Search Results

Search found 8466 results on 339 pages for 'nested forms'.

Page 109/339 | < Previous Page | 105 106 107 108 109 110 111 112 113 114 115 116  | Next Page >

  • SpringMvc java.lang.NullPointerException When Posting Form To Server

    - by dev_darin
    I have a form with a user name field on it when i tab out of the field i use a RESTFUL Web Service that makes a call to a handler method in the controller. The method makes a call to a DAO class that checks the database if the user name exists. This works fine, however when the form is posted to the server i call the same exact function i would call in the handler method however i get a java.lang.NullPointerException when it accesses the class that makes a call to the DAO object. So it does not even access the DAO object the second time. I have exception handlers around the calls in all my classes that makes calls. Any ideas as to whats happening here why i would get the java.lang.NullPointerException the second time the function is called.Does this have anything to do with Spring instantiating DAO classes using a Singleton method or something to that effect? What can be done to resolve this? This is what happens the First Time The Method is called using the Web Service(this is suppose to happen): 13011 [http-8084-2] INFO com.crimetrack.jdbc.JdbcOfficersDAO - Inside jdbcOfficersDAO 13031 [http-8084-2] DEBUG org.springframework.jdbc.core.JdbcTemplate - Executing prepared SQL query 13034 [http-8084-2] DEBUG org.springframework.jdbc.core.JdbcTemplate - Executing prepared SQL statement [SELECT userName FROM crimetrack.tblofficers WHERE userName = ?] 13071 [http-8084-2] DEBUG org.springframework.jdbc.datasource.DataSourceUtils - Fetching JDBC Connection from DataSource 13496 [http-8084-2] DEBUG org.springframework.jdbc.core.StatementCreatorUtils - Setting SQL statement parameter value: column index 1, parameter value [adminz], value class [java.lang.String], SQL type unknown 13534 [http-8084-2] DEBUG org.springframework.jdbc.datasource.DataSourceUtils - Returning JDBC Connection to DataSource 13537 [http-8084-2] INFO com.crimetrack.jdbc.JdbcOfficersDAO - No username was found in exception 13537 [http-8084-2] INFO com.crimetrack.service.ValidateUserNameManager - UserName :adminz does NOT exist The Second time When The Form Is 'Post' and a validation method handles the form and calls the same method the web service would call: 17199 [http-8084-2] INFO com.crimetrack.service.OfficerRegistrationValidation - UserName is not null so going to check if its valid for :adminz 17199 [http-8084-2] INFO com.crimetrack.service.OfficerRegistrationValidation - User Name in try.....catch block is adminz 17199 [http-8084-2] INFO com.crimetrack.service.ValidateUserNameManager - Inside Do UserNameExist about to validate with username : adminz 17199 [http-8084-2] INFO com.crimetrack.service.ValidateUserNameManager - UserName :adminz EXCEPTION OCCURED java.lang.NullPointerException

    Read the article

  • How to set the ReturnUrl for the Login link in MVC 3 app?

    - by user762196
    using System; using Microsoft.Practices.Unity; namespace <MyNameSpace> { public class UrlFactory { public static UrlFactory Current { get { return HttpApplicationUnityContext.Current.Resolve<UrlFactory>(); } } public string GetLoginUrl() { return String.Format("{0}/login?ReturnUrl={1}", MyConfig.BaseHttpUrl, <GET_PAGE_URL>); } } The user can be on any page on the site and click the Login link. But the ReturnUrl must always point to the exact page where he clicked it. I must take the user back to the page he clicked the login link. In my code above, how do I get the page url in <GET_PAGE_URL>? Thanks

    Read the article

  • Drupal: How to render a form and table on same page

    - by Aaron
    Can someone help me render a form and table on the same page? I'm sure it's easy, but can't think of how to do it. Here's hook_menu: function ncbi_subsites_menu() { $items = array(); $items['admin/content/ncbi_subsites'] = array( 'title' => 'NCBI Subsites Module', 'description' => 'Informs Drupal about NCBI subsites as defined by the Content Inventory database', 'page callback' => 'ncbi_subsites_show_main_page', 'access arguments' => array( 'administer site configuration' ), 'type' => MENU_NORMAL_ITEM, ); return $items; } Here's the callback: function ncbi_subsites_show_main_page() { $subsites = ncbi_subsites_get_subsites_from_inventory(); // fnc returns associative array from inventory, defined in include return ncbi_subsites_make_table( $subsites ); } In the callback I call some helper functions that return a themed, paged table. What I want is a small form above the table. How would I that?

    Read the article

  • Ms Access. How to resize a web browser in Access Form?

    - by tksy
    Hi, I have a web browser in my access form. I am embedding a gif file on it. but how ever i re size it there is a white border coming in the top and left side. The adjustments take place only at the bottom and right side. So when i embed a gif file with black background i end up getting a white background on the top and left sides, how do i make this go. thanks tksy

    Read the article

  • Rails -- Cant set value for date_select in form

    - by ChrisWesAllen
    I'm pulling data from an API where the date data comes in as "2008-02-11 00:00:00 " I would like that data to go into my form within the date_select as a value so I can view it correctly before I add it into my database. The view looks like <%= f.label :start_date %><br /> <%= f.date_select :start_date, :value => " #{@stdate[idx]} " %> The object is actually an array of dates since I'm doing this action several times do thats why the [idx] is there; serving as an index. <%= @stdate[idx] % ends up outputting "2008-02-11 00:00:00 " but the fields for the date_select helper only outputs the current date "2010" "June" "5" in those dropdown date selects fields... Do I need to set the values of the Year, Month, and Date Individually? I have Chronic and tried to parse the object before using it as a value for the date_select and that didnt work either. Any ideas?

    Read the article

  • Is there a way to do this with basic JS DOM?

    - by Thomas
    I need to apply/remove to an input field according to a user's selection in a separate drop down form - but I can't figure out how to target the input's class. I need to add/remove the 'pageRequired' class from this input: <input type="text" title="Company Required" name="customfields-tf-2-tf" class="inputclass pageRequired textInput" id="customfields-tf-2-tf" /> When the user selects one of two options from a drop down field. For example: <select class="dropdown" name="customfields-s-1-s" id="customfields-s-1-s" > <option value="Owner"<?php if(in_array("Owner",$temp_values)) { ?> selected='selected'<?php } ?>> Owner</option> <option value="Broker"<?php if(in_array("Broker",$temp_values)) { ?> selected='selected'<?php } ?>> Broker</option> </select> If the user selects broker than I want to add the pageRequired class to the first input field and remove it if the user selects Owner.

    Read the article

  • codeigniter populate form from database

    - by Delirium tremens
    In the controller, I have... function update($id = null) { $this->load->database(); // more code $data = array(); $data = $this->db->get_where( 'users', array( 'id' => $id ) ); $data = $data->result_array(); $data = $data[0]; // more code $this->load->view('update', $data); } In the view, I have... <h5>Username</h5> <input type="text" name="username" value="<?php echo set_value('username'); ?>" size="50" /> <h5>Email</h5> <input type="text" name="email" value="<?php echo set_value('email'); ?>" size="50" /> <h5>Email Confirmation</h5> <input type="text" name="emailconf" value="<?php echo set_value('emailconf'); ?>" size="50" /> <h5>Password</h5> <input type="text" name="password" value="<?php echo set_value('password'); ?>" size="50" /> <h5>Password Confirmation</h5> <input type="text" name="passconf" value="<?php echo set_value('passconf'); ?>" size="50" /> set_value() isn't reading $data search for value="" at http://codeigniter.com/forums/viewthread/103837/ The poster uses only the set_value() function between "" in value="". I'm wondering how to do the same, but I can't get it to work. Help?

    Read the article

  • Overriding initial value in ModelForm

    - by schneck
    Hi, in my Django (1.2) project, I want to prepopulate a field in a modelform, but my new value is ignored. This is the snippet: class ArtefactForm(ModelForm): material = CharField(widget=AutoCompleteWidget('material', force_selection=False)) def __init__(self, *args, **kwargs): super(ArtefactForm, self).__init__(*args, **kwargs) self.fields['material'].initial = 'Test' I also tried with self.base_fields, but no effect: there is always the database-value displaying in the form. Any ideas?

    Read the article

  • jQuery focus on content of input / textarea - not working properly in IE8

    - by katebp
    I want the input fields on my site to select all the text when the user first clicks on them, but in IE8 the text is selected for a split second then reverts back to normal. Works fine in FF. My js code: $(document).ready(function () { //HTML DOM document is ready // Add this behavior to all text fields $("input[type='text'], textarea").live("focus", function(){ // Select field contents this.focus(); }); }); Any ideas? I've tried adding ".select()" after "this" and bizarrely enough it works, but throws loads of js errors in FF and IE. Thanks

    Read the article

  • How to detect if a form input element of type file is empty

    - by Ankur
    I have some code which reads a file through a form field of type file <input type="file" ... /> I want to give the user another option of providing a url to a file rather than having to upload it as many are already online. How can I detect when this field is empty on the server side. I am using Apache Commons FileUpload FileItemStream item = iter.next(); name = item.getFieldName(); stream = item.openStream(); if(!item.isFormField()){ if(item.toString()!=""){ .... I need to detect when item is empty. The above code doesn't work, nor does using: if(item.equals(null)){ ....

    Read the article

  • breaking datetime into constituent parts ASP.NET MVC form

    - by nick
    hi guys, i have searched the web relentlessly for this and have not found anything - which is surprising because i would think it is such a common scenario! Basically, on my model i have a DateTime field which i wish the user to populate through a form. I am using the Html helper to render all other parts of the form (along with validation) So this question is in two parts... Html Helper Firstly, is there any way to use the Html helper to split the DateTime field to be rendered as the three constituent parts of a date: day, month, year (since i do not care about the time part). This could be rendered as text boxes, drop down lists or a combination of both. Model Binding And then when the form is posted, what is the best approach for binding back up to the model? I have seen Scott Hanselmann's solution to this, but it seems a little bloated for what i need - i was hoping for a slightly more elegant solution. Is it recommended to extend DefaultModelBinder and set that as default binder (since all dates would be handled in this way) or write a class that implements IModelBionder and set it as the default binder for the DateTime type? Thanks for all the help in advance :-) i'm loving MVC but it's infuriating me that something so trivial is causing so much headaches!

    Read the article

  • why resubmit after refresh php page

    - by user2719452
    why resubmit after refresh php page? try it, go to: http://qass.im/message-envelope/ and upload any image now try click F5, after refresh page "resubmit" Why? I don't want resubmit after refresh page What is the solution? See this is my form code: <form id="uploadedfile" name="uploadedfile" enctype="multipart/form-data" action="upload.php" method="POST"> <input name="uploadedfile" type="file" /> <input type="submit" value="upload" /> </form> See this is php code upload.php file: <?php $allowedExts = array("gif", "jpeg", "jpg", "png", "zip", "pdf", "docx", "rar", "txt", "doc"); $temp = explode(".", $_FILES["uploadedfile"]["name"]); $extension = end($temp); $newname = $extension.'_'.substr(str_shuffle(str_repeat("0123456789abcdefghijklmnopqrstuvwxyz", 7)), 4, 7); $imglink = 'attachment/attachment_file_'; $uploaded = $imglink .$newname.'.'.$extension; if ((($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpg") || ($_FILES["uploadedfile"]["type"] == "image/pjpeg") || ($_FILES["uploadedfile"]["type"] == "image/x-png") || ($_FILES["uploadedfile"]["type"] == "image/gif") || ($_FILES["uploadedfile"]["type"] == "image/png") || ($_FILES["uploadedfile"]["type"] == "application/msword") || ($_FILES["uploadedfile"]["type"] == "text/plain") || ($_FILES["uploadedfile"]["type"] == "application/vnd.openxmlformats-officedocument.wordprocessingml.document") || ($_FILES["uploadedfile"]["type"] == "application/pdf") || ($_FILES["uploadedfile"]["type"] == "application/x-rar-compressed") || ($_FILES["uploadedfile"]["type"] == "application/x-zip-compressed") || ($_FILES["uploadedfile"]["type"] == "application/zip") || ($_FILES["uploadedfile"]["type"] == "multipart/x-zip") || ($_FILES["uploadedfile"]["type"] == "application/x-compressed") || ($_FILES["uploadedfile"]["type"] == "application/octet-stream")) && ($_FILES["uploadedfile"]["size"] < 5242880) // Max size is 5MB && in_array($extension, $allowedExts)) { move_uploaded_file($_FILES["uploadedfile"]["tmp_name"], $uploaded ); echo '<a target="_blank" href="'.$uploaded.'">click</a>'; // If has been uploaded file echo '<h3>'.$uploaded.'</h3>'; } if($_FILES["uploadedfile"]["error"] > 0){ echo '<h3>Please choose file to upload it!</h3>'; // If you don't choose file } elseif(!in_array($extension, $allowedExts)){ echo '<h3>This extension is not allowed!</h3>'; // If you choose file not allowed } elseif($_FILES["uploadedfile"]["size"] > 5242880){ echo "Big size!"; // If you choose big file } ?> if you have solution, please edit my php code and paste your solution code! Thanks.

    Read the article

  • PHP Form - Empty input enter this text - Validation

    - by James Skelton
    No doubt very simple question for someone with php knowledge. I have a form with a datepicker, all is fine when a user has selected a date the email is send with: Date: 2012 04 10 But i would like if the user has skipped this and left blank (as i have not made this required) to send as: Date: Not Entered (<-- Or something) Instead at the minute of course it reads: Date: Form input <input type="text" class="form-control" id="datepicker" name="datepicker" size="50" value="Date Of Wedding" /> This is the validator $(document).ready(function(){ //validation contact form $('#submit').click(function(event){ event.preventDefault(); var fname = $('#name').val(); var validInput = new RegExp(/^[a-zA-Z0-9\s]+$/); var email = $('#email').val(); var validEmail = new RegExp(/^([a-zA-Z0-9_\.\-])+\@(([a-zA-Z0-9\-])+\.)+([a-zA-Z0-9]{2,4})+$/); var message = $('#message').val(); if(fname==''){ showError('<div class="alert alert-danger">Please enter your name.</div>', $('#name')); $('#name').addClass('required'); return;} if(!validInput.test(fname)){ showError('<div class="alert alert-danger">Please enter a valid name.</div>', $('#name')); $('#name').addClass('required'); return;} if(email==''){ showError('<div class="alert alert-danger">Please enter an email address.</div>', $('#email')); $('#email').addClass('required'); return;} if(!validEmail.test(email)){ showError('<div class="alert alert-danger">Please enter a valid email.</div>', $('#email')); $('#email').addClass('required'); return;} if(message==''){ showError('<div class="alert alert-danger">Please enter a message.</div>', $('#message')); $('#message').addClass('required'); return;} // setup some local variables var request; var form = $(this).closest('form'); // serialize the data in the form var serializedData = form.serialize(); // fire off the request to /contact.php request = $.ajax({ url: "contact.php", type: "post", data: serializedData }); // callback handler that will be called on success request.done(function (response, textStatus, jqXHR){ $('.contactWrap').show( 'slow' ).fadeIn("slow").html(' <div class="alert alert-success centered"><h3>Thank you! Your message has been sent.</h3></div> '); }); // callback handler that will be called on failure request.fail(function (jqXHR, textStatus, errorThrown){ // log the error to the console console.error( "The following error occured: "+ textStatus, errorThrown ); }); }); //remove 'required' class and hide error $('input, textarea').keyup( function(event){ if($(this).hasClass('required')){ $(this).removeClass('required'); $('.error').hide("slow").fadeOut("slow"); } }); // show error showError = function (error, target){ $('.error').removeClass('hidden').show("slow").fadeIn("slow").html(error); $('.error').data('target', target); $(target).focus(); console.log(target); console.log(error); return; } });

    Read the article

  • django updating m2m field

    - by Marconi
    I have a model service and a ModelForm named Service which I use to add and update the service model. The model looks like this: class Service(models.Model): categories = models.ManyToManyField(Category) The categories field is displayed as a tag with that allows multiple selection. It works well when I'm adding a new record but when I'm updating it, only one service is showing up on the request.POST['categories'] even if I selected multiple categories. I tried dumping the request object and I can see that the categories is showing something like: u'categories': [u'3', u'4', u'2'] I tried calling the request._get_post() and it did return only 1 category, hence the request.POST['categories'] returns only 1. Anybody who knows what's happening and how to fix it?

    Read the article

  • c# passing something from child form to parent

    - by Alan Bennett
    hi guys. so i have this form and on it is a combo box populated from a database via a SQL method. and i have another form which allows us to maintain the database table etc. so i make a new instance of the second form doing: Form1 frm = new Form2; frm.show(); once i have done what ever i wanted to do on the second form and i close it, i need to somehow trigger an event or something which will refresh the combo box and the code behind it. i was thinking of some onchange or focus event for the whole form, the problem is i have 5 of these combo boxes and running all the SQL again. i also thought of passing somesort of variable thro but then i would still need an event for that. any ideals would be awesome

    Read the article

  • Adding new records in Access without wrecking the form

    - by Matt Parker
    I'm working on a simple Access 2003 application to keep track of things that need to be done for clients for some colleagues. Each colleague has a set of clients, and each client has a set of actions that need to be taken by a certain date. I've set up a form that consists of a combobox for client ID (indexed), a drop-down for the person who is handling that client's case, and a button for adding new clients (a standard Access-created Add Record button). The actions are listed in a subform below these three elements. The problem I've run into is that the first person I tested this on clicked the button to add a new record, then didn't fill it out and tried to select another client from the drop-down list. Access interprets this as an attempt to set the selected Client ID as the ID for the new record and rightfully throws an error for duplicate primary keys. I can think of a couple of ways around this problem, but I'd much rather hear your elegant solutions than kludge together some junk in a language I don't know. Let me know if you have any questions. Thank you.

    Read the article

  • Get Data from Windows Form into C# program

    - by Jimmy
    I want my C# program to collect data. Then, when the OK button is clicked, I want this data to be loaded into my program -- such as into variables in Main(), or into data members of a class I have constructed, and I want the form to then go away -- not be hidden, but actually closed. Alas, read as I might in the book I have, the data collected by the form stays in the form, execution proceeds within the form, and the same form is used to display the result of the program's computations. Sheesh. All I want is to capture the form's information, close the form and proceed with my program. I would appreciate some tips on geting data from a form into Main() or into a class's data members. Thanks, Lucky

    Read the article

  • Drupal: How to Render Results of Form on Same Page as Form

    - by Aaron
    How would I print the results of a form submission on the same page as the form itself? Relevant hook_menu: $items['admin/content/ncbi_subsites/paths'] = array( 'title' => 'Paths', 'description' => 'Paths for a particular subsite', 'page callback' => 'ncbi_subsites_show_path_page', 'access arguments' => array( 'administer site configuration' ), 'type' => MENU_LOCAL_TASK, ); page callback: function ncbi_subsites_show_path_page() { $f = drupal_get_form('_ncbi_subsites_show_paths_form'); return $f; } Form building function: function _ncbi_subsites_show_paths_form() { // bunch of code here $form['subsite'] = array( '#title' => t('Subsites'), '#type' => 'select', '#description' => 'Choose a subsite to get its paths', '#default_value' => 'Choose a subsite', '#options'=> $tmp, ); $form['showthem'] = array( '#type' => 'submit', '#value' => 'Show paths', '#submit' => array( 'ncbi_subsites_show_paths_submit'), ); return $form; } Submit function (skipped validate function for brevity) function ncbi_subsites_show_paths_submit( &$form, &$form_state ) { //dpm ( $form_state ); $subsite_name = $form_state['values']['subsite']; $subsite = new Subsite( $subsite_name ); //y own class that I use internally in this module $paths = $subsite->normalized_paths; // build list $list = theme_item_list( $paths ); } If I print that $list variable, it is exactly what I want, but I am not sure how to get it into the page with the original form page built from 'ncbi_subsites_show_path_page'. Any help is much appreciated!

    Read the article

  • Remembering Form information

    - by Pete Herbert Penito
    Hi everyone! I'm sorry if this has been asked before but I feel my situation is a little different... I have a huge form (like 50 questions involving checkboxes, drop downs, text boxes and textareas) When a user submits a form and the validation page throws an error, is there an easy way to keep the info they entered? My intitial form is on form.php and then the form action is form_posted.php, before anything is run on form_posted.php I have my validation code which sends the user back to form.php with an error number (eg. form.php?error=3) if there was a problem with any in particular. This is done with header("form.php?error=3") so on form.php do the posted variables exist? even tho the page wasn't specifically sent with any posted variables. Also if this is the case, is it completely secure to be making the value of a textbox what it was before? like <input type="text" value="php echo $_POSTED["username"] ?>">

    Read the article

  • ZF2 Vertical Form

    - by yunhasnawa
    I created a simple form in typical ZF2 application. The form class code is just a modified code provided by Zend's Album example. <?php namespace Admin\Form; use Zend\Form\Form; class CityForm extends Form { public function __construct($name = null) { parent::__construct('city'); $this->setAttribute('method', 'post'); $this->add(array( 'name' => 'id', 'attributes' => array( 'type' => 'hidden', ), )); $this->add(array( 'name' => 'name', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Name', ), )); $this->add(array( 'name' => 'province', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Province', ), )); $this->add(array( 'name' => 'country', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Country', ), )); $this->add(array( 'name' => 'coordinate', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Coordinate', ), )); $this->add(array( 'name' => 'submit', 'attributes' => array( 'type' => 'submit', 'value' => 'Save', 'id' => 'submitButton', ), )); } } And call it like this in CityController, a typical controller extends AbstractActionController: public function addAction() { $form = new CityForm(); $viewData = array( 'form' => $form ); return new ViewModel($viewData); } Finally in view I echo it like this: <?php $title = 'Add New City'; ?> <?php $this->headtitle($title); ?> <h1><?php echo $this->escapehtml($title); ?></h1> <?php $form = $this->form; ?> <?php $form->setAttribute('action', $this->url('city', array('action' => 'add'))); ?> <?php $form->prepare(); ?> <?php echo $this->form()->openTag($form); echo $this->formHidden($form->get('id')); echo $this->formRow($form->get('name')); echo $this->formRow($form->get('province')); echo $this->formRow($form->get('country')); echo $this->formRow($form->get('coordinate')); echo $this->formSubmit($form->get('submit')); echo $this->form()->closeTag(); ?> What I expected to see is a vertical form like this: But what i got is an ugly form like this: What's wrong with my code? Please help. EDIT: When I inspect element, the form generated is strange. The <input> element is inside the <label> element. <form id="city" name="city" method="post" action="/karciscus/public/admin/city/add"> <input type="hidden" value="" name="id"> <label> <span>Name</span><input type="text" value="" name="name"> </label> <label> <span>Province</span><input type="text" value="" name="province"> </label> <label> <span>Country</span><input type="text" value="" name="country"> </label> <label> <span> Coordinate</span><input type="text" value="" name="coordinate"> </label> <input type="submit" value="Save" id="submitButton" name="submit"> </form> I'm pretty sure it is the cause of my ugly rendered form. I think it is not supposedly like that. How to fix it?

    Read the article

  • extending spring form tag library attributes

    - by TimmyJ
    I'm using Spring's form tag library in a Spring MVC application that I am developing. The company I am working for has implemented some company-wide policies based on the definition of custom attributes for certain tags. For instance, by default (though the inclusion of a standard javascript file) all tags have their values automatically converted to upper case. In order to disable this one would define their tag with a custom attribute in the following way: <input type="text" uppercase="false" /> The problem is that the addition of these custom attributes to a spring:form tag causes an error at runtime. I've pasted the error below. org.apache.jasper.JasperException: /WEB-INF/jsp/reportCriteria.jsp(45,5) Attribute uppercase invalid for tag input according to TLD My question is: is there any way to extend the TLD to allow for these attributes, or is there any other way add these custom attributes to these spring:form tags?

    Read the article

  • Displaying form validation errors in a template (Symfony)

    - by Jay
    Hi, let's say I have a blog with a module "post". now I display a post like this: post/index?id=1 in the index-action i generate a new CommentForm and pass it as $this-form to the template and it is being displayed at the bottom of a post (it's just a textfield, nothing special). form action is set to "post/addcomment". How can I display the validation errors in this form? using setTemplate('index') doesn't work because I would have to pass the id=1 to it... thanks

    Read the article

  • MYSQL/PHP: Inserting data via HTML form, same "input name"

    - by Camen
    I'm new to MySQL and as a learning project I'd like to make a recipe database. I'd like to the user to be able to enter ingredients through a simple HTML form but I'm stuck in how to label the form so that I can enter several ingredients into the database at once. I'd like to do something like this: <form method="post" action="insert.php"> Ingredient 1: <input type="text" name="ingredient"><br /> Ingredient 2: <input type="text" name="ingredient"><br /> Ingredient 3: <input type="text" name="ingredient"><br /> <input type="submit" value="Submit"> </form> When I do this, I add rows to the table but they're all empty. I know it's got something to do with me using "ingredient" (the table value where I want to add the ingredient name) several times in the form, but I just don't know how to solve it. I would absolutely love some input on how to make it work.

    Read the article

  • Authenticating a user for a single app with multiple domains

    - by hofnarwillie
    I have one asp.net web application, but two different domains point to this web app. For instance: www.one.com and www.two.com both point to the same web app. I have an issue where I need certain pages to be on a specific domain (due to some security requirements from our online payment provider - a third party website). So let's say page1.aspx needs to be called on www.two.com The process is as follows: A user logs into www.one.com The authentication cookie is saved to the browser The user then navigates to page1.aspx and, if on the wrong domain, gets redirected to the correct domain. (this redirection happens on page1.aspx in the page_load event) Then asp.net redirects the user to the login screen, because the authentication cookie is not sent to www.two.com. How can I track the user and keep him/her logged in between the two domains?

    Read the article

< Previous Page | 105 106 107 108 109 110 111 112 113 114 115 116  | Next Page >