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  • Mod_rewrite works on local, not on remote, version?

    - by TylerT
    I have this site. Let's call it htp://www.mysite.com I have a rewrite rule to change htp://www.mysite.com/?q=words%20etc/0/10 into http://www.mysite.com/words%20etc/0/10 (or http://www.mysite.com//0/10 or http://www.mysite.com/0/10) .htaccess:ErrorDocument 404 htp://www.mysite.com/404.html options +FollowSymlinks rewriteEngine on rewriteCond %{REQUEST_URI} !-f rewriteCond %{REQUEST_URI} !-d rewriteCond %{REQUEST_URI} !index\.php rewriteRule ^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$ index.php/%{THE_REQUEST} [NC] Now, this works on my local apache 2.2.11 server, no errors. However on my host's apache 1.3.41 server, I get the following error: [Sat Mar 5 21:42:14 2011] [alert] [client [ip]] /home/_/public_html/mysite.com/.htaccess: RewriteRule: cannot compile regular expression '^/?([^/]+?)?/?([0-9]+?)/([0-9]+?)$'\n I imagine it's something quirky about the apache version as other sites on this host use mod_rewrite without a hitch. I've tried removing the +followSymlinks line, even the rewrite engine line. I haven't tried removing the conditions cause I don't think I should have to, I'm probably wrong.

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  • 'Scanner' does not name a type error in g++

    - by Max
    Hi. I'm trying to compile code in g++ and I get the following errors: In file included from scanner.hpp:8, from scanner.cpp:5: parser.hpp:14: error: ‘Scanner’ does not name a type parser.hpp:15: error: ‘Token’ does not name a type Here's my g++ command: g++ parser.cpp scanner.cpp -Wall Here's parser.hpp: #ifndef PARSER_HPP #define PARSER_HPP #include <string> #include <map> #include "scanner.hpp" using std::string; class Parser { // Member Variables private: Scanner lex; // Lexical analyzer Token look; // tracks the current lookahead token // Member Functions <some function declarations> }; #endif and here's scanner.hpp: #ifndef SCANNER_HPP #define SCANNER_HPP #include <iostream> #include <cctype> #include <string> #include <map> #include "parser.hpp" using std::string; using std::map; enum { // reserved words BOOL, ELSE, IF, TRUE, WHILE, DO, FALSE, INT, VOID, // punctuation and operators LPAREN, RPAREN, LBRACK, RBRACK, LBRACE, RBRACE, SEMI, COMMA, PLUS, MINUS, TIMES, DIV, MOD, AND, OR, NOT, IS, ADDR, EQ, NE, LT, GT, LE, GE, // symbolic constants NUM, ID, ENDFILE, ERROR }; class Token { public: int tag; int value; string lexeme; Token() {tag = 0;} Token(int t) {tag = t;} }; class Num : public Token { public: Num(int v) {tag = NUM; value = v;} }; class Word : public Token { public: Word() {tag = 0; lexeme = "default";} Word(int t, string l) {tag = t; lexeme = l;} }; class Scanner { private: int line; // which line the compiler is currently on int depth; // how deep in the parse tree the compiler is map<string,Word> words; // list of reserved words and used identifiers // Member Functions public: Scanner(); Token scan(); string printTag(int); friend class Parser; }; #endif anyone see the problem? I feel like I'm missing something incredibly obvious.

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  • What is on the 68000 stack when classic MacOS enters a program?

    - by John Källén
    I'm trying to understand an old classic Mac application's entry point. I've disassembled the first CODE resource (not CODE#0, which is the jump table). The code refers to some variables off the stack: a word at 0004(A7), an array of long words of starting at 000C(A7) whose length is the value at 0004(A7), and a final long word beyond that array that seems to be a pointer to a character string. The array of long words looks like strings at first glance, so it looks superficially like we're dealing with an (int argc, char ** argv) situation, except the "argv" array is inline in the stack frame. What should a program be expecting on its stack / registers when it first gets called by the Mac OS?

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  • Access outer class from inner class: Why is it done this way?

    - by Vuntic
    So most of us know how to access an outer class from an inner class. Searches with those words give oodles of answered questions on that topic. But what I want to know is why the syntax is the way it is. Example: public class A { private class B { public void c() {A.this.d();} } public void d() {System.out.println("You've called d()! Go, you!");} } Why is it A.this.d()? It looks like this is a static field of class A, but... * am confused * Forgive me if this is a repeat; like I said, searches with those words give how-answers.

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  • Minimum 4 Characters or Show Nothing - PHP

    - by ali
    Hi, I want to show up only words with minimum 4 Characters, actually I can limit the hits and show only words with min. 100 hits - but how can I set a min. character length? thank you! function sm_list_recent_searches($before = '', $after = '', $count = 20) { // List the most recent successful searches. global $wpdb, $table_prefix; $count = intval($count); $results = $wpdb->get_results( "SELECT `terms`, `datetime` FROM `{$table_prefix}searchmeter_recent` WHERE 100 < `hits` ORDER BY `datetime` DESC LIMIT $count"); if (count($results)) { foreach ($results as $result) { echo '<a href="'. get_settings('home') . '/search/' . urlencode($result->terms) . '">'. htmlspecialchars($result->terms) .'</a>'.", "; } } }

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  • Simple interlinear gloss: aligned bilingual paragraph

    - by D W
    An interlinear gloss can be used to layout a translation of a document. http://en.wikipedia.org/wiki/Interlinear_gloss Usually this is done word-by-word or morpheme-by-morpheme. However, I would like to do this in a different way, translating entire paragraphs at a time. http://www.optimnem.co.uk/learning/spanish/three-little-pigs.php For now I am not interested in taking into account the order of words or phrases that change order between languages. That is, I don't mind if the words in the paragraph are not aligned or if the length of one paragraph is much longer than the other, causing an overhanging line. As far as I can tell, the following packages do not meet my needs: covingtn.sty cgloss4e.sty gb4e.sty lingmacros.sty - shortex

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  • Regular Expression for accurate word-count using JavaScript

    - by Haidon
    I'm trying to put together a regular expression for a JavaScript command that accurately counts the number of words in a textarea. One solution I had found is as follows: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\b\w+\b/).length -1; But this doesn't count any non-Latin characters (eg: Cyrillic, Hangul, etc); it skips over them completely. Another one I put together: document.querySelector("#wordcount").innerHTML = document.querySelector("#editor").value.split(/\s+/g).length -1; But this doesn't count accurately unless the document ends in a space character. If a space character is appended to the value being counted it counts 1 word even with an empty document. Furthermore, if the document begins with a space character an extraneous word is counted. Is there a regular expression I can put into this command that counts the words accurately, regardless of input method?

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  • How can I reference only a portion of a TextArea's htmlText block?

    - by Charles Shoults
    I have a number of very poor-quality pdf documents that look like 80's photocopies, which I'm rebuilding in Flash (Flex Builder 3 MXML application), representing paragraphs of text in TextAreas so that selected portions can be bold or italic, or whatever I need. I need a way to apply toolTips or event listeners to individual words within the block of text to link those words to a glossary. I'm perfectly happy to create a definition panel that is populated and made visible with a mouseOver, but don't know how to do it to just a portion of the text. Is there a good / clean / easy way to do this?

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  • Using `.index()` on repeating letters

    - by Yarden
    I'm building a function that builds a dictionary with words, such as: {'b': ['b', 'bi', 'bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday'], 'bi': ['bi', 'bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday'], 'birt': ['birt', 'birth', 'birthd', 'birthda', 'birthday'], 'birthda': ['birthda', 'birthday'], 'birthday': ['birthday'], 'birth': ['birth', 'birthd', 'birthda', 'birthday'], 'birthd': ['birthd', 'birthda', 'birthday'], 'bir': ['bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday']} This is what it looks like: def add_prefixs(word, prefix_dict): lst=[] for letter in word: n=word.index(letter) if n==0: lst.append(word[0]) else: lst.append(word[0:n]) lst.append(word) lst.remove(lst[0]) for elem in lst: b=lst.index(elem) prefix_dict[elem]=lst[b:] return prefix_dict It works great for words like "birthday", but when I have a letter that repeats itself, I have a problem... for example, "hello". {'h': ['h', 'he', 'he', 'hell', 'hello'], 'hell': ['hell', 'hello'], 'hello': ['hello'], 'he': ['he', 'he', 'hell', 'hello']} I know it's because of the index (python chooses the index of the first time the letter appears) but I do not know how to solve it. Yes, this is my homework and I'm really trying to learn from you guys :)

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  • iPhone: different icon for homescreen and App Store

    - by arne_
    I would like to know if the app icon on the iPhone can be slightly different than the one shown in a large version in Apple's App Store. It was discussed in short here: http://stackoverflow.com/questions/28551/tips-for-a-successful-appstore-submission/266657#266657 But I wanted to make sure if anyone has more experience with that. To give an example: The New York Times has many words incorporated in its app icon (see http://itunes.apple.com/de/app/nytimes/id284862083?mt=8). Would it be okay to have a full black colored background without the words in the small/homescreen version of the icon?

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  • Java - Optimize finding a string in a list

    - by Mark
    I have an ArrayList of objects where each object contains a string 'word' and a date. I need to check to see if the date has passed for a list of 500 words. The ArrayList could contain up to a million words and dates. The dates I store as integers, so the problem I have is attempting to find the word I am looking for in the ArrayList. Is there a way to make this faster? In python I have a dict and mWords['foo'] is a simple lookup without looping through the whole 1 million items in the mWords array. Is there something like this in java? for (int i = 0; i < mWords.size(); i++) { if ( word == mWords.get(i).word ) { mLastFindIndex = i; return mWords.get(i); } }

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  • Best way in Python to determine all possible intersections in a matrix?

    - by ssweens
    So if I have a matrix (list of lists) of unique words as my column headings, document ids as my row headings, and a 0 or 1 as the values if the word exists in that particular document. What I'd like to know is how to determine all the possible combinations of words and documents where more than one word is in common with more than one document. So something like: [[Docid_3, Docid_5], ['word1', 'word17', 'word23']], [[Docid_3, Docid_9, Docid_334], ['word2', 'word7', 'word23', 'word68', 'word982']], and so on for each possible combination. Would love a solution that provides the complete set of combinations and one that yields only the combinations that are not a subset of another, so from the example, not [[Docid_3, Docid_5], ['word1', 'word17']] since it's a complete subset of the first example. I feel like there is an elegant solution that just isn't coming to mind and the beer isn't helping. Thanks.

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  • Select rows where column LIKE dictionary word

    - by Gerve
    I have 2 tables: Dictionary - Contains roughly 36,000 words CREATE TABLE IF NOT EXISTS `dictionary` ( `word` varchar(255) NOT NULL, PRIMARY KEY (`word`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; Datas - Contains roughly 100,000 rows CREATE TABLE IF NOT EXISTS `datas` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `hash` varchar(32) NOT NULL, `data` varchar(255) NOT NULL, `length` int(11) NOT NULL, `time` int(11) NOT NULL, PRIMARY KEY (`ID`), UNIQUE KEY `hash` (`hash`), KEY `data` (`data`), KEY `length` (`length`), KEY `time` (`time`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=105316 ; I would like to somehow select all the rows from datas where the column data contains 1 or more words. I understand this is a big ask, it would need to match all of these rows together in every combination possible, so it needs the best optimization. I have tried the below query, but it just hangs for ages: SELECT `datas`.*, `dictionary`.`word` FROM `datas`, `dictionary` WHERE `datas`.`data` LIKE CONCAT('%', `dictionary`.`word`, '%') AND LENGTH(`dictionary`.`word`) > 3 ORDER BY `length` ASC LIMIT 15 I have also tried something similar to the above with a left join, and on clause that specified the like statement.

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  • preg_replace or regex string translation

    - by ccolon
    I found some partial help but cannot seem to fully accomplish what I need. I need to be able to do the following: I need an regular expression to replace any 1 to 3 character words between two words that are longer than 3 characters with a match any expression: For example: walk to the beach == walk(.*)beach If the 1 to 3 character word is not preceded by a word that's longer than 3 characters then I want to translate that 1 to 3 letter word to ' ?' For example: on the beach == on ?the ?beach The simpler the rule the better (of course, if there's an alternative more complicated version that's more performant then I'll take that as well as I eventually anticipate heavy usage eventually). This will be used in a PHP context most likely with preg_replace. Thus, if you can put it in that context then even better!

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  • PHP/MySQL - an array filter for bots

    - by Mike
    Hello, I'm making a hit counter. I have a database and I store the IP and $_SERVER['HTTP_USER_AGENT']; of the visitors. Now I need to add a filter, so I can put away the hits, that are made by bots. I found out, that many bots usually keep some common words in the $_SERVER['HTTP_USER_AGENT']; , so I's like to make and array of words, that would keep the bot from displaying in the results. Here is what I have now: while($row = mysql_fetch_array($yesterday, MYSQL_ASSOC)) { <-- Here I need a code, that would run through an array and check, if it containts the keywords and if it doesn't ... just count++; -- } Also if you know any other way of detecting and removing the bots from the results, I'd be verry thankful. Cheers

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  • How to change word recognition in vim spell?

    - by David
    I like that vim 7.0 supports spell checking via :set spell, and I like that it by default only checks comments and text strings in my C code. But I wanted to find a way to change the behavior so that vim will know that when I write words containing underscores, I don't want that word spell checked. The problem is that I often will refer to variable or function names in my comments, and so right now vim thinks that each piece of text that isn't a complete correct word is a spelling error. Eg. /* The variable proj_abc_ptr is used in function do_func_stuff' */ Most of the time, the pieces seperated by underscores are complete words, but other times they are abbreviations that I would prefer not to add to a word list. Is there any global way to tell vim to include _'s as part of the word when spell checking?

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  • Line formatting with Ruby.

    - by dbtek
    There is a text file containing words with 1 space between each of them. And there is also a command line entry that gives the length of line (output) wanted. Output will be words that fit into the length of the line (taken from command line). Also the first word will be on the left side of the line and the last word will be right side of it. The spaces between each word will be same. Any help will be appreciated thanks for replying.

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  • How to run a module

    - by Jimmy
    I have a module file containing the following functions: def replace(filename): match = re.sub(r'[^\s^\w]risk', 'risk', filename) return match def count_words(newstring): from collections import defaultdict word_dict=defaultdict(int) for line in newstring: words=line.lower().split() for word in words: word_dict[word]+=1 for word in word_dict: if'risk'==word: return word, word_dict[word] when I do this in IDLE: >>> mylist = open('C:\\Users\\ahn_133\\Desktop\\Python Project\\test10.txt').read() >>> newstrings=replace(mylist) ### This works fine. >>> newone=count_words(newstrings) ### This leads to the following error. I get the following error: Traceback (most recent call last): File "<pyshell#134>", line 1, in <module> newPH = replace(newPassage) File "C:\Users\ahn_133\Desktop\Python Project\text_modules.py", line 56, in replace match = re.sub(r'[^\s^\w]risk', 'risk', filename) File "C:\Python27\lib\re.py", line 151, in sub return _compile(pattern, flags).sub(repl, string, count) TypeError: expected string or buffer Is there anyway to run both functions without saving newstrings into a file, opening it using readlines(), and then running count_words function?

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  • Match Phrases (in array) in text string

    - by Tim Hanssen
    I'm using the Twitter API streaming to collect thousand of tweets every minute. They need to be matched to a list of keywords (can contain spaces). This is my current method: $text = preg_replace( '/[^a-z0-9]+/i', ' ', strtolower( $data['text'] ) ); $breakout = explode( " ", $text ); $result = array_intersect( $this->_currentTracks, $breakout ); I chop the tweet into words, and the matches them against my current keywords. This works well for all the keywords without a space ofc. If I wanted to find for example "Den Haag", It won't show up, because the string is exploded into words (based on the spaces). Any ideas about how I can do this in a quick way? Kind regards, Tim

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