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  • How to uncompress a 9GB file in Windows FAT32

    - by Kashif
    I have a 2GB RAR file that contains a 9GB video file. I'm using a FAT32 file system. Now I want to unzip that file but after 4GB I get an error due to the FAT32 file size limit. Now I want to know that how I can extract that video? I know that one way is to convert my partition to NTFS but I don't want to follow that way. I've also tried 7-zip but that again gives error after 4GB. One other way is to split that file but I don't know how I can split a video file that is zipped. So any idea please? How can I get rid of this problem.

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  • Why does a zip file appear larger than the source file especially when it is text?

    - by PeanutsMonkey
    I have a text file that is 19 bytes in size and having compressed the file using zip and 7zip, it appears to be larger. I had a read of the question on Why is a 7zipped file larger than the raw file? as well as Why doesn't ZIP Compression compress anything? but considering the file is not already compressed I would have expected further compression. Attached is a screenshot. EDIT0 I took the example further by creating a file that contained random data as follows dd if=/dev/urandom of=sample.log bs=1G count=1 and attempted to compress the file using both zip and 7zip however there were no compression gains. Why is that?

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  • Apache2 server does not start cannot pen shared object file

    - by sid__
    I am working with Apache and Passenger for a Rails project. And a during a restart I got the following error Cannot load /usr/lib/ruby/gems/1.8/gems/passenger-2.2.11/ext/apache2/mod_passenger.so into server: /usr/lib/ruby/gems/1.8/gems/passenger-2.2.11/ext/apache2/mod_passenger.so: cannot open shared object file: No such file or directory However there is no change in the apache configuration file. I have attached the snippet from the conf file 287 LoadModule passenger_module /usr/lib/ruby/gems/1.8/gems/passenger-2.2.11/ext/apache2/mod_passenger.so 288 PassengerRoot /usr/lib/ruby/gems/1.8/gems/passenger-2.2.11 289 PassengerRuby /usr/bin/ruby1.8 I am also unable to locate the shared object file in the location pointed to by the server though I am not really sure how the .so file is works (created/destroyed) I would also appreciate it if someone could explain to me what exactly has happened. I understand the shared object file is mission, what could be the reason it got deleted.

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  • How to Unblock Previously Unblocked CHM File

    - by OnesimusUnbound
    Wierd? Anyway, on Windows 7, I've downloaded a CHM file on the desktop and unblocked it by Property > Unblock. I moved the CHM file to a folder on the desktop to organize the files, and when I opened the file, the content of the CHM reader couldn't open the pages in the CHM file. I've open the file property, but the unblocked button is gone. Well, I can simply download the file, though I find the problem interesting and I need to know how to troubleshoot it. So, how can I unblock the said file? Update Clarified location. I was referring to a folder in the desktop, not in network drive.

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  • mini-dinstall chmod 0600 changes file: Operation not permitted

    - by V. Reileno
    I'm getting "Operation not permitted" in the mini-dinstall.log everytime a new debian package has been uploaded on the custom debian repository using dput. The deb file is installed successfuly but the changes file remains in the incoming folder. I can not use a post-install script when the changes file can not be processed. How can I fix this problem? Traceback (most recent call last): File "/usr/bin/mini-dinstall", line 780, in install retval = self._install_run_scripts(changefilename, changefile) File "/usr/bin/mini-dinstall", line 826, in _install_run_scripts do_chmod(changefilename, 0600) File "/usr/bin/mini-dinstall", line 193, in do_chmod do_and_log('Changing mode of "%s" to %o' % (name, mode), os.chmod, name, mode) File "/usr/bin/mini-dinstall", line 176, in do_and_log function(*args) OSError: [Errno 1] Operation not permitted: '/srv/debian-repository/mini-dinstall/incoming/debian-repository_1.3_amd64.changes' The mini-dinstall permissions: ls -lad incoming/ drwxrws--- 2 mini-dinstall debian-repository-uploader 4096 Jun 6 11:45 incoming/ ls -la incoming/debian-repository_1.3_amd64.changes -rw-rw---- 1 uploader-user debian-repository-uploader 1322 Jun 6 11:43 incoming/debian-repository_1.3_amd64.changes groups uploader-user uploader-user : uploader-user adm users debian-repository debian-repository-uploader puppet-client-updater groups mini-dinstall mini-dinstall : mini-dinstall debian-repository-uploader Cheers and thanks V.

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  • MPlayer refuses to generate mono wav file

    - by JCCyC
    I want to downsample an existing audio file to 8KHz mono. This command line downsamples it to stereo: mplayer -quiet -vo null -vc dummy -af volume=0,resample=8000:0:1 -ao pcm:waveheader:file="/tmp/blah1.wav" ~/from_my_cellphone.3ga It generates a file that the file utility identifies as stereo: $ file /tmp/blah1.wav /tmp/blah1.wav: RIFF (little-endian) data, WAVE audio, Microsoft PCM, 16 bit, stereo 8000 Hz Now, if I read the documentation correctly, I should add pan=1:0.5:0.5 so I get a file that's half the size: mplayer -quiet -vo null -vc dummy -af volume=0,resample=8000:0:1:pan=1:0.5:0.5 -ao pcm:waveheader:file="/tmp/blah2.wav" ~/from_my_cellphone.3ga But it doesn't! blah2.wav is identical to blah1.wav! What am I doing wrong?

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  • Unrecognized file format .mdb in Microsoft Access -- repair doesn't fix it

    - by user1282159
    So what I have is a file from a staff computer that I believe is an access file b/c its called .mdb, however it does not open! I even tried to follow the repair steps (create a new file and use the "compact and repair" tool. and all I keep getting is "unrecognized file format *.mdb" (replace the * with the filename). I am not even sure it is an access file. I have tried using Office 2007 and office 2010 but neither work. Is there a way to fix this that is not on the Microsoft website? Or to determine whether this is actually an access file and not some other file with the extension renamed? Any help would be appricated, thanks.

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  • How can I find the original un-changed configuration file to compare with the *.rpmnew file?

    - by User
    While upgrading from CentOS 5.7 to 5.8 I've received the following warnings: warning: /etc/sysconfig/iptables-config created as /etc/sysconfig/iptables-config.rpmnew warning: /etc/ssh/sshd_config created as /etc/ssh/sshd_config.rpmnew warning: /etc/odbcinst.ini created as /etc/odbcinst.ini.rpmnew (To know the reason for such files, and what one can do with them read - Why do I have .rpmnew file after an update? ) I want to know what exactly has been change in the default config file by comparing the old default file (the original un-changed configuration file) with the new default file (*.rpmnew). Then, I can apply the changes to my modified file (aka diff merge). The problem is I don't know where can I find the original un-changed configuration file...

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  • word 2010 Macro to name and Save file when opened

    - by Phillip Clark
    I have a word document template and will be using a hyper link in Excel to access the word file. The issue I need to resolve is making sure once it is opened a message field box is "popped" up asking the user to create a new file name ... (in this case the current date) for each time the file is opened. In the message pop when finished entering in file name they click yes and then the save screen comes up with the path/file type (macro enabled document) and the file name they have already entered in the pop up.. All they should have to do from the save screen is click ok and it saves the file to a certain path/folder on the C drive of the computer. Once they finish typing in their notes they click a active x button to save and close and they are finished. If anyone can help with this it would be fantastic.

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  • How to Split a Big Postscript file (3000 pages) into one individual file per page (using Windows 7)?

    - by Pablo
    Hi, I'm having trouble doing the following: I have a big PDF file that I converted to postscript (for commercial printing). The resulting file is too big to be processed by the printer (machine). I've been trying to find a way to either: Convert from the original (many pages) PDF file to many Postscript file (one postcript file per PDF page in original PDF file(. Convert from PDF to PS (or even EPS). - I managed to do this Then split the PS file into a collection of smaller files. I've tried using Ghostscript, but it is all gibberish to me. Thanks. PS. If you have a good GS tutorial (for dummies?), please share the link.

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  • split a textfile after each n matches to a new file using sed or awk

    - by ozz
    i tried to split a file in parts of n matches each. The file is just one line and the seperator is '<br>' foo<br>bar<br>.....<br> I just want to split the file in parts, where each file has 100 datasets (text plus <br>)( normaly 100 datasets, but at the end maybe less) I already played around with this ... split-file-in-2-with-sed and this split-one-file-into-multiple-files-based-on-pattern sed.exe -e "^.*.<br>{0,100}/g" < original.txt > first_half.txt The split do not work an the result is only 1 file instead of many.

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  • Stream tar.gz file from FTP server

    - by linker
    Here is the situation: I have a tar.gz file on a FTP server which can contain an arbitrary number of files. Now what I'm trying to accomplish is have this file streamed and uploaded to HDFS through a Hadoop job. The fact that it's Hadoop is not important, in the end what I need to do is write some shell script that would take this file form ftp with wget and write the output to a stream. The reason why I really need to use streams is that there will be a large number of these files, and each file will be huge. It's fairly easy to do if I have a gzipped file and I'm doing something like this: wget -O - "ftp://${user}:${pass}@${host}/$file" | zcat But I'm not even sure if this is possible for a tar.gz file, especially since there are mutliple files in the archive. I'm a bit confused on what direction to take for this, any help would be greatly appreciated.

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  • SQL SERVER – SHRINKFILE and TRUNCATE Log File in SQL Server 2008

    - by pinaldave
    Note: Please read the complete post before taking any actions. This blog post would discuss SHRINKFILE and TRUNCATE Log File. The script mentioned in the email received from reader contains the following questionable code: “Hi Pinal, If you could remember, I and my manager met you at TechEd in Bangalore. We just upgraded to SQL Server 2008. One of our jobs failed as it was using the following code. The error was: Msg 155, Level 15, State 1, Line 1 ‘TRUNCATE_ONLY’ is not a recognized BACKUP option. The code was: DBCC SHRINKFILE(TestDBLog, 1) BACKUP LOG TestDB WITH TRUNCATE_ONLY DBCC SHRINKFILE(TestDBLog, 1) GO I have modified that code to subsequent code and it works fine. But, are there other suggestions you have at the moment? USE [master] GO ALTER DATABASE [TestDb] SET RECOVERY SIMPLE WITH NO_WAIT DBCC SHRINKFILE(TestDbLog, 1) ALTER DATABASE [TestDb] SET RECOVERY FULL WITH NO_WAIT GO Configuration of our server and system is as follows: [Removed not relevant data]“ An email like this that suddenly pops out in early morning is alarming email. Because I am a dead, busy mind, so I had only one min to reply. I wrote down quickly the following note. (As I said, it was a single-minute email so it is not completely accurate). Here is that quick email shared with all of you. “Hi Mr. DBA [removed the name] Thanks for your email. I suggest you stop this practice. There are many issues included here, but I would list two major issues: 1) From the setting database to simple recovery, shrinking the file and once again setting in full recovery, you are in fact losing your valuable log data and will be not able to restore point in time. Not only that, you will also not able to use subsequent log files. 2) Shrinking file or database adds fragmentation. There are a lot of things you can do. First, start taking proper log backup using following command instead of truncating them and losing them frequently. BACKUP LOG [TestDb] TO  DISK = N'C:\Backup\TestDb.bak' GO Remove the code of SHRINKING the file. If you are taking proper log backups, your log file usually (again usually, special cases are excluded) do not grow very big. There are so many things to add here, but you can call me on my [phone number]. Before you call me, I suggest for accuracy you read Paul Randel‘s two posts here and here and Brent Ozar‘s Post here. Kind Regards, Pinal Dave” I guess this post is very much clear to you. Please leave your comments here. As mentioned, this is a very huge subject; I have just touched a tip of the ice-berg and have tried to point to authentic knowledge. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Backup and Restore, SQL Data Storage, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – master Database Log File Grew Too Big

    - by pinaldave
    Couple of the days ago, I received following email and I find this email very interesting and I feel like sharing with all of you. Note: Please read the whole email before providing your suggestions. “Hi Pinal, If you can share these details on your blog, it will help many. We understand the value of the master database and we take its regular back up (everyday midnight). Yesterday we noticed that our master database log file has grown very large. This is very first time that we have encountered such an issue. The master database is in simple recovery mode; so we assumed that it will never grow big; however, we now have a big log file. We ran the following command USE [master] GO DBCC SHRINKFILE (N'mastlog' , 0, TRUNCATEONLY) GO We know this command will break the chains of LSN but as per our understanding; it should not matter as we are in simple recovery model.     After running this, the log file becomes very small. Just to be cautious, we took full backup of the master database right away. We totally understand that this is not the normal practice; so if you are going to tell us the same, we are aware of it. However, here is the question for you? What operation in master database would have caused our log file to grow too large? Thanks, [name and company name removed as per request]“ Here was my response to them: “Hi [name removed], It is great that you are aware of all the right steps and method. Taking full backup when you are not sure is always a good practice. Regarding your question what could have caused your master database log to grow larger, let me try to guess what could have happened. Do you have any user table in the master database? If yes, this is not recommended and also NOT a good practice. If have user tables in master database and you are doing any long operation (may be lots of insert, update, delete or rebuilding them), then it can cause this situation. You have made me curious about your scenario; do revert back. Kind Regards, Pinal” Within few minutes I received reply: “That was it Pinal. We had one of the maintenance task log tables created in the master table, which had many long transactions during the night. We moved it to newly created database named ‘maintenance’, and we will keep you updated.” I was very glad to receive the email. I do not suggest that any user table should be created in the master database. It should be left alone from user objects. Now here is the question for you – can you think of any other reason for master log file growth? Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Backup and Restore, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Extract Audio from a Video File with Pazera Free Audio Extractor

    - by DigitalGeekery
    Have you ever wanted to extract some or all of the audio from a video file?  Today we’ll take a look at Pazera Free Audio Extractor. A simple audio converter that specializes in that very task. Download the Pazera Free Audio Extractor. (See download link below) You’ll need to unzip the download folder, but there is no need to install the application. Simply double-click the AudioExtractor.exe file to run the application. To add your video files to the queue to be converted, click on the Add files  button at the top left. You can add multiple files to the queue and convert them all at one time. Browse for your video file, and click Open.   Your video will be added to the Queue for processing.   Under Output directory you can choose to output to a folder of your choice. Outputting to the same folder as the input folder is the default.   Pazera Free Audio Extractor includes pre-configured profiles that will simplify the process of choosing conversion settings. To load a profile, choose one from the Profile drop down list and then click the Load button. You can choose to output to MP3, AAC, AC3, WMA, FLAC, OGG or WAV file format.   You will see the profile update the Audio settings in the panels at the lower left of the application. If you wish, you may also select your own custom settings. Advanced Settings The Advanced settings can be used if you want to extract only a portion of the the audio, such as a clip of dialog or a song from a movie. To extract only a portion of the audio, set the start time by selecting the Start time offset check box, then entering the time in the video clip where the audio begins. To set the end time, begin by selecting the Duration check box. Now, you can either select the Duration radio button and enter the amount of time for which you would like to extract the audio, or you can select the End time offset radio button and enter the time in the video clip where the audio ends. When you are ready to convert, click the CONVERT button on the menu at the top of the screen.   An output box will open and display the conversion progress. When finished, click Close.   Now you are ready to enjoy your audio clip. Pazera Free Audio Extractor is a basic audio tool that is easy enough for everyone to use. It runs on Windows only and supports most common video formats including AVI, FLV, MP4, MPG, MOV, 3GP, and WMV. Download Free Audio Extractor 1.3 Similar Articles Productive Geek Tips Eufony Free Audio Player – Resource Gentle Audio PlayerConvert .3GP and .3G2 Files to AVI / MPEG for FreeTurn Off Auto-Play of Audio and Video CDs and DVDs in UbuntuHow to Make/Edit a movie with Windows Movie Maker in Windows VistaEasily Change Audio File Formats with XRECODE TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Use Printflush to Solve Printing Problems Icelandic Volcano Webcams Open Multiple Links At One Go NachoFoto Searches Images in Real-time Office 2010 Product Guides Google Maps Place marks – Pizza, Guns or Strip Clubs

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  • Open a File Browser From Your Current Command Prompt/Terminal Directory

    - by The Geek
    Ever been doing some work at the command line when you realized… it would be a lot easier if I could just use the mouse for this task? One command later, you’ll have a window open to the same place that you’re at. This same tip works in more than one operating system, so we’ll detail how to do it in every way we know how. Open a File Browser in Windows We’ve actually covered this before when we told you how to open an Explorer window from the command prompt’s current directory, but we’ll briefly review: Just type the follow command into your command prompt: explorer . Note: You could actually just type “start .” instead. And you’ll then see a file browsing window set to the same directory you were previous at. And yes, this screenshot is from Vista, but it works the same in every version of Windows. If that wasn’t good enough, you should really read how you can navigate in the File Open/Save dialogs with just the keyboard—now that’s a Stupid Geek Trick! Open a File Browser in Linux For this exercise, we’re going to assume that you’re using Gnome under a Linux flavor like Ubuntu, because that’s the most common. From your terminal window, just type in the following command: nautilus . And the next thing you know, you’ll have a file browser window open at the current location. You’ll see some type of error message at the prompt, but you can pretty much ignore that. You can also use “gnome-open .” if you want. Open Finder in Mac OS X All the Mac computers in this office are running Linux, so we haven’t had a chance to verify, but you should be able to use the following command on OS X to open Finder in the current terminal location: open . Open Dolphin on Linux KDE4 dolphin . Got any extra tips to help out your fellow readers? How do you do the same thing in KDE3? What about OS X? Leave your savvy advice in the comments, and maybe we’ll update the article. Or not. Either way, it’ll help somebody! Similar Articles Productive Geek Tips Keyboard Ninja: Concatenate Multiple Text Files in WindowsStupid Geek Tricks: Open an Explorer Window from the Command Prompt’s Current DirectoryHow to automate FTP uploads from the Windows Command LineShell Geek: Rename Multiple Files At OnceAdd "Open with gedit" to the right click menu in Ubuntu TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Home Networks – How do they look like & the problems they cause Check Your IMAP Mail Offline In Thunderbird Follow Finder Finds You Twitter Users To Follow Combine MP3 Files Easily QuicklyCode Provides Cheatsheets & Other Programming Stuff Download Free MP3s from Amazon

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  • Solving File Upload Cancel Issue

    - by Frank Nimphius
    In Oracle JDeveloper 11g R1 (I did not test 11g R2) the file upload component is submitted even if users click a cancel button with immediate="true" set. Usually, immediate="true" on a command button by-passes all modle updates, which would make you think that the file upload isn't processed either. However, using a form like shown below, pressing the cancel button has no effect in that the file upload is not suppressed. <af:form id="f1" usesUpload="true">        <af:inputFile label="Choose file" id="fileup" clientComponent="true"                 value="#{FileUploadBean.file}"  valueChangeListener="#{FileUploadBean.onFileUpload}">   </af:inputFile>   <af:commandButton text="Submit" id="cb1" partialSubmit="true"                     action="#{FileUploadBean.onInputFormSubmit}"/>   <af:commandButton text="cancel" id="cb2" immediate="true"/> </af:form> The solution to this problem is a change of the event root, which you can achieve either by setting i) partialSubmit="true" on the command button, or by surrounding the form parts that should not be submitted when the cancel button is pressed with an ii) af:subform tag. i) partialSubmit solution <af:form id="f1" usesUpload="true">      <af:inputFile .../>   <af:commandButton text="Submit" .../>   <af:commandButton text="cancel" immediate="true" partialSubmit="true" .../> </af:form> ii) subform solution <af:form id="f1" usesUpload="true">   <af:subform id="sf1">     <af:inputFile ... />     <af:commandButton text="Submit" ..."/>   </af:subform>   <af:commandButton text="cancel" immediate="true" .../> </af:form> Note that the af:subform surrounds the input form parts that you want to submit when the submit button is pressed. By default, the af:subform only submits its contained content if the submit issued from within.

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  • Is redis a durable datastore?

    - by allyourcode
    By "durable" I mean, the server can crash at any time, and as long as the disk remains in tact, no data is lost (see ACID). Seems like that's what journaling mode is for, but if you enable journaling, doesn't that defeat the purpose of operating on in-memory data? Read operations might not be affected by journaling, but it seems like journaling would kill your write performance.

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  • read url in binary mode in java

    - by Andrew Zawok
    In java I need to read a binary file from a site and write it to a disk file. This example http://java.sun.com/docs/books/tutorial/networking/urls/readingURL.html could read webpages succesfully, but when I try to read a binary file from my localhost server and write it to a disk file the contents change, corrupting the binary file. Using fc I see that 0x90 is changed to 0x3F and other changes. How do I acess the binary files (read url and write to file) without java or anything else changing ANY characters, like doing any newline conversions or character conversions or anything else, simply reading input url and writing it out as a file.

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  • How to get a 64 bit dll with c source file, def file, link file by using command line in vc 6.0

    - by allan
    Hi, all My compile environment is windows xp and vc 6.0. Now I have a c source file(msgRout.c), def file(msgRout.def), link file(msgRout.link), then I use commands below to get a 32 bit dll: 1.cl /I ../include -c -W3 -Gs- -Z7 -Od -nologo -LD -D_X86_=1 -DWIN32 -D_WIN32 -D_MT -D_DLL msgRout.c 2.lib -out:msgRout.lib -def:msgRout.def -machine:i386 3.link /LIBPATH:../../Lib -nod -nologo -debug:full -dll @msgRout.link -out:msgRout.dll But the dll I got cannot be loaded on X64 application. it required a 64 bit dll. So here is my question: Can I get a 64 bit dll with vc 6.0? Using only above 3 commands alike, how can I get 64 bit dll? Many GREAT THANKS!!! Allan

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  • What are possible reasons for java.io.IOException: "The filename, directory name, or volume label sy

    - by Turismo
    I am trying to copy a file using the following code: File targetFile = new File(targetPath + File.separator + filename); ... targetFile.createNewFile(); fileInputStream = new FileInputStream(fileToCopy); fileOutputStream = new FileOutputStream(targetFile); byte[] buffer = new byte[64*1024]; int i = 0; while((i = fileInputStream.read(buffer)) != -1) { fileOutputStream.write(buffer, 0, i); } For some users the targetFile.createNewFile results in this exception: java.io.IOException: The filename, directory name, or volume label syntax is incorrect at java.io.WinNTFileSystem.createFileExclusively(Native Method) at java.io.File.createNewFile(File.java:850) Filename and directory name seem to be correct. The directory targetPath is even checked for existence before the copy code is executed and the filename looks like this: AB_timestamp.xml The user has write permissions to the targetPath and can copy the file without problems using the OS. As I don't have access to a machine this happens on yet and can't reproduce the problem on my own machine I turn to you for hints on the reason for this exception.

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  • Shell script to process files

    - by Harish
    I need to write a Shell Script to process a huge folder of nearly 20 levels.I have to process each and every file and check which files contain lines like select insert update When I mean line it should take the line till I find a semicolon in that file. I should get a result like this C:/test.java select * from dual C:/test.java select * from test C:/test1.java select * from tester C:/test1.java select * from dual and so on.Right now I have a script to read all the files #!bin/ksh FILE=<FILEPATH to be traversed> TEMPFILE=<Location of Temp file> cd $FILE for f in `find . ! -type d`; do cat $FILE/addedText.txt>>$TEMPFILE/newFile.txt cat $f>>$TEMPFILE/newFile.txt rm $f cat $TEMPFILE/newFile.txt>>$f rm $TEMPFILE/newFile.txt done I have very little knowledge of awk and sed to proceed further in reading each file and achieve what I want to.Can anyone help me in this

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  • How to instantiate a FormFile Object ?

    - by Mercer
    Hello, i have a String with a path of my file and i want to instancie a new FormFile with this String. It's possible ..? My code: public ArrayList<FormFile> getFilesFromFolder(String path) { File file = new File(path); ArrayList<FormFile> vFiles = new ArrayList<FormFile>(); if (file.exists()) { File[] files = file.listFiles(); int i; for (i = 0; i < files.length; i++) { if (files[i].isFile()) { vFiles.add((FormFile) files[i]); } } } else { vFiles = null; } return vFiles; } but i have an error in this line vFiles.add((FormFile) files[i]);

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  • How can I test whether a csv file is currently open and being written to - the file, not a file hand

    - by Henry
    I've seen a few questions/answers here that deal with this, but none really give me an answer/solution. I've got a Clipper system writing csv files to a Windows directory. I have a perl script running on a Linux server that is reading a mount of that Windows directory and importing the files to a database. Right now we're using flag files to indicate when a csv is no longer being written to; the flag files gets written after the csv is done. I'd really rather just get what I need from the csv itself, but I can't seem to find a way to tell when the file is open and being written to. lsof doesn't seem to answer my need. I've tried using flock and open the file with an exclusive lock, thinking it might throw an error if the file is being modified, but it doesn't. Any thoughts?

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  • Reuse C++ Header files

    - by Amrish
    Guys, I have a Visual C++ solution with 2 projects AlgorithmA & AlgorithmB and both share a common header file RunAlgo.h with the class declaration. Each project in the solution has its own unique implementation for the header file. I am trying to compile a DLL out of the common header file RunAlgo.h and add reference to this DLL in the projects AlgorithmA & AlgorithmB. I have then included separate RunAlgo.cpp definition file in both my projects. The problem is that I am getting linker errors while compiling the new DLL project which has only the header file. So, the question is Can a header file with only class declaration be compiled into a DLL (Similar to class library containing an Interface in C#)? For the above scenario, is there a better approach to reuse the common Header file among projects? Should the above method work (re-check my code?)

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