Search Results

Search found 36111 results on 1445 pages for 'mysql update'.

Page 105/1445 | < Previous Page | 101 102 103 104 105 106 107 108 109 110 111 112  | Next Page >

  • Load huge sql dump to mySql

    - by jonathan
    Hi I have a huge mysql dump file generated from phpmyAdmin (150 000 lines of create table, inserts....) The mySql query tool fails to open such a big file. As a result i can't insert all the records. Is there a way to do this ? Thanks John

    Read the article

  • How to count NULL values in MySQL?

    - by abbr
    I want to know how can i find all the values that are NULL in the MySQL database for example I'm trying to display all the users who don't have an average yet. Here is the MySQL code. SELECT COUNT(average) as num FROM users WHERE user_id = '$user_id' AND average IS_NULL

    Read the article

  • What is the best PHP MYSQL wrapper?

    - by Jestro
    I've bounced around between different wrappers, my own, and using straight php mysql functions over the years but I'm sure there's a really good solution out there. What is it? :) EDIT: Only needs to connect to MYSQL and it would be nice if it was lightweight.

    Read the article

  • MySql LINK to SQL Server

    - by XkiD
    I have a host with php+mysql and i need to run a script here to register accounts to another host that has SQL Server and i also have php+mysql here also , but i need the accounts to be in SQL Server. how can i do this?

    Read the article

  • iPhone to host server to mySQL and back?

    - by ronbowalker
    Can someone please direct me to process for doing this? I have already done the Login verification exercise using mySQL for the dbase on my host server (thanks to kiksy). Now I am trying to move forward and "Query" from the iPhone a list of "users" that currently occupy the table (iphoneusers) in MySQL. And of course get it back to the iPhone via the php connection. Any help would be very much appreciated. ronbowalker

    Read the article

  • Unable to configure a service to run at startup with update-rc.d

    - by ujjain
    I would like to have transmission-daemon and vnstat automatically run at startup. I was able to configure this for apache2 and proftpd with exactly the same commands. 795 sudo update-rc.d transmission-daemon remove 797 sudo update-rc.d -f transmission-daemon remove 798 sudo update-rc.d transmission-daemon defaults 799 sudo update-rc.d vnstat remove 800 sudo update-rc.d -f vnstat remove 801 sudo update-rc.d -f vnstat defaults 802 sudo update-rc.d -f vnstat enable 805 reboot 807 history root@htpc:/home/administrator# sudo update-rc.d -f transmission-daemon remove Removing any system startup links for /etc/init.d/transmission-daemon ... /etc/rc0.d/K20transmission-daemon /etc/rc1.d/K20transmission-daemon /etc/rc2.d/S20transmission-daemon /etc/rc3.d/S20transmission-daemon /etc/rc4.d/S20transmission-daemon /etc/rc5.d/S20transmission-daemon /etc/rc6.d/K20transmission-daemon root@htpc:/home/administrator# sudo update-rc.d -f transmission-daemon defaults Adding system startup for /etc/init.d/transmission-daemon ... /etc/rc0.d/K20transmission-daemon -> ../init.d/transmission-daemon /etc/rc1.d/K20transmission-daemon -> ../init.d/transmission-daemon /etc/rc6.d/K20transmission-daemon -> ../init.d/transmission-daemon /etc/rc2.d/S20transmission-daemon -> ../init.d/transmission-daemon /etc/rc3.d/S20transmission-daemon -> ../init.d/transmission-daemon /etc/rc4.d/S20transmission-daemon -> ../init.d/transmission-daemon /etc/rc5.d/S20transmission-daemon -> ../init.d/transmission-daemon root@htpc:/home/administrator# service vnstat status * vnStat daemon is not running root@htpc:/home/administrator# service transmission-daemon status * transmission-daemon is not running root@htpc:/home/administrator# service transmission-daemon start * Starting bittorrent daemon transmission-daemon [ OK ] root@htpc:/home/administrator# service vnstat start * Starting vnStat daemon vnstatd [ OK ] root@htpc:/home/administrator# service apache2 status Apache2 is running (pid 1137). root@htpc:/home/administrator#

    Read the article

  • PHP PDO Related: Update SQL Statement not Updating the content of Database

    - by Rachel
    I am trying to implement update statement using prepared statement in php script but it appears that it is not update record in the database and am not sure why and so would appreciate if you can share some insights. Code $query = "UPDATE DatTable SET DF_PARTY_ID = :party_id, DF_PARTY_CODE = :party_code, DF_CONNECTION_ID = :connection_id WHERE DF_PARTY_ID = ':party_id'"; $stmt = $this->connection->prepare($query); $stmt->bindValue(':party_id', $data[0], PDO::PARAM_INT); $stmt->bindValue(':party_code', $data[1], PDO::PARAM_INT); $stmt->bindValue(':connection_id', $data[2], PDO::PARAM_INT); $stmt->execute(); Inspiring Solution leading to this approach. Any Suggestions ?

    Read the article

  • Select From MySQL PHP

    - by Liju
    Sir, I have one Database Table named "table1" with 8 column, that is Date, Time, Name, t1, t2, t3, t4, t5. I want to update the same table like the following... my existing table:- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 10/11/2010 09:00 bob 10/11/2010 10:00 bob 10/11/2010 13:00 bob 10/11/2010 10:00 john 10/11/2010 12:00 john 10/11/2010 14:00 john 12/11/2010 08:00 bob 12/11/2010 09:00 bob 12/11/2010 10:00 bob 12/11/2010 13:00 bob 12/11/2010 10:00 john 12/11/2010 12:00 john 12/11/2010 14:00 john 12/11/2010 16:00 john I want to update this as follows :- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 08:00 09:00 10:00 13:00 10/11/2010 10:00 john 10:00 12:00 14:00 12/11/2010 08:00 bob 08:00 09:00 10:00 13:00 12/11/2010 10:00 john 10:00 12:00 14:00 16:00 is it posible to update like this please help me.. Liju

    Read the article

  • Update table.column with another table.column with common joined column

    - by Matt
    Hit a speed bump, trying to update some column values in my table from another table. This is what is supposed to happen when everything works Correct all the city, state entries in tblWADonations by creating an update statement that moves the zip city from the joined city/state zip field to the tblWADonations city state TBL NAME | COLUMN NAMES tblZipcodes with zip,city,State tblWADonations with zip,oldcity,oldstate This is what I have so far: UPDATE tblWADonations SET oldCity = tblZipCodes.city, oldState = tblZipCodes.state FROM tblWADonations INNER JOIN tblZipCodes ON tblWADonations.zip = tblZipCodes.zip Where oldCity <> tblZipcodes.city; There seems to be easy ways to do this online but I am overlooking something. Tried this by hand and in editor this is what it kicks back. Msg 8152, Level 16, State 2, Line 1 String or binary data would be truncated. The statement has been terminated. Please include a sql statement or where I need to make the edit so I can mark this post as a reference in my favorites. Thanks!

    Read the article

  • Update/Increment a single column on multiple rows at once

    - by Jordan Feldstein
    I'm trying to add rows to a column, keeping the order of the newest column set to one, and all other rows counting up from there. In this case, I add a new row with order=0, then use this query to update all the rows by one. "UPDATE favorits SET order = order+1" However, what happens is that all the rows are updated to the same value. I get a stack of favorites, all with order 6 for example, when it should be one with 1, the next with 2 and so on. How do I update these rows in a way that orders them the way they should be? Thanks, ~Jordan

    Read the article

  • C#/.Net Error: MySql.Data Object reference not set to an instance of an object.

    - by Simon
    Hello, I get this exception on my Windows 7 64bit in application running in VS 2008 express. I am using Connector/Net 6.2.2.0: Message: Object reference not set to an instance of an object. Source: MySql.Data in MySql.Data.MySqlClient.NativeDriver.GetResult(Int32& affectedRow, Int32& insertedId) Stack trace: in MySql.Data.MySqlClient.Driver.GetResult(Int32 statementId, Int32& affectedRows, Int32& insertedId) in MySql.Data.MySqlClient.Driver.NextResult(Int32 statementId) in MySql.Data.MySqlClient.MySqlDataReader.NextResult() in MySql.Data.MySqlClient.MySqlDataReader.Close() in MySql.Data.MySqlClient.MySqlConnection.Close() in MySql.Data.MySqlClient.MySqlConnection.Dispose(Boolean disposing) in System.ComponentModel.Component.Finalize() No inner exception. This exception is unhalted and the debugger dont point on any code line. It just say "Object reference not set to an instance of an object. MySql.Data" This error is really hard to repeat. On my Windows XP 32bit is all ok. Could it be error in 64bit Windows 7? Thank you very much for your answers. Regards, simon

    Read the article

  • jQuery Connected Sortable Lists, Save Order to MySQL

    - by user300999
    Hello Hoping that using something like this demo it is possible to drag items within and between two columns, and update their order either live or with a "save" button to MySQL. Point being that you can make changes and return to the page later to view or update your ordering. http://pilotmade.com/draggable2.html Doing it for just one column is fine, but when I try to pass the order of both columns, the issue seems to be passing multiple serialized arrays with jQuery to a PHP/MySQL update script. Any insight would be much appreciated.

    Read the article

  • how to update mysql with inputs and checkboxes

    - by Ronnie Chester Lynwood
    hi. with this code: <? if (isset($_POST['onay'])) { foreach ($_POST['secilen'] as $zuha) { $olay = mysql_query("update mp3 SET aktif = '1' WHERE id = '$zuha'"); } if ($olay) { echo "islem tamam"; exit; } } ?> and with this form: (select * from mp3 aktif = '0') <form name="form" method="post"> <input readonly type="text" name="id" value="<?=$haciosman['id']?>" /> <input type="text" name="baslik" value="<?=$haciosman['baslik']?> <input type="checkbox" name="secilen[]" value="<?=$haciosman['id']?>"> <input type="submit" name="onay" value="Onayla" /> I can set "aktif to 1" for each row that i checked. but i want to update "baslik" too! how can i update each "baslik" with that php code?

    Read the article

  • mysql ON DUPLICATE KEY UPDATE

    - by julio
    Hi-- I'm stuck on a mySQL query using ON DUPLICATE KEY UPDATE. I'm getting the error: mySQL Error: 1062 - Duplicate entry 'hr2461809-3' for key 'fname' The table looks like this: id int(10) NOT NULL default '0', picid int(10) unsigned NOT NULL default '0', fname varchar(255) NOT NULL default '', type varchar(5) NOT NULL default '.jpg', path varchar(255) NOT NULL default '', PRIMARY KEY (id), UNIQUE KEY fname (fname), KEY picid (propid) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; And the query that's breaking is this: INSERT INTO images SET picid=732, fname='hr2461809-3', path='pictures/' ON DUPLICATE KEY UPDATE picid=732, fname='hr2461809-3', path='pictures/' I'm using a very similar query elsewhere in the app with no issues. I'm not sure why this one breaks. I expected that when the UNIQUE KEY on fname gets violated, that it would simply update the row where the violation occurred? Thanks for any help

    Read the article

  • How do you get SQLAlchemy to override MySQL "on update CURRENT_TIMESTAMP"

    - by nocola
    I've inherited an older database that was setup with a "on update CURRENT_TIMESTAMP" put on a field that should only describe an item's creation. With PHP I have been using "timestamp=timestamp" on UPDATE clauses, but in SQLAlchemy I can't seem to force the system to use the set timestamp. Do I have no choice and need to update the MySQL table (millions of rows)? foo = session.query(f).get(int(1)) ts = foo.timestamp setattr(foo, 'timestamp', ts) setattr(foo, 'bar', bar) www_model.www_Session.commit() I have also tried: foo = session.query(f).get(int(1)) setattr(foo, 'timestamp', foo.timestamp) setattr(foo, 'bar', bar) www_model.www_Session.commit()

    Read the article

  • Improving MySQL Update Query Efficiency

    - by Russell C.
    In our database tables we keep a number of counting columns to help reduce the number of simple lookup queries. For example, in our users table we have columns for the number of reviews written, photos uploaded, friends, followers, etc. To help make sure these stay in sync we have a script that runs periodically to check and update these counting columns. The problem is that now that our database has grown significantly the queries we have been using are taking forever to run since they are totally inefficient. I would appreciate someone with more MySQL knowledge than myself to recommend how we can improve it's efficiency: update users set photos=(select count(*) from photos where photos.status="A" AND photos.user_id=users.id) where users.status="A"; If this were a select statement I would just use a join but I'm not sure if that is possible with update. Thanks in advance for your help!

    Read the article

  • MySQL ON DUPLICATE KEY UPDATE issue

    - by user644347
    Hi could some one look at this and tell me where I am going wrong. I have an SQL statement that when I echo using php I get this to screen INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '18' , 'GenreName' = 'Drama' ON DUPLICATE KEY UPDATE 'GenreName' = 'Drama' WHERE 'GenreID' = '18' INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '16' , 'GenreName' = 'Animation' ON DUPLICATE KEY UPDATE 'GenreName' = 'Animation' WHERE 'GenreID' = '16' And here is the statement $sql="INSERT INTO 'moviedb'.'genre' SET 'GenreID' = '{$genresID[$i]}' , 'GenreName' = '{$genreName[$i]}' ON DUPLICATE KEY UPDATE 'GenreName' = '{$genreName[$i]}' WHERE 'GenreID' = '{$genresID[$i]}'"; This is the error I recieve: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''moviedb'.'genre' SET 'GenreID' = '18' , 'GenreName' = 'Drama' ON DUPLICATE KEY ' at line 1 Any help would be greatly appreciated, thanks in advance.

    Read the article

  • MySQL update query, how to skip empty values?

    - by Pawel
    I've got such query: $sql = "UPDATE test_accs SET acc_owner = '$owner_id', acc_policy_version = '$version', acc_policy_last_update = '$approved', acc_policy_next_update = '$renewed' WHERE acc_id = '1'"; Now, all of these values on the web folmular are optional, one can set one of these values, two, or so. Now, after I submit the form, it goes in the query like that: UPDATE test_accs SET acc_owner = '2', acc_policy_version = '1.2', acc_policy_last_update = '2012-12-19', acc_policy_next_update = '2012-12-18' WHERE acc_id = '1' It works only when I submit all values from the form. Can you please show me how could it work even if not all the values has been sent, just for example one of them? When I set one value (f.ex. policy version), it looks like that: UPDATE test_accs SET acc_owner = '', acc_policy_version = '1.2', acc_policy_last_update = '', acc_policy_next_update = '' WHERE acc_id = '1' and it isn't working. It might be possible cause of the acc_owner table values? #1366 - Incorrect integer value: '' for column 'acc_owner' at row 1 Thanks in advice.

    Read the article

  • How to self-update PHP+MySQL CMS?

    - by SaltLake
    I'm writing a CMS on PHP+MySQL. I want it to be self-updatable (throw one click in admin panel). What are the best practices? How to compare current version of cms and a version of the update (application itself and database). Should it just download zip archive, upzip it and overwrite files? (but what to do with files that are no longer used). How to check if an update is downloaded correctly? Also it supports modules and I want this modules to be downloadable from the admin panel of cms. And how should I update MySQL tables?

    Read the article

  • How to update mutual entries in DB?

    - by Sthita
    I am not able to perform mutual update to my Database. My Requirement is like this : Insert IDS UPDate DB Entries ID ConnectedTo ID connectedTo connectedVia 2 1 --- No Entry ----- 2 3 -- No Entry ----- When ID 1 Comes in to picture (Enties happened to Table) 1 4 1 3 2 1 5 2 4 1 1 2 2 5 1 When ID 3 Comes into picture (Enties happened to Table) 3 4 3 5 1 3 1 ---- 3 2 ---- Similarly when ID 4 Comes in to picture 4 9 4 2 3 4 10 4 5 1 4 3 4 2 1 4 1 1 9 4 1 10 4 Its basically Updating the mutual connections.No Duplicate entries should happen. Like for example 2 3 and 3 2 are mutually connected and 1 is associated with them so there is no need to insert (3 2 via 1). I think this is my requirement. Anything possible combinations i have missed please let me know. i will Update. Please help me writing the logic or any example using jdbc and java.

    Read the article

  • Updating cached counts in MySQL

    - by phleet
    In order to fix a bug, I have to iterate over all the rows in a table, updating a cached count of children to what its real value should be. The structure of the things in the table form a tree. In rails, the following does what I want: Thing.all.each do |th| Thing.connection.update( " UPDATE #{Thing.quoted_table_name} SET children_count = #{th.children.count} WHERE id = #{th.id} " ) end Is there any way of doing this in a single MySQL query? Alternatively, is there any way of doing this in multiple queries, but in pure MySQL? I want something like UPDATE table_name SET children_count = ( SELECT COUNT(*) FROM table_name AS tbl WHERE tbl.parent_id = table_name.id ) except the above doesn't work (I understand why it doesn't).

    Read the article

  • asp.net detailsview update method not getting new values

    - by Ali
    Hi all, I am binding a detailsview with objectdatasource which gets the select parameter from the querystring. The detailsview shows the desired record, but when I try to update it, my update method gets the old values for the record (and hence no update). here is my detailsview code: <asp:DetailsView ID="dvUsers" runat="server" Height="50px" Width="125px" AutoGenerateRows="False" DataSourceID="odsUserDetails" onitemupdating="dvUsers_ItemUpdating"> <Fields> <asp:CommandField ShowEditButton="True" /> <asp:BoundField DataField="Username" HeaderText="Username" SortExpression="Username" ReadOnly="true" /> <asp:BoundField DataField="FirstName" HeaderText="First Name" SortExpression="FirstName" /> <asp:BoundField DataField="LastName" HeaderText="Last Name" SortExpression="LastName" /> <asp:BoundField DataField="Email" runat="server" HeaderText="Email" SortExpression="Email" /> <asp:BoundField DataField="IsActive" HeaderText="Is Active" SortExpression="IsActive" /> <asp:BoundField DataField="IsOnline" HeaderText="Is Online" SortExpression="IsOnline" ReadOnly="true" /> <asp:BoundField DataField="LastLoginDate" HeaderText="Last Login" SortExpression="LastLoginDate" ReadOnly="true" /> <asp:BoundField DataField="CreateDate" HeaderText="Member Since" SortExpression="CreateDate" ReadOnly="true" /> <asp:TemplateField HeaderText="Membership Ends" SortExpression="ExpiryDate"> <EditItemTemplate> <asp:TextBox ID="TextBox1" runat="server" Text='<%# Bind("ExpiryDate") %>'></asp:TextBox> <cc1:CalendarExtender ID="TextBox1_CalendarExtender" runat="server" Enabled="True" TargetControlID="TextBox1"> </cc1:CalendarExtender> </EditItemTemplate> <InsertItemTemplate> <asp:TextBox ID="TextBox1" runat="server" Text='<%# Bind("ExpiryDate") %>'></asp:TextBox> </InsertItemTemplate> <ItemTemplate> <asp:Label ID="Label1" runat="server" Text='<%# Bind("ExpiryDate") %>'></asp:Label> </ItemTemplate> </asp:TemplateField> </Fields> and here is the objectdatasource code: <asp:ObjectDataSource ID="odsUserDetails" runat="server" SelectMethod="GetAllUserDetailsByUserId" TypeName="QMS_BLL.Membership" UpdateMethod="UpdateUserForClient"> <UpdateParameters> <asp:Parameter Name="User_ID" Type="Int32" /> <asp:Parameter Name="firstName" Type="String" /> <asp:Parameter Name="lastName" Type="String" /> <asp:SessionParameter Name="updatedByUser" SessionField="userId" DefaultValue="1" /> <asp:Parameter Name="expiryDate" Type="DateTime" /> <asp:Parameter Name="Email" Type="String" /> <asp:Parameter Name="isActive" Type="String" /> </UpdateParameters> <SelectParameters> <asp:QueryStringParameter DefaultValue="1" Name="User_ID" QueryStringField="User_ID" Type="Int32" /> </SelectParameters> </asp:ObjectDataSource> Is the OnItemUpdating method still required when you have your custom BLL method called on insertevent? (which is being executed fine in my case but updating with the old values) or am I missing something else? Also I tried to provide an OnItemUpdating method and in there I tried to capture the contents of the textboxes (the new values). I got an exception: "Specified argument was out of the range of valid values. Parameter name: index" when I tried to do: TextBox txtFirstName = (TextBox)dvUsers.Rows[1].Cells[1].Controls[0]; Any help will be most appreciated.

    Read the article

  • how to access mysql table from wamp database using this php code? [migrated]

    - by user3909877
    how to access tables from database by using php in wamp server.i have done the following code but its not working for some reason.is there anything to put in 'action=""'.it is not giving any error but displaying the same page.i want to display table from database on any different entry in dropdown menu and pressing search button.. <p class="h2">Quick Search</p> <div class="sb2_opts"> <p> </p> <form method="post" action="" > <p>Enter your source and destination.</p> <p> From:</p> <select name="from"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <p> To:</p> <select name="To"> <option value="Islamabad">Islamabad</option> <option value="Lahore">Lahore</option> <option value="murree">Murree</option> <option value="Muzaffarabad">Muzaffarabad</option> </select> <input type="submit" value="search" /> </form> </form> </table> <?php if(isset($_POST['from']) and isset($_POST['To'])) { $from = $_POST['from'] ; $to = $_POST['To'] ; $table = array($from, $to); $con=mysqli_connect("localhost"); $mydb=mysql_select_db("homedb"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } switch ($table) { case array ("Islamabad", "Lahore") : $result = mysqli_query($con,"SELECT * FROM flights"); echo "</flights>"; //table name is flights break; case array ("Islamabad", "Murree") : $result = mysqli_query($con,"SELECT * FROM `isb to murree`"); echo "</`isb to murree`>"; //table name isb to murree ; break; case array ("Islamabad", "Muzaffarabad") : $result = mysqli_query($con,"SELECT * FROM `isb to muzz`"); echo "</`isb to muzz`>"; break; //..... //...... default: echo "Your choice is nor valid !!"; } } mysqli_close($con); ?>

    Read the article

< Previous Page | 101 102 103 104 105 106 107 108 109 110 111 112  | Next Page >