I have a
form that when you submit it, it sends the data for
validation to another php script via ajax.
Validation errors are echo'd back in a div in my
form. A success message also is returned if
validation passes.
The problem is that the
form is still displayed after submit and successful
validation. I want to hid the div after success.
So, I wrote this simple CSS method which works fine when called from the page the
form is displayed on.
The problem is that I cannot seem to call the hide script via returned code. I can return html like
echo "<p>Thanks, your
form passed
validation and is being sent</p>";
So I assumed I could simply echo another line after that
echo "window.onload=displayDiv()"; inside script tags (which I cannot get to display here)...
and that it would hide the
form div.
It does not work. I am assuming that the problem is that the javascript is being returned incorrectly and not being interpreted by the browser...
How can I invoke my 'hide' script on the page via returned data from my
validation script? I can echo back text but the script call is ineffective.
Thanks!
This is the script on the page with the
form...
I can call it to show/hide with something like onclick="displayDiv()" while on the
form but I don't want the user to invoke this... it has be called as the result of a successful
validation when I write the results back to the div...
function displayDiv()
{
var divstyle = new String();
divstyle = document.getElementById("myForm").style.display;
if(divstyle.toLowerCase()=="block" || divstyle == "")
{
document.getElementById("myForm").style.display = "none";
}
else
{
document.getElementById("myForm").style.display = "block";
}
}
PS: I am using the mootools.js library for the
form validation if this matters for the syntax..
