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  • What is the result of this SQL query?

    - by Martin
    I'm working on a mock exam paper at the moment, however I have no set of correct answers and I'm not sure what the correct answer of this SQL query is. Given a table: foo, bar a , 1 b , 3 a , 2 c , 1 and the query: SELECT foo, sum(bar) FROM table GROUP BY foo The two ways I can see this going are either: a 3 a 3 b 3 c 1 or a 3 b 3 c 1 Thanks.

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  • How to get an array of members of an array

    - by Mystere Man
    Suppose I have a class public class Foo { public Bar { get; set; } } Then I have another class public class Gloop { public List<Foo> Foos { get; set; } } What's the easiest way to get a List of Foo.Bars? I'm using C# 4.0 and can use Linq if that is the best choice. My first thought was something like

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  • Flattening out a lib directory using jarjar

    - by voodoogiant
    I'm trying to flatten out the lib directory of a project using jarjar, where it will produce a jar file with my main code and all my required libraries inside of it. I can get the project code into the jar, but I need to find a way to get every jar in the './lib/' directory extracted to the base directory of the final output jar. I don't want it flattened in the sense that I still want the package hiearchy preserved. I could manually list every jar file using zipfileset, but I was hoping to do it dynamically. I would also like to include any *.so files flattened into the base directory of the output jar so I can extract them into a temp dir easily without having to search through the jar. For example my lib directory... ./lib/library1.jar ./lib/library2.jar ./lib/foo/library3.jar ./lib/foo/bar.so would look like this when cracked open in the output jar file... /..library1_package_hierarchy../lib1.class /..library1_package_heirarchy../lib2.class ... (and so on) /..library2_package_hierarchy../lib1.class /..library2_package_heirarchy../lib2.class ... (and so on) /..library3_package_hierarchy../lib1.class <-- foo gone /..library3_package_heirarchy../lib2.class <-- foo gone /bar.so <-- foo gone

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  • template specilization using member enums

    - by Altan
    struct Bar { enum { Special = 4 }; }; template<class T, int K> struct Foo {}; template<class T> struct Foo<T::Special> {}; Usage: Foo<Bar> aa; fails to compile using gcc 4.1.2 It complains about the usage of T::Special for partial specilization of Foo. If Special was a class the solution would be to a typename in front of it. Is there something equivalent to it for enums (or integers)? Thanks, Altan

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  • Why can't I enforce derived classes to have parameterless constructors?

    - by FrisbeeBen
    I am trying to do the following: public class foo<T> where T : bar, new() { public foo() { _t = new T(); } private T _t; } public abstract class bar { public abstract void someMethod(); // Some implementation } public class baz : bar { public overide someMethod(){//Implementation} } And I am attempting to use it as follows: foo<baz> fooObject = new foo<baz>(); And I get an error explaining that 'T' must be a non-abstract type with a public parameterless constructor in order to use it as parameter 'T' in the generic type or method. I fully understand why this must be, and also understand that I could pass a pre-initialized object of type 'T' in as a constructor argument to avoid having to 'new' it, but is there any way around this? any way to enforce classes that derive from 'bar' to supply parameterless constructors?

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  • Override one css class with another?

    - by user246114
    Hi, I have a list, with an li style defined. I want to replace the style of an individual element, but it doesn't seem to have any visual effect. Example: .myList li { background-color: yellow; } .foo { background-color: green; } <ul class='myList'> <li>Hello</li> </ul> When I add an item to the list, it has the .myList li style applied properly. I try now to remove all styles and apply the foo style to a single item (using jquery): $(item).removeClass(); $(item).addClass("foo"); the item does not change color to green though, but this reports the class is set to 'foo': alert($(item).attr('class')); so I guess I'm not understanding css rules here, looks like the li class definition is just overriding whatever else I do, however I want the reverse to be true, I want to override the li style definition with foo. How do we do this? Thanks

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  • Deserialize Xml with empty elements in C#

    - by user204086
    Trying to deserialize some xml snippits into objects. The problem is that I'm getting an invalid format on every empy element tag. I can deserialize the object no problem when all of the elements have values. Or the empty elements are ommitted. Xml Snippit: <foo><propOne>1</propOne><propTwo /></foo> C# Class: [Serialilbe()] public class foo { public foo(){} [XmlElementAttribute(IsNullable = true)] public int? propOne {get;set;} [XmlElementAttribute(IsNullable = true)] public int? propTwo {get;set;} } Is there a setting on the class I can make to adjust the parsing? or Is there an easy way I can apply xsl to remove these elements? or Should I use regEx to remove the empty elements be fore desrializing? or an even better way?

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  • autofac's Func<T> to resolve named service

    - by ppiotrowicz
    Given registered services: builder.RegisterType<Foo1>().Named<IFoo>("one").As<IFoo>(); builder.RegisterType<Foo2>().Named<IFoo>("two").As<IFoo>(); builder.RegisterType<Foo3>().Named<IFoo>("three").As<IFoo>(); Can I retrieve named implementations of IFoo interface by injecting something like Func<string, IFoo ? public class SomeClass(Func<string, IFoo> foo) { var f = foo("one"); Debug.Assert(f is Foo1); var g = foo("two"); Debug.Assert(g is Foo2); var h = foo("three"); Debug.Assert(h is Foo3); } I know I can do it with Meta<, but I don't want to use it.

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  • Rails 2.3.5: How does one access code inside of lib/directory/file.rb?

    - by randombits
    I created a file so I can share a method amongst many models in lib/foo/bar_woo.rb. Inside of bar_woo.rb I defined the following: module BarWoo def hello puts "hello" end end Then in my model I'm doing something like: def MyModel < ActiveRecord::Base include Foo::BarWoo def some_method Foo::BarWoo.hello end end The interpreter is complaining that it expected bar_woo.rb to define Foo::BarWoo. The Agile Web Development with Rails book states that if files contain classes or modules and the files are named using the lowercase form of the class or module name, then Rails will load the file automatically. I didn't require it because of this.

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  • zend form multicheckboxes naming

    - by neziric
    how do i have to nest multicheckboxes so that they are named like this 'foo[]['bar']' . i've used subforms but they give me naming like this 'foo[bar][]'. my code: $sub = new Zend_Form_SubForm('sub'); $wish = new Zend_Form_Element_MultiCheckbox('bar'); $wish ->setMultiOptions($education_direction->getAll()) ->setLabel('Wish') ->setRequired(true); $sub-addElements(array( $wish )); $this-addSubForm($sub, 'foo');

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  • C++: Delete a struct?

    - by Rosarch
    I have a struct that contains pointers: struct foo { char* f; int* d; wchar* m; } I have a vector of shared pointers to these structs: vector<shared_ptr<foo>> vec; vec is allocated on the stack. When it passes out of scope at the end of the method, its destructor will be called. (Right?) That will in turn call the destructor of each element in the vector. (Right?) Does calling delete foo delete just the pointers such as foo.f, or does it actually free the memory from the heap?

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  • Is it possibile to modify a link value with Beautifulsoup without recreating the all link?

    - by systempuntoout
    Starting from an Html input like this: <p> <a href="http://www.foo.com" rel="nofollow">this is foo</a> <a href="http://www.bar.com" rel="nofollow">this is bar</a> </p> is it possible to modify the <a> node values ("this i foo" and "this is bar") adding the suffix "PARSED" to the value without recreating the all link? The result need to be like this: <p> <a href="http://www.foo.com" rel="nofollow">this is foo_PARSED</a> <a href="http://www.bar.com" rel="nofollow">this is bar_PARSED</a> </p> And code should be something like: from BeautifulSoup import BeautifulSoup soup = BeautifulSoup(html) for link_tag in soup.findAll('a'): link_tag.string = link_tag.string + '_PARSED' #This obviously does not work

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  • AS3: Performance question calling an event function with null param

    - by adehaas
    Lately I needed to call a listener function without an actual listener like so: foo(null); private function foo(event:Event):void { //do something } So I was wondering if there is a significant difference regarding performance between this and using the following, in which I can prevent the null in calling the function without the listener, but am still able to call it with a listener as well: foo(); private function foo(event:Event = null):void { } I am not sure wether it is just a question of style, or actually bad practice and I should write two similar functions, one with and one without the event param (which seems cumbersome to me). Looking forward to your opinions, thx.

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  • How can I make hash key lookup case-insensitive?

    - by mseery
    Evidently hash keys are compared in a case-sensitive manner. $ perl -e '%hash = ( FOO => 1 ); printf "%s\n", ( exists $hash{foo} ) ? "Yes" : "No";' No $ perl -e '%hash = ( FOO => 1 ); printf "%s\n", ( exists $hash{FOO} ) ? "Yes" : "No";' Yes Is there a setting to change that for the current script? Thanks.

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  • Using memset on structures in C++

    - by garry
    Hey guys. I am working on fixing older code for my job. It is currently written in C++. They converted static allocation to dynamic but didn't edit the memsets/memcmp/memcpy. This is my first programming internship so bare with my newbe-like question. The following code is in C, but I want to have it in C++ ( I read that malloc isn't good practice in C++). I have two scenarios: First, we have f created. Then you use &f in order to fill with zero. The second is a pointer *pf. I'm not sure how to set pf to all 0's like the previous example in C++. Could you just do pf = new foo instead of malloc and then call memset(pf, 0, sizeof(foo))? struct foo { ... } f; memset( &f, 0, sizeof(f) ); //or struct foo { ... } *pf; pf = (struct foo*) malloc( sizeof(*pf) ); memset( pf, 0, sizeof(*pf) );

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  • C++ Template Question

    - by user323422
    see following code and please clear doubts1. as ABC is template why it not showing error when we put defination of ABC class member function in test.cpp 2.if i put test.cpp code in test.h , then it working fine // test.h template <typename T> class ABC { public: void foo( T& ); void bar( T& ); }; // test.cpp template <typename T> void ABC<T>::foo( T& ) {} // definition template <typename T> void ABC<T>::bar( T& ) {} // definition template void ABC<char>::foo( char & ); // 1 // main.cpp #include "test.h" int main() { ABC<char> a; a.foo(); // working a.bar(); // link error }

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  • Validate a string

    - by Activist
    I'm not that good with regular expressions... I need a JavaScript regular expression that will do the following: The string can contain letters (upper and lower case), but not punctuations such as éàïç... The string can contain numbers (0..9) anywhere in the string, except on the first position. The string can contain underscores (_). Valid strings: foo foo1 foo_bar fooBar Invalid strings: 1foo -- number as first character foo bar -- space föo -- punctuation ö Many thanks!

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  • Functional equivalent of if (p(f(a), f(b)) a else b

    - by oxbow_lakes
    I'm guessing that there must be a better functional way of expressing the following: def foo(i: Any) : Int if (foo(a) < foo(b)) a else b So in this example f == foo and p == _ < _. There's bound to be some masterful cleverness in scalaz for this! I can see that using BooleanW I can write: p(f(a), f(b)).option(a).getOrElse(b) But I was sure that I would be able to write some code which only referred to a and b once. If this exists it must be on some combination of Function1W and something else but scalaz is a bit of a mystery to me! EDIT: I guess what I'm asking here is not "how do I write this?" but "What is the correct name and signature for such a function and does it have anything to do with FP stuff I do not yet understand like Kleisli, Comonad etc?"

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  • How do I restrict accepting only one type in my generic method?

    - by kunjaan
    I have a generic function foo, which accepts any type and prints them out. public static <T> T foo(T... arg) { List<T> foo = Arrays.asList(arg); for (T t : foo) { System.out.println(t); } return null; } How do I make sure that the arguments received are of only 1 type. For example, {1,'a',3} should be invalid. It should either be all numbers or all characters.

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  • Is a string formatter that pulls variables from its calling scope bad practice?

    - by Eric
    I have some code that does an awful lot of string formatting, Often, I end up with code along the lines of: "...".format(x=x, y=y, z=z, foo=foo, ...) Where I'm trying to interpolate a large number of variables into a large string. Is there a good reason not to write a function like this that uses the inspect module to find variables to interpolate? import inspect def interpolate(s): return s.format(**inspect.currentframe().f_back.f_locals) def generateTheString(x): y = foo(x) z = x + y # more calculations go here return interpolate("{x}, {y}, {z}")

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  • How to get a variable name as a string in Python?

    - by e-satis
    I would like to be able to get the name of a variable as a string but I don't know if Python has that much introspection capabilities. Something like: >>> print(my_var.__name__) 'my_var' I want to do that because I have a bunch of vars I'd like to turn into a dictionary like : bar=True foo=False >>> my_dict=dict(bar=bar, foo=foo) >>> print mydict >>> print my_dict {'foo': False, 'bar': True} But I'd like something more automatic than that. Python have locals() and vars(), so I guess there is a way.

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  • How can I pass a type as a parameter in scala?

    - by rsan
    I'm having a really hard time trying to figure out how can I store or pass a type in scala. What I want to achive is something like this: abstract class Foo( val theType : type ) object Foo{ case object Foo1 extends Foo(String) case object Foo2 extends Foo(Long) } So at some point I can do this: theFoo match{ case String => "Is a string" case Long => "Is a long" } and when obtaining the object being able to cast it: theFoo.asInstanceOf[Foo1.theType] Is this possible? If is possible, is a good aproach? What I'm trying to achieve ultimately is writing a pseudo schema for byte stream treatment. E.g if I have an schema Array(Foo1,Foo1,Foo2,Foo3,Foo1) I could parse Arrays of bytes that complain with that schema, if at some point I have a different stream of bytes I could just write a new schema Array(Foo3, Foo4, Foo5) without having to reimplement parsing logic. Regards,

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  • std::thread and class constructor and destructor

    - by toeplitz
    When testing threads in C++11 I have created the following example: #include <iostream> #include <thread> class Foo { public: Foo(void) { std::cout << "Constructor called: " << this << std::endl; } ~Foo(void) { std::cout << "Destructor called: " << this << std::endl; } void operator()() const { std::cout << "Operatior called: " << this << std::endl; } }; void test_normal(void) { std::cout << "====> Standard example:" << std::endl; Foo f; } void test_thread(void) { std::cout << "====> Thread example:" << std::endl; Foo f; std::thread t(f); t.detach(); } int main(int argc, char **argv) { test_normal(); test_thread(); for(;;); } Which prints the following: Why is the destructor called 6 times for the thread? And why does the thread report different memory locations?

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