/>"; $query2 = "SELECT * FROM friends WHERE friend='$view'"; $result2 = $db->query($query2); while($row2=$result2->fetch_array()) { $following=$row2['user']; $followings[] = $following; } print_r($followings); echo "<br/>"; $mutual = array_intersect($followers, $followings); print_r($mutual); **DISPLAY** Your mutual friends avian Your followers avian You are following avian cen mike (I know avian is in all 3 displays, but I want to keep it that way)

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  • Python DictReader - Skipping rows with missing columns?

    - by victorhooi
    heya, I have a Excel .CSV file I'm attempting to read in with DictReader. All seems to be well, except it seems to omit rows, specifically those with missing columns. Our input looks like: mail,givenName,sn,lorem,ipsum,dolor,telephoneNumber [email protected],ian,bay,3424,8403,2535,+65(2)34523534545 mike[email protected],mike,gibson,3424,8403,2535,+65(2)34523534545 [email protected],ross,martin,,,,+65(2)34523534545 [email protected],david,connor,,,,+65(2)34523534545 [email protected],chris,call,3424,8403,2535,+65(2)34523534545 So some of the rows have missing lorem/ipsum/dolor columns, and it's just a string of commas for those. We're reading it in with: def read_gd_dump(input_file="blah 20100423.csv"): gd_extract = csv.DictReader(open('blah 20100423.csv'), restval='missing', dialect='excel') return dict([(row['something'], row) for row in gd_extract]) And I checked that "something" (the key for our dict) isn't one of the missing columns, I had originally suspected it might be that. It's one of the columns after that. However, DictReader seems to completely skip over the rows. I tried setting restval to something, didn't seem to make any difference. I can't seem to find anything in Python's CSV docs (http://docs.python.org/library/csv.html) that would explain this behaviour, but I may have misread something. Any ideas? Thanks, Victor

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  • how to join tables sql server

    - by Rick
    Im having some trouble with joining two tables. This is what my two tables look like: Table 1 Customer_ID CustomerName Add. 1000 John Smith 1001 Mike Coles 1002 Sam Carter Table 2 Sensor_ID Location Temp CustIDFK 1000 NY 70 1002 NY 70 1000 ... ... 1001 1001 1002 Desired: Sensor_ID Location Temp CustIDFK 1000 NY 70 John Smith 1002 NY 70 Sam Carter 1000 ... ... John Smith 1001 Mike Coles 1001 1002 I have made Customer_ID from table 1 my primary key, created custIDFK in table 2 and set that as my foreign key. I am really new to sql server so I am still having trouble with the whole relationship piece of it. My goal is to match one customer_ID with one Sensor_ID. The problem is that the table 2 does not have "unique IDs" since they repeat so I cant set that to my foreign key. I know I will have to do either an inner join or outer join, I just dont know how to link the sensor id with customer one. I was thinking of giving my sensor_ID a unique ID but the data that is being inserted into table 2 is coming from another program. Any suggestions?

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  • Package visible in Synaptic but not in aptitude?

    - by sleepycat
    I can see libfreeimage3-dev in synaptic and have installed it from there, but what is it that I can't see it from the command line? I tried sudo aptitude update... mike@sleepycat:~$ sudo aptitude search '~n.*freeimage3.*' i libfreeimage3 - Support library for graphics image formats p libfreeimage3-dbg - Support library for graphics image formats Any ideas?

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  • Elinks and flash

    - by bajki
    Hello everybody, is there a possibility to "use" flash based objects with elinks ? I mean, i have an online flash based multiplayer game ( http://haxball.appspot.com ) and i want to connect to game with elinks installed on my shell server to create an always-present game room. To do it, i need a terminal-based webbrowser with flash support. There is an elinks installed so it would be great if there is such a possibility in it. Any ideas? Thanks, Mike

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  • remote desktop client with panning of large desktops?

    - by mikewse
    When using the standard Windows remote desktop client in Full Screen to connect to a large remote desktop, the result is usually that the remote desktop is resized to a smaller size matching the local display. Are there any RDP clients that in Full Screen instead leave the remote desktop at its original size and pan this larger area when the mouse reaches the border edges of the local display? Thanks Mike

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  • Script to monitor free space in Hdd

    - by s.mihai
    I have a server app that crushes when the HDD free space it's a multiple of 4Gb (on a Windows Server 2003). In general i keep track myself o that weekly since i use the machine from time to time. Can you point out an app or script (i don't wanna install powershell, is this doable???) that copies some larger files from one folder to another to get the free space out of the multiple of 4Gb range. Best regards, Mike

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  • Script to check a shared Exchange calendar and tehn email detial

    - by SJN
    Hi, We're running Server and Exchange 2003 here. There's a shared calendar which HR keep up-to-date detailing staff who are on leave. I'm looking for a VB Script (or alternate) which will extract the "appointment" titles of each item for the current day and then email the detail to a mail group, in doing so notifying the group with regard to which staff are on leave for the day. The resulting email body should be: Staff on leave today: Mike Davis James Stead Any ideas?

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  • CUPS Web Admin Error 500 Unknown

    - by Floyd Resler
    I keep getting a 500 Unknown error whenever I navigate off the home page of my CUPS web admin. I'm sure I have something misconfigured but I'm not sure what. Here's my configuration: # # "$Id: cupsd.conf.in 8805 2009-08-31 16:34:06Z mike $" # # Sample configuration file for the CUPS scheduler. See "man cupsd.conf" for a # complete description of this file. # # Log general information in error_log - change "warn" to "debug" # for troubleshooting... LogLevel warn # Administrator user group... SystemGroup lpadmin sys root # Only listen for connections from the local machine. Listen 192.168.6.101:631 Listen /var/run/cups/cups.sock ServerName 192.168.6.101 # Show shared printers on the local network. Browsing On BrowseOrder allow,deny BrowseAllow all BrowseLocalProtocols CUPS BrowseAddress 192.168.6.255 # Default authentication type, when authentication is required... DefaultAuthType Basic # Restrict access to the server... Order allow,deny Allow From All Allow From 127.0.0.1 # Restrict access to the admin pages... AuthType Default Require user @SYSTEM Order allow,deny Allow From All Allow From 127.0.0.1 # Restrict access to configuration files... AuthType Default Require user @SYSTEM Order allow,deny Allow From All Allow From 127.0.0.1 # Set the default printer/job policies... # Job-related operations must be done by the owner or an administrator... Require user @OWNER @SYSTEM Order deny,allow # All administration operations require an administrator to authenticate... AuthType Default Require user @SYSTEM Order deny,allow # All printer operations require a printer operator to authenticate... AuthType Default Require user @SYSTEM Order deny,allow # Only the owner or an administrator can cancel or authenticate a job... Require user @OWNER @SYSTEM Order deny,allow Order deny,allow # Set the authenticated printer/job policies... # Job-related operations must be done by the owner or an administrator... AuthType Default Order deny,allow AuthType Default Require user @OWNER @SYSTEM Order deny,allow # All administration operations require an administrator to authenticate... AuthType Default Require user @SYSTEM Order deny,allow # All printer operations require a printer operator to authenticate... AuthType Default Require user @SYSTEM Order deny,allow # Only the owner or an administrator can cancel or authenticate a job... AuthType Default Require user @OWNER @SYSTEM Order deny,allow Order deny,allow # # End of "$Id: cupsd.conf.in 8805 2009-08-31 16:34:06Z mike $". #

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